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Related Questions
In the figure, a 700-kg crate is on a rough surface inclined at 30°. a constant external force p = 5600 n is applied horizontally to the crate. as the force pushes the crate a distance of 3.00 m up the incline, the speed changes from 1.40 m/s to 2.50 m/s. how much work does gravity do on the crate during this process?
Answers
This problem might be confusing since there are a lot of given variable but we must take note that the problem only asks about the Work done by gravity, therefore:
Work = - Potential Energy
Where,
Potential Energy = mass * gravity * height
Note: It is negative since it is gravity doing the work on our system, not work being done on gravity.
Since the surface is inclined at 30 degrees, therefore:
height = 3 m * sin 30
height = 1.5 m
Calculating for Work:
Work = - 700 kg * 9.8 m / s^2 * 1.5 m
Work = - 10,290 J
Work = -10,300 J
Work do on the crate by gravity : W = -10290 J
Further explanationWork is the transfer of energy caused by the force acting on a moving object
Work is the product of force with the displacement of objects.
Can be formulated
W = F x SW = Work, J, Nm
F = Force, N
S = distance, m
Force and displacement of objects are vector. Multiplication of both is in accordance with the dot product concept of two vectors. Whereas W is a scalar quantity. Then if there is an angle formed by the force F and the displacement S is θ, then it can be formulated
W = F cos θ.SThere are 4 forces on the crate, so there are 4 work that occurs
work done by the applied force = Wp work done by the frictional force = Wfthe magnitude is the same as the force applied by the applied force (Fp) but the opposite direction
work done by the normal force = Wnthe direction is upward with F = mg
work done by the gravitational force = WgBecause what is sought is only work by the force of gravity, then
we can find it from the formula of potential energy
W = ΔPE = - m. g. (h2-h1)
W = - mgh2 (h1 = 0)
Negative value are caused by the movement of objects in the opposite direction to the downward force of gravity
W = - 700. 9.8. 3 sin 30 (h2 has an angle of 30°)
W = -10290 J
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Resistance is a measure of how well a material conducts an electric charge. Would you expect to find a high or low, level of resistance in a copper wire and why
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The yellow wire connected to a power supply carries 12v. if the power supply provides 60w of power to the yellow wire, how much current is passing through the yellow wire?
Answers
P = IV
Substituting the values into the equation,
60 W = I*12V
I = 60/12
I = 5 Amperes
Therefore, a current of 5 Amperes is passing through the yellow wire.
In general, the rate of evaporation increases with ___________. in general, the rate of evaporation increases with ___________. decreasing intermolecular forces decreasing volatility decreasing temperature decreasing surface area
Answers
In general, the rate of evaporation of liquid increases with increase in temperature and increases with increase in surface area of the liquid exposed to air. The rate of evaporation decreases with increasing of the intermolecular forces. The bigger intermolecular forces , the harder the molecules can escape from the liquid and become gas.
Water in the oceans may become fresh water available to humans through the processes of
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In these processes, water is heated to a very high temperature until it evaporates in order to kill the germs and remove the salts which remains after water evaporation. The next step in condensing the water vapor (which is now fresh) and precipitating this vapor to be used by humans.
Ocean water can be made into fresh water via desalination, a process which removes salt and minerals. This technology is essential in areas with scarce water supplies but is energy-intensive and contributes to environmental issues with its saline byproduct.
Water in the oceans can become fresh water available to humans primarily through the process of desalination. Desalination is a method that increases the amount of fresh water on Earth by removing dissolved salt and minerals from seawater or saline groundwater. Despite the virtually unlimited supply of saltwater, desalination techniques such as boiling, filtration, electrodialysis, and reverse osmosis are energy-intensive and costly. They also produce highly saline wastewater, which poses significant environmental challenges and must be managed appropriately. Desalination is a vital technology, especially in regions like the Middle East where water is scarce but energy resources are abundant.
When considering the water (hydrologic) cycle, it's important to note that while the Earth has an abundance of water, less than 1 percent of it is accessible fresh water. Through the water cycle, processes such as evaporation and condensation contribute to the natural distribution of water, but they do not desalinate it. For desalination to occur and produce fresh water for human use, technological intervention is required. The importance of these technologies cannot be overstated, as the availability of freshwater is critical to the survival of many living organisms, including humans.
