A model for my number has 2 hundreds blocks no tens blocks and 3 ones blocks

Answers

Answer 1
2 hundreds + 0 tens + 3 ones
200 + 0 + 3
203

Related Questions

Choose the compound inequality that can be used to solve the original inequality |3x – 5| > 10.

A. –10 < |3x – 5| < 10

B. 3x – 5 > –10 or 3x – 5 < 10

C. 3x – 5 < –10 or 3x – 5 > 10

D. –10 < 3x – 5 < 10

Answers

C i think , look at it maybe true

Compound inequality is the combination of more than one inequality.

The compound inequality from [tex]|3x - 5| > 10[/tex] is:

(c) [tex]3x - 5 < -10[/tex] or [tex]3x - 5 > 10[/tex]

Given that:

[tex]|3x - 5| > 10[/tex]

When the above inequality is split, we have the following inequalities:

[tex]3x - 5 > 10[/tex]. [tex]3x - 5 < -10[/tex]

So, the result of the split is:

[tex]3x - 5 < -10[/tex] or [tex]3x - 5 > 10[/tex]

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Set up a proportion for the problem below:

15 is 1 1/2% of what number?

Please answer ASAP!! Thank you :)

Answers

let's say that number is "x", therefore "x" is the 100%, and we know that 15 is 1 and 1/2% of that,

[tex]\bf \begin{array}{ccll} amount&\%\\ \text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\ x&100\\ 15&1\frac{1}{2} \end{array}\implies \cfrac{x}{15}=\cfrac{100}{1\frac{1}{2}}\implies \cfrac{x}{5}=\cfrac{100}{\frac{3}{2}}\implies \cfrac{x}{5}=\cfrac{\frac{100}{1}}{\frac{3}{2}} \\\\\\ \cfrac{x}{5}=\cfrac{100}{1}\cdot \cfrac{2}{3}\implies \cfrac{x}{5}=\cfrac{200}{3}[/tex]

HURRY

At the grocery store checkout, you watch at the register as it rings up your purchases and coupons. The prices are as follows: $2.95 $1.19 $4.61 $1.74 $3.04 $8.83 $1.16 − $0.75 (coupon) − $1.00 (coupon) The register gives your total bill as $21.77. Round each price and coupon to the nearest dollar and then estimate the total amount of the bill. Using your estimate, determine whether the total on the register is reasonable. Justify your answer.

Answers

$3, $1, $5, $2, $3, $9, $1 = $24 - $1 = $23 - $1 = $22.

$22 is the estimation of the bill when all of the amounts are rounded to the nearest dollar. The estimation is greater than the total bill which is 23 cents less than the estimation. The total on the register is reasonable and accurate.

Which number sentence correctly solves this problem?

Mount Everest is 8,848 meters high. K2 Mountain is 8,611 meters high. How much higher is Mt. Everest than K2 Mountain?



A.
8,848 + 8,611 = 17,459


B.


8,848 – 8,611 = 1,237


C.


8,848 – 8,611 = 237


D.
8,848 + 8,611 = 16,459

Answers

its c because when you subtract the two mountains you will get 237

How can you use transformations to graph this function?

y=3x[tex] 7^{-x} [/tex]+2

Answers

[tex]\bf \qquad \qquad \qquad \qquad \textit{function transformations} \\ \quad \\\\ % left side templates \begin{array}{llll} f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}} \\ \quad \\ y=&{{ A}}({{ B}}x+{{ C}})+{{ D}} \\ \quad \\ f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}} \\ \quad \\ f(x)=&{{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}} \\ \quad \\ f(x)=&{{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}} \end{array}\\\\ --------------------[/tex]

[tex]\bf \bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\ \bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}\\ \left. \qquad \right. \textit{reflection over the x-axis} \\\\ \bullet \textit{ flips it sideways if }{{ B}}\textit{ is negative}\\ \left. \qquad \right. \textit{reflection over the y-axis}[/tex]

[tex]\bf \bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\ \left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\ \left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\ \bullet \textit{ vertical shift by }{{ D}}\\ \left. \qquad \right. if\ {{ D}}\textit{ is negative, downwards}\\\\ \left. \qquad \right. if\ {{ D}}\textit{ is positive, upwards}\\\\ \bullet \textit{ period of }\frac{2\pi }{{{ B}}}[/tex]

with that template in mind, let's check

[tex]\bf y=\stackrel{A}{3}(7^{\stackrel{B}{-1}x})\stackrel{D}{+2}[/tex]    <---- so the parent function will then be y = 7⁻ˣ

A = 3    it shrinks, in relation the y-axis, by a factor of 3 times, so is narrower.

