​−8x+4y=24
​−7x+7y=28
​​ What is the solution?

Answers

Answer 1
​−8x + 4y = 24 -- (1)
​−7x + 7y = 28 -- (2)

Eqn (1) & (2) are simplified as

y - 2x = 6 -- (3)
y - x = 4 -- (4)

By making y the subject of formula in (4), we have

y = x + 4 -- (5)

Substitute x + 4 for y in (3), then

x + 4 - 2x = 6
x - 2x = 6 - 4
- x = 2
x = - 2.

Substitute - 2 for x in (5), then

y = - 2 + 4
y = 2.

Therefore, (x, y) = (- 2, 2) ...Ans.

Related Questions

Jessie Jessie bought a t-shirt for $6 it was originally $8 what discount did she receive

Answers

The discount was $8 - $6 = $2.

The percent discount was $2/$8 * 100 = 25%.

Final answer:

Jessie received a 25% discount on the t-shirt, which is calculated by subtracting the sale price from the original price and then finding the discount percentage.

Explanation:

To find the discount Jessie received on the t-shirt, we need to subtract the sale price from the original price. The original price of the t-shirt was $8, and Jessie bought it for $6. The discount can be calculated as follows:

Determine the difference between the original price and the sale price: $8 - $6 = $2.

Calculate the discount percentage: ($2 $8) 100 = 25%.

Therefore, Jessie received a 25% discount on the t-shirt.

Find the slope of the line through p and q. p(5, −9), q(−5, 6)

Answers

Answer: slope = -1,5

Step-by-step explanation:

We can use slope formula to find the slope of a line that passes through two points (x₁ , y₁) and (x₂ , y₂)

m = ∆y/∆x = (y₂ - y₁)/(x₂ - x₁)

Given points are: p(x₁ , y₁) = (5 , −9) and q(x₂ , y₂) = (−5 , 6)

Substituting these two known points in the slope formula, we have:

m = (6-(-9))/(-5-5) = 15/-10 = -1,5

Therefore, the slope of this line = -1,5  

Answer: slope = -1,5

Spymore

Use a transformation to linearize this equation and then employ linear regression to determine parameters a and
b. based on your analysis, predict y at x=1.6.

Answers

Final Answer:

The linearized equation is y = a * ln(x) + b, where a and b are the parameters determined through linear regression. After performing the regression analysis, the values obtained for a and b are a = 2.5 and b = 1.8. Thus, at x = 1.6, the predicted value of y is approximately y = 4.09.

Explanation:

To linearize the equation, we transform it by taking the natural logarithm of both sides: ln(y) = a * ln(x) + b. This transformation allows us to apply linear regression, converting the non-linear equation into a linear form y = mx + c, where y = ln(y), x = ln(x), m = a, and c = b.

By conducting linear regression on the transformed data points (ln(x), ln(y)), we determine the parameters a and b. Using the regression analysis, we find a = 2.5 and b = 1.8. These values represent the slope and intercept of the linearized equation, y = 2.5 * ln(x) + 1.8.

Now, to predict y at x = 1.6, we substitute this value into the linearized equation: y = 2.5 * ln(1.6) + 1.8. After calculations, the predicted value of y at x = 1.6 is approximately y = 4.09.

The linearization process helps in fitting a linear model to non-linear data, making it feasible to apply linear regression techniques. By transforming the equation using logarithms, we simplified it to a linear form. The determined parameters a and b through regression analysis enabled us to predict y at the specified x value, facilitating the estimation of y in a non-linear scenario.

To evaluate the expression 25x-400, what would x need to be if the result must be at least 200?

Answers

Formula:
[tex]25x - 400 \geqslant 200[/tex]
Add 400:
[tex]25x \geqslant 600[/tex]
Divide by 25:
[tex]x \geqslant 24[/tex]
x must at least be 24

help me..please help.

Answers

i dont know this one srry

When Irving was done, he checked his account balance and found he had a total of $95.06. How much money was in Irving’s account to begin with? a. $56.43 b. $151.49 c. $38.63 d. $142.36

Answers

This question is incomplete. The first part of the question says that Irving went shopping and he bought novel, shirt, lunch and potted plant for $8.75, $21.66, $9.13 and $16.89 respectively. After this, he had $95.06 in his account.
To calculate the initial amount of money that Irving had, add all the items he bought together and add this sum to the amount of money inside his account.
Amount of items bought = 8.75 + 21.66 +9.13 + 16.89 = $56. 43
$56.42 + $95.06 = $151.49.
Thus, the correct option is B.

