1.
A 2 kg toy car moves at a speed of 5 m/s.
a. What is the kinetic energy of the car?
b. If a child applies a 3 N force for 2 m in the same direction the car is already moving, how much work is
done on the car?
c. What is the change in the car’s kinetic energy from the applied force?
d. What is the final kinetic energy of the car?
e. What is the velocity of the car after the child applies the 3 N force?

Answers

Answer 1

Answer:

a.25J b.6J c.6J d.31J e.[tex]\sqrt{31}[/tex] m/s

Explanation:

a. using the formula Ek=1/2mv^2, the kinetic energy would be 1/2*2*5^2=25J

b. we can separate the work the child applied. So the work he/she applied would be 2*3=6J (W=FS)

c. by the "Energy conservation law", we knew the energy can be "add up" since they wouldn't "disappear". Thus, the change in the car’s kinetic energy is 6J.

d.25+6=31J

e.now you know the new Ek, and the m, just use the formula again! 31=1/2*2*v^2. So the velocity after the child push it would be [tex]\sqrt{31}[/tex] m/s

Answer 2

The kinetic energy and the work done by the car is:

(a) 25 J

(b) 6 J

(c) 6 J

(d) 31 J

(e) 5.57 m/s

According to the question,

Force,

F = 3 N

Distance,

d = 2 m

(a)

The Kinetic energy of the car will be:

→ [tex]K_i = \frac{1}{2} mv_0^2[/tex]

       [tex]= \frac{1}{2}\times (2)\times (5)^2[/tex]

       [tex]= 25 \ J[/tex]

(b)

The work done by the car will be:

→ [tex]W = fd[/tex]  

       [tex]= 3\times 2[/tex]

       [tex]= 6 \ J[/tex]

(c)

The change in the car's K.E will be:

→ [tex]\Delta K = W[/tex]

          [tex]= 6 \ J[/tex]

(d)

The car's final K.E will be:

→ [tex]K_f = W+K_i[/tex]

        [tex]= 6+25[/tex]

        [tex]= 31 \ J[/tex]

(e)

The final velocity of the car will be:

→ [tex]v_f = \sqrt{\frac{2 K_f}{m}}[/tex]

       [tex]= \sqrt{\frac{2\times 31}{2} }[/tex]

       [tex]= 5.57 \ m/s[/tex]

Thus the above solution is correct.

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Related Questions

AS AIRPLANE WENT FROM 120 m/s to 180 m/s in 4.0 seconds what is the acceleration

Answers

Answer:15metre per second squ

I

Explanation:

acceleration=(final velocity-initial velocity)÷t

acceleration=(180-120)÷4

acceleration=60÷4

acceleration=15 metre per second square

The graph below shows the force required to stretch a spring various distances. Review the graph below.

A graph of Force versus Elongation. Elongation (m) is on the x axis and Force (N) is on the y axis. A straight line passes through the points 0 comma 0 and 10 comma 15.

What is the best approximate value for the elastic potential energy (EPE) of the spring elongated by 7.0 meters?

1.5 J
11 J
37 J
74 J

Answers

Answer:

37 J

Explanation:

Given:

A graph of force versus elongation in which a line passes through the points (0, 0) and (10, 15).

The x-axis represents elongation and y-axis represents force.

Elongation (x) = 7.0 m

Now, we know that the slope of a line of force versus elongation graph is the value of the spring constant.

Therefore, finding the slope of the line passing through (0, 0) and (10, 15), we get:

[tex]k=\frac{15-0}{10-0}=1.5\ N/m[/tex]

Therefore, the spring constant (k) = 1.5 N/m.

Now, the elastic potential energy (EPE) of the spring is given as:

[tex]EPE=\frac{1}{2}kx^2[/tex]

Plug in 1.5 for 'k' and 7.0 for 'x'. Solve for EPE.

[tex]EPE=\frac{1}{2}\times 1.5\times (7.0)^2\\\\EPE=\frac{1.5\times 49}{2}\\\\EPE=36.75\approx 37\ J[/tex]

Therefore, the best approximate value for the elastic potential energy (EPE) of the spring elongated by 7.0 meters is 37 J.

