A 0.35 kg ball moving in a circle at the end of a string has a centripetal acceleration of 5 m/s^2. What is the magnitude of the centripetal force exerted by the string on the ball to produce this acceleration?

The apparent shift in measurement is called Parallax.

Parallax is a displacement or difference in the apparent position of an object viewed along two different lines of sight, and is measured by the angle or semi-angle of inclination between those two lines.

Parallax is the apparent shift of an object's position relative to more distant background objects caused by a change in the observer's position.

In other words, parallax is a perspective effect of geometry.

The apparent shift of an observed object's position resulting from a change of perspective is called "parallax." With the previous demonstration, we've established an inverse relationship.

The closer the object, the greater the parallax angle. We can apply the same principle to the stars.

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Answer: A (Incident ray).

Explanation:

Answer: 5.17 m

Explanation:

The football reaches its maximum height when the vertical component of the velocity is zero:

[tex]V_{y}=0 m/s[/tex]

This is exactly at the point where the football stops and then begins to fall thanks to the acceleration due gravity.

So, we can use the following equation:

[tex](V_{y})^{2}=(V_{oy})^{2}-2gy_{max}[/tex]

Where:

[tex]V_{y}=0[/tex] is the final velocity

[tex]V_{oy}=V_{o} sin(32\°)[/tex] is the vertical component of the initial velocity

[tex]V_{o}=19 m/s[/tex] is the initial velocity

[tex]g=9.8 m/s^{2}[/tex] is the acceleration due gravity

[tex]y_{max}[/tex] is the football's maximum height

Isolating [tex]y_{max}[/tex]:

[tex]y_{max}=\frac{(V_{o} sin(32\°))^{2}}{2g}[/tex]

[tex]y_{max}=\frac{(19 m/s sin(32\°))^{2}}{2(9.8 m/s^{2})}[/tex]

Finally:

[tex]y_{max}=5.17 m[/tex] This is the football's maximum height

Answer:  " 1.03 " .

____________________________________

Explanation:

_____________________________________

When we add "measured" or "obtained values" ; the rules for "signficant digits" (also known as "significant figures" ; or "sig figs")  are different from the rules we use when we multiply "measured or obtained values".

We are given 2 (two) "measured or obtained values" ; and we are asked to add these values together using the "significant digit rules.

In this case, we add up the "sum total value" of all the values—Not taking into account the number of significant figures.  Then, we take that "sum value" ; and we round that value to the number of "decimal places" that corresponds to the the number of decimals places in the "measured/obtained valued" that occurs in the value using to calculate the sum —the one that also happens to have the least number of significant digits among all the values used to calculate the "sum total".

As such:

_____________________________________

              1.0090 cm

+            0.02      cm          

      ________________    

           1.0290  cm.                                    

 →  Now, there were two (2) values used to calculate the "sum total" ;

1)  1.0090 cm ; which has 5 (five) significant digits.

2)  0.02 cm ;  which as 1 (one)  significant digits.

_____________________________________

 So, " 1" is less than "5" ;  so:  " 0.02" is the value within the calculations used to find the sum total — that has the "least" number of significant digits.    

  →  " 0.02 " ;  happens to have 2 (two) decimal spaces.

_____________________________________

So, we take the "sum total" :

      →   "  1.0290 cm " ;

      →  And round this number to:  " 2 (two) decimal places:

            → 1.029... ;  

      →  If the number after the second decimal place is from "1 to 4" ; we round down.  If the number after the second decimal place is

from "5 and 9" ; to round up.  Since the third decimal place is:  "9" ;

  [Note:  " 1.029.." ;  is between "5 to 9" } ; we round up:

→  The answer is:  " 1.03 " .

_____________________________________

Hope this is helpful to you!

     Wishing you the best!

_____________________________________

Answer:

The kinetic energy gained is 40[J]

Explanation:

This is a problem that applies the work and energy conservation. We must analyze the initial and final positions as well as the forces that act on the couch during displacement.

The working and energy conservation theorem says:

[tex]E_{k1} + W_{1-2}= E_{k2}[/tex]

The above equation tells us that kinetic energy plus the work done to move an object from one position to another will be equal to kinetic energy in the last position.

