A hair dryer with a resistance of 9.6 ohms operates at 120 volts for 2.5 minutes. The total electrical energy used by the dryer during this time interval is

Answers

Answer 1

Answer:

[tex]2.25\cdot 10^5 J[/tex]

Explanation:

First of all, we have to find the power used by the hair dryer, which is given by

[tex]P=\frac{V^2}{R}[/tex]

where

V = 120 V is the voltage

[tex]R=9.6 \Omega[/tex] is the resistance of the hair dryer

Substituting,

[tex]P=\frac{(120 V)^2}{9.6 \Omega}=1500 W[/tex]

Now we can find the total electrical energy used, given by

[tex]E=Pt[/tex]

where P is the power and

t = 2.5 min = 150 s is the time

Substituting,

[tex]E=(1500 W)(150 s)=2.25\cdot 10^5 J[/tex]


Related Questions

The minimum energy required for an effective collision is called

Answers

Answer:

Activation Energy

Explanation:

Effective collisions are those that result in a chemical reaction. In order to produce an effective collision, reactant particles must possess some minimum amount of energy. This energy, used to initiate the reaction, is called the activation energy.

Which property describes the amount of energy that flows past a given area per unit of time?
A.Intensity
B.Pitch
C.Speed
D.Wavelength

Answers

it is intensity. Option A

The visible light spectrum ranges between

Answers

Answer: 380 nm (violet-blue) and 780 nm (red)

Explanation:

The portion visible by the human eye of the electromagnetic spectrum is between 380 nm (violet-blue) and 780 nm (red) approximately.  

This part of the spectrum is located between ultraviolet light and infrared light.  

It should be noted that the fact only part of the whole electromagnetic spectrum is visible to humans is because the receptors in our eyes are only sensitive to these wavelengths.

Red goes in the first blank and violet goes in the second blank if you're using plato

The four inner planets of our solar system are

Answers

The four innermost planets in the Solar System (Mercury, Venus, Earth, and Mars)

The four inner planets of our solar system are Mercury, Venus, Earth, and Mars.

What is the solar system?

A solar system is a group of celestial bodies, which is constituted of stars, planets, asteroids, and so on.

here,
The four inner planets of our solar system, also known as the terrestrial planets, are,

Mercury: The closest planet to the Sun, and the smallest planet in our solar system.Venus: The second planet from the Sun, and the hottest planet in our solar system due to its thick atmosphere of carbon dioxide.Earth: The third planet from the Sun, and the only planet known to support life.Mars: The fourth planet from the Sun, often called the "Red Planet" due to its reddish appearance caused by iron oxide on its surface.

These four planets are called "terrestrial" because they are rocky and relatively small compared to the outer gas giants, such as Jupiter, Saturn, Uranus, and Neptune. They are also closer to the Sun and have shorter orbital periods than the outer planets.

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Crime scene investigators find that a car hit the ground 60m from the point where it left the cliff. The cliff is 45 m high. Approximately what speed was the car going when it left the cliff (assume no air resistance)?

Answers

Answer:

20 m/s

Explanation:

In the y direction:

y = y₀ + v₀ᵧ t + ½ gt²

0 m = 45 m + (0 m/s) t + ½ (-9.8 m/s²) t²

t = 3.03 s

In the x direction:

x = x₀ + v₀ₓ t + ½ at²

60 m = 0 m + v (3.03 s) + ½ (0 m/s²) (3.03 s)²

v = 19.8 m/s

Rounded to one sig-fig, the car's velocity was approximately 20 m/s.

What happens to steam during condensation

Answers

Explanation:

Condensation is the process of changing the physical state of matter, from gas to liquid state. During condensation of matter, the physical state of the matter changes. Now in this question it is asked that what happens to the steam during the process of condensation. So steam is the matter, and during this process, steam converts its molecules from gaseous to the liquid state without heating. After this process, the steam is converted back to its liquid state. The liquid now take less space than that of the gas and exert less pressure on the walls of the container.

what is the magnification of a virtual image if the image is 10.0 cm....

Answers

Answer:

5.0

Explanation:

because 50.0 / 10.0 equals 5

Which of the following statements are true concerning a stable nucleus?Check all that apply..There is a limit to the size of a stable nucleus because of the short range of the strong nuclear force.A stable nucleus contains a larger number of neutrons than protons.There is no limit to the size of a stable nucleus because of the great strength of the strong nuclear force.A stable nucleus contains nearly equal numbers of protons and neutrons.A stable nucleus contains a larger number of protons than neutrons.

