To calculate the pressure at the entrance end of the pipe, we can apply Bernoulli's principle and the equation of continuity. First, we can find the speed of the liquid at the exit end of the pipe using the equation of continuity. Then, we can use Bernoulli's equation to calculate the pressure at the entrance end of the pipe. The pressure at the entrance end of the pipe is approximately 1.08 × 10^5 Pa.
Explanation:To calculate the pressure at the entrance end of the pipe, we can apply Bernoulli's principle, which states that the total energy of a fluid flowing in a pipe is constant. Bernoulli's equation is given by:
P1 + (1/2)ρv1^2 + ρgh1 = P2 + (1/2)ρv2^2 + ρgh2
In this equation, P1 and P2 are the pressures at the entrance and exit ends of the pipe, ρ is the density of the liquid, v1 and v2 are the speeds of the liquid at the entrance and exit ends, g is the acceleration due to gravity, and h1 and h2 are the heights of the liquid at the entrance and exit ends, respectively.
Using the given values, we can calculate:
ρ = 1136 kg/m³v1 = 1.06 m/sv2 = ?D1 = 0.26 mD2 = 0.05 mP2 = 1.2 atm = 1.2 × 101325 Pah2 - h1 = 4.25 mFirst, we need to calculate v2 using the equation of continuity, which states that the mass flow rate is constant:
A1v1 = A2v2
Using the diameters of the pipe at the entrance and exit ends, we can find the areas:
A1 = (π/4)(D1^2)A2 = (π/4)(D2^2)Substituting the given values, we can solve for v2:
A1v1 = A2v2
[(π/4)(0.26^2)](1.06) = [(π/4)(0.05^2)]v2
v2 = [(π/4)(0.26^2)](1.06) / [(π/4)(0.05^2)]
v2 ≈ 22.22 m/s
Now that we have v2, we can substitute all the values into Bernoulli's equation and solve for P1:
P1 + (1/2)ρv1^2 + ρgh1 = P2 + (1/2)ρv2^2 + ρgh2
Substituting the given values:
P1 + (1/2)(1136)(1.06^2) + (1136)(9.8)(0) = (1.2 × 101325) + (1/2)(1136)(22.22^2) + (1136)(9.8)(4.25)
Solving for P1:
P1 ≈ 1.08 × 10^5 Pa
Therefore, the pressure at the entrance end of the pipe is approximately 1.08 × 10^5 Pa.
Please help on this one? PLEASE.
Answer:
option d: microwave industrial drying equipment
Explanation:
What aviation first is paul maccready credited with
Answer:
Paul B. MacCready, 81; inventor of human-powered aircraft, other innovations. Paul B. MacCready, the Caltech-trained scientist and inventor who created the Gossamer Condor -- the first successful human-powered airplane -- as well as other innovative aircraft, has died. He was 81.
Explanation:
Paul MacCready is credited with creating the first human-powered aircraft, the Gossamer Condor, which was able to follow a controlled, pre-determined course.
Explanation:Paul MacCready is a renowned figure in the world of aviation. He is mainly credited with creating the first human-powered aircraft to fly a pre-determined course. This aircraft is recognized as the Gossamer Condor, a revolutionary aircraft design that not only was powered by a human but also had the ability to be controlled and maneuver in flight. MacCready's innovative work in aviation technology has greatly contributed to how we understand and approach the concept of flight in the modern day.
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In baseball, a home run means the batter has hit the baseball into the stands, beyond the baseball field. Compare the force of the batter when bunting the ball into the in-field versus hitting a grand slam.
A) There is no way to estimate the batter's force.
B) The force is much less when bunting into the in-field.
C) The force of the batters in each case is about the same.
D) The force of the batter is much less when hitting the ball out of the park.
Answer:
B
Explanation:
"Bunting" is when the batter lets the ball hit the bat without swinging it.
Force is mass times acceleration. The mass of the ball is the same in both scenarios, but the acceleration is much lower when bunting than it is when hitting a grand slam, so the force is much lower.
Therefore, the answer is B.
Answer: The force is much less when bunting into the in-field.
Explanation: usually, a home run is more a technique thing than a force thing.
an example can be that, two swings with the same force, but one hits the ball with the border of the bat, and the other hits the ball with the middle, in the second case more force will be transmitted to the ball, and it will go further away (increasing in this way the probability of a home run).
