A fast food restaurant sold 30 burgers with cheese if the ratio burger soup with cheese compared to without cheese was 5 : 1 one how many burgers did they sell total

Answers

Answer 1

Answer:36 burgers were sold.

Step-by-step explanation:

Let x represent the total number of burgers, with or without cheese that was sold.

The total number of burgers with cheese that the fast food sold is 30.

if the ratio burger sold with cheese compared to without cheese was

5 : 1 , the total ratio would be the sum of both proportions. It becomes

5 + 1 = 6

Therefore

5/6 × x = 30

5x/6 = 30

Cross multiplying by 6, it becomes

5x = 30 × 6 = 180

x = 180/5 = 36

Therefore, the number of burgers without cheese sold would be

36 - 30 = 6


Related Questions

Adrienne's annual take-home pay is $57,000. What is the maximum amount that she can spend per month paying off credit cards and loans and not be in danger of credit overload?
A. $950.00
B. $1187.50
C. $4750.00
D. $3800.00

Answers

Answer:

Option C. is correct.

Step-by-step explanation:

Given:

Adrienne's annual take-home pay = $57,000

To find:

The maximum amount that she can spend per month on paying off credit cards and loans and not be in danger of credit overload.

Solution:

Number of months in a year = 12

So, amount she can spend per month =

Annual pay of Adrienne / Number of months in a year = [tex]\frac{57000}{12} =\frac{28500}{6}=\frac{14250}{3}=4750[/tex]

So, option C. is correct.

Answer:

A. $950.00

Step-by-step explanation:

A p e x

In a school, 3/4 of the students study a language. Of those who study a language, 3/5 study French. Find the ratio of students who study French to students who do not study French. Give your answer in its simplest form.

Answers

Answer: 9:11

Step-by-step explanation:

Let x be the total number of students.

If 3/4 of students study a language That mean 3x/4 students study a language.

Number of students that don't study a language becomes

x - 3x/4 = x/4.

and 3/5 of those who study language study French, that means 3x/4 * 3/5 of students study French.

This gives 3x/4 * 3/5 = 9x/20 Studying French.

Number of students that study language but do not study French becomes

3x/4 - 9x/20 = 6x/20

Total number of students that do not study French becomes

[total number of students not studying any language] + [total number of students studying a language but do not study French ]

Which becomes

x/4 + 6x/20 = 11x/20

Hence ratio of those that study French to those that do not study French Becomes

9x/20 : 11x/20

9:11.

The number of question on a math test is represented (3x+1). The number of questions on the spelling test is represented by (x+12). Write an expression to find how many more questions were on the math test. Then evaluate the expression if the value x is 8

Answers

Answer:

Step-by-step explanation:

The number of questions on a math test is represented (3x+1). The number of questions on the spelling test is represented by (x+12).

An expression to find how many more questions were on the math test would be

= 3x + 1 - (x + 12)

= 3x + 1 - x - 12

= 3x - x + 1 - 12

= 2x - 11

When the value of x = 8, then the expression becomes

2× 8 - 11 = 16 - 11 = 5

Final answer:

To find how many more questions are on the math test compared to the spelling test, you subtract the spelling test expression from the math test expression. Simplifying this gives 2x - 11. Evaluating this expression for x = 8 shows there are 5 more questions on the math test.

Explanation:

The question asks you to write an expression to find out how many more questions are on the math test compared to the spelling test, and then evaluate this expression for x = 8.

Step 1: Write the expression

To find how many more questions are on the math test, you subtract the number of questions on the spelling test from the number of questions on the math test. Therefore, the expression is:

(3x + 1) - (x + 12)

Step 2: Simplify the expression

First, distribute the negative sign: 3x + 1 - x - 12. Simplify by combining like terms: 2x - 11. This simplified expression represents how many more questions are on the math test compared to the spelling test.

Step 3: Evaluate the expression for x = 8

Plug in x = 8 into the simplification, 2x - 11. So, you get: 2(8) - 11 = 16 - 11 = 5.

Therefore, there are 5 more questions on the math test than on the spelling test when x = 8.

For #1-4, graph the polygon with the given vertices and its image after the transformation. Label all vertices in both the Pre-image and image using the correct notation.

