A 150 n sled is being pulled up a 28 ° rough ramp at constant speed by a force of 100 n parallel to the ramp. with what acceleration will the crate slide down, if it is released at some point on the ramp?

Answers

Answer 1
the answer:

we can use newton's second law for finding the value of acceleration

that is    F=MxA
M the mass
A is the acceleration

F= P-Fk,  Fk= -Mgcosθμ and P=Mgsinθ
μ is the coefficient of friction

The value of μ can be found with the above condition
(pulled up a 28 ° rough ramp at constant speed)
this implies the acceleration is equal to zero
 100N - mgsin(28°) -mgcos(28°)μ = 0 , from where 
μ= [100N - mgsin(28°)] / mgcos(28°)
μ=0.2

and then, 
F=MxA= Mgsinθ -Mgcosθμ   finally  A=gsin28° -gcos28° x0.2 =2.6m/s²

Answer 2
Refer to the diagram shown below.

θ = 28°, the angle of the slope.
W = 150 N, the weight of the sled.
The normal reaction is
N = W cosθ = 150*cos(28) = 132.442 N
The component of the weight acting down the plane is
F = W sin θ = 150*sin(8) = 70.421 N

Case A; The sled is pulled up the slope.
Because the sled is in dynamic equilibrium, therefore
F + μN = 100
where μ = the kinetic coefficient of friction.
That is,
70.421 + 132.442μ = 100
μ = (100 - 70.421)/132.442 = 0.2233

Case B: The sled accelerates down the slope.
When the applied force of 100 N is removed, the sled accelerates down the slope due to its weight acting down the slope. The motion is opposed by kinetic friction.
That is,
Wsinθ - μWcosθ = ma
where
m = (150 N)/(9.8 m/s²) = 15.306 kg, the mass of the sled
a =  the acceleration of the sled

Therefore
70.421 - 0.2233*132.442 = 15.306*a
a = 40.8467/15.306 = 2.669 m/s²

Answer:2.67 m/s²  (nearest hundredth)

A 150 N Sled Is Being Pulled Up A 28 Rough Ramp At Constant Speed By A Force Of 100 N Parallel To The

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Magnetic field lines curve out from one pole and return to the same pole.
t/f

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That statement is a big fat prevarication.
Magnetic field lines start at one Pole and end at the OTHER one.

Answer:

the answer is false

Explanation:

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If f = 136 lb , determine the resultant couple moment.

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136lb?? I'm so confused rn!! I'm super sorry!!

A golf ball is hit with an initial speed of 33 m/s at an angle less than 45∘ above the horizontal.

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what is the question?

A second order chemical reaction involves the interaction (collision) of one molecule of a substance p with one molecule of a substance q to produce one molecule of a new substance x; this is denoted by p + q → x. suppose that p and q, where p = q, are the initial concentrations of p and q, respectively, and let x(t) be the concentration of x at time t. then p − x(t) and q − x(t) are the concentrations of p and q at time t, and the rate at which the reaction occurs is given by the equation dx/dt = α(p − x)(q − x), (i) where α is a positive constant. (a) if x(0) = 0, determine the limiting value of x(t) as t → ∞ without solving the differential equation. then solve the initial value problem and find x(t) for any t.

Answers

From (i) it’s indistinct that there are two equilibrium solutions x = p and x = q. Since p 6= q we might as well accept p < q (or else we just switch the roles of p and q). By examining the derivatives of f(x) = α(p − x)(q − x) at p and q we see that f 0 (p) = −α(q − p) < 0 and f 0 (q) > 0. Therefore x = p is an asymptotically stable solution and we expect x → p as t → ∞

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Rosa uses the formula (vi cos)t to do a calculation. Which value is Rosa most likely trying to find? the vertical acceleration of a projectile launched at an angle the vertical acceleration of a projectile launched horizontally the horizontal displacement of a projectile launched at an angle the horizontal displacement of a projectile launched horizontally

Answers

the horizontal displacement of a projectile launched at an angle

If Rosa uses the formula (vi cos)t to do a calculation, then Rosa most likely trying to find the horizontal displacement of a projectile launched at an angle to the horizontal, therefore the correct answer is option C.

What is a projectile motion?

It can be defined as the motion of any object or body when thrown from the earth's surface and follows any curved path under the effect of the gravitational force of the earth.

