Final answer:
The speed of sound in the metal is 444.44 m/s.
Explanation:
To determine the speed of sound in the metal, we can use the information given and the speed of sound in air. The pulse traveling through the metal arrives 9ms earlier than the pulse traveling through air. From this, we can calculate the time difference it takes for the pulses to travel through the length of the metal bar. The speed of sound in air is given as 343 m/s. We can use the formula: speed = distance/time. Rearranging the formula, we have: time = distance/speed. As the distance is given as 4.00 m and the time difference is given as 9 ms (0.009 s), we can calculate the speed of sound in the metal by dividing the distance by the time difference: speed = 4.00 m / 0.009 s = 444.44 m/s.
When flying the LNAV approach, the missed approach point (MAP) would be indicated by reaching __________. A. an altitude of 3100 feet.B. a distance of 1.5 NM to RW30.C. the RW30 waypoint.
Answer:
When flying the LNAV Approach, the missed approach point (MAP) would be indicated by reaching:
C. the RW30 waypoint.
Explanation:
In Aviation, LNAV stands for Lateral Navigation. The option a is incorrect as an altitude of 3100 feet refers to the decision altitude not the missed approach point.The option b is incorrect as a distance of 1.5 NM to RW30 referring to the Visual descent point (VDP) is 1.5 nautical miles for the Runway (RW) 30 from threshold.The option c is correct as Missed approach point is designed to coincide with the runway threshold. The RW 30 way point is referring to the way point to the threshold for the Runway 30.The missed approach point (MAP) during an LNAV approach is indicated by reaching the RW30 waypoint.
When flying the LNAV approach, the missed approach point (MAP) would be indicated by reaching the RW30 waypoint. During an LNAV approach, which is a type of non-precision instrument approach procedure, pilots use lateral navigation to align with the runway. The MAP is typically defined by a waypoint and not by reaching a particular altitude or distance to the runway. Unlike precision approaches that can bring an aircraft to a lower minimum descent altitude or decision height based on a glideslope, LNAV approaches only provide lateral guidance and rely on predetermined waypoints to establish the MAP.
What is the displacement current in the capacitor if the potential difference across the capacitor is increasing at 500
Answer:
I = 1.21x10^-5 A
Explanation:
You are missing the first part of the problem. This is an example, but it will give you the idea of how to solve yours with your data.
The first part is like this:
A 4.0 cm diameter parallel plate capacitor has a 0.44 m m gap. What is the displacement current in the capacitor if the potential difference across the capacitor is increasing at 500,000 V/s?
Now with this, we can solve the problem.
In order to do this, we need to use the following expression:
q = CV (1)
Where:
C: Capacitance of a parellel capacitor (in Faraday)
q: charge of plate or capacitor (In coulombs)
V: voltage in Volts.
However, we need is the current, and we have data of potential difference, so, all we have to do is divide the expression between time so:
q/t = CV/t
And the current is q/t, thus:
I = C * V/t (2)
And finally, Capacitance C with two plates of area A separated by a distance d is:
C = Eo*A/d (3)
Where:
Eo = constant equals to 8.85x10^-12 F/m.
A = Area of the plate, in this case, πr²
d = gap of the capacitor.
Let's calculate first the Capacitance using equation (3):
C = 8.85x10^-12 * π * (0.04/2)² / 0.00046 = 2.42x10^-11 F
Now, it's time to use equation (2) and solve for I:
I = 2.42x10^-11 * 500,000
I = 1.21x10^-5 A
How far will it go, given that the coefficient of kinetic friction is 0.10 and the push imparts an initial speed of 3.9 m/s ?
The question is asking for the distance an object will travel given its initial speed and a coefficient of friction. However, without knowing the object's mass, we cannot calculate the exact distance.
Explanation:The question is asking you to calculate the distance an object will travel, given an initial speed and friction. This is a physics problem that can be solved using the principles of friction and kinetic energy.
Since we know the coefficient of kinetic friction (μk) and initial speed (v), we can calculate the distance travelled. The frictional force is equal to μk * m * g, where m is the mass of the object and g is the gravity. However, we do not have the mass of the object.
As we have incomplete information provided in the question, we cannot calculate the exact distance travelled. The chapter references given also do not give us the necessary information to solve the problem. With full information, we would use the formula relating kinetic energy to work done by friction to find the distance:
1/2 * m * v² = μk * m * g * d, which simplifies to d = v² / (2 * g * μk)
Learn more about Kinetic Friction here:https://brainly.com/question/36370309
#SPJ12
Electrolytes are considered ________ when placed in a solution and allow for adequate conduction of ________ charges.
Answer:
Electrolytes are considered ions when placed in a solution and allow for adequate conduction of particle charges.
Explanation:
Electrolytes are substances that, when are dissolved in solution, separates into electrical positive charges (cations) and electrical negative charges (anions) which are known as ions.
