The correct answer is: A) acidic, basic.
How might a recent college graduate’s investment portfolio differ from someone who is nearing retirement?
Older people had no money to buy stuff
Answer:
The recent graduate invests taking risks and betting on profitability.
The retired man protects the estate by sacrificing the gain.
Explanation:
In the lab, you are thirsty and would like a drink. Can you use the beaker as a cup?
No you can’t do that, that’s idiotic
what is the ultimate end of a high mass star that has a core about 2.8x the mass of our sun?
A. a pulsar
B. a black hole
C. a brown dwarf
D. a magnetar
Answer:
A
Explanation:
It is formed after the star has ended its star cycle into a supernova. The star collapsed into a neutron star that is smaller than the progenitor star but has inherited angular momentum. IT, therefore, spins faster emitting electromagnetic radiation that seems to pulsate.
Answer:
A) Pulsar
Explanation:
Pulsars are collapsed cores of stars usually supergiant stars
this happens when a supernova leaves behind the star core that has no outer protection layer of high gravity so the core collapses in on itself to create a very high magnitude star and also has trillions more mass.
When a single 1-gram piece of zinc is added to 3 M hydrochloric acid at 25°C, the reaction is slow. Which procedure would most likely increase the rate of the reaction if the reaction were repeated? A. using 1 gram of powdered zinc B. using 1 M hydrochloric acid C. decreasing the temperature to 20.°C D. decreasing the concentration of the zinc
Answer: option A, using 1 gram of powdered zinc.
Explanation:
The rate of chemical reactions are affected by a number of factors, which you can summarize in this form:
1) Concentration of the reactants
The more concentrate are the reactants, more frequently they will interact (collide) and will be able to yield product. So, the higher the concentration the higher the rate.
This means using 1 M hydrochloric acid, as the option B states, instead of 3 M (stated for the original reaction) will slow down the reaction instead of increase the rate.
The same is valid for the option D. Decreasing the concentration of zinc will not increase the rate of the reaction, but will decrease it.
2) Surface area of the reactants
Increasing the surface area will permit that the reactants reach a faster intimate contact, occurring more of collisions per unit of time, and, consequently increasing the rate of the reaction.
Then, option A, using 1 gram of powdered zinc, i.e. the same amount stated for the original reaction, but with more surface area, will produce the desired effect of increasing the rate of reaction.
3) Temperature
Higher temperatures means that the kinetic energies of the reactants are higher and so the collisions will occur with more energy and the probability of effective collisions will increase. Decreasing the temperature will have the opposite effect (the rate of reaction will decrease).
Hence, the option C, decreasing the temperature to 20° C will not increanse the rate of the reaction.
3) Catalyst
Catalyst ares substances that modify the path of the reaction, decreasing the activation energy and, consequently, increasing the rate of reaction. Since, none of the statements indicates the use of catalyst, this is not an option.
The correct option is A. using 1 gram of powdered zinc.
To understand why using powdered zinc would most likely increase the rate of the reaction, one must consider the factors that affect reaction rates. These factors include the concentration of reactants, the surface area of reactants, the temperature at which the reaction occurs, and the presence of a catalyst.
In this case, the reaction between zinc and hydrochloric acid can be represented by the following equation:
[tex]\[ \text{Zn}(s) + 2\text{HCl}(aq) \rightarrow \text{ZnCl}_2(aq) + \text{H}_2(g)[/tex]
Now, let's analyze each option:
A. Using 1 gram of powdered zinc: Increasing the surface area of the zinc by using it in powdered form would increase the number of particles that can react with the hydrochloric acid at any given time. This would increase the rate of the reaction because more collisions between the zinc and hydrochloric acid molecules would occur, leading to a faster reaction rate.
B. Using 1 M hydrochloric acid: Decreasing the concentration of hydrochloric acid from 3 M to 1 M would actually decrease the rate of the reaction. According to the collision theory, a higher concentration of reactants leads to more frequent collisions and thus a faster reaction rate.
C. Decreasing the temperature to 20°C: Generally, decreasing the temperature would decrease the kinetic energy of the particles, leading to fewer successful collisions and a slower reaction rate. The Arrhenius equation shows that the rate constant \(k\) is directly related to the temperature [tex]T[/tex] by the equation [tex](k = A \cdot e^{-\frac{E_a}{RT}}\)[/tex], where [tex]\(A\)[/tex] is the pre-exponential factor, [tex]\(E_a\)[/tex] is the activation energy, and [tex]R[/tex] is the gas constant.
