A 3-column table with 4 rows. The first column labeled Scenario has entries A, B, C, D. The second column labeled Object 1 has entries lotion at 26 degrees Celsius, lasagna at 170 degrees Celsius, ocean water at 25 degrees Celsius, eggs at 2 degrees Celsius. The third column labeled Object 2 has entries skin at 37 degrees Celsius, plate at 20 degrees Celsius, lava 950 degrees Celsius, sidewalk at 80 degrees Celsius.
Indicate the direction of heat flow in each scenario.
Scenario A:
Scenario B:
Scenario C:
Scenario D:
Answers
The direction of heat flow in each scenario will be:
Scenario A = toward object 1Scenario B = toward object 2Scenario C = toward object 1Scenario D = toward object 1What is heat transfer?It should be noted that heat transfer means the transfer of heat from a location to another.
It is the process in which the molecules are moved from a region of higher temperature to that of a lower temperature.
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Answer:
It Is Scenario D.
Explanation:
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Answers
Click to review the online content. Then answer the question(s) below, using complete sentences. Scroll down to view additional questions.
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What factors can contribute to the process of desertification? (Site 1)
Answers
Answer:
Some of the factors include:
i. climate change
ii. urbanization
iii. overgrazing
iv. deforestation
v. natural disasters e.g yearly occurrence of wild fire in Austrailian forests
vi. soil erosion
Explanation:
Desertification is a process by which a fertile land degenerates into a desert due to some activities. These activities can either be natural or due to human activities, causing a land to become a desert. It has major effects on plants and animals (either domestic, wild or human).
In the world today, desertification is majorly caused by overgrazing and climate change. But other factors that can contribute to the process of desertification are; soil erosion, urbanization, deforestation, natural disasters etc.
Answer:
There are several reasons why the number of snow leopards is decreasing. Historically, and occasionally still today, snow leopards were hunted for their thick, soft fur.Other times snow leopards are killed by ranchers when the leopards attack their livestock. Humans now use some of the snow leopard’s habitat for farming and mining. This can make the snow leopards or their prey move to different habitats. Conservation groups are working to protect snow leopards and their habitat. Because of this the leopard species has decreased significantly.
Explanation:
Got 100%
Bison are found in grasslands.
They spend much of their time in herds eating grasses and other small plants.
What kind of teeth do bison likely have?
Answers
Answer: Broad, flat teeth for grinding.
Explanation:
Bison are large herbivorous mammals. These belong to the family of Bovidae. They create habitat on the Great Plains and grassland for many different species. Bison are called a keystone species. As the bison forage they cause aeration of soil. This promotes plant growth. They have broad, and flat teeth which help them to grind food. These mammals appear in herd which helps in maintaining a balanced ecosystem.
Write the balanced half‑reaction that occurs at the anode in a hydrogen‑oxygen fuel cell in which an acidic electrolyte is used. A hydrogen fuel cell. H 2 flows into the cell at the negative electrode. O 2 flows into the cell at the positive electrode. Electrons travel through an external circuit from the negative to the positive electrode. Between the two electrodes is an electrolyte solution. Arrows in the electrolyte point from the negative electrode to the positive electrode. anode half-reaction: Write the balanced half‑reaction that occurs at the cathode in a hydrogen‑oxygen fuel cell in which an acidic electrolyte is used. cathode half-reaction: Write the balanced overall cell reaction. overall cell reaction:
Answers
Answer:
Cathode: O2 + 4H+ +4e--------> 2H20
Anode: 2H2 -4e- ---------> 4H+
Overall: 2H2 + O2 → 2H2O
Explanation:
A hydrogen-oxygen fuel cell is an alternative cell to rechargeable cells and batteries. In this cell, hydrogen and oxygen is used to produce voltage and water is the only byproduct.
At the cathode (positive electrode):
O2 + 4H+ +4e--------> 2H2O
At the anode (negative electrode);
2H2 -4e- ---------> 4H+
Adding the two half reactions we have:
2H2 + O2 + 4H+ + 4e- -----------> 2H2O + 4H + 4e-
The overall reaction after cancelling out the like terms in the reaction is:
2H2 (g) + O2 (g) --------> 2H2O (l)
The hydrogen fuel cell is an electrochemical cell in which hydrogen is oxidized and oxygen is reduced.
A fuel cell is an electrochemical cell in which oxygen enters into the positive cathode and hydrogen flows into the negative cathode. Hydrogen is oxidized and oxygen is reduced during the electrochemical reaction.