These ions have an adequate capacity to conduct particle charges and, therefore electricity.
Sodium, calcium, phosphate and potassium, are examples of electrolytes.
Hence, the correct answer is:
Electrolytes are considered ions when placed in a solution and allow for adequate conduction of particle charges.
I hope it helps you!
Technician A says that a MAF sensor is a high-authority sensor and is responsible for determining the fuel needs of the engine based on the measured amount of air entering the engine. Technician B says that a cold wire MAF sensor uses the electronics in the sensor itself to heat a wire 20°C below the temperature of the air entering the engine. Who is right?
A) Technician A
B) Technician B
C) Both technicians
D) Neither technician
Answer:
a. Technician A
Explanation:
Technician A says that a MAF sensor is a high-authority sensor and is responsible for determining the fuel needs of the engine based on the measured amount of air entering the engine. Technician B says that a cold wire MAF sensor uses the electronics in the sensor itself to heat a wire 20°C below the temperature of the air entering the engine. Who is right
MAF wich stands for mass airflow sensor determines the mass of air flowing into the engine's air intake system. ... , the wire cools When air flows past the wire, decreasing its resistance, thereby more current flows through the circuit. When the MAf goes bad, it can not sense the amount of air intake into the engine.
A student is asked to determine the work done on a block of wood when the block is pulled horizontally using an attached string. The student is supplied with a spring scale, a stopwatch, and a meterstick. Which of the following graphical analysis techniques will allow the student to determine the work done on the block by the string?
A. Graphing the force as a function of time and calculating the slope
B. Graphing the force as a function of time and calculating the area under the curve
C. Graphing the force as a function of distance and calculating the slope
D. Graphing the force as a function of distance and calculating the area under the curve
Answer:
D. Graphing the force as a function of distance and calculating the area under the curve.
Explanation:
Answer:
The correct option is (D). "Graphing the force as a function of distance and calculating the area under the curve"
Explanation:
1) As we know from the definition of Work done which is Work = Force × Displacement. Time doesn't have any use in the mentioned equation and thus the stop watch is of no use to us.
2) Using the meter stick, we can measure the distance for which the block is pulled horizontally i.e "Displacement"
3) Using the spring scale, we can calculate the "Force" applied on the block of wood to move it horizontally.
4) For example, lets say that for a constant force of 4 Newtons, the wooden block is pulled horizontally 4 meters. Plotting Force vs Displacement on a graph would yield a horizontal line as shown in the attachment. Area under the F vs D graph will give us the total work done.
A 24 year old motorcycle driver would not be required to wear protective eyewear when riding in Florida.
A) True
B) False
Answer:
False
Explanation:
A 24 year old motorcycle driver would not be required to wear protective eyewear when riding in Florida,This is a False statement.
The law is all riders would have to wear protective eyewear when riding in Florida.
The force of friction on a sliding object is 10 N. The applied force needed to maintain a constant velocity is
A) more than 10 N.
B) less than 10 N.
C) 10 N
Answer:C. 10N
Explanation:
The applied force needed to maintain a constant velocity is 10N. This is because the moving force acting on the body will always be equal to the frictional force if the velocity of the body is constant.
But note that this is not the case if the body ia accelerating. If the body is accelerating then the frictional force will not be able to overcome the moving force acting on the body and such the moving force will be greater than the frictional force in that regards.
The applied force needed to maintain a constant velocity is 10 N.
The given parameters;
frictional force on the object, Fk = 10 NThe net horizontal force on the object is calculated by applying Newton's second law of motion as shown below;
∑F = ma
[tex]F- F_k = ma[/tex]
where;
F is the applied force on the objectm is the mass of the objecta is the acceleration of the objectAt constant velocity, the acceleration of the object is zero.
[tex]F-F_k = m(0)\\\\F-F_k = 0\\\\F= F_k\\\\F = 10 \ N[/tex]
Thus, the applied force needed to maintain a constant velocity is 10 N.
Learn more here:https://brainly.com/question/21684583
Pedestrians, bicyclists and slow-moving vehicles are not allowed on expressways because expressways have minimum speed limit requirements that these travelers cannot reach.
A. True
B. False
Answer:
TRUE
Explanation:
It is TRUE that pedestrians, bicyclists and slow-moving vehicles are not allowed on expressways because expressways have minimum speed limit requirements that these travelers cannot reach. This minimum limit of speed varies country to country.
In America, the minimum speed limit in Rural Areas is 40 mph (miles per hour) i.e. 65km/h (kilometer per hour) while in Urban Areas it is 55mph i.e. 90km/h which cannot be met by pedestrians and by-cycles easily.