B=-1     well, it flips it sideways, reflection over the y-axis.

D= +2  well, that's just a vertical shift of 2 units.

Sketch the graph of Y=7^X.

Reflect the graph across the y-axis to show the function y=7^-x.

Stretch the graph vertically by a factor of 3 to show the function y=3 x 7^-x.

Shift the graph up 2 units to show the function y= 3 x 7^-x +2

What is 27 multiplied by 36 worked out?

Answers

    1
    4
    36
    27
 x___ 
    252
    72
   _____
    972

write an addition problem that has sum of 8/5

Answers

3/5 + 5/5 = 8/5

4/5 + 4/5 = 8/5

7/5 + 1/5 = 8/5

8/10 + 8/10 = 8/5

These are just a few examples

hope this helps

Valerie earns $24 per hour. Which expression can be used to show how much money she earns in 7 hours?

A. ( 7 + 20 ) + ( 7 + 4 )

B. ( 7 x 20 ) + ( 7 x 4 )

C. ( 7 + 20 ) x ( 7 + 4 )

D. ( 7 x 20 ) x ( 7 x 4 )

Who ever answers the best gets brainliest!

Answers

The answer is B) (7x20) + (7x4)
The answer is B (7•20)•(7+4)

At each turn, a gambler bets a certain amount, wins it with probability p and loses it with probability q = 1−p. when he begins playing, he has $k for some integer k > 0 and his goal is to reach $n for some integer n > k, after which he stops playing. he also stops playing if he loses all his money. the gambler has the option of betting $1 at each turn and the option of betting $0.5 at each turn. show that betting $0.5 is a better option if p > 1/2 and that betting $1 is a better option if p < 1/2.

Answers

Here two cases of the probability,
p > 1/2 or p <1/2

Here, q = 1 - p
So, When p > 1/2 the q < 1/2 &
When p < 1/2 the q > 1/2

So, in first case (p > 1/2 the q < 1/2) Winning chances is more compare to Loosing, So put the Bet maximum and is of $1

Another case (p < 1/2 the q > 1/2) Winning chances is less compare to Loosing, So put the Bet minimum and is of $0.5

How to find the sum of the forces in the y direction of an elevator?

Answers

The way to calculate the sum of the forces in the y direction of an elevator; has been outlined below

Equilibrium of Forces

If you are in an elevator by itself, then the combined system of you and the elevator could have 3 possible situations which are;

The elevator has no acceleration because it is standing still or moving with constant velocity.The elevator has an upward acceleration because it is accelerating upward, or decelerating while it's way down.The elevator has a downward acceleration since it is accelerating down, or decelerating while on the way up.

Now, in the vertical y direction, there are three forces namely;

The force of gravity.A downward normal force.An upward force from the tension in the cable holding the elevator.

Thus, the sum of forces in the y-direction with the normal force acting on you from the elevator are any of the following;

N = mg;  provided that the elevator is at rest or moving at constant velocity.

N = mg + ma; Provided that the elevator has an upward acceleration.

N = mg - ma; Provided that the elevator has a downward acceleration.

Read more about Sum of Forces at; https://brainly.com/question/20892645

Final answer:

In an elevator at rest, the sum of the forces in the y direction is equal to the weight of the person.

Explanation:

If the elevator is at rest, the sum of the forces in the y direction is equal to zero. This means that the upward force exerted by the scale, Fs, must be equal to the downward force exerted by the weight of the person, w. According to Newton's third law, Fs and Fp (the force exerted by the person on the scale) are equal in magnitude and opposite in direction.

