Answer:
Even if the gene is inactive, you can inherit the gene from your children.
Explanation:
Genetic inheritance is determined by the patterns that are dominant or recessive, not with the activation or not of the gene that you already possess, so depending on whether your partner is a carrier of the gene, there will be a greater probability of inheriting it from your children, even if your partner is a non-carrier of the gene none of the descendants inherits the condition, but they are all carriers, if their partner is a carrier but does not affect it, there is a 50% probability that one descendant is affected, and the rest are carriers but not inherited the condition, if their partner is a carrier, there is a 25% probability that a descendant is affected, a 50% probability that they are carriers but without manifesting the condition, and a 25% probability of not having any recessive allele.
In this case, the inactive gene of man affects the probability his future children might inherit the PKU allele - remain same or 1.
PKU is a latent ailment recessive disorder that leads to brain damage because proteins aren't digested properly, and the man in this issue is two alleles of the recessive allele.
he carries on with a typical life by staying away from protein-rich sustenance
he conveys those passive alleles in his genome when he creates gametes with passive alleles.
on the off chance that P is overwhelming ordinary allele and p is latent allele.
man is pp and gametes he creates are p so the majority of his descendants will have this allele p
so the likelihood that he will acquire this allele p to his youngsters is 1 since the majority of his gametes contains p allele.
The probability of inheritance of that gene remains the same
Thus, In this case, inactive gene of man affects the probability his future children might inherit the PKU allele - remain same or 1.
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Name the two main parts of an angiosperm leaf. What is the function of each part?
Answer:
Stomata, Guard cells.
Explanation:
Angiosperms are known as flowering plants that contain their seeds in fruits. They are including a variety of plants such as submerged, aquatics, trees, herbs, etc. Two main parts of an angiosperm leaf are:
Stomata: They are tiny pores present on the plant epidermis, these small openings on the leaves allow gas exchange to occur in plants.
Guard cells: These cells help to controls stomata opening and closing, also helps to stimulate gas exchange and control transpiration in plants.
Final answer:
The angiosperm leaf has a blade for photosynthesis and a petiole for support and nutrient transport. Deciduous plants drop leaves to conserve water, while evergreens have needle-like leaves to reduce water loss. Variation in leaf structure among angiosperms is often an adaptation to environmental conditions.
Explanation:
The angiosperm leaf consists of two main parts: the blade (or lamina) and the petiole. The blade is the broad, flat part of the leaf which contains a high concentration of chloroplasts, making it the primary site for photosynthesis.
The petiole is the stalk that attaches the leaf blade to the stem at a node, providing support and transporting water and nutrients between the leaf and the rest of the plant.
Different environmental conditions lead to variations in leaf structure and function. Angiosperms exhibit a wide range of leaf shapes, margins, and venation patterns, which are often adaptations to specific climatic and environmental factors such as light, water availability, and temperature.
which organism is able to make its own oxygen gas?
Answer:
cyanobacteria
cyanobacteria is The answer is tiny organisms known as cyanobacteria, or blue-green algae. These microbes conduct photosynthesis: using sunshine, water and carbon dioxide to produce carbohydrates and, yes, oxygen
Explanation:
Hope this helps:)
Answer:
Plants
Explanation:
Plants do photosynthesis which releases oxygen gas as a by-product.
Trehalose is a disaccharide that is associated with plants and animals that are relatively resistant to drying out. For example, Artemia spp. (brine shrimp, or \"sea monkeys\") utilize trehalose as an energy source and can withstand periods of heat and dehydration. Trehalose may make up as much as 15% of an encysted embryo\'s weight, and \"sea monkey\" eggs can be shipped dry in the mail with no harm to the embryo. Answer parts (a) and (b). a) Identify trehalose, which is formed by an
Find the answer in the attachment.
Note: The complete question is also attached.
Which are characteristics of all bacteria? Check all that apply.
They lack a nucleus.
They have a nucleus.
They eat other organisms.
They make their own food.
They are eukaryotes.
They are prokaryotes.
Answer:
1 and 6
Explanation:
The characteristic that are present in bacteria is lack a nucleus, are prokaryotes. The correct options are a and f.
