20 PTS!!!David's company reimburses his expenses on food, lodging, and conveyance during business trips. The company pays $60 a day for food and lodging and $0.65 for each mile traveled. David drove 600 miles and was reimbursed $3,390. Part A: Create an equation that will determine the number of days on the trip. (3 points) Part B: Solve this equation justifying each step with an algebraic property of equality. (6 points) Part C: How many days did David spend on this trip? (1 point)

Answers

Answer 1
Part A)

$60 for each day of the trip (d) + $0.65 * the number of miles (600 mi) = the total cost ($3390):

[tex]60d + 390 = 3390[/tex]

Part B)

[tex]60d + 390 = 3390[/tex] (Given equation)
[tex]60d + 390 - 390 = 3390 - 390[/tex] (Subtraction property of Inequalities)
[tex]60d = 3000[/tex] (Simplification)
[tex]\frac{60d}{60} = \frac{3000}{60}[/tex] (Division property of inequalities)
[tex]d = 50[/tex] (Simplification)

Part C)

David spent 50 days on his trip.
Answer 2

Answer:

The company pays $60 a day for food and lodging and $0.65 for each mile traveled.

David drove 600 miles and was reimbursed $3,390.

Part A:

Let the number of days of trip be = x

Equation forms:

[tex]600(0.65)+60x=3390[/tex]

=> [tex]390+60x=3390[/tex]      .......(1)

Part B:

Solving (1) for x.

[tex]390+60x=3390[/tex]     (given)

Applying subtraction property of equality;

[tex]60x+390-390=3390-390[/tex]

Now simplifying this we get;

[tex]60x=3000[/tex]

Applying division property by dividing 60 on both sides, we get

x = 50

Part C:

We get x = 50, so David spent 50 days on the trip.


Related Questions

Jack was 11 years older than Pricilla. Together their ages totaled 151 years.what are their ages?

Answers

151 - 11 = 140
140 ÷ 2 = 70

70 + 11 = 81

Jack is 81 years old.
Pricilla is 70 years old.

Davis Construction is building a new housing development. They begin by mapping the development out on a coordinate grid. They place one of the two swimming pools at (-4, -1) and another at (6, 3). If they want the clubhouse to be exactly halfway between the two pools, find the coordinates of the clubhouse.

Answers

[tex]\bf \textit{middle point of 2 points }\\ \quad \\ \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) &({{ -4}}\quad ,&{{ -1}})\quad % (c,d) &({{ 6}}\quad ,&{{ 3}}) \end{array}\qquad % coordinates of midpoint \left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right) \\\\\\ \left(\cfrac{{{ 6}} -4}{2}\quad ,\quad \cfrac{3-1}{2} \right)[/tex]

what is the equation to solve it

Answers

which equation has to be solved
Please ask your question

6/5 × 25/24 multiple

Answers

6/5 × 25/24
= 5/4

hope it helps

It takes 8 minutes for Byron to fill the kiddie pool in the backyard using only a handheld hose. When his younger sister is impatient, Byron also uses the lawn sprinkler to add water to the pool so it is filled more quickly. If the hose and sprinkler are used together, it takes 5 minutes to fill the pool. Which equation can be used to determine r, the rate in parts per minute, at which the lawn sprinkler would fill the pool if used alone?
 + 5r = 8
 + 5r = 1
5() = r 
 = 5r

Answers

Let us say that the procedure of completely filling up the pool with water is called “1 job”. Therefore the rates of the equipment in doing the job would be:

Rate of handheld hose = 1 job / 8 minutes                  ---> 1

Rate of lawn sprinkler = r                                             ---> 2

Rate of the two combines = 1 job/ 5 minutes               ---> 3

So we are to find the equation to use, in this case, we simply have to add equations 1 and 2 to get 3:

1 / 8 + r = 1 / 5

Multiplying both sides by 5:

(5 / 8) + 5 r = 1                                                               ---> ANSWER

Answer:

5/8 + 5r = 1

Step-by-step explanation:

Right on edge!