Answers

Answer:

There is a limit to the size of a stable nucleus because of the short range of the strong nuclear force

A stable nucleus contains nearly equal numbers of protons and neutrons

Explanation:

For an atom nucleus to be stable it has to have a balance between the strong nuclear forces keeping the protons and neutrons together against the repulsive electrostatic forces of the positively charged protons. When the nucleus is too large, the binding energy of the strong nuclear forces, that act over a short range,  may not be sufficient to hold the nucleus together hence causing instability.

Light amplification by stimulated emission of radiation is the full meaning of the acronym _________

Answers

Answer: LASER (Light Amplification by Stimulated Emission of Radiation)

A laser is a device that works by the principles of optics that emits a monochromatic light beam (of a single wavelength), coherent and with high intensity. Being this possible thanks to the electrical or thermal stimulation of  atoms of a specific material and, on which the color of the emitted light will depend.

Basically, this instrument concentrates the light in a narrow beam and emits it in a concentrated and coherent form.

A typical american family uses 1000 kwh of electricity a month. what is the average rrns current in the 120 v power line to a typical house?

Answers

Power = (1000 kilo-Watt-hr/mo) x (1000/kilo) x (mo/30day) x (day/24 hr)

Power = (1000 x 1000 / 30 x 24) (kilo-watt-hr-mo-day/mo-kilo-day-hr)

Power = (1,000,000/720) watt

(voltage x current) = (1,000,000/720) watts

120v x current = (1,000,000/720) watts

Current =  1,000,000 / (720 x 120) Amperes

Current = 11.57 Amperes

Final answer:

The typical American home draws around an average effective (RMS) current of 11.58 amps from a 120 V power line.

Explanation:

The average current in the power line of a typical American house can be calculated using Ohm's law and the power equation. If a typical American family uses 1000 kWh per month, we need to convert this to average power in kW, which gives (1000 kWh) / (30 days*24 hours) = 1.39 kW = 1390 W.

Given that the voltage is 120 V, we can use the formula: P = IV, rearranging to find I = P/V. Therefore, I = 1390 W / 120 V = 11.58 A.

This means the power to a standard American home running at typical usage rates should draw an average effective(RMS) current of around 11.58 amps from a 120 V power line.

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Which shows the correct order of events after the big bang occurred? strong force separated from the unified force, inflationary expansion occurred, quarks and electrons formed, electromagnetic and weak forces separated from the unified force, gravity separated from the unified force electromagnetic and weak forces separated from the unified force, gravity separated from the unified force, strong force separated from the unified force, inflationary expansion occurred, quarks and electrons formed gravity separated from the unified force, strong force separated from the unified force, inflationary expansion occurred, electromagnetic and weak forces separated from the unified force, quarks and electrons formed quarks and electrons formed, electromagnetic and weak forces separated from the unified force, inflationary expansion occurred, strong force separated from the unified force, gravity separated from the unified force

Answers

Answer:

C) gravity separated from the unified force, strong force separated from the unified force, inflationary expansion occurred, electromagnetic and weak forces separated from the unified force, quarks and electrons formed

Gravity separated from the unified force, strong force separated from the unified force, inflationary expansion occurred, electromagnetic and weak forces separated from the unified force, quarks and electrons formed.

What is big bang theory?

The big bang theory is a scientific theory that tries to explain the existence of the universe from the earliest known periods through small to large evolution.

In the first moments after the Big Bang, the universe was extremely hot and dense, and matter was formed as the universe cooled.

The formation of the matter is as a result of the following forces;

Gravity separated from the unified force, Strong force separated from the unified force, Inflationary expansion occurred, Electromagnetic and weak forces separated from the unified forceQuarks and electrons formed

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A hockey puck is set in motion across a frozen pond. If ice friction and air resistance are neglected, the force
required to keep the puck sliding at constant velocity is
A) the weight of the puck divided by the mass of the puck.
B) the mass of the puck multiplied by 9.8 meters per second per second.
C) qual to the weight of the puck.
D) zero newtons.
E) none of these.

