A multipurpose transformer has a secondary coil with several points at which a voltage can be extracted, giving outputs of 5.60, 12.0, and 480 V. (a) The input voltage is 240 V to a primary coil of 280 turns. What are the numbers of turns in the parts of the secondary used to produce the output voltages? (b) If the maximum input current is 5.00 A, what are the maximum output currents (each used alone)?

Answer:

c. electric attraction is a force that can act at a distance.

Explanation:

stuisland

Final answer:

A negatively charged balloon attracting positively charged hair strands without contact illustrates that c. electric attraction can act at a distance.

Explanation:

When Katie rubs the balloon against her hair, electrons move from her hair to the balloon, resulting in the balloon having a negative charge and her hair having a positive charge. If the negatively charged balloon is brought near Katie's hair and the hair strands move toward it without direct contact, this demonstrates electric attraction as a force that can act at a distance.

Therefore, electric attraction is a force that can act at a distance. This example, similar to the effect observed when someone touches a Van de Graaff generator, shows charge separation and induction. It validates the scientific concept that electric forces can operate between charged objects even when they are not in physical contact.

Answer:

q₁  = -2.92 nC

Explanation:

Given;

first point charge, q₁ = ?

second point charge, q₂ = 10 nC

net flux through the surface of the sphere, Φ =  800 N.m²/C

According to Gauss’s law, the flux through any closed surface (Gaussian surface), is equal to the net charge enclosed divided by the permittivity of free space.

[tex]\phi = \frac{q_{enc.}}{\epsilon_o}[/tex]

where;

Φ is net flux

[tex]q_{enc.}[/tex] net charge enclosed

ε₀ is permittivity of free space.

[tex]q_{enc.}[/tex] = Φε₀

       = 800 x 8.85 x 10⁻¹²

       = 7.08 x 10⁻⁹ C

[tex]q_{enc.}[/tex] = 7.08 nC

q₁ + q₂ = [tex]q_{enc.}[/tex]

q₁ = [tex]q_{enc.}[/tex] - q₂

q₁  = 7.08nC -  10 nC

q₁  = -2.92 nC

Answer:

3.83*10^7 m

Explanation:

Assume that the distance at which gravitational force due to both Earth and moon is zero and it l is given by force force balance

F(moon) = F(earth)

F(moon) = GM(moon) / r²

F(earth) = GM(earth) / (d - r)²

If F(moon) = F(earth), then

GM(moon) / r² = GM(earth) / (d - r)²

7.35*10^22 / r² = 5.97*10^24 / (3.84*10^8 - r)²

now, we take the square root of both sides, we have

2.71*10^11 / r² = 24.4*10^11 / (3.84*10^8 - r) =>

2.71 / r² = 24.4 / (3.84*10^8 - r)

if we cross multiply, we have

24.4r = 1.04064*10^9 - 2.71r

24.4r + 2.71r = 1.04064*10^9

27.11r = 1.04064*10^9

r = 1.04064*10^9 / 27.11

r = 3.83*10^7 m

Answer:

Explanation:

flux through the coil = NBA

Change in flux = NBA - 0 = NBA

rate of change of flux = NBA / Δt

emf induced = NBA / Δt

current i = emf / resistance

= NBA / (RΔt)

Charge flowing through the search coil

=  NBA Δt/ (RΔt)

Q = NBA/R

Answer:

When they are approaching each other

    [tex]f_a = 2228.7 \ Hz[/tex]

When they are passing  each other

    [tex]f_a = 2100Hz[/tex]

 When they are retreating  from each other

     [tex]f_a = 1980.7 Hz[/tex]

Explanation:

From the question we are told that

     The velocity of car one is  [tex]v_1 = 13.0 m/s[/tex]

      The velocity of car two is  [tex]v_2 = 7.22 m/s[/tex]

     The frequency of sound from car one is  [tex]f_e = 2.10 kHz[/tex]

Generally the speed of sound at normal temperature is  [tex]v = 343 m/s[/tex]

  Now as the cars move relative to each other doppler effect is created and this  can be represented  mathematically  as

              [tex]f_a = f_o [\frac{v \pm v_o}{v \pm v_s} ][/tex]