At the negative electrode;
2H2(g) -----> 4H^+(aq)+ 4e
At the positive electrode;
O2(g) + 4H^+(aq) + 4e -----> 2H2O(l)
The overall reaction is;
2H2(g) + O2(g) -----> 4H^+(aq) + 2H2O(l)
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Consider the following reaction at equilibrium. What effect will adding 1.4 mole of He to the reaction mixture have on the system? 2 H2S(g) + 3 O2(g) ⇌ 2 H2O(g) + 2 SO2(g) Consider the following reaction at equilibrium. What effect will adding 1.4 mole of He to the reaction mixture have on the system? 2 H2S(g) + 3 O2(g) ⇌ 2 H2O(g) + 2 SO2(g) The reaction will shift to the left in the direction of reactants. No effect will be observed. The reaction will shift to the right in the direction of products. The equilibrium constant will increase. The equilibrium constant will decrease.
Answers
Adding 1.4 moles of He to the reaction mixture will have no effect on the equilibrium of the system.
Explanation:Adding 1.4 moles of He to the reaction mixture will have no effect on the system. The equilibrium of the reaction will not shift to the left or right, and there will be no change in the equilibrium constant. This is because He is considered an inert gas and does not participate in the reaction.
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Pure substances cannot be separated by physical means into simpler substances. True or False?
Answers
Answer:
true
Explanation:
Methanol, ethanol, and n−propanol are three common alcohols. When 1.00 g of each of these alcohols is burned in air, heat is liberated as indicated. Calculate the heats of combustion of these alcohols in kJ/mol. (a) methanol (CH3OH), −22.6 kJ kJ/mol (b) ethanol (C2H5OH), −29.7 kJ Enter your answer in scientific notation. × 10 kJ/mol (c) n−propanol (C3H7OH), −33.4 kJ Enter your answer in scientific notation. × 10 kJ/mol
Answers
The heats of combustion for methanol, ethanol, and n-propanol, when expressed in kJ/mol, are -0.710 × 10³ kJ/mol, -0.644 × 10³ kJ/mol, and -0.56 × 10³ kJ/mol, respectively. This shows that the amount of heat liberated decreases as the molecular weight of the alcohol increases.
Explanation:The heat of combustion of a substance is defined as the amount of heat energy released when 1 mole of a substance is completely burned in oxygen. Here, the heats of combustion for methanol (CH3OH), ethanol (C2H5OH), and n−propanol (C3H7OH) are given in kJ/g, and we need to convert them into kJ/mol.
To do this conversion, you first need to find the molar mass of each alcohol. You can do this by adding up the atomic masses of each element in the molecule.
Using the atomic masses in g/mol from the periodic table, we have: Methanol (CH3OH): 12.01 + 3(1.01) + 16 + 1.01 = 32.05 g/mol; Ethanol (C2H5OH): 2(12.01) + 5(1.01) +16 + 1.01=46.07 g/mol; n-Propanol (C3H7OH): 3(12.01) + 7(1.01) + 16 + 1.01 = 60.1 g/mol.
Next, divide the heat of combustion given in kJ/g by the molar mass calculated in g/mol to obtain the heat of combustion in kJ/mol:
Methanol: -22.6 kJ/g ÷ 32.05 g/mol = -0.710 × 10³ kJ/mol (scientific notation)
Ethanol: -29.7 kJ/g ÷ 46.07 g/mol = -0.644 × 10³ kJ/mol (scientific notation)
n-Propanol: -33.4 kJ/g ÷ 60.1 g/mol = -0.56 × 10³ kJ/mol (scientific notation)
So, the heats of combustion for the alcohols are: Methanol: -0.710 × 10³ kJ/mol, Ethanol: -0.644 × 10³ kJ/mol, and n-Propanol: -0.56 × 10³ kJ/mol. As you can see, the amount of heat liberated per mole decreases as the molecular mass of the alcohol increases.
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Consider the reaction.
2 upper N upper o upper c l double-headed arrow 2 upper N upper O (g) plus upper C l subscript 2 (g).
At equilibrium, the concentrations are as follows.
[NOCl] = 1.4 ´ 10–2 M
[NO] = 1.2 ´ 10–3 M
[Cl2] = 2.2 ´ 10–3 M
What is the value of Keq for the reaction expressed in scientific notation?
Answers
Answer: The value of Keq for the reaction expressed in scientific notation is [tex]1.6\times 10^{-5}[/tex]
Explanation:
Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios.