The kinetic energy in the initial position is zero since the couch is at rest, Ek1=0

The work will be given by the force that drives the couch multiplied by the distance, and the friction force that acts in the opposite direction to the displacement.

[tex]0+(200-180)*2= Ek2\\Ek2=20*2= 40 [J][/tex]

The frequency of light changes when it is emitted from a moving source. When a galaxy is moving away from Earth, the light it emits becomes redshifted, meaning the frequency decreases. In this case, the observed frequency when the light reaches Earth is approximately 4.945 * 10^14 Hz. Option a is correct.

The frequency of light changes when it is emitted from a moving source. This change in frequency is known as the Doppler effect. When a galaxy is moving away from Earth, the light it emits becomes redshifted, meaning the frequency decreases. To calculate the new frequency, we can use the formula f' = f/(1+v/c), where f' is the observed frequency, f is the emitted frequency, v is the speed of the galaxy, and c is the speed of light.

In this case, the galaxy is moving away from Earth with a speed of 3325 km/s. The emitted frequency is 5.00 * 10^14 Hz. Plugging these values into the formula, we get f' = 5.00 * 10^14 Hz / (1 + 3325 km/s / 3 * 10^5 km/s). Simplifying this expression, we find that the observed frequency when the light reaches Earth is approximately 4.945 * 10^14 Hz.

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A) 4.945 x [tex]10^{14}[/tex] Hz is correct option. Using the Doppler effect formula, we calculate the observed frequency of the light from a galaxy receding at 3325 km/s.

To determine the frequency of light from a receding galaxy as observed on Earth, we use the Doppler effect formula for light:

[tex]f_{obs}[/tex] = [tex]f_{em}[/tex] x (1 - v/c)

Where:

Let’s substitute the values into the formula:

[tex]f_{obs}[/tex] = 5.00 x [tex]10^{14}[/tex] Hz x (1 - 3325000 m/s / 3.00 x [tex]10^{8}[/tex] m/s)

[tex]f_{obs}[/tex] = 5.00 x [tex]10^{14}[/tex] Hz x (1 - 0.01108333)

[tex]f_{obs}[/tex] ≈ 4.945 x [tex]10^{14}[/tex] Hz

Therefore, the frequency of the light observed on Earth is 4.945 x [tex]10^{14}[/tex] Hz.

It is really important to cite units while engaging with scientific problems as they help in evaluating the right solution without any mistake.

Explanation:

While solving analytical questions to evaluate the right answers, the units play a crucial role in the equations. With the help of units in the formula, we can easily judge whether we are placing the values in the same parameters and hence, lessen the probabilities of wrong answers.

For example, while adding two measurements i.e. 4 m and 36 cm; if we don't consider the units and move on with the addition, the answer will be 40. Now, the first thing is that we are adding two measurements of different parameters. Besides this, the answers will be wrong i.e. 4.36 m is the correct answer instead of 40 and that too without mentioning the unit.

The chances of selecting the wrong answer are more when we need to choose options out of multiple choices because here we often get confused. That's why we should always make sure that we approach the scientific questions along with the units.

Answer:

The different values are in the located in the word document

Explanation:

In the attached document in  word, we can find each of the conversion for each one of the quantities.

In the given physics problem, the ball comes to a stop at the highest point. This is because it has transformed all of its kinetic energy into potential energy, and has no more energy to continue moving upwards, as there is no energy transfer with either the track or the air.

In this physics problem, the ball on the track is an example of a system that conserves energy. Since there is no energy transfer with either the track or the surrounding air, the total mechanical energy of the ball, which comprises potential and kinetic energy, remains constant throughout its motion. Potential energy is energy due to height, and kinetic energy is energy due to motion.

To place the dot at the highest point the ball will reach, you identify where the ball has maximum potential energy and minimum kinetic energy because at the highest point, the ball momentarily stops and hence, kinetic energy is zero.

Therefore, the ball will stop at the highest point because it has converted all its kinetic energy (energy of motion) into potential energy (energy stored due to its position) and has no more energy left to continue moving upwards. At this point, it starts converting its potential energy back into kinetic energy as it moves downwards, hence it starts moving back down the track.