Use a triple integral to find the volume of the given solid. the solid enclosed by the cylinder x2 + y2 = 9 and the planes y + z = 14 and z = 2.

Answers

Using cylindrical coordinates, we have

[tex]\begin{cases}x=r\cos\theta\\y=r\sin\theta\\z=\zeta\end{cases}[/tex]

so that the Jacobian gives

[tex]\mathrm dV=\mathrm dx\,\mathrm dy\,\mathrm dz=r\,\mathrm dr\,\mathrm d\theta\,\mathrm d\zeta[/tex]

The volume is given by the triple integral

[tex]\displaystyle\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=3}\int_{\zeta=2}^{\zeta=14-r\sin\theta}r\,\mathrm d\zeta\,\mathrm dr\,\mathrm d\theta[/tex]
[tex]=\displaystyle\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=3}r(14-r\sin\theta-2)\,\mathrm dr\,\mathrm d\theta[/tex]
[tex]=\displaystyle\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=3}(12r-r^2\sin\theta)\,\mathrm dr\,\mathrm d\theta[/tex]
[tex]=\displaystyle\int_{\theta=0}^{\theta=2\pi}(54-9\sin\theta)\,\mathrm d\theta[/tex]
[tex]=108\pi[/tex]
Final answer:

To find the volume of the solid enclosed by the given cylinder and planes, you convert to cylindrical coordinates. Then, you set up a triple integral with respect to these coordinates as ∫∫∫ dz dr dθ where the bounds of integration are 0<=θ<=2π, 0<=r<=3, and 2<=z<=14-r.

Explanation:

The volume of the solid can be found using a triple integral in cylindrical coordinates. First, we need to identify the boundaries of the solid. From the cylinder equation, we see that x² + y² = 9, which in cylindrical coordinates converts to r^2 = 9, so 0<=r<=3. Then, from the plane equations y + z = 14 and z=2, we can determine that in cylindrical coordinates, 2<=z<=14-r.

Therefore, the volume V can be found by:

V = ∫∫∫ dz dr dθ

with bounds for integration being 0<=θ<=2π, 0<=r<=3, and 2<=z<=14-r.

Running this triple integral will provide the volume of the solid.

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-7=7d-8

help me with the equation for that problem

Answers

Hello there! Thanks for asking your question here at Brainly. I will be assisting you in answering your question here today.

Let's take a look at our problem:
-7 = 7d - 8

To solve for this, we need to isolate the variable and then simplify if needed.
To clarify, the variable is (usually) a letter that represents a constant value. Our variable is "d".

-7 = 7d - 8
Isolate 7d by adding 8 to both sides.
-7 + 8 = 1

We're now left with:
1 = 7d

To solve for d, divide both sides by 7.
1 / 7 = 1/7
7d / 7 = d

We are now left with the solution:
d = 1/7

I hope this helps!

the following data values represents a population. What is the variance of the values? 6, 10, 14, 2

Answers

first we find the mean (average)
(6 + 10 + 14 + 2) / 4 = 32/4 = 8

now subtract the mean value from every data value....and square it.
6 - 8 = -2....-2^2 = 4
10 - 8 = 2....2^2 = 4
14 - 8 = 6...6^2 = 36
2 - 8 = -6...-6^2 = 36

now find the mean of those numbers
(4 + 4 + 36 + 36) / 4 = 80/4 = 20 <== ur variance

Answer:20 !

Step-by-step explanation:

Problem Page
Lucy's shop sells
712
quarts of ice cream each day. How much is this in pints?
Write your answer as a whole number or a mixed number in simplest form. Include the correct unit in your answer.

Answers

Because there are 2 pints in a quart, 712 quarts would equal 1,424 pints.

A forest ranger can see for a distance of 12 miles from a firetower how many square miles can he observe?

Answers

using 3.14 for pi

area = pi x r^2

 since he can see 12 miles in any direction 12 would be the radius

 so 3.14 x 12^2 = 452.16 square miles

 round the answer as needed.

why you delete my answer? it obviously was a legitamant answer.