For the given chemical reaction:
[tex]2NOCl(g)\rightarrow 2NO(g)+Cl_2(g)[/tex]
The expression for [tex]K_{eq}[/tex] is written as:
[tex]K_{eq}=\frac{[NO]^2\times [Cl_2]}{[NOCl]^2}[/tex]
[tex]K_{eq}=\frac{(1.2\times 10^{-3})^2\times (2.2\times 10^{-3})}{(1.4\times 10^{-2})^2}[/tex]
[tex]K_{eq}=1.6\times 10^{-5}[/tex]
The value of Keq for the reaction expressed in scientific notation is [tex]1.6\times 10^{-5}[/tex]
Answer:
its A
Explanation:
ball has a volume of 5.27 liters and is at a temperature of 27.0°C. A pressure gauge attached to the ball reads 0.25 atmosphere. The atmospheric pressure is 1.00 atmosphere.
Answers
Answer:
The absolute pressure inside the ball is 1.25atm.
Explanation:
Given-
Volume, V = 5..27L
Temperature, T = 27°C
Gauge Pressure, Pg = 0.25 atm
Atmospheric pressure, Patm = 1 atm
Absolute pressure, Pabs = ?
We know,
Therefore, absolute pressure inside the ball is 1.25atm.
Answer:
The absolute pressure inside the ball is 1.25 atmospheres.
The ball contains 0.267 moles of air
Explanation:
Consider two cells, the first with Al and Ag electrodes and the second with Zn and Ni electrodes, each in 1.00 M solutions of their ions. If connected as voltaic cells in series, which two metals are plated, and what is the total potential, E ∘ ? Which two metals are plated?
a. Al ( s )
b. Ag ( s )
c. Zn ( s )
d. Ni ( s )
E ∘ =
Answers
Answer:
b. Ag ( s )
d. Ni ( s )
[tex]E^0_{total}[/tex] = 2.97 V
Explanation:
The reduction potentials for the given four (4) electrodes are:
In the first cell:
[tex]Ag^+ + e^- \to Ag \ \ \ \ E^0 = 0.80 \ V \\ \\ \\ Al^{3+} + 3e^- \to Al \ \ \ \ E^0 = - 1.66 \ V[/tex]
In the second cell:
[tex]Zn^{2+} + 2e^- \to Zn \ \ \ E^0 = -0.76 \ V \\ \\ \\ Ni^{2+} + 2e^- \to Ni \ \ \ E^0 =-0.25 \ V[/tex]
Since the cells are connected in series :
[tex]E_{total } > 0[/tex]
Thus; Metal plated in the first cell = Ag
Metal plated in the second cell = Ni
The total potential [tex]E^0_{total}[/tex] = [tex]E^0 {cell \ 1} - E^0 _{cell \ 2}[/tex]
= (0.80 + 1.66 ) V - (0.25 +0.76 ) V
= 2.97 V
In the first cell, silver is plated and in the second cell, nickel is plated.
In a voltaic cell, there is the production of electrical energy via a chemical reaction. We have two cells;
In the first cell, we have Al and Ag electrodes In the second cell we have Zn and Ni electrodesIn the first cell, silver is plated and the Ecell is 2.46 V while in the second cell, nickel is plated with Ecell of 0.51 V.
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Devin is watching two runners at the park. The runners are the same weight, and the speed that each of them is running is not changing.
Devin wants to know which runner has the most energy of motion. What would he need to find out about the runners in order to determine this?
Answers
Answer:
Reeeeeeeeeerereeeee
Reeeee reee reee ree ree re
Answer:
the speed of which they are running.
Explanation:
Compared to the ideal angle, you would expect the actual angle between the bromine-oxygen bonds to be
Answers
The expected bond angle between bromine and oxygen, based on hybridization and molecular geometry, would likely be slightly less than the ideal tetrahedral angle of 109.5°, due to electron repulsion effects.
Explanation:The bond angle between bromine and oxygen can be predicted using the concepts of hybridization and molecular geometry. If bromine and oxygen were to form a molecule similar to water (H₂O), one might expect a tetrahedral geometry because the valence orbitals of oxygen consist of one 2s orbital and three 2p orbitals. These combine during hybridization to form four hybrid orbitals that point toward the corners of a tetrahedron. The ideal bond angle for a tetrahedron is 109.5°. However, due to the effects of lone pair repulsion, the actual bond angle would likely be less, similar to how the H-O-H bond angle in water is experimentally found to be 104.5°.
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The actual angle between the bromine-oxygen bonds in BrO3⁻ is expected to be less than 120° due to the presence of the lone pair on the central bromine atom.