What are prokaryotes?Prokaryotes are the basic creatures without a nucleus or other organelles in their cells. Bacteria and archaea, two distinct groupings of prokaryotes with allegedly independent evolutionary histories, are separated into.
The majority of prokaryotes are tiny, single-celled creatures with a straightforward structure.
Since prokaryotic cells lack a membrane-bound nucleus, eukaryotic cells are the main difference between these two types of creatures. Eukaryotes store their genetic material in their nuclei.
Bacteria are common, largely free-living organisms that frequently only have one biological cell. They make up a significant portion of the prokaryotic microbial kingdom. Prokaryotes, which lack a nucleus, are a hallmark of bacteria.
Thus, a and f are the correct options.
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NEED IMMEDIATE HELP!! WILL GIVE BRAINLIEST!!!
Type the correct answer in the box. Spell all words correctly.
Which of the intertidal zones experiences the highest complexity and diversity of marine life?
The *BLANK* intertidal zone experiences the highest complexity and diversity of marine life.
Answer: Pacific northwest intertidal zone experiences the highest complexity and diversity of marine life.
Explanation:
Answer:
pacific northwest
Explanation:
What phrase describes short-term environmental changes
Answer:
A short-term environmental change is drought, smog, flooding, volcanic eruption, blizzards, and pollution this could happen in anyone of the food webs.
Explanation:
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Forever friend and helper,
Cammie:)
I found a baby snow leopard behind my house and adopted it.
We can't find much meat in the market because of the virus, I don't know what to feed it.
Pls help.
Answer:
take to local DNR, you can't just adopt a wild animal with out proper licensing.
Explanation:
its against the law
Answer: hi thank you so much for this question, the answer is simple
, snow lepords eat mice, try giving it water maybe try a milk baby bottle put honey on the sucking part. y
Explanation:
Urea... Multiple Choice is completely reabsorbed by the nephron. is secreted into the filtrate by cells of the distal convoluted tubule. None of these choices is correct. ia actively transported into the filtrate by cells of the collecting duct. diffuses out of the collecting ducts into the interstitial fluid of the medulla and then diffuses into the descending loop of Henle.
Answer:
Option B
Explanation:
Urea, the main nitrogenous excretory product of mammals and a major organic component of urine is cleared from the blood by the kidney. Urea's concentration builds up in the renal medulla as they leave through the walls of the cortical collecting duct and go into the interstitial fluid in the region of the inner medulla, then some diffuses into the descending loop of Henle.
3.why the number of xylem are less than the number of phloem in hydrophytes plant?
Answer:
Hydrophytes are defined as the plants that grow in aquatic environment.
Xylem and phloem are part of transport system in plants. Water and minerals from roots to leaves are carried by Xylem and sugar and other organic nutrients are carried by Phloem.
Hydrophytes grow in water, so have access to abundant water. It helps water to diffuse easily in hydrophytes and hence require less number of xylem for water transport.
So, number of xylem are less than the number of phloem in hydrophytes plant.
If there are 40 chromosomes in each body cell of an organism what is the total number of chromosomes normally present in a gamet produced by that organism ?
Answer:
The gametes are haploid, having half the number of cells as compared to somatic cells. The gametes or cells produced by the organism will have 6 chromosomes if the organism has 12 chromosomes.
What does the phrase “extreme environments” suggest as it is used in the sentence below?
Organisms that use chemosynthesis live in extreme environments, where the toxic chemicals needed for oxidation are found.
(A) that the organisms live in places where toxins are scarce
(B) that the organisms live off the high heat of the sun
(C) that the organisms live far away and by themselves
(D) that the organisms live in harsh conditions
plz reply!!!
Answer:
Its D
Explanation:
The phrase “extreme environments” refers to harsh conditions that are difficult for most life forms to endure, which is where extremophiles live. The correct answer is that the organisms live in harsh conditions.
Explanation:The phrase “extreme environments” suggests that the organisms live in harsh conditions that are challenging for most life forms to survive. Such places are known for their extreme temperatures, pressures, chemical makeup, or radiation levels, and organisms that live there, known as extremophiles, have adapted to thrive in these environments. Therefore, the correct answer to the given question is (D) that the organisms live in harsh conditions.
