Answer:
3.143 m/s
Explanation:
m1 = 9 kg
u1 = 14 m/s
m2 = 12 kg
u2 = - 5 m/s
Let the velocity after the collision is V
By using the principle of conservation of momentum
Momentum of two bodies before collision = momentum of two bodies after collision
m1 x u1 + m2 x u2 = (m1 + m2) x V
9 x 14 - 12 x 5 = (9 + 12) x V
126 - 60 = 21 x V
V = 3.143 m/s
Thus, the velocity of the sticked bodies after the collision is given by 3.143 m/s.
To find the final velocity of two colliding masses sticking together, use the conservation of momentum equation. The total momentum before collision equals total momentum after collision, yielding a final velocity of 3.14 m/s to the right.
To find the final velocity of the combination of the two masses after the collision, we can use the principle of conservation of momentum. The total momentum before the collision is equal to the total momentum after the collision.
Step-by-Step Solution:
Determine the initial momenta of each mass:
Momentum of the 9.00 kg mass:
p₁ = m₁v₁
p₁ = 9.00 kg × 14.0 m/s
p₁ = 126 kg·m/s (to the right)
Momentum of the 12.0 kg mass:
p₂ = m₂v₂
p₂ = 12.0 kg × (-5.00 m/s)
p₂ = -60 kg·m/s (to the left)
Add the momenta to find the total initial momentum:
[tex]p_{total[/tex] = p₁ + p₂
[tex]p_{total[/tex] = 126 kg·m/s - 60 kg·m/s
[tex]p_{total[/tex] = 66 kg·m/s
Calculate the total mass after the collision:
[tex]m_{total[/tex] = m₁ + m₂
[tex]m_{total[/tex] = 9.00 kg + 12.0 kg
[tex]m_{total[/tex] = 21.0 kg
Using the conservation of momentum, the combined mass's final velocity (vf) is given by:
[tex]v_f[/tex] = [tex]p_{total[/tex] / [tex]m_{total[/tex]
[tex]v_f[/tex] = 66 kg·m/s / 21.0 kg
[tex]v_f[/tex] = 3.14 m/s
Therefore, the final velocity of the combination after the collision is 3.14 m/s to the right.
Which is constant for a freely falling object
Answer: acceleration
For a freely falling body acceleration is always constant and it is equal to gravitational force.i.e., a = g =9.81 m/s² at sea level of the earth
The weight , size and shape are not the factors to describe the free fall.What happens to your weight on Earth when your mass increases? It stays constant. It also increases. It decreases.
When your mass increases your weight on earth also increases
2- it also increases
When a person's mass increases on Earth, their weight also increases since weight is the gravitational force acting on mass. Mass does not change with location, while weight can vary with gravity's strength. An astronaut's mass is constant, but their weight decreases on the Moon due to lower gravity.
The relationship between mass and weight is a fundamental concept in physics. When your mass on Earth increases, your weight also increases. This is because weight is the force of gravity acting on an object's mass. Since gravity on Earth is essentially constant, an increase in mass results in a directly proportional increase in weight.
It is essential to understand that while mass is a measure of the quantity of matter in an object and does not change with location, weight is the gravitational force exerted on that mass and can vary with the strength of the gravitational field. On Earth, the acceleration due to gravity is approximately 9.80 m/s².
An example to illustrate this is comparing your weight on Earth to that on the Moon. If an astronaut traveled from Earth to the Moon, their mass would remain the same but their weight would decrease because the Moon's gravitational acceleration is only about one-sixth that of Earth's (1.67 m/s² compared to 9.80 m/s²).
You walk 20 m north, then 5 meters south . What is your displacement?
-- You start out.
-- You walk 20 m north.
-- Then you walk 5 m south.
-- Your displacement, relative to where you started from is 15 m north .
Ethan made a diagram to compare examples of the first and second laws of thermodynamics. What belongs in the areas marked X and Y?
First law of thermodynamics:
It states that "Energy neither be created nor it can be destroyed". simply it converts one form of energy into another form. It is also known as "law of conservation of energy"Limitations of First law
It doesn't provide a clear idea about the direction of transfer of heat.It doesn't provide the information that how much heat energy converted inti work.Its not given any practical applications.II law of thermodynamics:
It states that "the total entropy of the system can never decrease over time"
It is strongly proved by two laws, they are
1. Kelvin-plank statement:
He stated that "any engine does not give 100% efficiency". It violates the Perpetual motion of machine II kind(PMM-II).
2. Classius statement:
It states that "Heat always flows from high temperature body to low temperature body, without aid of external energy".
