A kayaker spends a morning paddling on a river. She travels 9 miles upstream and 9 miles downstream in a total of 6 hours. In still water, she can travel at an average speed of 4 miles per hour. What is the average speed of the river's current in miles per hour?
A) 1 mi/h
B) 2 mi/h
C) 3 mi/h
D) 1.5 mi/h

Answers

Answer 1
To answer this item, we have 4 as the speed of the kayaker in still water and the speed of current be y.

When the karayaker moves upstream or against the current, his speed would be 4 - y. Further, if he moves downstream or with the current, the total speed would be 4 + y. The time utilized for the travel is equal to the ratio of the distance and the speed. 

 Total time = 9/(4 - y)  + 9/(4 + y) = 6

We multiply the equation by (4-y)(4+y)
              9(4-y) + 9(4 + y) = 6(4-y)(4+y)

Simplifying,
                72 = 96 - 6y²
Transposing all the constants to only one side of the equation and rearranging,
               6y² = 96 - 72
                 y² = 4
                    y = 2

Hence, the speed of the river's current is 2 miles/hr. The answer is letter B.) 2 miles/hour.
Answer 2

Average speed is the ratio of the total distance traveled to the total time taken. The average speed of the river's current is 2 mi/h.

What is Average speed?

Average speed is the ratio of the total distance traveled to the total time taken.

As we know that the total time taken by the boat to travel upstream and downstream is 6 hours. And the distance traveled by Kayaker is 9 miles, each time while going upstream and downstream.

We know that when the boat is traveling upstream the water current will try to resist the boat, therefore, the speed of the boat while going upstream is (4-x), where x is the speed of the boat. Similarly, the speed of the boat when going downstream will be (4+x), as the water stream will try to provide a push to the boat. Therefore, the total time taken by the Kayaker can be written as,

Total Time

= Time taken while going upstream + Time taken while going downstream

[tex]\rm 6 = \dfrac{Distance\ upstream}{Speed\ upstream} + \dfrac{Distance\ Downstream}{Speed\ Downstream}[/tex]

[tex]\rm 6 = \dfrac{9}{(4+x)} + \dfrac{9}{(4-x)}[/tex]

Taking the LCM,

[tex]6 = \dfrac{9(4+x)+9(4-x)}{(4+x)(4-x)}\\\\6\times (4+x)(4-x) = 9(4+x)+9(4-x)\\\\6(16-x^2) = 36+9x+36-9x\\\\96 - 6x^2 = 72\\\\-6x^2 = 72-96\\\\6x^2 = 24\\\\x^2 = 4\\\\x =2[/tex]

Hence, the average speed of the river's current in miles per hour is 2 mi/h.

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Related Questions

PLEASE HELP ASAP 20 POINTS PLUS BRAINIEST!

Find the greatest possible error for each measurement.

3 ft

a.
1 ft
b.
1/2 ft
c.
1/4 c
d.
1/6 c

Answers

the greatest possible error when measuring in feet is 1/2 foot

 answer is B


Find the missing factor x(y+6)-5(y+6)( ) (y+6)

Answers

We are given the equation:

x (y + 6) – 5 (y + 6)                           ---> 1

We are to look for the missing factor in the equation: (_) (y + 6) from the given values.

Knowing the rules of the polynomial multiplicity, we can have an idea that the given equation can also be written in the form of:

(x – 5) (y + 6)                                      ---> 2

wherein the whole factor (y + 6) was simply distributed to the values in the factor (x – 5). To prove that equations 1 and 2 are equal:

x (y + 6) – 5 (y + 6) = (x – 5) (y + 6)

Expanding:         

x y + 6 x - 5 y – 30 = x y + 6 x – 5 y – 30     (EQUAL!)

 

Therefore our missing factor is:

(x – 5)

During a recent snowstorm in red hook ny Jaime notice that there were 4 inches of snow on the ground at 3:00p.m and there were 6 inches of snow on the ground at 7:00p.m. If she were to graph these data what does the slope of the line connecting these two point represent in the context of this problem

Answers

the slope of the line should be the amount of snow per hour

Find the prime factors of each of the following numbers. a. 25 b. 38 c. 36 d. 285 e. 650 f. 1,740

Answers

Gonna give u how to do it and then u sdo it for each one:

You have to try all prime numbers less or equal than the sqrt(number).