The horizontal component of the velocity during any projectile motion is constant and is given by vicosθ.

Thus, If Rosa uses the formula (vi cos)t to do a calculation, then Rosa most likely trying to find the horizontal displacement of a projectile launched at an angle to the horizontal, therefore the correct answer is option C.

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A race car is moving with a velocity of 144 kilometers/hour. The driver applies the brakes, and the car comes to a halt in 12.0 seconds. What is the average acceleration of the car during those 12.0 seconds? –12.0 meters/second2

Answers

First, we need to convert the units of the given velocity to m/sec
144 km/hr = (144 km / hr) x (1000 m / 1 km) x (1 hr / 3600 s) = 40 m/s

Now, to solve this question, we can use one of the equations of motion:
 a = (Vf - Vi) / t where:
a is the acceleration we are looking for
Vf is the final velocity of the car = 0 m/sec
Vi is the initial velocity of the car = 40 m/sec
t is the time taken = 12 seconds

Substitute with these givens in the above equation to get the acceleration as follows:
a = (0-40)/12 = -3.334 m/s^2

if you push a block across the floor with constant force the block will

Answers

Move I'm not sure if that is what you were looking for though

what energy is the flow of electrons that creates a charge, one of the main forms of energy

Answers

What energy is the flow of electrons that creates a charge, one of the main forms of energy=  Electrical Energy

Answer:

electricity

Explanation:

just got the question and it was right

A car goes from 40n/s to 60 m/s in 8s the acceleration of the car is

Answers

Acceleration= change in velocity/ change in time.

60-40=20 m/s (change in speed)
Time= 8 seconds

20/8= 2.5
Acceleration= 2.5 m/s^2

Hope this helps! :)
The acceleration is the change in velocity. The kinematic formula that is used is a=Δv/Δt.
Δ- stands for change in velocity 
given: vi=40 m/s, vf=60 m/s, t= 8s
Δv= vf-vi= 60-40=20
a=20/8=2.5
a=2.5 m/s^2

The branch of mechanics dealing with the mathematical methods of describing motion is calle

Answers

This branch of mechanics is called kinematics. A way to remember this is to remember that energy in motion is called kinetic energy. So, kinematics deals with describing motion. 

An airport has runways only 198 m long. a small plane must reach a ground speed of 39 m/s before it can become airborne. what average acceleration must the plane's engines provide if it is to take off safely from its airport? answer in units of m/s 2 .

Answers

s: 198 m 
v=39 m/s 
u=0
t=? 
a=?

v²=u²+2as
(39)²=(0)²+2(a)(198) 
1521=396a
1521/396=a
3.84 m/s^2 = a 

Hope I helped :) 

What determines the amount of chemical energy asubstance has

Answers

The amount of chemical energy a substance has is determined by its molecular structure and the type of chemical bonds it contains.

1. Molecular Structure:

  - The arrangement of atoms within a molecule determines its potential energy content.

  - Different substances have varying numbers and arrangements of atoms, leading to differences in chemical energy.

2. Type of Chemical Bonds:

  - Chemical energy is stored in the bonds between atoms within molecules.

  - The strength and type of chemical bonds, such as covalent bonds, ionic bonds, and hydrogen bonds, dictate the amount of energy stored in the substance.

  - Stronger bonds require more energy to break and thus store more chemical energy.

3. Potential Energy:

  - Chemical energy represents the potential energy stored within a substance's chemical bonds.

  - When chemical bonds are broken during a chemical reaction, the stored energy is released as heat or used to perform work.

4. Examples:

  - Substances with complex molecular structures and strong chemical bonds, such as hydrocarbons in fossil fuels, tend to have high chemical energy content.

  - Conversely, simpler molecules with weaker bonds, such as gases like hydrogen and oxygen, have lower chemical energy content.

Therefore, the amount of chemical energy a substance possesses is determined by its molecular structure and the type of chemical bonds it contains, with stronger bonds and more complex structures generally correlating with higher chemical energy content.

The complete Question is given below:

What determines the amount of chemical energy a substance has?

What is the connection between the liver (organ), UV radiation (sunlight), and bone tissue

Answers

The answer to this question would be: vitamin D

The UV is needed by the skin to make previtamin D3. Previtamin D3 or cholecalciferol made from the skin will be changed in the liver into 25- hydroxyvitamin D3 and then sent to the kidney to be changed into 1,25- dihydroxyvitamin D3. The last change in the kidney will active the vitamin D. Vitamin D has a role in the calcium absorption which was will strengthen the bone tissue.

