A class of 24 students is planning a field trip to a science museum. A nonrefundable deposit of $50 is required for the day-long program, plus a charge of $4.50 per student. Determine a linear function that models the cost, c, and the number of students, s. Which statements about the linear function and its graph are correct? Check all that apply.
A. The linear model is f(s) = 4.5s + 50.
B The linear model is f(c) = 54.5c + 24.
C.The domain is {x| 0 ≤ x ≤ 24}.
D.The range is {y| 50 ≤ y ≤ 158}.
E.The graph is continuous.

Answers

Answer 1

The answer to this question would be A

Answer 2

A,C, & D

have a nice day:)

Related Questions

There were n balloons at the beginning of the party. By the end of the party, 5 of them had popped. Using n, write an expression for the number of balloons that were left

Answers

Answer:

The expression for the number of balloons that were left is [tex]n-5[/tex].

Step-by-step explanation:

There were n balloons at the beginning of the party.

By the end of the party, 5 of them had popped.

Let the remaining balloons be represented by x

So, x = total balloons minus 5

This gives: [tex]x=n-5[/tex]

Therefore, the expression for the number of balloons that were left is [tex]n-5[/tex].

If x-5=2 then find the value of 6x-20

Answers

First solve the first equation to find x.

x-5=2
x=7

Now plug it in to the other equation to get your answer.

6(7)-20
42-20
22

The answer is 22.

so x in the fist problem is 7. So the x is substituted be 7. guessing you want me to solve,
6x-20
=6(7)-20
=42-20
=22

The sum of three consecutive even integers is 288. find the three integers.

Answers

288/3 =96

96-2 = 94

96+2 = 98

94 +96 +98 = 288

Answer:

94, 96, 98

Step-by-step explanation:

Let the smallest integer is x,

So, second larger integer = x + 2 (Because integer are even and consecutive),

And, largest integer = x + 2 + 2 = x + 4,

So, the sum of these integers = x + x + 2 + x + 4 = 3x + 6

According to the question,

3x + 6 = 288

3x = 282

⇒ x = 94

Hence, the integers are,

94, 94+2, 94+4

= 94, 96, 98

Write the equation of a line that is perpendicular to the given line and that passes through the given point.

2x+9y=-30;(-8,0

Answers

2x+9y=-30 subtract 2x from both sides

9y=-2x-30 divide both sides by 9

y=-2x/9-30/9

So the slope of the reference line is -2/9. For a line to be perpendicular to this line their slopes must be negative reciprocals of one another, mathematically:

m1*m2=-1 and in this case:

-2m/9=-1

m=9/2

m=4.5, so far we have:

y=4.5x+b, using point (-8, 0) we can solve for b

0=4.5(-8)+b

0=-36+b

36=b, so our line is:

y=4.5x+36

Triangle ABC is similar to triangle XYZ. Which of the following proportions is correct?

1) AB/XY = AC/YZ

2) AC/XY=BC/XZ

3) AB/XY=AC/XZ

4) BC/XY=AB/YX

Answers

Similar shapes are figures which have the same form or shapes but not necessarily are congruent shapes. These shapes could have different side lengths. Given that triangle ABC is equal triangle XYZ, then side AB would correspond to side XY, side BC would correspond to side YZ and side AC would correspond to side XZ. Therefore, the correct answer would be option 3. The correct proportion would be AB / XY = AC / XZ. From the choices, given it is the only option where the side lengths corresponds to each other (side AB to side XY and side AC to side XZ).

Answer:

The correct option is 3.

Step-by-step explanation:

It is given that triangle ABC is similar to triangle XYZ.

The corresponding sides of similar triangles are proportional.

Since it is given that the triangle ABC is similar to triangle XYZ, so by using the definition of similarity triangles

[tex]\frac{AB}{XY}=\frac{BC}{YZ}=\frac{AC}{XZ}[/tex]

From first and third term, we get

[tex]\frac{AB}{XY}=\frac{AC}{XZ}[/tex]

Therefore the correct option is 3.

If k pencils cost c cents what is the cost in cents of p pencils

Answers

the cost in cents of 1 pencil = c/k

the cost in cents of p pencils = (c/k) * p

If k pencils cost c cents. Then the cost in cents of p pencils will be cp / k.

What is Algebra?

Algebra is the study of abstract symbols, while logic is the manipulation of all those ideas.