D. Decreasing the concentration of the zinc: This option would decrease the rate of the reaction for the same reason as option B. A lower concentration of zinc would mean fewer zinc particles are available to react with the hydrochloric acid, resulting in a slower reaction rate.
Therefore, the most effective way to increase the rate of the reaction, based on the given options, is to increase the surface area of the zinc by using it in powdered form, which corresponds to option A.
Water contrasts on freezing ?
No. When water first begins to cool down, it contracts. However, as it gets colder and eventually freezes, it begins to expand.
You can test this by freezing water in a water bottle: when you take it out of the freezer, the cap might have popped off or cracks may have formed in the sides of the bottle.
Answer: Water expands when frozen, not contracts.
What is the best description for a solution with a hydroxide-ion concentration equal to 1 x 10-4m?
Answer:
Basic solution.
Explanation:
∵ pOH = -log[OH⁻] = - log(1.0 x 10⁻⁴) = 4.
∵ pH + pOH = 14.
∴ pH = 14 - pOH = 14 - 4 = 10.
Since, the pH of the solution is 10 (> 7) and the concentration of [OH⁻] is 1.0 x 10⁻⁴ (> 1.0 x 10⁻⁷) is a basic solution.
Answer:
The solution is basic
Explanation:
Given:
Concentration of OH- = 1*10⁻⁴ m
To determine:
The nature of the solution i.e. acidic or basic
Formula:
A solution where the pH = 7 is neutral
pH < 7 is acidic
pH > 7 is basic
[tex]p[OH] = -log[OH-] = -log[1*10^{-4}] = 4\\ \\p[H] + p[OH] = 14\\\\Therefore\ pH = 14 - p[OH] = 14 - 4 = 10[/tex]
Since, pH > 7, the solution is basic
Explain where your space mission will take you and why you wish to explore that particular feature of the solar system. List what you hope to learn from your mission. (3 points)
The answer is that you have to write this in your own words.
To help you on how to get started, here's what you need to do:
Just say what planet you want to go and why you want to go there. Then, say what you wish to learn on that planet.
Template: My space mission would be going to planet _______. I would like to go there because ___________________. I hope to learn that ________________.
Our space mission involves studying Mars' geological features and potential for life. This will enhance our understanding of the possibility of life beyond our solar system and specifically detail the environment on Mars. The mission might also reveal evidence of past or present life.
Explanation:Our space mission will aim to explore the unique geological features and potential habitability of Mars. Mars is a planet of particular interest due to evidence suggesting its past was warmer and wetter, hinting at the possibility of life beyond our solar system.
We wish to explore this aspect of the solar system because it could fundamentally alter our understanding of life's existence in the universe. The mission will involve the use of hi-tech equipment to identify potential biomarkers, signs of past or present life.
Through this mission, we hope to learn more about the environment on Mars, detail its capacity for sustaining life, and possibly find evidence of life itself. Our findings will not only influence future Mars missions but also add a significant chapter to our understanding of life in the universe.
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1. Fill one container with very hot water and the other with ice water. 2. Place one end of spoon into the cup with hot water and hold on to the other end with your finger tips. 3. Hold the spoon for a minute or two. What do you feel happening?
The spoon will get warmer as it takes in the heat of the water
Draw the correct structure of the indicated product for each of the following reactions.
To draw the structure of each reaction first determine the product of the reaction and then draw the structure by using the line formula method.
What is a product?In chemistry, the word product refer to the substance or substances after a reaction. For example in the reaction H2+O = H2O, the product is water (H2O).
How to draw the structure of a product?Determine the product: Bear in mind that the product or products have the same atoms and number of atoms as the reactants.Draw the structure: One simple way to do this is by using the line formula method that involves representing carbons with lines and other products along these. Below you find an example.Note: This question is incomplete; due to this, I answered it based on general knowledge.
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what is solubility?
1) solubility is how much solute will precipitate out of solvent
2) solubility is how much solvent will dissolve in solute
3) solubility is how much solid only will dissolve in liquid only
Answer:
The answer is "solubility is how much solvent will dissolve in solute."
Explanation:
Final answer:
Solubility is the amount of solute that can dissolve in a given quantity of solvent at a certain temperature and pressure, resulting in a saturated solution.
Explanation:
Solubility is defined as the maximum amount of a substance (solute) that can dissolve in a given amount of solvent at a specified temperature and pressure, leading to a saturated solution. It is often expressed in grams of solute dissolved in 100 grams of solvent.
The concept of solubility is essential in chemistry as it helps predict the behavior of substances in various environments and is a key factor in reactions like precipitation.
For instance, when a solution's concentration exceeds the substance's solubility, the excess will precipitate out of the solution. Meanwhile, substances with low solubility tend to precipitate readily under most conditions.