Which of the following drugs would NOT block the cell cycle, and thus would NOT be appropriate cancer treatment? Nocodazole, a drug that blocks spindle fiber (microtubule) formation 5-flurouracil, a DNA analog that blocks DNA replication Sphingosine-1-phosphate, a molecule that stimulates relay molecules in signaling Brinapant, a drug that increases apoptosis (cell death) Bevacizumab, a drug that blocks formation of new blood vessels so that less oxygen is available for cancer cells
Answer:
The correct answer is Sphingosine-1-phosphate.
Explanation:
Sphingosine-1-phosphate or S-1-P refers to a signaling sphingolipid that takes part in various of the cell proliferation procedures. Mainly the sphingosine-1-phosphate performs the work of monitoring the process of permeability, angiogenesis, and vascular stability that can further interfere in the process of metastasis.
However, it has been found that due to the tendency of developing the novel blood vessels, the sphingosine-1-phosphate also has some connection with certain kinds of cancers.
which organ system includes accessory organ like liver and pancrease
Answer:
digestive system
Explanation:
The accessory digestive organs are the tongue, salivary glands, pancreas, liver, and gallbladder.
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Jacob and Monod proposed a unified hypothesis of gene regulation. Which of the following is/are NOT part of the hypothesis?
a) Operons contain regulatory elements that control the expression of contiguous genes.
b) Repressors and operators regulate messenger RNA.
c) Transcription is regulated specifically at the level of initiation.
d) All of the listed statements are part of the hypothesis.
Answer:
A
Explanation:
An operon is:A) a gene coding for a repressor protein.B) a region of DNA consisting of the promoter, operator, and coding sequence for more than one protein.C) a region of DNA consisting of the operator and coding sequence for structural proteins.D) a region of DNA consisting of the promoter and operator sequences needed to regulate one or more structural genes. a single molecule of RNA coding for more than one protein.
Answer: Option D.
A region of DNA consisting of the promoter and operator sequences needed to regulate one or more structural genes.
Explanation:
An operon is a part of the the DNA that is found in bacteria or viruses which function in transcription and genetic regulation. Operon is under control of an operator, consist of promoter, regulator and structural genes. Operon is normally under the control of a single operator in which genes coding for protein are clustered along the DNA.
Ashley is taking a test. She has to write why comb jellies and jellyfish belong to two different phyla. What should Ashley write?
A that jellyfish are vertebrates, while comb jellies are not
B. that jellyfish are mobile, while comb jellies are not
C. that jellyfish have stinging cells, while comb jellies do not
D.
that jellyfish have an exoskeleton, while comb jellies do not
Answer: C. That jellyfish have stinging cells, while comb jellies do not
Explanation:
Comb Jellies to the untrained eye are the same as Jellyfish but as the question says, they are different in that they belong to different phyla.
The Comb Kelly belongs to the Ctenophora Phylum while the Jellyfish belongs to the Coelenterate phylum.
Perhaps the largest difference between them is that Ctenophora do not have stinging cells as opposed to members of the Coelenterate Phylum that do.
Jellyfish and comb jellies are in different phyla because jellyfish have stinging cells for capturing prey while comb jellies do not. Hence, option C is correct.
Ashley should write that jellyfish and comb jellies belong to two different phyla because jellyfish have stinging cells, while comb jellies do not. Specifically, jellyfish are part of the phylum Cnidaria, characterized by their stinging cells called nematocysts which they use for capturing prey. On the other hand, comb jellies belong to the phylum Ctenophora, and they lack these stinging cells. Instead, comb jellies use colloblasts or sticky cells to capture prey. Additionally, while both creatures are invertebrates and live in aquatic environments, they have different biological structures and genetic makeup that necessitate their classification into separate phyla.
Which is a need?
A.shelter
B.gum
C.chocolate bar
D.toys
Answer:
A-Shelter, the others are for enjoyment while shelter takes care of your physical state
Explain what is meant by the term environmental justice.Explain why land use planning has to incorporate such diverse disciplines as architecture, urban planning, and environmental planning.
Answer:
Land use planning is about more than addressing the physical layout of development, how much it will cost, where it will be located and aesthetics. Land use planning also incorporates environmental impacts such as chemical pollution, noise pollution, flooding due to the loss of trees and plants, etc. In order to meet all these requirements land use planning must draw from a wide array of disciplines' expertise.
