A 50/50 blend of engine coolant and water (by volume) is usually used in an automobile's engine cooling system. If a car's cooling system holds 4.90 gal, what is the boiling point of the solution?

Answers

Answer 1

Answer:

108.25 ºC

Explanation:

The boiling point elevation for a given solute in water is given by the expression:

ΔTb = i Kbm

where ΔTb is the boiling point elevation

           i is the van´t Hoff factor

           Kb the boiling constant which for water is 0.512 ºC/molal

           m is the molality of the solution

The molality of the solution is the number of moles per kilogram of solvent. Here we run into a problem since we are not given the identity of the coolant, but a search in the literature tells you that the most typical are ethylene glycol and propylene glycol. The most common is ethylene glycol and this it the one we will using in this question.

Now the i factor in the equation above is 1 for non ionizable compounds such as ethylene glycol.

Our equation is then:

ΔTb =  Kbm

So lets calculate the molality and then ΔTb:

m = moles ethylene glycol / Kg solvent

Converting gal to L

4.90 g x 3.785 L/gal = 18.55 L

in a 50/50 blend by volume we have 9.27 L of ethylene glycol, and 9.27 L of water.

We need to convert this 9.27 l of ethylene glycol to grams assuming a solution density of 1 g/cm³

9.27 L x 1000 cm³ / L = 9273.25 cm³

mass ethylene glycol = 9273.25 cm³ x 1 g/cm³ = 9273.25 g

mol ethylene glycol = 9273.25 g/ M.W ethylene glycol

                                 = 9273.25 g / 62.07 g/mol =149.4mol

molality solution =  149.4 mol / 9.27 Kg H₂O = 16.12 m

( density of water 1 kg/L )

Finally we can calculate ΔTb:

ΔTb =  Kbm = 0.512  ºC/molal x 16.12 molal = 8.25 ºC

boiling point = 100 º C +8.25 ºC = 108.25 ºC

( You could try to solve for propylene glycol the other popular coolant which should give around 106.7 ºC )


Related Questions

describe the activity of electrons when a substance is vaporized in a flame: what is viewed through a spectroscope and how does this instrument serve in identifying substance?

Answers

Answer:

The electrons are exposed to thermal energy/heat causing the excitation of the electron that is the electron in the outer orbital get absorbed and bounce to higher energy level.

Under the spectroscope, omitted wavelengths are seen with bright colors. For instance, light with longer wavelength appears red and light with shorter wavelength appear purple.

So, therefore, different metals will produce different wavelengths of light that are giving off a characteristic color of light.

Comparing the position of the colored light helps in the identification of substances.

Final answer:

When a substance is vaporized in a flame, the activity of electrons can be observed. The light emitted by the substance can be viewed through a spectroscope, which can help identify the substance based on its characteristic spectral lines or patterns.

Explanation:

When a substance is vaporized in a flame, the activity of electrons can be observed. This is because the high temperature of the flame causes the electrons in the substance to become excited and move to higher energy levels. When these excited electrons return to their ground state, they release energy in the form of light.

The light emitted by the substance can be viewed through a spectroscope, which is an instrument used to separate light into its different wavelengths or colors. By analyzing the specific wavelengths of light emitted, scientists can identify the substance based on its characteristic spectral lines or patterns.

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The client's lab values are sodium 166 mEq/L, potassium 5.0 mEq/L, chloride 115 mEq/L, and bicarbonate 35 mEq/L. What condition is this client likely to have, judging by anion gap?

Answers

Answer: metabolic acidosis.

Explanation:

Anion Gap(AG) is the difference between positively charged ions and negatively charged ions. It is usually expressed in milliequivalents per litre of millimoles per litres.

Anion Gap is measured or calculated when there is a need to know the cause of metabolic acidosis. To

Anion Gap can be calculated with or without potassium.

(1). With potassium= ([Na^+] + [K^+]) − ([Cl^−] + [HCO^−3]).

From the question; client's lab values are sodium 166 mEq/L, potassium 5.0 mEq/L, chloride 115 mEq/L, and bicarbonate 35 mEq/L.

Slotting in the values, we have;

==>[ (166+5) - (115+35)] mEq/L.

(2). Without potassium:

==> [Na^+] - ([Cl^−] + [HCO^−3]).

==> [(166) - 115 + (35)] mEq/L

Normal Anion gap is 20 mEq/L(Calculating with Potassium) and 8-16 mEq/L (calculating without potassium).

58-Ni has an atomic number of 28 which are the protons and a mass number of 58. Since the mass number is 58 this is the protons and neutrons. 58- 28 equals 30 neutrons. Protons equal electrons in a normal atom so 28 protons then there is 28 electrons.

60-Ni +2 will have the same number of protons as the normal atom of Ni so it has 28 protons and it lost two electrons due to the + charge. so it will have 28 regular protons because it is still nickel, 26 electrons since it lost 2 giving it a positive charge but it had to gain 2 neutrons by the loss of electrons, resulting in 32 neutrons.

28 regular protons
26 electrons due to loss
32 neutrons due to gain by loss of electrons to keep peace in atm

Answers

Final answer:

In the nickel nucleus, the atomic number indicates the number of protons, and the mass number represents the sum of protons and neutrons. When nickel forms a +2 ion, the number of protons remains the same, but electrons decrease and neutrons increase to maintain electrical neutrality.

Explanation:

In the nickel nucleus represented above, the atomic number 28 indicates that the nucleus contains 28 protons, and therefore, it must contain 30 neutrons to have a mass number of 58.

When the nickel atom forms a +2 ion, it loses 2 electrons and becomes 60-Ni+2.