Assuming that in both cases the ball is hit exactly in the same way, now the force matters. Then a ball that goes out of the field is hit with more force than one that does not go out of the field.
Then the correct option would be option B: The force is much less when bunting into the in-field.
In an electric motor, periodically changing the direction of current in the electromagnet can cause the axle to spin because
A. the electromagnet loses its magnetism.
B. mechanical energy is converted to electric energy.
C. the force is constant.
D. the magnetic field reverses direction.
Answer:
The magnetic field reverses direction.
Explanation:
Answer:
D The magnetic field reverses direction.
Explanation:
An electric motor works based on the principle of electromagnetic induction. It is the interaction of electric current and the magnetic field that makes a motor function.
An electric motor is a machine that will convert the electric energy to mechanical energy. In this a commutator is used to change the direction of current.
When the direction of flow of current is made to change, the magnetic field also reverses the direction.
There are different types of motors like AC motor,DC motor, Induction motor etc.
The magnetic field about a straight length of current-carrying wire is _________.
a. similar to the shape of an electric field about a charged wire
b. circular in shape
c. aligned from north to south poles in the wire
d. in accord with the inverse-square law
Answer:
b. circular in shape
Explanation:
The magnetic field around a current-carrying wire forms concentric circles around the axis of the wire. In particular, the direction of the field lines can be found by using the right hand rule:
- the thumb must be placed along the direction of the current in the wire
- the other fingers, wrapped around the wire, give the direction of the magnetic field lines
The strenght of the magnetic field around the wire decreases linearly with the distance from the wire, according to the equation:
[tex]B=\frac{\mu_0 I}{2\pi r}[/tex]
where
[tex]\mu_0[/tex] is the vacuum permeability
I is the current in the wire
r is the distance from the wire
What can Lisa do to increase the strength of the electromagnet?
She can use a nail with weaker magnetic properties.
She can change the direction of the nail.
She can move the wire loops closer together.
She can reduce the number of wire loops.
Answer:
move the wire loops closer
Explanation:
because the closer t they are the more concentrated the energy is in that specific area
Lisa can move the wire loops closer together to increase the strength of the electromagnet. Option C is correct.
What is electromagnet?An electromagnet is a magnet whose magnetic field is generated by an electric current. Wire coiled into a coil is used to make electromagnets.
A current flowing through the wire produces a magnetic field that is focused in the hole.
The strength of the electromagnet is increased by;
Adding further twists to the coil by wrapping it around a piece of iron and increasing the amount of electricity that flows through the coil.
Hence, option C is correct.
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BRAINLIEST ANSWER
Find the angle of the resultant vector for the vectors shown below. (nearest whole number and angles measured from the positive x-axis)
vector
A) 39 degrees
B) 51 degrees
C) 70 degrees
Answer:
A
Explanation:
The horizontal component of the resultant vector is:
x = 18 cos 70° + 15
x = 21.2
The vertical component of the resultant vector is:
y = 18 sin 70°
y = 16.9
So the angle from the positive x-axis is:
θ = atan (y/x)
θ = atan (16.9 / 21.2)
θ = 39°
Answer is A.
What is the value of work when a piston of volume 0.2 L expands against an external pressure of 200 kPa to a volume of 3.4 L?640 J3.40 kJ-640 J-3.40 kJ
Answer:
640 J
Explanation:
The work done by the piston when expanding is given by
[tex]W=p\Delta V[/tex]
where we have
[tex]p=200 kPa = 2.0\cdot 10^5 Pa[/tex] is the pressure
[tex]\Delta V[/tex] is the change in volume of the gas inside the piston;
since we have
[tex]V_i = 0.2 L[/tex] is the initial volume
[tex]V_f = 3.4 L[/tex] is the final volume
The change in volume is
[tex]\Delta V=3.4 L-0.2 L=3.2 L=3.2\cdot 10^{-3} m^3[/tex]
and so the work done is
[tex]W=(2.00\cdot 10^5 Pa)(3.2 \cdot 10^{-3}m^3)=640 J[/tex]
Two small spheres spaced 20.0 cm apart have equal charge. How many excess electrons must be present on each sphere if the magnitude of the force of repulsion between them is 4.57 x 10^(-21) N?