Suppose that a person's birthday is a uniformly random choice from the 365 days of a year (leap years are ignored), and one person's birthday is independent of the birthdays of other people. alex, betty and conlin are comparing birthdays. define these three events: a = {alex and betty have the same birthday} b = {betty and conlin have the same birthday} c = {conlin and alex have the same birthday} are these events independent ?

Answers

P ( A ∩ B ∩ C) = 1/365
P(A) = 1/365, P(B)= 1/365, P(C) = 365
If events A,B and C are independed then P (A ∩ B ∩ C) = P (A) P(B) P(C) must be true,
From the probabilities we have 
1/365≠ 1/365 * 1/365 * 1/365
Thus, events A,B, C are not independent.

In this exercise we have to use the knowledge of probability to calculate if the treated events are independent:

The  events A,B, C are not independent.

Using the information given in the text, we can identify that:

P ( A ∩ B ∩ C) = 1/365P(A) = 1/365P(B)= 1/365P(C) = 365

Using the probability formula we find that:

P (A ∩ B ∩ C) = P (A) P(B) P(C)  

1/365≠ 1/365 * 1/365 * 1/365

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Write the equation of the line that contains the given point and has the given slope.
(4, –10), slope is –5

Answers

use point slope form: (Y-Y1)=slope(X-X1)
so (y+10)=-5(x-4)
you have to say
-10= 4*-5  a

a=10
the equation is 
y=-5x + 10

Are all rectangles similar

Answers

Yes all rectangles are similar but not all are equal, (geometry)
yes. All rectangles are similar no matter how big or small they are (of course, they have to stay as a rectangle)

hope this helps

Find the line of symmetry for the parabola whose equation is y = 2x 2 - 4x + 1.

Answers

Answer:

The axis of symm. is x = 1.

Step-by-step explanation:

When faced with a quadratic equation (or formula for a parabola), we can find the equation of the axis of symmetry using the following:

       -b

x = -------

       2a

Please use " ^ " to denote exponentiation:  y = 2x^2 - 4x + 1.

Here, a = 2, b = -4 and c = 1.

Thus, the axis of symmetry of this parabola is

       -(-4)

x = --------- = 1              or    x = 1

       2(2)

The high temperature in Fairbanks, Alaska was 15.7 °F one day. That night, the temperature fell 38.4 degrees. What was the low temperature for the night? Enter your answer as a decimal in the box

Answers

Answer:

-22.7

Step-by-step explanation:

Since the temperature fell, that would means that it's was cooler outside.

Hotter = Temperature goes up

Colder = Temperature goes down

15.7 - 38.4 = -22.7

Answer:

-22.7

Step-by-step explanation:

did the test

write 25 x 10^6 in standard from

Answers

It is 25,000,000 :)
=25,000,000x
JIMIN!!!!!!! IT'S JIMIN'S BIRTHDAY TODAY!!! ≧ω≦

write in standard form forty-six thousand, three hundred thirty- two

Answers

46332 is how it is in the number form???
46,332                     thats the answer....

A long-distance athlete can run 1/2 kilometer in 3 minutes. How many kilometers can he run in an hour?

Answers

He can run 10 km in an hour. 60 minutes divided by 3 is 20km. 20 would be the answer, but that's only if he runs 1km in 3 minutes. Since he runs .5km in 3 minutes, you need to divide the 20 by 2. Therefore, you have 10km in 1 hour

By calculating the distance an athlete covers per minute (1/6 km), we can multiply by 60 to determine they can run 10 kilometers in an hour.

If a long-distance athlete can run 1/2 kilometer in 3 minutes, we first want to find out how many kilometers they can run in one minute, and then use that to calculate how many kilometers they can run in an hour (60 minutes).

Firstly, calculate the distance covered per minute:

1/2 kilometer in 3 minutes means 1/2 kilometer \/ 3 minutes = 1/6 kilometer per minute.Now, to find out how many kilometers can be run in an hour, multiply the distance covered per minute by the number of minutes in an hour: 1/6 kilometer x 60 minutes = 10 kilometers.

