A compact car has a maximum acceleration of 4.0 m/s2 when it carries only the driver and has a total mass of 1200 kg . you may want to review ( pages 108 - 109) . part a what is its maximum acceleration after picking up four passengers and their luggage, adding an additional 400 kg of mass?

To calculate the acceleration of the elevator, we can use Newton's second law, Fnet = ma, where Fnet is the net force acting on the person and m is the mass of the person. The acceleration of the elevator is equal to 0.34 times the person's weight divided by the person's mass.

When the elevator starts to move, the scale briefly reads only 0.66 of the person's regular weight. To calculate the acceleration of the elevator, we can use Newton's second law, Fnet = ma, where Fnet is the net force acting on the person and m is the mass of the person. In this case, the net force is equal to the difference between the weight of the person and the scale reading, so we have Fnet = w - Fs. The scale reading is given as 0.66 of the person's weight, so Fs = 0.66w. Plugging this into the equation, we get Fnet = w - 0.66w = 0.34w. Since Fnet = ma, we can write 0.34w = ma. Dividing both sides by the mass, we get a = 0.34w/m. Therefore, the acceleration of the elevator is equal to 0.34 times the person's weight divided by the person's mass.

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Answer:

1.41:1

Explanation:

Answer:

Like electric charges repel each other. ... Why can't conductors generate static electricity when rubbed together? They will direct excess charge to earth. Suppose you acquire a positive charge from walking across a carpet.

Explanation:

[tex]hope \: it \: helps \: you[/tex]

To calculate the deceleration of a snowboarder going uphill on a 5.0° slope, use the formula a = g(sin(θ) − μk cos(θ)), where θ is the angle of the slope, g is the acceleration due to gravity, and μk is the coefficient of kinetic friction for waxed wood on wet snow.

Calculation of Deceleration of a Snowboarder Going Uphill

To calculate the deceleration of a snowboarder going uphill on a 5.0° slope, we can use the formula a = g(sin(θ) − μk cos(θ)). Here, θ is the angle of the slope, g is the acceleration due to gravity (9.8 m/s²), and μk is the coefficient of kinetic friction for waxed wood on wet snow.

Plugging in the values, we have a = 9.8(sin(5.0°) − μk cos(5.0°)). However, since the snowboarder is going uphill, the acceleration will be in the opposite direction of motion, so the magnitude will be the negative value of a. Hence, the deceleration will be -9.8(sin(5.0°) − μk cos(5.0°)).

Remember to substitute the appropriate value for μk based on the coefficient of friction for waxed wood on wet snow.

Answer:

A). The nuclear regulatory commission.

Explanation:

I am taking the test rnn.

Flvs

The label which belongs in the area marked Z having characteristics as

are producers.

Autotrophs, also called as primary producers are organisms that acquire their energy from sunlight and materials from nonliving sources. Algae, and some bacteria are important autotrophs in running waters.

Heterotrophs obtain energy and materials by taking living or dead plants or animals matter.

Producers create their own food using sunlight and absorb water from the soil.

Thus, the category labelled as producers.

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The vertical component of her acceleration during push-off, when the positive direction is upward, is -9.8 m/s².

The vertical component of her acceleration during push-off, when the positive direction is upward, is -9.8 m/s². In physics, the acceleration due to gravity is typically denoted by -9.8 m/s² when taken in the upward direction.

The maximum efficiency of heat is 72%.

To find the efficiency, the given values are:

Temperature T1 = 2 degree celsius,

Temperature T2 = 200 degree celsius.

The peak level of performance that uses the least amount of inputs to achieve the highest amount of output can be defined as the efficiency.

Usually the word efficient means as quality or being efficient.

Efficiency value will be calculated in percentage.

The formula of efficiency can be,

                  Efficiency =( T1 - T2/ T1) × 100

T1 - First temperature

T2 - Second temperature

Converting the values from degree celsius to Kelvin,

T1= 2+273 =275 K

T2 = 200 +273=473 K

Substituting the values in the formula,

Efficiency = (275 - 473 / 275)×100

= ( 198 ×100)/275

= 72 %

The maximum efficiency of a heat is 72%.