Answers

See the attached picture:

Edited graph 4. I missed the negative sign in front of the one. The new graph is attached.

A scatter plot shows a set of data points that are clustered close to a line that slopes down to the right. Which of the following values would be closest to the correlation for these data? a. -0.40 b. 0.40 c. 0.80 d. -0.80

Answers

Answer:

Option D. -0.80

Step-by-step explanation:

A scatter plot that shows a set of data points having two properties

1). If the points are clustered close to the line that reveals the high correlation.

2). Data points are clustered close to the line having slope down to the right or negative slope.

Therefore, Option D. has the highest correlation with negative slope.

A box with a square base and open top must have a volume of 32,000cm^3. How do you find the dimensions of the box that minimize the amount of material used?

Answers

Answer:

Side of 40 and height of 20

Step-by-step explanation:

Let s be the side of the square base and h be the height of the box. Since the box volume is restricted to 32000 cubic centimeters  we have the following equation:

[tex]V = hs^2 = 32000[/tex]

[tex]h = 32000/ s^2[/tex]

Assume that we cannot change the thickness, we can minimize the weight by minimizing the surface area of the tank

Base area with open top [tex]s^2[/tex]

Side area 4hs

Total surface area [tex]A = s^2 + 4hs[/tex]

We can substitute [tex]h = 32000/ s^2[/tex]

[tex]A = s^2 + 4s\frac{32000}{s^2}[/tex]

[tex]A = s^2 + 128000/s[/tex]

To find the minimum of this function, we can take the first derivative, and set it to 0

[tex]A' = 2s - 128000/s^2 = 0[/tex]

[tex]2s = 128000/s^2[/tex]

[tex]s^3 = 64000[/tex]

[tex]s = \sqrt[3]{64000} = 40[/tex]

[tex]h = 32000/ s^2 = 32000/ 40^2 = 20[/tex]

When you graph a square root does it curve

Answers

Answer:

yes

Step-by-step explanation:

because it is not a whole number so you cant tell

A salesperson at a car dealership has a salary of 900 dollars per week plus 3% commission on sales if a salesperson has sales of 72000$ in one week what was the salesperson paid that week

Answers

Answer:

Step-by-step explanation:

A salesperson at a car dealership has a salary of 900 dollars per week plus 3% commission on sales if a salesperson has sales of $72000 in one week, it means that the amount of commission that was received by the salesperson would be

3/100 × 72000 = 0.03 × 72000 = $2160

Therefore, the total amount of pay that the salesperson would receive for the week would be

900 + 2160 = $3060

Malcom coasted 32 miles from Moonridge to to Mentine and then pedaled back hard. If the round trip took 4 hours, what was Malcombs average speed in mph

Answers

Answer:

  16 mph

Step-by-step explanation:

The relationship between distance, speed, and time is ...

  speed = distance/time . . . . . "miles per hour"

Malcom's distance was 32 miles each way, for a total of 64 miles. Then his average speed was ...

  speed = (64 mi)/(4 h) = 16 mi/h

Ms Thomas drove at a constant rate for 45. She drove 39 miles during that time. If distance is determined by the equation d=rt where r is the constant rate in miles per hours what was ms Thomas constant rate?

Answers

Answer:

Ms. Thomas was driving at constant rate of 52 miles/hour.

Step-by-step explanation:

Given:

Total time to travel (t) = 45 minutes

Distance drove (d) = 39 miles

we need to find the constant rate in miles per hour at which she was driving.

Solution:

Now we know that;

We need to find constant rate at miles per hour;

But time is given in minutes.

So we will convert minutes into hour by dividing by 60 we get;

time [tex]t =\frac{45}{60}= 0.75\ hrs[/tex]

Now we know that;

Distance is equal to rate times time.

framing in equation form we get;

distance [tex]d =rt[/tex]

Or

rate [tex]r= \frac{d}{t} = \frac{39}{0.75}= 52 \ mi/hr[/tex]

Hence Ms. Thomas was driving at constant rate of 52 miles/hour.


A pilot knows she descended 1,000 feet and traveled a diagonal distance of 18,000 feet.
What was the horizontal distance covered by the pilot?