Also it stated that " Heat can also be transferred from low temperature body to high temperature body, by the aid of an external energy".
Applications of II law:
Refrigeration &Air conditioning, Heat transfer, I.C. engines, etc.
Answer:
The answer is D.
Explanation:
I just took the quiz.
What is the acceleration of a bus that goes from rest to a speed of 50km/h in 10s?
a = (Vf - Vi) / t = (13.9 m/s - 0 m/s) / 10 s = 1.4 m/s^2
Answer:
Acceleration of the bus is 1.38 m/s^2
Explanation:
Given that,
Initial speed of the bus, u = 0 m/s (rest)
Final speed of the bus, v = 50 km/h
or v = 13.88 m/s
Time taken, t = 10 s
To find :
The magnitude of the acceleration of the car.
Solve :
Let a is the acceleration of the car. The rate of change of velocity is called the acceleration of the bus. Its formula is given by :
[tex]a=\dfrac{v-u}{t}[/tex]
[tex]a=\dfrac{(13.88-0)\ m/s}{10\ s}[/tex]
[tex]a=1.38\ m/s^2[/tex]
Therefore, the magnitude of the car's acceleration is 1.38 m/s^2.
a car moving 60km/hr in one hour will travel.
Given that
Speed = 60 Km/hr
In one hour, how much distance travelled by car
We know that
Distance = Speed × time
S = 60 × 1
S = 60 Km
In one hour car will travel 60 Km
Which simple machine is the lid of a jar? a lever a screw an inclined plane a wheel and axle
The answer is a screw.
If you look up screws you can see they work the exact same!
Consider a stone at rest on the ground. There are two interactions that involve the stone. One is between the stone and the Earth; Earth pulls down on the stone and the stone pulls up on the Earth. What is the other interaction? 1. All are wrong. 2. between the ground and the Earth 3. between the ground and air 4. between the Earth and air 5. between the stone and the ground
5. between the stone and the ground
for a stone at rest on the ground, we have two forces acting on the stone. first is the force on the stone by the earth due to gravity of earth. second is the force applied by the ground in upward direction to balance the force of gravity on the stone.
so first interaction is between earth and stone : earth pulls stone towards it and stone pulls earth towards it by same amount of force.
second interaction is between stone and ground : ground push the stone in upward direction and stone push the ground in down direction by same amount of force.
hence the correct choice is
5. between the stone and the ground
The stone at rest on the ground is not only interacting with the Earth through gravitational force but also interacting with the ground through what's known as a normal force. The ground pushes up on the stone with a force equal to the stone's weight, balancing out the pull of gravity and keeping the stone at rest.
Explanation:The other interaction involving the stone you're asking about is the interaction between the stone and the ground. According to Newton's third law, every action has an equal and opposite reaction. Therefore, as Earth exerts a gravitational force pulling the stone down, the stone exerts an equivalent force onto the Earth. Similarly, the stone's contact with the ground is also a significant interaction. When the stone rests on the ground, the ground exerts a force (the reaction force or the normal force) that balances the weight of the stone, which is the force due to gravity. As a result, the stone doesn't move further downwards.
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A 0.013 rubber stopper attached to a 0.93 string is swung in a circle if the tension in the string is 0.35 what is the period of the stoppers motion
1.2
0.45
0.59
1.8
The period of the stoppers motion is 1.2 second. Hence, option (A) is correct.
What is centripetal acceleration?Centripetal acceleration is a characteristic of an object's motion along a circular path. Centripetal acceleration applies to any item travelling in a circle with an acceleration vector pointing in the direction of the circle's center.
A centripetal acceleration occurs when you drive in a circle, and a centripetal acceleration also occurs when a satellite orbits the earth. Centripetal refers to being in the center.
Mass of the rubber stopper: m = 0.013 kg.
Length of the string: r = 0.93 meter.
Tension in the string is: T = 0.35 Newton.
Hence, centripetal acceleration of the rubber stopper: a = 0.35/0.013 m/s²
= 26.92 m/s²
Let the angular velocity is ω; then
ω²r = a
ω = √(26.92/0.93) rad/s
= 5.38 rad/second.
Hence, the period of the stoppers motion is = 2π/ω
= 2π/5.38 second
= 1.2 second.
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A 50 Kg box sits at rest on a 30 degree ramp where the coef of static friction is 0.5773. If your push was directed at an angle of 40 degrees to the ramp, how hard would you have to push to get the box to move up the ramp?
