A constant force of f = 47i + 30j moves an object along a vector d = 13i - 8j, where units are in pounds and feet. find the work done.

Answers

Answer 1

Answer:

The work is  371 lb ft

Explanation:

The work can be calculated with yhe scalar product between the force and the displacement:

[tex] W = F.d [/tex]

The scalar product is obtained multiplying component to comoponent and summing the terms:

[tex] W [/tex] = <47, 30> · <13, -8>  [lb ft]

[tex] W [/tex] = 47*13  + 30*(-8) [lb ft]

Finally:

W = 371 [lb ft]


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