Answers

Answer:

D) Zero newtons

Explanation:

According to the First Newton Law:

"An object keeps its state of rest or its state of uniform motion at constant velocity, when the net force acting on the object is zero"

In this problem, the hockey puck is initially set in motion. While in motion, there are no ice friction and air resistance acting on it: this means that the net force acting on it is zero, so there is no need for an additional force to keep the puck in its state of uniform motion at constant velocity, according to the abovementioned law.

Therefore, the correct answer is

D) zero newtons

Final answer:

In line with Newton's First Law of Motion, the force required to keep a hockey puck sliding at constant velocity on a frictionless surface is zero newtons, because it moves at a constant velocity unless acted upon by an unbalanced force.

Explanation:

The answer is D) zero newtons. According to Newton's First Law of Motion, an object will continue to move at a constant velocity unless acted upon by an unbalanced force. When the hockey puck is in motion on a frictionless surface, it keeps moving at a steady velocity without the need for an additional force. The net force acting on the puck is zero. Thus, no extra force is required to maintain its constant velocity.

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A friend asks you how much pressure is in your car tires. You know that the tire manufacturer recommends 30 psi, but it's been a while since you've checked. You can't find a tire gauge in the car, but you do find the owner's manual and a ruler. Fortunately, you've just finished taking physics, so you tell your friend, "I don't know, but I can figure it out." From the owner's manual you find that the car's mass is 1550 kg. It seems reasonable to assume that each tire supports one-fourth of the weight. With the ruler you find that the tires are 16 cm wide and the flattened segment of the tire in contact with the road is 14 cm long. What answer will you give your friend?

Answers

Answer:

25 psi

Explanation:

The weight of the car is:

W = mg

W = 1550 kg * 9.8 m/s²

W = 15,190 N

Divided by 4 tires, each tire supports:

F = W/4

F = 15,190 N / 4

F = 3797.5 N

Pressure is force divided by area, so:

P = F / A

P = (3797.5 N) / (0.16 m × 0.14 m)

P ≈ 170,000 Pa

101,325 Pa is the same as 14.7 psi, so:

P ≈ 170,000 Pa × (14.7 psi / 101,325 Pa)

P ≈ 25 psi

The pressure in each tire is ≈ 25 psi which falls within the recommended manufacturer pressure

Given data ;

mass of car ( m ) = 1550 kg

width of tires ( w ) = 16 cm = 0.16 m

length of tires ( l ) = 14 cm = 0.14 m

First step : Determine the Total weight of car

W = m*g  ---- ( 1 )

   = 1550 * 9.8 = 15,190 N

Weight supported by each tire = ( W / 4 )

= 15,190 / 4 = 3797.5 N

Final step : determine the Pressure in the tires

P = F / A  -------- ( 2 )

F ( force ) = 3797.5 N

A ( area ) =  0.14 * 0.16 = 0.0224

back to equation ( 2 )

P = 3797.5 / 0.0224  

    170,000 Pa

Pressure in each tire ≈ 25 psi

Hence we can conclude that the pressure in each tire is ≈ 25 psi.

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What is an elastic collision?

Answers

Answer:

A collision in which both total momentum and total kinetic energy are conserved

Explanation:

In classical physics, we have two types of collisions:

- Elastic collision: elastic collision is a collision in which both the total momentum of the objects involved and the total kinetic energy of the objects involved are conserved

- Inelastic collision: in an inelastic collision, the total momentum of the objects involved is conserved, while the total kinetic energy is not. In this type of collisions, part of the total kinetic energy is converted into heat or other forms of energy due to the presence of frictional forces. When the objects stick together after the collision, the collisions is called 'perfectly inelastic collision'

An elastic collision is where the total kinetic energy and total momentum before and after the collision are conserved. These collisions occur without permanent deformation or energy loss in other forms. This concept is important in physics, particularly in one-dimensional collisions involving atoms.

An elastic collision is a type of collision in which the total kinetic energy and total momentum of the system are conserved. This means that the kinetic energy before the collision is equal to the kinetic energy after the collision, and there is no permanent deformation of the objects involved or conversion into other energy forms like heat or sound. Elastic collisions are particularly relevant in atomic interactions, where collisions between atoms can often be considered elastic.

In one-dimensional collisions, conservation of kinetic energy and momentum allow us to calculate the final velocities of the colliding bodies using their initial velocities and their masses. A common example of nearly elastic collisions in a macroscopic context includes collisions of steel blocks on an icy surface or carts with spring bumpers on an air track, where friction is minimal.