A spherical object (with non-uniform density) of mass 16 kg and radius 0.22 m rolls along a horizontal surface at a constant linear speed without slipping. The moment of inertia of the object about a diameter is 0.59 M R2 . The object’s rotational kinetic energy about its own center is what fraction of the object’s total kinetic energy
Final answer:
The question pertains to the rotational kinetic energy of a rolling spherical object with non-uniform density and how it compares to the total kinetic energy using its moment of inertia.
Explanation:
The student is asking about the rotational kinetic energy of a spherical object with non-uniform density in comparison to its total kinetic energy. The given moment of inertia for the object is 0.59 M R2, where M is the mass, and R is the radius of the sphere. Using the formula for rotational kinetic energy, Krot = (1/2) I ω2, and the formula for translational kinetic energy, Ktrans = (1/2) m v2, we can find the energy components. However, because the spherical object rolls without slipping, there is a relationship between linear velocity (v) and angular velocity (ω) which is v = ωR. This allows us to compare the rotational kinetic energy to the total kinetic energy.
A pump is required to lift 800 kg of water per minute from a well 14.6 m deep and eject it with a speed of 18.2 m/s..
a. How much work is done per minute in lifting the water?b. How much in giving the water the kinetic energy it has when ejected?K =?c. What must be the power output of the pump?
Answer:
a)W = 116800 J
b)KE=132496 J
c)P=4154.93 W
Explanation:
Given that
m= 800 kg/min
h= 14.6 m
v= 18.2 m/s
a)
Work done required ,W= m g h
h=height of the well
m=mass
W= 800 x 14.6 x 10 ( take g= 10 m/s²)
W = 116800 J
b)
kinetic energy = KE
[tex]KE=\dfrac{1}{2}mv^2[/tex]
m=mass
v=velocity
[tex]KE=\dfrac{1}{2}\times 800\times 18.2^2[/tex]
KE=132496 J
c)
Pump power given as
[tex]P=\dfrac{W'}{t}[/tex]
W'=Total work done
t=time
[tex]P=\dfrac{116800+132496}{60}[/tex]
P=4154.93 W
The work done per minute in lifting the water is 114,464 J. The kinetic energy given to the water when it is ejected is 132,488 J. The power output of the pump is 4116.2 W.
Explanation:The subject of this question is Physics, specifically the topic of work, energy, and power.
To calculate the work done in lifting the water, we can use the formula:
Work = Force × Distance
The force required to lift the water can be calculated using the formula:
Force = Mass × Gravity
(a) To find the work done per minute in lifting the water, we multiply the weight of the water by the height it is lifted. The weight of the water is mass times gravity, which is
Force =800 kg * 9.8 m/s^2 = 7840 N.
So, the work done is 7840 N * 14.6 m = 114,464 J.
(b) To find the kinetic energy given to the water when it is ejected, we use the formula for kinetic energy, which is 1/2 * mass * speed^2.
So, the kinetic energy = 1/2 * 800 kg * (18.2 m/s)^2
= 132,488 J.
(c) The power output of the pump is the total work done per minute divided by the time, which is
Power =(114,464 J + 132,488 J) / 60 s
= 4116.2 W.
Learn more about Work and Energy here:https://brainly.com/question/17290830
#SPJ3
Biologists think that some spiders "tune" strands of their web to give enhanced response at frequencies corresponding to those at which desirable prey might struggle. Orb spider web silk has a typical diameter of 20μm, and spider silk has a density of 1300 kg/m³.
To have a fundamental frequency at 150Hz , to what tension must a spider adjust a 14cm -long strand of silk?
Answer:
T=2.94*10^-10 N/m.
Explanation:
Biologists think that some spiders "tune" strands of their web to give enhanced response at frequencies corresponding to those at which desirable prey might struggle. Orb spider web silk has a typical diameter of 20μm, and spider silk has a density of 1300 kg/m³.
To have a fundamental frequency at 150Hz , to what tension must a spider adjust a 14cm -long strand of silk?
l=length of the spider silk, 14cm
velocity of wave = √(T/μ)
where T = tension and
μ = mass per unit length)
λ/2=l
for fundamental frequency λ/2 =14cm
(λ= wavelength of standing wave; as there will be no node
except the endpoints of silk strand)
λ = 28 cm = 0.28 m
and since frequency * wavelength = speed of wave. we have,
150 * 0.28 = √(T/μ) ..................(#)
now μ = mass/length = [volume * density]/length = [(length*area) * density] / length = area * density
= [π * (10 * 10^(-6))²] * 1300 = 13π * 10^(-8).
now putting this in equation (#) we get
150 * 0.28 = √(T/[13π * 10^(-8)]).
thus T = [13π * 10^(-8)] * (42)² =
2.94*10^-10 N/m.