The phrase 'like dissolves like' is a useful heuristic that indicates that polar solvents will typically dissolve polar solutes, while nonpolar solvents will dissolve nonpolar solutes. This is key when trying to determine if a solute will be soluble in a given solvent.
The transfer of a phosphate group to a molecule or compound is called
Answer: Phosphorylation
can you mark me as brainiest please?If kb for nx3 is 4.0×10−6, what is the poh of a 0.175 m aqueous solution of nx3?
pOH = 3.08
Explanation;NX3 + H2O <----> NHX3+ + OH-
Kb = 4.0 x 10^-6
Kb = c(NH₄⁺) · c(OH⁻) ÷ c(NH₃).
c(NH₄⁺) = c(OH⁻) = x.
x² = Kb · c(NH₃)
x² = 4.0 × 10⁻⁶ × 0.175 = 7.0 × 10⁻⁷.
x = c(OH⁻) = √(7.0 × 10⁻⁷)
= 8.367 × 10⁻⁴
pOH = -log(c(OH⁻))
=- log ( 8.367 × 10⁻⁴)
= 3.08
Final answer:
To calculate the pOH of a 0.175 M aqueous solution of NX₃ with Kb of 4.0×10⁻⁶, we simplify the dissociation equation and find the OH- concentration to be approximately 1.67×10⁻³ M, resulting in a pOH of about 2.78.
Explanation:
To find the pOH of a 0.175 M aqueous solution of NX₃, given that Kb for NX3 is 4.0×10⁻⁶, we start by setting up the base dissociation reaction NX₃ + H₂O → NX₃H+ + OH−. The equilibrium expression associated with this dissociation is Kb = [NX3H+][OH−]/[NX3]. We can assume the concentrations of NX₃H+ and OH− to be equal (x) and much smaller than the initial concentration of NX₃, thus [NX₃] approximately equals 0.175 M. With these assumptions, Kb can be rewritten as 4.0×10⁻⁶ = x₂ / (0.175 − x).
Assuming x is much smaller than 0.175, we simplify to 4.0×10⁻⁶ ≈ x2 / 0.175. Solving for x gives us x ≈ √(4.0×10⁻⁶ ∗ 0.175) ≈ 1.67×10⁻³ M, which is the concentration of OH−. The pOH is calculated using the formula pOH = −log[OH−], resulting in pOH ≈ 2.78.
A solution of SO2 in water contains 0.00023 g of SO2 per liter of solution. What is the concentration of SO2 in ppm? in ppb?
Answer:
= 230 ppb
Explanation:
Considering that;
1ppm = 1mg/L
Then;
0.00023g = 0.23mg
Therefore;
0.00023 g/L = 0.23 mg/L
0.23 mg/L = 0.23 ppm
1 ppm = 100 ppb
Therefore;
0.23 ppm = 0.23 ×1000
= 230 ppb
Answer:
0.23 ppm , 230 ppb
Explanation:
1 ppm (parts per million) is equivalent to 1 mg of SO₂ in 1 L of the water
Given mass of SO₂ = 0.00023 g = 0.00023 x 1000 mg (1g = 1000 mg) = 0.23 mg
So 0.23 mg/ L = 0.23 ppm
1 ppb (parts per billion) (10⁹) = 1000 ppm (parts per million) (10⁶)
0.23 ppm x 1000 = 230 ppb
What type of reaction is the digestion of solid copper wire by nitric acid?
Copper nitrate and nitric oxide are produced in this reaction.
The digestion of copper wire by nitric acid is a redox reaction producing copper(II) nitrate, nitrogen dioxide, and water. The resulting copper salts are blue in solution.
The digestion of solid copper wire by nitric acid is a type of redox reaction.
When copper metal reacts with concentrated nitric acid, it forms aqueous copper(II) nitrate, accompanies by the release of brown fumes of nitrogen dioxide (NO₂) and water. This chemical reaction is influenced by factors such as concentration of the acid, the metal's activity, and temperature. With concentrated nitric acid, copper generally reduces the acid to nitrogen dioxide.
In a redox reaction, there is a transfer of electrons between the reacting species, with one substance being oxidized (losing electrons) and the other being reduced (gaining electrons).
For the reaction of copper with concentrated nitric acid, the balanced chemical equation would reflect the formation of Cu(NO₃)₂ and NO₂, which can be represented as follows after balancing:
Cu(s) + 4HNO₃(aq) → Cu(NO₃)₂(aq) + 2NO₂(g) + 2H₂O(l).