Convert 21.0 cm to inches
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Although the class has no water, the students want to know if the cube will float or sink in water. Explain, in detail, the steps that must be taken to determine if the cube will float or sink. Be sure to use the following key terms: triple beam balance, metric ruler ,and density.
Answers
hope this helps, and I didn't know how to use the word "metric ruler"
After observing the electric field in your trials above, where was the electric field the strongest? what was the direction of the electric field?
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Electric field strength is highest close to central charges with closely spaced field lines, indicating intensity and weaker electric fields occur farther away.
Electric field strength: The electric field is strongest close to the central charges, where the field lines are closely spaced together. This is where the electric field is most intense. Field lines that are farther away from the central charges indicate weaker electric fields.
Find the number of certifications held by people grouped by planet. this should have two columns the first, "name" will be the names of planets that have at least one certification. the second column should be "certcount" an
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The tables are the following:
CREATE TABLE `bsg_cert` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`title` varchar(255) NOT NULL,
PRIMARY KEY (`id`)
) ENGINE=InnoDB
CREATE TABLE `bsg_cert_people` (
`cid` int(11) NOT NULL DEFAULT '0',
`pid` int(11) NOT NULL DEFAULT '0',
PRIMARY KEY (`cid`,`pid`),
KEY `pid` (`pid`),
CONSTRAINT `bsg_cert_people_ibfk_1` FOREIGN KEY (`cid`) REFERENCES `bsg_cert` (`id`),
CONSTRAINT `bsg_cert_people_ibfk_2` FOREIGN KEY (`pid`) REFERENCES `bsg_people` (`id`)
) ENGINE=InnoDB
CREATE TABLE `bsg_people` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`fname` varchar(255) NOT NULL,
`lname` varchar(255) DEFAULT NULL,
`homeworld` int(11) DEFAULT NULL,
`age` int(11) DEFAULT NULL,
PRIMARY KEY (`id`),
KEY `homeworld` (`homeworld`),
CONSTRAINT `bsg_people_ibfk_1` FOREIGN KEY (`homeworld`) REFERENCES `bsg_planets` (`id`) ON DELETE SET NULL ON UPDATE CASCADE
) ENGINE=InnoDB
CREATE TABLE `bsg_planets` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`name` varchar(255) NOT NULL,
`population` bigint(20) DEFAULT NULL,
`language` varchar(255) DEFAULT NULL,
`capital` varchar(255) DEFAULT NULL,
PRIMARY KEY (`id`),
UNIQUE KEY `name` (`name`)
) ENGINE=InnoDB
Joining them all up doing a count with a group by should do the trick:
SELECT planet.name ,
COUNT(*) AS cert_count
FROM bsg_cert_people people_cert
JOIN bsg_people people ON people.id = people_cert.pid
JOIN bsg_planet planet ON people.homeworld = planet.id
GROUP BY planet.name
Or we can also use this syntax to get the same result:
SELECT pl.name, count(cert) AS "CertCount"
FROM bsg_planets pl
JOIN bsg_people pe ON pl.id = pe.homeworld
JOIN bsg_cert_people cp ON cp.pid = pe.id
GROUP BY pl.id
The circuit to the right is constructed using 9 identical batteries and 9 identical resistors. the lower left corner of the circuit is grounded. determine whether the current through each resistor is zero or non-zero.
Answers
Final answer:
Without seeing the specific circuit diagram, it is not possible to accurately determine whether the current through each resistor is zero or non-zero. The answer requires applying circuit analysis techniques such as Ohm's Law and the Loop Rule to the provided configuration of batteries and resistors.
Explanation:
To determine whether the current through each resistor is zero or non-zero in a circuit with 9 identical batteries and 9 identical resistors, one would need to apply principles from circuit analysis, such as Ohm's Law and the Loop Rule. However, without the provided circuit diagram, it cannot be deduced whether the current is zero or non-zero. In a typical circuit arrangement, if the circuit is properly connected with a path for the current to flow and if the batteries and resistors are arranged appropriately without any shorts, there would be a non-zero current through the resistors. The determination of this would require analyzing the specific configuration of the batteries and resistors, such as whether they are arranged in series or parallel, and applying the loop rule which states that the sum of the voltage drops in a closed loop must equal the sum of the emf sources within that loop.