One bag of Glizard wood chips covers a 215 square foot area. How many total bags of wood chips must be purchased to cover an area that is 42 feet by 61 feet?

Answers

42 x 61 = 2562

2562/215 = 11.92


 12 total bags are needed

A set of data with a mean of 62 and a standard deviation of 5.7 is normally distributed. what is the value that is −1 standard deviation from the mean

Answers

Here, the mean is 62 and the std. dev. is 5.7  One standard dev below the mean is thus calculated as 62 - 5.7, or 56.3.  This is equivalent to "the mean less one std. dev.")

A store has a $43.89 item on sale. The total discount of the sale is $9.66. What is the sale percentage off on this item?

Answers

well, if we take 43.89 to be the 100%, what is 9.66 off of it in percentage?

[tex]\bf \begin{array}{ccllll} amount&\%\\ \text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\ 43.89&100\\ 9.66&x \end{array}\implies \cfrac{43.89}{9.66}=\cfrac{100}{x}[/tex]

solve for "x".

$765.13 is deposited at the end of each month for 2 years in an account paying 12% interest compounded monthly. Find the amount of the account. Round your answer to the nearest cent.

Answers

The final amount is = $ 959.779

What is compound interest?

Compound interest is when you earn a hobby on both the cash we've got stored and the hobby we earn.

calculation:-

principal amount = $765.13

rate if interest = 12%

for 1st year:-

interest amount= $765.13*12/100

                            = $ 91.8156

final amount = $765.13 + $ 91.8156

                     = $ 856.9456

for 2nd year:-

principal amount = $ 856.9456

       12% interest on $ 856.9456 = $ 102.833472

final amount = $ 856.9456+$ 102.833472

                      = $ 959.779 answer

                   

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Write the phrase as an algebraic expression 6 less than a number times 11

Answers

6-x•11 is the answer u r looking for

Whats the quotient of 2 1/4 and 5/8

Answers

[tex]\bf 2\frac{1}{4}\implies \cfrac{2\cdot 4+1}{4}\implies \cfrac{9}{4}\\\\ -------------------------------\\\\ \cfrac{9}{4}\div \cfrac{5}{8}\implies \cfrac{9}{4}\cdot \cfrac{8}{5}\implies \cfrac{9\cdot 8}{4\cdot 5}\implies \cfrac{72}{20}\implies \cfrac{18}{5}\implies 3\frac{3}{5}[/tex]

Is 703.005 is greater than or less than seven hundred three and five hundredths

Answers

703.005 is less because .005 is less than .050

the oringinal cost of a lamp is $18.95. the lamp is on sale for 25% off. how much will you pay?

Answers

100% - 25% = 75%

so, if 18.95 is the 100%, how much is the 75% of that?

[tex]\bf \begin{array}{ccllll} amount&\%\\ \text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\ 18.95&100\\ x&75 \end{array}\implies \cfrac{18.95}{x}=\cfrac{100}{75}[/tex]

solve for "x".

What is the simplified form of the expression? (2 – 9c)(–8)

Answers

I am pretty sure this is what you are looking for:
You have to use the distributive property i am pretty sure
Distribute -8 to both 2 and -9c
-16+72c
hope this helps:)
please mark thanks and brainliest:)
Just distribute the -8 across the 2 and -9c.

(2 - 9c)(-8) = -16 + 72c

So, -16 + 72c is the answer.

In a certain town 22 of voters favor a given ballot measure for groups of 21 voters find the variance for the number who favor the measure

Answers

What is the equation.

Answer:

4.6

Step-by-step explanation:

Allow me to revise your question and hope it will be the same as the original one:

In a certain town 22% of voters favor a given ballot measure for groups of 21 voters find the variance for the number who favor the measure

a. 1.9

b. 13

c. 4.6

d. 3.6

Here is my answer:

Given:

22% of voters favor a given ballot = 0.22 Groups of 21 voters

So the variance is: 21*0.22 = 4.6

We choose B

eliminate the parameter. x = 5 cos t, y = 5 sin t help please!

