1. 3/5x -7 = 23
A. x = 40
B. x = 45
C. x = 50
D. x = 55
2.When Patrick and Cameron went bowling at Victory Lanes, they spent a total of $42. This included rental of shoes at $3.50 per pair. Patrick bowled 2 games, and Cameron bowled 3 games.
How much did each game cost?
A. $6.00
B. $7.00
C. $7.70
D. $8.75
3.A local movie theater offers a special deal for birthday parties. The price, which covers the cost of the tickets and a box lunch, includes a flat fee of $75 plus $5 per ticket. Sarah’s parents spent $150 altogether at the theater to celebrate her birthday.
Which equation can be used to determine how many children, x, were in the group?
A. 75/150=5x
B. 150/75=5x
C. 150 = 5x – 75
D. 150 = 5x + 75
4. 35 + 0.25x = 53.75
A. x = 75
B. x = 140
C. x = 215
D. x = 250
5.T he perimeter of this isosceles triangle is 47 cm.
top point. (B) left bottom point (A) right bottom point (C) in between 12cm
What is the length of each of its legs (it doesn't have legs)?
A. 15 cm
B. 17.5 cm
C. 19.5 cm
D. 35 cm
Kate has a serving account that contains $230. She decides to deposit $5 each month from her monthly earnings for baby-sitting after school. Write an expression to find how much money Mata will have in her savings account after x months. Let x represent the number of months. Then find out how much she will have in her account after 1 year
What is the sign of-5×-1/-2
Bob is a high school basketball player. his probability of making a free throw is 0.70. let x denote the number of hits in 10 shots. . find the probability that bob makes at least 9 hits. the probability is _____________.
Simplify (25x2 − 14xy + 4) − (7x2 − 9y) + (2xy + 7)
Answer:
18x2 − 12xy + 9y + 11
Step-by-step explanation:
Expanded form for 4082
x+2y=8 in slope intercept form
[tex]x+2y=8[/tex] can be written in a slope-intercept form as [tex]y = 4-\dfrac{x}{2}[/tex].
SlopeA slope is also known as the gradient of a line is a number that helps to know both the direction and the steepness of the line.
Given to us,[tex]x+2y=8[/tex]
To find the slope-intercept formTo find the function, simply isolate y.
[tex]x+2y=8\\2y = 8-x\\y = \dfrac{8-x}{2}\\\\y = \dfrac{8}{2}-\dfrac{x}{2}\\\\y = 4-\dfrac{x}{2}[/tex]
Hence, [tex]x+2y=8[/tex] can be written in a slope-intercept form as [tex]y = 4-\dfrac{x}{2}[/tex].
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Find two numbers with a sum of 20 and a difference of 14.
which pair of fractions is equivalent to this pair : 3/5 and 2/7
a. 21/35 & 10/35
b. 10/35 & 7/35
c. 7/35. & 5/35
d. 24/35 & 12/35
Sarah's craft project uses pieces of yarn that are 1/8 long. She has a piece of yarn that is 3 yards long. How many 1/8 yard pieces can she cut and still have 1 1/4 yards left?
At full power, how long would it take for the car to accelerate from 0 to 64.0 mph ? neglect friction and air resistance. express your answer in seconds.
The graph of y = –3x + 4 is:
A. a point that shows the y-intercept.
B. a line that shows the set of all solutions to the equation.
C. a point that shows one solution to the equation.
D. a line that shows only one solution to the equation.
Answer: The answer is B, just got this one on a test.
Step-by-step explanation:
What reason explains why (-6,8) must also be a point on the graph?
Suppose that f(t)f(t) is continuous and twice-differentiable for t≥0t≥0. further suppose f′′(t)≤3f″(t)≤3 for all t≥0t≥0 and f(0)=f′(0)=0f(0)=f′(0)=0. using the racetrack principle, what linear function g(t)g(t) can we prove is greater than or equal to f′(t)f′(t) (for t≥0t≥0)?