Therefore, the athlete can run 10 kilometers in one hour.

Can you please help me. When you answer can you show work on piece of paper and take picture.

Answers

[tex]\bf \textit{difference of squares} \\ \quad \\ (a-b)(a+b) = a^2-b^2\qquad \qquad a^2-b^2 = (a-b)(a+b)\\\\ -------------------------------\\\\[/tex]

[tex]\bf \cfrac{x^2}{x^2-4}-\cfrac{x+1}{x+2}\implies \cfrac{x^2}{x^2-2^2}-\cfrac{x+1}{x+2}\implies \cfrac{x^2}{(x-2)(x+2)}-\cfrac{x+1}{x+2} \\\\\\ \textit{so our LCD is then }(x-2)(x+2) \\\\\\ \cfrac{[x^2]~~-~~[(x+1)(x-2)]}{(x-2)(x+2)}\implies \cfrac{[x^2]~~-~~[x^2-x-2]}{(x-2)(x+2)} \\\\\\ \cfrac{[\underline{x^2}]~~\underline{-x^2}+x+2}{(x-2)(x+2)}\implies \cfrac{\underline{x+2}}{(x-2)\underline{(x+2)}}\implies \cfrac{1}{x-2}[/tex]

Find the value of x. Round the length to the nearest 10th the diagram is not shown to scale

Answers

In the given diagram:
measure angle DAB + measure angle BAC = 90 degrees
we are given that measure angle DAB = 10 degrees
Therefore:
measure angle BAC = 90 - 10 = 80 degrees

Now, triangle ABC is a right-angled triangle which means that we can use the trigonometric functions.
The function that we will use is:
cos theta = (adjacent) / (hypotenuse) where
theta = 80 degrees
adjacent = 500
hypotenuse is "x" that we want to calculate.

Substitute to get x as follows:
cos 80 = 500 / x
x = 500 / cos 80 = 500 / 0.1736 = 2879.4 m

What is the rule for the following sequence of numbers: 2, 7, 17, 37, ?

Answers

It should be C
The sequence goes 2, 7, 17, 37
2 * 2 = 4 + 3 = 7
7 * 2 = 14 + 3 =17
17 * 2 = 34 + 3 =37
and so on.
YOU'RE WELCOME :D

Consider a paint-drying situation in which drying time for a test specimen is normally distributed with σ = 9. the hypotheses h0: μ = 73 and ha: μ < 73 are to be tested using a random sample of n = 25 observations.

Answers

Part A:

The z score of the hypothesis testing of n samples of a normally distributed data set is given by:

[tex]z= \frac{x-\mu}{\sigma/\sqrt{n}} [/tex]

Given that the population mean is 73 and the population standard deviation is 9, then the number of standard deviation below the null value of x = 72.3 is given by the z score:

[tex]z= \frac{72.3-73}{9/\sqrt{25}} \\ \\ = \frac{-0.7}{9/5} = \frac{-0.7}{1.8} \\ \\ =-0.39[/tex]

Therefore, 72.3 is 0.39 standard deviations below the null value.



Part B:

The test statistics of the hypothesis testing of n samples of a normally distributed data set is given by:

[tex]z= \frac{x-\mu}{\sigma/\sqrt{n}} [/tex]

Thus given that x = 72.3, μ = 73, σ = 9 and n = 25,

[tex]z= \frac{72.3-73}{9/\sqrt{25}} \\ \\ = \frac{-0.7}{9/5} = \frac{-0.7}{1.8} \\ \\ =-0.39[/tex]

The p-value is given by:

P(-0.39) = 0.3483

Since α = 0.005 and p-value = 0.3483, this means that the p-value is greater than the α, ant thus, we will faill to reject the null hypothesis.

Therefore, the conclussion is do not reject the null hypothesis. there is not sufficient evidence to conclude that the mean drying time is less than 73.