Copper salts, such as Cu(NO₃)₂, are characterized by a blue color in solution, which indicates the presence of copper(II) ions that have emerged from the copper metal.
Plz I need help!!!!!!!!!!!!!!
Answer:
C) 8.9x10-19M
Explanation:
Whe disolving a solid in water, this solid splits in anions and cations, in our example for CuS solid:
CuS (s) -------> Cu+2 (ac) + S-2 (ac)
Whe this solution is saturated, and balance is reached, this balance can be represented with Ksp formula (solubility constant), as following:
Ksp= [Cu+2][S-2], and for tgis ecuation, you only consider aqueous ions, but not the solid salt
When balance is reached, you may suppose that "X" moles of CuC gives you "X" moles of Cu+2 and "X" moles of S-2 (according to the stoicheometry of the above reaction):
XCuS (s) ------> XCu+2(ac) + XS-2(ac) , for which:
[Cu+2]=X and [S-2]=X so this gives us: Ksp=8x10-37=X.X=X²
X= √8x10-37 and finally X=[Cu+2]=8.9x10-19M (expressed in molar units)
A 75.0-mL volume of 0.200 M NH3 (Kb=1.8×10−5) is titrated with 0.500 M HNO3. Calculate the pH after the addition of 15.0 mL of HNO3.
The pH IS 9.6
Explanation;Moles NH3 initially present = 0.0750 L X 0.2 mol/L = 0.015 mol NH3
Moles HNO3 added = 0.015 L X 0.500 mol/L = 7.5X10^-3 mol HNO3 added
NH3 + HNO3 --> NH4+ + NO3-
So, after the addition, the solution contains 7.50X10^-3 mol NH4+ and 9.5X10^-3 mol NH3. The concentrations are:
[NH4+] = 7.5X10^-3 mol / 0.090 L = 0.0833 M
[NH3] = 1,5X10^-2mol / 0.090 L = 0.1667 M
The equilbirium involved is:
NH3 + H2O <--> NH4+ + OH-
Kb = [NH4+][OH-]/[NH3] = 1.8X10^-5
1.8X10^-5 = (0.0833)[OH-]/0.1667
[OH-] = 3.602 X10^-5
pOH = 4.44
pH = 14.00 - pOH
= 9.557 or 9.6
What can you learn about a compound from its chemical formula
Answer:
From the chemical formula of a compound you can learn about its composition:
kind of atoms (elements) that form it, andthe ratios (relative proportions of number of atoms)Also, with the ratios and the atomic masses of each kind of atom, you can obtain the mass composition (%) of the compound.
Explanation:
Using indexes (subscripts), the chemical formula of a compound shows the elements (kind of atoms) in the compound and the relative proportions of those elements.
The following example will show you how you learn that information from the chemical formula.
A very familiar compound is water and its chemical formula (also very familiar) is H₂O.
From that, you learn that water (a chemical compound):
Is formed of hydrogen and oxygen atomsHas two atoms of hydrogen per each atom of oxygen (2:1 ratio)Molar mass: Using the atomic masses of hydrogen and oxygen obtain the mass of one mole of water molecules:* hydrogen, H: 2 × 1.008 g/ mol = 2.016 g/,ol
* oxygen, O: 1 × 15.999 g/mol = 15.999 g/mol
* Molar mass of water: 2.016 g/mol + 15.999 g/mol = 18.015 g/ mol
Percent composition:* H: (2.016 g/mol / 18.015 g/mol) × 100 = 11.19%
* O: (15.999 g/mol / 18.015 g/mol) × 100 = 88.81%
HELP ASAP PLEASAE!!!
The structural formula for butane is: CH3-CH2-CH2-CH3 Which of these structures represents a correct isomer of butane?
A. CH3-CH2- CH3 CH3
B. CH3-CH- CH3 CH3
C. CH3-CH2- CH3 CH2
D. CH2-CH2- CH3 CH3
I believe the answer is A. However, I would double check the formula.
The isomer of the given structure of the Butane is Iso-Butane. Therefore, option (B) is correct.
What are structural isomers?Structural isomers are those isomers with the same molecular formulas but the atoms are completely arranged in a different manner. These are the molecules having the same molecular formula with different connectivities among the atoms.
For example, the structure of alkane (C₄H₁₀) is representing structural isomers with different structures. As there is an increase in the number of carbon atoms, the structural isomers of the alkane molecule increase.
The phenomenon of this structural isomer is known as structural isomerism. Structural isomerism is also known as constitutional isomerism as per the IUPAC.
The molecular formula of the butane is C₄H₁₀ where the linear chain of the four carbon atoms of butane is n-butane isomer. While the branched chain of the butane is an iso-butane isomer in which one carbon is tertiary.