What is the relationship between the masses of the objects and the gravitational force between them?​

Answers

Answer:

Gravitational force is directly proportional to the masses of the objects.

Explanation:

A cart rolling down an incline for 5.0 seconds has an acceleration of 4.0 m/s .If the cart has an initial speed of of 2.0 m/s ,what’s its final speed.

Answers

Applying

v=u+a.t

(all the symbols are bearing their conventional meaning)

Here,u=2ms−1,t=5,a=4ms−2

So,v=2+4⋅5=22ms−1

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Answer:

22m/s

Explanation:

V = u + at

= 2 + ( 4x5)

= 2 + 20

= 22m/s

Which forces affect a baseball's speed as it rises after being hit by a bat?
A. net force and drag
B. applied force and net force
C. gravity and drag
D. applied force and gravity

Answers

C) Gravity and drag

Explanation:

Here we are considering the ball after it has been hit by a bat.

When the ball is in the air, there are only two forces acting on it:

The weight of the ball (force of gravity), acting downward. Its magnitude is given by [tex]F_g = mg[/tex], where m is the mass of the ball and g is the acceleration of gravityThe air drag, which is the resistance of the air on the ball, acting downward as well (it acts against the direction of motion of the ball). The magnitude of this force is proportional to the speed of the ball

There is no applied force on the ball, since that one only acts on the ball when it is in contact with the bat - however, when the ball is in the air, the applied force no longer acts on the ball.

Therefore, the correct answer is

C. gravity and drag

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Answer:

C) Gravity and drag

Explanation:

Here we are considering the ball after it has been hit by a bat.

When the ball is in the air, there are only two forces acting on it:

The weight of the ball (force of gravity), acting downward. Its magnitude is given by , where m is the mass of the ball and g is the acceleration of gravity

The air drag, which is the resistance of the air on the ball, acting downward as well (it acts against the direction of motion of the ball). The magnitude of this force is proportional to the speed of the ball

There is no applied force on the ball, since that one only acts on the ball when it is in contact with the bat - however, when the ball is in the air, the applied force no longer acts on the ball.

Therefore, the correct answer is

C. gravity and drag

The work done on a box is 532 joules. The force applied to the box was 48 N. What was the displacement of the box? *

Answers

Explanation:

Work = force × displacement

532 J = 48 N × d

d ≈ 11 m

If the sine of an angle is 4/7 what is the cosine of its complement.

Answers

Answer: 0.57

Explanation:

Let's begin by explaining that two angles are complementary when they sum is [tex]90\°[/tex]:

[tex]\theta + \alpha=90\°[/tex]

Having this clear, let's find [tex]\theta[/tex] from the following trigonometric function:

[tex]sin \theta=\frac{4}{7}[/tex]

[tex]\theta=sin^{-1} (\frac{4}{7})=34.84 \°[/tex]

Now that we have the value of [tex]\theta[/tex], let's find [tex]\alpha[/tex]:

[tex]\alpha=90\°-\theta[/tex]

[tex]\alpha=90\°-34.84 \°[/tex]

[tex]\alpha=55.15\°[/tex] This is the complement of angle [tex]\theta[/tex]

Then, the cosine of the complement [tex]\alpha[/tex] is:

[tex]cos \alpha=cos(55.15\°)[/tex]

[tex]cos \alpha=0.57[/tex] This is the answer

A plastic-foam container used as a picnic cooler contains a block of ice at 0°C. If 225g of ice melts, how much heat passes through the walls of the container?

Answers

Final answer:

To determine the amount of heat passing through the walls of the container, we can calculate the rate of heat transfer through conduction using the formula q = k * A * (T2 - T1) / d. Once we have the rate of heat transfer, we can multiply it by the time to find the total heat transferred.

Explanation:

To determine how much heat passes through the walls of the container, we need to calculate the heat transfer through conduction. The rate of heat transfer can be calculated using the formula q = k * A * (T2 - T1) / d, where q is the heat transfer, k is the thermal conductivity of the material, A is the surface area, T2 is the temperature outside the container, T1 is the temperature inside the container, and d is the thickness of the walls. We can then multiply the rate of heat transfer by the time to find the total heat transferred. In this case, the temperature outside the container is 35.0°C and the temperature inside the container is 0°C.