Example: 285, sqrt(285) =16.88194301613413

Try all below 16: 2, 3, 5, 7, 11 and 13:

285 / 3 = 95, 95 / 5 = 19 (19 is prime, end),

285 = 3*5*19, the prime factors are 3, 5 and 19

25 = 5*5
38=2*19
36 = 2^2 * 3^2, so 2 and 3.

That's why I let you do the last one

Answer:

The prime factors are:

a. 5 and 5 (5 × 5 = 25)

b. 2 and 19 (2 × 19 = 38)

c. 2, 2, 3, and 3 (2 × 2 × 3 × 3 = 36)

d. 3, 5, and 19 (3 × 5× 19 = 285)

e. 2, 5, 5, and 13 (2 × 5 × 5 × 13 = 650)

f. 2, 2, 3, 5, and 29 (2 × 2 × 3 × 5 × 29 = 1,740)

Step-by-step explanation:

straight from Penn

A hyperbola centered at the origin has a vertex at (3, 0) and a focus of the hyperbola is located at (9, 0). What are the equations of the directrices?
x = ±

Answers

Final answer:

To find the equations of the directrices for a hyperbola centered at the origin with a vertex at (3, 0) and a focus at (9, 0), we use the formula x = ±a/e. The hyperbola's directrices are x = ± 1.

Explanation:

The student asked about the equations of the directrices for a hyperbola that is centered at the origin, with a vertex at (3, 0) and a focus at (9, 0). A hyperbola has two directrices, and each is a line that is perpendicular to the transverse axis and equidistant from the center as the foci are, but on the opposite side. The equation of a directrix can be found using the formula x = ±a/e, where 'a' is the distance from the center to the vertex and 'e' is the eccentricity, which is the ratio of the distance from the center to a focus (c) over 'a'.

In this case, the hyperbola is aligned along the x-axis. Given a vertex at (3, 0), it implies that 'a' is equal to 3. Since the focus is at (9, 0), it suggests 'c' is equal to 9. The eccentricity 'e' can be found by e = c/a, which is 9/3 = 3. Using the directrix formula x = ±a/e, the two directrices of the hyperbola would be x = ±(3/3), which simplifies to x = ± 1.

Match the pairs of values of f(x) and g(x) with the corresponding values of h(x) if h(x) = f(x) ÷ g(x).

Screenshot of the tiles below

(Please help)

Answers

1)f(x)/g(x)=(x^2-9)/(x-3)=x+3
2)f(x)/g(x)=x^2-4x+3/x-3=x+1
3)f(x)/g(x)=x^2+4x-5/x-1=x+5
4)f(x)/g(x)=x^2-16/x-4=x+4

The We have given that the pairs of values of f(x) and g(x) with the corresponding values of h(x) s given below.

(x^2-9)/(x-3)

x^2-4x+3/x-3

x^2+4x-5/x-1

x^2-16/x-4

We have to match the pairs  of values of f(x) and g(x) with the corresponding values of h(x) if h(x) = f(x) ÷ g(x).

What is the function?

A function from a set X to a set Y assigns to each element of X exactly one element of Y. The set X is called the domain of the function and the set Y is called the codomain of the function. Functions were originally the idealization of how a varying quantity depends on another quantity.

1)f(x)/g(x)=(x^2-9)/(x-3)=x+3

2)f(x)/g(x)=x^2-4x+3/x-3=x+1

3)f(x)/g(x)=x^2+4x-5/x-1=x+5

4)f(x)/g(x)=x^2-16/x-4=x+4

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PLEASE HELP!!! Evaluate Show your work.