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The ball will reach the highest position at the same height as position B because of the conservation of mechanical energy. At this point, all kinetic energy converts back to potential energy, causing the ball to momentarily stop before reversing direction. This principle assumes no energy losses in the system.

To determine the highest position the ball will reach on the track before stopping and reversing direction, we need to consider the conservation of energy principle. In this scenario, the total mechanical energy (sum of potential and kinetic energy) remains constant because no energy is transferred between the ball and the track or the air.

When the ball starts from rest at position B, it possesses only potential energy and no kinetic energy. As the ball moves downward, it loses potential energy but gains kinetic energy, and as it moves upward, it loses kinetic energy and gains potential energy. The ball will reach the same height on the opposite side of the track as it started, assuming no energy losses. Therefore, the highest position the ball will reach will be the same height as position B.

The ball stops at this highest position because all of its kinetic energy is converted back to potential energy at that point, making its speed momentarily zero before it reverses direction. This illustrates the conservation of mechanical energy where the initial and final heights are the same when no external forces are acting on the system.

Answer:

(D) all of the above

Explanation:

All of the choices describe matter.

Answer:

longitudinal waves have those properties

Answer:

There are more than 2 but you are probably thinking of kinetic and static friction.  Kinetic friction is the friction between objects as they are moving.  Static friction keeps something in place and resists the movement.  Static friction can be overcome by force to move the object.

Explanation:

Answer:

8.25 m/s

Explanation:

From the fundamental equation of motion, velocity is rate of change of displacement per unit time

[tex]Velocity=\frac {Displacement}{time}[/tex]

Given information

Displacement=2862 m

Time=347 s

Substituting the given information we obtain

[tex]Velocity=\frac {2862 m}{347 s}=8.247838617\approx 8.25 s[/tex]

Answer:

Speed at the bottom of the roller coaster = 49.79 m/s

Explanation:

A new ride being built at an amusement park includes a vertical drop of 126.5 meters. Starting from rest, the ride vertically drops that distance before the track curves forward.

We have to find the speed at the bottom.

Here the gravitational energy fully converts to kinetic energy, so we equate it.

Gravitational energy = [tex]m\times g\times h[/tex]

Kinetic energy = [tex]0.5 \times m\times v^{2}[/tex]

[tex]m\times g\times h[/tex] = [tex]0.5 \times m\times v^{2}[/tex]

[tex]9.8\times 126.5 = 0.5\times v^{2}[/tex]

[tex]v^{2}[/tex] = 2479.4

Velocity, v = 49.79 m/s

Answer:

Horizontal acceleration=0

Explanation:

Horizontal Launching

When an object is launched horizontally at a certain speed [tex]v_o[/tex], only one force will be acting throughout the whole duration of the motion: the force of gravity. If no effect of the wind is to be considered, then the horizontal speed will not change over time. It means the horizontal acceleration is zero. Please note the vertical acceleration is not zero, it is in fact, the acceleration of gravity (0.8 m/sec^2)

According to the Law of Conservation of Mass, the mass of the rust should be greater than the original mass of the iron nail, because the mass of the oxygen and water that form the rust are added to the mass of the iron nail.

The principle at play here is the Law of Conservation of Mass, which states that matter cannot be created or destroyed in a chemical reaction. In this scenario, an iron nail is reacting with oxygen and water from the environment to form rust, or iron(III) oxide.

If the nail were left to rust completely, the mass of the rust would be greater than the original mass of the nail. This is because the mass of the oxygen and water that combines with the iron is added to the mass of the nail to form the rust. The additional mass comes from the oxygen atoms in the air and in the water that combine with the iron atoms in the nail.

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7000 Joules

We are given;

But, Force = mass × g (taking g as 10 N/kg)

Assuming we are given the distance moved by the object as 7 m

We can calculate the work done by the force

We need to know that;

Work done = Force × distance

Therefore;

Work done = 1000 N × 7 m

                   = 7000 Joules

Therefore, the work done by the force is 7000 Joules

The distances are:

- E and F: 4 units.