Answer:
894 electrons
Explanation:
The electrostatic force between the two charges is given by:
[tex]F=\frac{k q_1 q_2}{r^2}[/tex]
where we have
[tex]F=4.57\cdot 10^{-21} N[/tex] is the force
k is the Coulomb's constant
q1 = q2 =q is the magnitude of the charge on each sphere
r = 20.0 cm = 0.20 m is the distance between the two spheres
Substituting and solving for q, we find the charge on each sphere:
[tex]q=\sqrt{\frac{Fr^2}{k}}=\sqrt{\frac{(4.57\cdot 10^{-21} N)(0.20 m)^2}{9\cdot 10^9 Nm^2C^{-2}}}=1.43\cdot 10^{-16} C[/tex]
And since each electron has a charge of
[tex]e=1.6\cdot 10^{-19}C[/tex]
the net charge on each sphere will be given by
[tex]q=Ne[/tex]
where N is the number of excess electrons; solving for N,
[tex]N=\frac{q}{e}=\frac{1.43\cdot 10^{-16}C}{1.6\cdot 10^{-19}C}=894[/tex]
Using Coulomb's Law and the given values, we find that each sphere must have approximately 891 excess electrons to produce a repulsive force of [tex]4.57 \times 10^{-21} N[/tex] at a distance of 20 cm.
To solve this problem, we will use Coulomb's Law, which is given by:
[tex]F = k_e \times (q_1 \times q_2) / r^2[/tex]
Where:
F is the force of repulsion between the charges.[tex]k_e[/tex] is Coulomb's constant ([tex]8.99 \times 10^9 N m^2/C^2[/tex]).q₁ and q₂ are the charges (since the charges are equal, we can use q²).r is the distance between the charges.Given data:
[tex]F = 4.57 \times 10^{-21} N[/tex][tex]r = 20.0\left cm = 0.20\left m[/tex]We can rearrange Coulomb's Law to solve for the charge:
[tex](q_1 \times q_2) = F \times r^2 / k_e[/tex]Since [tex]q_1 = q_2 = q[/tex], the equation becomes:
[tex]q^2 = F \times r^2 / k_e[/tex]Now, we can plug in the values:
[tex]q^2 = (4.57 \times 10^{-21} N) \times (0.20 m)^2 / (8.99 \times 10^9 N m^2/C^2)[/tex][tex]q^2 = 4.57 \times 10^{-21} \times 0.04 / 8.99 \times 10^9[/tex][tex]q^2 = 1.828 \times 10^{-22} / 8.99 \times 10^9[/tex][tex]q^2 \approx 2.034 \times 10^{-32}[/tex]Taking the square root of both sides, we get:
[tex]q \approx 1.426 \times 10^{-16} C[/tex]Since we need to find the number of excess electrons, we divide by the elementary charge ([tex]e = 1.6 \times 10^{-19} C[/tex]):
Number of excess electrons [tex]\approx 1.426 \times 10^{-16} C / 1.6 \times 10^{-19} C/electron[/tex]Number of excess electrons [tex]\approx 891\left electrons[/tex]So, each sphere must have approximately 891 excess electrons to produce the given force of repulsion.
Earth is closest to the sun at a point called
Answer:
It is called Perihelion.
Explanation:
How many joules of heat are absorbed to raise the temperature of 435 grams of water at 1 atm from 25°c to its boiling point?
Explanation:
The amount of heat [tex]Q[/tex] absorbed in the temperature variation of a material is:
[tex]Q=m. c. \Delta T[/tex] (1)
Where:
[tex]m=435g[/tex] is the mass of water
[tex]c[/tex] is the specific heat of the element. In the case of water [tex]c=1 cal/g\°C [/tex]
[tex]\Delta T[/tex] is the variation in temperature, which in this case is [tex]\Delta T=100\°C-25\°C=75\°C[/tex]
(The boiling point of water at the pressure of 1 atm is [tex]100\°C[/tex])
Rewriting equation (1) with the known values:
[tex]Q=(435g)(1 cal/g\°C)(75\°C)[/tex]
(2)
[tex]Q=32625 cal[/tex] (3)
Nevertheless, we are asked to find this value in Joules. So, we have to convert this 32625 calories to Joules, knowing the following:
[tex]1 cal=4.187 J[/tex] (4)
Hence:
[tex]Q=32625 cal=136600.875 J=136.6kJ[/tex]
A 0.0240 kg bullet moving horizontally at 400 m/s embeds itself into an initially stationary 0.500 kg block.