The ideal bond angle for a sp³ hybridized central atom is 109.5°. However, the presence of lone pairs on the central atom can distort the bond angles. Lone pairs are more electron-rich than bonding pairs, so they repel the bonding pairs more strongly. This repulsion causes the bond angles to decrease.
In the case of BrO3⁻, the central bromine atom is sp³ hybridized and has one lone pair. The lone pair will repel the two bonding pairs between the bromine and oxygen atoms. This repulsion will cause the bond angles between the bromine and oxygen atoms to decrease from the ideal angle of 120°.
The actual bond angle between the bromine-oxygen bonds in BrO3⁻ has been measured to be 107.1°. This is slightly less than the ideal angle of 120°, as expected.
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The question probable may be:
Compared to the ideal angle 120 ,the central atom Br lone pair 1 How you would expect the actual angle between the bromine-oxygen bonds to be
Which option is a solution that is 20% (v/v) methanol in water?
Answers
Answer:
Explanation:
1.The solution contains 20 mL of methanol and 100 mL of water.
2.The solution contains 20 mL of methanol and 80 mL of water.
3.The solution contains 20 g of methanol and 100 mL of water.
4.The solution contains 20 g of methanol and 80 mL of water.
Answer:
20 % volume/volume methanol in water contains 20 mL of methanol and 80 mL of water.
Explanation:
Total volume of the solution= 20 + 80 = 100 mL
10.3 5-Methylcyclopentadiene undergoes homolytic bond cleavage of a bond to form a radical that exhibits five resonance structures. Determine which hydrogen atom is abstracted and draw all five resonance structures of the resulting radical.
Answers
Answer:
Explanation:
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Which compound contains a triple bond?
Answers
Answer: C2H2
Explanation: Because each of the lines represent one bond, and because there are three lines (bonds) between the carbons, it means that they are bonded by three bonds, also known as a triple bond.
The triple bond that we have is shown by image D.
What is a triple bond?Two atoms share three pairs of electrons in a triple bond, making a total of six electrons present in the bond. Multiple bonds are formed between the atoms as a result of the sharing of electrons, offering a high degree of stability.
Two pi (π) bonds and a sigma (σ) bond define a triple bond. Atomic orbitals overlap head-on to form the sigma bond, whereas side-to-side overlap produces the two pi bonds.
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A 35.161 mg sample of a chemical known to contain only carbon, hydrogen, sulfur, and oxygen is put into a combustion analysis apparatus, yielding 62.637 mg of carbon dioxide and 25.641 mg of water. In another experiment, 31.321 mg of the compound is reacted with excess oxygen to produce 13.54 mg of sulfur dioxide. Add subscripts to the formula provided to correctly identify the empirical formula of this compound. Do not change the order of the elements.
Answers
Answer:
The empirical formulae is C6H12S02
Explanation:
1. First we need to obtain the mass of each element in the sample and compound formed
Carbon = (62.637 mg * 12.011 g/mol / 44.009 g/mol) = 17.094 mg of Carbon
Hydrogen = ( 25.641 mg * (2 *1..008 g/mol) / 18.015 g/mol) = 2.869 mg of Hydrogen
Sulphur = (13.54 mg * 32.066 g/mol / 64.066 g/mol) = 6.777 mg of Sulphur
2. Next is to determine the percentage composition. Here we divide the respective mass by the mass of the sample
Carbon = 17.094 / 35.161 * 100 = 48.62 %
Hydrogen = 2.869/ 35.161 *100 = 8.16 %
Sulphur = 6.777/ 31.321 *100 = 21.64 %
Oxygen = (100 - (48.62 + 8.16 + 21.64)) = 21.58 %
3. Next is to divide the mass assuming there are 100 mg by the respective atomic masses to obtain the number of moles
Carbon = 48.62 / 12.011 = 4.048 mol
Hydrogen = 8.16 / 1.008 = 8.095 mol
Sulphur = 21.64 / 32.066 = 0.675 mol
Oxygen = 21.58 / 16.000 = 1.348 mol
Next is to divide by the smallest value
Carbon = 4.048/ 0.675 =5.997 = 6
Hydrogen = 8.095 / 0.675 =11.993 =12
Sulphur = 0.675/ 0.675 = 1
Oxygen = 1.348 / 0.675 = 1.997 = 2
So therefore the empirical formulae of the sample is C6H12SO2
a) A 25.3 mg sample of sodium carbonate is present in a container.
i) Write the formula of sodium carbonate:
Answers
Answer:
Formula of sodium carbonate is [tex]Na_{2}CO_{3}[/tex].