Let's calculate the heat transfer rate:

q = k * A * (T2 - T1) / d

Assuming the thermal conductivity of the plastic-foam material is known and given, we can substitute the values into the equation and calculate the rate of heat transfer. Once we have the rate of heat transfer, we can multiply it by the time to find the total heat transferred.

5. What is the kinetic energy of a 2,000 kg car that is traveling
10 m/s?

Answers

Final answer:

The kinetic energy of the car is calculated using the formula KE = 1/2 * m * v^2, where m is mass and v is velocity. Substituting the given values yields a kinetic energy of 100,000 Joules for the car.

Explanation:

The kinetic energy of an object can be calculated using the formula: KE = 1/2 * m * v^2, where 'm' stands for mass and 'v' stands for velocity. In this scenario, the mass (m) of the car is 2,000 kg and the velocity (v) is 10 m/s. Plugging these values into the formula we get: KE = 1/2 * 2000 kg * (10 m/s)^2. Therefore, the kinetic energy of the car is 100,000 Joules.

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Plate A and Plate B are both made of continental plate material where they touch. What will happen as the plates press together?

Answers

Answer:

Plate A and Plate B are both made of continental plate material where they touch. What will happen as the plates press together? The edges of both plates will be pushed upward as the plates continue to move toward each other.

Explanation:

When two continental plates collide with each other and they fold the rock at the boundary, lifting up, and leading to the formation of mountains and mountain ranges.

What are continental plates?

Tectonic plates are pieces of the crust of the earth and the uppermost mantle, together referred to as the lithosphere. The plates are around 100 km thick and consist of two types of material: oceanic crust and continental crust which generally have silicon and aluminum.

When two continental plates collide, the edge of one plate is thrust onto that of the other plate. The rocks in the lower slab undergo changes in their mineral content due to heat and pressure and will probably become exposed at the surface.

Rocks changed to new mineral assemblages due to changing temperatures and pressures are known as metamorphic. The regions of the crust undergo melting and subsequent extrusion of melt magma appears at the surface as volcanic rocks that rise to form granites at high crustal levels lead to the formation of mountains.

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A motorcycle is traveling along a highway at 26 m/s. How far does the motorcycle travel in 15 s?​

Answers

26 m/s for fifteen seconds. distance = rate times time, so distance = 26 m/s * 15 seconds. this gives you distance = 390 meters.

The total distance travelled will be 390 m.

We have a motorcycle travelling on a Highway.

We have to find the distance travelled by the motorcycle in 15 seconds.

What is distance ?

The distance covered by the body moving with speed 's' in time 't' is given by the relation -

Distance (d) = s x t

According to the question -

Average speed = s = 26 m/s

Time = t = 15 s

Distance = s x t = 26 x 15 = 390 m

Therefore, the total distance travelled will be 390 m.

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A ball is being thrown straight upward and rises to a maximum height of 12.0m above its launch point. At what height above it’s launch point has the speed of the ball decreased to one-half of its initial value

Answers

Final answer:

To determine the height at which the speed of the ball decreases to one-half of its initial value, we need to consider the vertical motion of the ball. By finding the time it takes for the ball to reach its maximum height and the time it takes for the speed to decrease on its way down, we can calculate the height above the launch point.

Explanation:

The question is asking at what height above its launch point the speed of the ball decreases to one-half of its initial value. To determine this, we need to consider the vertical motion of the ball. Let's assume the launch point is at a height of 0 m.

Using the given information, we can find the time it takes for the ball to reach its maximum height using Equation 4.22. Then, we can calculate the time it takes for the speed of the ball to decrease to one-half of its initial value by finding the time it takes for the ball to reach the same height on its way down.

By considering the time it takes for the ball to reach its maximum height and the time it takes for the speed to decrease, we can determine the height above the launch point at which the speed is one-half of its initial value.

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Two golf balls with the same mass were hit at the same time. Golf ball A went a shorter distance than golf ball B. What could be a reason that this happened?

Golf ball B experienced more friction.
Golf ball A experienced less friction.
Golf ball B was hit with a weaker force.
Golf ball A was hit with a weaker force.