What kind of materials can become electrically charged when they are rubbed together?

Answers

Negatively charged particles called electrons move from one material to the other. But i am not sure what kind of material 

Answer:

When insulating materials rub against each other, they may become electrically charged . Electrons , which are negatively charged, may be 'rubbed off' one material and on to the other. The material that gains electrons becomes negatively charged.

Explanation:

[tex]hope \: it \: helps \: you \: [/tex]

An object starts from rest and falls under the influence of gravity. draw graphs of its speed and the distance it has fallen as a function of time from t=0 to t=5s

Answers

For an object that is under the pull of only the force of gravity, the motion is called free-fall. The equations that would allow us to calculate for the speed and distance is,

        Speed = gt

Where g is the acceleration due to gravity and the t is the time.

For the distance, it is calculated through the equation,

     Distance = vt + 1/2gt^2

Where v is the initial velocity and is equal to zero.

 

The graphs are attached.



______ interference occurs when two waves overlap and the resulting wave has a larger amplitude.

Answers

Answer: The correct answer is constructive interference.

Explanation:

Interference is the phenomenon in which there is superposition of the two waves. Interference are of two types: Constructive interference and Destructive interference.

Constructive interference occurs when the there is a superposition of the two waves. The resulting wave has a large amplitude.

Destructive interference occurs when the there is a superposition of the two waves. The resulting wave has a low amplitude.

Therefore, Constructive interference occurs when two waves overlap and the resulting wave has a larger amplitude.

Answer:

B. Constructive

A favorable entropy change occurs when δs is positive. what can be said about the order of the system when δs is positive?

Answers

Final answer:

A positive entropy change (delta S) indicates that the system has become less ordered, as there is an increase in the number of possible microstates. This is aligned with the Second Law of Thermodynamics, which states that entropy increases in spontaneous processes, leading to greater disorder.

Explanation:

When a system undergoes a change and the entropy change (δS) is positive, this implies that the order of the system has decreased. This is because positive entropy reflects an increase in the number of microstates or possible configurations that the system can adopt, leading to a less ordered, more random state. A common example is the melting of a solid into a liquid where the rigid structure of the solid is lost, providing the particles more freedom to move in the liquid state, which translates into an increased entropy.

As per the Second Law of Thermodynamics, for all spontaneous processes in the real world, the change in entropy is positive (dδS > 0), which is consistent with the natural tendency for systems to move towards greater disorder and randomness. This concept is fundamental in predicting the spontaneous direction of chemical and physical processes. For instance, when a liquid freezes into a solid, the process is accompanied by a negative entropy change, signifying increased order in the system.

Final answer:

A positive entropy change (δS > 0) means that the order of the system has decreased, leading to a more disordered and randomized state with more microstates. This is in line with the Second Law of Thermodynamics, which predicts that the entropy of an isolated system tends to increase in spontaneous processes.

Explanation:

When the entropy change (δS) is positive, it indicates that the order of the system has decreased. This is because a positive δS suggests that the number of microstates and, therefore, the randomness of the system has increased. For example, when a solid changes into a liquid, there is an increase in entropy because the liquid state allows the particles more freedom of movement and positioning, leading to a higher number of microstates compared to the solid state. If the process were reversed and the liquid turned into a solid, δS would be negative, signifying a decrease in entropy as the system becomes more ordered.

Furthermore, the Second Law of Thermodynamics asserts that for any spontaneous process, the entropy of an isolated system will increase. This means the system will move towards a state with more microstates or higher disorder. It aligns with the observation that in irreversible processes, entropy tends to increase, indicating a spontaneous change in an isolated system.

In conclusion, a positive entropy change (δS > 0) aligns with the expectation that there are more microstates available in the final state compared to the initial one, resulting in a decrease in the orderliness of the system. The increase in entropy reflects the fundamental tendency for systems to evolve towards states of higher disorder and randomness.

The position of a 2.75×105n training helicopter under test is given by r⃗ =(0.020m/s3)t3i^+(2.2m/s)tj^−(0.060m/s2)t2k^. part a find the net force on the helicopter at t=5.0s.