A-17.9722 ft
B-18027.8 ft
C-16.000 ft
D-15.457 8 ft

Answers

The horizontal distance covered by pilot is 17,972.2 feet.

Step-by-step explanation:

Given,

Distance covered descending = 1000 feet

Diagonal distance = 18,000 feet

The horizontal distance will form a right triangle, therefore, we can find the horizontal distance by using pythagoras theorem.

Here,

a = 1000

b = horizontal distance

c = 18000

[tex]a^2+b^2=c^2\\(1000)^2+b^2=(18000)^2\\1000000+b^2=324000000\\b^2 = 324000000-1000000\\b^2=323000000[/tex]

Taking square root on both sides

[tex]\sqrt{b^2}=\sqrt{323000000}\\b=17972.2[/tex]

The horizontal distance covered by pilot is 17,972.2 feet.

Keywords: pyathoras theorem, square root

Learn more about square root at:

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Suppose that the number of worker-hours required to distribute new telephone books to x% of the households in a certain rural community is given by the function W(x)=250x/(400−x). (a) What is the domain of the function W? (Give the domain in interval notation. If the answer includes more than one interval write the intervals separated by the "union" symbol, U.) (b) For what values of x does W(x) have a practical interpretation in this context? (c) How many worker-hours were required to distribute new telephone books to the first 70% of the households? (d) How many worker-hours were required to distribute new telephone books to the entire community? (e) What percentage of the households in the community had received new telephone books by the time 3 worker-hours had been expended?

Answers

Answer:

a) Domain = [tex](-\infty,400)\cup (400,\infty)[/tex]

b) [tex]x \in [0,100][/tex]

c) 53.03 worker hours

d) 83.33 worker hours

e) 83.33 worker hours

Step-by-step explanation:

We are given the following in the question:

[tex]W(x) = \dfrac{250x}{(400-x)}[/tex]

where W(x) is the number of worker-hours required to distribute new telephone books to x% of the households in a certain rural community.

a) Domain of function.

The domain is the all the possible values of x that the function can take.

Domain = [tex](-\infty,400)\cup (400,\infty)[/tex]

b) Values of x

Since x is a percentage in reference to context, it can only take value upto 100. Also it cannot take any negative value.

So domain n reference to context will be

[tex]x \in [0,100][/tex]

c) worker-hours were required to distribute new telephone books to the first 70% of the households

[tex]W(70) = \dfrac{250(70)}{(400-70)} = 53.03[/tex]

53.03 worker hours were required to distribute new telephone books to the first 70% of the households.

d) Worker hour for entire community

For entire community, x = 100

[tex]W(100) = \dfrac{250(100)}{(400-100)} = 83.33[/tex]

83.33 worker hours were required to distribute new telephone books to the entire households.

e) Percentage of the households in the community for 3 worker hours

[tex]3 = \dfrac{250x}{(400-x)}\\\\1200-3x = 250x\\253x = 1200\\\\x = \dfrac{1200}{253} = 4.74\%[/tex]

Thus, 4.74% of the households in the community had received new telephone books by the time 3 worker-hours had been expended.

Final answer:

The domain of the function W(x) is (-∞, 400) U (400, +∞). The values of x that have a practical interpretation in this context are in the interval [0, 100]. Approximately 53.03 worker-hours were required to distribute new telephone books to the first 70% of households, and approximately 83.33 worker-hours were required to distribute to the entire community. After 3 worker-hours, approximately 4.73% of the households had received new telephone books.

Explanation:

(a) The domain of the function W is the set of all possible values of x that make the function defined and meaningful. In this case, the function W(x) is defined except when the denominator 400-x is equal to zero. So, we need to find the values of x that make the denominator zero.

To do that, we solve the equation 400-x = 0, which gives x = 400.

Therefore, the domain of the function W is the set of all real numbers except x = 400. We can express this in interval notation as (-∞, 400) U (400, +∞).

(b) In this context, the function W(x) represents the number of worker-hours required to distribute new telephone books to x% of the households in the rural community. A practical interpretation is only meaningful when x represents a valid percentage, meaning that it is between 0% and 100%, inclusive. So, the values of x that have a practical interpretation in this context are in the interval [0, 100].
(c) To find the worker-hours required to distribute new telephone books to the first 70% of households, we substitute x = 70 into the function W(x). Evaluating the expression, we get: W(70) = 250(70) / (400 - 70) = 17500 / 330 = 53.03.