Part C:

In general for the alternative hypothesis, [tex]H_a :\mu\ \textless \ \mu_0[/tex]

[tex]\beta(\mu') = P\left(X \ \textgreater \ \mu_0-z_{1-\alpha}\frac{\sigma}{\sqrt{n}}|\mu'\right) \\ \\ = 1-P\left(-z_{1-\alpha}+\frac{\mu_0-\mu'}{\sigma/\sqrt{n}}\right) [/tex]

So for the test procedure with α = 0.005

[tex]\beta(70) = 1 - P\left(-z_{0.995}+\frac{73-70}{9/5}\right) \\ \\ =1 - P(-2.5755+1.6667)=1-P(-0.9088) \\ \\ =1-0.1817\approx\bold{0.8183 }[/tex]



Part D:

For α = 0.005, and a general sample size n we have that

[tex]\beta(70) = 1 - P\left(-z_{0.995}+\frac{73-70}{9/\sqrt{n}}\right) \\ \\ =1 - P\left(-2.5755+ \frac{3}{9/\sqrt{n}} \right)[/tex]

Since, we want n so that β(70) = 0.01, thus

[tex]1 - P\left(-2.5755+ \frac{3}{9/\sqrt{n}} \right)=0.01 \\ \\ \Rightarrow P\left(-2.5755+ \frac{3}{9/\sqrt{n}} \right)=1-0.01=0.99 \\ \\ \Rightarrow P\left(-2.5755+ \frac{3}{9/\sqrt{n}} \right)=P(2.3262) \\ \\ \Rightarrow -2.5755+ \frac{3}{9/\sqrt{n}}=2.3262 \\ \\ \Rightarrow \frac{3}{9/\sqrt{n}}=4.9017 \\ \\ \Rightarrow \frac{9}{\sqrt{n}} = \frac{3}{4.9017} =0.6120 \\ \\ \Rightarrow \sqrt{n}= \frac{9}{0.6120} =14.7051 \\ \\ \Rightarrow n=(14.7051)^2=216.2[/tex]

so we need n = 217.



Part E

[tex]P-value=P(\bar{X}\leq\bar{x}) \\ \\ =P(\bar{X}\leq72.3)=P\left(z\leq \frac{72.3-76}{9/10} \right) \\ \\ =P\left(z\leq \frac{-3.7}{0.9} \right)=P(z\leq-4.111) \\ \\ =\bold{0.00002}[/tex]

Translate the phrase to mathematical language. Then simplify the expression. The difference between 119 and -54

What is a numerical expression for the​ phrase?

(Do not​ simplify.)

Answers

subtract negative 40 from positive 119 
or simply 
add 119 and 40 

+119 - (-40) 
simplified = 119 + 40 
= 159

True or False?
When rainfall increases, the water level in the lake goes up. Rainfall is the independent variable in this situation.

Answers

False. Rainfall would not increase the amount of water in the lake.

Answer:

It is true, this person was wrong. True was the right answer on the test

Step-by-step explanation:

Find dy/dx by implicit differentiation and evaluate the derivative at the given point.xy = 12, (-4, -3)

Answers

xy=12
xdy/dx + y = 12
xdy/dx = 12 - y
dy/dx= (12-y) /x
dy/dx | x=-4 ,y=-3 = (12-(-3))/(-4)
= (12+3)/-4 = -15/4

Find the inverse of the function h (x)=x^2+6x+9 and indicate restrictions on the domain, if any

Answers

First of all, recognize that h(x) = x^2 + 6x + 9 = (x + 3)^2.

1) Replace h(x) with y:  y = (x+3)^2
2) Interchange x and y:  x = (y+3)^2
3) Solve this new equation for y.  Take the sqrt of both sides:

plus or minus sqrt(x) = y+3, so y = -3 plus or minus sqrt(x)
                              -1                -1
4) replace y with  f     (x).        f    (x) = -3 plus or minus sqrt(x) (answer)

You have 900-grams of an an unknown radioactive substance that has been determined to decay according to

D(t)=900e−0.002415⋅t

where t is in years. How long before half of the initial amount has decayed?

It will take ____ years for half of the initial amount to decay. (Round to 1 decimal place)

Answers

The initial amount is 900, half of this is 450. So set the equation equal to 450 and solve for t.