To find the value of Fs, we can apply Newton's second law, which states that the net force in the y direction is equal to the mass of the object times its acceleration. In this case, the net force is Fs - w and the acceleration is zero. Therefore, Fs = w.

So, the sum of the forces in the y direction of the elevator is equal to the weight of the person.

At a rate of 4%, you paid $144.00 in interest over a two-year period. What was the original amount of your loan?

A. $2,000.00
B. $2,550.00
C. $2,250.00
D. $1,800.00

Answers

Simple interest - not compounded you got $ 1,800 
Formula

I= P x r x t
where:
I= Interest 
P is the principal amount, $1800.00.
r is the interest rate, 4% per year, or in decimal form, 4/100=0.04.
t is the time involved, 2 year(s) time periods.

So, t is 2 year time periods.
To find the simple interest, we multiply 1800 × 0.04 × 2 to get that: $144.00
The formula that will be used here is: I = PRT,
Where I = interest = $144.00
P = principal = ?
R = rate = 4% = 0.04
T = time = 2 years
I = PRT
P = I / RT
P = 144 / [0.04 * 2] = 144 / 0.08
P = 1800.
Therefore, the principal is $1,800.00.
The correct answer is D.

A quotient of 8.4×10^9 and a number n results in 5.6×10^27 what is the value of n

Answers

Translated to notation, this question is asking you to solve for n when:

[tex] \frac{8.4\times10^9}{n}=5.6\times10^{27} [/tex]

A good first step would be to multiply both sides by n, cancelling out the n in the denominator on the left side and leaving you with:

[tex]8.4\times10^9=(5.6\times10^{27})n[/tex]

And of course, to get n by itself from here, you simply divide both sides by [tex]5.6\times10^{27}[/tex]:

[tex]n= \frac{8.4\times10^9}{5.6\times10^{27}} [/tex]

If the variance of a probability was computed to be 3.6 grams, what is the standard deviation

Answers

the standard deviation is the square root of the variance
so if the variance is 3.6, the standard deviation is the sqrt 3.6...
sqrt 3.6 = 1.897 <= if u need it rounded, it is 1.9 grams
Final answer:

The standard deviation is the square root of the variance, which is about 1.897 grams when the variance is 3.6 grams.

Explanation:

If the variance of a probability was computed to be 3.6 grams, the standard deviation is the square root of the variance. To calculate the standard deviation, you perform the following steps:

First, recognize that variance (σ²) is the square of the standard deviation (σ).To find the standard deviation, take the square root of the variance.Therefore, the standard deviation is √3.6 g.

By using a calculator, we find that the standard deviation is approximately 1.897 grams.

Which statements about the sum of the interior angle measures of a triangle in Euclidean and non-Euclidean geometries are true?
A) In Euclidian geometry the sum of the interior angle measures of a triangle is 180 degrees, but in elliptical or spherical geometry the sum is less than 180 degrees.
B) In Euclidian geometry the sum of the interior angle measures of a triangle is 180 degrees, but in elliptical or spherical geometry the sum is greater than 180 degrees.
C) In Euclidian geometry the sum of the interior angle measures of a triangle is less than 180 degrees, but in hyperbolic geometry the sum is equal to 180 degrees.
D) In Euclidian geometry the sum of the interior angle measures of a triangle is greater than 180 degrees, but in hyperbolic geometry the sum is less than 180 degrees.
In Euclidian geometry the sum of the interior angle measures of a triangle is 180 degrees, but in hyperbolic geometry the sum is less than 180 degrees.

Answers

In Euclidian geometry the sum of the interior angle measures of a triangle is 180 degrees, but in elliptical or spherical geometry the sum is greater than 180 degrees. As well as In Euclidian geometry the sum of the interior angle measures of a triangle is 180 degrees, but in hyperbolic geometry the sum is less than 180 degrees. Are the answers.

The statements that are true about the information given will be:

In Euclidian geometry, the sum of the interior angle measures of a triangle is 180 degrees, but in elliptical or spherical geometry the sum is greater than 180 degrees.In Euclidian geometry the sum of the interior angle measures of a triangle is 180 degrees, but in hyperbolic geometry the sum is less than 180 degrees.