Therefore, approximately 53.03 worker-hours were required to distribute new telephone books to the first 70% of households.

(d) To find the worker-hours required to distribute new telephone books to the entire community, we substitute x = 100 into the function W(x). Evaluating the expression, we get: W(100) = 250(100) / (400 - 100) = 25000 / 300 = 83.33.

Therefore, approximately 83.33 worker-hours were required to distribute new telephone books to the entire community.

(e) To find the percentage of households that had received new telephone books after 3 worker-hours, we rearrange the function W(x) to solve for x. We have:

W(x) = 250x / (400 - x)

3 = 250x / (400 - x)

3(400 - x) = 250x

1200 - 3x = 250x

1200 = 253x

x = 1200 / 253 ≈ 4.73

Therefore, approximately 4.73% of the households in the community had received new telephone books after 3 worker-hours.

11. A(-2,1), B(2,5), C(5,1) (round answers to the nearest tenth)

Perimeter___________

Area_______________




Answers

See the attached picture:

Shane's neighbor pledged $1.25 for every 0.5 miles that Shane swims and the charity swim-a-thon. If Shane swims 3 miles how much money would his neighbors donate

Answers

Answer:

7.5

Step-by-step explanation:

1.25/ (.5) = 2.5

2.5 x 3 = 7.5

A buyer paid ​$55 comma 68055,680​, including the​ buyer's premium, for a car auction. If the auction adds a 1616​% ​buyer's premium to the sale price of the​ car, then what was the sale price of the​ car?

Answers

Answer:

The sale price of the car is $48000.

Step-by-step explanation:

i) let the sale price of the car be = $x

ii) the premium is given as 16%

  therefore the premium of the car will be equal to = 16% of $x

  the premium of the car will be = $0.16x

iii) therefore total price of car in terms of sale price x  = $x + $0.16x

           therefore total price = $1.16x

iv) total price is given as $55,680

 

Therefore   $55,680 = $1.16x,    therefore $x = [tex]\dfrac{55,680}{1.16} = \$\hspace{0.15cm}48000[/tex].

Therefore the sale price of the car is $48000.

Working together, two people can cut a large lawn in 4 hr. One person can do the job alone in 1 hr less than the other. How long would it take the faster person to do the job? the faster person would do the job alone in hours.

Answers

Answer:The faster person will do the job in 7.53hours

Step-by-step explanation:

Let t=faster person

Let t-1= the other person

The job to be done =1

Each person will do a fraction of the job

4/t+4/t-1=1

Multiply both sides wit t(t-1)

4(t+1)+4t=t(t-1)

4t+4+4t=t^2+t

8t+4=t^2+t

0=t^2+t-8t-4

t^2-7t-4=0

Use Almighty formular to solve d quadratic equation

X=-b+- rootb^2-4ac/2a

X=t,a=1,b=-7 c=4

Substituting the values you get:

t=-7 +- root 49+16/2

t=-7 +- root 65/2

t=7 +8.06/2=15.06/2

t=7.53 hours

1 question 60 points need help now
Solve the equation and show all your work
[tex]\frac{x}{x-2} + \frac{x-1}{x+1} =-1[/tex]

Answers

Answer:

The answer to your question is  x = 0 and x = 1

Step-by-step explanation:

Equation

                       [tex]\frac{x}{x - 2} + \frac{x - 1}{x + 1} = -1[/tex]

1)

                      [tex]\frac{x(x + 1) + (x - 2)(x - 1)}{(x - 2)(x + 1)} = - 1[/tex]

Expand

2)                  x² + x + x² - x - 2x + 2 = -1(x - 2)(x + 1)

Simplify

3)                  2x² -2x + 2 = -1(x² + x - 2x - 2)

4)                  2x² - 2x + 2 = -x² + x + 2

Equal to zero

5)                  2x² - 2x + 2 + x² - x - 2 = 0

6)                  3x² - 3x = 0

Factor

7)                  3x(x - 1) = 0

8)                  3x₁ = 0                   x₂ - 1 = 0

9)                    x₁ = 0/3                x₂ = 1

10)                  x₁ = 0                    x₂ = 1

Evaluate the expression x^3 - (3 + x)^2x 3 −(3+x) 2 x, cubed, minus, left parenthesis, 3, plus, x, right parenthesis, squared for x=4x=4x, equals, 4.