As a result of the motion through the magnetic field, a charge in the rod will experience a force F⃗ =qv⃗ ×B⃗ : the usual part of the Lorentz force for charges moving through magnetic fields. This force will push the charge in the rod, and hence this force will be an electromotive force (EMF). For now, we shall say that the force that moves the charges is due to an induced electric field Einduced, which will enable us to calculate the EMF. The fact that there is an induced electric field at all is rather subtle, because there is no closed loop that encloses some changing flux. Therefore, a method that does not involve Faraday's law must be used to solve this motional EMF problem. In fact, this problem is a good introduction to some of the ideas behind Faraday's law. Find the y component of the induced electric field Einduced.
Based on the information given, it should be noted that the y component of the induced electric field will be E = -Bv.
An induced electric field simply means a nonconversative field that is generated due to a changing magnetic field.
The force that acts on the charge moving with the velocity is given. In this case, the component of the induced electric field will be E = -Bv.
Learn more about electric field on:
https://brainly.com/question/14372859
A 92.0-kg skydiver falls straight downward with an open parachute through a vertical height of 325 m. The skydiver's velocity remains constant. What is the work done by the nonconservative force of air resistance, which is the only nonconservative force acting?
A) +2.93 times 10^5 J
B) 0J
C) Answer is not obtainable, because insufficient information about the skydiver's speed is given.
D) -2.93 times 10^5 J
The work done by air resistance on a skydiver with a constant velocity is -2.93 × 10⁵ J, as the air resistance force is equal but opposite to the gravitational force, and work is calculated as force times distance in the direction of the force.
Explanation:The work done by a nonconservative force such as air resistance can be calculated as the product of the force and the distance over which it acts, in the direction of the force. Since the skydiver is falling with a constant velocity, the force of air resistance must be equal and opposite to the gravitational force acting on the skydiver, resulting in no net force and therefore no acceleration. The work done by air resistance is thus equal to the gravitational force times the distance fallen, with a negative sign because the force of air resistance acts in the opposite direction to the displacement.
First, we need to calculate the gravitational force acting on the skydiver:
F_gravity = mass × acceleration due to gravity
F_gravity = 92.0 kg × 9.8 m/s²
F_gravity = 901.6 N
Now, we can calculate the work done by air resistance:
Work = force × distance × cos(ϸ)
Since the angle (ϸ) between the force of air resistance and the direction of displacement is 180 degrees (opposite directions), cos(ϸ) is -1. Therefore:
Work = -901.6 N × 325 m × -1
Work = -2.93 × 10⁵ J
The correct answer is D) -2.93 times 10⁵ J, which means the work done by air resistance is negative because it acts in the direction opposite to the displacement.
What is the person’s displacement for the trip?
what is a vector quantity? give an example.
Answer:
+ 3.0 m
Explanation:
displacement is shortest distance from fixed point O in particular direction . in diagram shortest distance at end from O is 3 m and it is right of O so +. HENCE +3.0m
In the double-slit experiment with electrons, the electrons arrive at the screen in a
A. Wave-like way with a pattern that is particle-like
B. Wave-like way with a pattern that is wave-like
C. Particle-like way with a pattern that is particle-like
D. Particle-like way with a pattern that is wave-like
Answer:
B. Wave-like way with a pattern that is wave-like
Explanation:
The double slit experiment when performed with electromagnetic waves, gives a pattern of light lines and dark areas, equally spaced.
In the case of electrons we must use Broglie's duality principle that states that all things have the characteristics of particles and waves together. The characteristic observed in a given experiment depends on the type of experiment, using the relationship
p = h /λ
Where p is the amount of motion of the particle and λ the wavelength associated with this particle
In consequence of the previous one to the screen it should arrive as a wave with a wave type pattern
Let's review the answer.
A) False. The pattern is wave type
B) True. The whole process is with undulating characteristics
C) False. A wave arrives
D) False. A wave arrives
_________is a system that uses the reflection of underwater sound waves to detect objects.
1. sounds
2. ultrasound
3. sonar
4. refraction
Answer:3-Sonar
Explanation:
Sonar system is used to detect the under water objects by using the deflection of sound waves.
Sonar is an acronym of Sound navigation ranging.Two types of sonar sets are used for working: active and passive. The active sonar system pushes out sound signals called pings, and then absorbs the return sound echo. Passive sound sets obtain sound echoes without transmitting their actual sound signals. Submarines are using sonar to track other vessels.
If two vehicles are traveling at a speed of 50 miles per hour and they collide with one another, the speed of the head-on impact is actually ___ miles per hour.