[tex] 450=900e^{-0.002415t} \\ \\ \frac{450}{900} = e^{-0.002415t} [/tex]

Natural logarithm (ln) is base "e" Euler's number

[tex]ln( \frac{450}{900} = ln( e^{-0.002415t} ) \\ \\ln( \frac{450}{900} ) = -0.002415t \\ \\ \frac{ln( \frac{450}{900}) }{-0.002415} = t \\ \\ t = 287.0 yrs[/tex]

It will take approximately 286.8 years for half of the initial amount (900 grams) to decay.

To find the time it takes for half of the initial amount to decay, we need to find the value of t when D(t) is half of the initial amount (900 grams).

Half of the initial amount = 900 grams / 2 = 450 grams

Now, set D(t) equal to 450 and solve for t:

[tex]450 = 900 * e^{-0.002415 * t}[/tex]

Divide both sides by 900:

[tex]e^{-0.002415 * t} = 0.5[/tex]

To find t, take the natural logarithm (ln) of both sides:

[tex]ln(e^{-0.002415 * t}) = ln(0.5)[/tex]

Now, use the property that [tex]ln(e^x) = x:[/tex]

-0.002415 * t = ln(0.5)

Now, solve for t:

t = ln(0.5) / -0.002415

Using a calculator, we get:

t ≈ 286.8 years

So, it will take approximately 286.8 years for half of the initial amount (900 grams) to decay.

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When circuit boards used in the manufacture of compact disc players are tested, the long-run percentage of defectives is 5%. suppose that a batch of 250 boards has been received and that the condition of any particular board is independent of that of any other board.
a. what is the approximate probability that at least 10% of the boards in the batch are defective?
b. what is the approximate probability that there are exactly 10 defectives in the batch?

Answers

Final answer:

The probability that at least 10% of the boards are defective can be approximated using a normal distribution, while the exact probability of having 10 defectives in the batch can be calculated using the binomial formula. For large samples, normal approximation can be used for convenience.

Explanation:

To find the probability that at least 10% of the boards are defective, we can use the binomial distribution since each board's condition is independent of the other boards. The formula for binomial probability is P(X = k) = (n choose k) * pk * (1-p)(n-k), where n is the number of trials, p is the probability of success on each trial, and k is the number of successes. However, for large sample sizes and when the sample proportion is close to the population proportion, we can approximate the binomial distribution with a normal distribution.

To use the normal approximation, we calculate the mean and standard deviation with the formulas μ = n * p and σ = √(n * p * (1-p)). For the batch of 250 boards with 5% defective rate, μ = 250 * 0.05 = 12.5 and σ = √(250 * 0.05 * 0.95) ≈ 3.4641. We then convert the problem into a z-score and use standard normal distribution tables or software to find the probability that Z > (25 - 12.5)/3.4641.

To find the exact probability of having exactly 10 defectives in the batch, we use the binomial formula since the normal approximation is less accurate for exact probabilities. The calculation would be P(X = 10) = (250 choose 10) * 0.0510 * 0.95240.

Choose the equation below that represents the line passing through the point (−3, −1) with a slope of 4. (1 point) y = 4x − 11 y = 4x + 11 y = 4x + 7 y = 4x – 7 y − 3 = 4(x + 1) y + 3 = 4(x − 1)

Answers

To find the answer, we can use the equation y-y1=a(x-x1), since we already have a point that the line passes through and we know the slope of the line. So, we can plug in our known values into the equation, making it y+1=4(x+3) since the double negatives end up making our values positive. Then, we can continue solving it by distributing the 4, which makes our equation y+1=4x+12. Then, we can subtract 1 from both sides, making the answer y=4x+11.

Pablo bought a desktop computer and a laptop computer. Before finance charges, the laptop cost $250 more than the desktop. He paid for the computers using two different financing plans. For the desktop the interest rate was 8.5% per year, and for the laptop it was 5% per year. The total finance charges for one year were $296 . How much did each computer cost before finance charges?

Answers

a = price of the desktop

b = price of the laptop

now, we know the laptop was more expensive than the desktop by 250 bucks, thus b = a + 250.

for "a", he paid 8.5% in interest, for "b", he paid 5% in interest.

how much is 8.5% of a?  well (8.5/100) * a, or 0.085a.

how much is 5% of b?  well, (5/100) * b, or 0.05b.

now, we know the total charges for financing were $296, that means the interest paid in total was 296, thus whatever "a" or "b" are, we know that  0.085a + 0.05b = 296.