What is the potential difference across a 15 Ω resistor that has a current of 3.0 A?

Answers

Answer:

45 V

Explanation:

Use Ohm's law:

V = IR

V = (3.0 A) (15 Ω)

V = 45 V

Answer:

45V

Explanation:

R=V/I

V=I/R

V=15ohms•3.0 A

V=45V

A student pushes a 35-kg block on a frictionless, horizontal surface with a force of 18 N. What is the acceleration of the block ?


A. 1.0m/sSquared

B. 1.4m/sSquared

C. 1.6m/sSquared

D. 1.9m/sSquared

Answers

Newton wrote . . . F = m a

From that, we can derive . . . a = F/m

a = (18 N) / (35 kg)

a = 0.514... m/s^2

None of the choices says this.

Choice-D is the reciprocal of the correct answer ... the result of doing the division backwards ... m/F .

An object of mass m is dropped from height h above a planet of mass M and radius R. Find an expression for the object's speed as it hits the ground. Express your answer in terms of the variables m, M, h, R and appropriate constants.

Answers

Answer:

v = √(2 MGh) / R

Explanation:

Assuming that h is much smaller than R, we can say the acceleration of gravity is approximately constant during the fall.

Potential energy = Kinetic energy

mgh = 1/2 mv²

v = √(2gh)

v = √(2 (MG/R²) h)

v = √(2 MGh) / R

In Millikan’s experiment, the oil droplets acquire one or more negative charges by combining with the negative charges that are produced from the ionization of air by X rays. By measuring the charges on the oil droplets, he calculated the charge on a single electron as −1.60×10−19 C. The charge on any negatively charged oil droplet is always a whole-number multiple of the fundamental charge of a single electron.If Millikan was measuring the charge on an oil droplet with 10 negatively charged electrons on it, what charge would he have measured on the droplet?

Answers

Answer:

[tex]-1.6\cdot 10^{-18}C[/tex]

Explanation:

The charge of a single electron is:

[tex]q=-1.6\cdot 10^{-19}C[/tex]

If the oil droplet has N electrons, the total charge of the droplet will be

[tex]Q=Nq[/tex]

In this case, we have

N = 10

Therefore, the total charge on the droplet is

[tex]Q=(10)(-1.6\cdot 10^{-19} C)=-1.6\cdot 10^{-18}C[/tex]

Final answer:

In Millikan's experiment, the charge on any negatively charged oil droplet is always a whole-number multiple of the fundamental charge of a single electron. If the oil droplet had 10 negatively charged electrons, Millikan would have measured a charge of [tex]-1.60x10^-18[/tex] let.

Explanation:

Millikan's experiment involved measuring the charges on oil droplets that acquire negative charges by combining with the negative charges produced from the ionization of air by X rays. Millikan found that the charge on any negatively charged oil droplet is always a whole-number multiple of the fundamental charge of a single electron, which is [tex]-1.60x10^-19[/tex]

If Millikan was measuring the charge on an oil droplet with 10 negatively charged electrons on it, he would have measured a charge of[tex]-1.60x10^-19[/tex] y 10, which is [tex]-1.60x10^-18[/tex]

What is the law of conservation of matter

Answers

Answer:

The law of conservation of matter (or mass), also known as the Law of Lomonosov-Lavoisier, states the following:

"In a chemical reaction the sum of the mass of the reactants is equal to the sum of the mass of the products."

Hence the famous phrase:

"The mass is not created or destroyed, it only transforms."

This was raised by the Russian scientist Mikhail Lomonosov in 1748 and independently discovered years later by the French chemist Antoine Lavoisier in 1785.

It should be noted that this principle is quite accurate for low-energy chemical reactions, but for nuclear reactions (collisions between particles at high energies), this classical definition does not apply (the total mass of the system does not have to be strictly conserved) and must be taken into account the equivalence between mass and energy that was postulated in Albert Einstein's theory of relativity:

 "The amount of mass-energy that manifests a certain space-time is constant throughout the universe."

Being this expressed mathematically by his famous equation where he relates the energy [tex]E[/tex] with the mass [tex]m[/tex] and the speed of light [tex]c[/tex]:

[tex]E=mc^{2} [/tex]

Answer:

Matter cannot be created or destroyed.