However, the number of protons remains the same at 28 because the atomic number defines the element.

Therefore, 60-Ni+2 still has 28 protons, but the number of electrons decreases to 26.

To maintain electrical neutrality, the ion gains 2 more neutrons resulting in 32 neutrons.

Based on extrapolation of your lab results, write the dissolution reaction for the ionic solids below. (Use the lowest possible coefficients. Include states-of-matter under the given conditions in your answer.)(A) Mn(ClO4)2(B) Li2CO3The two solutions, when mixed, will have two cations and two anions.(C) Based on your lab results, enter the cation and anion for which a precipitate will form. (Separate substances in a list with a comma.)(D) Write the net precipitation reaction that occurs. (Use the lowest possible coefficients. Include states-of-matter under the given conditions in your answer.)

Answers

Answer:

The answer has been provided in the attachment

Explanation:

The step by step explanation is as given in the attachment below.

Final answer:

The dissolution reactions for Mn(ClO4)2 and Li2CO3 are Mn(ClO4)2(s) -> Mn2+(aq) + 2ClO4-(aq) and Li2CO3(s) -> 2Li+(aq) + CO3^2-(aq) respectively. The cations Mn^2+ and Li+ will react with the anions ClO4^- and CO3^2- respectively to form a precipitate. The net precipitation reaction is Mn2+(aq) + 2ClO4-(aq) + 2Li+(aq) + CO3^2-(aq) -> Mn(ClO4)2(s) + Li2CO3(s).

Explanation:

(A) The dissolution reaction for Mn(ClO4)2 is:



Mn(ClO4)2(s)  →  Mn2+(aq) + 2ClO4-(aq)



(B) The dissolution reaction for Li2CO3 is:



Li2CO3(s)  →  2Li+(aq) + CO32-(aq)



(C) Based on the lab results and the solutions, a precipitate will form when the cations Mn2+ and Li+ react with the anions ClO4- and CO32- respectively.



(D) The net precipitation reaction that occurs is:



Mn2+(aq) + 2ClO4-(aq) + 2Li+(aq) + CO32-(aq)  →  Mn(ClO4)2(s) + Li2CO3(s)

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A ________ is a solid, naturally occurring, cohesive substance composed of minerals or mineral-like materials.

Answers

Answer:

Rock

Explanation:

Rock -

It refers to the substance composed of minerals which occurs naturally , is referred to as a rock.

Rocks are basically found in the outermost layer of the Earth i.e. , the crust .

There are three major type of rock known, i.e. , sedimentary rocks , metamorphic rocks and igneous rocks .

Hence, from the given information of the question,

The correct answer is rock.

Final answer:

A rock is a solid, naturally occurring, cohesive substance composed of minerals or mineral-like materials. Examples include granite which comprises various minerals. Rocks are classified into three types: igneous, sedimentary, and metamorphic.

Explanation:

A rock is a solid, naturally occurring, cohesive substance composed of minerals or mineral-like materials. For instance, granite is a common form of rock that comprises several minerals including feldspar, mica, and quartz. Rocks can be classified into three main types: igneous, sedimentary, and metamorphic, each type formed under different geological conditions and processes.

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Refrigerators are usually kept at about 5°C, while room temperature is about 20°C. If you were to take an ""empty"" sealed 2-liter soda bottle at room temperature and place it in the fridge, would you expect it to contract to one-fourth its original volume?
1. Yes, because 5 is one-fourth of 20.
2. No, because there is no gas inside the bottle.
3. No, because Celsius is not an absolute temperature scale.

Answers

Answer: option 3. No, because Celsius is not an absolute temperature scale.

Explanation:

Answer:

3. No, because Celsius is not an absolute temperature scale.

Explanation:

Note that  20∘C=293K  and  5∘C=278K . So the absolute temperature has not decreased by very much at all, certainly not by a factor of four. Therefore, the change in size of the plastic bottle would not be very noticeable.

What is the molarity (M) of chloride ions in a solution prepared by mixing 155 ml of 0.276 M calcium chloride with 384 ml of 0.471 M aluminum chloride?

Answers

Answer: The concentration of [tex]Cl^-[/tex] ions in the resulting solution is 1.16 M.

Explanation:

To calculate the molarity of the solution after mixing 2 solutions, we use the equation:

[tex]M=\frac{n_1M_1V_1+n_2M_2V_2}{V_1+V_2}[/tex]

where,

[tex]n_1,M_1\text{ and }V_1[/tex] are the n-factor, molarity and volume of the [tex]CaCl_2[/tex]

[tex]n_2,M_2\text{ and }V_2[/tex] are the n-factor, molarity and volume of the [tex]AlCl_3[/tex]

We are given:

[tex]n_1=2\\M_1=0.276M\\V_1=155mL\\n_2=3\\M_2=0.471M\\V_2=384mL[/tex]  

Putting all the values in above equation, we get

[tex]M=\frac{(2\times 0.276\times 155)+(3\times 0.471\times 384)}{155+384}\\\\M=1.16M[/tex]

The concentration of [tex]Cl^-[/tex] ions in the resulting solution will be same as the molarity of solution which is 1.16 M.

Hence, the concentration of [tex]Cl^-[/tex] ions in the resulting solution is 1.16 M.

The molarity of Cl¯ in the solution made by mixing 155 mL of 0.276 M CaCl₂ with 384 mL of 0.471 M AlCl₃ is 1.165 M

We'll begin by calculating the number of mole of chloride ion, Cl¯ in each solution.