Is it true or false that air pollution only occurs as a result of human activity
Answers
Answer:
This is false
Explanation:
The given statement "Air pollution only occurs as a result of human activity" is false because air pollution can occur as a result of both human activity and natural processes.
Human activities that contribute to air pollution include:
Burning fossil fuels: Burning fossil fuels, such as coal, oil, and natural gas, releases pollutants into the air. These pollutants include carbon dioxide, sulfur dioxide, nitrogen oxides, and particulate matter.Transportation: Transportation is another major source of air pollution. Cars, trucks, buses, and airplanes emit pollutants into the air, including carbon monoxide, hydrocarbons, and nitrogen oxides.Industry: Industrial activities, such as power plants, factories, and refineries, also emit pollutants into the air. These pollutants include sulfur dioxide, nitrogen oxides, and particulate matter.Natural processes that can contribute to air pollution include:
Volcanic eruptions: Volcanic eruptions can release large amounts of pollutants into the air, including sulfur dioxide, carbon dioxide, and particulate matter.Wildfires: Wildfires can also release large amounts of pollutants into the air, including carbon dioxide, particulate matter, and ozone.Dust storms: Dust storms can stir up dust and other particles into the air, which can contribute to air pollution.To know more about the Air pollution, here
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A sand core used to form the internal surfaces of a steel casting experiences a buoyancy force of 225 n. the volume of the mold cavity forming the outside surfaces of the casting = 4840 cm3. what is the weight (in kg) of the final casting? ignore considerations of shrinkage
Answers
Newton’s second law gives us the relationship of force F, mass m and acceleration a. The formula is given as:
F = m a --> 1
However we also know that the relationship of mass m, density ρ, and volume V is:
m = V ρ --> 2
Therefore substituting equation 2 to equation 1:
F = ρ V a = ρ V g
where a is acceleration due to gravity, ρ is density of water and V is the volume of the casting, therefore:
F = (1x10^-3 kg/cm^3) (4840 cm^3) (9.8 m/s^2)
F = 47.432 kg m/s^2
F = 47.432 N
Going back to equation 1:
47.432 N = m (9.8 m/s^2)
m = 4.84 kg
Hence the weight of the final casting is 4.84 kg
To find the weight of the final casting, we use the principles of buoyancy to solve. Given the volume and the approximate density of steel, we multiply them to find the mass. The weight of the final casting is therefore approximately 37.974 kg.
Explanation:This problem's solution involves the application of Archimedes' Principle which states that an object submerged in fluid, experiences a buoyant force equal to the weight of the fluid displaced by the volume of that object.
In this circumstance, the sand core is completely submerged and the fluid (molten steel) that fills its cavity takes its form after solidifying. The given buoyancy force (225 N) is essentially the weight of the fluid displaced by it ( weight = mass x gravity). The weight of the mold cavity would hence be the weight of the steel casting.
Given the volume of the mold cavity (4840 cm
3
), we can determine the mass of the steel using the volume and the density of the steel (assuming the density of steel to be around 7.85 g/cm
3
).
The mass (m) would hence be: m = volume x density = 7.85 g/cm3 x 4840 cm3 = 37974 g = 37.974 kg.
Therefore, the weight of the final steel casting is approximately 37.974 kg.
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True or false The theory of plate tectonics is the study of how Earth's surface has remained the same for billions of years
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A certain string on a piano is tuned to produce middle c (f = 261.63 hz) by carefully adjusting the tension in the string. for a fixed wavelength, what is the frequency when this tension is tripled?
Answers
The final frequency is 453.16 Hz when the tension is tripled.
We know that:
f = v / λ
Where,
f = frequency of sound wave.
v= speed of sound wave
λ = wavelength of sound wave
So, for a fixed wavelength ( let it be λ), frequency is directly proportional to velocity of the sound wave.
Again for a certain tension T, velocity of sound wave in a string is given by, v = √(T/μ) where, μ is mass per unit length of the string.