Answers

well first you have to distribute the sqrt (7x). So:
sqrt (7x)(sqrt (x) - 7sqrt (7)) =
sqrt (7x) * sqrt (x) - sqrt (7x) * 7sqrt (7)

now if you have two things multiplied by each other and they are both under the sqrt sign then we can multiply them by each other But we have to leave them under the sqrt sign. so this becomes:
sqrt (7x * x) - 7sqrt (7x *7) =
sqrt (7x^2) - 7sqrt (7^2 *x)

in the first sqrt we have x^2 And in the second we have 7^2. The sqrt of anything squared is the same number without the square. So sqrt (x^2) becomes x and sqrt(7^2) becomes 7. So now we have:
x * sqrt (7) - 7 * 7sqrt (x) =
xsqrt (7) - 49sqrt (x)

Answer:

[tex]\sqrt{7x}(\sqrt{x}-7\sqrt{7})\Rightarrow x\sqrt{7}-49\sqrt{x}[/tex]

Step-by-step explanation:

Given: [tex]\sqrt{7x}(\sqrt{x}-7\sqrt{7})[/tex]

Simplify the expression.

[tex]\Rightarrow \sqrt{7x}(\sqrt{x}-7\sqrt{7})[/tex]

Distribute  [tex]\sqrt{7x}[/tex] over parentheses

[tex]\Rightarrow \sqrt{7x}\cdot\sqrt{x}-\sqrt{7x}\cdot7\sqrt{7}[/tex]

[tex]\Rightarrow \sqrt{7x^2}-7\sqrt{7^2x}[/tex]

square term take out from square root

[tex]\Rightarrow x\sqrt{7}-7\cdot 7\sqrt{x}[/tex]

[tex]\Rightarrow x\sqrt{7}-49\sqrt{x}[/tex]

[tex]\sqrt{7x}(\sqrt{x}-7\sqrt{7})\Rightarrow x\sqrt{7}-49\sqrt{x}[/tex]


Double vision can be the result of _________________.
Wearing glasses that are too strong
Looking directly into bright headlights Passing other cars
Eye muscles relaxed from fatigue, drugs, or alcohol
Rapid eye blinking

Answers

The answer is eye muscles relaxed from fatigue, drugs, or alcohol. Double vision is usually related with alcohol and other drugs. This is often triggered by alcohol intoxication, benzodiazepines, opioids, or certain types of drugs for seizures and epilepsy. Head injuries, like concussions, can also cause double vision. 

Final answer:

Double vision can be caused by wearing glasses that are too strong, eye muscles being relaxed from fatigue, drugs, or alcohol, or by rapid eye blinking. Nearsightedness and farsightedness are common vision defects related to the eye's focusing ability but do not usually cause double vision, which can also be a result of misalignment.

Explanation:

Double vision can be the result of several factors including wearing glasses that are too strong, eye muscles relaxed from fatigue, drugs, or alcohol, or rapid eye blinking. It is not typically caused by looking directly into bright headlights or the action of passing other cars, which are more likely to cause temporary glare or flash blindness rather than persistent double vision.

Common vision defects such as nearsightedness (myopia) and farsightedness (hyperopia) are related to the focusing ability of the eyes. Myopia occurs when the eye over-converges the rays from a distant object in front of the retina, causing distant objects to appear blurry. Hyperopia, on the other hand, happens when the eye does not converge rays from a close object sufficiently, making close objects appear blurry. Misalignment can also cause double vision, and this can be due to a variety of factors including strabismus or nerve damage. Correction of vision defects often involves the use of glasses or contact lenses with the appropriate lens power or surgery for more severe cases.

Find all solutions to the equation in the interval [0, 2π). cos 2x - cos x = 0

Answers

this is the concept of algebra, to solve the expression we proceed as follows;
cos 2x-cosx=0
cos 2x=cosx
but:
cos 2x+1=2(cos^2x)
thereore;
from:
cos 2x=cos x
adding 1 on both sides we get:
cos 2x+1=cos x+1
2(cos^2x)=cosx+1
suppose;
cos x=a
thus;
2a^2=a+1
a^2-1/2a-1/2=0
solving the above quadratic we get:
a=-0.5 and a=1
when a=-0.5
cosx=-0.5
x=120=2/3π
when x=1
cos x=1
x=0
the answer is:
x=0 or x=2/3π

Answer:

The other answer is correct here except it is missing the answer 4pi/3

other wise its correct. The answers are 0, 2pi/3, and 4pi/3

Step-by-step explanation:

see previous answer

Fill in the missing term in the equation. x/x^2-4x+4-x/x^2-3x+2=?/(x-2)^2(x-1)