For CaCl₂:

Volume = 155 mL = 155 / 1000 = 0.155 L

Molarity = 0.276 M

Mole of CaCl₂ =?

Mole = Molarity x Volume

Mole of CaCl₂ = 0.276 × 0.155

Mole of CaCl₂ = 0.04278 mole

CaCl₂(aq) —> Ca²⁺(aq) + 2Cl¯(aq)

From the balanced equation above,

1 mole of CaCl₂ contains 2 moles of Cl¯

Therefore,

0.04278 mole of CaCl₂ will contain = 0.04278 × 2 = 0.08556 mole of Cl¯

Thus, 0.08556 mole of Cl¯ is present in 155 mL of 0.276 M of CaCl₂.

For AlCl₃:

Volume = 384 mL = 384 / 1000 = 0.384 L

Molarity = 0.471 M

Mole of AlCl₃ =?

Mole = Molarity x Volume

Mole of AlCl₃ = 0.471 × 0.384

Mole of AlCl₃ = 0.180864 mole

AlCl₃(aq) —> Al³⁺(aq) + 3Cl¯(aq)

From the balanced equation above,

1 mole of AlCl₃ contains 3 moles of Cl¯

Therefore,

0.180864 mole of AlCl₃ will contain = 0.180864 × 3 = 0.542592 mole of Cl¯

Thus, 0.542592 mole of Cl¯ is present in 384 ml of 0.471 M of AlCl₃

Next, we shall determine the total mole of Cl¯ in the resulting solution.

Mole of Cl¯ in CaCl₂ = 0.08556 mole

Mole of Cl¯ in AlCl₃ = 0.542592

Total mole = 0.08556 + 0.542592

Total mole = 0.628152 mole

Next, we shall determine the total volume of the resulting solution

Volume of CaCl₂ = 0.155 L

Volume of AlCl₃ = 0.384 L

Total volume = 0.155 + 0.384

Total volume = 0.539 L

Finally, we shall determine the molarity of Cl¯ in the resulting solution

Total mole = 0.628152 mole

Total volume = 0.539 L

Molarity of Cl¯ =?

Molarity = mole / Volume

Molarity of Cl¯ = 0.628152 / 0.539

Molarity of Cl¯ = 1.165 M

Therefore, the molarity of Cl¯ in the resulting solution is 1.165 M

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At a certain temperature this reaction follows second-order kinetics with a rate constant of 14.1 M⁻¹s⁻¹ : ---> 2SO₃g + 2SO₂g O₂g Suppose a vessel contains SO₃ at a concentration of 1.44M . Calculate the concentration of SO₃ in the vessel 0.240 seconds later. You may assume no other reaction is important.Round your answer to 2 significant digits.

Answers

Answer : The concentration of SO₃ in the vessel 0.240 seconds later is, 0.24 M

Explanation :

The expression used for second order kinetics is:

[tex]kt=\frac{1}{[A_t]}-\frac{1}{[A_o]}[/tex]

where,

k = rate constant = [tex]14.1M^{-1}s^{-1}[/tex]

t = time = 0.240 s

[tex][A_t][/tex] = final concentration = ?

[tex][A_o][/tex] = initial concentration = 1.44 M

Now put all the given values in the above expression, we get:

[tex]14.1\times 0.240=\frac{1}{[A_t]}-\frac{1}{1.44}[/tex]

[tex][A_]t=0.24M[/tex]

Therefore, the concentration of SO₃ in the vessel 0.240 seconds later is, 0.24 M

Choose the answer that best completes the following statement: When an aluminum atom reacts so as to attain a noble gas electron configuration?

Answers

The options

Select one:

a. a 3- ion forms.

b. the noble gas configuration of argon is achieved.

c. the result is a configuration of 1s2 2s2 2p6.

d. the atom gains five electrons.

Answer:

c. the result is a configuration of 1s2 2s2 2p6.

Explanation:

Aluminium atom has atomic number of 13 , hence the number of electron is 13 for a neutral atom of aluminium. When aluminium atom reacts with other elements it usually gives out three electron to attain the octet configuration.

The cation representation of aluminium is Al3+ because it has loss three electron to attain the octet rule. Aluminium will be left with 10 electrons after losing 3 of it electrons. The electronic configuration will be represented as follows after losing three electrons;

1S² 2S² 2P∧6 .

At this stage the octet rule has been achieved as it will be represented as

2  8.  The first energy shell now contains two electron and the second energy shell contains 8 electrons.

The configuration of  Neon has been formed in the process.

A sample has a mass of 7.412 grams and a volume of 0.217 liters. What is the density of this sample?

Answers

Answer : The density of a sample is, 34.2 g/L

Explanation :

Density : It is defined as the mass contained per unit volume.

Formula used for density :

[tex]Density=\frac{Mass}{Volume}[/tex]

Given :

Mass of a sample = 7.412 grams

Volume =0.217 L

Now put all the given values in the above formula, we get the density of a sample.

[tex]Density=\frac{7.412g}{0.217L}=34.2g/L[/tex]

Therefore, the density of a sample is, 34.2 g/L

ilver bromide is used to coat ordinary black-and-white photographic film, while high-speed film uses silver iodide. (a) When 56.6 mL of 5.00 g/L AgNO3 is added to a coffee-cup calorimeter containing 56.6 mL of 5.00 g/L NaI, with both solutions at 25°C, what mass of AgI forms?