It should be noted that Euclidian geometry is simply about understanding the geometry of flat, two-dimensional spaces while non-Euclidian geometry is about curved surfaces.

Read related link on:

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Convert 4 fluid ounces of soap per quart of water to cups of soap per gallon of water.

Answers

Attached a solution and showed work.

whole numbers includes zero but natural numbers do not

Answers

That is most certainly true!

I'm currently learning about this too. 

I hope this helps you! :)

This is a true statement!

The set of counting numbers {1, 2, 3, 4, 5, ...} is called the set of natural numbers. The natural numbers begin at 1 and go on indefinitely.

When we include 0 in the natural numbers, we then have a new set of numbers called the whole numbers. All the natural numbers are contained within the set of whole numbers.

What are the amplitude, period, and midline of f(x) = −4 cos(2x − π) + 3?

Answers

[tex]\bf \qquad \qquad \qquad \qquad \textit{function transformations} \\ \quad \\ % function transformations for trigonometric functions \begin{array}{rllll} % left side templates f(x)=&{{ A}}sin({{ B}}x+{{ C}})+{{ D}} \\\\ f(x)=&{{ A}}cos({{ B}}x+{{ C}})+{{ D}}\\\\ f(x)=&{{ A}}tan({{ B}}x+{{ C}})+{{ D}} \end{array} \\\\ -------------------\\\\[/tex]

[tex]\bf \bullet \textit{ stretches or shrinks}\\ \left. \qquad \right. \textit{horizontally by amplitude } |{{ A}}|\\\\ \bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}\\ \left. \qquad \right. \textit{reflection over the x-axis} \\\\ \bullet \textit{ flips it sideways if }{{ B}}\textit{ is negative}\\ \left. \qquad \right. \textit{reflection over the y-axis}[/tex]

[tex]\bf \bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\ \left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\ \left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\ \bullet \textit{vertical shift by }{{ D}}\\ \left. \qquad \right. if\ {{ D}}\textit{ is negative, downwards}\\\\ \left. \qquad \right. if\ {{ D}}\textit{ is positive, upwards}[/tex]

[tex]\bf \bullet \textit{function period or frequency}\\ \left. \qquad \right. \frac{2\pi }{{{ B}}}\ for\ cos(\theta),\ sin(\theta),\ sec(\theta),\ csc(\theta)\\\\ \left. \qquad \right. \frac{\pi }{{{ B}}}\ for\ tan(\theta),\ cot(\theta)[/tex]

with that template in mind, let's check

[tex]\bf f(x)=-\stackrel{A}{4}(\stackrel{B}{2}x\stackrel{C}{-\pi } )\stackrel{D}{+3}\\\\ -------------------------------\\\\ Amplitude\implies 4\\\\ Period\implies \cfrac{2\pi }{B}\implies \cfrac{2\pi }{2}\implies \pi [/tex]

now, the function is just the parent cos(x), shrunk some, -4, and shifted about, now D = +3, that means it has a vertical shift of 3 units up.

the parent function cos(x), has a midline of y = 0, now, if we shift it upwards by 3 units, the new midline will then be y = 3.

write the equation for a line that intersects points (1,3) and (2,5)

Answers

y=2x+1 is your answer
y=2x+1 is the correct answer

In a certain game, a player can solve easy or hard puzzles. A player earns 30 points for solving an easy puzzle and 60 points for solving a hard puzzle. Tina solved a total of 50 puzzles playing this game, earning 1,950 points in all. How many hard puzzles did Tina solve? A) 10 B) 15 C) 25 D) 35

Answers

The answer is C. 25...

Answer:

B) 15

Step-by-step explanation:

In order to solve this we have to create a system of equations, where the easy puzzles are represented by x, and the hard puzzles are y, so you just have to multiply that for the points to get the total points in all:

30x+60y=1950

If the player did 50 in total:

x+y=50

Now we just solve for x in the second equation and then insert that into the first equation:

x=50-y

30(50-y)+60y=1950

1500-30y+60y=1950

30y=450

y=450/30

y=15

So we know that Tina solved 15 hard puzzles.