Answer:
[tex]v_{f}[/tex] = 0 miles/h
Explanation:
This exercise should be resolved with the moment. The system is formed by the two cars. Let's write the moment
Initial. Before the crash
p₀ = m v₁ - m v₂
The sign is because they go in the opposite direction
Final. After the crash
[tex]p_{f}[/tex] = (m + m) [tex]v_{f}[/tex]
The moment is preserved
p₀ = [tex]p_{f}[/tex]
m v₁- m v₂ = 2m [tex]v_{f}[/tex]
[tex]v_{f}[/tex] = m / 2m (v₁-v₂)
But the speed of the cars is the same v1 = v2 = 50 liters / h
[tex]v_{f}[/tex] = 0
so the two faces do not move after the crash
The height of a cone is increasing at a rate of 10 cm/sec and its radius is decreasing so that its volume remains constant. How fast is the radius changing when the radius is 4 cm and the height is 10 cm?
Answer:
dr/dt = -2 cm/s.
Explanation:
The volume of a cone is given by:
[tex]V=\frac{1}{3} \pi r^{2}h[/tex] (1)
r is the radiush is the heightLet's take the derivative with respect to time in each side of (1).
[tex]\frac{dV}{dt}=\frac{1}{3} \pi \frac{d}{dt}(r^{2}h)=\frac{1}{3} \pi \left(2r\frac{dr}{dt}h+r^{2}\frac{dh}{dt} \right)[/tex] (2)
We know that:
dh/dt = 10 cm / s (rate increasing of height)dV/dt = 0 (constant volume means no variation with respect of time)r = 4 cm h = 10 cmWe can calculate how fast is the radius changing using the above information.
[tex]0=\frac{1}{3} \pi \left( 2\cdot 4\cdot \frac{dr}{dt} \cdot 10 + 4^{2}\cdot 10)\right[/tex]
Therefore dr/dt will be:
[tex]\frac{dr}{dt}=-\frac{160}{80}=-2 cm/s[/tex]
The minus signs means that r is decreasing.
I hope it helps you!
The main water line enters a house on the first floor. The line has a gauge pressure of 2.64 x 105 Pa.
(a) A faucet on the second floor, 6.50 m above the first floor is turned off. What is the gauge pressure at this faucet?
(b) How high could a faucet be before no water would flow from it, even if the faucet were open?
Answer:
a. P1=200235pa
b. h=26.91m
Explanation:
The main water line enters a house on the first floor. The line has a gauge pressure of 2.64 x 105 Pa.
(a) A faucet on the second floor, 6.50 m above the first floor is turned off. What is the gauge pressure at this faucet?
(b) How high could a faucet be before no water would flow from it, even if the faucet were open?
pressure is the force per unit area.
force is that which tends to change a boy's state of rest or uniform motion in a straight line
rho stands for the density of water which is 1000kg/m3
p2=p1+rhogh
p1=p2-rhogh
the gauge pressure at 6.5m
will be:
2.64 x 10^5 Pa-100kg/m3*9.81*6.5
P1=200235pa
b. How high could a faucet be before no water would flow from it, even if the faucet were open?
b.h=p2-p1/(grho)
h=2.64 x 105 Pa/(1000*9.81)
h=26.91m
To find the gauge pressure and height limit of a faucet on the second floor compared to the first floor in a house with a main water line.
Explanation:(a) To find the gauge pressure at the faucet on the second floor, we can use the equation: P2 = P1 + ρgh. Here, P1 = 2.64 x 105 Pa, ρ is the density of water, g is the acceleration due to gravity, and h is the height difference between the first and second floor. Plugging in the values, we get: P2 = 2.64 x 105 + (1000 kg/m3) x (9.8 m/s2) x 6.50 m. Solving for P2 gives us the gauge pressure at the faucet on the second floor.
(b) To find the maximum height a faucet could be before no water would flow from it, we can equate the gauge pressure to zero in the equation: P2 = P1 + ρgh. Solving for h, we can find the maximum height.
Learn more about gauge pressure here:https://brainly.com/question/37599608
#SPJ3
Simone created a chart to summarize the energy transformations that take place when energy from the wind is used to generate electricity. Which best completes the chart?
a) nuclear energy transformed to electrical energy
b) chemical energy transformed to electrical energy
c) radiant energy transformed to mechanical energy
d) kinetic energy transformed to mechanical energy
Answer:
d) kinetic energy transformed to mechanical energy
Explanation:
Wind energy comes from its movement, so kinetic energy
Em = K = ½ m v²2
This energy spins the mill aspadle that this movement of the rotor within a magnetic field creates electricity in accordance with Faraday's law.
Consequently, from the above we should make a graph of the wind speed (kinetic energy) according to the electricity produced
The correct answer is d
kinetic energy transformed to mechanical energy this best completes the chart. Hence option D is correct.
What is Kinetic Energy ?Kinetic energy is the energy associated with a motion of a body. When a body is in motion having mass m then it has kinetic energy. Kinetic energy is denoted by K or T. it is expressed in joules. Kinetic energy is given by,
K = 1/2 mv²
Hence an object having zero mass or zero velocity have zero kinetic energy.