Answers

Answer:

Mass of AgI formed=0.352g

Explanation:

AgNO3 + NaI ----‐>AgI + NaNO3

Volume of AgNO3 =5g/L

Mass of AgNO3 =C×V=0.25g

n(AgNO3)= m/Mr=0.0015mol

For NaI

V= 5g/l

Mass= C×v=0.25g

n=m/Mr=0.0017mol

n=0.0015mol

Mass=n× mr=0.352g

From the stoichiometry of the reaction, 0.45 g of AgI is formed.

First of all we have to obtain the molar concentration of AgNO3 using the formula;

Mass concentration = molar concentration × molar mass

Molar concentration = Mass concentration /molar mass

Molar concentration = 5.00 g/L/170 g/mol = 0.029 M

Number of moles of AgNO3  = molar concentration × volume

=  0.029 M  × 56.6/1000 L= 0.0016 moles

Molar concentration of NaI =  5.00 g/L /150 g/mol = 0.033 M

Number of moles of NaI = 0.033 M  × 56.6/1000 L = 0.0019 moles

The reaction equation is;

AgNO3 + NaI -----> AgI + NaNO3

Since the reaction is 1:1 then AgNO3 is the limiting reactant.

Mass of AgI formed = 0.0016 moles  × 235 g/mol = 0.45 g

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To identify a diatomic gas (X2), a researcher carried out the following experiment: She weighed an empty 4.4-L bulb, then filled it with the gas at 1.00 atm and 22.0 ∘C and weighed it again. The difference in mass was 5.1 g . Identify the gas.

Answers

Answer : The diatomic gas is nitrogen gas, N₂.

Explanation :

First we have to calculate the moles of gas.

Using ideal gas equation:

[tex]PV=nRT[/tex]

where,

P = Pressure of gas = 1.00 atm

V = Volume of gas = 4.4 L

n = number of moles of gas = ?

R = Gas constant = [tex]0.0821L.atm/mol.K[/tex]

T = Temperature of gas = [tex]22.0^oC=273+22.0=295.0K[/tex]

Putting values in above equation, we get:

[tex]1.00atm\times 4.4L=n\times (0.0821L.atm/mol.K)\times 295.0K[/tex]

[tex]n=0.1817mol[/tex]

Now we have to calculate the molar mass of gas.

[tex]\text{Molar mass of gas}=\frac{\text{Given mass of gas}}{\text{Moles of gas}}[/tex]

[tex]\text{Molar mass of gas}=\frac{5.1g}{0.1817mol}=28.07g/mol[/tex]

As we are given that the gas is diatomic X₂.

As, 2 atoms of gas X has mass = 28.07 g/mol

So, 1 atom of gas will have mass = [tex]\frac{28.07}{2}=14.04g/mol[/tex]

From this we conclude that the nitrogen atom has mass of 14.04 g/mol.

Thus, the diatomic gas is nitrogen gas, N₂.

1. a substance that changes the rate of the reaction, and is not consumed in the reaction solution
2. a uniform mixture of molecules or ions of one substance in another solvent
3. the substance dissolved in a solution solute
4. that component of a solution which dissolves the solute catalyst

Answers

Answer:

1. Catalyst

2. Solution

3. Solute

4. Solvent

Explanation:

1. A catalyst increases reaction rate but is not used up or consumed in the reaction

Example of a catalyst found in nature are Enzymes

2. Solution, an homogeneous mixture of two or more substances solutes and solvents

3. Solute, the component of a solution dissolved in the solvent

4. Solvent, the component of a solution that dissolves the solute

White vinegar is available as a 5% acetic acid solution and a 10% solution, by volume. How many millilitres of each solution must be added to make 100ml of a 7%solution?

Answers

Answer:

The answer to your question is 60 ml of solution 5% and 40 ml of solution 10 %

Explanation:

Data

acetic acid = 5% = concentration 1

acetic acid 2 = 10% = concentration 2

final solution = 7 % =

final volume = 100 ml

Process

1.- Write an equation of the process

x = volume of solution 5%

100 - x = volume of solution 10%

Final concentration x final volume = concentration 1 x volume 1 + concentration 2 x volume 2

      0.07(100) = 0.05x + 0.10(100 - x)

2.- Solve for x

                  7 = 0.05x + 10 - 0.1x

                 7 - 10 = 0.05 - 0.1 x

                   - 3 = -0.05 x

                     x = -3/-0.05

                     x = 60 ml of solution 5%

3.- Calculate the volume of solution 10%

     Volume of 10% = 100 - 60

     Volume of 10% = 40 ml        

                         

give an examoke of a simple chemical reaction that involves the transfer of electrons from a metallic element ot a nonmetallic element

Answers

Answer:

Below.

Explanation:

The reactions between sodium and chlorine.

2Na + Cj2 ---->  2NaCl.

1 electron from the sodium is transferred to the chlorine atom.

A simple chemical reaction involving the transfer of electrons from a metal to a nonmetal is the formation of sodium chloride from sodium and chlorine gas. This is an oxidation-reduction reaction where sodium is oxidized and chlorine is reduced, leading to the creation of an ionic compound.

An example of a simple chemical reaction that involves the transfer of electrons from a metallic element to a nonmetallic element is the reaction between metallic sodium and chlorine gas to form sodium chloride. This type of reaction is known as an oxidation-reduction or redox reaction. In the reaction, sodium, the metal, donates its electrons to chlorine, the nonmetal, resulting in the formation of sodium ions (Na⁺) and chloride ions (Cl⁻), which together form the ionic compound sodium chloride (NaCl).

The reaction can be represented by the equation:

2 Na (s) + Cl₂ (g) ⇒ 2 NaCl (s)

In this reaction, each sodium atom loses one electron (oxidation) to become a sodium ion, while each chlorine molecule gains two electrons (reduction) to form two chloride ions. The sodium cation (Na⁺) and the chloride anion (Cl⁻) then bond together to create the ionic compound sodium chloride.