The acronym PEMDAS stands for Parenthesis, Exponent, Multiplication, Division, Addition, and Subtraction. This approach is used to answer the problem correctly and completely.

If k pencils cost c cents. Then the cost of each pencil is given as,

⇒ c / k

Then the cost in cents of p pencils is given as,

⇒ (c / k) x p

⇒ (cp) / k

If k pencils cost c cents. Then the cost in cents of p pencils will be cp / k.

More about the Algebra link is given below.

https://brainly.com/question/953809

#SPJ5

The scale on a map indicates that 1 in = 2.5mi. How far apart are two cities that measure 2.5 ft apart on the map? A. 60 miles B. 6.25 miles C. 75 miles D. 90 miles

Answers

The answer is C. 75 miles

Line p contains points A(–7, –9) and B(4, 0). Line q is parallel to line p. Line r is perpendicular to line q. What is the
slope of line r? Explain.

Answers

(-7,-9)(4,0)
slope = (0 - (-9) / (4 - (-7) = 9/11...line P slope

line q is parallel....parallel lines have the same slope, so line q has a slope of 9/11.

line r is perpendicular to line q....that means line r will have a slope of -11/9. The reason is because perpendicular lines will have negative reciprocal slopes. To find the negative reciprocal of a number, just flip the number and change the sign. So, 9/11, when flipped and the sign changed is -11/9. <==

1. Find the coordinates of the circumcenter for ∆DEF with coordinates D(1,1) E (7,1) and F(1,5). Show your work.

2. What is the length of the 2nd base of a trapezoid if the length of one base is 24 and the length of the midsegment is 19? Show your work.

Answers

1. Draw an accurate drawing of the triangle in the coordinate axis, as shown in the picture.

FD and DE are perpendicular, because D and F have the same x coordinate, and D and E the same y coordinate.

Let A(4, 1) be the midpoint of DE and B(1, 3) be the midpoint of FD.

Draw the perpendiculars from A and B. They meet at O(4, 3), since AO is parallel to DF and BO is parallel to DE.

the point where the perpendicular bisectors of the sides meet is the circumcenter, so the circumcenter is O(4, 3)

2.

Let the length of the second base be x.

the length of the midsegment is the sum of the ases divided by 2.

[tex]19= \frac{x+24}{2} [/tex]

19*2=x+24

38=x+24

x=38-24=14

Answers:

1) O(4, 3)
2) length of second base = 14 units

Work out problem in picture

Answers

for x multiply 6 by sin(45) = 3sqrt(2) = 4.2426

for y since it is a right triangle with 45 degree angle both legs are equal

so y = x

A local carpet company has been hired to carpet a planetarium which is in the shape of a circle. If the radius of the planetarium is six yards, and the cost of the carpet is $14 per square yard, find the total cost to carpet the planetarium. (use 3.14 for π )

Answers

This is the concept of application of geometry and financial mathematics; To calculate for the total cost of the carpet we proceed as follows;
Total cost=[area of the carpet]*[price per square yard]
area of carpet is given by:
Area=πr^2
where;
radius,r=6 yeards
=π*6^2
=113.1 square yards
therefore the price of the carpet will be:
113.1*14
=$1,583.4

Given the points (2,k) and (0,−6) for which values of k would the distance between the points be square root of 5
?

Answers

So, the distance between two points (x1,y1) and (x2,y2) is:

d = sqrt( (x2-x1)^2 + (y2-y)^2 )

Some times is better the square of the distance:

d^2 = (x2-x1)^2 + (y2-y)^2

Now, in your case:

5^2 = (0-2)^2 + ( -6-k)^2 = (-2)^2 + (6+k)^2 = 4 + (6+k)^2

Notice the little thing about (-6-k)^2 = (6+k)^2 (less '-') Finally:

25 = 4 + (6+k)^2 ===> (6+k)^2 = 21,

6+k = sqrt(21)

Notice we did not expand (6+k)^2! No need this time. But now, the tricky part!

6+k=+sqrt(21) and 6+k=-sqrt(21), because both work (never forget that sqrt come with +/- when looking for solutions!)

k = -6 + sqrt(21) and k=-6-sqrt(21).

Both are valid answers. Some times one is not good because you need the solution be positive (for instance), but here, both are good.

Given the points (2,k) and (0,−6) for which values of k would the distance between the points be √5 ?