Where [tex]v_s[/tex] is the velocity of the source of sound

            [tex]v_o[/tex] is the velocity of the observer of the sound

            [tex]f_o[/tex] is the actual frequence

             [tex]f_a[/tex]  is the apparent frequency

Considering the case when they are approaching each other

        [tex]f_a = f_o [\frac{v + v_o}{v - v_s} ][/tex]

          [tex]v_o = v_2[/tex]  

         [tex]v_s = v_1[/tex]

         [tex]f_o = f_e[/tex]

Substituting value

            [tex]f_a = 2100 [\frac{343 + 7.22}{ 343 - 13} ][/tex]

              [tex]f_a = 2228.7 \ Hz[/tex]

Considering the case when they are passing  each other    

At that instant

                  [tex]v_o = v_s = 0m/s[/tex]

                   [tex]f_o = f_e[/tex]

               [tex]f_a = f_o [\frac{v }{v } ][/tex]

              [tex]f_a = f_o[/tex]

Substituting value

             [tex]f_a = 2100Hz[/tex]

Considering the case when they are retreating  from each other    

                [tex]f_a = f_o [\frac{v - v_o}{v + v_s} ][/tex]

          [tex]v_o = v_2[/tex]  

         [tex]v_s = v_1[/tex]

         [tex]f_o = f_e[/tex]      

Substituting value

         [tex]f_a = 2100 [\frac{343 - 7.22}{343 + 13} ][/tex]    

          [tex]f_a = 1980.7 Hz[/tex]    

Ball 1 floats with half exposed above water level. Tension on rope holding Ball 2 is calculated using weight and buoyant force. Tension on rope holding Ball 3 is equal to buoyant force.

A. Ball 1 is floating with half of it exposed above the water level.

This means that the buoyant force on the ball is equal to the weight of the ball.

Since the buoyant force is greater than the weight of the ball, the ball floats.

B. The tension on the rope holding Ball 2 can be found using the equation:

Tension = Weight - Buoyant force.

The weight of the ball is calculated by multiplying its volume by its density and acceleration due to gravity.

The buoyant force can be found by multiplying the volume of the ball submerged in water by the density of water and acceleration due to gravity.

C. The tension on the rope holding Ball 3 is the same as the buoyant force acting on it.

The buoyant force can be found by multiplying the volume of the ball submerged in water by the density of water and acceleration due to gravity.

Ball 1's density is 500 kg/m³. The tension on the rope holding Ball 2 is 41.15 N. The tension on the rope holding Ball 3 is 121.24 N.

Let's solve this problem step-by-step to better understand floating and submerged objects in water.

A.) Which is true for Ball 1?

Ball 1 floats with half of it exposed above the water level. This means the density of Ball 1 must be half the density of water. Since the density of water is 1000 kg/m³, the density of Ball 1 is:

B.) What is the tension on the rope holding the second ball, in newtons?

Ball 2 has a density of 893 kg/m³ and is held below the surface of water. The buoyant force is equal to the weight of the volume of water displaced by Ball 2.

Calculate the volume of Ball 2: (Volume of a sphere = 4/3 π r³)

Calculate the buoyant force:

Calculate the weight of Ball 2:

Calculate the tension in the rope:

C.) What is the tension on the rope holding the third ball in N?

Ball 3 has a density of 1320 kg/m³ and is also fully submerged, suspended by a rope.

Calculate the weight of Ball 3:

Calculate the tension in the rope:

This example shows how to calculate buoyant forces and tensions for submerged and floating objects.

Answer:

t = 10 minutes

Emma’s scarf will be longer than tish scarf after 10 minutes

Explanation:

Given;

The length of tish scarf after t minutes can be written as;

L1 = 17.75 + 2 3/8 ×t

L1 = 17.75 + 2.375t

The length of emma scarf after t minutes can be written as;

L2 = 4 + 3 3/4 × t

L2 = 4 + 3.75t

For emma scarf to be longer than tish;

L2 >/= L1

At L2 = L1

4+3.75t = 17.75 + 2.375t

Solving for t

3.75t - 2.375t = 17.75 - 4

1.375t = 13.75

t = 13.75/1.375

t = 10 minutes

Emma’s scarf will be longer than tish scarf after 10 minutes

Answer:

741 J/kg°C

Explanation:

Given that

Initial temperature of glass, T(g) = 72° C

Specific heat capacity of glass, c(g) = 840 J/kg°C

Temperature of liquid, T(l)= 40° C

Final temperature, T(2) = 57° C

Specific heat capacity of the liquid, c(l) = ?