Answers

Answer:

  15

Step-by-step explanation:

Put the given value of x where x is in the expression and do the arithmetic.

  4^3 -(3 +4)^2 = 64 -49 = 15

The value of the expression for x=4 is 15.

Final answer:

The expression x³ - (3 + x)² for x = 4 simplifies to 64 - 49, resulting in a final answer of 15.

Explanation:

The student has asked to evaluate the expression x³ - (3 + x)² for x = 4. To do this, we will substitute x with 4 and simplify the expression step by step. First, calculate the value inside the parentheses: (3 + 4) = 7. Then, we square this value to get 7² = 49. After that, subtract the squared value from 4³ (which is 64), to get the final answer.

The final answer is 15

help in anyway in this ixl

Answers

Answer:

Step-by-step explanation:

Triangle ABC is a right angle triangle.

From the given right angle triangle shown,

AB represents the hypotenuse of the right angle triangle.

With 45 degrees as the reference angle,

AC represents the adjacent side of the right angle triangle.

BC represents the opposite side of the right angle triangle.

To determine QR, we would apply trigonometric ratio

Sin θ = opposite side/hypotenuse side. Therefore,

Sin 45 = BC/6√2

√2/2 = BC/6√2

BC = √2/2 × 6√2

BC = 6

Tiwa spent 1 1/2 hours setting up her computer. It took her 3 times as long to install the software. How long did it take Tiwa to set up the computer and install the software

Answers

Answer:

Total time spent by Tiwa to set up the computer and install software = 6 hours

Step-by-step explanation:

Given:

Time spent by Tiwa to set up  her computer = [tex]1\frac{1}{2}\ hours[/tex]

Time spent to install the software is 3 times the time she took to set up the computer.

To find the total time Tiwa took to set up her computer and install the software.

Solution:

Time spent by Tiwa to install the software can be given as:

[tex]3\times 1\frac{1}{2} \ hours[/tex]

In order to multiply mixed numbers we first change them to fractions.

We multiply the denominator to the whole number and add the numerator to it. Then we write the number as numerator of a fraction with the same denominator.

So, [tex]1\frac{1}{2}=\frac{3}{2}[/tex]

So, we have:

⇒ [tex]3\times \frac{3}{2}\ hours[/tex]

⇒ [tex]\frac{9}{2}\ hours[/tex]

Total time spent by Tiwa to set up the computer and install software can be given as:

⇒ [tex]\frac{3}{2}\ hours+\frac{9}{2}\ hours[/tex]

Since denominators are same, so we simply add the numerators.

⇒ [tex]\frac{3+9}{2}\ hours[/tex]

⇒ [tex]\frac{12}{2}\ hours[/tex]

⇒ [tex]6\ hours[/tex]

What is the slope of the line through (-9,6)(−9,6)(, minus, 9, comma, 6, )and (-3,9)(−3,9)(, minus, 3, comma, 9, )?

Answers

Answer:

0.5

Step-by-step explanation:

The slope m of a linear equation y = mx + b that goes through point (-9,6) and point (-3, 9) would have the following formula

[tex]m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{9 - 6}{-3 - (-9)} = \frac{3}{6}= \frac{1}{2}[/tex] or 0.5

Where [tex](x_1,y_1), (x_2, y_2)[/tex] are the coordinates of the 2 points that this line goes through


Players in any sport who are having great​ seasons, turning in performances that are much better than anyone might have​anticipated, often are pictured on the cover of Sports Illustrated.​ Frequently, their performances then falter​somewhat, leading some athletes to believe in a​ "Sports Illustrated​ jinx." Similarly, it is common for phenomenal rookies to have less stellar second​ seasons, the​ so-called "sophomore​ slump." While​ fans, athletes, and analysts have proposed many theories about what leads to such​ declines, a statistician might offer a simpler​(statistical) explanation. Explain.