Given data:
m= 50 Kg,
W= m×g = 50 × 9.81 = 490.5 N
ramp angle (α) = 30 degrees,
coefficient of friction (μs) = 0.5773,
Push at an angle (Θ) = 40 degrees,
Determine: Push to get box move up (P)=?
From the figure,
Resolving the forces along the plane
W sinα + μs.R = P cos Θ --------------------- (i)
Resolving the forces perpendicular to the inclined plane
W cosα = R+Psin Θ => R= W cosα - Psin Θ -------------- (ii)
Solving (i) and (ii) and keeping μs = tan Φ, Φ = Θ
Pmin = W sin( α +Θ )
= W[ sin α.Cos Θ + cos α.sin Θ]
= 490.5 [ (sin 30.cos40) + (cos30.sin 40)]
= 460.9 N
Minimum push required to move the box up the ramp is 460.9 N
How much physical activity should an adult have each week?
A.60 minutes per day, 7 days a week
B.30 minutes per day, 7 days a week
C.60 minutes per day, 5 days a week
D.30 minutes per day, 5 days a week
d 30 minutes a day , 5 days a week
Answer:
D. 30 minutes per day, 5 days a week
Explanation:
As per World Health Organization (WHO) physical activity includes the following :
- Leisure time physical activity like running
- Occupational work
- Household chores
- Sports
An adult (aged 18-64) should do at least 150 minutes of physical activity per week. That can be divided over 5 days a week as well with 30 minutes of physical activity per day.
What is the net force acting on a falling object when it reaches terminal velocity? a force equal to gravity 9.8 m/s2 two times the initial net force zero
Answer:
The net force is zero
Explanation:
When an object is falling, there are two forces acting on it:
- The force of gravity, which is equal to the weight of the object, which pushes the object downwards
- The air resistance, which acts against the motion of the object, so it pulls upward
While the magnitude of the force of gravity is constant, the magnitude of the air resistance increases as the velocity of the falling object increases: at some point of the motion, the air resistance becomes equal in magnitude to the force of gravity. At this point, the net force on the object becomes zero, and according to Newton's second law, the acceleration of the object becomes also zero:
[tex]F=ma[/tex]
But zero acceleration means that the velocity of the object is now constant: this is known as terminal velocity.
Which of these reactions is responsible for energy radiating from stars, including the Sun? A) nuclear fusion B) nuclear fission C) an exothermic chemical reaction D) an endothermic chemical reaction
Answer:
A) Nuclear fusion
Explanation:
Nuclear fusion is a process that occurs when two light nuclei fuse together forming a heavier nucleus. In such a process, the mass of the final nucleus is slightly lower than the total mass of the initial nuclei, so part of the mass is converted into energy, according to Einstein's equation:
[tex]E=mc^2[/tex]
where
E is the energy released in the process
m is the difference in mass between final products and initial nuclei
[tex]c=3.0\cdot 10^8 m/s[/tex] is the speed of light
Given the huge value of [tex]c^2[/tex], we see that in the process of nuclear fusion a tremendous amount of energy is released even for very small values of the mass, m.
Nuclear fusion occurs inside the core of the stars and it is the process responsible for the energy produced by the stars. The main process that occurs inside the core of a star is the fusion of two nuclei of hydrogen into a nucleus of helium.
Answer:
A) nuclear fusion
Explanation:
The reactions that occur in stars are nuclear fusion in which two lighter nuclei combine to give a heavier nucleus with release of enormous energy.
What do chefs change with many dishes they serve
Chefs may adjust their recipes to enhance the taste and presentation of dishes using various techniques and ingredients, drawing upon their knowledge of food science and nutrition to make each meal appealing to both the eye and palate.
Chefs often modify the dishes they serve to enhance the taste, texture, and presentation. They might use various techniques and ingredients, such as gels, chemicals, and other substances to modify liquids or to transform the food experience, as seen in molecular gastronomy. Expert chefs combine their knowledge of food science, nutrition, and diet to create meals that are as visually appealing as they are delicious. Additionally, chefs are known to make adjustments on the fly, such as adding a little salt to a soup after tasting or altering recipes to suit specific dietary needs or preferences. This adaptability and attention to detail are part of what makes a chef proficient in the culinary arts.
If you were to apply a force of 15N to a medicine ball with a mass of 5kg, what would its acceleration be
Given that
Force (F) = 15 N ,
mass (m) = 5 Kg ,
acceleartion = ?
We know that, From Newtons II law
F = m. a
15 = 5 × a
a = 15÷ 5
a = 3 m/s²
acceleration of the ball is 3 m/s²
A disturbance sends ripples across water in a tub.