Using the relation

Heat gained by the liquid = Heat lost by the glass

m(l).C(l).ΔT(l) = m(g).C(g).ΔT(g)

Since their mass are the same, then

C(l)ΔT(l) = C(g)ΔT(g)

C(l) = C(g)ΔT(g) / ΔT(l)

C(l) = 840 * (72 - 57) / (57 - 40)

C(l) = 12600 / 17

C(l) = 741 J/kg°C

Answer:

Wavelength of the incident wave in air = 1 m

Wavelength of the incident wave in medium 2 = 0.33 m

Intrinsic impedance of media 1 = 377 ohms

Intrinsic impedance of media 2 = 125.68 ohms

Check the explanation section for a better understanding

Explanation:

a) Wavelength of the incident wave in air

The frequency of the electromagnetic wave in air, f = 300 MHz = 3 * 10⁸ Hz

Speed of light in air, c =  3 * 10⁸ Hz

Wavelength of the incident wave in air:

[tex]\lambda_{air} = \frac{c}{f} \\\lambda_{air} = \frac{3 * 10^{8} }{3 * 10^{8}} \\\lambda_{air} = 1 m[/tex]

Wavelength of the incident wave in medium 2

The refractive index of air in the lossless dielectric medium:

[tex]n = \sqrt{\epsilon_{r} } \\n = \sqrt{9 }\\n =3[/tex]

[tex]\lambda_{2} = \frac{c}{nf}\\\lambda_{2} = \frac{3 * 10^{6} }{3 * 3 * 10^{6}}\\\lambda_{2} = 1/3\\\lambda_{2} = 0.33 m[/tex]

b) Intrinsic impedances of media 1 and media 2

The intrinsic impedance of media 1 is given as:

[tex]n_1 = \sqrt{\frac{\mu_0}{\epsilon_{0} } }[/tex]

Permeability of free space, [tex]\mu_{0} = 4 \pi * 10^{-7} H/m[/tex]

Permittivity for air, [tex]\epsilon_{0} = 8.84 * 10^{-12} F/m[/tex]

[tex]n_1 = \sqrt{\frac{4\pi * 10^{-7} }{8.84 * 10^{-12} } }[/tex]

[tex]n_1 = 377 \Omega[/tex]

The intrinsic impedance of media 2 is given as:

[tex]n_2 = \sqrt{\frac{\mu_r \mu_0}{\epsilon_r \epsilon_{0} } }[/tex]

Permeability of free space, [tex]\mu_{0} = 4 \pi * 10^{-7} H/m[/tex]

Permittivity for air, [tex]\epsilon_{0} = 8.84 * 10^{-12} F/m[/tex]

ϵr = 9

[tex]n_2 = \sqrt{\frac{4\pi * 10^{-7} *1 }{8.84 * 10^{-12} *9 } }[/tex]

[tex]n_2 = 125.68 \Omega[/tex]

c) The reflection coefficient,r  and the transmission coefficient,t at the boundary.

Reflection coefficient, [tex]r = \frac{n - n_{0} }{n + n_{0} }[/tex]

You didn't put the refractive index at the boundary in the question, you can substitute it into the formula above to find it.

[tex]r = \frac{3 - n_{0} }{3 + n_{0} }[/tex]

Transmission coefficient at the boundary, t = r -1

d) The amplitude of the incident electric field is [tex]E_{0} = 10 V/m[/tex]

Maximum amplitudes in the total field is given by:

[tex]E = tE_{0}[/tex] and [tex]E = r E_{0}[/tex]

E = 10r, E = 10t

Answer:

1) The track is 200 meters long, the athletes do 4 rounds, so the total distance ran is:

4*200 meters = 800 meters

2) The displacement is defined as the difference between the final position and the initial position.