A scientist obtains the number 1250.37986 on a calculator. If this number actually has four (4) significant figures, how should it be written?

A)1251
B)1250.3799
C)1250.4
D)1.250 x 10^3
E)1.250 x 10^–3

Answers

Answer:

D

Explanation:

the zero is trailing with a decimal so it counts. A is wrong because you can't round up, C is too many SF and E is wrong because a negative exponent would give you .001250

Answer: D

Explanation:

Not A: You don’t round up to 1251 because 3 is less than 5

Not B: That’s more than 4 sig figs

Not C: More than 4 sig figs

D: 1.250 has 4 sig figs and 1250 is the correct answer

Not E: negative exponent makes it into decimal which is way off

If an impure sample of soda ash is known to contain 40.00% of Na2CO3, calculate the sample size in mg which will react with exactly 40.00 mL of 0.1100 M HCl.What is the % purity of a soda ash sample if it took 42.15mL of 0.1100 M HCl to titrate 0.5017 g of the sample?

Answers

The sample size is 233.19 mg and the purity of the sample is 48.97%

Why?

The chemical reaction between Na₂CO₃ and HCl is

Na₂CO₃ + 2HCl → 2NaCl + H₂O + CO₂

The sample size that will react with 40 mL of 0.1100 M HCl is found by applying the following conversion factor to go from L of solution of HCl to mg of Na₂CO₃:

[tex]0.04 Lsolution*\frac{0.1100molesHCl}{1L solution}*\frac{1 mole Na_2CO_3}{2 moles HCl}*\frac{105.99 gNa_2CO_3}{1 mole Na_2CO_3}*\frac{1000mg}{1 g}\\ \\=233.19mgNa_2CO_3[/tex]

Now, in order to find the percentage purity we have to apply another conversion factor to go from mL of solution of HCl to g of Na2CO3, and dividing everything over the mass of the soda ash sample, followed by multiplying the result times 100 to find the percentage:

[tex]0.04215 Lsolution*\frac{0.1100molesHCl}{1L solution}*\frac{1 mole Na_2CO_3}{2 moles HCl}*\frac{105.99 gNa_2CO_3}{1 mole Na_2CO_3}\\ \\=0.2457mgNa_2CO_3*\frac{100\%}{0.5017 g} = 48.97 \%\\[/tex]

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Final answer:

These chemistry problems involve calculating the moles of reactants in a stoichiometry equation to establish necessary sample size and the purity of a sample. By understanding these concepts, you can calculate the sample's purity and size.

Explanation:

The subject of this question is a stoichiometry problem, relating the amounts of reactants and products in a chemical reaction, and how to calculate a sample's purity. Stoichiometrically, each mole of sodium carbonate, Na2CO3, reacts with two moles of hydrochloric acid, HCl. Given the molarity of HCl (0.1100 M), you can calculate the number of moles by multiplying the molarity by the volume used in liters.

For the first question, it's given that the sample contains 40.00% Na2CO3. Therefore, the number of moles of HCl needed would be twice the number of moles of Na2CO3 (given that the reaction is 1:2). From there, you can calculate the required sample mass in milligrams.

For the second question, if it took 42.15 mL of 0.1100 M HCl to titrate a 0.5017 g sample, again calculate the moles of HCl used, and hence moles of Na2CO3. The mass of Na2CO3 is determined from its molar mass, and then the purity can be calculated as the mass of Na2CO3 divided by the total mass of the sample multiplied by 100%.

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780. mm Hg to kPa,
I'm struggling to get the answer with the correct sig figs ;(

Answers

Answer:

103.9 kPa

Explanation:

It's more easy to convert mmHg to Pa and then /1000

Let's try the rule of three:

760 mmHg  is 101325 Pa

780 mmHg (780 mmHg . 101325 Pa) / 760mmHg = 103991.4 Pa

1 kPa = 1000 Pa

103991.4 Pa / 1000 = 103.9 kPa

The Balmer Series of lines in the hydrogen atom was very important in the history of physics and astronomy. What made it so important?
A) It helped Rutherford explain the workings of the atomic nucleus.
B) Balmer's experiments with these lines helped prove Wien's Law.
C) When electrons change levels to produce the Balmer series, the emitted light is in the visible part of the spectrum.
D) The Balmer series of lines can only be observed from outer space; so the competition to see these lines led to the space race.
E) Mr. Balmer never got the Nobel prize, which made everyone in the field of spectroscopy so angry, they worked extra hard.

Answers

Answer:

C) When electrons change levels to produce the Balmer series, the emitted light is in the visible part of the spectrum

Explanation:

The Balmer Series of lines in the hydrogen atom was very important in the history of physics and astronomy. What made it so important?

A) It helped Rutherford explain the workings of the atomic nucleus.

B) Balmer's experiments with these lines helped prove Wien's Law.

C) When electrons change levels to produce the Balmer series, the emitted light is in the visible part of the spectrum.

D) The Balmer series of lines can only be observed from outer space; so the competition to see these lines led to the space race.

E) Mr. Balmer never got the Nobel prize, which made everyone in the field of spectroscopy so angry, they worked extra hard.

the most appropriate will be

C) When electrons change levels to produce the Balmer series, the emitted light is in the visible part of the spectrum

Balmer series of hydrogen lines. These lines are emitted when the electron in the hydrogen atom moves from the orbital n = 3 or greater shell down to the n = 2 shell/orbit. ... Energy is emitted from the atom when the electron leaps from one orbit to another closer to the nucleus.