Answers

The net force on the helicopter at t=5.0s = F = 1.65.10⁴i - 3.3.10³k

Further explanation

Newton's 2nd law explains that the acceleration produced by the resultant force on an object is proportional and in line with the resultant force and inversely proportional to the mass of the object

[tex]\large{\boxed{\bold{a~=~\frac{F}{m} }}}[/tex]

∑F = m. a

F = force, N

m = mass = kg

a = acceleration due to gravity, m / s²

While the speed is the first derivative of distance  

[tex]\large{\boxed{\bold{V~=~\frac{dr}{dt} }}}[/tex]

While acceleration is the first derivative of the velocity function for t

[tex]\large{\boxed{\bold{a~=~\frac{dv}{dt} }}}[/tex]

It is known that the distance function (r) = (0.020 t³i + 2.2 tj-0.06t²k

Then the speed (v)

[tex]v~=~\frac{dr}{dt}[/tex]

v = 0.06t²i + 2.2j - 0.12tk

Then acceleration (a)

[tex]a~=~\frac{dv}{dt}[/tex]

a = 0.12ti - 0.12k

While :

W = m . g

[tex]m~=~\frac{W}{g}[/tex]

m = 2.75.10⁵ : 10

m = 2.75.10⁴

so  net force :

F = m . a

F = 2.75.10⁴ . ( 0.12ti - 0.12k)

for t = 5  

F = 2.75.10⁴ . ( 0.12.5i - 0.12k)

F = 2.75.10⁴ (0.6i-0.12k)

F = 1.65.10⁴i - 3.3.10³k

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Keywords : Newton's Law, acceleration, net force

The net force on the helicopter at time [tex]t = 5.0\,{\text{s}}[/tex] is [tex]\fbox{\begin\\\left( {1.68 \times {{10}^4}\,\hat i - 3.36 \times {{10}^3}\,\hat j} \right)\,{\text{N}}\end{minispace}}[/tex].

Further Explanation:

The helicopter moves under the action of the force which changes the position of the helicopter with respect to time according to the following equation.

[tex]\vec{r}=(0.020\text{ m}/\text{s}^3)\text{ t}^3\hat{i}+(2.2\text{ m}/\text{s})\text{ t}^3\hat{j}-(0.060\text{ m}/\text{s}^2)\text{ t}^2\hat{k}[/tex]

The force acting on the helicopter at a particular time is given by:

[tex]\fbox{\begin\\F= m\cdot{a}\end{minispace}}[/tex]

Here, [tex]m[/tex] is the mass of the helicopter and [tex]a[/tex] is the acceleration of helicopter.

The helicopter has a weight of [tex]2.75 \times {10^5}\,{\text{N}}[/tex]. This weight of the helicopter can be converted into the mass of the helicopter.

The weight of the helicopter can be represented as.

[tex]\fbox{\begin\\W=m \cdot g\end{minispace}}[/tex]

Rearrange and simplify the expression for the mass of helicopter.

[tex]\begin{aligned}m&=\frac{W}{g}\\&=\frac{{2.75\times{{10}^5}}}{{9.8}}\,{\text{kg}}\\&=2.{\text{80}}\times{\text{1}}{{\text{0}}^4}\,{\text{kg}}\\\end{aligned}[/tex]

The velocity of the helicopter can be determined by the differentiation of the position vector of the helicopter with respect to time.

[tex]\begin{aligned}\vec{v}&=\dfrac{{d\vec{r}}}{{dt}}\\&=\dfrac{d}{{dt}}\ [(0.020\text{ m}/\text{s}^3)\text{ t}^3\hat{i}+(2.2\text{ m}/\text{s})\text{ t}^3\hat{j}-(0.060\text{ m}/\text{s}^2)\text{ t}^2\hat{k}]\\&=0.060{t^2}\hat{i}+2.2\hat{j}-0.12t\hat{k}\end{aligned}[/tex]

The acceleration of the helicopter is the derivative of the velocity with respect to the time.

[tex]\begin{aligned}\vec a&=\frac{{d\vec v}}{{dt}}\\&=\frac{d}{{dt}}\left({0.060{t^2}\hat i+2.2\hat j-0.12t\hat k}\right)\\&=0.12t\hat i-0.12\hat k\\\end{aligned}[/tex]

Substitute the value of [tex]t = 5.0\,{\text{s}}[/tex] in equation of the acceleration.