When you are in a track, and you run a full round, you end in the same position where you started, so the total displacement is 0 meters.

3) As they are running in a closed track (for example, a circular track), they must change the direction of motion at some point, so the motion is not uniform (uniform motion happens when the movement is always in the same direction and always at the same speed)

4) no, is not equal because in the end, the total distance is 800 meters and the displacement is 0 meters.

Answer:

1.3*10^14 J

Explanation:

The energy of the satellite that orbits the earth is given by the second Newton law:

[tex]F=ma_c\\\\-G\frac{mM_s}{r^2}=m\frac{v^2}{r}\\\\v^2=\frac{GM}{r}\\\\E_T=K+U=G\frac{mM_s}{2r}-G\frac{mM}{r}=-G\frac{mM}{2r}[/tex]

where you have taken into account the centripetal acceleration of the satellite.

m: mass of the satellite

M_s: mass of the sun = 1.98*10^30 kg

G: Cavendish's constant = 6.67*10^-11 m^3/kg s^2

r: distance to the center of the Earth = Earth radius + distance satellite-Earth surface

To find the needed energy, you first compute the energy for a constant altitude of 99km:

r = 6.371*10^6m + 99*10^3m = 6.47*10^6 m

[tex]E_T=-(6.67*10^-11 m^3 /kg.s^2)\frac{(969kg)(1.98*10^{30}kg)}{2(6.47*10^6)}\\\\E_T=-9.88*10^{15} \ J[/tex]

Next, you calculate the energy for an altitude of 195km:

r = 6.371*10^6m + 195*10^{3}m = 6.56*10^6 m

[tex]E_T=-(6.67*10^-11 m^3 /kg.s^2)\frac{(969kg)(1.98*10^{30}kg)}{2(6.56*10^6)}\\\\E_T=-9.75*10^{15} \ J[/tex]

Finally, the energy required to put the satellite in the new orbit is:

-9.75*10^15 J - (-9.88*10^15 J) = 1.3*10^14 J

Answer:

Explanation:

The solution to the problem is given in the pictures attached below; the three pictures explains the problem fully and I hope it helps you. Thank you

Answer:

28 grams

Explanation:

The equation for the reaction is

3H(2) + N(2) -> 2NH(3)

Then we have.

The molar mass, M of ammonia is 17 g/mol.

34 grams of ammonia, NH3 then would be

34 g / 17 g/mol

= 2 moles

2 moles of ammonia will be obtained from

(2 * 1) / 2

​= 1 mole of nitrogen

The molar masses of nitrogen is 28 g/mol

2 moles of nitrogen corresponds to 1 * 28 = 28 grams.

Answer:

10n to the right

Explanation:

Answer:[tex]d+\frac{L}{2}[/tex]

Explanation:

Given

Length of skateboard is L

distance of skateboard from the wall is d

Suppose mass of skateboard is M

so mass of Professor is M

When Professor moves towards wall skateboard started moving away from wall.

If the professor moves L distance on the skateboard

Therefore relative displacement of the skateboard is

[tex]=\frac{ML}{M+M}[/tex]

[tex]=\frac{L}{2}[/tex]

Therefore professor is at a distance of [tex]d+\frac{L}{2}[/tex] from wall

Final answer:

The professor is 0 meters from the wall when he stops at the opposite end of the skateboard from where he started.

Explanation:

To solve this problem, we can apply the principle of conservation of momentum. The initial momentum of the system, consisting of the professor and the skateboard, is equal to the final momentum of the system. Initially, both the professor and the skateboard are at rest, so the initial momentum is zero.

When the professor walks towards the wall, he exerts a force on the ground, causing an equal and opposite force on him (according to Newton's third law). This force propels the skateboard forward, resulting in a change in momentum of the professor-skateboard system. The total momentum is conserved during this process.

When the professor reaches the opposite end of the skateboard, he comes to a stop. At this point, the skateboard would have moved a certain distance, which we'll call x. If the professor and the board have the same mass, the professor would have moved a distance equal to (d + x) from the wall, while the board would have moved a distance equal to x from the wall.