What would be a better explanation for the decrease in performance of the Sports Illustrated cover​ athlete?

A. People on the cover are usually there for outstanding performances. Because they are so far from the​ mean, the performance in the next year is likely to be closer to the mean.
B. The slope of the linear​ regression, predicting performance from years in the​ sport, must be negative because an​ athlete's performance always decreases over time. No matter how well an athlete performed one​ year, they must perform worse the next year.
C. People on the cover are usually considered the best of the​year, so naturally they reached the maximum level of athletic performance that year and it is impossible to improve upon that.
D. Once an athlete has made the cover of Sports​ Illustrated, they have reached their ultimate goal as an athlete and lack motivation to try the following year.

Answers

Answer:

I pick the reasoning of option A

Step-by-step explanation:

I like the reasoning given in B, however, there are many cases of Athletes that, after reaching the top, maintain supremacy and improve over the years, adapting to their old age. Usually speed and physical resistance are replaced by technique and experience in the case of the top athletes.

I dont like C and D argument too much because being the best in a sport doesnt mean either that you reach the maximum level possible (in many cases you can keep growing) or that you dont have more motivations. Many athletes are super competitive people and they try to improve themselves all the time to reach, and stay, in the top.

I choose option A as answer because people on the cover doesnt neccesarily mean that they are the absolute best. Their performance was way better than their usual performance, and that may be due to either real skill growth, heavy training or a lucky streak. If it is a lucky streak, it is natural for that player's performance to go down into more terrenal levels for him. On the other hand, If he trained heavily, then he might have big injuries on later seasons and his performance wont be able to keep up for long. Thats why 'surprises' (that also sell better due to be a novelty) tend to go downhill after they reach the cover of sports illustrated.

Final answer:

The decrease in performance after an athlete's phenomenal season could be due to a statistical phenomenon called regression to the mean. This principle suggests that if a variable (e.g., athletic performance) is extreme on its first measurement, it will tend to be closer to the average on its subsequent measurement, which could explain why some athletes have less stunning seasons after achieving outstanding performances.

Explanation:

A better explanation for the decrease in performance of the Sports Illustrated cover athlete could be option A. People on the cover are usually highlighted for their outstanding performances, which are far from the mean. Due to a phenomenon called regression to the mean, it is likely that their performance in the next season would be closer to the mean (average).

Regression to the mean is a statistical concept that suggests that if a variable is extreme on its first measurement, it will tend to be closer to the average on its second measurement, and vice-versa.

This has nothing to do with a jinx, but rather with the statistical principle that performances, both good and bad, tend to cluster around the mean over time. So, outstanding performance is often followed by less exceptional performance, not necessarily because the player got worse, but because the original performance was likely above their true average.

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In a mid-size company, the distribution of the number of phone calls answered each day by each of the 12 receptionists is bell-shaped and has a mean of 37 and a standard deviation of 9. Using the empirical rule (as presented in the book), what is the approximate percentage of daily phone calls numbering between 28 and 46?

Answers

Answer:

0.6826

Step-by-step explanation:

Mean(μ) = 37

Standard deviation (σ) = 9

P(28 < x < 46) = ???

Using normal distribution

Z = (x - μ)/σ

For x = 28

Z = (28 - 37)/9

Z = -9/9

Z = -1

For x = 46

Z = (46 - 37)/9

Z = 9/9

Z = 1

We now have

P(-1 < Z < 1)

= P(Z < 1) - P(Z < -1)

From the table, Z = 1 = 0.3413

φ(Z) = 0.3413

Recall that

When Z is positive, P(x<a) = 0.5 +φ(Z)

P(Z<1)= 0.5 + 0.3413

= 0.8413

When Z is negative, P(x<a) = 0.5 - φ(Z)

P(Z< -1)= 0.5 - 0.3413

= 0.1587

We now have

0.8413 - 0.1587

= 0.6826

Jeff wants to know how many miles it is from his house to school. On a map, the scale is 0.5 inches=2 miles. If his house island school are 3 inches apart on the map, how many miles is it to the school?