Wiens law has to do with the radiation  of a black body.

A sample of oxygen gas occupies a volume of 250. mL at a pressure of 740. torr. What volume will the gas occupy at a pressure of 800. torr if temperature is held constant?

Answers

Answer: we will solve it using Boyle's law that is:

P1V1 = P2V2

Explanation:

Substituting the given values

740 torr × 250 mL = 800 torr × V2

rearranging the equation for V2

740 torr × 250 mL / 800 torr = V2

'torr' in numerator cancelled by 'torr' in denominator

740 × 250 mL / 800 = V2

V2 = 231.24 mL

Final answer:

The volume of the oxygen gas will be approximately 231.25 mL at 800 torr, according to Boyle's law.

Explanation:

To answer your question, we can use Boyle's law, which states that the pressure and volume of a gas have an inverse relationship when the temperature is kept constant. In mathematical format, this is represented as P₁V₁ = P₂V₂, where P represents pressure, V represents volume, and the subscripts 1 and 2 represent the initial and final states, respectively. If we substitute the known values into the equation, we get (740. torr)(250. mL) = (800. torr)(V₂). By solving for V₂, we find that the new volume is approximately 231.25 mL.

Boyle's law and its implications are critical parts of understanding gas behavior, particularly in applications involving pressure and volume changes such as this one. Note that it's crucial to maintain a constant temperature for Boyle's law to be applicable, as stated in your question.

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a graduated cylinder contains 18.0ml of water. what is the new water level after 35.6g of silver metal with a density of 10.5 g/ml is submerged in the water?

2.a thermometer containing 8.3g of mercury has broken. if mercury has a density of 13.6 g/ml what volumn spilled.

3. a fish tank holds 345gal of water. using the density of 1.0 g/ml for water, determine the number of pounds of water in the fish tank.

Answers

Answer:

The answer to your question is

1.- Volume = 3.4 ml

2.- Volume = 0.61 ml

3.- Mass = 2872.8 pounds

Explanation:

Problem 1

Volume = 18 ml

mass = 35.6 g

density = 10.5 g/ml

Process

1.- Calculate the volume of silver

Formula

[tex]density = \frac{mass}{volume}[/tex]

solve for volume

[tex]volume = \frac{mass}{density}[/tex]

Substitution

[tex]volume = \frac{35.6}{10.5}[/tex]

volume = 3.4 ml

2.- Problem 2

Total volume = ?

Volume = 18 + 3.4

Volume = 21.4 ml

Data

mass = 8.3 g

density = 13.6 g(ml

volume = ?

Formula

[tex]density = \frac{mass}{volume}[/tex]

Solve for volume

[tex]volume = \frac{mass}{density}[/tex]

Substitution

[tex]volume = \frac{8.3}{13.6}[/tex]

Result

volume = 0.61 ml

3.- Problem 3

Data

volume = 345 gal

density = 1 g/ml

mass = ?

Formula

[tex]density = \frac{mass}{volume}[/tex]

Solve for mass

mass = density x volume

Covert gal to ml

                            1 gal --------------- 3785 ml

                         345 gal -------------  x

                            x = (345 x 3785) / 1

                            x = 1305825 ml

Substitution

mass = 1 x 1305825

mass = 1305825 g

Convert g to pounds

                        1 g ------------------- 0.0022 pounds

              1305825 g ----------------   x

                        x = (1305825 x 0.0022)

                        x = 2872.8 pounds

Each molecule of testosterone contains 19 atoms of carbon (plus other atoms). The mass percent of carbon in testosterone is 79.12%. What is the molar mass of testosterone?A. 576.8 g/molB. 180.5 g/molC. 228.2 g/molD. 240.1 g/molE. 288.4 g/mol

Answers

Answer:

The answer to your question is letter E. 288.4 g/mol

Explanation:

Data

Number of carbons = 19

mass percent of carbon = 79.12

molar mass = ?

Process

1.- Calculate the molar mass of 19 atoms of carbon

Atomic mass of carbon = 12 g

Atomic mass of 19 atoms of carbon = 228 g                            

2.- Use proportions to calculate the mass of testosterone

                        228 g ---------------  79.12 %

                           x      --------------      100 %                          

                          x = (228 x 100) / 79.12

Simplify

                          x = 22800 / 79.12

Molar mass of testosterone = 288.2 g          

Match the associations with the "light" and "dark" phases of photosynthesis:
a. solar energy.
b. CO 2 intake.
c. release of energy.
d. storage of energy.
e. release of O2.
f. release of water.
g. ATP.
h. forms carbohydrates.

Answers

Answer:

Explanation:

Light:

Solar Energy, Storage of Energy, Release of O2, & ATP

Dark:

CO2 Intake, Release of Energy, Release of Water, & Forms Carbohydrates.

Hope this helps!

Final answer:

In photosynthesis, solar energy is utilized during the light phase to produce ATP and release O₂, while the Calvin cycle (dark phase) involves CO₂ intake and the formation of energy-storing carbohydrates.

Explanation:

Photosynthesis consists of two main phases: the light reactions and the Calvin cycle (often referred to as the 'dark' phase). Here is the association of the given elements to each phase:

Solar energy (a) is used during the light reactionsCO₂ intake (b) and forms carbohydrates (h) occur during the Calvin cycleThe light reactions involve the release of energy (c), which is captured in the form of ATP (g)Storage of energy (d) takes place in the Calvin cycle as energy is stored in carbohydrate moleculesThe release of O₂ (e) is a by-product of the light reactionsRelease of water (f) is not directly a product of photosynthesis and generally relates to transpiration rather than photosynthesis itself

Light Phase Associations

Solar energy (a)Release of energy as ATP (c and g)Release of O₂ (e)

Dark Phase (Calvin cycle) Associations

CO₂ intake (b)Storage of energy in carbohydrates (d and h)

These associations help the processes involved in photosynthesis, where light energy is captured to produce ATP and NADPH, and then used along with CO₂ in the Calvin cycle to produce energy-storing carbohydrates, with O₂ released as a by-product.