Answers

Answer:

Golf ball A was hit with a weaker force

Explanation:

Golf ball B went a larger distance than golf ball A, so we could think friction affected golf ball A rather than golf ball B. That is why the first two choices are wrong.

The strongest forced applied made golf ball B go further.

Golf ball A went a shorter distance than golf ball B because Golf ball A was hit with a weaker force. Therefore, option D is correct.

What is acceleration?

The rate of change of an object's velocity with respect to time is known as acceleration. The acceleration exhibits both magnitude and direction so it is a vector.

The second derivative of position w.r.t. time can be used to calculate the acceleration and the 1st derivative of the object's velocity w.r.t. time.

The net of all external forces acting in magnitude is directly proportional to this net resulting force. The magnitude of the acceleration is inversely proportional to the object's mass. From Newton's second law of motion we can deduce the acceleration:

F = ma   ⇒ a = F/m

As both balls have the same mass so the ball hit with lesser force will have less acceleration and cover a shorter distance.

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why is it important for digestive system functions that mucous membranes can secrete and absorb susbstances?

Answers

Answer:

It pushes food through the GI tract. The inside of GI tract is lined with mucous membranes. Mucous membranes are moist tissues that can secrete and absorb substances. The ability to secrete and absorb substances is necessary for the functions of the digestive system.

Explanation:

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Final answer:

Mucous membranes in the digestive system secrete mucus and absorb nutrients, which is vital for its functioning.

Explanation:

The mucous membranes lining the digestive system have the ability to secrete and absorb substances, which is important for the functioning of the digestive system.

They secrete mucus that lubricates and protects the digestive tract, preventing damage from harsh stomach acids and facilitating the smooth movement of food.

They also absorb nutrients and water from the digested food, allowing the body to efficiently extract energy and essential substances.

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4. A ball has 17J of kinetic energy (KE) and its mechanical energy is 25J. What is the speed of the
ball? The ball has a mass of 3.2 kg.

Answers

Answer:3.25914099112

Explanation:

Do you have the formula? I pretty sure this is correct but I’m not sure

Speed of ball is 3.2 m/s (Approx.)

Given that;

Kinetic energy (KE) = 17 J

Mechanical energy = 25 J

Mass of ball = 3.2 kg

Find:

Speed of ball

Computation:

Kinetic energy (KE) = [1/2][mv²]

17 = [1/2][(3.2)v²]

17 = [1.6][v²]

v² = 17 / 1.6

v² = 10.625

v = √10.625

v = 3.2596

Speed of ball (v) = 3.2 m/s (Approx.)

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What is the mass of a baseball thrown at 25 m/s resulting in a momentum of 10 kg·m/s?

Answers

Answer: m = 0.4 kg

Explanation: Momentum is the product of mass and velocity also expressed in this equation:

p = m x v

Derive to find m

m = p / v

= 10 kg•m/s / 25 m/s

= 0.4 kg

The mass of baseball is 0.4 kg.

Given data:

The velocity of the baseball is, v = 25 m/s.

The resulting momentum of baseball is, p = 10 kg-m/s.

The momentum of any object is defined as the impact produced by the applied force. Hence it is expressed at the product of mass and velocity. The expression for the momentum is,

[tex]p = mv[/tex]

here, m is the mass of baseball.

Solving as,

[tex]10 = m \times 25\\\\m = 0.4 \;\rm kg[/tex]

Thus, we can conclude that the mass of baseball is 0.4 kg.

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Which two Bible verses state that Jesus Christ holds together everything in the universe by His power?

John 3:16

Colossians 1:17

Psalm 119:56

Hebrews 13

Answers

Answer:

Colossians 1:17

Explanation:

He is before all things, and in him all things hold together.

Answer:

John 3:16

Colossians 1:17

Explanation:

What does the electron do in an atom?

Answers

Answer:

Electrons are the negatively charged particles of an atom.Together,all of the electrons of a atom create a negitive charge that balances the positive charge of the protons

Explanation:

PLZ HELP ME 3 MIINS 50 POINTS AND BRAINLEIST

Juan uses a lever to lift a rock. He places the rock on the short arm of the lever and pushes down on the other arm of the lever. He applies 30 N of force over a distance of 1 m. The other end of the lever moves in the opposite direction and raises the rock a distance of 0.2 M. What is the weight (force) of the rock
What is the mechanical advantage of the lever in question 1?