[tex]\begin{aligned}a&=0.12\left({5.0}\right)\hat i-0.12\hat k\\&=0.6\hat i-0.12\hat k\\\end{aligned}[/tex]

Substitute the values of the acceleration and the mass of the helicopter in the equation of force.

[tex]\begin{aligned}F&=\left( {2.80\times{{10}^4}\,{\text{kg}}}\right)\left({0.6\hat i-0.12\hat k}\right) \\&=\left({1.68\times{{10}^4}\,\hat i-3.36\times{{10}^3}\,\hat j}\right)\,{\text{N}}\\\end{aligned}[/tex]

Thus, the net force acting on the helicopter at time [tex]t = 5\,{\text{s}}[/tex] is [tex]\fbox{\begin\\\left( {1.68 \times {{10}^4}\,\hat i - 3.36 \times {{10}^3}\,\hat j} \right)\,{\text{N}}\end{minispace}}[/tex].

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2.  Conservation of energy https://brainly.com/question/3943029

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Answer Details:

Grade: College

Subject: Physics

Chapter: Force and acceleration

Keywords:

Helicopter, force, time, 5s, position, velocity, derivative, acceleration, weight, net force, t=5s, 0.020t3 m/s3, 2.75x10^5 N, helicopter under test, gravity, mass of helicopter.

A source emits monochromatic light of wavelength 495 nm in air. when the light passes through a liquid, its wavelength reduces to 434 nm what is the liquid's index of refraction?
a. 1.14
b. 1.49
c. 2.03
d. 1.26
e. 1.33

Answers

By definition, the refractive index is
n = c/v
where c =  3 x 10⁸ m/s,  the speed of light in vacuum
v = the speed of light in the medium (the liquid).

The frequency of the light source is
f = (3 x 10⁸ m/s)/(495 x 10⁻⁹ m) = 6.0606 x 10¹⁴ Hz

Because the wavelength in the liquid is 434 nm = 434 x 10⁻⁹ m, 
v = (6.0606 x 10¹⁴ 1/s)*(434 x 10⁻⁹ m) = 2.6303 x 10⁸ m/s

The refractive index is (3 x 10⁸)/(2.6303 x 10⁸) = 1.1406

Answer:  a.  1.14
Final answer:

The liquid's index of refraction is approximately 1.88.

Explanation:

To find the index of refraction for the liquid, we can use the formula:

n₁ / n₂ = λ₁ / λ₂

where n₁ and n₂ are the indices of refraction for air and the liquid, respectively, and λ₁ and λ₂ are the wavelengths of light in air and the liquid, respectively.

In this problem, we are given that the wavelength of light in air is 495 nm and the wavelength in the liquid is 434 nm. Plugging in these values, we get:

n₁ / n₂ = 495 nm / 434 nm

n₂ ≈ n₁ * (434 nm / 495 nm)

n₂ ≈ 1 * (434 nm / 495 nm)

n₂ ≈ 0.876

To convert the index of refraction to its decimal form, we add 1, giving us:

n₂ ≈ 0.876 + 1

n₂ ≈ 1.876

The liquid's index of refraction is approximately 1.876, which can be rounded to 1.88.

A 20000 kg rocket has a rocket motor that generates 3.0×105 n of thrust. part a what is the rocket's initial upward acceleration?

Answers

Answer:

a=5.20 m/s²

Explanation:

Given Data

Thrust = T (N)=3.0×10⁵N

Mass=m=20000kg

To find

acceleration=a=?

Solution

Newton Second law states that

The acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object.

(resultant force F)=ma

a=(resultant force F)/m

where

(resultant force F) is (Thrust-weight)  

Weight = mg = 2.0^4 kg*9.8 N/kg = 1.96^5 N

a = (resultant force F) / mass

a = (T - mg)/m = (3.0^5 N - 1.96^5 N)/ 2.0^4 kg

a=5.20 m/s²

The rocket's initial upward acceleration is 5.2m/s²

According to Newton's second law of motion

[tex]\sum F = ma[/tex]

The sum of forces is the difference between the weight and the thrust

[tex]\sum F = T -W[/tex]

[tex]T - W = ma\\a=\frac{T-W}{a}[/tex]

Given the following parameters:

T = [tex]3.0 \times 10^5 N[/tex]

W = [tex]20,000 \times 9.8 = 1.96 \times 10^5 N[/tex]

m = [tex]20,000kg[/tex]

Substitute the given parameters into the formula to have:

[tex]a=\frac{(3.0-1.96)\times 10^5}{2\times 10^4} \\a=\frac{1.04\times 10^5}{2\times 10^4} \\a = 0.52 \tmes 10\\a = 5.2m/s^2[/tex]

Hence the rocket's initial upward acceleration is 5.2m/s²

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A helicopter is ascending vertically with a speed of 7.00 m/s. at a height of 155 m above the earth, a package is dropped from a window. how much time does it take for the package to reach the ground? [hint: the package's initial speed equals the helicopter's.]