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To solve this problem, we can use the cosine formula for calculating the length of the displacement:

c^2 = a^2 + b^2 – 2 a b cos θ

where c is the displacement, a = 3.5 km, b = 4.5 km, and θ is the angle inside the triangle

Since the geeze turned 40° from west to north, so the angle inside the triangle must be:

θ = 180 – 40 = 140°

c^2 = 3.5^2 + 4.5^2 – 2 (3.5) (4.5) cos 140

c^2 = 56.63

c = 7.53 km

So the magnitude of the displacement is 7.53 km

The magnitude of their displacement is 7.5 km

Vector is a quantity that has a magnitude and direction.

A vector in a cartesian coordinate is represented by an arrow in which the slope of the arrow shows the direction of the vector and the length of the arrow shows the magnitude of the vector.

A position vector of a point is a vector drawn from the base point of the coordinates O (0,0) to that point.

The addition of two vectors can be done in the following ways:

[tex]\overrightarrow {AB} + \overrightarrow {BC} = \overrightarrow {AC}[/tex]

A negative vector is a vector with the same magnitude but in opposite direction.

[tex]\overrightarrow {AB} = -\overrightarrow {BA}[/tex]

Let's tackle the problem!

First, let's look at the picture in the attachment!

Let:

[tex]\overrightarrow{d_1} = -3.5 \widehat{i}[/tex]

[tex]\overrightarrow{d_2} = -(4.5 \cos 40^o) \widehat{i} + (4.5 \sin 40^o) \widehat{j}[/tex]

Then:

[tex]\overrightarrow{d} = \overrightarrow{d_1} + \overrightarrow{d_2}[/tex]

[tex]\overrightarrow{d} = -3.5 \widehat{i} + -(4.5 \cos 40^o) \widehat{i} + (4.5 \sin 40^o) \widehat{j}[/tex]

[tex]\overrightarrow{d} = -(3.5 + 4.5 \cos 40^o)\widehat{i} + (4.5 \sin 40^o) \widehat{j}[/tex]

[tex]|\overrightarrow{d}| = \sqrt{ (3.5 + 4.5 \cos 40^o)^2 + (4.5 \sin 40^o)^2}[/tex]

[tex]|\overrightarrow{d}| \approx 7.5 ~ km[/tex]

Grade: High School

Subject: Physics

Chapter: Vectors

Keywords: Velocity , Driver , Car , Deceleration , Acceleration , Obstacle , Speed , Time , Rate , Vector , Scalar

Radiation transfers energy through electromagnetic waves, not by moving matter.

The statement that 'radiation transfers energy by moving matter' is false.

Radiation transfers energy through electromagnetic waves, which do not require the movement of matter. Atoms and molecules emit electromagnetic radiation as their electrons move about and collide or vibrate in place. This radiation carries energy and can be absorbed by other material.

For example, in a hot material, the individual particles vibrate or move rapidly from collisions, resulting in more energetic waves being emitted. On the other hand, cool material generates lower-energy waves due to low-energy atomic and molecular motions.

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Momentum is a property of matter related to mass and velocity. It has a directional component, aligning with the velocity of the object. Additionally, it has importance in physics principles and displays wave properties on a subatomic level.

Momentum is a property of matter that is intrinsically connected to both the object's mass and velocity. From the formula of momentum, p=mv, we can see that momentum is directly proportional to mass and also velocity. Thus, the greater an object's mass or the faster it moves, the greater its momentum.

Momentum is a vector quantity, meaning it also has a direction aligning with the velocity of the object. Many concepts in physics such as Newton's second law of motion, can be restated in terms of momentum. Furthermore, momentum conservation is a fundamental principal used to analyze matters from simple collisions to complex particle physics.

Also, on a microscopic scale, momentum is observed to have wave properties that are integral to understanding the behaviours of subatomic particles.

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Answer:

Because when the gas runs out, there is still energy in the car, but another form of energy.