Answers

[tex]\bf \begin{cases} x=5cos(t)\implies \cfrac{x}{5}=cos(t)\\\\ y=5sin(t)\implies \cfrac{y}{5}=sin(t) \end{cases} \\\\\\ \textit{now, recall that }sin^2(\theta)+cos^2(\theta)=1\qquad thus \\\\\\ \left( \cfrac{x}{5} \right)^2+\left( \cfrac{y}{5} \right)^2=1\implies \cfrac{x^2}{5^2}+\cfrac{y^2}{5^2}=1\implies \cfrac{x^2+y^2}{25}=1 \\\\\\ x^2+y^2=25\implies x^2+y^2=5^2\impliedby \textit{which is just a circle}[/tex]

Final answer:

To eliminate the parameter 't' from the equations x = 5 cos t and y = 5 sin t, use the Pythagorean identity which leads to the non-parametric equation of a circle: x^2 + y^2 = 25.

Explanation:

To eliminate the parameter 't' from the parametric equations x = 5 cos t, y = 5 sin t, we can use the Pythagorean identity sin^2(t) + cos^2(t) = 1. Plugging in the given expressions for x and y:

(x/5) = cos(t)

(y/5) = sin(t)

We can square both sides of these equations and then add them together:

(x/5)^2 + (y/5)^2 = cos^2(t) + sin^2(t)

As cos^2(t) + sin^2(t) equals 1, the equation simplifies to:

(x/5)^2 + (y/5)^2 = 1

Thus, the eliminated parameter equation representing the same curve without the parameter 't' is:

x^2 + y^2 = 25

This is the equation of a circle with a radius of 5, centered at the origin.

What percent of 645 is 187.05?

Answers

Percent means per one hundred...

645(p/100)=187.05

645p/100=187.05

645p=18705

p=18705/645

p=29%

To find what percent 187.05 is of 645, one can use the following formula:

[tex]\[ \text{Percentage} = \left( \frac{\text{Part}}{\text{Whole}} \right) \times 100 \][/tex]

In this case, the Part is 187.05 and the Whole is 645. Plugging these values into the formula gives:

[tex]\[ \text{Percentage} = \left( \frac{187.05}{645} \right) \times 100 \][/tex]

Now, calculate the fraction:

[tex]\[ \text{Percentage} = \left( \frac{187.05}{645} \right) \times 100 = \left( 0.29155 \right) \times 100 \][/tex]

[tex]\[ \text{Percentage} = 29.155 \][/tex]

Therefore, 187.05 is approximately 29.155% of 645. To express this as a fraction, one can write:

[tex]\[ \text{Percentage} = \frac{187.05}{645} \times 100 = \frac{18705}{645} \approx 29.155\% \][/tex]

To get the exact fraction, we can simplify:

[tex]\[ \text{Percentage} = \frac{187.05}{645} \times 100 = \frac{18705}{645} \times \frac{20}{20} = \frac{374100}{12900} \][/tex]

Simplifying the fraction by dividing both the numerator and the denominator by their greatest common divisor, which is 300, we get:

[tex]\[ \text{Percentage} = \frac{374100 \div 300}{12900 \div 300} = \frac{1247}{430} \][/tex]

So, the exact fraction representing the percentage is:

[tex]\[ \text{Percentage} = \frac{1247}{430} \times 100 \][/tex]

[tex]\[ \text{Percentage} = \frac{1247}{4.3} \][/tex]

[tex]\[ \text{Percentage} = 29.00 \% \][/tex]

Thus, 187.05 is exactly 29% of 645.

If (h, •) and (k, •) are subgroups of (g, •), prove that (h n k, •) is a subgroup of (g, •). can the same be said for the union, hu k? prove or give a counterexample.