Answers

Given:
u = 7.00m/s, the initial vertical velocity of the package.

Assume that g = 9.8 m/s².
Neglect air resistance.
All quantities are measured as positive upwards.

The height from which the package is dropped is 155 m above ground.
Let t = the time for the package to hit the ground.
Therefore
(7.00 m/s)*(t s) - (1/2)*(9.8 m/s²)*(t s)² = (- 155 m)
4.9t² - 7t - 155 = 0
or
t² - 1.4286t - 31.6327  0
Solve with the quadratic formula.
t = (1/2)*[1.4286 +/- √(2.0409 + 126.5308)]
  = 6.384 s or - 4.955 s
Reject negative time.

Answer: 6.384 s

A satellite revolves around a planet at an altitude equal to the radius of the planet. the force of gravitational interaction between the satellite and the planet is f0. then the satellite is brought back to the surface of the planet. find the new force of gravitational interaction f4. express your answer in terms of f0.

Answers

Let
M = the mass of the planet
n = the mass of the satellite.
r = the radius of the planet

When the satellite is at a distance r from the surface of the planet, the distance between the centers of the two masses is 2r.
The gravitational force between them is
[tex]f_{0} = \frac{GMm}{(2r)^{2}} = \frac{1}{4} ( \frac{GMm}{r^{2}} )[/tex]
where
G =  the gravitational constant.

When the satellite is on the surface of the planet, the distance between the two masses is r.
The gravitational force between them is
[tex]f_{4} = \frac{GMm}{r^{2}} =4f_{0}[/tex]

Answer:  [tex]f_{4} = 4f_{0}[/tex]

f4 is 4 times larger than f0 The force of gravity between two masses is F = G M1M2/r^2 where F = Force G = Gravitational constant M1 = Mass of object 1 M2 = Mass of object 2 r = distance between the center of masses of the objects. So in the first case, the satellite is at an altitude of r above the surface. But it's really at a distance of 2r from the center of mass of the planet. And in the second case, the situation is that it's at distance r from the center of mass of the planet. So we have: f0 = G M1M2/((2r)^2) = G M1M2/(4r^2) and f4 = G M1M2/r^2 Let's divide f4 by f0 (G M1M2/r^2) / G M1M2/(4r^2) = (G M1M2/r^2) * (4r^2)/(G M1M2) = (1/r^2) * (4r^2)/1 = (4r^2)/r^2 = 4/1 = 4 So f4 = f0 * 4

Newton's first law of motion states that an object remains at rest unless a(n) ____ force acts on it. a. balanced c. gravitational b. frictional d. unbalanced Please select the best answer from the choice

Answers

It is an unbalanced force.
The answer is d. Unbalanced

The normal boiling point of cyclohexane is 81.0 ℃. what is the vapor pressure of cyclohexane at 81.0 ℃?

Answers

The boiling point is defined as the temperature at which the pressure of the vapor of the liquid is equivalent to the external atmospheric pressure surrounding the liquid. Therefore, the boiling point of the liquid is dependent on the atmospheric pressure.

Based on this, the vapor pressure of cyclohexane at 81 degrees celcius will be equal to atmospheric pressure (based on barometric readings)

Final answer:

The vapor pressure of cyclohexane at its normal boiling point of 81.0 ℃ is 101.3 kPa.

Explanation:

The question is asking for the vapor pressure of cyclohexane at its normal boiling point of 81.0 ℃. By definition, the normal boiling point of a liquid is the temperature at which its vapor pressure is equal to the external atmospheric pressure at sea level, which is 101.3 kPa (or 1 atmosphere). Therefore, the vapor pressure of cyclohexane at 81.0 ℃ is 101.3 kPa.