Explanation:

Car, motorcycle, bus, and truck engines produce motion from a chemical reaction known as combustion. We can say that the chemical energy of gas in a car is converted to thermal energy during the explosion of gasoline or diesel. This released thermal energy causes the engine to tighten the engine piston, producing movement and hence kinetic energy.

However, the car has other forms of energy as it needs an entire electrical system to function. For this reason, it is wrong to say that "We ran out of gas." when it comes to your car's energy source.

When we say directly northeast that is equivalent to 45˚ north of east.

First let us determine the north and east components of the acceleration using cos and sin functions:

North = 2.18 * sin 45 
East = 2.18 * cos 45 

Then we set to determine the east component of the plane’s displacement by calculating using the formula:

d = vi * t + ½ * a * t^2 
d = 135 * 18 + ½ * 2.18 * cos 45 * 18^2 
d = 2430 + 353.16 * cos 45 = 2679.72 m

Calculating for the north component:
North = ½ * 2.18 * sin 45 * 18^2

North = 249.72 m 

Hence magnitude is:

Magnitude = sqrt (2679.72^2 + 249.72^2)

Magnitude = 2,691. 33 m

Calculating for angle:

Tan θ = North ÷ East 
Tan θ = 249.72 m  ÷ 2679.72 m

θ = 5.32°

So the plane was flying at 2,691. 33 m at 5.32°

Answer:

2,691.33 - magnitude

Explanation:

5.32 - direction

The answer is No. The explanation behind this is found in Article III, it is stated there that the “Supreme Court shall have original jurisdiction in all circumstances touching ambassadors, other public ministers and diplomats, and those in which a state shall be a party. In all other circumstances the Supreme Court shall have appellate jurisdiction”. Therefore if the legislature augments to their jurisdictions, then there would be numerous courts with definite jurisdiction.

When k = 2.40 and [tex]\rm \( \theta = 18.0^\circ \)[/tex], the ratio [tex]\rm \( \frac{F}{F_A} \)[/tex] is approximately 0.7368.

Work through the calculation step by step to find the ratio [tex]\rm \( \frac{F}{F_A} \)[/tex] when k = 2.40 and the angle [tex]\rm \( \theta = 18.0^\circ \)[/tex].

Given:

Magnitude of the additional forces [tex]\rm \( F_B = F_C = F \)[/tex]

Magnitude of the resultant force in part b Resultant Force = [tex]\rm 2.4 \cdot F_A \)[/tex]

Angle [tex]\rm \( \theta = 18.0^\circ \)[/tex]

Step 1: Decompose Forces

Let's first decompose the additional forces [tex]\rm \( F_B \)[/tex] and [tex]\rm \( F_C \)[/tex] into components parallel and perpendicular to the direction of [tex]\rm \( F_A \)[/tex].

The component of [tex]\rm \( F_B \)[/tex] perpendicular to [tex]\rm \( F_A \)[/tex] is [tex]\rm \( F_B \cdot \sin(\theta) \)[/tex].

The component of [tex]\rm \( F_C \)[/tex] perpendicular to [tex]\rm \( F_A \)[/tex] is [tex]\rm \( F_C \cdot \sin(\theta) \)[/tex].

Since [tex]\rm \( F_B \)[/tex] and [tex]\rm \( F_C \)[/tex] are on opposite sides of [tex]\rm \( F_A \)[/tex] and make the same angle with [tex]\rm \( F_A \)[/tex], these perpendicular components will cancel each other.

Step 2: Calculate Resultant Force

The resultant force Resultant Force is the sum of [tex]\rm \( F_A \)[/tex] and the components of [tex]\rm \( F_B \)[/tex] and [tex]\rm \( F_C \)[/tex] along [tex]\rm \( F_A \)[/tex].