- C and D: 5 units.

- G and H: 3 units.

- A and B: 6 units.

Why?

We can find the distance between each pair of points using the following formula:

[tex]d(P_1,P_2)=\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}[/tex]

So, calculating we have:

- E(-2, -1) and F(-2, -5):

[tex]d(E,F)=\sqrt{(-2-(-2))^{2}+(-5-(-1))^{2}}\\\\d(E,F)=\sqrt{0+(-5+1)^{2}}=\sqrt{0+(-4)^{2}}=\sqrt{16}=4units[/tex]

- C(-4, 1) and D(1, 1):

[tex]d(C,D)=\sqrt{(1-(-4))^{2}+(1-(1))^{2}}\\\\d(C,D)=\sqrt{(5)^{2}+0^{2}}=\sqrt{25+0}=\sqrt{25}=5units[/tex]

- G(3, -5) and H(6, -5):

[tex]d(G,H)=\sqrt{(6-(3))^{2}+(-5-(-5))^{2}}\\\\d(G,H)=\sqrt{(3)^{2}+0^{2}}=\sqrt{9+0}=\sqrt{9}=3units[/tex]

- A(5, 4) and B( 5, -2):

[tex]d(A,B)=\sqrt{(5-(5))^{2}+(-2-(4))^{2}}\\\\d(A,B)=\sqrt{0+(-6)^{2}}=\sqrt{0+36}=\sqrt{36}=6units[/tex]

Have a nice day!

Answer:

G(3, -5) and H(6, -5) ------>3 units

arrowRight

E(-2, -1) and F(-2, -5)------->4 units

arrowRight

A (5, 4) and B( 5, -2)------->6 units

arrowRight

C(-4, 1) and D(1, 1)---------->5 units

arrowRight

Explanation:

43.48 mph

We are given;

First instance;

Second instance;

We are required to determine the average speed for the entire journey.

Time = Distance ÷ speed

First instance

Time = 50 miles ÷ 40 mph

        = 1.25 hours

Second instance;

Time = 20 miles ÷ 55 mph

        = 0.36 hours

Therefore;

Total distance = 70 miles

Total time = 1.25 hrs + 0.36 hr

               = 1.61 hrs

Thus;

Average speed = 70 miles ÷ 1.61 hrs

                          = 43.478 miles per hour

                          = 43.48 mph

Answer:

37.1

Explanation:

mass of 2 atoms of chlorine-35 = 2× 35 = 70

mass of 5 atoms of chlorine-38 = 5 × 38 =  190

average mass = total mass / total number of atoms

                        = (70 +190) / (2 +5)

                        =  260 / 7

                        = 37.143

                        = 37.1

Final answer:

The average mass of chlorine-35 and chlorine-38 can be calculated using their respective atomic masses and percent abundances. The average mass of chlorine is 35.46 amu.

Explanation:

The average mass of chlorine can be calculated using the information provided. Chlorine-35 has an atomic mass of 34.969 amu and a percent abundance of 75.77%. Chlorine-38 has an atomic mass of 36.966 amu and a percent abundance of 24.23%. To calculate the average mass, we multiply the fraction of chlorine-35 (0.7577) by its mass, and add it to the fraction of chlorine-38 (0.2423) multiplied by its mass.

Therefore, the average mass of chlorine is: (0.7577 * 34.969) + (0.2423 * 36.966) = 35.46 amu.

Answer:

20N option C

Explanation:

10× 2

Answer:

Option D)The date of future earthquakes cannot be precisely predicted.

Explanation:

Natural disasters take place without being able to be precisely predicted at times. For example, the volcanoes can more or less likely to be predicted due to the plate tectonics and profiling the history of the volcano.

However, earthquakes cannot be predicted. For example, the massive earthquake in Lisbon in Portugal hit unexpectedly. In addition, Japan was hit by an earthquake which could not be predicted. Thus, an earthquake's future is unpredictable.

D) The correct statement is that the date of future earthquakes cannot be precisely predicted. This is due to the complexity of the geological processes involved, which also explains why the other statements are false.