So, when this tension is tripled; velocity of sound wave becomes √3 times of its initial value and as frequency is directly proportional to the velocity, final frequency becomes = √3 × initial frequency
= √3 × 261.63 Hz. ( as given in the question, initial frequency = 261.63 Hz)
= 453.16 Hz.
Hence, when this tension is tripled, the frequency will be 453.16 Hz.
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Which expression is equivalent to 3m+1-m
Answers
You would simplify the expression by subtracting the 3m by the m.
Answer:
Th equivalent of [tex]3m+1-m[/tex] is [tex]2m+1[/tex]
Explanation:
We need to write the equivalent expression of [tex]3m+1-m[/tex]
first, combine the like terms,
[tex]3m-m+1[/tex]
take out the common variable,
[tex](3-1)m+1[/tex]
[tex]2m+1[/tex]
Therefore, the equivalent of [tex]3m+1-m[/tex] is [tex]2m+1[/tex]
If three devices are plugged into one port on a switch and two devices are plugged into a different port, how many collision domains are on the switch?
Answers
For this item, the first packet is the whole switch with the three devices. Next one would be first of the three devices that is connected to the other port. Similarly, the third one would be the second of the three devices that is also connected to the switch. Therefore, the answer is 3.
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Consider a girl that has a mass of 55.0 kg and is standing on the floor, how much supporting force does the floor have?
at least 55 kg up
at least 55 kg down
at least 539 N up
at least 539 N down
Answers
acceleration due to gravity =9.8m/s^2
So, the force she is applying on the floor must equal
55× 9.8 N
(Because force =mass ×acceleration)
=539N
Now, according to newton's third law the floor must be applying the same force on the body in the opposite direction.
So the force applied here by the floor is 539N upward.
Option "C" is the correct one.
The famous leaning tower of pisa doesn't topple over because its center of gravity is
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When are you safe outside if you hear thunder?
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In an isochoric process, the internal (thermal) energy of a gas decreases by 50 j. how much work is done by the gas during this process
Answers
The isochoric process is a thermodynamic process in which the volume will always remain contant.
work could be calculated = P x dV
since dV = 0, there wore the amount of work done by this process is also 0
In an isochoric process where the gas's internal energy decreases by 50 J, no work is done by the gas because the volume is constant. The work done is 0 J.
Explanation:In an isochoric process (also known as an isovolumetric process), the volume of a gas remains constant. According to the first law of thermodynamics, the change in internal energy (ΔU) of a system is equal to the heat added to the system (Q) minus the work done by the system (W): ΔU = Q - W. In an isochoric process, because the volume does not change, no work is done by the gas (W = 0). Therefore, if the internal energy of the gas decreases by 50 Joules, and no work is done, the amount of heat removed from the gas would be equivalent to the decrease in internal energy, which is -50 Joules.
The answer to the student's question is that in an isochoric process where the internal energy decreases by 50 Joules, no work is done by the gas since the volume is constant; the work done is 0 Joules.
A cyclist does work at the rate of 500 w while riding. how much force does her foot push with when she is traveling at 8.0 m/s?
Answers
F=P/V
F=500W/8=62.5N
Answer:
The foot push of the cyclist exerted a force of 63 Newton.
Explanation:
Given data
Power (P): 500 WattVelocity (v): 8.0 m/sForce (F): ?We can find the force exerted by the foot push of the cyclist using the following expression.
P = F × v
v = P/F = 500 W/ (8.0 m/s) = 63 N
The foot push of the cyclist exerted a force of 63 Newton.
A red blood cell is placed in a hypertonic solution. this means the concentration of solutes in the solution is ________ than the concentration of solutes in the intracellular fluid, and will cause the cell to ________.
Answers
A hypertonic solution has a higher concentration of solutes than the inside of a red blood cell. This causes water to move out of the cell, causing the cell to shrink or crenate.
Explanation:When a red blood cell is placed in a hypertonic solution, the concentration of solutes in the solution is higher than that in the intracellular fluid. As a result of this difference in solute concentration, water will move out of the cell and into the solution in a process called osmosis. This will cause the cell to shrink or create due to water loss.