We will find that there are two possible values of k;

k = -5 and k = -7.

We know that the distance between two points (x₁, y₁) and (x₂, y₂) is given by:

[tex]d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}[/tex]

Here we have the points (2,k) and (0,−6), then the distance will be given by:

[tex]d = \sqrt{(2 - 0)^2 + (k - (-6))^2} = \sqrt{4 + (k + 6)^2}[/tex]

Now we want to find the value of k such that the distance is equal to √5, then we need to solve:

[tex]\sqrt{5} = \sqrt{4 + (k + 6)^2}[/tex]

removing the square root in both sides we get:

[tex]5 = 4 + (k + 6)^2\\\\5 - 4 = (k + 6)^2\\\\1 = (k + 6)^2[/tex]

Then we can see that (k + 6) = ± 1, solving these two equations (one for each sign) we get:

k + 6 = 1

k = 1 - 6 = -5

and

k + 6 = -1

k = -1 - 6 = -7

Then we found two possible values of k:

k = -5

k = -7

Below you can see the graph of the points A = (2, -5), B = (0, -6) and C = (2, -7)

If you want to learn more about distances, you can read:

https://brainly.com/question/5057237

88 is the product of
8
and Jenny's score

Answers

product means multiplication

88 is the product of 8 multiplied by a number

so 88/8 =11

jenny's score is 11

Calvin and hobbes are making snowballs to throw at suzi calvin made 3/7 of the snowballs and hobbes made 8/14 of the snowballs who mae more snowballs in fractions

Answers

recalculate 3/7 to have the same denominator as 8/14 ( 14)

so multiply both top and bottom by 2. 3/7 becomes 6/14

8/14 - 6/14 = 2/14 reduces to 1/7

Hobbes made more snowballs by 1/7

recalculate 3/7 to have the same denominator as 8/14 ( 14)

so multiply both top and bottom by 2. 3/7 becomes 6/14

8/14 - 6/14 = 2/14 reduces to 1/7

Hobbes made more snowballs by 1/7

How do you solve all of these ?

Answers

5)

[tex]\bf \begin{array}{lllll} &x_1&y_1\\ % (a,b) &({{ 5}}\quad ,&{{ -3}})\quad % (c,d) \end{array} \\\\\\ % slope = m slope = {{ m}}= \cfrac{rise}{run} \implies -1 \\\\\\ % point-slope intercept y-{{ y_1}}={{ m}}(x-{{ x_1}})\implies y-(-3)=-1(x-5) \\ \left. \qquad \right. \uparrow\\ \textit{point-slope form} \\\\\\ y+3=-x+5\implies y=-x+2[/tex]

6)

[tex]\bf \begin{array}{lllll} &x_1&y_1\\ % (a,b) &({{ 2}}\quad ,&{{ 1}})\quad % (c,d) \end{array} \\\\\\ % slope = m slope = {{ m}}= \cfrac{rise}{run} \implies 3 \\\\\\ % point-slope intercept y-{{ y_1}}={{ m}}(x-{{ x_1}})\implies y-1=3(x-2) \\ \left. \qquad \right. \uparrow\\ \textit{point-slope form} \\\\\\ y-1=3x-6\implies y=3x-5[/tex]

7)

[tex]\bf \begin{array}{lllll} &x_1&y_1\\ % (a,b) &({{ 5}}\quad ,&{{ 2}})\quad % (c,d) \end{array} \\\\\\ % slope = m slope = {{ m}}= \cfrac{rise}{run} \implies 0 \\\\\\ % point-slope intercept y-{{ y_1}}={{ m}}(x-{{ x_1}})\implies y-2=0(x-5) \\ \left. \qquad \right. \uparrow\\ \textit{point-slope form} \\\\\\ y-2=0\implies y=2[/tex]

8)

[tex]\bf \begin{array}{lllll} &x_1&y_1\\ % (a,b) &({{ -2}}\quad ,&{{ 0}})\quad % (c,d) \end{array} \\\\\\ % slope = m slope = {{ m}}= \cfrac{rise}{run} \implies \cfrac{5}{2} \\\\\\ % point-slope intercept y-{{ y_1}}={{ m}}(x-{{ x_1}})\implies y-0=\cfrac{5}{2}(x-(-2)) \\ \left. \qquad \right. \uparrow\\ \textit{point-slope form} \\\\\\ y=\cfrac{5}{2}(x+2)\implies y=\cfrac{5}{2}x+5[/tex]