In line with Faraday's law, when the mill asp rotates under the influence of this energy, electricity is generated.
In light of the foregoing, we should create a graph showing the wind speed (kinetic energy) in relation to the power generated.
To know more about Kinetic Energy :
https://brainly.com/question/26472013
#SPJ5.
950 - kg toyota collides into the rear end of a 2200-kg cadillac stopped at a red light. THe bumpers lock, the brakes are locked and the two car skid forward 4.8 meteres before stopping. The police officer, knowing the the coefficient of kinetic friction between tires and road is 0.4, calculates the speed of the toyota impact. What was the speed of the car?
Answer:
u = 20.33 m/s
Explanation:
given,
mass of Toyota car = 950 Kg
mass of Cadillac = 2200 Kg
distance to stop = 4.8 m
coefficient of friction = 0.4
initial speed of the Toyota = ?
we know,
F = ma
and frictional foce
F = μ N = μ m g
where N is normal force
now equating both the equation
ma = μ m g
a = μ g
a = 0.4 x 9.8
a = 3.92 m/s²
using equation of motion
v² = u² + 2 a s
v² = 0² + 2 x 3.92 x 4.8
v = 6.13 m/s
above given velocity is the combined velocity of the Toyota and Cadillac
now, using conservation of momentum
m u = (M + m) v
950 x u = (2200+ 950) x 6.13
u = 20.33 m/s
The speed of Toyota before impact is equal to u = 20.33 m/s
Final answer:
The speed of the Toyota at the moment of impact is 0 m/s.
Explanation:
To find the speed of the Toyota at the moment of impact, we can use the principle of conservation of momentum. The momentum before the collision is equal to the momentum after the collision.
The momentum of an object is given by the product of its mass and velocity. So, we can write:
massT * velocityT = massC * velocityC
where massT and velocityT are the mass and velocity of the Toyota, and massC and velocityC are the mass and velocity of the Cadillac.
The mass of the Toyota is 950 kg, and the mass of the Cadillac is 2200 kg. The velocity of the Cadillac is 0 m/s because it is stopped. Solving for the velocity of the Toyota:
velocityT = (massC * velocityC) / massT
velocityT = (2200 kg * 0 m/s) / 950 kg = 0 m/s
Therefore, the speed of the Toyota at the moment of impact is 0 m/s.
During an investigation, a scientist heated 123.6 g of copper carbonate till it decomposed to form a black residue. The total mass of the black residue formed was 79.6 g. Does the law of conservation of mass hold true in this case? Use complete sentences to justify your answer based on numerical calculations
Answer:
See below explanation
Explanation:
The correspondent chemical reaction for copper carbonate decomposed by heat is:
CuCO₃ (s) → CuO (s) + CO₂ (g)
Considering all molar mass (MM) for each element ( we consider rounded numbers) :
MM CuCO₃ = 123 g/mol
MM CuO = 79 g/mol
MM CO₂ = 44 g/mol
Statement mentions that scientis heated 123.6 g of CuCO₃ (almost a MM), until a black residue is obtained, which weights 79.6 g : this solid residue is formed by CuO, and the remaining mass (approximatelly 44 g) belongs to teh second product, this is, CO₂; as it is a gas compund, it is not certainly included on the solid residue.
So, law of conservation mass is true for this case, since: 123.6 g = 79.6 g + 44 g. As explained, on the solid residue, we don not include the 44 g, which "escaped" from our system, since it is a gas compound (CO₂)
Which statement is TRUE? Group of answer choices a) An object that is slowing down while traveling in the negative x-direction always has a positive acceleration. b) An object that is speeding up while traveling in the negative x-direction always has a positive acceleration. c) An object that is slowing down always has a negative acceleration, regardless of the direction it travels. d) An object that is speeding up always has a positive acceleration, regardless of the direction it travels. e) An object that is slowing down always has a positive acceleration, regardless of the direction it travels.
Answer:
d) An object that is speeding up always has a positive acceleration, regardless of the direction it travels.
Explanation:
a ) a) An object that is slowing down while traveling in the negative x-direction always has a positive acceleration.
It has negative acceleration in the negative x-direction.
b) An object that is speeding up while traveling in the negative x-direction always has a positive acceleration.
It has a positive acceleration in the negative x-direction'
c) An object that is slowing down always has a negative acceleration, regardless of the direction it travels.
It has a positive acceleration in opposite direction.
e ) An object that is slowing down always has a positive acceleration, regardless of the direction it travels.
It has a positive acceleration only in opposite direction .