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Calculate the work energy, w, gained or lost by the system when a gas expands from 15 l to 35 l against a constant external pressure of 1.5 atm
Answers
The work done by the gas is about 30 L.atm
[tex]\texttt{ }[/tex]
Further explanationThe Ideal Gas Law and Work formula that needs to be recalled is:
[tex]\boxed {PV = nRT}[/tex]
[tex]\boxed { W = P \Delta V }[/tex]
where:
W = Work ( J )
P = Pressure ( Pa )
V = Volume ( m³ )
n = number of moles ( moles )
R = Gas Constant ( 8.314 J/mol K )
T = Absolute Temperature ( K )
Let us now tackle the problem !
[tex]\texttt{ }[/tex]
Given:
initial volume = Vo = 15 L
final volume = V = 35 L
constant pressure = P = 1.5 atm
Asked:
word done by the gas = W = ?
Solution:
[tex]W = P \Delta V[/tex]
[tex]W = P \times ( V - Vo )[/tex]
[tex]W = 1.5 \times ( 35 - 15 )[/tex]
[tex]W = 1.5 \times 20[/tex]
[tex]W = 30 \texttt{ L.atm }[/tex]
[tex]\texttt{ }[/tex]
Conclusion:The work done by the gas is about 30 L.atm
[tex]\texttt{ }[/tex]
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Answer detailsGrade: High School
Subject: Physics
Chapter: Pressure
The work energy, w, gained or lost by the system when the gas expands is 30 Joules.
Given the following data:
Pressure = 1.5 atmInitial volume = 15 litersFinal volume = 35 litersTo find the work energy, w, gained or lost by the system when the gas expands:
Mathematically, the work energy by a system is given by the formula:
[tex]Work = P \delta V[/tex]
Where:
P is the pressure.V is the volume.Substituting the given parameters into the formula, we have;
[tex]Work\;energy = 1.5(35-15)\\\\Work\;energy = 1.5(20)[/tex]
Work energy = 30 Joules.
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Why is it that the two possible faults wit inductors are short circuit and open circuit
Answers
Which transmits the most light?
A. Tinted glass
B. Opaque glass
C. Clear glass
D. All types transmit light equally
Answers
A howler monkey is the loudest land animal and, under some circumstances, can be heard up to a distance of 4.6 km. assume the acoustic output of a howler to be uniform in all directions and that the threshold of hearing is 1.0 × 10-12 w/m2. what is the acoustic power emitted by the howler?
Answers
distance = (4.6 km) x (1000 meters/ 1 km) = 4600 meters
Performing the required operation,
Acoustic power = (1.0 x 10^-12 W/m²)(4600 m)²
Acoustic power = 2.116 x 10^-5 W
Thus, the acoustic power is approximately 2.12 x 10^-5 W.
The rotating nozzle sprays a large circular area and turns with the constant angular rate theta overscript dot endscripts = 2.2 rad/s. particles of water move along the tube at the constant rate l overscript dot endscripts = 1.8 m/s relative to the tube. find the magnitudes of the velocity v and acceleration a of a water particle p when the distance l = 0.85 m if the angle beta = 64°.
Answers
The magnitude of the velocity of the water particle is approximately 2.6 m/s, and the magnitude of the acceleration of the water particle is approximately 7.5 m/s^2.
Explanation:The magnitudes of the velocity v and acceleration a of a water particle can be calculated using the concepts of angular velocity, and the relationships between linear and angular motion.
The velocity of the water particle v has two components: a tangential component due to the rotation (equal to the angular velocity times the distance from the center of rotation), and a radial component due to the flow of water along the tube.
The tangential velocity Vt = ωr, where r = 0.85 m is the distance of the water particle from the center of rotation and ω = 2.2 rad/s is the angular velocity. Substituting these values we find that Vt = 2.2 rad/s * 0.85 m = 1.87 m/s. The radial velocity Vr = l_dot = 1.8 m/s is given in the problem.
The total velocity is obtained by combining the radial and tangential velocities. Its magnitude is given by v = sqrt(Vr^2 + Vt^2). Substituting the known values, we find that the magnitude of the velocity v of the water particle is approximately 2.6 m/s.