Explanation:

APEX

When Anna eats an apple, the sugars in that apple are broken down into the substance called glucose. Glucose is then burned in her body for energy. One of the body parts that needs this energy is the heart, which beats due to electrical impulses. A byproduct of this glucose breakdown is the heat that warms her body and is later released. Which identifies the energy transformations that take place in Anna’s body as this process takes place? Mechanical energy is converted to kinetic energy, which is then converted to potential energy. Chemical energy is converted to thermal energy and electrical energy. Electrical energy is converted to chemical energy and thermal energy. Mechanical energy is converted to potential energy which is then converted to kinetic energy.

Answers

Answer:

Chemical energy is converted to thermal energy and electrical energy.

Explanation:

The sugar present in the apple is broken down into Glucose. This is chemical energy stored in the apple which is broken down into energy which is utilized by body for everyday works. The chemical energy gets converted to thermal energy which warms the body and electrical energy due to which the heart beats.

Answer:

Chemical energy is converted to thermal energy and electrical energy.

Explanation:

The small currents in axons corresponding to nerve impulses produce measurable magnetic fields. a typical axon carries a peak current of 0.040 μa. what is the strength of the field at a distance of 1.2 mm

Answers

Answer:

[tex]6.66\cdot 10^{-12}T[/tex]

Explanation:

The magnetic field produced by a current-carrying wire is given by

[tex]B=\frac{\mu_0 I}{2\pi r}[/tex]

where

[tex]\mu_0[/tex] is the vacuum permeability

I is the current

r is the distance from the wire

In this problem we have

[tex]I=0.040 \mu A=4\cdot 10^{-8}A[/tex]

r = 1.2 mm = 0.0012 m

So the magnetic field strength is

[tex]B=\frac{(4\pi \cdot 10^{-7} H/m)(4\cdot 10^{-8}A)}{2\pi (0.0012 m)}=6.66\cdot 10^{-12}T[/tex]

Planet that has an orbit that intersects the orbit of pluto

Answers

Answer:

Neptune

Explanation:

"Answer: Pluto is usually farthest from the Sun. However, its orbit "crosses" inside of Neptune's orbit for 20 years out of every 248 years. Pluto last crossed inside Neptune's orbit on February 7, 1979, and temporarily became the 8th planet from the Sun. "

Source:https://starchild.gsfc.nasa.gov/docs/StarChild/questions/question5.html

Where is visible light located on the electromagnetic spectrum

Answers

Answer:

The portion visible by the human eye of the electromagnetic spectrum is between 380 nm (violet-blue) and 780 nm (red) approximately.

This part of the spectrum is located between ultraviolet light and infrared light.

It should be noted that the fact only part of the whole electromagnetic spectrum is visible to humans is because the receptors in our eyes are only sensitive to these wavelengths.

Answer:

near the middle

Explanation:

for gradpoint anyway

The atmosphere is made up of several layers of air. The bottom two layers are the troposphere and the stratosphere. How does the troposphere differ from the stratosphere?

Answers

Troposhere is differ from stratosphere by the following reason

1. all weather pheonamena take place in trosphere

2. in trosposphere temperature increase by increasing height which is just opposite in the case of stratosphere

3. the maximum air is found in trosposphere

Final answer:

The troposphere is the earthly atmospheric layer where weather and major atmospheric changes take place due to its high density and temperature that decreases with altitude. Above it sits the stratosphere, which contains the ozone layer, and exhibits a temperature inversion, stability, and a lack of weather phenomena.

Explanation:

Comparison of Troposphere and Stratosphere

The troposphere and stratosphere are the two lowest layers of the Earth's atmosphere. The troposphere is the bottommost layer, where nearly all weather occurs and which houses most of the atmospheric mass. This layer extends from sea level up to about 9 km at the poles and averages 12 km in thickness, reaching up to 17 km at the equator due to the Earth's rotation. The troposphere is characterized by a temperature that decreases with altitude, making it denser near the surface. By contrast, the stratosphere is the second layer that lies above the troposphere, stretching from approximately 12 km to 50 km above Earth's surface. It contains the ozone layer and is known for its temperature inversion, where temperature increases with altitude due to the absorption of ultraviolet radiation by ozone.

The most discernible difference between the troposphere and the stratosphere is the temperature gradient. In the troposphere, temperature generally decreases with altitude, while in the stratosphere, it increases with altitude due to the presence of the ozone layer which absorbs and scatters the Sun's ultraviolet light. This temperature inversion creates a stable layer that prevents convective currents, marking a clear boundary between these two atmospheric layers known as the tropopause.