"In a Young’s double-slit experiment, the separation between slits is d and the screen is a distance D from the slits. D is much greater than d and λ is the wavelength of the light. The number of bright fringes per unit width on the screen is: "
A. Dd/λ
B. Dλ/d
C. D/dλ
D. λ/Dd
E. d/Dλ"
Answer:
The number of bright fringes per unit width on the screen is, [tex]x=\dfrac{\lambda D}{d}[/tex]
Explanation:
If d is the separation between slits, D is the distance between the slit and the screen and [tex]\lambda[/tex] is the wavelength of the light. Let x is the number of bright fringes per unit width on the screen is given by :
[tex]x=\dfrac{n\lambda D}{d}[/tex]
[tex]\lambda[/tex] is the wavelength
n is the order
If n = 1,
[tex]x=\dfrac{\lambda D}{d}[/tex]
So, the the number of bright fringes per unit width on the screen is [tex]\dfrac{\lambda D}{d}[/tex]. Hence, the correct option is (B).
Final answer:
The number of bright fringes per unit width in a Young's double-slit experiment is given by the reciprocal of the fringe spacing, which is d/(Dλ), corresponding to answer choice E.
Explanation:
In a Young's double-slit experiment, to find the number of bright fringes per unit width on the screen, we consider the separation between the slits (d), the distance from the slits to the screen (D), and the wavelength of light used (λ). The distance between adjacent bright fringes, or fringe spacing, is given by Δy = Dλ/d. From this relation, the number of bright fringes per unit width can be obtained by taking the reciprocal of the fringe spacing, which implies 1/Δy = d/(Dλ).
Therefore, the correct formula to calculate the number of bright fringes per unit width on the screen is the reciprocal of Δy, which is d/(Dλ), matching answer choice E.
Which of the following increases atmospheric loss by thermal escape? A.increasing the mass of the gas particles B.increasing the temperature of the atmosphere C.increasing the escape velocity of the planet D.all of the above
Answer:
B. increasing the temperature of the atmosphere
Explanation:
Generally, atmospheric loss can be defined as the loss of the gases in the atmosphere to outer space. This process usually occur through either thermal escape or non-thermal escape. Atmospheric loss of gases to outer space by thermal escape occurs when the molecular velocity due to thermal energy is considerably high. One of the factors that can lead to increase in thermal energy and ultimately increase in atmospheric loss is increase in the temperature of the atmosphere. Therefore, the correct answer is option B.
A 1055-kg van, stopped at a traffic light, is hit directly in the rear by a 715-kg car traveling with a velocity of +2.25 m/s. Assume the transmission of the van is in neutral, the brakes are not being applied, and the collision is elastic. What is the final velocity of (a) the car (b)the van?
Answer:
1.81779 m/s in the same direction as the car
0.43220 m/s in the same direction
Explanation:
[tex]m_1[/tex] = Mass of van= 1055 kg
[tex]m_2[/tex] = Mass of car = 715 kg
[tex]u_1[/tex] = Initial Velocity of van = 0 m/s
[tex]u_2[/tex] = Initial Velocity of car = 2.25 m/s
[tex]v_1[/tex] = Final Velocity of van
[tex]v_2[/tex] = Final Velocity of car
As momentum and Energy is conserved
[tex]m_{1}u_{1}+m_{2}u_{2}=m_{1}v_{1}+m_{2}v_{2}[/tex]
[tex]{\tfrac {1}{2}}m_{1}u_{1}^{2}+{\tfrac {1}{2}}m_{2}u_{2}^{2}={\tfrac {1}{2}}m_{1}v_{1}^{2}+{\tfrac {1}{2}}m_{2}v_{2}^{2}[/tex]
From the two equations we get
[tex]v_{1}=\dfrac{m_1-m_2}{m_1+m_2}u_{1}+\dfrac{2m_2}{m_1+m_2}u_2\\\Rightarrow v_1=\dfrac{1055-715}{1055+715}\times 0+\dfrac{2\times 715}{1055+715}\times 2.25\\\Rightarrow v_1=1.81779\ m/s[/tex]
The final velocity of the van is 1.81779 m/s in the same direction as the car
[tex]v_{2}=\dfrac{2m_1}{m_1+m_2}u_{1}+\dfrac{m_2-m_1}{m_1+m_2}u_2\\\Rightarrow v_2=\dfrac{2\times 1055}{1055+715}\times 0+\dfrac{1055-715}{1055+715}\times 2.25\\\Rightarrow v_2=0.43220\ m/s[/tex]
The final velocity of the car is 0.43220 m/s in the same direction
Answer:
(a). The final velocity of the car is -0.432 m/s.
(b). The final velocity of the van is 1.82 m/s.