Explanation:
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Two major problems occur in water intoxication; one problem is that the overhydration leads to a non-homeostatic decrease in the concentration of __________; this leads to a significant decrease in blood osmotic pressure. The second problem is that the excessive increase in water volume, due to too much water intake, increases its extracellular (intravascular and interstitial) concentration out of normal homeostatic range. This high extracellular concentration of water causes water to move down its concentration gradient into cells; cells begin to __________ to a non-physiologic size.
Options are not provided inthe question. Hence, the complete question is
Two major problems occur in water intoxication; one problem is that the overhydration leads to a non-homeostatic decrease in the concentration of __________; this leads to a significant decrease in blood osmotic pressure. The second problem is that the excessive increase in water volume, due to too much water intake, increases its extracellular (intravascular and interstitial) concentration out of normal homeostatic range. This high extracellular concentration of water causes water to move down its concentration gradient into cells; cells begin to __________ to a non-physiologic size.
A. antibodies; shrink
B. hormones; swell
C. blood solutes; swell
D. blood solutes; shrink
Answer:
C. blood solutes; swell
Explanation:
Water intoxication or hyperhydration or water poisoning is a fatal brain functional disorder caused due to excessive water consumption forces the normal electrolyte balance in the body outside safe limits.
There are two major impact sofwater intoxication on health that includes:
Due to overhydration, blood solutes concentration decreases due to imbalance in blood level and results in decrease in blood osmotic pressure.Due to intake of excessive water, extracellular concentration increases which is out of normal homeostatic range. This excessive water and high etracellular concentration allows water to move down its concentration gradient into cells and resluts into swelling of cell.Hence, the correct option is C.
Sperm can survive in the female reproductive system for six days, but they need to have 10 hours after ejaculation to undergo capacitation. Ovulation typically occurs on day 14 of a woman's menstrual cycle. An ovulated egg can survive only up to 24 hours if it is not fertilized. Given this information, what days of a woman's sexual cycle would be a window of opportunity for an egg to be fertilized
Answer:
Five days prior to ovulation and day of ovulation represents a six day fertile window of a women’s cycle
Explanation:
In the five days prior to ovulation and day of ovulation, the chances of conception are high. These six days represents the fertile window of a women’s cycle during which the sperm with a life span of five days and egg with a life span of 24 hours can fuse. However, likelihood of conceiving increases if two individuals mate in the first three days of these six days fertile window of women’s cycle.
why is the cycling of matter important to all living things
Answer:The cycling of matter is among the three main factors upon which life on the earth depends. Concerning the cycling of matter, because there are only finite amounts of nutrients available on the earth, they must be recycled in order to ensure the continued existence of living organisms
Explanation:
The cycling of matter, such as the carbon cycle, is essential for providing the materials necessary for life. These biogeochemical cycles ensure readily available elements for organisms to use, preventing essential elements for maintaining ecosystem sustainability.
The cycling of matter is fundamentally important to all living things as it ensures the continuous availability of essential elements like carbon, nitrogen, hydrogen, oxygen, phosphorus, and sulfur. Biogeochemical cycles involve both biotic and abiotic components and are essential for life on Earth because they provide the materials necessary for organisms to construct their bodies, carry out life processes, and maintain ecosystem sustainability.
The carbon cycle, for instance, plays a critical role in the fixation of atmospheric carbon dioxide into biomass through photosynthesis. This is a primary pathway for solar energy to be captured and converted into chemical energy that can be used by organisms.
Without the cycling of matter, essential elements could become trapped in unavailable forms, hindering the survival of living organisms. For example, if carbon were to become sequestered in crustal rocks and sediments without being recycled, living organisms would lack the raw materials needed for vital organic compounds. Also, the recycling of elements like phosphorus and sulfur is crucial as they undergo various state changes and move through the atmosphere, water, and soil, affecting many aspects of the ecosystem.
Through these cycles, matter is conserved within the biosphere, continually moving between living organisms and the environment in a balanced manner. Such processes are necessary for the production of food, energy storage, and the regeneration of raw materials which are all required for the persistence and functioning of life on Earth.
List at least 3 different biotic (living/products of organisms) limiting factors and at least 3 different abiotic (nonliving) limiting factors of deer. Make sure you label your list (biotic & abiotic).