Answers

           x                            x
-----------------  -  --------------------
x^2 -4x + 4            x^2-3x+2

           x                            x
= ----------------  -  --------------------
    (x -2)^2            (x - 2)(x - 1)

        x (x-1)  - x(x +2)                       
= ----------------------------
          (x -2)^2 (x - 1)

      x^2 -x -x^2 - 2x                    
= --------------------------
      (x -2)^2 (x - 1)

           -3x                    
= -----------------------
      (x -2)^2 (x - 1)

answer 
missing term in the equation: -3x

Answer:

The missing term is x.

Step-by-step explanation:

Given expression is,

[tex]\frac{x}{x^2-4x+4}-\frac{x}{x^2-3x+2}------(1)[/tex]

Since, [tex]x^2-4x+4=(x)^2-2\times (2x)+(2)^2[/tex]

[tex]\implies x^2-4x+4=(x-2)^2------(2)[/tex]    ( (a-b)² = a² - 2ab + b² )

Now,   [tex]x^2-3x+2=x^2-2x-x+2[/tex]    ( By middle term splitting )

[tex]=x(x-2)-1(x-2)[/tex]

[tex]\implies x^2-3x+2=(x-1)(x-2)------(3)[/tex]

From equation (1), (2) and (3),

[tex]\frac{x}{x^2-4x+4}-\frac{x}{x^2-3x+2}=\frac{x}{(x-2)^2}-\frac{x}{(x-2)(x-1)}[/tex]

[tex]=\frac{x(x-1)-x(x-2)}{(x-2)^2(x-1)}[/tex]

[tex]=\frac{x(x-1-x+2)}{(x-2)^2(x-1)}[/tex]

[tex]=\frac{x(1)}{(x-2)^2(x-1)}[/tex]

[tex]=\frac{x}{(x-2)^2(x-1)}[/tex]

Hence, the missing term in the equation is x.

What is the equation of a line that has a slope of -5 and passes through the point (0, 2)?

Answers

The equation is [tex]y = -5x + 2[/tex]. This is because the slope form is y = mx + b, and if -5 is the slope, -5 = m. 2 is the y-intercept, and the y-intercept is b.

If 35% of a natural area is to be developed, leaving 500 acres untouched, how many acres are to be developed?

Answers

Answer:

Area to be developed = 269.23 acres

Step-by-step explanation:

Let there is A acres natural area to be developed.

If 35% of A acres is developed then untouched area will be (100 - 35 = 65%)

Now it has been given in the question that 65% of A (untouched area) = 500 acres

[tex]A.\frac{65}{100}=500[/tex]

[tex]A=\frac{500}{0.65}=769.23[/tex]

So area of the natural field = 769.23 acres

Now 35% of the natural area which is to be developed = A×35%

[tex]=769.23.\frac{35}{100}=(769.23)(.35)=269.23[/tex]

Area of the natural area to be developed is 269.23 acres

The number of acres that are to be developed is 269 acres.

Number of acres

Using this formula

Number of acres=(Number of acres untouched/(100%-Percentage of natural area)×Percentage of natural area

Let plug in the formula

Number of acres=500 acres/(100%-35%)×35%

Number of acres=(500 acres/65%)×35%

Number of acres=769.23×35%

Number of acres=269 acres

Inconclusion the number of acres that are to be developed is 269 acres.

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Determine the distance between a(-1, 2,3) and b(4,-5, 6) to the nearest tenth

Answers

hello :
 the distance between A(-1, 2,3) and B(4,-5, 6)
AB= √((4-(-1)²+(-5-2)² + (6 - 3 ) ²) =√(25 +49 +9) =  √83 ≅ 9.11

Which polynomial is a perfect square trinomial?