Hd 10180g orbits with a period of 600 days at a distance of 1.4 au from its star. what is the ratio of the star's mass to our sun's mass?

Answers

Use the expression -

P²k = a³---(i)

Where P is time in years, a is in AU, k is the function of the Sun's mass and set to unity.

Further, we're looking for the mass of the new star we have slightly modified Kepler's Third Law. After all, the inverse of a constant is also a constant. The reason we do it is because we want an answer in the form of K:1, where K is the mass of the HD 10180 and the mass of the Sun is 1, so k needs to start out on the other side.

Convert 600 days in years = 600/365 = 1.64 years

Put this in the expression mentioned at (i) -

1.64²k = a³

You gave us a = 1.4 AU

1.64²k = 1.4³ ; isolating k

k = 1.4³/1.64²

k = 2.744/2.702 = 1.015

So, the requisite ratio = 1.015 : 1

 

The ratio of the star's mass to the sun's mass is about 1.02 : 1

[tex]\texttt{ }[/tex]

Further explanation

Centripetal Acceleration can be formulated as follows:

[tex]\large {\boxed {a = \frac{ v^2 } { R } }[/tex]

a = Centripetal Acceleration ( m/s² )

v = Tangential Speed of Particle ( m/s )

R = Radius of Circular Motion ( m )

[tex]\texttt{ }[/tex]

Centripetal Force can be formulated as follows:

[tex]\large {\boxed {F = m \frac{ v^2 } { R } }[/tex]

F = Centripetal Force ( m/s² )

m = mass of Particle ( kg )

v = Tangential Speed of Particle ( m/s )

R = Radius of Circular Motion ( m )

Let us now tackle the problem !

[tex]\texttt{ }[/tex]

Given:

mass of the sun = M_sun = 1.99 × 10³⁰ kg

radius of the orbit = R = 1.4 AU = 2.094 × 10¹¹ m

Orbital Period of planet = T = 600 days = 600 × 24 × 3600 = 5.184 × 10⁷ seconds

Asked:

mass of the star = M = ?

Solution:

Firstly , we will use this following formula to find the mass of the star:

[tex]F = ma[/tex]

[tex]G \frac{ Mm}{R^2}=m \omega^2 R[/tex]

[tex]G M = \omega^2 R^3[/tex]

[tex]\frac{GM}{R^3} = \omega^2[/tex]

[tex]\omega = \sqrt{ \frac{GM}{R^3}}[/tex]

[tex]\frac{2\pi}{T} = \sqrt{ \frac{GM}{R^3}}[/tex]

[tex]M = \frac{4 \pi^2 R^3}{GT^2}[/tex]

[tex]M = \frac{4 \pi^2 (2.094 \times 10^{11})^3}{6.67 \times 10^{-11} \times (5.184 \times 10^7)^2}[/tex]

[tex]\boxed {M \approx 2.0 \times 10^{30} \texttt{ kg} }[/tex]

[tex]\texttt{ }[/tex]

Next , we will calculate the ratio of the star's mass to the sun's mass as follows:

[tex]M : M_{sun} = (2.0 \times 10^{30}) : (1.99 \times 10^{30})[/tex]

[tex]\boxed{M : M_{sun} \approx 1.02 : 1}[/tex]

[tex]\texttt{ }[/tex]

Learn moreImpacts of Gravity : https://brainly.com/question/5330244Effect of Earth’s Gravity on Objects : https://brainly.com/question/8844454The Acceleration Due To Gravity : https://brainly.com/question/4189441

[tex]\texttt{ }[/tex]

Answer details

Grade: High School

Subject: Physics

Chapter: Circular Motion

In order to climb a steep hill on a bicycle, a rider shifts to the lowest gear. The lowest gear has the greatest mechanical advantage because it

Answers

because it uses petional energy

The lowest gear on a bicycle provides the greatest mechanical advantage by amplifying the force exerted on the pedals, requiring the rider to pedal more but with less effort per stroke, due to the conservation of energy.

In order to climb a steep hill on a bicycle, a rider shifts to the lowest gear. The lowest gear has the greatest mechanical advantage because it allows the rider to apply a force over a greater distance. When a gear with many teeth drives a gear with fewer teeth, the driven gear spins more times but with a smaller turning force, amplifying the force the rider exerts on the pedals.

However, this means the rider will have to spin the pedals more times to cover the same distance, which is a trade-off.