What are these ripples called?
surface waves
longitudinal waves
rarefactions
compressions
I believe it is surface waves because it happens at the surface of the water.
Answer:
Option (1)
Explanation:
Ripples (ripple marks) are formed due to the forward and backward motion of water over the surface of a rock bed or water bodies. They are usually formed when the flow velocity is less and the diameter of the grains is relatively small.
These are sedimentary structures that are found in many places. These ripples are divided into 2 types, namely the symmetric and the asymmetric ripples. Asymmetrical ripples are helpful in identifying the palaeocurrent direction.
These are formed when water travels over the surface, so it can be considered as the surface waves.
Hence, the most appropriate answer is option (1).
ionic compound molecules have strong forces of attraction between neighboring molecules what conclusion can be drawn about material is held together by ionic bonds
Answer:
In general, the ionic bond is formed through transfer of electrons from metal atoms to non-metallic atoms. In this process the metal atoms loose their valence electrons to achieve a stable noble gas. In forming an ionic bond, two ions which have an opposite charges, move together due to attraction between opposite charges. The ionic compounds have very strong attraction between the ions. So the lot of energy expensed to overcome attractive forces and break the individual ions apart. The conclusion is the ionic compound dissolve easily, have high melting points and non malleable.define commercial unit of energy
The commercial unit of energy is given as kWh or kilo-watt-hour.
It is defined as the work done at a rate of 1000 Watt in a time of one hour.
there are other units of energy also like joules, calories but they are not big enough to express large quantity of energy. that is why we use kWh as the commercial unit since it is bigger compared to other energy units.
Im stressing out about this cause obviously i thought i did good but i guess not can someone explain to me where i went wrong this is her feedback
Comments: Mia,
I am happy to see you are jumping right into the course. You are correct that physics and Newton's laws of motion are important to swimming. You are off to a good start, but you have not mastered the 3 laws of motion, yet. I would like you review the definitions and examples in the lesson and to then download the worksheet and complete the questions directly on the sheet. It will guide you to write in Newton's 3 Laws of motion and provide examples. If you need any help please reach out to me. With some more hard work, I know you can do this. I am excited to see what your resubmit.
I would recommend, to include the scientific part of Newton's Laws of motion, with an example. Also, state how all three laws play a part in the activity. It seems like you just did the realistic part of it, swimming, now include how it happens with correct vocabulary. Good Luck!
how to solve for average speed
The Average speed can be found by dividing the total traveled by the amount of time it took to travel that distance.
For example, if it took you 10 hours to travel 100 miles, your average speed is the amount of miles you traveled in 1 hour. Simplify.
100/10 = 10/1
Your average speed is 10 miles per hour.
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what is Br charge after it gains an electron?
Im not 100% sure but i think its bromine.
Hope this helps ^_^
a girl throws a marshmallow that lands in her friends mouth 92m away. The girl threw the marshmallow at an angle of 67 degrees. How hard was did she throw the marshmallow?
Answer:
The girl threw the marshmallow with a speed of 35.4 m/s.
Explanation:
Use the formula for the range of projectile motion:
[tex]R = \frac{v^2\cdot \sin2\theta}{g}[/tex]
with R the range or distance (92m), theta the elevation angle (67 degrees) and g the gravitational acceleration. The velocity can be determined from this as follows:
[tex]|v| = \sqrt{\frac{R\cdot g}{\sin 2 \theta}} = \sqrt{\frac{92m\cdot 9.8 \frac{m}{s^2}}{\sin 134^\circ}}=35.40\frac{m}{s}[/tex]
The girl threw the marshmallow with a speed of 35.4 m/s, which is approximately 79 mph. No word on the boy's condition after the marshmallow's landing.
The volume of the lung 0.0024m^3 following exhalation and the pressure is 101.70KPa. Calculate the volume of the lungs during inhalation if the pressure falls to 84.16KPa
According to Boyle-Mariotte:
p₁V₁=p₂V₂=>V₂=p₁V₁/p₂= 0.0024*101.70/ 84.16=0.0028 m³
imagine that two balls, a basketball and a much larger exercise ball, are dropped from a parking garage. If both the mass and radius of the exercise ball are 3 times larger than the mass and radius of the basketball, which of the two balls do you think will reach the ground first? Make a hypothesis below and describe your reasoning.
Hypothesis
Let there is no air drag or any other resistance force due to surrounding
Now the force equation of ball is given as
[tex]F = mg[/tex]
[tex]ma = mg[/tex]
[tex]a = g[/tex]
so the ball will be dropped down by acceleration a = g and this acceleration is independent of size and mass of the ball
So in this case both balls will be dropped by same acceleration.