Explanation:
Sodium carbonate is an ionic compound consists of [tex]Na^{+}[/tex] and [tex]CO_{3}^{2-}[/tex] ions.
In a formula unit of sodium carbonate, there should be two [tex]Na^{+}[/tex] ions and one [tex]CO_{3}^{2-}[/tex] ion to maintain charge neutrality.
In general, formula of an ionic compound consists of [tex]A^{x+}[/tex] and [tex]B^{y-}[/tex] ions is written as : [tex]A_{y}B_{x}[/tex] ([tex]x\neq y[/tex]) and AB ([tex]x= y[/tex])
If x or y is equal to 1 then it is not written explicitly in formula.
So, formula of sodium carbonate = [tex]Na_{2}CO_{3}[/tex]
Final answer:
The formula for sodium carbonate is Na₂CO₃; it is used for various purposes in chemical experiments such as stoichiometry, titration, and hydration analysis.
Explanation:
The formula for sodium carbonate is Na₂CO₃. In the context of these questions, sodium carbonate is often used in stoichiometric calculations, titrations, determining solubility of compounds, and calculating the formula of a hydrated compound by heating the sample to remove water of hydration. A sample of sodium carbonate is specified in different quantities across various experimental setups, which highlights its versatile use in chemical reactions and in the preparation of specific molar concentration solutions.
A weather balloon has a volume of 200.0 L at a pressure of 760 mm Hg. As it rises, the pressure decreases to 282 mm Hg. What is the new volume of the balloon? (Assume constant temperature)
Answers
Answer:
The new volume of the balloon is 539 L
Explanation:
As the volume increases, the gas particles (atoms or molecules) take longer to reach the walls of the container and therefore collide less times per unit time against them. This means that the pressure will be less because it represents the frequency of gas strikes against the walls. In this way, pressure and volume are related, determining Boyle's law that says:
"The volume occupied by a given gas mass at constant temperature is inversely proportional to the pressure"
Boyle's law is expressed mathematically as:
Pressure * Volume = constant
o P * V = k
Having an initial state 1 and an final state 2 will be fulfilled:
P1 * V1 = P2 * V2
So, in this case, you know:
P1= 760 mmHgV1= 200 LP2= 282 mmHgV2= ?Replacing:
760 mmHg*200 L= 282 mmHg*V2
Solving:
[tex]V2=\frac{760 mmHg*200 L}{282 mmHg}[/tex]
V2=539 L
The new volume of the balloon is 539 L
Using Boyle's Law, we calculated the new volume of the weather balloon as approximately 538.7 L when the pressure decreases from 760 mm Hg to 282 mm Hg at constant temperature.
To find the new volume of the weather balloon when the pressure changes, we can use Boyle's Law, which states that the product of the initial pressure and volume is equal to the product of the final pressure and volume, assuming constant temperature.
The formula is:
P₁V₁= P₂V₂
Given: P₁ = 760 mm Hg, V₁ = 200.0 L, P₂ = 282 mm Hg
We need to find V₂.
Rearranging the formula to solve for V₂:
V₂= (P₁V1₁ / P₂)
Substituting the given values:
V₂ = (760 mm Hg * 200.0 L) / 282 mm Hg
V₂ = 152000 mm Hg L / 282 mm Hg
V₂ ≈ 538.7 L
Therefore, the new volume of the balloon is approximately 538.7 L.
Calculate the pressure exerted by 66.0 g of CO2 gas at -14.5°C that occupies a volume of 50.0 L
Answers
The pressure exerted by 66.0 g of CO₂ gas at -14.5°C that occupies a volume of 50.0 L is 0.636 atm.
How do we calculate pressure?Pressure of any gas will be calculated by using the ideal gas equation as:
PV = nRT, where
P = pressure of gas = ?
V = volume of gas = 50L
R = universal gas constant = 0.082 L.atm/K.mol
T = temperature of gas = -14.5°C = 258.65 K
n is moles of gas and it will be calculated as:
n = W/M, where
W = given mass of CO₂ = 66g
M = molar mass of CO₂ = 44 g/mol
n = 66/44 = 1.5 moles
On putting values we get
P = (1.5)(0.082)(258.65) / (50)
P = 0.636 atm
Hence required pressure is 0.636 atm.
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To calculate the pressure exerted by a gas, we can use the Ideal Gas Law equation and convert the given values to the appropriate units. Then, plug these values into the equation to calculate the pressure.