Among the given statements, it is true that the date of future earthquakes cannot be precisely predicted (Option D). This is due to the complex nature of geological processes. Volcanic eruptions and earthquakes do not always coincide (Option A).

Earthquakes can occur not only on dry land but also under water, at much greater depths than 100 meters (Option B). Earthquakes also do not occur at regular, predictable intervals (Option C).

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Scientists measure the time between the arrival of an earthquake's __P____ and ___S____ waves to help determine the distance between the recording seismograph and the earthquake epicenter.

Explanation:

P- (compressional) and S- (shear) waves produced in earthquakes travel at different speeds. P waves are faster than S waves and hence will be detected first by a seismograph after an earthquake. The further away a seismograph is from the epicenter of an earthquake,  the longer the time difference between the two (2) waves will be.

Using several, at least 3, seismographs located at different geoghraphical locations and detecting earthquakes, geologists can extrapolate the epicenter of an earthquake using the time differences in arrivals of the two waves in each of the seismographs, using the mathematics of triangulation.

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The time between the arrival of P waves and S waves, recorded by seismographs, is used to determine the distance to an earthquake's epicenter, with the precision being affected by the accuracy of wave speed and arrival time measurements.

Scientists gauge the distance to an earthquake's epicenter by measuring the time between the arrival of an earthquake's P waves and S waves. Seismographs can record these waves with a precision of 0.100 seconds. Given that P waves travel at 7.20 km/s and S waves travel at 4.00 km/s, the time difference recorded on seismograms allows scientists to calculate the distance to an epicenter with considerable accuracy. However, the precision of this distance measurement can be limited by the exactitude of the wave speed measurements and the timing of their arrivals.

Furthermore, the tracking of seismic waves can also be significant for monitoring underground nuclear tests. If there is uncertainty in the speeds of S and P waves, or in the measurement of their arrival times, this poses a limitation in accurately determining the source of seismic energy, which could hinder detection capabilities for such underground activities.

Answer:

3

3.75

Explanation:

First ball

Givens

a = 5m/s^2

m = ??

F = 15N

Formula

F = m*a

Solution

15 = m * 5

15/5 = m

m = 3 kg

Second ball

Givens

a = 4m/s^2

m = ??

F = 15N

Formula

F = m*a

Solution

15 = m * 4

15/4 = m

m = 3.75 kg

The law of inertia states that an object:

e. Will do all of the above.

Why?

Newton's First Law or the Law of inertia, states that an object at rest will always remain at rest if a force does not act on/upon it. Also, when an object is moving describing a straight line, if a force does not act upon it, it will keep the motion forever.

According to the Law, if an object is moving at constant velocity (same speed and same direction) it will keep the motion unless an outside force acts on it.

So, the correct option will be:

e. The object will do all of the above options.

Have a nice day!

The law of inertia states that an object at rest will remain at rest unless acted on by an outside force, while an object in motion will continue moving in a straight line at a constant speed unless acted on by an outside force.

The law of inertia, also known as Newton's first law of motion, states that an object at rest will remain at rest unless acted on by an outside force. Similarly, an object in motion will continue moving in a straight line at a constant speed unless acted on by an outside force. This law applies to all objects and is a fundamental principle in physics.

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Answer:

3 m/s

Explanation:

average  speed = distance traveled / total time taken

                           = 6m/ 2s

                           = 3 m/s

Answer:

Pressure = 20 MPa

Explanation:

Given:

Force acting on the shoe is, [tex]F=100\ N[/tex]

Area of shoe on which the force acts is, [tex]A= 0.05\ cm^2[/tex]

Now, first we convert the area into its standard unit of m².