From the conservation of momentum, we can write:

(0) + (m)(v) = (m)(v) + (M)(V)

Here, m represents the mass of the professor, v represents his initial velocity, M represents the mass of the skateboard, and V represents its final velocity.

Since the professor starts from rest, his initial velocity v is zero. The final velocity V of the skateboard can be calculated using the equation:

(m)(v) = (M)(V)

From the given information, we know that the professor's mass is equal to the skateboard's mass, so m = M. Plugging this into the equation, we get:

(M)(0) = (M)(V)

This simplifies to:

0 = V

Since the final velocity V of the skateboard is zero, we can conclude that the professor comes to a stop at the opposite end of the skateboard. Therefore, he would be a distance x from the wall. To find the value of x, we need to analyze the forces and motion of the system.

When the professor exerts a force on the ground, causing an equal and opposite force on him, the system experiences a net force. According to Newton's second law, the net force on the system is equal to the product of the mass of the system and its acceleration.

Let's define the positive direction as the direction the professor is moving towards the wall. The net force on the system in the positive direction is:

F_net = F_applied - F_opposing

Where F_applied is the force exerted by the professor on the ground, and F_opposing is the sum of all the opposing forces, such as friction.

Since the skateboard rolls with negligible friction, the opposing forces can be considered negligible. Therefore, we have:

F_net = F_applied

From Newton's second law, we can write:

F_net = (M + m)a

Where a is the acceleration of the system.

Plugging in the given information, we have:

150 N = (2M)a

Solving for a gives:

a = 75 N / M

Now, let's consider the motion of the skateboard. Since there is no friction, the only horizontal force acting on the skateboard is the force exerted by the professor on the ground. This force causes the skateboard to accelerate in the positive direction.

The distance x is related to the acceleration a and the time taken t to reach the opposite end of the skateboard. We can use the kinematic equation:

x = (1/2)at^2

Since the professor is initially at rest and comes to a stop at the opposite end, his final velocity vf is zero. We can use the equation:

vf = vi + at

Where vi is the initial velocity of the professor, and a is the acceleration.

Since the professor is initially at rest, his initial velocity vi is zero. Plugging in the known values, we have:

0 = 0 + (75 N / M)t

This simplifies to:

t = 0

Since the time t is zero in this case, the professor reaches the opposite end of the skateboard instantaneously. Therefore, the distance x is also zero.

In conclusion, the professor is 0 meters from the wall when he stops at the opposite end of the skateboard from where he started.

Answer:

true

Explanation:

Answer:true

Explanation:

Acceleration is measured in meters per second squared

Answer:

i need some explanation

Explanation:

The correct statements are D, C, and E. Blood flows from the heart to the lungs to pick up oxygen and then to the rest of the body to deliver oxygen, sugar, and nutrients while collecting carbon dioxide.

Understanding the flow of blood in the body is essential. Here are the correct statements regarding blood circulation:

The heart pumps oxygen-poor blood to the lungs through the pulmonary circuit where it releases carbon dioxide and picks up oxygen.

The oxygen-rich blood is then pumped through the systemic circuit to the rest of the body, delivering oxygen, sugar, and nutrients to the cells and collecting carbon dioxide to be expelled during the next circulation.

Therefore, the correct statements are D, C, and E.

Complete Question

Which statements are true about the flow of blood in the body? Check all that apply.

A. Blood picks up oxygen from the cells of the body.

B. Blood delivers carbon dioxide to cells in the body.

C. Blood picks up carbon dioxide from the cells of the body.

D. Blood flows from the heart to the lungs to pick up oxygen.

E. Blood delivers sugar and nutrients to cells in the body.

F. Blood flows from the lungs to the heart to pick up oxygen.

Answer:

The correct answer is intensity.

Explanation:

The principle of overload is a basic sports fitness training concept which means that in order to improve, athletes must continually work harder as they their bodies adjust to existing workouts. Thus, overloading also plays a role in skill learning.

Now, since erhen wants to increase his mile run from eight to six minutes by run some sandy hills near his home, it means the principle at work is making his training runs more intense for better speed results. Thus the principle at work is intensity because he is trying to do something that makes him run faster.