(x) is continuous and twice differentiable for ±≥ 0. Suppose f”( ±) ≤ 5 for all ±≥ 0 and f (0) = f’(0) = 0. The linear function with a derivation of 0 is y = 0. Thus we have g(t) = 0. The quadratic function with concavity 5 and initial slope 0 is y = 5/2 x^2 + 0x. Therefore, h(t) = (5/2)x^2
Given the conditions, the function g(t)=3t is always greater than or equal to f'(t), as it represents the maximum possible velocity considering the maximum constant acceleration of 3 over time.
Explanation:Given that f(t) is a continuous and twice-differentiable function for t≥0 and that f''(t)≤3 for all t≥0, the function f(t) represents the position of an object over time, with f'(t) and f''(t) being the velocity and acceleration, respectively. Further, given that f(0)=f'(0)=0, it is stated that at time t=0, the object is at the origin and is at rest.
Using the Racetrack Principle, we know that velocity must be less than or equal to the maximum acceleration times time. In plain terms, the actual speed of a body at a time 't' (f'(t)) could not be more than the distance it would have covered if it was accelerating at the maximum possible rate from rest. Since f''(t)≤3, the maximum possible acceleration is 3.
Thus, for all t≥0, if we consider the linear function g(t)=3t, we can say g(t) is greater than or equal to f'(t). Because even if the acceleration was at the maximum value of 3 for the entire duration, the velocity wouldn't exceed 3t.
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What Is two thirds of a straight angle
Two thirds of a straight angle is calculated as 120 degrees.
Two thirds of a straight angle can be calculated by first understanding that a straight angle is equal to 180 degrees. When we want to find a fraction of a given angle, we multiply the fraction by the total degree measure of that angle.
In this case, to find two thirds of a straight angle, we multiply 180 degrees by 2/3.
Here is a step-by-step explanation of the calculation:
Understand that a straight angle equals 180 degrees.
Multiply 180 degrees by the fraction 2/3:
(180 degrees) * (2/3) = 120 degrees.
Suppose you buy a piece of office equipment for $9,000.00. After 5 years you sell it for a scrap value of $2,000.00. The equipment is depreciated linearly over 5 years. The value of the piece of equipment after 2 years is (rounded to the nearest whole dollar)
The value of the piece of equipment after 2 years is $6,200.00.
What is a Linear equation?A linear equation is an algebraic equation of the form y=mx+b, where m is the slope and b is the y-intercept, and only a constant and a first-order (linear) term are included. Sometimes, the aforementioned is referred to as a "linear equation of two variables," with y and x serving as the variables.
The equipment is depreciated linearly, which means that its value decreases at a constant rate each year. We can find the rate of depreciation by subtracting the scrap value from the purchase price, and then dividing by the number of years of useful life:
Rate of depreciation = (Purchase price - Scrap value) / Useful life
Rate of depreciation = (9000 - 2000) / 5
Rate of depreciation = 1400
This means that the equipment loses $1,400 of value each year. After 2 years, the value of the equipment will be:
Value after 2 years = Purchase price - (Rate of depreciation x Number of years)
Value after 2 years = 9000 - (1400 x 2)
Value after 2 years = 6200
Therefore, the value of the piece of equipment after 2 years is $6,200.00.
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Calc find the maximum of f(x, y) = y2 + xy â x2 on the square 0 ⤠x ⤠6, 0 ⤠y ⤠6.
To find the maximum of the function f(x, y) = y² + xy – x² on the square 0 ≤ x ≤ 6, 0 ≤ y ≤ 6, we need to find the critical points by taking the partial derivatives with respect to x and y.
To find the maximum of the function f(x, y), we need to find the critical points by taking the partial derivatives with respect to x and y:
[tex]f_x[/tex] = y - 2x
[tex]f_y[/tex] = 2y + x
Setting these derivatives equal to zero and solving for x and y, we get the critical point (2,2). To determine if this point is a maximum, minimum, or point of inflection, we can use the second derivative test. Taking the second partial derivatives:
[tex]f_{xx[/tex] = -2, [tex]f_{yy[/tex] = 2, [tex]f_{xy[/tex] = 1
Using the discriminant D = [tex]f_{xx} \times f_{yy} - {(f_{xy})}^2[/tex], we have D = [tex](-2) \times 2 - {1}^2[/tex] = -4. Since D is negative, the critical point (2,2) is a saddle point, which means there is no maximum or minimum on the given square.