A. 36x²-18x-9
B. 4a²-28a-49
C. 25b²-40b+16
D. 4x²-6x+9

Answers

ANSWER: C
because of how the multiples of 25 are 5 and 5 and the multiples of 16 can be -4,-4...
 5*-4+5*-4=-40
(5x-4)²= ((5²)x²-40x+(-4²))=25x²-40+16
C
//Brief explanation
Using a discriminant (b^2 - 4ac), for a perfect square the discriminant = 0.
For A the discriminant is >0 (1620)
For B the discriminant is >0 (1568)
For C the discriminant = 0
For D the discriminant is < 0 (-108)

Margie and four friends are eating lunch at a restaurant. The total bill is $52.50 before tax and tip. Margie has a coupon good for $10off their total purchase. If sales tax of 6 percent is collected on the discount amount, what is the total cost after tax?

Answers

52.50....before tax and discount (don't see anything about a tip)
has a $ 10 off coupon..
52.50 - 10 = 42.50...this is the discount amount
has a 6% sales tax
0.06(42.50) = 2.55...this is the sales tax
for a total of : 42.50 + 2.55 = 45.05 <==

In the triangle below, determine the value of a.

Answers

tan42°=a/14

a=14tan42°

a≈12.61 (to the nearest hundredth of a unit)
You have to use tangent (ratio of sine and cosine).

Use tangent to find the opposite to the adjacent side (14) from the angle (in this case a).

a = 14*tan(42°) = 14*0,9 = 12,6 (approssimatively)

Write cos 53 degrees in terms of sine.

Answers

cos(x) = sin(90 - x)
cos(53) = sin(90 - 53)
cos(53) = sin(37)

The value of cos 53 degrees in terms of sine is,

⇒ sin 37 degree

What is mean by Angle?

An angle is a combination of two rays (half-lines) with a common endpoint. The latter is known as the vertex of the angle and the rays as the sides, sometimes as the legs and sometimes the arms of the angle.

We have to given that;

⇒ cos 53 degree

Hence, We can change it into sine as;

⇒ cos 53 degree

⇒ sin (90 - 53)

⇒ sin 37 degree

Thus, The value of cos 53 degrees in terms of sine is,

⇒ sin 37 degree

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I NEEED HELPOPOP!!!!

PLEASE ASSIT ME FOR TWO MATH QUESTIONS

Answers

Hello,

The only function in B has an inverse which is also a function (one x must have only 0 or 1 image (y)) for the first picture

Answer D for the second picture.


Answer B

25 POINTS PLZ HELP ASAP!!!

Match the functions with their inverse functions.

Answers

To calculate the inverse isolate x on one side and switch x with y on both sides

1)
y=(2x-3)/5
5y=2x-3
5y+3=2x
(5y+3)/2=x
-> f(x)=(5x+3)/2

2)
y=(x+8)/2
2y=x+8
2y-8=x
-> f(x)=2x-8

3)
y=(x+2)/7
7y=x+2
7y-2=x
-> f(x)=7x-2

4)
y=(1-2x)/x
y=(1/x)-2
y+2=1/x
x=1/(y+2)
-> f(x)=1/(x+2)
Answer with explanation:

We know that when we are given a inverse function as: [tex]f^{-1}(x)[/tex]

Then we find the function by the method:

Put [tex]f^{-1}(x)=y[/tex]

Then we switch the places of x and y and solve for y.

1)

[tex]f^{-1}(x)=\dfrac{2x-3}{5}[/tex]

Hence, we find the function as follows:

[tex]\dfrac{2x-3}{5}=y[/tex]

Then we switch for x and y

[tex]\dfrac{2y-3}{5}=x\\\\\\i.e.\\\\2y-3=5x\\\\\\i.e.\\\\\\2y=5x+3\\\\\\i.e.\\\\\\y=\dfrac{5x+3}{2}[/tex]

Hence, inverse function is:

  [tex]f(x)=\dfrac{5x+3}{2}[/tex]

2)

[tex]f^{-1}(x)=\dfrac{x+8}{2}[/tex]

Hence, we find the function as follows:

[tex]\dfrac{x+8}{2}=y[/tex]

Then we switch for x and y

[tex]\dfrac{y+8}{2}=x[/tex]

[tex]y=2x-8[/tex]

Hence, inverse function is:

           [tex]f(x)=2x-8[/tex]

3)

[tex]f^{-1}(x)=\dfrac{x+2}{7}[/tex]

Hence, we find the function as follows:

[tex]\dfrac{x+2}{7}=y[/tex]

Then we switch for x and y

[tex]\dfrac{y+2}{7}=x[/tex]

[tex]y=7x-2[/tex]

Hence, inverse function is:

           [tex]f(x)=7x-2[/tex]

4)

[tex]f^{-1}(x)=\dfrac{1-2x}{x}[/tex]

Hence, we find the function as follows:

[tex]\dfrac{1-2x}{x}=y[/tex]

Then we switch for x and y

[tex]\dfrac{1-2y}{y}=x[/tex]

i.e.