Final answer:

Ehren is employing the Overload Principle, focusing on the component of intensity to improve his mile run time by running up sandy hills. This method increases resistance and is aligned with the Progression Principle to safely enhance his fitness and performance.

Explanation:

Ehren is working on improving his mile run time and has decided to include running up sandy hills as part of his training. This implementation of intensity in his workouts is a component of the Overload Principle. The principle of overload necessitates a "greater than normal workload or exertion" for an individual to improve in aspects such as aerobic endurance, muscular strength, endurance, and flexibility. By running on sandy hills, Ehren increases the resistance and difficulty compared to running on a flat surface, thus intensifying his training sessions to drive physiological adaptations.

The Progression Principle is also at play here, which entails the gradual increase in stress placed on the body to safely enhance fitness without risking overuse or injury. This principle aligns with the Overload Principle, as it supports the idea of incrementally adding stress to the body through exercises to foster continual improvements. Overall, Ehren's choice to run sandy hills is applying both the intensity and progression components of the overload to achieve his goal of increasing his running pace.

Answer:

f = 687.85 Hz

Explanation:

Given that,

The wavelength of sound wave, [tex]\lambda=0.75\ m[/tex]

We need to find the frequency of the sound wave. The relation between wavelength and frequency is given by :

[tex]v=f\lambda[/tex]

v is speed of sound at T = 35°C = 308.15 K

[tex]v=331+0.6T\\\\v=331+0.6\times 308.15 \\\\v=515.89\ m/s[/tex]

So,

[tex]f=\dfrac{v}{\lambda}\\\\f=\dfrac{515.89}{0.75}\\\\f=687.85\ Hz[/tex]

So, the frequency of the sound is 687.85 Hz.

Final answer:

To calculate the frequency of a sound wave, use the formula frequency = speed of sound / wavelength. For this specific scenario, the frequency of the sound wave is 3400 Hz.

Explanation:

The frequency of the sound wave can be calculated using the formula:

frequency = speed of sound / wavelength

Given that the speed of sound in air is 340 m/s and the wavelength is 0.10 m, we can plug in the values to find the frequency:

frequency = 340 m/s / 0.10 m = 3400 Hz

Therefore, the frequency of the sound wave is 3400 Hz.

Answer:

Magnetic field is in south west direction .

Explanation:

Let us represent various direction by  i , j, k . i representing east , j representing north and k representing vertically upward direction .

magnetic field is represented vectorially as follows

B = B₀ ( - i - j )

In the first case velocity of electron

v = v k

Force = q ( v x B )

= -e [ vk x B₀ ( - i - j ) ]

= evB₀ ( j -i )

Direction of force is north -west .

In the second case velocity of electron

v = vj

Force = -e [ vj x B₀ ( - i - j ) ]

= - evB₀ k

force is downward

In the third case, velocity of electron

v = v( -j +i )

Force = -e [ v( -j +i ) x B₀ ( - i - j ) ]

= 2 evB₀ k

Force is upward.

Answer:

the maximum velocity of the mass v (max) = 2 ft/s

the amount of time it takes for the mass to move from its lowest position to its highest position∆t = 1/3 seconds = 0.33 seconds

Explanation:

Given the velocity equation;

v=−2 cos(3πt)

The maximum velocity would be at cos(3πt) = 1 or cos(3πt) = -1

v (max) = -2 × -1 = 2 ft/s

The time taken for the mass to move from lowest position to highest position

At Lowest position, vertical velocity equals zero.

At highest position, vertical velocity equals zero.

The time taken for the mass to move from one v = 0 to the next v = 0

Cos(π/2) = 0 and

Cos(3π/2) = 0

For the first;

Cos(3πt) = cos(π/2)

3πt1 = π/2

t1 = π/2(3π)

t1 = 1/6 second

For the second;

Cos(3πt) = cos(3π/2)

3πt2 = 3π/2

t2 = 3π/2(3π)

t2 = 1/2 second

∆t = t2 - t1 = 1/2 - 1/6 = 3/6 - 1/6 = 2/6 = 1/3 seconds

∆t = 1/3 seconds

Answer:

C

Explanation:

i took the test

A small, positively charged ball is moved close to a large, positively charged ball. "It will move away from the large ball because like charges repel." The correct option is A.