So here both balls will hit the ground at same time
Final answer:
The hypothesis is that the basketball will reach the ground first due to its lower air resistance compared to the larger exercise ball.
Explanation:
Hypothesis: The basketball will reach the ground first.
Reasoning: When objects fall, they accelerate at the same rate due to gravity, regardless of their mass. The air resistance acting on the larger exercise ball will be greater due to its larger size, causing it to fall slightly slower than the smaller basketball.
Example: Consider dropping a feather (light but has air resistance) and a coin (heavier but less air resistance) simultaneously from the same height, and you'll notice the feather takes longer to reach the ground.
If you are pushing on a door trying to make it slide open if your friend stands behind you and helps you push how hase the forces changed
Answer
The net force applied will increase
Explanation
According to Newton’s second law , force is the product of mass and acceleration. In this case, when a friend joins in the pushing of the door, the total net force applied on the door increases and the door will open with much ease. Force=mass × acceleration,
F=m × a
Answer:
The force will change as the net force applied will increase.
Explanation:
If you are pushing on a door really hard, trying to make it slide open and if your friend is also stand behind you and contributes to help you push towards the door, then the overall force will change as the net amount of force applied will increase.
This is an example of Newton's second law according to which you need more force to move an object with heavier mass.
F = ma
Therefore, the force applied by you and your friend will add and the net force applied will be increased.
Imagine a small child asks you to push them on a swing at the park. After a few pushes, they yell, "I want to go higher!"
How can you apply Newton's 2nd Law of Motion to push them higher?
To push the child higher on the swing, you can apply Newton's Second Law of Motion. By exerting a greater force on them and pushing at the right moment, you can increase their height on the swing.
Explanation:To push the child higher on the swing, you can apply Newton's Second Law of Motion. This law states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass. To push the child higher, you need to exert a greater force on them by pushing with more strength or pushing for a longer time.
The force you apply to the child is the net force, which is the force pushing them forward minus the force of gravity pulling them down. By increasing the net force, you can increase the acceleration of the child and make them move higher on the swing.
Additionally, you can also push the child at the right moment to take advantage of the swing's motion. Pushing when the child is moving forward and upward can help increase their height on the swing.
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A star is 10 light years away from the earth.suppose it brightens up suddenly today ,after how long can we see this change?
We will see the star brighten up 10 years later, because it takes 10 years for the light emitted from that star to reach the earth.
Light year = the distance light can travel in 1 year
10 light years = distance that takes light 10 years to travel
A 70.0 kg skydiver falls towards the earth. The force due to air resistance is 1200 N. What is the acceleration of the skydiver?
The force of gravity on the skydiver is
F(g) = (mass) x (gravity)
F(g) = (70 kg) x (9.8 m/s²)
F(g) = 686 Newtons, downward (her "weight")
If, through some mysterious process, the force due to air resistance acting on her is 1,200 Newtons upward, then the net force on the skydiver is
F(net) = (686 N down) + (1,200 N up)
F(net) = 514 Newtons, up
The skydiver is accelerating UP, at 7.34 m/s² .
I have no idea how this could actually happen in the real world, but the Math and Physics are bullet-proof here.
Final answer:
The acceleration of the skydiver is approximately 17.14 m/s².
Explanation:
The acceleration of the skydiver can be found using Newton's second law of motion, which states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration.
Given that the force due to air resistance is 1200 N and the mass of the skydiver is 70.0 kg, we can set up the equation:
Net force = Force due to air resistance
70.0 kg * acceleration = 1200 N
Solving for acceleration:
acceleration = 1200 N / 70.0 kg
acceleration ≈ 17.14 m/s²
Therefore, the acceleration of the skydiver is approximately 17.14 m/s².
What is the speed or a softball that travel 20m in 2sec
To find speed with distance and time, you need to remember the speed formula:
Speed = distance ÷ time
So we need speed and we have the other two values, we can plug the values in:
Speed = 20 ÷ 2 = 10
The measurement for speed in this case is m/s (metres per second)
So the answer is 10m/sThe answer would be 10mph
when neutral charge comes into contact with a positive charge
If they come in direct contact, then with certain restrictions, the neutral charge will experience a transfer of 1/2 a charge from the positive body providing we're talking about a large enough charge that can be transferred.
So if one sphere starts with no charge and one with 6 * 10^-14 Q, if they touch,then each sphere will have a charge of 3*10^-14 Q which is still a pretty big charge.