9)

[tex]\bf \begin{array}{lllll} &x_1&y_1\\ % (a,b) &({{ -2}}\quad ,&{{ 0}})\quad % (c,d) \end{array} \\\\\\ % slope = m slope = {{ m}}= \cfrac{rise}{run} \implies \cfrac{5}{2} \\\\\\ % point-slope intercept y-{{ y_1}}={{ m}}(x-{{ x_1}})\implies y-0=\cfrac{5}{2}(x-(-2)) \\ \left. \qquad \right. \uparrow\\ \textit{point-slope form} \\\\\\ y=\cfrac{5}{2}(x+2)\implies y=\cfrac{5}{2}x+5[/tex]

10)

[tex]\bf \begin{array}{lllll} &x_1&y_1\\ % (a,b) &({{-2}}\quad ,&{{ -2}})\quad % (c,d) \end{array} \\\\\\ % slope = m slope = {{ m}}= \cfrac{rise}{run} \implies \cfrac{3}{2} \\\\\\ % point-slope intercept y-{{ y_1}}={{ m}}(x-{{ x_1}})\implies y-(-2)=\cfrac{3}{2}(x-(-2)) \\ \left. \qquad \right. \uparrow\\ \textit{point-slope form} \\\\\\ y+2=\cfrac{3}{2}(x+2)\implies y+2=\cfrac{3}{2}x+3\implies y=\cfrac{3}{2}x+1[/tex]

which is enough information to prove that s||t

Answers

The answer is: <2 = <8

It will be the second option

what is the domain and range of each function graohed below?

Answers

domain is the x values you can use
range is the y values

a.
the domain
hmm, seems to be all real numbers except for at x=0, it gets really close tho
so D=(-∞,0)U(0,∞)

range is all real numbers except for y=0, it gets really close tho
R=(-∞,0)U(0,∞)

b.
domain
that empty circle means something like < or >
goes from 5 to 6, not including 5
so domain is D=(5,6]

range is from -4 to 2, not including -4
range is R=(-4,2]

check the picture below.

notice the holes, the excluded values, on the first one,due to an asymptote, on the second one, is in the line itself.

How do I find ac in this problem

Answers

7 / x+4 = 5/x+1 =

5x+20 = 7x+7 =

20=2x+7

13=2x

x=13/2 = 6.5

6.5+4 = 10.5

6.5+1 =7.5

10.5+7.5 = 18

length of AC = 18

What are the solutions of the equation 2x2=2 use a graph of the related function

Answers

The equation given is
2x² = 2
x² = 1
x = √1
x = 1

The solution is both -1 and 1 and the graph is shown below

Answer:

[tex]x=-1\text{ or }x=1[/tex]

Step-by-step explanation:

We have been given an equation [tex]2x^2=2[/tex]. We are asked to find the solutions of our given equation.

First of all, let us divide both sides of our equation by 2.

[tex]\frac{2x^2}{2}=\frac{2}{2}[/tex]

[tex]x^2=1[/tex]

Upon taking square root of both sides of our equation we will get,

[tex]x=\sqrt{1}[/tex]

[tex]x=\pm 1[/tex]

[tex]x=-1\text{ or }x=1[/tex]

Therefore, [tex]x=-1\text{ or }x=1[/tex] are two solutions for our given function.

Solve 4r2 – 7 = 29.
a. +-6
b. +-3
c. +-4
d. +-5

Answers

4r^2-7=29
+7 both sides
4r^2=36
÷4 both sides
r^2=9
square root both sides
r=+/-3 B

Please help me and show work so I can understand worth 20 points!!!

Answers

The steps and final answer is shown in the attached image. I wrote it there so I could write out complex algebraic formulas. Let me know if you have any questions about any of the steps. Thank you.

(06.01 LC)

What type of association does the graph show between x and y?
Linear positive association
Nonlinear positive association
Linear negative association
Nonlinear negative association

Answers

non-linear positive association

Answer:

im taking the same test 4 years later

Which of these is NOT a part of formal proof? A.Reasons
b.statements
c. given
d. diagram
e.none of the above

Answers

the answer would be A. reasons

Use the discriminant of x^2+4x-32=0 to describe the roots

Answers

The formula for discriminant is:

discriminant = sqrt (b^2 – 4 a c)
Where,

a = 1

b = 4

c = -32

Therefore:

discriminant = sqrt (4^2 – 4 (1) (-32))

discriminant = sqrt 144

discriminant = 12

Since the discriminant is a positive real integer, then there are 2 unequal roots or 2 distinct real roots.