(a) What is their velocity (in m/s) just after the collision? m/s
(b) The bullet-embedded block slides 8.0 m on a horizontal surface with a 0.30 kinetic coefficient of friction. Now what is its velocity (in m/s)? m/s
(c) The bullet-embedded block now strikes and sticks to a stationary 2.00 kg block. How far (in m) does this combination travel before stopping? m
(a) 18.3 m/s
According to the law of conservation of momentum, the total initial momentum of the system must be equal to the total final momentum, so we have
[tex]p_i = p_f\\m u = (m+M)v[/tex]
where
m = 0.0240 kg is the mass of the bullet
u = 400 m/s is the initial speed of the bullet
M = 0.5 kg is the mass of the block
v is the final speed of the block+bullet together
Solving for v, we find the velocity after the collision
[tex]v=\frac{mu}{m+M}=\frac{(0.0240 kg)(400 m/s)}{0.0240 kg+0.5 kg}=18.3 m/s[/tex]
(b) 17.0 m/s
The frictional force acting on the bullet-block system is
[tex]F_f = -\mu (m+M)g[/tex]
where
[tex]\mu = 0.30[/tex] is the coefficient of kinetic friction
The acceleration due to the frictional force, therefore, will be equal to the frictional force divided by the total mass:
[tex]a=\frac{F_f}{m+M}=\-mu g = -(0.30)(9.8 m/s^2)=-2.94 m/s^2[/tex]
The system travels for a distance of
d = 8.0 m
So we can find the final velocity using the equation:
[tex]v_f^2 = v^2 + 2ad[/tex]
where
v = 18.3 m/s is the initial velocity, found at point a). Substituting,
[tex]v_f = \sqrt{(18.3 m/s)^2+2(-2.94 m/s^2)(8.0 m)}=17.0 m/s[/tex]
(c) 2.1 m
We can use again the law of conservation of momentum:
[tex](m+M) v = (m+M+M')v'[/tex]
where
v = 17.0 m/s is the initial velocity of the initial bullet+block system
M = 2.00 kg is the mass of the second block
v' is the final velocity of the system
Solving for v',
[tex]v=\frac{(m+M)v}{m+M+M'}=\frac{(0.0240 kg+0.5 kg)(17.0 m/s)}{0.0240 kg+0.5 kg+2.00 kg}=3.5 m/s[/tex]
The acceleration of the system on the rough surface is still
[tex]a=-2.94 m/s^2[/tex]
So we can find the distance covered by using again the formula used before, and requiring that the final velocity should be zero (v''=0):
[tex]v''^2 - v'^2 = 2ad\\d=\frac{v''^2-v'^2}{2a}=\frac{0-(3.5 m/s)^2}{2(-2.94 m/s^2)}=2.1 m[/tex]
a)The velocity of the combined bullet and block just after collision is 18.32 m/s. b)After sliding with friction, the velocity is 16.99 m/s, and c) after sticking to a 2.00 kg block, the combined system travels 2.13 m before stopping.
First, we need to find the velocity of the combined bullet and block system just after the collision using conservation of momentum.
(a) Using conservation of momentum:
initial momentum = final momentum
m₁ = mass of bullet , v₁= vel of bullet , m₂ = mass of block ,v₂ = final velocity
( m₁ × v₁) = (m₁ + m₂) × v₂
(0.0240 kg × 400 m/s) = (0.0240 kg + 0.500 kg) × v₂
9.6 kg×m/s = 0.524 kg × v₂
v₂ = 9.6 kg×m/s / 0.524 kg
v₂ ≈ 18.32 m/s
(b) To find the velocity after sliding with friction:
The work done by friction = kinetic energy loss , total mass = M
friction force = μ × M × g
work done by friction = friction force × distance
M = 0.524 kg
μ = 0.30
d = 8.0 m
work = μ × M × g × d
work = 0.30 × 0.524 kg × 9.8 m/s² × 8.0 m
work ≈ 12.31 J
initial kinetic energy = 0.5 × M × (v₂)²
initial kinetic energy ≈ 0.5 × 0.524 kg × (18.32 m/s)² ≈ 87.84 J
final kinetic energy = initial kinetic energy - work by friction
final kinetic energy ≈ 87.84 J - 12.31 J ≈ 75.53 J
final velocity = √(2 × final kinetic energy / M)
final velocity ≈ √(2 × 75.53 J / 0.524 kg) ≈ 16.99 m/s
(c) To find the distance traveled after sticking to the 2.00 kg block:
Using conservation of momentum:
(m₃ × v₂) = (m₃ + m₄) × V , V = final velocity new
mass of bullet block ≈ m₃ = 0.524 kg
mass of new block = m₄ = 2.00 kg
(m₃ × final velocity found in (b))
0.524 kg × 16.99 m/s = (0.524 kg + 2.00 kg) × V
8.90 kg×m/s = 2.524 kg * V_new_final
V ≈ 3.53 m/s
Now we deal with the kinetic friction again to find the stopping distance:
work = μ × M₁ × g × d , M₁ = new total mass
M₁ = 2.524 kg
μ = 0.30
work = 0.3 × 2.524 kg × 9.8 m/s² × d
initial kinetic energy = 0.5 × M₁ × V₁²
initial kinetic energy ≈ 0.5 × 2.524 kg × (3.53 m/s)² ≈ 15.70 J
work = initial kinetic energy
0.3 × 2.524 kg × 9.8 m/s² × d = 15.70 J
d ≈ 2.13 m
How might an intense solar storm affect people on Earth?