Answers

Answer:

I calculated the mechanical advantage. It is in the picture above

but I haven't gotten the weight but I know the general formula of weight 2 be m×g (mass ×gravity) I will get back 2 u once I solve it plz don't be offended and plz Mark me brainliest answer

Final answer:

Juan uses a lever to lift a rock. The weight of the rock can be calculated by multiplying the force applied on the lever arm by the mechanical advantage of the lever. The mechanical advantage is calculated by dividing the length of the effort arm by the length of the resistance arm.

Explanation:

In this question, Juan uses a lever to lift a rock. He applies a force of 30 N over a distance of 1 m on one arm of the lever. The other end of the lever moves in the opposite direction and raises the rock a distance of 0.2 m.

To find the weight (force) of the rock, we can use the principle of moments. The weight of the rock can be calculated by multiplying the force applied on the lever arm by the mechanical advantage of the lever.

The mechanical advantage of a lever is calculated by dividing the length of the effort arm by the length of the resistance arm. In this case, the length of the effort arm is 1 m and the length of the resistance arm is 0.2 m, so the mechanical advantage is 1/0.2 = 5.

Therefore, the weight of the rock is 30 N * 5 = 150 N.

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Heated air moves from baseboard heaters to the rest of a room in a process called a radiation b conduction c insulation d convection

Answers

D. convection

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if a mint is on a turn table that is rotating at 34 RPM’s, and is 23 (cm) away from the center of the record, what is the Tangential Acceleration?

Answers

Answer:

The tangential acceleration is zero

Explanation:

Tangential Acceleration

It's a measure of how fast is the tangential velocity changing when the object has rotational motion. It's perpendicular to the centripetal acceleration and equal to the product of the angular acceleration by the radius of rotation. In a uniform circular motion, the angular speed is constant, i.e. the angular acceleration is zero.

If the tangential acceleration was different from zero, the rotating object would change its angular and tangential velocities.

The turntable is rotating at a constant speed, so, regardless of the position of the mint, its tangential acceleration is zero

Picture attached please help! 2 different questions!

Answers

Wave A would have higher amplitude

Hope this helps :D

Wave A has higher amplitude because it is stretched out and the energy of the sound wave is loud

P.S. hope this is helpful

Explanation:

A new ride being built at an amusement park includes a vertical drop of 71.6 meters. Starting from rest the ride vertically drops that distance before the track curves forward. If the velocity at the bottom of the drop is 10.0 m/s and the mass of the cart and passengers is 3,5x10^4kg, how much potential energy was converted into thermal energy? 2.3x10^7, 2.6x10^7, 4.3x107, 6.7x10^7

Answers

Answer:

We can conclude 2.3x10^7 J was converted to thermal energy

Explanation:

Energy Conservation

According to the law of conservation of energy, the total energy of an isolated system must be constant. If some kind of energy is 'lost', we know it was transformed into another type.

Let's check the conditions of the problem. The ride vertically drops a distance of 71.6 m starting from rest, and at the bottom of the drop, its speed is 10 m/s. Knowing the mass of the cart plus passengers is 3.5X10^4 kg, we compute the total energy at the top of the drop.

[tex]E=U+K[/tex]

Where E is the total energy (which must be conserved) at the top of the drop, U is the gravitational potential energy and K is the kinetic energy. We use the equations for each:

[tex]U=m.g.h[/tex]

[tex]\displaystyle K=\frac{mv^2}{2}[/tex]

[tex]\displaystyle E=m.g.h+\frac{mv^2}{2}[/tex]

At the top, the speed is 0, thus

[tex]\displaystyle E=m.g.h=(35000)(9.8)(71.6)=2.5X10^7\ J[/tex]

Now we compute the 'total' energy at the bottom (quoted because we know there is some mechanical energy loss in the drop)

[tex]\displaystyle E'=m.g.h'+\frac{mv'^2}{2}[/tex]