Therefore, the structure in option (B) is isobutane, which is an isomer of butane.
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At what temperature (hot or cold) can we dissolve a gas in a solution
Depends on the gas and grams of solute. If you were able to give me a gas i would be able to help you but i cannot without the gas or chemical makeup.
What is the molarity of a solution containing 3.0 moles of silver chloride dissolved in enough water to make 2.0 liter solutuion
Answer:
1.5 mol/L.
Explanation:
The molarity is defined as the no. of moles of solute in 1.0 L of the solution.∵ M = no. of moles of solute/V of the solution.
∴ M = (3.0 mol)/(2.0 L) = 1.5 mol/L.
The molarity of the given silver chloride solution is 1.5 M, calculated by dividing the number of moles of solute by the liters of solution. To find the concentration of chlorine, one must calculate the moles from the mass of each chloride compound, convert to grams, and divide by the solution volume in liters.
Explanation:The molarity of a solution is defined as the number of moles of solute per liter of solution. For the first question provided with 3.0 moles of silver chloride (AgCl) dissolved to make a 2.0-liter solution, the molarity (M) can be calculated using the formula M = moles of solute / liters of solution. Therefore, the molarity is 1.5 M, because M = 3.0 moles / 2.0 liters.
For the second question, to calculate the concentration of chlorine in grams per liter, first determine the moles of chlorine in each compound, then convert the total moles to grams and divide by the volume of solution in liters. We can find the molar mass of CaCl₂, MgCl₂, and MnO₂, calculate how many moles of Cl are in each using their respective weights, and sum them up to find the total chlorine content. The grams of chlorine per liter can then be calculated by converting the total grams of chlorine to the volume of the solution.
What forces must be overcome for a substance to melt
Intermolecular forces.
which element would you think is the best conductor of electricity?
A. zinc (Zn)
B. argon (Ar)
C. silicon (Si)
D. hydrogen (H)
A. Zinc (Zn)
Like all the other metals, it has a cloud of an electron because of the free electrons in the valence shell. These electrons are easier to move.
When some electric force is applied, the electrons start moving towards the positive end due to the attraction. This causes the flow of electrons, and, ultimately, the generation of electricity. Zinc one has 27%
Enter a balanced chemical equation for the reaction between potassium metal and liquid water.
Answer:
2K (s) + 2H₂O (l) → 2KOH (aq) + H₂(g)↑Explanation:
1) Word equation (given)
Potassium + water → ?2) Kind of reaction
Potassium is an alkali metal.This is a single replacement reaction.
Alkali metals is the group of metals in the group 1 of the periodic table. These are the most active metals, meaning that they react violently with water releasing hydrogen gas.
Alkali metals can lose an electron to form compounds with oxidation number +1.The general equation for the reaction of an alkali metal and water is:Metal + Water → hydroxide + gaseous hydrogen
X + H₂O → XOH(aq) + H₂ (g) ↑
3) Chemical equation
K (s) + H₂O (l) → KOH(aq) + H₂(g)↑4) Balance
2K (s) + 2H₂O (l) → 2KOH(aq) + H₂(g)↑There is the same number of each atom on both sides: 2 K in the left and in the right, 4 H in the left and in the right, and 2 oxygen in the left and in the right. So, the equation is balanced.
The reaction of potassium metal with water produces potassium hydroxide and hydrogen gas, represented by the balanced chemical equation [tex]2K(s) + 2H_2O(l) \rightarrow 2KOH(aq) + H_2(g)[/tex]
The balanced chemical equation for the reaction between potassium metal (K) and liquid water (H2O) is:
[tex]2K(s) + 2H_2O(l) \rightarrow 2KOH(aq) + H_2(g)[/tex]
In this reaction, potassium metal reacts vigorously with water to produce potassium hydroxide (KOH), which is an alkali, and hydrogen gas ([tex]H_2[/tex]). This is an exothermic reaction and heat is also released. The products include the aqueous potassium hydroxide and gaseous hydrogen. The equation is balanced with two atoms of potassium and two molecules of water on the reactant side, and two formula units of potassium hydroxide and one molecule of hydrogen gas on the product side.
The average kinetic energy of the particles of a substance _____.
A.is equal to the total energy absorbed by the substance
B. increases as the temperature of the substance is lowered
C. is directly proportional to the temperature of the substance
D. is not affected by the temperature of the substance
Answer:
C
Explanation:
The higher the temperatures the higher the kinetic energy of the particles. This is because the particles move more rapidly and faster with increased temperatures. This is why the more you heat a substance it changes phases as it molecules/particles move more rapidly and collide with more force.