The troposphere is significantly more turbulent and dynamic, housing all the weather systems and majority of the atmospheric water vapors. Meanwhile, the stratosphere maintains a more stable environment. The difference in density and temperature between the two layers is responsible for the distinctive weather phenomena and atmospheric conditions unique to each layer.

A roller coaster car rapidly picks up speed as it rolls down a slope. As it starts down the slope, its speed is 4m/s. But 3 seconds later at the bottom of the slope its speed is 22m/s. What is its average acceleration?

Answers

Answer:

6 m/s^2

Explanation:

The average acceleration of the car is given by:

[tex]a=\frac{v-u}{t}[/tex]

where

v is the final speed

u is the initial speed

t is the time elapsed

For the car in this problem,

v = 22 m/s

u = 4 m/s

t = 3 s

Therefore, the acceleration of the car is

[tex]a=\frac{22 m/s-4 m/s}{3 s}=6 m/s^2[/tex]

How many calories are required to raise the temperature of 105 g of water from 30.0°c to 70.0°c?

Answers

Answer: 4200 calories

Let's start by explaining that 1 Calorie ([tex]1 cal[/tex]) is defined as a unit of thermal energy that is equivalent to the amount of heat ([tex]Q[/tex]) needed to raise the temperature of 1 gram [tex]1g[/tex] of water by 1 degree Celsius [tex]1\°C[/tex].

The formula to calculate it is:

[tex]Q=m. c. \Delta T[/tex]   (1)

Where:

[tex]m[/tex]  is the mass

[tex]c[/tex]  is the specific heat of the element. In the case of water [tex]c=1cal/g[/tex]

[tex]\Delta T[/tex]  is the variation in temperature, which in this case is  [tex]\Delta T=70\°C-30\°C=40\°C[/tex]  

Rewriting equation (1) with the known values:

[tex]Q=(105g)(1 cal/g)(40\°C)[/tex]  

[tex]Q=4200 cal[/tex]  

You are driving your small, fuel-efficient car when you have a head-on collision with a big, fuel-efficient truck that is three times as massive as your car. Head-on means, for example that if you are traveling in the positive x direction, the truck is traveling in the negative x direction. Right before the collision, you were traveling at a speed of 3.0 m/s and right after the collision, both vehicles are at rest. Due to the conservation of the momentum, you can find the speed of the truck before the collision. What was the kinetic energy of the truck Ktruck before the collision when the kinetic energy of the car was Kcar

Answers

Explanation:

Momentum before = momentum after

mv + MV = 0

(m) (3.0 m/s) + (3m) (V) = 0

V = -1.0 m/s

The truck was moving at 1.0 m/s before the collision.

The kinetic energy of the car was:

KE = 1/2 m v²

Kcar = 1/2 m (3.0)²

Kcar = 9/2 m

Ktruck = 1/2 M V²

Ktruck = 1/2 (3m) (1.0)²

Ktruck = 3/2 m

Ktruck = 1/3 Kcar

So the truck had 1/3 the kinetic energy of the car.

A small planet having a radius of 1000 km exerts a gravitational force of 100 N on an object that is 500 km above its surface. If this object is moved 500 km farther from the planet, the gravitational force on it will be closest to :(A) 75 N(B) 71 N(C) 56 N(D) 50 N(E) 25 N

Answers

Answer:

56 N

Explanation:

Gravitational force on the object:

[tex]F = G\frac{Mm}{d^2}[/tex]

where, G is the gravitational constant, M is the mass of the planet and m is the mass of the object, d is the distance between the planet and the object.

[tex]F \times d^2= GMm\\ \Rightarrow GMm= (100)(1.5\times10^6)^2[/tex]

d'=d+500 km

[tex]F'=\frac{(100)(1.5\times10^6)^2}{(2\times10^6)^2} = 56.25N[/tex]

Thus, option (c) is correct.

Final answer:

The new gravitational force on the object, when moved 500km farther from the planet, will be closest to 56N. This result is calculated using inverse square law of gravity where the gravitational force decreases with the square of the increase in distance.

Explanation:

The physics concept at work here is the inverse square law of gravity, which states that the gravitational force between two objects decreases with the square of the distance between them. In mathematical terms, it is written as F = G*((m1*m2)/r^2), where F is the force of gravity, G is the gravitational constant, m1 and m2 are the masses of the two objects, and r is the distance between the centers of the two objects.