Answers

Let [tex]\eta\in H\cap K[/tex]. Since both [tex]H[/tex] and [tex]K[/tex] are subgroups of [tex]G[/tex], we have

[tex]\eta\in H\cap K\implies\begin{cases}\eta\in H\\\eta\in K\end{cases}\implies\eta\in G[/tex]

Because both [tex]H,K[/tex] are subgroups of [tex]G[/tex], then [tex](H\cap K,\bullet)[/tex] contains the identity element [tex]e[/tex]. Furthermore, there must be some element [tex]\eta^{-1}\in H[/tex] and [tex]\eta^{-1}\in K[/tex], i.e. [tex]\eta^{-1}\in H\cap K[/tex], such that [tex]\eta\bullet\eta^{-1}=e[/tex].

Now let [tex]\eta_1,\eta_2,\eta_3\in H\cap K[/tex]. By the same reasoning as above it follows that each of these belong in [tex]G[/tex], and since [tex](G,\bullet)[/tex] is a group, we have [tex]\eta_1\bullet(\eta_2\bullet\eta_3)=(\eta_1\bullet\eta_2)\bullet\eta_3[/tex], so [tex]H\cap K[/tex] is associative under [tex]\bullet[/tex].

So [tex]H\cap K[/tex] contains the identity, is closed with respect to inverses, and is associative under [tex]\bullet[/tex]. Therefore [tex]H\cap K[/tex] must be a subgroup of [tex]G[/tex].

In the case of union, this is not always the case. Consider the group [tex](\mathbb Z,+)[/tex] with subgroups [tex](H,+)[/tex] and [tex](K,+)[/tex] where [tex]H[/tex] is the set of all integer multiples of 2 and [tex]K[/tex] is the set of all integer multiples of 3.

It's easy to show that [tex]H[/tex] and [tex]K[/tex] are indeed subgroups, but this is not the case for [tex]H\cup K[/tex]. We have

[tex]H\cup K=\{0,\pm2,\pm4,\ldots\}\cup\{0,\pm3,\pm6,\ldots\}[/tex]

Take the elements [tex]2\in H[/tex] and [tex]3\in K[/tex]. Addition yields [tex]2+3=5[/tex], but [tex]5\not\in H\cup K[/tex], so [tex]H\cup K[/tex] is not closed under [tex]+[/tex].

find cosx if tanx cscx=2

A)2
B)square root 2
C)square root 2/2
D)1/2

Answers

DDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDD
↓↓↓↓↓↓↓

The value of cosx if "tanx cscx = 2" is 1/2. The correct option is D)1/2

What is Trigonometry?

From the question, we are to determine the value of cosx

From the given information,

tanx cscx=2

Recall that,

[tex]tan(x )= \frac{sin (x)}{cos(x)}[/tex]

and

[tex]csc(x) = \frac{1}{sin(x)}[/tex]

Then,

Substitute these values into the given equation

tanx cscx = 2 becomes

[tex]\frac{sin (x)}{cos(x)} \times \frac{1}{sin(x)} = 2[/tex]

[tex]\frac{1}{cos(x)} = 2[/tex]

∴ [tex]cos(x) = \frac{1}{2}[/tex]

Hence, the value of cosx if "tanx cscx = 2" is 1/2. The correct option is D)1/2

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A mountaineer climbed 1,000 feet at a rate of x feet per hour. He climbed an additional 5,000 feet at a different rate. This rate was 10 feet per hour less than twice the first rate. Which expression represents the number of hours the mountaineer climbed

Answers

Your question asks for an expression, so you would expect an answer in the form of an equation containing variables. This is because you have only 2 independent equations with 3 unknowns. That makes the system unsolvable. 