[tex]\rm \[ \text{Resultant Force} = F_A + F_B \cdot \cos(\theta) + F_C \cdot \cos(\theta) \]\\\ \text{Resultant Force} = F_A + 2F \cdot \cos(\theta) \][/tex]

Step 3: Equate Resultant Forces

We are given that Resultant Force = [tex]\rm 2.4 \cdot F_A[/tex], so we can equate the two expressions for the resultant force:

[tex]\rm \[ F_A + 2F \cdot \cos(\theta) = 2.4 \cdot F_A \][/tex]

Step 4: Solve for [tex]\rm \( \frac{F}{F_A} \)[/tex]

Now, solve for [tex]\rm \( \frac{F}{F_A} \)[/tex]:

[tex]\rm \[ 2F \cdot \cos(\theta) = 1.4 \cdot F_A \\\ \\\frac{F}{F_A} = \frac{1.4}{2 \cdot \cos(\theta)}\\\ \\\frac{F}{F_A} = \frac{1.4}{2 \cdot \cos(18.0^\circ)}\\\\\ \frac{F}{F_A} \approx 0.7368 \][/tex]

Therefore, when k = 2.40 and [tex]\rm \( \theta = 18.0^\circ \)[/tex], the ratio [tex]\rm \( \frac{F}{F_A} \)[/tex] is approximately 0.7368.

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Answer:

The more energy a wave carries the higher its amplitude.

Explanation:

The energy of a wave is defined by the equation:

[tex]E=\frac{1}{2} m\omega^2 A^2[/tex]

Where [tex]E[/tex] is energy, [tex]m[/tex] is mass, [tex]\omega[/tex] is angular velocity, and [tex]A[/tex] is amplitude.

The previous equation indicates that the energy is directly proportional to the amplitude; if the energy of a wave increases so does the amplitude, and if the energy of a wave decreases the amplitude also decreases.

Thus the answer is:

The more energy a wave carries the higher its amplitude.

Final answer:

The best way to remember kinematics for your physics exam is to follow a step-by-step approach, including examining the situation, identifying knowns and unknowns, and using appropriate kinematic equations.

Explanation:

Steps to Remember Kinematics for a Physics Exam:

Examine the situation to determine the physical principles involved.

Identify the knowns and unknowns in the problem.

Find an appropriate kinematic equation(s) to solve the problem.

For example, if time is not given, you can use the kinematic equation that does not involve time.

Remember to draw a simple sketch of the situation and assign positive/negative directions.

Practice applying these steps to different kinematic problems to improve your understanding and retention.

Answer:

14,286 kg

Explanation:

Mass and velocity, have a positive correlation to momentum.

The formula to determine momentum is:

Momentum = Mass x Velocity

So if we want to determine the mass of the object, the formula can be rearranged to look like this:

Momentum/Velocity = Mass

And can be solved by imputing the values given in the question:

Mass = (100 kg*m/s) ÷ (7 m/s)

Mass = 14,286 kg

Answer: A. electric and magnetic forces

Explanation:

Thus, an electric force and magnetic force are repulsive and attractive in nature.

The relevant equation we can use in this problem is:

h = v0 t + 0.5 g t^2

where h is height, v0 is initial velocity, t is time, g is gravity

Since it was stated that the rock was drop, so it was free fall and v0 = 0, therefore:

h = 0 + 0.5 * 9.81 m/s^2 * (4.9 s)^2

h = 117.77 m

Final answer:

To find the height of the building, the formula for the distance an object falls due to gravity is used: d = 1/2 g t². Inserting the given time of 4.9 seconds and the gravitational constant of 9.8 m/s² the calculated height of the building is approximately 117.549 meters.

Explanation:

To measure the height of a building by dropping a rock and timing its fall, we use the physics of free fall motion. The equation to find the distance an object falls due to gravity (when air resistance is negligible) is:

d = ½ g t²

where:

d is the distance the object falls (height of the building in this case),

g is the acceleration due to gravity (approximately 9.8 m/s² on Earth), and

t is the time it takes for the object to reach the ground.

Given the time of 4.9 seconds for the rock to reach the ground, we plug in the values:

d = ½ (9.8 m/s²) (4.9 s)²

This gives us:

d = ½ (9.8) (24.01)

d = 117.549 m

By using this formula, we can find that the building is approximately 117.549 meters high.

The statement which best describes the effect of scientific advances on society is that they are inspired by the needs of society. Thus, the correct option for this question is B.