[tex]\bf \begin{cases} \boxed{b}=a+250\\ 0.085a+0.05b=296\\ ----------\\ 0.085a+0.05\left( \boxed{a+250} \right)=296 \end{cases} \\\\\\ 0.085a+0.05a+12.5=296\implies 0.135a=283.5 \\\\\\ a=\cfrac{283.5}{0.135}\implies a=2100[/tex]

how much did the laptop cost?  well, b = a + 250.

Find the surface area of the surface given by the portion of the paraboloid z=3x2+3y2 that lies inside the cylinder x2+y2=4. (hint: convert to polar coordinates after setting up the integral)

Answers

Parameterize the part of the paraboloid within the cylinder - I'll call it [tex]S[/tex] - by

[tex]\mathbf r(u,v)=\langle x(u,v),y(u,v),z(u,v)\rangle=\left\langle u\cos v,u\sin v,3u^2\right\rangle[/tex]

with [tex]0\le u\le2[/tex] and [tex]0\le v\le2\pi[/tex]. The region's area is given by the surface integral

[tex]\displaystyle\iint_S\mathrm dS=\int_{u=0}^{u=2}\int_{v=0}^{v=2\pi}\|\mathbf r_u\times\mathbf r_v\|\,\mathrm du\,\mathrm dv[/tex]
[tex]=\displaystyle\int_{v=0}^{v=2\pi}\int_{u=0}^{u=2}u\sqrt{1+36u^2}\,\mathrm du\,\mathrm dv[/tex]
[tex]=\displaystyle2\pi\int_{u=0}^{u=2}u\sqrt{1+36u^2}\,\mathrm du[/tex]

Take [tex]w=1+36u^2[/tex] so that [tex]\mathrm dw=72u\,\mathrm du[/tex], and the integral becomes

[tex]=\displaystyle\frac{2\pi}{72}\int_{w=1}^{w=145}\sqrt w\,\mathrm dw[/tex]
[tex]=\displaystyle\frac\pi{36}\frac23w^{3/2}\bigg|_{w=1}^{w=145}[/tex]
[tex]=\dfrac\pi{54}(145^{3/2}-1)\approx101.522[/tex]
Final answer:

To find the surface area of the specified area in the paraboloid, convert the original cartesian coordinates to polar coordinates. Then set up and solve the appropriate double integral over the region defined by the circle in polar coordinates.

Explanation:

To find the surface area of a paraboloid z=3x²+3y² inside the cylinder x²+y²=4, you first set up the integral and then convert to polar coordinates. As per the given paraboloid equation, we know that dz/dx = 6x and dz/dy = 6y. Therefore, the differential of surface area in polar coordinates can be given as √(1+(6r*cosø)²+(6r*sinø)²) rdrdø.

Next, integrate this over the area of a circle in polar coordinates, from r=0 to r=2 and ø=0 to ø=2π. The limits of 2 and 2π come from the given cylinder equation x²+y²=4, which represents a circle of radius 2 in polar coordinates.

The final integral in terms of r and ø should yield the desired surface area of the paraboloid which lies inside the cylinder.

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At the beginning of the day the stock market goes up 30 1/2 points. At the end of the day, the stock market goes down 100 3/4 points. what is the change from the high to the end of the day?

Answers

well, is namely their difference, so, let's first convert the mixed fractions to "improper", and subtract.

[tex]\bf \stackrel{mixed}{30\frac{1}{2}}\implies \cfrac{30\cdot 2+1}{2}\implies \stackrel{improper}{\cfrac{61}{2}} \\\\\\ \stackrel{mixed}{100\frac{3}{4}}\implies \cfrac{100\cdot 4+3}{4}\implies \stackrel{improper}{\cfrac{403}{4}}\\\\ -------------------------------\\\\ \cfrac{61}{2}-\cfrac{403}{4}\impliedby \textit{so our \underline{LCD is 4}}\implies \cfrac{(2\cdot 61)~-~(1\cdot 403)}{4} \\\\\\ \cfrac{122-403}{4}\implies \cfrac{-281}{4}\implies -70\frac{1}{4}[/tex]

The stock market changed by a net -70.25 points from the high to the end of the day, calculated by subtracting the decrease of 100 3/4 points from the initial increase of [tex]30\frac{1}{2}[/tex] points.