The average kinetic energy of the particles of a substance is directly proportional to the temperature of the substance (Option C).
Kinetic energy refers to the form of energy of an object due to its motion (movement).Kinetic energy is directly proportional to the motion of its constituent particles, which depends on the temperature (higher temperature higher motion).Conversely, potential energy refers to the energy stored by an object because of its position with regard to other objects.Kinetic energy cannot be negative, but potential energy can be negative.In conclusion, the average kinetic energy of the particles of a substance is directly proportional to the temperature of the substance (Option C).
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Write equations showing how each of the following weak bases ionizes water to form OH-.
a.) CO3^2-. Express your answer as a chemical equation.
b.) C6H5NH2. Express your answer as a chemical equation.
c.) C2H5NH2. Express your answer as a chemical equation.
Bases produce OH- when they react with water.
A weak base is a substance that ionizes only to a small extent in water. A weak base remains largely undissociated in water. Recall that bases produce OH- in solution.
The equation of the reaction by which the following species produce OH- in water are shown below;
CO3^2-(aq) + H2O(l) -------> HCO2^-(aq) + OH^-(aq)
C6H5NH2(aq) + H2O(l) -------> C6H5NH3^+(aq) + OH^-(aq)
C2H5NH2(aq) + H2O(l) -------> C2H5NH3^+(aq) + OH^-(aq)
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The weak bases CO3^2-, C6H5NH2 and C2H5NH2 ionize in water by accepting a proton (H+) from water, and in the process, creating hydroxide ions (OH-) and their corresponding positive ions. The respective ionization equations are: CO3^2- + H2O ⟶ HCO3- + OH-, C6H5NH2 + H2O ⟶ C6H5NH3+ + OH-, and C2H5NH2 + H2O ⟶ C2H5NH3+ + OH-.
Explanation:The ionization of weak bases in water involves the base accepting a proton (H+) from water, creating hydroxide ions (OH-) and a corresponding positive ion. Here are the equations representing how the three given bases ionize in water:
CO3^2-: CO3^2- + H2O ⟶ HCO3- + OH- C6H5NH2 (Aniline): C6H5NH2 + H2O ⟶ C6H5NH3+ + OH-C2H5NH2 (Ethylamine): C2H5NH2 + H2O ⟶ C2H5NH3+ + OH-Note that in all these reactions, OH- is formed showing the formation of basic solutions.
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Calculate the ph for each case in the titration of 50.0 ml of 0.150 m hclo(aq) with 0.150 m koh(aq). use the ionization constant for hclo
PH = 7.58
Further Explanation
KOH will interact with HClO to provide KClO. you may have an answer that contains unreacted HClO and KOH. this is often a solution.
Equation:
HClO + KOH → KClO + H2O
HClO reacts with KOH in a very 1: 1 molar ratio
Mole of acid in 50 ml of an answer of 0.150 m = 50/1000 * 0,150 = 0.0075 mole of acid
Mole of KOH in 30 ml of 150 M solution = 30/1000 * 0,150 = 0.0045 mole of KOH
This reacts to provide 0.0045 moles of KClO and there are 0.0030 moles of HClO unreacted
The volume of the answer = 50 ml + 30 ml = 80 ml = 0.080 l
Deposition of acid in solution = 0.0030 / 0.080 = 0.0375M
KClO deposit in solution = 0.0045 / 0.080 = 0.0562 m
Using the Henderson-Hasselbalch equation, we will calculate pH;
pKa HClO = -log (4.0 * 10 ^ -8) = 7.40
PH = pKa + log ([KClO] / [HClO])
PH = 7.40 + notes (0.0562 / 0.0375)
PH = 7.40 + 1.50 notes
PH = 7.40+ 0.18
PH = 7.58
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Details
Grade: College
Subject: Chemistry
Keyword: mole, acid, HClO
Final answer:
In this titration of HClO with KOH, the pH at different volumes of added base is calculated. At 0.00 mL, the pH requires the ionization constant of HClO. At 15.0 mL, the pH is 0.903. At 25.0 mL, the pH is 7. At 30.0 mL, the pH is 14.
Explanation:
In this titration, we are diluting a 0.150 M solution of HClO with a 0.150 M solution of KOH. The goal is to calculate the pH at different volumes of added base.
In summary, the pH at different volumes of added base in the titration of HClO with KOH is as follows: 0.00 mL: pH = ? (Requires ionization constant of HClO); 15.0 mL: pH = **0.903**; 25.0 mL: pH = **7**; 30.0 mL: pH = **14**.