Charge Interaction: The behavior of charged objects is governed by the fundamental principle that opposite charges attract each other, and like charges repel each other.

Coulomb's Law: Coulomb's Law describes the electrostatic force between two charged objects. It states that the force of attraction or repulsion between two charged objects is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.

Repulsion: Because both the small and large balls have a positive charge, they will exert a repulsive force on each other when they are in close proximity.

Movement Away: When the small ball is released near the large ball, it will experience this repulsive force, causing it to move away from the large ball.

Try to know more about positively:

https://brainly.com/question/23709550

#SPJ12

Answer:

a)   E = 8.63 10³ N /C,  E = 7.49 10³ N/C

b)   E= 0 N/C,  E = 7.49 10³ N/C  

Explanation:

a)  For this exercise we can use Gauss's law

         Ф = ∫ E. dA = [tex]q_{int}[/tex] /ε₀

We must take a Gaussian surface in a spherical shape. In this way the line of the electric field and the radi of the sphere are parallel by which the scalar product is reduced to the algebraic product

The area of ​​a sphere is

        A = 4π r²

if we use the concept of density

        ρ = q_{int} / V

        q_{int} = ρ V

the volume of the sphere is

      V = 4/3 π r³

we substitute

         E 4π r² = ρ (4/3 π r³) /ε₀

         E = ρ r / 3ε₀

the density is

         ρ = Q / V

         V = 4/3 π a³

         E = Q 3 / (4π a³) r / 3ε₀

         k = 1 / 4π ε₀

         E = k Q r / a³

let's calculate

for r = 4.00cm = 0.04m

        E = 8.99 10⁹ 3.00 10⁻⁹ 0.04 / 0.05³

        E = 8.63 10³ N / c

for r = 6.00 cm

in this case the gaussine surface is outside the sphere, so all the charge is inside

         E (4π r²) = Q /ε₀

         E = k q / r²

let's calculate

         E = 8.99 10⁹ 3 10⁻⁹ / 0.06²

          E = 7.49 10³ N/C

b) We repeat in calculation for a conducting sphere.

For r = 4 cm

In this case, all the charge eta on the surface of the sphere, due to the mutual repulsion between the mobile charges, so since there is no charge inside the Gaussian surface, therefore the field is zero.

         E = 0

In the case of r = 0.06 m, in this case, all the load is inside the Gaussian surface, therefore the field is

        E = k q / r²

      E = 7.49 10³ N / C

Answer:

fR = f(c + v)/c

Explanation:

The speed of a wave is its frequency x wavelenght. Therefore,

Frequency is speed of wave over the wavelength.

Since the source (ultrasound machine) is stationary, and the receiver red blood cell is moving towards it. The wavelenght of the wave sent out towards the observer is c/f

The speed of the reflected sound wave is (c + v), so that the reflected frequency fR is given by

fR = f(c + v)/c

The measured reflected frequency (  fR) in Doppler-shifted ultrasound, when blood cells move towards the source, is calculated using the formula  fR = f * (c + v) / c, where f is the original frequency, c is the speed of sound in blood, and v is the velocity of blood cells.

The question relates to the principle of the Doppler effect and its application in calculating the velocity of blood flow using Doppler-shifted ultrasound. The Doppler effect occurs when a wave source and an observer are in relative motion, resulting in a change in the observed frequency. Specifically, when the blood cells move towards the ultrasound source, the frequency of the reflected ultrasound increases. This change in frequency can be measured for diagnostic purposes.

To find the measured reflected frequency fR when blood cells are moving towards the source, you can use the formula:

fR = f * (c + v) / c

Where,

f = original frequency of the ultrasound

c = speed of sound in blood (or human tissue)

v = velocity of blood cells relative to the ultrasound source

Answer:

239.55 KJ

Explanation:

Given:

Mass 'm' = 106 g

Latent heat of vaporization'L'= 2260 J/g.

Molecular weight of water'M' = 18 g/mol

Pressure 'P' = 101325 Pa

Temperature 'T' = 373.15 K

Using the formula of phase change, in order to determine the amount of heat required, we have

Q = mL

Q = 106 x 2260

Q = 239560J = 239.55 KJ

Answer:

The question above is repeated twice.