A. It could disrupt communications and damage the power grid.
B. It would cause an intensely hot summer.
C. It could cause the Van Allen belts to expand.
D. It would not affect people on the surface of Earth, only astronauts.
An intense solar storm COULD disrupt communications and damage the power grid. (A)
An intense solar storm may disrupt communications and damage the power grid, affecting technology-reliant services such as GPS and wireless communication, as well as increasing radiation exposure for astronauts and aircraft passengers on polar routes. Advanced warnings would allow for preventative measures to protect infrastructure and people.
An intense solar storm can have significant impacts on Earth, affecting various aspects of our technology-dependent civilization. The most accurate answer to how a solar storm might affect people on Earth is A. It could disrupt communications and damage the power grid. These storms can cause geomagnetic disturbances that induce currents capable of damaging power systems, leading to widespread outages. Furthermore, the high-energy particles and radiation from solar storms can severely affect satellites and spacecraft, leading to malfunctions in navigation, communication, and other satellite-based services. Moreover, increased radiation poses risks for astronauts and could lead to higher levels of radiation for aircraft passengers on polar routes.
Which of these is true for a fission reaction?
A) It is an endothermic reaction.
B) A heavy nucleus splits into two smaller nuclei.
C) Two light nuclei combine to form a single heavier nucleus.
D) It is an interaction between valence electrons of an atom.
Answer:
B (USA TestPrep)
Explanation:
A heavy nucleus splits into two smaller nuclei is true about fission reaction.
What is Fission reaction?Nuclear fission is the splitting of a heavy nucleus into two lighter ones. Fission was discovered in 1938 by the German scientists Otto Hahn, Lise Meitner, and Fritz Strassmann, who bombarded a sample of uranium with neutrons in an attempt to produce new elements with Z > 92.
Nuclear fusion, in which two light nuclei combine to produce a heavier, more stable nucleus, is the opposite of nuclear fission.
As in the nuclear transmutation reactions discussed. the positive charge on both nuclei results in a large electrostatic energy barrier to fusion.
Therefore, A heavy nucleus splits into two smaller nuclei is true about fission reaction.
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Susie goes out for a jog. She jogs South for 150.0 m before stopping to tie her shoe. After her shoe is tied she turns East and runs another 75.0 m. What distance does she go?
Answer: 225.0 m
Explanation:
Because you asked for distance, and not displacement, you simply need to add 150m + 75m, which is 225 m.
What happens if the volume of gas is reduced?
Answer:
the volume will increase
Explanation:
if the temperature is held constant , the equation is reduced yo Boyle's law
The energy of a photon is directly proportional to its
directly proportional to its frequency
consider the two forces acting on a person who stands still, namely ,the downward pull of gravity and the upward support of the floor. are these equal or opposite? do they comprise an action-reaction pair? why or why not?
The downward force of your weight on the floor and the upward force of the floor against the bottom of your shoes are an action-reaction pair.
Those two forces against the soles of your shoes are equal and opposite forces. If they were not equal and opposite, then they would add up to something that would not be zero. There would be some NET force there, and the soles of your shoes would be accelerating up or down. Since they're NOT doing that, and you're just standing there motionless, there can't be any net force there. Those two forces must exactly add up to zero.