Which statement does NOT apply to unsaturated hydrocarbons?
Unsaturated hydrocarbons require energy to react.
Unsaturated hydrocarbons are very reactive.
Unsaturated hydrocarbons contain double and triple bonds.
Unsaturated hydrocarbons undergo addition reactions to become saturated.
Unsaturated hydrocarbons undergo addition reactions to become saturated.
Answer: The correct statement is unsaturated hydrocarbons require energy to react.
Explanation:
Unsaturated hydrocarbons are defined as the hydrocarbons which have double or triple covalent C-C bonds. They are known as alkenes and alkynes respectively. The general formula for these hydrocarbons is [tex]C_nH_{2n}[/tex] and [tex]C_nH_{2n-2}[/tex]
These hydrocarbons are more reactive than the saturated ones because of the presence of [tex]\pi-[/tex]bonds. These bonds are weaker than [tex]\sigma-[/tex]bonds and thus can be easily broken. Addition reactions is more favorable for the compounds having [tex]\pi-[/tex]bonds.
These hydrocarbons do not require any energy to react. They are readily reactive.
Hence, the correct statement is unsaturated hydrocarbons require energy to react.
What color does red and yellow make?
Red and yellow make orange.
Red and yellow mix together to create the color orange.
When you mix red and yellow, you are essentially combining their respective pigments or light wavelengths.
Red has a longer wavelength and is a primary color, meaning it cannot be made by combining other colors. On the other hand, yellow, which is a primary hue as well, has a medium wavelength.
The color orange is perceived as a new color when red and yellow are combined. This occurs as a result of the red pigment's or wavelength's stimulation of our eyes' long-wavelength receptors and the yellow pigment's or wavelength's stimulation of our eyes' medium-wavelength receptors. The brain interprets the mix of inputs as the color orange after processing the data from these receptors.
When red and green light are combined at their maximum intensity in the RGB (Red, Green, Blue) color model, they produce yellow rather than orange. Red and yellow combine to form orange in the subtractive color model, which is the one utilized for physical pigments like paint. This is caused by variations in how light and pigments interact to create perceptions of color.
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Calculate [H+] for each of the following solutions, and indicate whether the solution is acidic, basic, or neutral.
Part A [OH−]= 4.5×10−4 M . Express your answer using two significant figures.
Part B 1) the solution is acidic 2) the solution is basic 3) the solution is neutral
Part C [OH−]= 7.7×10−9 M . Express your answer using two significant figures.
Part D 1) the solution is acidic 2) the solution is basic 3) the solution is neutral
Part E A solution in which [OH−] is 140 times greater than [H+]. Express your answer using two significant figures.
Part F 1) the solution is acidic 2) the solution is basic 3) the solution is neutral
Answer:
Part A: 10.7.
Part B: 2) the solution is basic.
Part C: 5.9.
Part D: 1) the solution is acidic.
Part E: 8.1.
Part F: 2) the solution is basic.
Explanation:
Part A [OH−]= 4.5×10−4 M . Express your answer using two significant figures.
∵ [H₃O⁺][OH⁻] = 10⁻¹⁴.
[OH⁻] = 4.5×10⁻⁴ M.
∴ [H₃O⁺] = 10⁻¹⁴/[OH⁻] = 10⁻¹⁴/(4.5×10⁻⁴ M) = 2.22 × 10⁻¹¹ M.
∵ pH = - log[H₃O⁺]
∴ pH = - log(2.22 × 10⁻¹¹) = 10.65 ≅ 10.7.
Part B 1) the solution is acidic 2) the solution is basic 3) the solution is neutral
The solution is basic, because the pH is higher than 7.
Part C [OH⁻]= 7.7×10⁻⁹ M . Express your answer using two significant figures.
∵ [H₃O⁺][OH⁻] = 10⁻¹⁴.
[OH⁻] = 7.7×10⁻⁹ M.
∴ [H₃O⁺] = 10⁻¹⁴/[OH⁻] = 10⁻¹⁴/(7.7×10⁻⁹ M) = 1.29 × 10⁻⁶ M.
∵ pH = - log[H₃O⁺]
∴ pH = - log(1.29 × 10⁻⁶) = 5.88 ≅ 5.9.
Part D 1) the solution is acidic 2) the solution is basic 3) the solution is neutral
The solution is acidic, because the pH is lower than 7.
Part E A solution in which [OH−] is 140 times greater than [H+]. Express your answer using two significant figures.
∵ [H₃O⁺][OH⁻] = 10⁻¹⁴.
∵ [OH⁻] = 140[H₃O⁺]
∴ [H₃O⁺](140[H₃O⁺]) = 10⁻¹⁴.