Answer:
If your question is referring to the factors limiting the growth and development of the species of deer,
Biotic:
1) Food sources like Grass
2) Predators like Wolf
3) parasites like leaches
Abiotic:
1)Temperature
2)Water
3) Pollutants in environment.
Which represent correct variations of the formula for speed? Check all that apply.
Answer:
d = st
Explanation:
t =
s =
t =
s = dt
d = st
d =
The formula that represents correct variation of the formula for speed would be d = st, where d = distance traveled by an object, s = speed of the object, and t = the time taken by the object.
Speed is defined as the distance traveled by a moving object per the time taken by the object to complete the distance. Mathematically, it is represented as:
Speed (s) = [tex]\frac{distance (d)}{time (t)}[/tex].
Hence, s = [tex]\frac{d}{t}[/tex]
If the formula is cross multiplied, then we will have;
d = st
Answer:
A, B, E
t = d/s, s = s/d, d = st
What moves through an ecosystem when one organism eats another?
Answer:
energy
Explanation:
Nina is learning about plants in school. Her teacher gives her group a stack of cards that list things that plants might need to make their own food. Written on the cards are the words “water,” “soil,” “sunlight,” and “air.” One card does not belong.
Which of the cards should Nina’s group take out of the pile?
A) air
B) soil
C) sunlight
D) water
Her teacher gives her group a stack of cards that list things that plants might need to make their own food. The card that does not need to be there is air. Thus option A is correct.
What is the composition of air ?Earth's atmosphere is composed up of only five gases like nitrogen, oxygen, water vapor, argon, and carbon dioxide, the primary component is nitrogen gas.
Nitrogen, oxygen, water vapor, argon, and carbon dioxide these gases account for about 99% of the air, Trace gases such as neon, methane, helium, krypton, hydrogen, xenon, ozone, and many other elements and compounds.
plants are needed carbon dioxide and animals need to breath the oxygen present in air and the available air is a natural element of nature that support on earth.
Air is very useful in animal ,plants other sources, uses air in the are sustain and growth, maintaining temperature, energy supplier combustion
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The card that Nina's group should remove from the pile is the one that says "air." Plants use water, soil, and sunlight to make their own food through photosynthesis, while air (specifically, carbon dioxide) is also a necessary component for this process.
Explanation:The card that Nina's group should take out of the pile is the one that says "air." While plants do require air to survive, it is not something they use to make their own food. Instead, plants use water, soil, and sunlight to make their own food through a process called photosynthesis.
Carbon dioxide from the air is also utilized in this process. Therefore, the other three cards belong in the stack as they represent the essential components for plants to make their own food.
An asynchronous culture is given 3H-thymidine for a period of time, usually about 30 minutes. During the labeling period, 42% of the cells incorporate radiolabel. At numerous times after the exposure, samples of the cells were collected and autoradiograms were prepared. The first radiolabeled mitotic figures appeared in the sample that was collected six hours after the 3H-thymidine radiolabel was first presented to the cells. The autoradiograms were stored for 75 hours before they were developed. How long is the G2 phase
Answer:
How long is the G2 phase = 6hours
Explanation:
Cell cycle undergoes various stages during mitotic cell division.
Normally cells are arrested in the resting phase G0 but as the cell division starts it undergoes G1 the growth phase then it undergoes S phase called the Synthesis phase in which the DNA synthesis occurs. Then it undergoes G2 Phase and is the shortest phase while G1 is the longest phase of the cycle. G2 normally lasts for 3-4 hours so here it may take 2.775 hours as due to presence of Thymidine the synthesis of DNA occur at high level so it contains higher levels of cellular DNA than in the G1 . so it will take 6hours G2 phase to occur.
The G2 phase will take 6 hours.
We can arrive at this answer because:
Detection of the 3H thymidine radiolabel will follow the duration of the G2 phase.This is because this phase refers to the interval between DNA duplication and the beginning of cell division.In this phase, it is possible to detect all molecules and elements that will be necessary for cell division.Thus, if the 3H thymidine radiolabel can be visualized after 6 hours and it will be a participating element in cell division, we can agree that the G2 phase will last 6 hours.
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1 Pterodactyl (reptile)
2. Bat (mammal)
3. Albatross (bird)
Why are the wings
considered analogous
structures while bones in
these forelimbs are
considered homologous
structures?