Which theorist is associated with the idea that information not actively attended to is not lost; rather, it simply decreases in signal strength and is therefore not given any significance or future attention?
Final answer:
Anne Treisman is associated with the Attenuation Model, which posits that unattended information is not lost but simply weakened. This model contrasts with filter theories, emphasizing that meaningful information can penetrate the attention barrier for further processing.
Explanation:
The theorist associated with the idea that information not actively attended to is not lost but rather decreases in signal strength and is therefore not given any significance or future attention is Anne Treisman. Treisman proposed the Attenuation Model, which challenges the filter theory, suggesting that selection of information begins at the physical or perceptual level. However, unlike the filter theory that assumes unattended information is completely blocked, Treisman believes that unattended information is just weakened or attenuated. This means that any highly meaningful or pertinent information, such as one's own name, can still get through the filter for further processing at the level of meaning.
Supporting this model, late selection models like that of Deutsch and Deutsch also propose that all information is processed on the basis of meaning, but only task-relevant information reaches conscious awareness. This concept is in line with the idea of subliminal perception where unconscious information can be fully processed for meaning.
Therefore, the attenuation model and late selection models suggest that our attention selects information but does not completely eliminate the processing of unattended stimuli, particularly if the unattended information holds some form of intrinsic importance or meaning to the individual.
Each side of a square is increasing at a rate of 5 cm/s. at what rate is the area of the square increasing when the area of the square is 49 cm2? 70 cm2/s
in triangle ABC, L is the midpoint of BC, M is the midpoint of AB and N is the midpoint of AC. If MN=8, ML 5 and NL=6, the perimeter of BMNC is?
Choose the fraction that goes in the blank. six over ten >_______> one over two A one over two B one over four C two over three D three over four
To determine which fraction is greater, we convert both fractions to decimal form. Six over ten is greater than one over two.
Explanation:To determine which fraction is greater, six over ten or one over two, we can convert both fractions to decimal form and compare them. Six over ten can be simplified to three over five, which is equal to 0.6. One over two is equal to 0.5. Since 0.6 is greater than 0.5, we can conclude that six over ten is greater than one over two.
Find the cost per pound of a "house blend" of coffee that is made from 20 lb of Central American coffee that costs $7 per pound and 30 lb of South American coffee that costs $4.50 per pound
Greg drank 5 cups of water on Monday. He drank 4 cups of water on Tuesday. How many 1/4 cup servings of water did Greg drink on Monday and Tuesday combined?
A certain vibrating system satisfies the equation u′′ + γu′ + u = 0. find the value of the damping coefficient γ for which the quasi period of the damped motion is 50% greater than the period of the corresponding undamped motion.
-3.1 * (- 2.9) Please help! Math.
The point(3,7) is reflected in the y axis what are the coordinates now
X/2-18=(-28)
What is x?
X=?
You are planning a party and want to know how many cans of soda to buy. a genie offers to tell you either the mean number of cans guests will drink
The first three values in a selected series are 3, 6, and 9. what are the next three va;ies that will be inserted by autofill?
Answer:
the answer is 12, 15. and 18.
Step-by-step explanation:
To extend the Sieve of Eratosthenes to 200, what is the largest prime whose multiples would have to be considered?
Therefore, the largest prime whose multiples need to be considered to extend the Sieve of Eratosthenes to 200 is 13.
The Sieve of Eratosthenes is a method used to find all prime numbers up to a given limit by iteratively marking the multiples of each prime number. To extend the Sieve of Eratosthenes to 200, determine the largest prime whose multiples need to be considered.
Begin by creating a list of numbers from 2 to 200. Mark 2 as the first prime number. Proceed to eliminate all multiples of 2 from the list (4, 6, 8, ...).
Move to the next unmarked number, which is 3. Mark it as a prime and eliminate all its multiples from the list (6, 9, 12, ...).
Continue this process for each unmarked number: marking it as a prime and eliminating its multiples. The next unmarked number after 3 is 5.
Continue this process until you reach the square root of the upper limit, which is √200 ≈ 14.14. Therefore, the largest prime whose multiples need to be considered to extend the Sieve of Eratosthenes to 200 is 13. Multiples of primes greater than 13 that fall below 200 have already been eliminated during the sieving process.