In this case, the radius of the planet is 1000 km and the object is 500 km above the surface of the planet, so the total distance (r) is 1500 km. When the object is moved 500 km farther, the new distance will be 2000 km or 4/3 times the original distance. This factor squared is 16/9, so the new gravitational force will be 9/16 of the original force. Therefore, the new gravitational force is 9/16 * 100 N = 56.25 N, so the closest choice is (C) 56 N.

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A 2.0-kg ball moving eastward at 3.0 m/s suddenly collides with and sticks to a 4.0-kg ball moving northward at 2.0 m/s. What is the magnitude of the momentum of this system just after the collision?

Answers

Answer:

10 kg m/s

Explanation:

Due to the law of conservation of momentum, the total momentum after the collision must be equal to the total momentum before the collision.

The momentum of each ball is given by:

p = mv

where m is the mass of the ball and v its velocity.

The momentum of ball 1 is:

p = mv = (2.0 kg)(3.0 m/s) = 6.0 kg m/s in the eastward direction

The momentum of ball 2 is:

p = mv = (4.0 kg)(2.0 m/s) = 8.0 kg m/s in the northward direction

The two momenta are in perpendicular directions, so the magnitude of the total momentum can be found as:

[tex]p=\sqrt{p_1^2 + p_2^2 }= \sqrt{(6.0 kg m/s)^2 + (8.0 kg m/s)^2}=10 kg m/s[/tex]

and due to the law of conservation of the momentum, this is also equal to the total momentum after the collision.

The magnitude of the momentum of this system just after the collision is about 10.0 kg.m/s

[tex]\texttt{ }[/tex]

Further explanation

Let's recall Impulse formula as follows:

[tex]\boxed {I = \Sigma F \times t}[/tex]

where:

I = impulse on the object ( kg m/s )

∑F = net force acting on object ( kg m /s² = Newton )

t = elapsed time ( s )

Let us now tackle the problem!

[tex]\texttt{ }[/tex]

Given:

mass of first ball = m₁ = 2.0 kg

velocity of first ball = v₁ = 3.0i m/s

mass of second ball = m₂ = 4.0 kg

velocity of second ball = v₂ = 2.0j m/s

Asked:

magnitude of the final momentum = p = ?

Solution:

We will use Conservation of Momentum formula to solve this problem:

[tex]\texttt{Total Momentum Before Collision = Total Momentum After Collision}[/tex]

[tex]m_1 v_1 + m_2 v_2 = \overrightarrow{p}[/tex]

[tex]2.0 ( 3.0\ \widehat{i} ) + 4.0 ( 2.0 \ \widehat{j} ) = \overrightarrow{p}[/tex]

[tex]\overrightarrow{p} = 6.0 \ \widehat{i} + 8.0 \ \widehat{j}[/tex]

[tex]|\overrightarrow{p}| = \sqrt{ 6.0^2 + 8.0^2 }[/tex]

[tex]|\overrightarrow{p}| = 10.0 \texttt{ kg.m/s}[/tex]

[tex]\texttt{ }[/tex]

Learn moreVelocity of Runner : https://brainly.com/question/3813437Kinetic Energy : https://brainly.com/question/692781Acceleration : https://brainly.com/question/2283922The Speed of Car : https://brainly.com/question/568302Average Speed of Plane : https://brainly.com/question/12826372Impulse : https://brainly.com/question/12855855Gravity : https://brainly.com/question/1724648

[tex]\texttt{ }[/tex]

Answer details

Grade: High School

Subject: Physics

Chapter: Dynamics

two cars collide at an intersection. one car has a mass of 900 kg and is moving 10 m/s to the north, while the other has a mass of 1000 kg and is moving 7 m/s to the south. what is their combined momentum?

Answers

Answer:

2000 kgm/s to the north.  

Explanation:

For any   colliding bodies, momentum must be conserved.

In this case we are required to find the momentum before collision.

Since the two cars are moving to different direction, we are going to take one velocity as negative.

∴ (900×10) + (1000× -7) = 9000 + - 7000

                                       = 9000 - 7000

                                       = 2000 kgm/s

Since the answer is positive and we had taken the velocity due north as positive, the combined momentum is 2000 kgm/s to the north.  

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