Answer:
Analogous structures are structures which serve similar function in different organisms and evolved independently in two living organisms while homologous structures are the structures which are similar in related orgnanism due to inheritance.
The wings of Pterodactyl, bats and birds are conisdered as analogous structure. they are similar in structure and same in function and evolved independently in the two groups of animals.
Bones in forelimbs of pterodactyl, bats and birds are considered homologous structures as they inherited the pattern from a common ancestor and have different functions.
The _____________ variable is the variable that is purposely changed.
A: independent
B: Dependent
C: Control
Answer:
dependent
Explanation:
Answer:
Independent
Explanation:
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In humans, "unattached" earlobes are dominant over "attached" earlobes. "Widows peak" hairline is dominant over "non-widows peak" hairline. Use E and e for the earlobe phenotype alleles, and W and w for the hairline phenotype alleles. A female and a male, both with genotype EeWw have a child. What is the probability it will be a boy, and have attached earlobes and a widows peak hairline?
Answer:
3/32
Explanation:
The probability would be 3/32
From the illustration:
Unattached earlobe E is dominant over attached earlobe e.Widows peak hairline is dominant over non-widows peak hairline.EeWw and EeWw were crossed (Assuming both traits are autosomal)
EeWw x EeWw
Progeny :
1 EEWW - unattached earlobe with widows peak
2 EEWw - unattached earlobe with widows peak
2 EeWW - unattached earlobe with widows peak
4 EeWw - unattached earlobe with widows peak
1 EEww - unattached earlobe with non-widows peak
2 Eeww - unattached earlobe with no-widows peak
1 eeWW - attached earlobe with widows peak
2 eeWw - attached earlobe with widows peak
1 eeww - attached earlobe with no-widows peak
Generally, the probability of obtaining a male or a female in a cross is 50/50 or 1/2.
From the crossing result, the probability of having attached earlobe and widows peak hairline is 3/16.
Hence, the probability of obtaining a boy with attached earlobes and widows peak airline:
1/2 x 3/16 = 3/32.
Final answer:
The probability of a child having attached earlobes and a widow's peak hairline from parents with genotypes EeWw is calculated using a Punnett square, resulting in a 18.75% chance or 3/16 probability for these traits to occur together.
Explanation:
In humans, unattached earlobes are dominant over attached earlobes, and widow's peak hairline is dominant over non-widow's peak hairline. When solving for the probability of a child inheriting attached earlobes and a widow's peak hairline from parents with genotypes EeWw, we use the Punnett square method.
First, let's determine the possible gametes for earlobes and hairline from each parent: E or e, and W or w.Create a two-trait Punnett square with these gametes to see all possible genotypes for their offspring.To calculate the probability of a child with attached earlobes (ee) and a widow's peak (either WW or Ww), we need to find the fraction of the Punnett square that corresponds to this combination.In a two-trait Punnett square, each parent can produce four types of gametes: EW, Ew, eW, and ew. The child must inherit an e from both parents for attached earlobes and at least one W for a widow's peak. The Punnett square for this cross would be a 4x4 grid, with each cell representing a possible genotype of the offspring.
After filling out the Punnett square, we find that the offspring will have a 1/4 chance (probability of 25%) for attached earlobes and a 3/4 chance (probability of 75%) for the widow's peak. The combined probability of having both attached earlobes and a widow's peak is the product of the individual probabilities, which is (1/4) × (3/4) = 3/16 or 18.75%.
Two Andalusian chickens are crossed to produce offspring. One parent has black feathers and the other parent has white feathers. In this type of chicken, feather color is a trait that exhibits incomplete dominance.
Which statement is most likely correct about the offspring?
All of the chicks will have both black and white feathers.
Some chicks will have only black feathers and others will have only gray feathers.
All of the chicks will have only black feathers.
All of the chicks will have only gray feathers.
Answer:
The answer is indeed option D
The correct statement of offspring should be All of the chicks will have only gray feathers.
Information regarding offspring;Offspring refers to the human child or animal child, or the children of a family for various years. An example of an offspring should represent the cub of two lions at the zoo. So the all type of chicks should have gray feathers.learn more about the parent here: https://brainly.com/question/24185208