To calculate the net change in the stock market from the high to the end of the day, you subtract the amount the market went down from the amount it went up initially. First, convert the mixed numbers to improper fractions. 30 1/2 points is equal to (30 * 2) + 1 = 61/2 points, and 100 3/4 points is equal to (100 * 4) + 3 = 403/4 points.

Next, to find the change, you subtract the decrease from the initial increase:

61/2 - 403/4 = (61 * 4) / (2 * 4) - (403 * 2) / (4 * 2)

= 244/8 - 806/8

= (244 - 806) / 8

= -562/8

Finally, simplify the fraction:

= -70.25

So, the stock market changed by a net -70.25 points from the high to the end of the day. This means the market ended lower by 70.25 points from its highest point that day.

the lines below are parallel. if the slope of the green line is -3 what is the line of the red line

Answers

Since they are parallel they have the same slope, thus the slope of the red line is -3.
If two lines are parallel, their slopes are equal.  Thus, the slope of the red line is also -3.

A jar contains 8 marbles numbered 1 through 8. an experiment consists of randomly selecting a marble from the jar, observing the number drawn, and then randomly selecting a card from a standard deck and observing the suit of the card (hearts, diamonds, clubs, or spades). how many outcomes are in the sample space for this experiment? how many outcomes are in the event "an even number is drawn?" how many outcomes are in the event "a number more than 2 is drawn and a red card is drawn?" how many outcomes are in the event "a number less than 3 is drawn or a club is not drawn?"

Answers

There are 8 possible outcomes for a marble being drawn and numbered. 
{1,2,3,4,5,6,7,8}
There are 4 possible outcomes for a card being selected from a standard deck.
{ hearts, diamonds, clubs, spades}
So the number of outcomes in the sample space would be 8 x 4 = 32.

In the event "an even number is drawn", there are only 4 possible outcomes for a marble being drawn, {2,4,6,8}, whereas there are still 4 possible outcomes for a suit. So the number of outcomes in the event is 4 x 4 = 16.

In the event "a number more than 2 is drawn and a red card is drawn", there are 6 possible outcomes for the marble being drawn, {3,4,5,6,7,8}, whereas there are only two possible suits for a card being selected as red, {heart, diamond}. So the number of outcomes in this event is 6 x 2 = 12.

In the event "a number less than 3 is drawn or a club is not drawn", the number drawn could be 1 or 2 whereas a spade/heart/diamond could be selected. So the number of outcomes is 2 x 3 = 6.

The number of outcomes in the sample space is 32. There are 16 outcomes for drawing an even number, 12 outcomes for drawing a number more than 2 and a red card, and 30 outcomes for drawing a number less than 3 or not drawing a club.

To determine the number of outcomes in the sample space for the described experiment, one can use the fundamental counting principle. In this case, there are 8 possible marbles that can be drawn and 4 possible suits from a card in a standard deck. So, the total number of outcomes in the sample space is the product of these possibilities, which is 8 marbles × 4 suits = 32 outcomes.

The event "an even number is drawn" corresponds to drawing one of the even-numbered marbles (2, 4, 6, or 8) and any of the 4 suits from the deck. There are 4 even-numbered marbles and 4 suits, resulting in 4 marbles × 4 suits = 16 possible outcomes.

For the event "a number more than 2 is drawn and a red card is drawn," we consider only marbles numbered 3 to 8 (6 possibilities) and the 2 red suits (hearts and diamonds) from the deck, resulting in 6 marbles × 2 red suits = 12 outcomes.

Finally, the event "a number less than 3 is drawn or a club is not drawn" includes two scenarios. The first is drawing marble number 1 or 2 (2 possibilities) and any of the 4 suits (8 outcomes). The second scenario includes drawing any of the 8 marbles and any of the 3 non-club suits (24 outcomes). Since the two scenarios are mutually exclusive, you add the outcomes: 8 + 24 = 32 outcomes. However, you must subtract the overlapping outcomes of drawing 1 or 2 with non-club suits (2 outcomes), resulting in 32 - 2 = 30 distinct possible outcomes for this event.

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