Find f '(−5), if f(x) = (−4x2 − 2x)(−x2 − 9)

Answers

*Answer*
x+0 or x=-0.63297

heres step by step
−5x=(−4x2−2x)(−x2−9)−5x=4x4+2x3+36x2+18x
heres step by step

Step 1: Subtract 4x^4+2x^3+36x^2+18x from both sides

−5x−(4x4+2x3+36x2+18x)=4x4+2x3+36x2+18x−(4x4+2x3+36x2+18x)−4x4−2x3−36x2−23x=0

Step 2: Factor left side of equation

x(−4x3−2x2−36x−23)=0Step 3: Set factors equal to 0.x=0 or −4x3−2x2−36x−23=0x=0 or x=−0.63297

Answer: the answer is -2192

which of the following is a correct interpretation of the expression -2+(-7)

Answers

I think the answer is negative 9.  

The correct interpretation of -2 + (-7) is that "the number 7 is to the left of -2 on the number line".

The correct interpretation of the expression -2 + (-7) which is results in -9.

Let's break this down:

-2 is our starting point on the number line. + (-7) means we move 7 units to the left of -2 (since adding a negative number is equivalent to subtraction).

When we move 7 units left from -2, we land on -9.

Thus, -2 + (-7) results in -9, which confirms that we have moved 7 to the left of -2 on the number line.

Complete question:

Which of the following is a correct interpretation of the expression -2 + (-7)?

Choose 1 answer:

The number that is 2 to the left of 7 on the number lineThe number that is 2 to the right of 7 on the number lineThe number that is 7 to the left of −2 on the number lineThe number that is 7 to the right of −2 on the number line

A student is taking a test. He has 37 questions left. If the test has 78 questions

Answers

a. Let x  represent the number of questions finished.
b. The equation is  x + 37 = 78 , and solving yields  x = 41 .
c. The student finished 41 questions.

a. Define a variable for the unknown value. Let  x  represent the number of questions the student has finished.

b. Write and solve the equation. The total number of questions is the sum of the questions finished and the questions left:  x + 37 = 78 . Now solve for  x :

x = 78 - 37 = 41

So, the student has finished 41 questions.

c. Answer the question with the correct units. The student has finished 41 questions out of the total 78. Therefore, the student has [tex]\( \frac{41}{78} \)[/tex] of the test complete. To express this as a percentage, multiply by 100:

[tex]\[ \frac{41}{78} \times 100 \approx 52.56\% \][/tex]

The student has finished approximately 52.56% of the test.

Que. A student is taking a test. He has 37 questions left. If the test has 78 questions, how many questions has he finished? a. Define a variable for the unknown value. Let ...........represent............
b. Write and solve the equation.
c. Answer the question with the correct units........

Find the LCM of 8 and 12.

Answers

✨24✨

the least common multiple is 24, the greatest common diviser is 4
You need to write out the 8 and the 12 times table and you then find the lowest number that is the same:

8:
8,16,24,32

12:
12,24,36,48

As you can see the lowest number that is the same for both of them is 24, thus the lowest common multiple is 24.

Hope this helps! :)

How many grains of sand in a 10kg bag if one grain weighs 10 to the negative third gram

Answers

If one grain of sand weighs 10^-3 gram, it is one thousandths of a gram. A kilogram (kg), is 1000 times the mass of a gram. So, you take the 10 kg and multiply by a conversion factor of 1 kg equaling 1000g. This results in you having 10000 grams. Multiply that by another thousand, seeing as each grain of sand weighs one thousandth of a gram. This should result in you getting 10000000, or 1.0 x 10^7 grains of sand.

Final answer:

To determine the number of grains of sand in a 10kg bag with each grain weighing 10 to the negative third gram, convert the weight to grams and then divide by the weight of one grain. The answer is 10 million grains.

Explanation:

Grains of sand in a 10kg bag can be calculated by converting the weight to grams first: 10kg = 10,000g. Then, since each grain weighs 10-3g, we divide the total weight by the weight of one grain: 10,000g / 10-3g = 10,000,000 grains. So, there are 10 million grains of sand in a 10kg bag.