Answers

It is 12 miles from house to school

Solution:

Given that, Jeff wants to know how many miles it is from his house to school

On a map, the scale is 0.5 inches = 2 miles

His house island school are 3 inches apart on the map

So, from the given scale,

0.5 inches = 2 miles

Distance between school and house in map = 3 inches

Therefore,

0.5 inches = 2 miles

Muliply both sides by 6

[tex]0.5 \times 6\ inches = 6 \times 2\ miles\\\\3\ inches = 12\ miles[/tex]

Thus, it is 12 miles from house to school

A stadium has 10500 seats and 8 VIP boxes. The stadium is divided into 12 equal sections: 2 premium sections and 10 standard sections. A seat at the premium section costs $48 per game. A seat at the standard section costs $27 per game.

Answers

Answer:

1). 875 seats

2). 25 rows in each section

3). $8400

4). Saving of $360

5). 2105 tickets remained unsold

6). x = 16

Step-by-step explanation:

This question is incomplete; here is the complete question.

A stadium has 10,500 seats and 8 VIP boxes. The stadium is divided into 12 equal  sections: 2 premium sections and 10 standard sections. A seat at the premium section  costs $48 per game. A seat at the standard section costs $27 per game.

1. How many seats are there in each section?

2. If there are 35 seats in each row, how many rows are in each section?

3. If all the seats in the premium section are sold out for a game, how much will the  stadium get from those ticket sales?

4. There are 50 games in each season. A season pass costs $2,040. A season pass  holder can go to all the games and have a seat in the premium section. How much can a fan save by buying the season pass?

5. For the night game on Tuesday, 8,395 tickets were sold. How many tickets were  left?

6. Write an equation using “x” and then solve  the equation. Each VIP boxes can seat X  people. If all the seats and VIP boxes are  filled up, there are 10,628 audience in the stadium.

1). Number of seats in the stadium = 10500

Number of sections = 2 premium + 10 standard = 12

Number of seats in each section = [tex]\frac{10500}{12}=875[/tex]

2). If the number of seats in each row = 35

Then number of rows in each section = [tex]\frac{875}{35}=25[/tex]

3). Number of seats in 2 premium sections = 2×875 = 1750

Cost of 1750 seats at the rate of $48 per game = 1750 × 48 = $84000

4). Cost of one ticket in premium section = $48 per game

If the games planned in one season = 50

Then cost of the tickets = 48×50 = $2400

Cost of the season ticket = $2040

Saving on the purchase of one season ticket = 2400 - 2040 = $360

5). For a night game number of tickets sold = 8395

Total number of seats in the stadium = 10500

Tickets remained unsold = 10500 - 8395 = 2105

6). Number of seats in each VIP box = x

Number of VIP boxes = 8

Number of seats in 8 VIP boxes = 8x

Total number of tickets sold = 10500 + 8x

Total number of audience in the stadium = 10628

Then the equation will be

8x + 10500 = 10628

8x = 10628 - 10500

x = [tex]\frac{128}{8}=16[/tex]

Final answer:

The subject of this question is Mathematics, specifically dealing with seating capacity and pricing in a stadium. To determine the maximum seating capacity of the stadium, add up the number of seats in each section. To calculate the total revenue from a single game, multiply the number of seats in each section by the corresponding ticket price, and then sum up the results.

Explanation:

The subject of this question is Mathematics, specifically dealing with the concepts of seating capacity and pricing in a stadium.

To determine the maximum seating capacity of the stadium, we add up the number of seats in each section: 2 premium sections with 48 seats each, 10 standard sections with 900 seats each, and 8 VIP boxes with a capacity of 12 seats each. This gives us a total of 1116 seats.

To calculate the total revenue from a single game, we multiply the number of seats in each section by the corresponding ticket price, and then sum up the results. For the premium sections, the revenue is $48 per seat multiplied by 96 seats, and for the standard sections, the revenue is $27 per seat multiplied by 900 seats. Adding up these two amounts gives us the total revenue from a single game.

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A typical marathon has 26.2 miles. allan makes an average of 12 kilometers per hour when running marathons. Determine how long it would take allan to complete a marathon at the nearest tenth of an hour.