[tex]1-2y=xy\\\\xy+2y=1\\\\i.e.\\\\y(x+2)=1\\\\y=\dfrac{1}{x+2}[/tex]

Hence, inverse function is:

  [tex]f(x)=\dfrac{1}{x+2}[/tex]

what is the degree of 12x^4-8x+4x^2-3

Answers

dat is 4th degree because x is raised to the 4th power and that is the highest power of the placholder

4th degree

Answer:

The degree of [tex]12x^4-8x+4x^2-3[/tex] is 4.

Step-by-step explanation:

The given polynomial is [tex]12x^4-8x+4x^2-3[/tex]

This polynomial is of one variable which is x. Hence, the degree of the polynomial is the highest exponent.

For the given polynomial, the highest exponent is 4.

Therefore, the degree of [tex]12x^4-8x+4x^2-3[/tex] is 4.

A circle has a diameter of 13 centimeters and a central angle EOG that measures 280 degrees. What is the length of the intercepted arc EG? Use 3.14 for pi and round your answer to the nearest tenth. A) 10.1 cm B) 15.9 cm C) 31.7 cm D) 63.5 cm

Answers

Circumference of the circle = pi * diameter = 3.14 *  13 =  40.82

Length of EG  =  40.82 * 280 / 360  =  31.7 cm.

what level of measurement is qualitative? Nominal? Ordinal? Interval? Or ration?

Answers

interval.............................


The level of measurement which is qualitative is nominal.
It is the only level of measurement which is only qualitative, whereas ordinal can be either qualitative or quantitative (depending on data), and interval and ratio can only be quantitative.
The term qualitative refers to the fact that non-numerical entries are used, meaning there are no numbers, and the word nominal refers to the Latin word for nouns, or words, which is why that is the correct answer. The rest of the options use numbers, but nominal doesn't.

What is the value of 35+20/5-4*7
11
49
245
35
Hellllpp :)

Answers

35+20/5-4*7 = 35 + (20/5) - (4*7)
= 35 + 4 - 28 = 11

The answer is 11
Follow the order of operations or PEMDAS. P for parentheses, E for exponents, M and D for multiplication and division (do these left to right and NOT all multiplication before division), then A and S are for addition and subtraction... Also do these left to right. So
35 + 20/5 - 4×7 =
35 + 4 - 28 =
39 - 28 =
11

Help Please!!!!!!

f(x)=5x^2+9x−4

g(x)=−8x^2−3x−4

Find (f+g)(x)

My Options Are...:
a. 3x^2+6x−8
b. −3x^3+6x^2−8x
c. −3x^4+6x^2−8
d. −3x^2+6x−8

Answers

f+g(x)=5x^2+9x-4-8x^2-3x-4
Combine like terms
f+g(x)=-3x^2+6x-8
Final answer: D

What is the equation of the line that is parallel to the line y = x + 4 and passes through the point (6, 5)?

Answers

y-5=1(x-6)

y-5=x-6

y=x-1 is parallel to y=x+4

What is the polygon being rotated to create the brown quilt block pattern?

Answers

It would be a parallelogram since if you look closely the individual shapes are indeed parallelograms.

Answer with explanation:

The pre image which is in blue color is parallelogram.

There are four blue parallelograms here,congruent to each other,each one of them when rotated by certain angle ,gives parallelogram in brown color.

When we rotate a polygon,after rotation neither the shape nor the size of polygon changes.The two shapes are congruent to each other.