The picture shows a triangular island Which expression shows the value of Q?

Answers

In trigonometric ratios, the cos (x) = adjacent over hypotenuse.

Therefore, in the diagram,  cos (55°) = s/q
To isolate q, divide both sides by s
cos (55°) / s = 1/ q
Then flip both numerators and denominators (raise both sides to the power of -1)
q = s / cos (55°)

Answer is D

S/cos 55• the answer D

Hey guys, I need help answering this question for my Algebra 2 class.

Answers

Put into standard form:  y^2 - 20x - 6y - 51 = 0
We can see immediately that this is a horiz. parabola, because y is squared, not x.  Because y^2 and x are both positive, we know that the parabola opens to the right.  Where is the vertex?

y^2 - 6y + 9 - 9 -51 = 20 x (after completing the square)
Then (y-3)^2 - 60 = 20x, or   (1/20)(y-3)^2 -3 = x, or (1/20)(y-3)^2=x+3
The vertex is at (-3,3).  


Comparing       (1/20)(y-3)^2=x+3   to   x-h = 4p(y-3)^2, we see that p = 1/80

The focus is p units to the right of the vertex, at (-3+1/80, 3).

The directrix, a vertical line, is p units to the left of the vertex, at x = -3-1/80.

Please ask questions if need be.

Which property is demonstrated below?

17/3 * 3/17=1

associative property of multiplication
inverse property of multiplication
identity property of multiplication
commutative property of multiplication

Answers

we know that

The Inverse Property of Multiplication states that the product of any number and its multiplicative inverse is one

so

[tex]\frac{a}{b}* \frac{b}{a}=1[/tex]

in this problem we have

[tex]\frac{a}{b}=\frac{17}{3}[/tex]

[tex]\frac{b}{a}=\frac{3}{17}[/tex] -----> multiplicative inverse of [tex]\frac{a}{b}[/tex]

substitute

[tex]\frac{17}{3}*\frac{3}{17}=1[/tex]

therefore

the answer is

inverse property of multiplication


Answer:

inverse property of multiplication or b on edg 2021

Step-by-step explanation:

The perimeter of a rectangular field is 264 yards. If the width of the field is 54 yards, what is its length?

Answers

P = 2(L + W)
P = 264
W = 54

264 = 2(L + 54)
264 = 2L + 108
264 - 108 = 2L
156 = 2L
156/2 = L
78 <=== Length is 78 yards
First, we must multiple the width by two. Then, we subtract the perimeter by that number. Next, we divide the number we have by two.

54 * 2 = 108
264 - 108 = 156
156 / 2 = 78

The perimeter is 78 yards.

a skirt that usually sells for $40 is on sale for $30. What is the discount percent?
A) 20%
B) 25%
C) 27%
D) 30%

Answers

That would be B) 25% off. Hope this helps!
Using "x" as the unknown, the equation would be 40x=30. Solving for x, you get ".75" or 75% meaning that 30 is 75% of 40. The discount, is just the difference between "x" and 100%, so 100%-75% is 25%. The answer is (B) 25%.

The length of a rectangle is three times its width. If the area of the rectangle is 192 ft^2, find its perimeter

Answers

Answer: 64 feet.

Explanation:
Perimeter formula: 2l + 2w
Area formula: l•w
Length = 3w
Area = 192 ft[tex] ^{2} [/tex]
192 = (3w) • w 
192 = 3[tex] w^{2} [/tex]
192 ÷ 3 = 3[tex] w^{2} [/tex] ÷ 3
64 = [tex] w^{2} [/tex] 
[tex] \sqrt{64} [/tex] = [tex] \sqrt{ w^{2} } [/tex]
8 = w 

Width = 8
Length = 3(8) = 24 
Perimeter = 2(24) + 2(8) = 64 feet.

Lets x = width
length = 3x

A = length times width
A = x * 3x
192 = 3x^2
192/3 = x^2
64 = x^2
8 = x

so width = 8
length = 3x = 3(8) = 24

P = 2(L + W)
P = 2(24 + 8)
P = 2(32)
P = 64

answer
P = 64 feet
Other Questions
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