Explanation:To calculate the pressure exerted by a gas, we can use the Ideal Gas Law equation:
PV = nRT
Where P is the pressure, V is the volume, n is the number of moles of gas, R is the ideal gas constant, and T is the temperature in Kelvin. Rearranging the equation to solve for pressure, we have:
P = (nRT) / V
In this case, we are given the mass of CO2 gas (66.0 g), the volume (50.0 L), and the temperature in Celsius (-14.5°C). First, we need to convert the mass to moles using the molar mass of CO2.
Next, we need to convert the temperature to Kelvin by adding 273.15. Once we have the number of moles and the temperature in Kelvin, we can plug these values into the equation to calculate the pressure.
Question 18 A chemist must prepare of sodium hydroxide solution with a pH of at . He will do this in three steps: Fill a volumetric flask about halfway with distilled water. Weigh out a small amount of solid sodium hydroxide and add it to the flask. Fill the flask to the mark with distilled water. Calculate the mass of sodium hydroxide that the chemist must weigh out in the second step. Round your answer to significant digits.
Answers
Answer:
9.0 g
Explanation:
There is some info missing. I think this is the original question.
A chemist must prepare 0.9 L of sodium hydroxide solution with a pH of 13.40 at 25°C. He will do this in three steps: Fill a volumetric flask about halfway with distilled water. Weigh out a small amount of solid sodium hydroxide and add it to the flask. Fill the flask to the mark with distilled water. Calculate the mass of sodium hydroxide that the chemist must weigh out in the second step. Round your answer to 2 significant digits.
Step 1: Calculate the pOH
We use the following expression.
pH + pOH = 14.00
pOH = 14.00 - pH = 14.00 - 13.40 = 0.60
Step 2: Calculate [OH⁻]
We use the following expression.
pOH = -log [OH⁻]
[OH⁻] = antilog -pOH = antilog -0.60 = 0.25 M
Step 3: Calculate [NaOH]
NaOH is a strong base that releases 1 OH⁻. Then, [NaOH] = 0.25 M
Step 4: Calculate the mass of NaOH
The molar mass of NaOH is 40.00 g/mol. The mass required to prepare 0.9 L of a 0.25 M solution is:
[tex]0.9 L \times \frac{0.25mol}{L} \times \frac{40.00g}{mol} = 9.0 g[/tex]
What is the de Broglie wavelength, in cm, of a 11.0-g hummingbird flying at 1.20 x 10^2 mph?
(1 mile=1.61 km.)
Answers
Answer:1.123 x 10^-31cm
Explanation:
mass of humming bird= 11.0g
speed= 1.20x10^2mph
but I mile = 1.6m
1km=1000
I mile = 1.6x10^3m
1.20x10^2mph= 1.6x10^3m /1mile x at 1.20 x 10^2
=1.932 x10^5m
recall that
1 hr= 60 min
1 min=60 secs, 1hr=3600s
Speed = distance/ time
=1.932 x10^5 / 3600= 5.366 x 10 ^1 m/s
m= a 11.0g= 11.0 x 10^-3kg
h=6.626*10^-34 (kg*m^2)/s
Wavelength = h/mu
= 6.626*10^-34/(11 x 10^-3 x 5.366x 10^1)
6.63x10^-34/ 590.26x 10 ^-3= 1.123 x10^-33m
but 1m = 100cm
1.123 x 10 ^-33 x 100 = 1.123 x 10^-31cm
de broglie wavelength of humming bird = 1.123 x 10 ^-31cm
which term is defined as the sum of protons and neutrons in an atomic number?
a) charge number
b) mass number
c) atomic number
d) balance number
Answers
Answer: B) Mass Number
Answer:
C. Mass Number
Explanation:
took the test and got 100% so i know its right
Compare the number of valence electrons for each to whether or not they donate or receive electrons
Answers
Answer:
Valency electrons is the number outermost electron present in atom of an element . The valency electron of an atom determines the kind of bonding an element undergoes. The valency electrons determines whether an atom of element will either donate electrons or receive electrons.
Explanation:
Valency electrons is the number outermost electron present in atom of an element . The valency electron of an atom determines the kind of bonding an element undergoes. The valency electrons determines whether an atom of element will either donate electrons or receive electrons.
Elements donates or receive electron to attain or fulfill the octet rule and this account for the stability. Most metallic elements donates electrons and because they have few valency electrons , this also contributes to their ability to loose electrons easily . Metallic elements like sodium, magnesium, calcium etc loose electrons during bonding with other non metals. When metals loose electrons they form cations
Non metallic element have high number of valency electron and they tend to receive electrons from metallic elements to attain stability . When they gain electron they form anions.