Scientific advancement may be defined as the generation or discovery of knowledge that advances the understanding of science or technology. It is also known as technological advancement. This mechanism stimulates when technologies or applied sciences become more precise, accurate, efficient, or more powerful or capable.

According to the context of this question, scientific advancement allows us to develop new technologies, solve practical problems, and make informed decisions both individually and collectively.

This is because its products are so useful, and the process of science is intertwined with those applications. This proves that it plays a major role in society. New scientific knowledge may lead to new applications.

Therefore, the correct option for this question is B.

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The electronic transition in a hydrogen atom from [tex]\boxed{{\text{a}}{\text{. n = 3 to n=2}}}[/tex] is an exothermic process.

Further explanation:

An electronic transition is a process when an electron undergoes emission or absorption from one energy level to another energy level.

When an electron undergoes a transition from lower energy to the higher energy level then it requires energy to complete the process. Thus this transition is an absorption process.

When an electron undergoes a transition from higher energy to lower energy level then it emits the energy to complete the process. Thus this transition is an emission process.

The formula to calculate the difference between two energy levels of a hydrogen atom is,

 [tex]\Delta E={R_{\text{H}}}\left({\frac{1}{{{{\left({{{\text{n}}_{\text{i}}}}\right)}^2}}}-\frac{1}{{{{\left({{{\text{n}}_{\text{f}}}}\right)}^2}}}}\right)[/tex]

Where,

[tex]\Delta E[/tex]  is the energy difference between two energy levels.

[tex]{R_{\text{H}}}[/tex]  is a Rydberg constant.

[tex]{{\text{n}}_{\text{i}}}[/tex]  is the initial energy level of transition.

[tex]{{\text{n}}_{\text{f}}}[/tex]  is the final energy level of transition.

The endothermic reactions are the reaction that absorbs heat from its surroundings. The exothermic reactions are reactions that release the heat to its surroundings.

Solution:

Classification of transitions

1. In the transition from n=1 to n=3, electron goes from lower energy level (n=1) to higher energy level (n=3). Therefore, it needs to absorb the energy. Hence, this transition is classified as an absorption process. Since absorption process required the energy to complete the process thus it is an endothermic process.

2. In transition from n=3 to n=2, electron goes from higher energy level (n=3) to lower energy level (n=2), therefore, it needs to emit the energy. Hence, this transition is classified as an emission process. Since emission process releases the energy to surrounding thus it is an exothermic process.

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Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Atomic structure

Keywords: transition, a hydrogen atom, transition from n=1 to n=3, transition from n=3 to n=2, hydrogen, absorption process, emission process, endothermic and exothermic process.

The rocket’s acceleration is [tex]21m/s^2[/tex]

Acceleration is the rate of change of the velocity of an object with respect to time. Acceleration is vector quantities as it has both magnitude and direction.

It is given by

[tex]a = \frac{v_f-v_0}{t}[/tex]

Where,

[tex]a =[/tex] average acceleration

[tex]v_f=[/tex] final velocity

[tex]v_0=[/tex] starting velocity

[tex]t =[/tex] elapsed time

The force acting on an object perpendicular to the surface is called thrust. It is vector quantity and SI Unit of thrust is Newton.

[tex]\mathbf{T}=\mathbf{v} \frac{\mathrm{d} m}{\mathrm{d} t}[/tex]

Where,

[tex]T=[/tex] thrust

[tex]v=[/tex] velocity

[tex]dm=[/tex] change of mass

[tex]dt=[/tex] change in time

Given,

Mass of rocket, [tex]m = 5*10^5Kg[/tex]

Thrust,[tex]T = 1.5*10^7N[/tex]

Air resistance [tex]F_a= 4.5*10^6N[/tex]

The net upward force will be

[tex]F_n= T-F_a\\F_n= 1.5*10^7-4.5*10^6\\F_n= 1.05*10^7N[/tex]

Using

[tex]F = ma\\a = \frac{F}{m}\\a = \frac{1.05*10^7}{5*10^5}\\a = 21 m/s^2[/tex]

Thus the acceleration is [tex]21m/s^2[/tex].