This concept of mechanical advantage applies to all machines and is governed by the conservation of energy, which states that work input is equal to work output, minus any losses due to inefficiency like friction.

A person's height and weight will change gradually, while other things, such as getting a driver's license, may occur suddenly and mark the beginning of a new phase in life. This difference is an example of the theme of development known as:

Answers

Continuity vs. Stages --APEX

Answer:

Continuity vs. Stages

Explanation:

Continuity is the gradual changes that a person may experiment throught their life, good examples are the ones given in the question, height and weght increasing or changing over time, but stages start whenever something happens that changes the way of life of the person, for example graduating college and going into the labor force, or getting married.

Describe what would happen if you rubbed a mineral with a Mohs hardness value of 7 against a mineral with a value of 5?

Answers

The mineral with Mohs hardness would be scratched because the mineral with Mohs 7 hardness is stronger than the Mohs 5 mineral. Eventually, that mineral would turn into dust if you kept rubbing it.

If a mineral with a Moh's hardness value of 7 is rubbed against the mineral with a value of 5, the mineral with value 5 get scratched with the mineral with hardness value 7.  

• A scale of relative mineral hardness invented by German scientist Mohs is known as the Mohs scale of hardness or Mohs scale.  

• It is a 10 point scale, with 10 given to mineral diamond as the most hardest mineral, which can scratch the minerals below it, that is, coming below it in the hardness scale.  

• The minerals coming in the 7 scale are Quartz, Citrine, Agate, and Amethyst, and the mineral coming in the 5 scale is apatite.  

• Thus, when one rubs the mineral with 7 hardness with a mineral with 5 hardness, than the mineral with 5 hardness will easily get scratched as it is less harder to the mineral in the 7 scale.  

Thus,  the mineral with value 5 get scratched with the mineral with hardness value 7.

To know more about:

https://brainly.com/question/11451129

In the winter sport of curling, players give a 20 kg stone a push across a sheet of ice. the stone moves approximately 40 m before coming to rest. the final position of the stone, in principle, only depends on the initial speed at which it is launched and the force of friction between the ice and the stone, but team members can use brooms to sweep the ice in front of the stone to adjust its speed and trajectory a bit; they must do this without touching the stone. judicious sweeping can lengthen the travel of the stone by 3 m.

Answers

From Newton’s law of motion, the relation for velocity, acceleration and displacement is given by v^2 = vo^2 + 2as. Where v and vo are final and initial velocity respectively, and a, s are the acceleration and displacement respectively. From Newton’s second law, F = ma. Where m is the mass.

The magnitude of the frictional fore can be calculated only before estimating the ston’s acceleration. The initial speed of stone is mentioned in the problem as 3 m/s. Also, after 40m, the stone will stop. This means that its final speed is 0 m/s and the displacement is 40m.The acceleration of rock is calculated as:

(0 m/s)^2 = (3 m/s)^2 + 2a (40m).

9 m^2/s^2 = -2a(40m)

a= -9m^2/s^2/80m = 0.1 m/s^2.

This means that deceleration will occur and this will stop the stone. Substituting to Newton’s second law of motion,

-F = 20kg * -0.1 m/s^2. Further solve,

F = 20kg * 0.1 m/s^2 = 2N. Hence, the magnitude frictional force is 2N. 

Final answer:

In curling, the final position of the stone depends on its initial speed and the force of friction. Team members can use brooms to adjust the stone's speed and trajectory. The force of friction opposes the stone's motion.

Explanation:

In the winter sport of curling, the final position of the stone depends on the initial speed at which it is launched and the force of friction between the ice and the stone. Team members can use brooms to sweep the ice, which can adjust the stone's speed and trajectory. By judicious sweeping, they can lengthen the travel of the stone by a few meters. The force of friction between the ice and the stone will oppose the motion of the stone and slow it down.

The initial speed at which the stone is launched will determine how far it travels before coming to rest. If the stone is launched with a higher initial speed, it will travel a farther distance. The force of friction between the ice and the stone will also influence the distance the stone travels. A higher frictional force will cause the stone to slow down more quickly, resulting in a shorter travel distance.

\a stone is dropped from the top of a cliff. it hits the ground below after 3.80s. how high is the cliff in meters?

Answers

no velocity ws given? let's use
H= ½gt²
H= ½×10×3.8
H= 19m
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