∴ 140 [H₃O⁺]² = 10⁻¹⁴.
[H₃O⁺]² = 10⁻¹⁴/ 140 = 7.14 x 10⁻¹⁷.
∴ [H₃O⁺] = √(7.14 x 10⁻¹⁷) = 8.45 x 10⁻⁹ M.
∵ pH = - log[H₃O⁺]
∴ pH = - log(8.45 x 10⁻⁹) = 8.07 ≅ 8.1.
Part F 1) the solution is acidic 2) the solution is basic 3) the solution is neutral
The solution is basic, because the pH is higher than 7.
The [H+] for solutions with given [OH−] are calculated using the ion product of water, with solutions having [H+] less than 1.0 × 10-7 being basic and those with more being acidic. The solutions for Part A and E were found to be basic while the solution for Part C was found to be acidic.
Explanation:The [H+] of a solution can be determined from its [OH−] by using the ion product of water, which is 1.0 × 10-14 at 25°C. This can be represented by the equation [H+][OH−] = 1.0 × 10-14.
For Part A, you needed to calculate [H+] for a solution with [OH−] = 4.5 × 10-4M. [H+] = 1.0 × 10-14 / [OH−] = 1.0 × 10-14 / 4.5 × 10-4= 2.2 × 10-11 M. Since [H+] is less than 1.0 × 10-7, the solution is basic.
For Part C, [OH−] is 7.7 × 10-9M. [H+] = 1.0 × 10-14 / 7.7 × 10-9= 1.3 × 10-6M. Because [H+] is higher than 1.0 × 10-7, the solution is acidic.
In Part E, the solution's [OH−] is 140 times that of [H+]. Therefore, if we let [H+] = x, we get [OH−] = 140x. Since [H+][OH−] = 1.0 × 10-14, we get x(140x) = 1.0 × 10-14. Solving for x, we get [H+] = x = 5.37 × 10-14M. Since [H+] is less than 1.0 × 10-7, the solution is basic.
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What is the pH of a solution with a 2.20 × 10−8 M hydroxide ion concentration?
Answer:
The pH of the solution is 6.35.
Explanation:
Concentration of hydroxide ions = [tex][OH^-]=2.20\times 10^{-8} M[/tex]
pH + pOH = 14
pH = 14 - pOH
[tex]pOH=-\log[OH^-][/tex]
[tex]pOH=-\log[2.20\times 10^{-8} M]=7.65[/tex]
[tex]pH=14-pOH=14-7.65=6.35[/tex]
The pH of the solution is 6.35.
The pH of the solution with a [tex]\( 2.20 \times 10^{-8} \)[/tex] M hydroxide ion concentration is approximately [tex]\( 6.34 \)[/tex].
To find the pH of a solution with a given hydroxide ion concentration [tex](\( [\text{OH}^-] \))[/tex], we can use the relationship between [tex]\( [\text{OH}^-] \)[/tex] and [tex]\( \text{pOH} \)[/tex], and then convert [tex]\( \text{pOH} \)[/tex] to pH.
The relationship between [tex]\( [\text{OH}^-] \)[/tex] and [tex]\( \text{pOH} \)[/tex] is:
[tex]\[ \text{pOH} = -\log([\text{OH}^-]) \][/tex]
Given [tex]\( [\text{OH}^-] = 2.20 \times 10^{-8} \) M[/tex], we can calculate [tex]\( \text{pOH} \)[/tex]:
[tex]\[ \text{pOH} = -\log(2.20 \times 10^{-8}) \][/tex]
[tex]\[ \text{pOH} = -\log(2.20) - \log(10^{-8}) \][/tex]
[tex]\[ \text{pOH} = -(\log(2.20) + (-8 \times \log(10))) \][/tex]
[tex]\[ \text{pOH} = -(0.3424 - 8 \times 1) \][/tex]
[tex]\[ \text{pOH} = -(0.3424 - 8) \][/tex]
[tex]\[ \text{pOH} = -(7.6576) \][/tex]
[tex]\[ \text{pOH} = -(-7.6576) \][/tex]
[tex]\[ \text{pOH} = 7.6576 \][/tex]
Now, we can convert [tex]\( \text{pOH} \)[/tex] to pH using the relationship:
[tex]\[ \text{pH} + \text{pOH} = 14 \][/tex]
[tex]\[ \text{pH} = 14 - \text{pOH} \][/tex]
[tex]\[ \text{pH} = 14 - 7.6576 \][/tex]
[tex]\[ \text{pH} = 6.3424 \][/tex]