Select the inequality that corresponds to the given graph. graph of an inequality with a solid line through the points negative 8 comma 0 and 0 comma negative 4 and shading above the line A 4x − 3y > − 12 B x + 4y > 4 C 4x − 2y < − 8 D 2x + 4y ≥ − 16

Answers

well by looking at the graph I can see that the equation for the line is y=-0.5x-4
rearranging I can get the answer.
y>=-0.5x-4
y+0.5x>=-4
2y+x>=-8

the answer is
2x+4y>=-16

Answer: 2x+4y ≥ -16

Step-by-step explanation: In the given graph x-intercept is -8 and y-intercept is -4.

Also the graph is shaded up of the line for greater values of y's.

On the option 2x+4y ≥ -16 has x-intercept at -8 and y-intercept at -4.

Also all other inequalities has only less than or greater than sign.

In the given graph we have a solid line.

So, there should be greater than or equal to inequality sign for the inequality.

Only option 4 has greater than with equal to sign.

Therefore, correct option is 2x+4y ≥ -16

Find the height of the figure below if the volume is 480.66^3 cm.

Answers

volume = PI x r^2 x H

you know the volume and the radius ( 12/2 = 6)

480.66 =3.14 x 6^2 x H

480.66 = 113.04 x h

h = 480.66/113.04 = 4.252

round off as needed.

One half of a number decreased by 16

Answers

1/2x-16 is an equation that can be used to represent this. The 1/2x represents the one half of a number and the -16 represents the decreased by 16.

Hey there!

"One half of a number" will be a number (x) divided by 2. This can also be shown as "0.5x" or "1/2x", whichever you prefer.

"...decreased by 16" will be "– 16", making your full equation 0.5x – 16. Remember that terms like remainder, difference, and fewer will always mean subtraction.

Hope this helped you out! :-)

Simplify the product using the distributive property. (-4h +2)(3h +7)

A.

-12h 2 - 22h + 14

B.

-12h 2 - 34h - 14

C.

-12h 2 + 34h - 14

D.

-12h 2 + 22h + 14

please help

Answers

Answer:

A. -12h² - 22h + 14

Step-by-step explanation:

(-4h +2)(3h +7) = -4h(3h +7) +2(3h +7) . . . . . . . (a +b)c = ac +bc

= (-4h)(3h) + (-4h)(7) + (2)(3h) + (2)(7) . . . . . . . a(b +c) = ab +ac . . . (twice)

= -12h² -28h +6h +14

= -12h² -22h +14 . . . . . . . . collect terms

If 300 cm^2 of material is available to make a box with a square base and an open top, find the maximum volume of the box in cubic centimeters. Answer to the nearest cubic centimeter without commas. For example, if the answer is 2,000 write 2000.

Answers

Hello,
Assume a the side of the base, b the height.

[tex]V=a^2*b\\ a^2+4ab=300==\ \textgreater \ b= \dfrac{300-a^2}{4a} \\ V=a^2*\dfrac{300-a^2}{4a}= \frac{1}{4} *(300a-a^3)\\ \dfrac{dV}{da} = \frac{1}{4} *(300-3*a^2)=0\\ ==\ \textgreater \ a=10 \ and\ b=5\\ V=10^2*5=500\\ [/tex]

An expression is shown below:

square root of 32 plus square root of 2

Which statement is true about the expression?

please help 25 points

A. It is rational and equal to 4

B. It is rational and equal to 5

C. It is rational and equal to 5√2

D. It is rational and equal to 4√2

Answers

C) sqrt(32) = sqrt(2^5)=4sqrt(2), then + sqrt(2) = 5 * sqrt(2)

√(2^5)+√2

4√2+√2

(4+1)√2

5√2

There is a problem however...5√2 is IRRATIONAL because √2 is irrational, ie, it cannot be expressed as a ration of two integers...

So the problems simplified is certainly 5√2, but it is irrational.

Maybe there is a typo and should read:

C. It is IRrational and equal to 5√2

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