Assuming 100% dissociation, calculate the freezing point and boiling point of 1.22 m SnCl₄(aq). Constants may be found here.
Colligative Constants
Constants for freezing-point depression and boiling-point elevation calculations at 1 atm:
Solvent - Formula - [tex]K_f[/tex] value*(°C/m) - Normal freezing point (°C) - [tex]K_b[/tex] value (°C/m) - Normal boiling point (°C)
water - H₂O - 1.86 - 0.00 - 0.512 - 100.00
benzene - C₆H₆ - 5.12 - 5.49 - 2.53 - 80.1
cyclohexane - C₆H₁₂ - 20.8 - 6.59 - 2.92 - 80.7
ethanol - C₂H₆O - 1.99 - -117.3 - 1.22 - 78.4
carbon tetrachloride - CCl₄ - 29.8 - -22.9 - 5.03 - 76.8
camphor - C₁₀H₁₆O - 37.8 - 176
*When using positive [tex]K_f[/tex] values, assume that ?[tex]T_f[/tex] is the absolute value of the change in temperature. If you would prefer to define ?[tex]T_f[/tex] as "final minus initial" temperature, then ?[tex]T_f[/tex] will be negative and so you must use negative [tex]K_f[/tex] values. Either way, the freezing point of the solution should be lower than that of the pure solvent.
[tex]T_f[/tex] = _______ Celsius
[tex]T_b[/tex] = _______ Celsius

Answers

Answer:

T° freezing solution → -11.3°C

T° boiling solution → 103.1 °C

Explanation:

Assuming 100 % dissociation, we must find the i, Van't Hoff factor which means "the ions that are dissolved in solution"

This salt dissociates as this:

SnCl₄ (aq)  →   1Sn⁴⁺ (aq)  +   4Cl⁻  (aq)   (so i =5)

The formula for the colligative property of freezing point depression and boiling point elevation are:

ΔT = Kf . m . i

where ΔT = T° freezing pure solvent - T° freezing solution

ΔT = Kb . m . i

where ΔT = T° boiling solution - T° boiling pure solvent

Freezing point depression:

0° - T° freezing solution = 1.86°C/m . 1.22 m . 5

T° freezing solution = - (1.86°C/m . 1.22 m . 5) → -11.3°C

Boiling point elevation:

T° boiling solution - 100°C = 0.512 °C/m . 1.22 m . 5

T° boiling solution = (0.512 °C/m . 1.22 m . 5) + 100°C → 103.1 °C

In order to have a positive charge, an atom must have ________. In order to have a positive charge, an atom must have ________. A. more electrons than protons B. more protons than neutrons C. more neutrons than protons D.more protons than electrons

Answers

Answer:

C

Explanation:

The charge on an atom depends on the number of protons and electrons present in it. The protons in an atom are positively charged while electrons have a negative charge. For a neutral atom, the number of protons balances the number of electrons. for a negatively charged atom, the number of electrons is more than the number of protons. for a positively charged atom , the number of protons are more than the number of electrons.

Final answer:

An atom must have more protons than electrons in order to have a positive charge.

Explanation:

In order to have a positive charge, an atom must have more protons than electrons.

An atom is electrically neutral when it has the same number of electrons and protons. But if an atom has more protons than electrons, it will have an overall positive charge. For example, a dime has more protons than electrons, so it has a positive charge.

The positive charge of a proton is balanced by the negative charge of an electron. If an atom gains or loses electrons, it becomes an ion with a positive or negative charge.

Which of the following will occur if a prokaryotic cell is placed in a solution that has a higher concentration of solutes (that cannot readily diffuse across the plasma membrane) than does the cytoplasm of the cell?

Answers

Answer:

This Question is incomplete

Explanation:

What is needed to be understood here is the concept of hypertonic and hypotonic solutions and their effects on cells.

Hypertonic solution is a solution in which the concentration of the solutes outside of the cell is greater than inside (in the cytoplasm) of the cell while hypotonic solution is a solution in which the concentration of solutes inside of the cell (in the cytoplasm) is greater than outside of the cell.

From the above, we can deduce that the question is about the effect of placing a prokaryotic cell in a hypertonic solution. When a prokaryotic cell is placed in a hypertonic solution, water moves (through osmosis) from inside of the cell to the outside environment causing the prokaryotic cell to shrink.

In a hypertonic solution, water will leave a prokaryotic cell through osmosis, causing it to shrink, which can interfere with its functions and lead to cell death if prolonged.

If a prokaryotic cell is placed in a solution that has a higher concentration of solutes than does the cytoplasm of the cell, the environment is described as being hypertonic. In this condition, the concentration of water outside the cell is lower than inside, leading to the net flow of water moving out of the cell. This process is known as osmosis. As water leaves the cell, it can cause the cell to shrink in a process termed plasmolysis. This can interfere with the cell's functions and potentially lead to cell death if the dehydration is prolonged. The cell wall in prokaryotes provides some protection against osmotic pressure, but the loss of water in a hypertonic solution still poses a significant challenge to the cell's viability.

A machine has a mechanical advantage of 0.6. What force should be applied to the machine to make it apply 600 N to an object?