Answer:
two forces such as weight and normal that are in the same body are not the force of action and reaction
Explanation:
Newton's third law says: "If two bodies interact the force exerted by the body 1 on the body 2 is of equal magnitude and opposite to the force exerted by the object 2 on the 1"
Let's analyze this sentence in our case, the bodies are the Earth and the chair
The Earth pulls the body creating its weight at the same time the body pulls the Earth, with an equal force, notice that each force is applied to a different body, so they cannot be added. These are forces of action and reaction
The chair does not accelerate due to its weight because it is supported by the floor, but it creates a very small deformation that creates a response called Normal force to this support, applied to the chair. The force of the deformation is applied to the floor. These are forces of action and reaction.
Therefore two forces such as weight and normal that are in the same body are not the force of action and reaction
When light strikes a red object, what happens to the light waves of all colors except red?
A. They are polarized
B. They are absorbed
C.They are diffracted
D.They are reflected
When light strikes a red object, the light waves of all colors except red are absorbed into the object, and never heard from again. (B)
The only thing left to bounce off of the object into anyone's eye is the waves of red.
When light strikes a red object, the light waves of all colors except red are absorbed. The correct option is B.
What is light?The light is the ray form of energy which falls on the object to enlighten them and make us able to see that object.
if an object is red, it will absorb almost all colors except red. The light falling on red object, couldn't absorb the red color. It is the only color which is completely reflected back.
Thus, when light strikes a red object, the light waves of all colors except red are absorbed. The correct option is B.
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A wooden block with mass 1.45 kg is placed against a compressed spring at the bottom of a slope inclined at an angle of 29.0 degrees (point A). When the spring is released, it projects the block up the incline. At point B, a distance of 4.60 m up the incline from A, the block is moving up the incline at a speed of 5.10 m/s and is no longer in contact with the spring. The coefficient of kinetic friction between the block and incline is μk=0.45. The mass of the spring is negligible.A.Calculate the amount of potential energy that was initially stored in the spring.Take free fall acceleration to be 9.80 m/s2 .
Answer:
76.3 J
Explanation:
I'm assuming the distance of 4.60 m is along the incline, not the vertical distance from the bottom. I'll call this distance d, so h = d sin θ.
Initial energy = final energy
Energy in spring = gravitational energy + kinetic energy + work by friction
E = mgh + 1/2 mv² + Fd
We need to find the force of friction. To do that, draw a free body diagram.
Normal to the incline, we have the normal force pointing up and the normal component of weight (mg cos θ).
Sum of the forces in the normal direction:
∑F = ma
N - mg cos θ = 0
N = mg cos θ
Friction is defined as:
F = Nμ
Plugging in the expression for N:
F = mgμ cos θ
Substituting:
E = mgh + 1/2 mv² + (mgμ cos θ) d
E = mg (d sin θ) + 1/2 mv² + (mgμ cos θ) d
E = mgd (sin θ + μ cos θ) + 1/2 mv²
Given:
m = 1.45 kg
g = 9.90 m/s²
d = 4.60 m
θ = 29.0°
μ = 0.45
v = 5.10 m/s
Solving:
E = mgd (sin θ + μ cos θ) + 1/2 mv²
E = (1.45) (9.80) (4.60) (sin 29.0 + 0.45 cos 29.0) + 1/2 (1.45) (5.10)²
E = 76.3 J
The amount of potential energy initially stored in the spring is 49.3 J.
Explanation:To calculate the amount of potential energy initially stored in the spring, we need to consider the conservation of mechanical energy. At the bottom of the slope, the initial potential energy stored in the spring is converted to a combination of kinetic energy and gravitational potential energy as the block moves up the incline. We can use the equation:
PE(initial) = KE(final) + PE(final)
Substituting the given values and using the fact that the block is moving at a constant velocity up the incline, we can solve for the initial potential energy and find that it is 49.3 J.
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The gravitational force between two objects is 1600 N what will be the gravitational force if they double
Final answer:
The new gravitational force between the two objects will be 6400 N.
Explanation:
The gravitational force between two objects can be calculated using Newton's law of gravitation, which states that the gravitational force (F) is directly proportional to the product of the masses of the objects (M1 and M2) and inversely proportional to the square of the distance between their centers (r).
So, if the gravitational force between two objects is initially 1600 N and the masses of the objects are doubled, the new gravitational force (F') can be calculated using the equation:
F' = (2M1)(2M2)G / (r^2)
Substituting the values into the equation and simplifying, we get:
F' = 4F
Therefore, the new gravitational force will be 4 times the initial force, which is 4 * 1600 N = 6400 N.
