1) Write in the formula. What equals the perimeter P of the rectangle wich is 25 cm wide. (show the length with the letter b.) 2) Calculate the perimeter of the rectangle when its length is equal to:
a) 45 cm; b) 0.25 m; c) 650 mm; d) 3 m by 9 cm; e) 3 dm.

Please I really need help

Answers

Answer 1

Answer:

1)P = 2 x(L+l) = 2 x (25+L)

2) Maintaing L= 25 cm

P= 2x (25+45) = 140 cm²

P= 2x (25+0,25m) =2x(25+25)= 100 cm²

P= 2x (25+650 mm) =2x(25+65)= 180 cm²

d) ambigous

P= 2x (25+3dm) = 2x (25+30)=110 cm²

Step-by-step explanation:


Related Questions

Kona’s mother wanted to find out how many minutes her family spends on the phone for each call made. She put her data in a table after a week of observation as shown below. She asked Kona to make a histogram from the data.

Minutes
Number of Calls
1 - 5
2
6 - 10
5
11 - 15
6
16 - 20
10
21 - 25
7
26 - 30
2
31 - 35
1
36 - 40
0
41 - 45
2
46 - 50
1

Which chart has the correct setup for Kona’s histogram?
A 2-column table with 4 rows tilted Time on Phone. Column 1 has entries interval use, appropriate scale, vertical axis represents, horizontal axis represents. Column 2 has entries 10, 0 to 12, minutes on phone, number of calls.
A 2-column table with 4 rows tilted Time on Phone. Column 1 has entries interval use, appropriate scale, vertical axis represents, horizontal axis represents. Column 2 has entries 10, 1 to 12, number of calls, minutes on phone.
A 2-column table with 4 rows tilted Time on Phone. Column 1 has entries interval use, appropriate scale, vertical axis represents, horizontal axis represents. Column 2 has entries 5, 1 to 12, minutes on phone, number of calls.
A 2-column table with 4 rows tilted Time on Phone. Column 1 has entries interval use, appropriate scale, vertical axis represents, horizontal axis represents. Column 2 has entries 5, 0 to 12, number of calls, minutes on phone.

Answers

Answer:

D—

The histogram will have a horizontal or an x axis of time/minute intervals of the calls (5 minutes in each), and the vertical axis or y axis will be the number of calls made.

Answer:

d

Step-by-step explanation:

yo welcome

Marvin washes 10 1/2 crates in 3/4 hours. At this rate how many crates can he wash in one hour?

Please help us due tomorrow 3/3/2020!!!

Answers

To work this one out, you want to divide 10 1/2 by 3/4 right? So to do that, you want to change 10 1/2 to an improper fraction (21/2) and multiply it by 3/4’s reciprocal (4/3) and use cancellation to get the answer 14. Attached is an example of how to work it out on paper.

Given f(x) and g(x) = k·f(x), use the graph to determine the value of k.
g(x)

Answers

Explanation:

The diagram for this exercise is attached below. We have two linear functions [tex]f(x) \ and \ g(x)[/tex] and the following relationship:

[tex]g(x) = kf(x)[/tex]

From the graph, we know that:

[tex]f(-3)=1 \\ \\ g(-3)=-3[/tex]

Then, substituting into the relationship:

[tex]g(-3)=kf(-3) \\ \\ -3=k(1) \\ \\ \\ Finally: \\ \\ \boxed{k=-3}[/tex]

Sin(pi/2-x)/cot^2(pi/2-x)+1

Answers

Answer:

[tex] { \cos}^{3} x[/tex]

Step-by-step explanation:

We want to simplify:

[tex] \frac{ \sin( \frac{\pi}{2} - x) }{ { \cot}^{2} ( \frac{\pi}{2} -1 ) + 1} [/tex]

Use the Pythagorean identity:

[tex] { \csc}^{2}x = { \cot}^{2}x + 1[/tex]

We apply this property to get:

[tex] \frac{ \sin( \frac{\pi}{2} - x) }{ { \csc}^{2} ( \frac{\pi}{2} -x) } [/tex]

This gives us:

[tex]\frac{ \sin( \frac{\pi}{2} - x) }{ \frac{1}{{ \sin}^{2} ( \frac{\pi}{2} -x)} } [/tex]

We simplify to get:

[tex]\sin^{3} ( \frac{\pi}{2} -x)[/tex]

[tex](\sin ( \frac{\pi}{2} -x))^{3}[/tex]

Apply the complementary identity;

[tex](\cos x)^{3} = { \cos}^{3} x[/tex]

Below is a drawing of a wall that is to be covered with either wallpaper or paint. The wall is 8 ft. high and
16 ft wide. The window, mirror, and fireplace are not to be painted or papered. The window measures 18 in wide
and 14t. high. The fireplace is sit wide and 3 it. High while the mirror above the fireplace is 4 ft. wide and 2 ft.
high. Note: this drawing is not to scale)
How many square feet of wallpaper are needed to cover the wall?

Answers

84 sq. ft of the wall has to be covered with paint or wallpaper.

Step-by-step explanation:

Step 1: Find the area of wallpaper to be covered by calculating the area of the wall and subtracting the areas of the window, mirror and fireplace from it. All are rectangular in shape with are given by A = length × width

Area of the wall = 8 × 16 = 128 ft²

Area of the window = 18/12 × 14 = 1.5 × 14 = 21 ft² (since 1 ft = 12 in)

Area of the fireplace = 5 × 3 = 15 ft²

Area of the mirror = 4 × 2 = 8 ft²

Step 2: Calculate the area to be painted or covered with wallpaper

Area of the wall to be covered with paint or wallpaper = 128 - (21 + 15 + 8)

                              = 128 - 44

                              = 84 ft²

Answer:

84 ft²

Step-by-step explanation:

Step 1: Find the area of the wall.

The wall is 8 ft high and  16 ft wide

A = LW

A = (16)(8)

A = 128 ft²

Step 2: Find the area of the window, fireplace, and mirror.

Window: The window measures 18 in wide  and 14 ft high

18 in = 1.5 ft

A = LW

A = (14)(1.5)

A = 21 ft²

Fireplace: The fireplace is 5 ft wide and 3 ft high

A = LW

A = (3)(5)

A = 15 ft²

Mirror: The mirror above the fireplace is 4 ft wide and 2 ft high

A = LW

A = (2)(4)

A = 8 ft²

Step 3: Add all the areas of the three objects (window, fireplace, and mirror)

A = 21 + 15 + 8

A = 36 + 8

A = 44 ft²

Step 4: Subtract the total area of the objects from the area of the wall.

A = 128 ft² - 44 ft²

A = 84 ft²

What is the answer 2-2n=3n+17

Answers

Answer:

n=-3

Step-by-step explanation:

2-2n=3n+17

Add 2n to each side

2-2n+2n=3n+2n+17

2 = 5n+17

Subtract 17 from each side

2-17 = 5n+17-17

-15 = 5n

Divide by 5

-15/5 = 5n/5

-3 =n

Answer:

n = -3

Step-by-step explanation:

2 - 2n = 3n + 17

Collect the like terms

-2n - 3n = 17 - 2

-5n = 15

Divide both sides by -5

n = 15/-5

n = -3

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