We have the conversion factor as:

1 cm² = [tex]10^{-4}\ m^2[/tex]

Therefore, the area of shoe in square meters is given as:

[tex]A=0.05\times 10^{-4}\ m^2\\A=5\times 10^{-6}\ m^2[/tex]

Now, pressure on the shoe is given as:

[tex]P=\frac{Force}{Area}\\P=\frac{F}{A}[/tex]

Plug in 100 N for 'F', [tex]5\times 10^{-6}[/tex] for 'A' and solve for 'P'. This gives,

[tex]P=\frac{100\ N}{5\times 10^{-6}\ m^2}\\P=20\times 10^{6}\ N/m^2[/tex]

Now, we know that,

[tex]10^{6}\ N/m^2=1\ MPa\\\therefore 20\times 10^{6}\ N/m^2=20\times 1\ MPa=20\ MPa[/tex]

Therefore, the pressure acting on the shoe is 20 MPa.

a) The impulse is 76.5 Ns

b) The average force is 546.4 N

c) The final speed is 31.5 m/s

Explanation:

a)

The impulse exerted on an object is defined as

[tex]J=\int F\Delta t[/tex]

where

F is the magnitude of the force exerted on the object

[tex]\Delta t[/tex] is the time interval during which the force is applied

If we consider a graph of the force applied vs time, it follows that the impulse exerted is equal to the area under the graph.

Therefore, in this problem, we can calculate the impulse by computing the area under the graph. We have a trapezium, whose bases are

[tex]B=0.14-0 = 0.14s\\b=8-5=3s[/tex]

and whose height is

[tex]h=900 N[/tex]

Therefore, the area (and the impulse) is

[tex]J=\frac{(B+b)h}{2}=\frac{(0.14+0.03)(900)}{2}=76.5 Ns[/tex]

b)

In this problem, the force applied is not constant. However, we can rewrite the impulse also as

[tex]J=F_{avg} \Delta t[/tex]

where

[tex]F_{avg}[/tex] is the average force exerted during the whole time [tex]\Delta t[/tex]

In this problem we have

J = 76.5 Ns is the impulse (calculated in part a)

[tex]\Delta t = 0.14 s[/tex] is the time interval

Solving for the average force, we find

[tex]\Delta t = \frac{J}{F_{avg}}=\frac{76.5}{0.14}=546.4 N[/tex]

c)

According to the impulse theorem, the impulse exerted on an object is equal to the change in momentum of the object:

[tex]J=\Delta p = m(v-u)[/tex]

where

m is the mass of the object

v is the final velocity

u is the initial velocity

In this problem, we have

J = 76.5 Ns

m = 3.0 kg is the mass

u = 6.0 m/s is the initial velocity

Solving for v, we find the final velocity (and speed):

[tex]v=u+\frac{J}{m}=6.0+\frac{76.5}{3}=31.5 m/s[/tex]

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Answer:

Distance-           The length along a path between two points .

Velocity-            The rate and direction at which an object moves .

Displacement-  The net change in position of an object .

Vector-               A measurement that has both magnitude and direction .

Speed-               Measure of the rate at which an object changes position .

Momentum-      The mass of an object multiplied by its velocity.

Explanation:

Vector: A physical quantity having both magnitude and direction is called Vector quantity. Example: Displacement, Velocity, Acceleration, Force etc.

On the other hand , quantity having only magnitude is called Scalar. Example: Distance, Speed, Time, Current etc.

Distance: The totle length of path traversed by a body in certain time is called distance. It is scalar quantity as it has only magnitude. SI unit of distance is meter.

Displacement: It is defined as change in position of a body in given period of time. Actually it is the distance between initial and final position along with given direction. So it is vector quantity. SI unit is meter.

Speed: The rate at which distance is traveled with respect to time is called speed.It is scalar quantity. SI unit is meter/second.

                                    [tex]Speed=\frac{Distance}{Time}[/tex]

Velocity: It can be defined as rate of change in position or displacement with respect to time.It is vector quantity. SI unit is meter/second.

                                    [tex]Velocity=\frac{Displacement}{Time}[/tex]

Momentum: The amount of motion contain in a body is the momentum. It is defined as product of mass and velocity. It is vector quantity. SI unit is kg.meter/second

                                    Momentum=Mass×Velocity

Answer: The answer above is correct! I got 100% :))

Explanation:

Answer: D

Explanation:

A -amount of work

F-force

s-distance

If you keep same Force(F) and increase distance(s), amount of work will increase, according to:

A=F*s

Answer:

D) The amount of work will increase

Explanation:

Took test