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To calculate the rocket's acceleration, subtract air resistance from the engine's thrust to get the net force and then divide it by the rocket's mass according to Newton's second law. The acceleration is found to be 21 [tex]m/s^2[/tex].

To determine the rocket's acceleration, we must apply Newton's second law of motion, which states that force equals mass times acceleration (F = ma). In this scenario, we have two forces to consider: the rocket engine's thrust and the air resistance acting against it. The net force is calculated by subtracting the air resistance from the engine's thrust.

Firstly, we must find the net force acting on the rocket. To do this, we subtract the air resistance from the thrust:

Net Force = Thrust - Air Resistance
[tex]Net Force = 1.50 X 10^7 N - 4.50 X 10^6 N\\Net Force = 10.5 X 10^6 N[/tex]

Now, using Newton's second law, we set up the equation for acceleration (a = F/m), where F is the net force and m is the mass of the rocket:

Acceleration (a) = Net Force (F) / Mass (m)
[tex]Acceleration (a) = \frac{10.5 X 10^6 N}{5.00 X 10^5 kg}\\Acceleration (a) = 21 \ m/s^2[/tex]

Thus, the acceleration of the rocket is 21 meters per second squared.

The ball will rise to a maximum height of [tex]\boxed{h=\dfrac{v^2}{2g}}[/tex].

Explanation:

The kinetic energy of a body is the energy associated with the body by virtue of its motion whereas the potential energy of the body is the amount of energy stored in a body by virtue of its position.

The amount of kinetic energy stored in a body is given by:

[tex]\boxed{K=\dfrac{1}{2}mv^2}[/tex]                                                ...... (1)

Here, [tex]K[/tex] is the kinetic energy, [tex]m[/tex] is the mass and [tex]v[/tex] is the speed of the body.

The potential energy stored in a body as it reaches its maximum height is given as:

[tex]\boxed{P=mgh}[/tex]                                                      ...... (2)

Here, [tex]P[/tex] is the potential energy stored, [tex]g[/tex] is the acceleration due to gravity and [tex]h[/tex] is the height attained by the body.

According to the conservation of energy, the energy can neither be created nor destroyed. It can only be converted from one form to another.

[tex]\text{kinetic energy}=\text{potential energy}[/tex]

Substitute the values of kinetic energy and potential energy and simplify the expression for the maximum height.

[tex]\begin{aligned}\dfrac{1}{2}mv^{2}=&mgh_{max}\\h_{max}=&\dfrac{v^2}{2g}\end{aligned}[/tex]

Therefore, the maximum height attained by the ball as it rises up is [tex]\boxed{h_{max}=\dfrac{v^2}{2g}}[/tex].

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Answer Details:

Grade: Senior School

Subject: Physics

Chapter: Conservation of Energy

Keywords:

Ball is launched, ground level, conservation of energy, kinetic, potential energy, motion, maximum height, in contact with hill, vertical height, in terms of v and g.

Using the conservation of energy, the maximum vertical height hmax a ball can reach when launched up a frictionless hill is given by the equation hmax = v²/2g. The ball's initial kinetic energy is converted into potential energy at the maximum height, at which point its speed is momentarily zero.

To determine the maximum vertical height hmax that the ball will reach, we can invoke the law of conservation of energy. This fundamental principle asserts that the total energy of an isolated system remains constant, expressing that energy can be converted from one form to another, but not created or destroyed.

At the initial moment before the launch, the ball has kinetic energy but no potential energy (since it's at ground level). The kinetic energy is given by the formula 1/2mv², where m is mass, and v is initial speed.

At the moment when the ball has climbed to maximum height (hmax), it comes momentarily at rest, so its kinetic energy is zero and all converted to the potential energy. The potential energy at this position is given by m*g*hmax, where g is the acceleration of gravity.

Forming an equation using the law of conservation of energy, we equate the initial kinetic energy and the final potential energy as: 1/2mv² = m*g*hmax. Solving for hmax we have: hmax = v²/2g.

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