Answers

Answer:

1000N is needed to be applied.

Explanation:

Machines make doing work easier. They allow us use small effort to carry out work on huge amount of load.

The mechanical advantage of a machine;

(M.A) =load/effort

M.A = 0.6

Load =600N

effort =?

0.6 = 600/effort

effort = 600/0.6

effort = 1000N

Answer:c

Explanation:

An air compressor takes atmospheric air (think about what pressure it is at) and pressures it up to 68 (psig). In the process, it warms up from 26 degC to 48 degC. If the original volume of air is 13 (m^3). What is the resulting volume (m^3) after the air is compressed and heated?

Answers

Answer:

5.19 m³  

Explanation:

Data Given:

initial Pressure P1 = atmospheric pressure

Reported atmospheric pressure =  14.696 psi

Final pressures P2 =  68 psi

initial Temperature T1 =  26 °C

final Temperature T2 =  48 °C

initial Volume V1= 13 m³

final Volume V2 = ?

Solution:

Formula will be used

                    P1 V1 / T1 = P2 V2 / T2

To calculate volume rearrange the above formula

                   V2 = (P1 V1) T2 / T1 P2 . . . . . . . .(1)

put values in equation 1

                  V2 = (14.696 psi x 13 m³) 48 °C / 26 °C x 68 psi

                  V2 = (191.05 psi m³) 48 °C / 1768 °C psi

                  V2 = (9170.3  psi m³ °C / 1768 °C psi

                  V2 = 5.19 m³

So, final volume is 5.19 m³                

The compound magnesium phosphate has the chemical formula Mg3(PO4)2. In this compound, phosphorous and oxygen act together as one charged particle, which is connected to magnesium, the other charged particle.What does the 2 mean in the formula 5Mg3(PO4)2?

Answers

The '2' in the chemical formula Mg₃(PO₄)₂ indicates that there are two phosphate groups for every three magnesium ions, forming the neutral ionic compound magnesium phosphate.

The chemical formula Mg₃(PO₄)₂ represents the compound magnesium phosphate. In this formula, Mg is the symbol for magnesium, and PO₄ is the polyatomic ion representing a phosphate group. The subscript '2' outside the parentheses indicates that there are two phosphate groups in the compound. When magnesium (Mg) has a 2⁺ charge and pairs with the phosphate ion (PO₄) that carries a 3⁻ charge, balancing the charges requires three magnesium ions to pair with two phosphate groups, resulting in the formula Mg₃(PO₄)₂. This substance is an example of an ionic compound where the constituents have different charges and combine in a ratio to form a neutral compound.

Thus, the '2' in the formula 5Mg₃(PO₄)₂ means that for every three magnesium ions, there are two phosphate ions. The leading '5' suggests that the entire formula is multiplied by five, indicating that there are five units of Mg₃(PO₄)₂ in the expression.

A solution of salt (molar mass 90 g mol-1) in water has a density of 1.29 g/mL. The concentration of the salt is 35% by mass.

a. Calculate the molality of the solution.

b. Calculate the molarity of the solution.

c. Calculate the mole fraction of the salt in the solution.

Answers

Answer:

a) 5.9846 mol/kg

b) 5.018 mol/L

c)0.09725

Explanation:

consider 100 g of solution

now

since the salt is 35 % , water will be 65 %

now

mass of salt = 35 g

mass of water = 65 g

we know that

moles = mass / molar mass

so

moles of salt = 35 g / 90 (g/mol) = 0.389 mol

moles of water = 65 / 18 = 3.6111 mol

now

volume of solution = mass of solution / density of solution

volume of solution = 100 g / ( 1.29 g/ml)

volume of solution = 77.52 ml

volume of solution = 0.07752 L

a)molality = moles of salt / mass of water (kg)

molality = 0.389 mol / 0.065 kg

molality = 5.9846 mol/kg

b)

molarity = moles of salt / volume of solution (L)

molarity = 0.389 mol / 0.07752 L

molarity = 5.018 mol/L

c)

now

total moles in the solution = moles of salt + moles of water

total moles in the solution = 0.389 + 3.6111

total moles in the solution = 4 mol

now

mole fraction of salt = moles of salt / total moles

mole fraction of salt = 0.389 mol / 4 mol

mole fraction of salt = 0.09725

The molarity of the solution is 5.018 mol/L and molality of the solution 5.9846 mol/kg.

 

Assume 100 g of solution the salt concentration- 35 % and water will be 65 %.    

So,  

mass of salt = 35 g  

mass of water = 65 g  

Number of moles,  

[tex]\bold {moles = \dfrac {mass} { molar\ mass}}[/tex]

So,    

moles of salt = 35 g / 90 (g/mol) = 0.389 mole  

moles of water = 65 / 18 = 3.6111 mole  

 

Volume of solution,

[tex]\bold {volume =\dfrac { mass } {density }}[/tex]  

volume = 100 g / ( 1.29 g/ml)  

volume of solution = 77.52 ml = 0.07752 L  

 

a)

[tex]\bold {Molality = \dfrac {moles\ of \salt} { mass\ of\ water (kg)}}[/tex]  

molality = 0.389 mol / 0.065 kg  

molality = 5.9846 mol/kg  

b)  

molarity = moles of salt / volume of solution (L)

molarity = 0.389 mol / 0.07752 L  

molarity = 5.018 mol/L  

c)    

 mole fraction of salt = moles of salt / total moles  

mole fraction of salt = 0.389 mol / ( 0.389 + 3.6111)  

mole fraction of salt = 0.09725

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