This time h'=0 and v=10 m/s, thus

[tex]\displaystyle E'=\frac{(35000)10^2}{2}=1.8x10^6\ J[/tex]

The mechanical energy at the top and the bottom are not the same, thus we can know part of it was converted to heat or thermal energy. We compute the difference

[tex]2.5x10^7\ J-1.8x10^6\ J=2.3x10^7\ J[/tex]

We can conclude 2.3x10^7 J was converted to thermal energy

Two cans of spam with identical masses collide. Before the collision, the hickory smoke flavor is moving to the left at 4m/s while the hot and spicy flavor is moving to the right at 2 m/s. After the collision, the hickory smoke is moving to the left at 1.2 m/s. What is their final velocity of the hot and spicy? Is this collision elastic?

Answers

1) Final velocity: 0.8 m/s to the left

2) This is not an elastic collision

Explanation:

1)

We can solve this problem by applying the law of conservation of momentum: in fact, if there are no external forces, the total momentum of the two cans must be conserved before and after the collision.

Mathematically:

[tex]p_i = p_f\\mu_1 + mu_2 = mv_1 + mv_2[/tex]  

where:  

m is the mass of each can

[tex]u_1 = -4 m/s[/tex] is the initial velocity of the first can (we take to the left as negative direction)

[tex]u_2 = 2 m/s[/tex] is the initial velocity of the second can (to the right, positive)

[tex]v_1 = -1.2 m/s[/tex] is the final velocity of the first can (the hickory one)

[tex]v_2[/tex] is the final velocity of the 2nd can (the hot and spicy one)

Re-arranging the equation and solving for v2, we find:  

[tex]v_2 = u_1 + u_2 - v_1 = (-4) + (+2) - (-1.2)=-0.8 m/s[/tex]

So, the final velocity of the hot and spicy can is 0.8 m/s to the left.

2)

There are two types of collisions in physics:

Elastic collision: the total kinetic energy is conservedInelastic  collision: the total kinetic energy is not conserved

In order to check if this collision is elastic or not, we need to compare the kinetic energy before the collision to the kinetic energy after the collision.

Before the collision:

[tex]K_i = \frac{1}{2}mu_1^2 + \frac{1}{2}mu_2^2 = \frac{1}{2}m(-4)^2+\frac{1}{2}m(2)^2=10m[/tex]

After the collision:

[tex]K_f = \frac{1}{2}mv_1^2 + \frac{1}{2}mv_2^2 = \frac{1}{2}m(-1.2)^2+\frac{1}{2}m(-0.8)^2=1.04m[/tex]

We see that the final kinetic energy is less than the initial kinetic energy: part of the kinetic energy has been converted into other forms of energy during the collision, therefore this is NOT an elastic collision.

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A test taker makes an estimate for a 30–second time interval. The estimate is 34.5 seconds. What is the percent error in this example?

Answers

Answer:

Its a 30 second interval

Explanation:

Sally and Conrad were arguing over the difference between a transverse wave and a longitudinal wave. Sally said that mechanical waves could be either transverse or longitudinal. Conrad said that sound waves were longitudinal and not transverse. Who is correct and why?
Group of answer choices

Neither are correct.

Only Conrad is correct because sound waves are not transverse waves.

Only Sally is correct because longitudinal waves and transverse waves are mechanical waves.

Both are correct since sound waves are mechanical waves.

Answers

Both are correct since sound waves are mechanical waves.

Option: D.

Explanation:

A wave is a recurring event that transfers energy through vibrations. It caused by the disturbance movement in a medium. The medium can be solid, liquid or gas and it can come in many forms and shapes.  

If the particles in the medium moved in the perpendicular direction to the wave is called transverse wave and if those particles moved in the parallel direction to the wave then it is a longitudinal wave.

Mechanical waves require a medium to transfer that energy. Moreover, based on the medium properties ( inertial and elastic) it can be changed as either transverse or longitude.  

In, sound wave the particles will move in the parallel direction to the wave. Also, it comes under mechanical wave since it requires an air medium to travel.  

describe in detail and example of a character from a television program movie or book you have recently read that is faced with physical needs in the plot please provide the name of the character what book movie or television program you saw them in and describe the context of the situation

Answers

Explanation:

I have watched "Sherlock Holmes". It is a story chain of various deeds of a British detective. He uses his senses with full confidence in order to solve various puzzles. He uses detailed observation of any incident or any character.