Suppose v₁ is the mountaineer's velocity during the 1,000-foot trail. Then, v₂ is his speed for the 5,000-foot trail. The equation relating these two variables is:

v₂ = 2v₁ - 10 ---> equation 1

Then, you find the equation for the total number of hours he climbed. That would be the distance divided by their respective speed.

t = 1000/v₁ + 5000/v₂ ----> equation 2

Substituting equation 1 to equation 2,

t = 1000/v₁ + 5000/(2v₁ - 10)
t = 1000/v₁ + 5000/2(v₁-5)
t = 1,000/v₁ + 2,500/(v₁-5) 

The equation that represents the number of hours the mountaineer climbed is t = 1000/V1 + 2600(V1 - 5).

How to compute the equation?

Based on the information given, V1 = 1000 and V2 = 2V1 - 10.

The time taken will be:

= 1000/V1 + 5000/V2

Well substitute the equations. This will be:

t = 1000/V1 + 5000//(2V1 - 10)

t = 1000/V1 + 5000/2(V1 - 5)

t = 1000/V1 + 2600(V1 - 5).

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Solve the following inequality: 2(x + 1) – (–x + 5) ≤ –18. A. x ≤ –9 B. x ≤ –20 C. x ≤ –37 D. x ≤ –5

Answers

2(x + 1) - (-x + 5) < = -18
2x + 2 + x - 5 < = -18
3x - 3 < = -18
3x < = -18 + 3
3x < = -15
x < = -15/3
x < = - 5 <==

Answer:

Solve the following inequality: 2(x + 1) – (–x + 5) ≤ –18. A. x ≤ –9 B. x ≤ –20 C. x ≤ –37 D. x ≤ –5

Step-by-step explanation:

2 (x + 1) - (-x + 5) ≤ -18

2x + 2 + x - 5 ≤ - 18

3x - 3 ≤ - 18

3x ≤ - 15

x ≤ - 15/3 ≤ - 5

The answer is: D. x ≤ - 5

A flat rectangular piece of aluminum has a perimeter of 66 inches. The length is 15 inches longer than the width. Find the width.

Answers

x is the length
y is the width
2x+2y=66
x-y=15
multiply the second equation by 2 (elimination)
2x-2y=30
add the equations together
4x=96
x=24
Plug this in to one of the original equations
24-y=15
the width is 9

For what values of b will f(x)= log b^x be an increasing function?

Answers

[tex]log(b^x) = xlog(b)[/tex]

This is basically a line with slope [tex]log(b)[/tex]

For this to be an increasing function, the slope has to be greater than 0.

[tex]log(b) \ \textgreater \ 0\\ b \ \textgreater \ 10^0\\ b \ \textgreater \ 1[/tex]

So f(x) will be an increasing function for all b > 1

Using logarithmic function concepts, it is found that for values of b > 1, [tex]f(x) = \log_b{x}[/tex] will be an increasing function.

What is an logarithmic function?

A logarithmic function is modeled by:

[tex]f(x) = \log_b{x}[/tex]

The coefficient b determines the behavior of the function, as follows:

b > 1: The function is increasing.b < 1: The function is decreasing.

Hence, for values of b > 1, [tex]f(x) = \log_b{x}[/tex] will be an increasing function.

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2.8 meters linen divided into 45 cm pieces = # of pieces and waste

Answers

2.8 meter= 2800cms

To solve this, we can create a simple algebraic equation:
45x=2800
Divide both sides by 45.
(45x)/45=(2800)/45
x=62.222

You can make 62 full pieces.

To find the waste, multiply the numbers of pieces by the length of each.
62*45
=2790
2800-2790
=10 centimeters

There would be 10 centimeters of wasted linen.

Hope this helps!
-Benjamin

Given the Arithmetic sequence A1,A2,A3,A4A1,A2,A3,A4
29, 39, 49, 59

What is the value of A33A33?

Answers

The given sequence is
a₁ = 29
a₂ = 39
a₃ = 49
a₄ = 59

This sequence is an arithmetic sequence. Th first term is a₁ = 29, and the common difference is d= 10.

The n-th term is
[tex]a_{n}=a_{1}+(n-1)d[/tex]
The 33-rd termis
a₃₃ = 29 + (33 - 1)*10
     = 29 + 320
     = 349

Answer: a₃₃ = 349
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