An example of bonding that involves donating and receiving are bonding between Na and Cl atoms to form NaCl . The metallic sodium loose one electron while the chlorine atom gains one electron to attain the octet rule.
A hydrogen atom transitions from the n = 6 excited state to the n = 3 excited state, emitting a photon. a) What is the energy, in electron volts, of the electron in the n = 6 state? How far from the nucleus is the electron? b) What is the energy, in electron volts, of the photon emitted by the hydrogen atom? What is the wavelength of this photon? c) How many different possible photons could the n = 6 electron generate by dropping to a lower level (not just the n = 3 state)? d) After reaching the n = 3 state, the electron absorbs an photon with an energy of 50 eV, which ionizes the hydrogen atom (i.e., the electron reaches n=infinity). What is the wavelength of the electron after it is ejected from the hydrogen ato
Answers
Answer:
Explanation:
a ) energy, in electron volts, of the electron in the n = 6 state
= -13.6 / 6² eV
= - .378 eV .
b )
energy of n=3
= - 13.6 / 3²
= - 1.5111 eV
Difference = - .378 + 1.511
= 1.133 eV
the energy, in electron volts, of the photon emitted by the hydrogen atom
= 1.133 eV
c ) No of possible photons
= 6C₂
= 15
d) energy at n = 3
= - 1.5111 eV
50 eV energy is added to it so its energy
= 50 - 1.5111 eV
= 48.4889 eV .
From De broglie wavelength formula
λ = h / √ mE , m is mass of electron , E is kinetic energy h is plank's constant.
λ = 6.6 x 10⁻³⁴ / √ ( 9.1 x 10⁻³¹ x 48.4889 x 1.6 x 10⁻¹⁹ )
= 6.6 x 10⁻³⁴ / 26.57 x 10⁻²⁵
= .248 x 10⁻⁹ m
= .248 nm .
Consider these generic half-reactions. Half-reaction E° (V) X+(aq)+e−⟶X(s) 1.52 Y2+(aq)+2e−⟶Y(s) −1.17 Z3+(aq)+3e−⟶Z(s) 0.84 Identify the strongest oxidizing agent. X+ Y2+ X Z Y Z3+ Identify the weakest oxidizing agent. X Z3+ Y Y2+ Z X+ Identify the strongest reducing agent. Z3+ X+ Y2+ Z X Y Identify the weakest reducing agent. Y Z X+ X Y2+ Z3+ Which substances can oxidize Z ?
Answers
The strongest reducing agent Y2+ and the weakest reducing agent is X+.
The more positive the reduction potential of a specie is, the better it serves as an oxidizing agent and is better able to accept electrons. In a nutshell, the specie that has a higher positive reduction potential is a better oxidizing agent. The reducing agent is the specie that has the most negative reduction potential.
Looking the half reaction equations;
X+(aq)+e−⟶X(s) 1.52 VY2+(aq)+2e−⟶Y(s) −1.17 V Z3+(aq)+3e−⟶Z(s) 0.84 VWe can see that the strongest oxidizing agent is X+, the weakest oxidizing agent is Y2+, the strongest reducing agent Y2+ and the weakest reducing agent is X+.
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Final answer:
The strongest oxidizing agent is Y2+(aq), the weakest oxidizing agent is X+(aq), the strongest reducing agent is Z3+(aq), the weakest reducing agent is Y(s), and substances with a higher reduction potential than Z3+(aq) can oxidize Z.
Explanation:
The strongest oxidizing agent can be identified by looking at the reduction potentials of the half-reactions. The half-reaction with the highest reduction potential is Y2+ → Y(s), with a reduction potential of -1.17 V. Therefore, Y2+(aq) is the strongest oxidizing agent.
The weakest oxidizing agent can be identified by looking at the reduction potentials of the half-reactions. The half-reaction with the lowest reduction potential is X+(aq) → X(s), with a reduction potential of 1.52 V. Therefore, X+(aq) is the weakest oxidizing agent.
The strongest reducing agent can be identified by looking at the reduction potentials of the half-reactions. The half-reaction with the highest reduction potential is Z3+(aq) → Z(s), with a reduction potential of 0.84 V. Therefore, Z3+(aq) is the strongest reducing agent.
The weakest reducing agent can be identified by looking at the reduction potentials of the half-reactions. The half-reaction with the lowest reduction potential is Y(s) → Y2+(aq), with a reduction potential of -1.17 V. Therefore, Y(s) is the weakest reducing agent.