Answers

Answer:

3hr 31mins

Step-by-step explanation:

First we convert miles to kilometers

1 miles to km = 1.60934 km

26.2 miles = 26.2 x 1.60934 = 42.164708

A typical marathon approx = 42.165km

If our runner covers 12 km = 1 hr

then he'll cover 42.165km = 42.165/12 = 3.5137 hrs

= 3 hrs + (0.514 * 60 mins) = 3hrs + (30.84mins)

Allan going at that speed would complete the marathon in appox = 3hrs : 31mins.

Answer:

2.34m2

Step-by-step explanation:

boom

Jacob and Ali want to run from one corner of a football field to the opposite corner. The rectangular football field is 50 yards wide and 120 yards long. Jacob runs around the perimeter of the field, while Ali runs in a straight line through the middle of the field. How many more yards does Jacob run than Ali?

Answers

Answer:

Jacob ran 40 yards more than Ali.

Step-by-step explanation:

Football field is in the shape of a rectangle having dimensions 120 yards × 50 yards

Since Jacob runs around the perimeter of the field from one corner to other corner, therefore, distance run by Jacob = [tex](\text{Length+width})[/tex]

Distance run by Jacob = 50 + 120 = 170 yards

Ali runs through the middle of the field diagonally on a straight line.

Therefore, distance covered by Ali = [tex]\sqrt{\text{length}^{2}+\text{width}^{2}}[/tex]

= [tex]\sqrt{(50)^{2}+(120)^{2}}[/tex]

= [tex]\sqrt{2500+14400}[/tex]

= [tex]\sqrt{16900}[/tex]

= 130 yards

Now difference between the distance covered by Jacob and Ali

= 170 - 130

= 40 yards

Therefore, Jacob ran 40 yards more than Ali.

what is the value of x? pls help!

Answers

Answer:The procedure to use the find the value of x calculator is as follows:

Step 1: Enter the values in the divisor and the product field

Step 2: Now click the button “Solve” to get the output

Step 3: The dividend or the x value will be displayed in the output field

Step-by-step explanation: In algebra, it is easy to find the third value when two values are given. Generally, the algebraic expression should be any one of the forms such as addition, subtraction, multiplication, and division. To find the value of x, bring the variable to the left side and bring all the remaining values to the right side. Simplify the values to find the result.

Pablo wishes to grow his baseball card collection to at least 3000 cards. He currently has 1200 and his favorite type of cards have 15 cards per package which inequality and solution represent the number of packages of cards that pablo wishes to buy , select all that apply

Answers

Answer:

x ≥ 120

Step-by-step explanation:

i) Let x be the number of packages of cards

ii) we know that Pablo currently has 1200 cards.

iii) Therefore the equation required is

15x + 1200 ≥ 3000 because we know that there are 15 cards in a package and the greater than equal to sign is used because Pablo has to collect at least 3000 cards

iv) Solving the equation we get

    15x + 1200 ≥ 3000

⇒  15x ≥ (3000 - 1200)

⇒ 15x ≥ 1800

⇒ x ≥ (1800 ÷ 15)

x ≥ 120

answer

x ≥ 120

Step-by-step explanation:

Step-by-step explanation:

i) Let x be the number of packages of cards

ii) we know that Pablo currently has 1200 cards.

iii) Therefore the equation required is

15x + 1200 ≥ 3000 because we know that there are 15 cards in a package and the greater than equal to sign is used because Pablo has to collect at least 3000 cards

iv) Solving the equation we get

   15x + 1200 ≥ 3000

⇒  15x ≥ (3000 - 1200)

⇒ 15x ≥ 1800

⇒ x ≥ (1800 ÷ 15)

∴ x ≥ 120

. Solve the equation. 3/7x + 5 = 8 1 2/7 7 7 2/7 –7

Answers

Answer:

x= −5621/201

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

3 /7x+5 =  812/7772/7-7

3 /7x+5=  1/67+−7

3 /7x+5=(  1/67+-7)(Combine Like Terms)

3 /7x+5=  −468 /67

3 /7x+5= −468/67

Step 2: Subtract 5 from both sides.

3 /7x+5−5=−468/67−5

3 /7x=−803/67

Step 3: Multiply both sides by 7/3.

(  7/3)*(3/7x)=(7/3)*(−803/67)

x= −5621/201

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