A clay pot at room temperature is placed in a kiln, and the pot\'s temperature doubles. how much more heat per second is the pot radiating when hot compared to when cool?
Answer:
16
Explanation:
If we treat the pot as a black body, then:
q = σ T⁴ A,
where q is the heat per second radiated,
σ is the Stefan-Boltzmann Constant,
T is the absolute temperature,
and A is the surface area.
If the absolute temperature doubles, then q increases by a factor of 2⁴ = 16.
A double-slit diffraction pattern is formed on a distant screen. If the separation between the slits decreases, what happens to the distance between interference fringes? Assume the angles involved remain small.
The distance between interference fringes remains the same.
The effect cannot be determined unless the distance between the slits and the screen is known.
The distance between interference fringes also decreases.
The distance between interference fringes increases.
Answer:
The distance between interference fringes increases
Explanation:
Once your rocket reaches space, the captain adjusts the speed. your captain goes from 24,000 km/hr to 17,000 km/hr over 90 seconds. what is your acceleration?
Answer:
-21.6 m/s^2
Explanation:
First of all, we need to convert the initial and final velocities into m/s:
[tex]u = 24,000 km/h = 6666.7 m/s[/tex] is the initial velocity
[tex]v=17,000 km/h =4722.2 m/s[/tex] is the final velocity
The acceleration is given by
[tex]a=\frac{v-u}{t}[/tex]
where
t = 90 s is the time elapsed
Substituting the numbers, we find
[tex]a=\frac{4722.2 m/s-6666.7 m/s}{90 s}=-21.6 m/s^2[/tex]
and the negative sign means the rocket is decelerating.
Given the initial and final velocity, the negative acceleration ( re-tardation ) of the rocket in space is -21.6m/s².
What is Motion?Motion is simply the change in position of an object over time.
From the First Equation of Motion;
v = u + at
Where v is final velocity, u is initial velocity, a is acceleration and t is time elapsed.
Given that;
Initial velocity u = 24,000 km/hr = 6666.67m/sFinal velocity v = 17,000 km/hr = 4722.22m/sElapsed time t = 90sAcceleration a = ?v = u + at
at = v - u
a = ( v - u )/t
a = ( 4722.22m/s - 6666.67m/s ) / 90s
a = ( -1944.45m/s ) / 90s
a = -21.6m/s²
Given the initial and final velocity, the negative acceleration ( re-tardation ) of the rocket in space is -21.6m/s².
Learn more about Equations of Motion here: brainly.com/question/18486505
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What is the most common fuel used in nuclear power plants
Answer:
uranium
Explanation:
it is radioactive
Answer:
UraniumExplanation:
uranium is the most common fuel used in a nuclear power because actinides produced by neutron captureWhich way does light bend when traveling from glass to air?
A. Toward the normal
B. Away from the normal
C. It does not bend
I think its B. Away from the normal because light speeds up going into a less dense substance, and the ray bends away from the normal.
Option B is the right answer!
Explanation :
When light rays travel from air into glass or from air into water, it bends towards normal. This is because the speed of light rays decrease while travelling from air into glass or water .
Cheer's ♡
⠀⠀━━━━━━━━━━━━B. In the vicinity of Earth’s orbit around the Sun, the energy intensity of sunlight is about 1600 W/m2 . What is the approximate magnitude of the electric field in the sunlight?
Answer:
1097.8 V/m
Explanation:
The equation that relates the intensity of an electromagnetic wave with the magnitude of the electric field is:
[tex]I=\frac{1}{2}c\epsilon_0 E^2[/tex]
where
c is the speed of light
[tex]\epsilon_0[/tex] is the vacuum permittivity
E is the peak magnitude of the electric field
In this problem, we know the intensity:
I = 1600 W/m^2
So we can rearrange the formula to find E:
[tex]E=\sqrt{\frac{2I}{c\epsilon_0}}=\sqrt{\frac{2(1600 W/m^2)}{(3\cdot 10^8 m/s)(8.85\cdot 10^{-12} F/m)}}=1097.8 V/m[/tex]
A stone is thrown straight up from the roof of an 80 ft building. the height, in feet, of the stone at any time t, in seconds, measured from the ground is given by ℎ(????) = −16???? 2 + 64???? + 80. what is the maximum height the stone reaches?