Substances that have a higher reduction potential than Z3+(aq), which is 0.84 V, can oxidize Z.
What’s the largest number?
○ 2 x 10^1
○ 5 x 10^3
○ 3 x 10^4
○ 7 x 10^-6
Answers
Answer:
3 x 10^4
Explanation:
○ 2 x 10^1 = 20
○ 5 x 10^3 = 5,000
○ 3 x 10^4 = 30,000
○ 7 x 10^-6 = 7/1,000,000
Answer:
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Which will not appear in the equilibrium constant expression for the reaction below?
H2O(g) + C(s) +
H2() + CO(g)
[H20]
[C]
[H2]
[CO]
Answers
Concentration of C, [C] will not appear in the equilibrium constant expression for the reaction.
What is meant by equilibrium constant ?Ratio of product of concentration of the products to the product of concentration of reactants.
Here,
H₂O(g) + C(s) ⇆ H₂ + CO
The expression for equilibrium constant for the reaction is given by,
K = [H₂] [CO]/ [H₂O] [C]
where K is the equilibrium constant of the reaction.
We know, the concentration of solids does not change in a reaction and therefore the concentration is taken as unity.
In the given reaction, since the reactant C is in solid form, its concentration is taken as 1.
So, K = [H₂] [CO]/ [H₂O]
As a result, the concentration of C, [C] will not be included in the expression for equilibrium constant.
Hence,
Concentration of C, [C] will not appear in the equilibrium constant expression for the reaction.
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In the reaction H2O(g) + C(s) → H2(g) + CO(g), the component that does not appear in the equilibrium constant expression is C(s), carbon in its solid form. This is because pure solids do not change concentration and do not affect the state of equilibrium.
Explanation:To answer which component will not appear in the equilibrium constant expression for the reaction H2O(g) + C(s) → H2(g) + CO(g), we need to understand how equilibrium expressions are formed. The equilibrium constant expression for a reaction is based on the balanced chemical equation and includes the concentrations of the gaseous and aqueous species, raised to the power of their coefficients in the balanced equation. Pure solids and pure liquids are not included in the expression because their concentrations don't change during the reaction.
In the given reaction, C(s), which is carbon in its solid form, does not appear in the equilibrium constant expression because as a pure solid, its concentration is constant and does not affect the state of equilibrium. Therefore, the equilibrium constant expression for this reaction would be K = [CO][H2], excluding both the water (H2O) because it is in gaseous form and included in the expression, and the carbon (C) because it is a solid.
what is the best definition of nuclear fusion
Answers
Answer:
A nuclear fusion is a nuclear reaction in which atomic nuclei of low atomic number fuse to form a heavier nucleus with the release of energy.
Answer:
Nuclear fusion is the joining of two or more nuclei into one nucleus
Explanation:
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Give TWO examples of energy conversion that produces unwanted forms of energy.
Answers
For example, consider the energy used by an electric fan. The amount of electrical energy used is greater than the kinetic energy of the moving fan blades. Because energy is always conserved, some of the electrical energy flowing into the fan's motor is obviously changed into unusable or unwanted forms.
In a car engine, the chemical energy in the fuel converts into mechanical energy, but also produces unwanted heat and sound energy. In electric lighting, electrical energy becomes light energy, but also generates unnecessary heat energy.
Explanation:Examples of Energy ConversionThe first example is a car engine. When a car engine operates, the chemical energy in the fuel is converted into mechanical energy that moves the car. However, this process also produces unwanted forms of energy, such as heat and sound energy. The heat is generated due to the combustion of fuel, and the sound is created due to the movement of engine parts. This wasted energy reduces the overall efficiency of the energy conversion process.
The second example is electric lighting. The electrical energy that is input into the lightbulb gets converted into light energy, which is useful. But at the same time, unwanted heat energy is also produced. This heat energy is unhelpful and represents inefficiency in the energy conversion process.
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What happens when the concentration of water inside a cell is lower than the concentration of water outside the cell?
Answers
Answer:
Water outside the cell will flow inwards by osmosis to attain equilibrium
Explanation:
In the hypotonic environment, the concentration of water is greater outside the cell and the concentration of solute is higher inside. A solution outside of a cell has a lower concentration of solutes relative to the cytosol.
If concentrations of dissolved solutes are greater inside the cell, the concentration of water inside the cell is correspondingly lower. As a result, water outside the cell will flow inwards by osmosis to attain equilibrium.
Osmosis is a process by which molecules of a solvent tend to pass from a less concentrated solution into a more concentrated one through a semipermeable membrane.