Explanation:
Given that,
Mass of van = 1055 kg
Mass of car = 715 kg
Initial velocity of car= 2.25 m/s
(a). We need to calculate the final velocity of the car
Using formula of velocity
[tex]v_{c}=\dfrac{m_{v}-m_{c}}{m_{v}+m_{c}}\times u_{c}[/tex]
Put the value into the formula
[tex]v_{c}=\dfrac{715-1055}{715+1055}\times2.25[/tex]
[tex]v_{c}=-0.432\ m/s[/tex]
(b). We need to calculate the final velocity of the van
Using formula of velocity
[tex]v_{v}=\dfrac{2m_{v}}{m_{v}+m_{c}}\times u_{c}[/tex]
Put the value into the formula
[tex]v_{v}=\dfrac{2\times715}{715+1055}\times2.25[/tex]
[tex]v_{v}=1.82\ m/s[/tex]
Hence, (a). The final velocity of the car is -0.432 m/s.
(b). The final velocity of the van is 1.82 m/s.
Using the information from Paul Hewitt's Conceptual Development Practice Page 25-1 and the image below, answer the following question.Image of a wave with two rulers, one vertical and one horizontal, measuring the wave is shown. The wave's first crest aligns from 0 to just less than 4 centimeters on the horizontal ruler and rises from the equilibrium located at 5 centimeters to just before 3 centimeters. The wave's first trough aligns continues to just less than 8 centimeters on the horizontal ruler and goes down from the equilibrium located at 5 centimeters to just before 7 centimeters.What was the measurement of the wavelength and amplitude respectively?
Answer:
A = 2 cm , λ = 8 cm
Explanation:
The amplitude of a wave is the maximum height it has, in this case the height is measured by the vertical ruler,
We are told the balance point is in the reading of 5 cm, that the maximum reading is 3 cm and the Minimum reading is 7 cm. Therefore, the distance from the ends of the ridge to the point of equilibrium is
d = 7-5 = 2 cm
d = 5-3 = 2 cm
A = 2 cm
The wavelength is the minimum horizontal distance for which the wave is repeated, that is measured by the horizontal ruler.
The initial reading for 4 cm and the final reading for 8 cm, this distance corresponds to a crest of the wave, the complete wave is formed by two crests whereby the wavelength is twice this value
Δx = 8-4 = 4 cm
λ = 2 Δx
λ = 8 cm
The amplitude of the wave is approximately [tex]2cm[/tex], measured from the equilibrium to the crest or trough. The wavelength of the wave is approximately [tex]8cm[/tex].
To determine the wavelength and amplitude of the given wave, we need to analyze the provided measurements.
Amplitude CalculationThe crest rises from the equilibrium position of [tex]5 cm `[/tex] to just before [tex]3 cm[/tex] , giving an amplitude measurement of approximately [tex]2 cm (5 cm - 3 cm)[/tex] .
Similarly, the trough falls from the equilibrium of [tex]5 cm[/tex] to just before [tex]7 cm[/tex], again giving a vertical displacement of approximately [tex]2 cm (7 cm - 5 cm)[/tex].
Wavelength CalculationThe horizontal distance from the start of the first crest to the start of the next crest should be measured. According to the provided data, the first crest aligns from [tex]0[/tex] to just under [tex]4 cm[/tex] , and the next crest starts just under [tex]8 cm[/tex].
The wavelength is the horizontal distance covering one complete cycle, measuring just less than [tex]8 cm[/tex]. Therefore, the wavelength is approximately [tex]8 cm[/tex] .
Hence,
Amplitude: [tex]2 cm[/tex]Wavelength: [tex]8 cm[/tex]How well does the infographic ""Plastics in the Ocean"" present a solution to the problem it describes?
Explanation:
The infographic lacks a possible solution to the issue, but it does explain where plastics emerge from, how they get into the marine, what they will do to marine wildlife, and how they will be removed to eliminate ocean plastic waste.
According to estimates reported in 2015 in the journal Science, between 4.8 million and 12.7 million tons of plastic enter the ocean every year. As large, identifiable items or as micro plastics, plastic can enter the ocean-pieces of less than five millimeters in length.
[Please help fast! Offering 100 points if it works!}
The diagram below shows four planets and their distances from the sun.
Light from the sun reaches Earth in 8.3 minutes. In how many minutes does light from the sun reach Mars?
12.62
13.34
15.85
16.60
Answer:
d=1.49×1011m
Explanation:
Velocity is defined as the rate of travel, and can be found using the distance formula.
velocity=distancetime
Rearranging this formula we can solve for distance given velocity and time of travel.
d=vt
We are given velocity and time, and so can solve for distance, but if we plug in the values given;
d=(3.00×108m/s)(8.3minutes)
We can see that the units do not match up. Since seconds are the SI unit for time, we will need to convert 8.3 minutes to seconds.
t=(8.3minutes)(60seconds/minute)=(498s)
Now our units work out and we can solve for distance.
= 15.85
(8.3 min)/(1 AU) = (T)/(1.52 AU)
(8.3 min)x(1.52 AU) = (T x 1 AU)
T = (8.3 min x 1.52 AU) / (1 AU)
T = 12.62 minutes