The Polygon being rotated to create the brown quilt block pattern is

Option C: Parallelogram

what are the roots of the polynomial equation x3-7x=6x-12? Use a graphing calculator and a system of equations.

Answers

x3-7x=6x-12
x3-7x-6x+12=0
x3-13x+12=0
(x-1)(x2+x-12)=0
Calculate delta of the second bracket:
delta = 1+4*12=49
sqrt(delta)=sqrt(49)=7
x_1=(-1-7)/2=-4
x_2=(-1+7)/2=3

(x-1)(x+4)(x-3)=0

Answear:
Roots: x=1, x=-4, x=3.

The roots of the polynomial equation x³ - 7x = 6x - 12 is x = 1, 3, -4 and graph is shown in the picture.

What is polynomial?

Polynomial is the combination of variables and constants systematically with "n" number of power in ascending or descending order.

[tex]\rm a_1x+a_2x^2+a_3x^3+a_4x^4..........a_nx^n[/tex]

We have a polynomial equation:

x³ - 7x = 6x - 12

[tex]\rm x^3-7x+12=6x[/tex]

x³ - 13x + 2 = 0

(x - 1)(x -3)(x + 4) = 0

x = 1, 3, -4

Thus, the roots of the polynomial equation x³ - 7x = 6x - 12 is x = 1, 3, -4 and graph is shown in the picture.

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If isosceles triangle ABC has a 130° angle at vertex B, which statement must be true?
m∠A = 15° and m∠C = 35°
m∠A + m∠B = 155°
m∠A + m∠C = 60°
m∠A = 20° and m∠C = 30°.

Answers

isocolese triangle has 2 angles of same length

all angles in a triangle add to 180

so
if the angles are m∠A, m∠B, m∠C, then
either m∠A=m∠B or m∠B=m∠C or m∠A=m∠C

anyway

so if we assume that vertex B is the one that has a twin then
130+130+?=180
260+?=180
?=-80
false, we can't have a negative angle measure

so 130 must be the odd one

?+?+130=180
2?+130=180
2?=50
?=25

so
m∠A=m∠C=25°

let's test the 2nd answer choice
m∠A+m∠B=25+130=155, yep

test 3rd
m∠A+m∠C=25+25=50≠60, nope
not 3rd one



so answer is 2nd statement
m∠A + m∠B = 155°

A coin collector bought a set of coins for $500, and then sold the set for $850, making a profit of $50 per coin. how many coins were in the set?

Answers

For this case, the first thing we must do is calculate the total profit.

We have then:

[tex] P = 850 - 500 [/tex]

[tex] P = 350 [/tex]

Then, we look for the number of coins.

For this, we need the total profit (which we already calculate) and the amount of profit per coin.

We have then:

[tex] N = \frac{350}{50} [/tex]

[tex] N = 7 [/tex]

Answer:

The amount of coins that was on the set is:

[tex] N = 7 [/tex]

Final answer:

The coin collector bought and sold a set of coins, making a total profit of $350. Dividing this profit by the $50 profit per coin reveals that there were 7 coins in the set.

Explanation:

The coin collector made a profit of $50 per coin by selling a set of coins. To find out how many coins were in the set, we need to calculate the total profit made from selling the coins and then divide that by the profit per coin.

The total profit is the selling price minus the buying price, so $850 - $500 = $350. If the collector made $50 profit per coin, then the number of coins in the set can be found by dividing the total profit by the profit per coin: $350 / $50 per coin = 7 coins.

He nine ring wraiths want to fly from barad-dur to rivendell. rivendell is directly north of barad-dur. the dark tower reports that the wind is coming from the west at 68 miles per hour. in order to travel in a straight line, the ring wraiths decide to head northwest. at what speed should they fly (omit units)?

Answers

This problem is better understood with a given figure. Assuming that the flight is in a perfect northwest direction such that the angle is 45°, therefore I believe I have the correct figure to simulate the situation (see attached).

 

Now we are asked to find for the value of the hypotenuse (flight speed) given the angle and the side opposite to the angle. In this case, we use the sin function:

sin θ = opposite side / hypotenuse

sin 45 = 68 miles per hr / flight

flight = 68 miles per hr / sin 45

flight = 96.17 miles per hr

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