He collects information from his logic and creates his own story which seems to be fit in given circumstances. He uses deductive reasoning in order to reach to a conclusion. There are various scenes in this whole series where he can tell the whole schedule of a person just simply observing his/her coat.

I remember a scene in which a person comes to him. He just looks at him for few seconds. Sherlock notices tea stain on his coat. In the very next minute, Sherlock asks him, how bad was his morning? The person gets confused and surprised also.

He asks the reason behind Sherlock's question. Sherlock tells him a story based on his deductive reasoning. He tells him about the noticing of tea stain. He also explains size and configuration of that stain. He also elaborates that such dimensions can be obtained only in a fast moving object when someone has fight at the same time.

He also tells him some other details. All these were based on his extreme senses and his detailed perceptions about the circumstances. Sherlock considers his perceptions as real and tests them according to his knowledge and logical reasoning. He mixes all these things with his deductive reasoning which provides him a meaningful story.

A monkey running through the jungle goes 0.198 km straight to the East, then turns 15.8° deflection from straight East toward the South, and then goes 145 m in a straight line in the diagonal direction he is now facing. What is the displacement of the monkey? (put your answer in standard units)

Answers

Answer:

[tex]|\vec r|=339.82\ m[/tex]

[tex]\theta=-6.67^o[/tex]

Explanation:

Displacement

It's a vector magnitude that measures the space traveled by a particle between an initial and a final position. The total displacement can be obtained by adding the vectors of each individual displacement. In the case of two displacements:

[tex]\vec r=\vec r_1+\vec r_2[/tex]

Given a vector as its polar coordinates (r,\theta), the corresponding rectangular coordinates are computed with

[tex]x=rcos\theta[/tex]

[tex]y=rsin\theta[/tex]

And the vector is expressed as

[tex]\vec z=<x,y>=<rcos\theta,rsin\theta>[/tex]

The monkey first makes a displacement given by (0.198 km,0°). The angle is 0 because it goes to the East, the zero-reference for angles. Thus the first displacement is

[tex]\vec r_1=<0.198cos0^o,0.198sin0^o>=<0.198,0>\ km=<198,0>\ m[/tex]

The second move is (145 m , -15.8°). The angle is negative because it points South of East. The second displacement is

[tex]\vec r_2=<145cos(-15.8^o),145sin(-15.8^o)>=<139.52,-39.48>\ m[/tex]

The total displacement is

[tex]\vec r=<198,0>\ m+<139.52,-39.48>\ m[/tex]

[tex]\vec r=<337.52,-39.48>\ m[/tex]

In (magnitude,angle) form:

[tex]|\vec r|=\sqrt{337.52^2+(-39.48)^2}=339.82\ m[/tex]

[tex]\boxed{|\vec r|=339.82\ m}[/tex]

[tex]\displaystyle tan\theta=\frac{-39.48}{337.52}=-0.1169[/tex]

[tex]\boxed{\theta=-6.67^o}[/tex]

What is the fuel of an aeroplane.?

Answers

Answer:  Jet fuel

Explanation:

Jet fuel is a clear to straw-colored fuel, based on either an unleaded kerosene (Jet A-1), or a naphtha-kerosene blend (Jet B). Similar to diesel fuel, it can be used in either compression ignition engines or turbine engines.

Answer:

the fuel of an aeroplane is called gasoline

In which situation is no work considered to be done by a force?
OA when the angle between the force and displacement is 180°
O B. when the angle between the force and displacement is 90°
Oc when the angle between the force and displacement is 45°
OD. when the angle between the force and displacement is 0°

Answers

Answer:

O B. when the angle between the force and displacement is 90°

Explanation:

work defined as   [tex]w = f cos Ф * d[/tex]. work  can only be done if object moves(displacement) in the direction of force. now a quick one. if you since the varrious angles into the cosine, you would see that Cos 90 will give zero which implies that no work is done. Again, angle means it is perpendicular and so it is not in the direction of force.
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