Answer:
144 ft
Explanation:
h(t) = -16t² + 64t + 80
The maximum height is at the vertex. We can find the vertex of a parabola using -b / (2a):
t = -64 / (2×-16)
t = 2
The vertex is at 2 seconds. The height of the stone at this time is:
h(2) = -16(2)² + 64(2) + 80
h(2) = 144
The maximum height is 144 feet.
Final answer:
To find the maximum height that the stone reaches, calculate the vertex of the quadratic equation, which leads to a time of 2 seconds. Substituting this back into the height function h(t), we find that the stone reaches its maximum height of 144 feet above the ground.
Explanation:
To determine the maximum height the stone reaches in the given quadratic function h(t) = -16t2 + 64t + 80, we need to find the vertex of the parabola. The vertex form of a parabola is y = a(x - h)2 + k, where (h, k) is the vertex of the parabola. Since our parabola opens downward (a = -16), the vertex will represent the maximum point.
The vertex of the parabola h(t) can be found by using the formula h = -b/2a, where a and b are coefficients from the quadratic equation in the form ax2 + bx + c. In this case, a = -16 and b = 64. Plugging these values into the vertex formula, we get h = -64/(2*-16), which simplifies to h = 2 seconds. This is the time at which the maximum height is reached.
Now, we can find the maximum height by substituting t = 2 back into the original equation to get h(2) = -16(2)2 + 64(2) + 80, which equals 144 feet. Therefore, the maximum height reached by the stone is 144 feet.
Are radio waves transverse or longitudinal
Answer:
Transverse
Explanation:
There are two types of waves, depending on the direction of the oscillation:
- Transverse wave: in a transverse wave, the direction of the oscillation is perpendicular to the direction of motion of the wave - examples of transverse waves are electromagnetic waves
- Longitudinal wave: in a longitudinal wave, the direction of the oscillation is parallel to the direction of motion of the wave - examples of longitudinal waves are sound waves
Radio waves are a type of electromagnetic waves - consisting of oscillations of electric and magnetic field that propagate in a vacuum at the speed of light - so they are an example of transverse wave.
Which of the following statements about Einstein’s explanation of the photoelectric effect is not correct?a) High-frequency photons contribute energy above the work function energy to the electron's kinetic energy. b)The energy of a photon is directly related to its frequency, thus photons below a given frequency will not have sufficient energy to cause the ejection of an electron from a metal. c) Because light is packaged discretely, increasing the intensity of light will increase the number of photons hitting a metal and thus the likelihood that an electron will be ejected. d) The kinetic energy of electrons leaving the metal does not depend on the intensity of the light because intensity only affects the numbers of light packages, not their energy.
Answer:
c) Because light is packaged discretely, increasing the intensity of light will increase the number of photons hitting a metal and thus the likelihood that an electron will be ejected.
Explanation:
In the photoelectric effect, light incident with a certain frequency causes the emission of photoelectrons from the surface of a metal. This effect is explained by considering light a "package" of several quanta, called photons: each photon hits only 1 electron at time, giving all its energy to the electron. If the energy given is above the work function, then the electron has enough energy to leave the metal.
The energy given off by the photon only depends on the frequency of the light, not on the intensity, according to the formula
[tex]E=hf[/tex]
where h is the Planck constant and f the frequency.
In this model, one photon hits only 1 electron at time: this means that the intensity of light (which is a measure of the number of photons in the light) does not affect the probability of emitting an electron from the material, because that probability depends only on the energy of the photon, which depends only on the frequency of the light.
So, statement c) is wrong.
Final answer:
The correct statement about Einstein's explanation of the photoelectric effect is that the kinetic energy of the ejected electrons is directly related to the frequency of the light.
Explanation:
In Einstein's explanation of the photoelectric effect, statement d) The kinetic energy of electrons leaving the metal does not depend on the intensity of the light because intensity only affects the numbers of light packages, not their energy, is not correct.
The correct statement is that the kinetic energy of the ejected electrons is directly related to the frequency of the light. Higher frequency photons have more energy, and when they strike the metal surface, they can transfer enough energy to the electrons to overcome the work function and eject them.
Additionally, increasing the intensity of the light does not increase the energy of the individual photons, but it does increase the number of photons hitting the metal. This can increase the number of ejected electrons, but the kinetic energy of each individual electron is determined by the frequency of the photons, not the intensity of the light.