The acceleration of the particle also has two components: a radial component equal to the square of the tangential velocity divided by the radius, and a tangential component equal to the product of the angular velocity and the radial velocity. Therefore, the magnitude of the acceleration a is given by a = sqrt((Vt^2 / r)^2 + (ωVr)^2), which gives us a value of approximately 7.5 m/s^2.
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The magnitude of the velocity [tex]v[/tex] of the water particle is approximately 2.6 m/s. The magnitude of the acceleration [tex]a[/tex] of the water particle is 4.114 m/s².
Velocity due to rotation (tangential velocity):
The tangential velocity [tex]v_{tangential}[/tex] is given by
[tex]v_{tangential} = l \cdot \dot{\theta}[/tex]
Substituting the values:
[tex]v_{tangential} = 0.85 \text{ m} \cdot 2.2 \text{ rad/s} = 1.87 \text{ m/s}[/tex]
Velocity along the tube:
The velocity along the tube [tex]v_{tube}[/tex] is given by [tex]\dot{l}[/tex], which is already provided as 1.8 m/s.
Resultant velocity:
The total velocity of the particle [tex]v[/tex] is the vector sum of the tangential and tube velocities. Since the angle [tex]\beta[/tex] between these two components is given, we can use the Pythagorean theorem:
[tex]v = \sqrt{( v_{tangential} )^2 + ( v_{tube} )^2}[/tex]
Substituting the values:
[tex]v = \sqrt{(1.87 \text{ m/s})^2 + (1.8 \text{ m/s})^2} \approx 2.6 \text{ m/s}[/tex]
Acceleration
Centripetal acceleration:
The centripetal (radial) acceleration [tex]a_c[/tex] is given by:
[tex]a_c = l \cdot \dot{\theta}^2[/tex]
Substituting the values:
[tex]a_c = 0.85 \text{ m} \cdot (2.2 \text{ rad/s})^2 = 4.114 \text{ m/s}^2[/tex]
Tangential acceleration:
The tangential acceleration [tex]a_t[/tex] will be zero because the angular velocity is constant (no angular acceleration).
Total acceleration:
The total acceleration [tex]a[/tex] is due to the centripetal acceleration alone, as there is no tangential component. Hence:
[tex]a = a_c = 4.114 \text{ m/s}^2[/tex]
how to divide electrons into energy levels?
Answers
In the first energy level, you only have one 1s orbital. In the second energy level, you have one 2s and one 2p orbital, the 2p having more energy than 2s. The other levels are shown in the picture.
A severe storm has an average peak wave height of 16.4 feet for waves hitting the shore. suppose that a storm is in progress with a severe storm class rating. let us say that we want to set up a statistical test to see if the wave action (i.e., height) is dying down or getting worse. if you wanted to test the hypothesis that the waves are dying down, what would you use for the alternate hypothesis?
Answers
Before we answer this question, let us first understand what alternate hypothesis is.
The alternative hypothesis is the hypothesis which is used in the hypothesis testing and this is opposite to the null hypothesis. This is the test hypothesis which is usually taken to be that the observations are the result of a real effect in an experiment.
In this case since what we want to set up is the statistical test to see if the waves are dying down, then this means we are trying to determine if the wave height are decreasing, so lesser than 16.4 feet. Therefore:
The alternative hypothesis would state (ANSWER)
Ha: μ less than 16.4 feet and P-value area is on the left of the mean.
While the null hypothesis is the opposite and would state
H0: mu equals 16.4 feet
Cube C1 has sides of length L, has an area A, and a volume V. Cube C2 has side that is 1/4 L. What is the area and the volume of cube C2?
Answers
C2 area= 3/8 [tex] L^{2} [/tex]
C2 volume= [tex] 1/64L^{3} [/tex]
To answer this question you must calculate the cube C2 area and volume using "L" as unit. The calculation formula should be same as a normal cube.
C2 area= 6x [tex] (1/4L)^{2} [/tex]
C2 area= 6x[tex] 1/16(L^{2} [/tex]
C2 area= 3/8 [tex] L^{2} [/tex]
C2 volume= [tex] (1/4L)^{3} [/tex]
C2 volume= [tex] 1/64L^{3} [/tex]