Removing the repetition, we have:  A plane flies toward a stationary siren at 1/4 the speed of sound. Then the plane stands still on the ground and the siren is driven toward it at 1/4 the speed of sound. In both cases, a person sitting in the plane will hear the same frequency of sound from the siren. True or False?

The correct answer to the question is "False"

Explanation:

The question above, illustrates a phenomenon referred to as "Doppler effect"

The Doppler effect only changes the frequency of the sound which explains how wavelength changes when a wave source is moving toward or away from an object. The Doppler effect occurs when a source of waves and/or observer move relative to each other.

When a sound source is moving toward the observer (a person sitting in the plane) in the case above,  the observer will hear a higher pitch as the source approaches. That is, the plane stands still on the ground and the siren is driven toward it.This is due to a decrease in the amplitude of the sound wave.

However, If the observer moves toward the stationary source, the observed frequency is higher than the source frequency. In this case, A plane flies toward a stationary siren.

λ = v/f = vT,

where T is the period,

The relationship  between frequency, speed, and wavelength is:

f = v/λ

v represents the speed of sound through the medium.

Doppler effect depends on things moving, as the observer moves, the frequency becomes higher as the distance decreases. If the observer moves and the distance becomes larger, it means that the sound frequency becomes lower.

Final answer:

The Doppler effect explains why a person sitting in a plane moving toward or away from a stationary siren at 1/4 the speed of sound perceives the same frequency of sound. This phenomenon is true due to the relative motion between the source of sound and the observer.

Explanation:

True

The phenomenon described in the question is related to the Doppler effect in physics. When a source of sound and an observer are in motion relative to each other, the frequency of the sound waves changes due to this motion. In this case, when the plane is moving toward or away from the siren at 1/4 the speed of sound, the observer perceives the same frequency of sound from the siren.

Answer:

a) v = 54.7m/s

b) v = (58 - 1.66a) m/s

c) t = 69.9 s

d) v = -58.0 m/s

Explanation:

Given;

The height equation of the arrow;

H = 58t - 0.83t^2

(a) Find the velocity of the arrow after two seconds. m/s;

The velocity of the arrow v can be given as dH/dt, the change in height per unit time.

v = dH/dt = 58 - 2(0.83t) ......1

At t = 2 seconds

v = dH/dt = 58 - 2(0.83×2)

v = 54.7m/s

(b) Find the velocity of the arrow when t = a. m/s

Substituting t = a into equation 1

v = 58 - 2(0.83×a)

v = (58 - 1.66a) m/s

(c) When will the arrow hit the surface? (Round your answer to one decimal place.) t = s

the time when H = 0

Substituting H = 0, we have;

H = 58t - 0.83t^2 = 0

0.83t^2 = 58t

0.83t = 58

t = 58/0.83

t = 69.9 s

(d) With what velocity will the arrow hit the surface? m/s

from equation 1;

v = dH/dt = 58 - 2(0.83t)

Substituting t = 69.9s

v = 58 - 2(0.83×69.9)

v = -58.0 m/s

Answer:

26.64°

Explanation:

Given:

a = 16.3 cm

b = 32.5 cm

Angle when laser beam reflects off the mirror and strike the wall =

θ [tex] = tan^-^1(\frac{b}{a}) [/tex]

[tex] = tan^-^1(\frac{32.5}{16.3}) [/tex]

= 63. 36°

For angle of reflection, we have:

θr = 90° - 63.36°

θr = 26.64°

Since angle of incidence, θi is equal to angle of reflection θr, the angle of incidence θi at which the laser beam strikes the mirror is =

θi = θr = 26.64°

Answer:

Find the given attachments for complete solution

Find the given attachment for solution

The electric flux trough x = 0 plane is = - EL² and the electric flux trough x = l plane is = EL².

Although an electric field cannot flow by itself, electric flux in electromagnetism is a measure of the electric field passing through a specific surface.

An electric field surrounds an electric charge, such as a solitary electron in space. Field lines have no physical significance and are merely a graphic representation of field strength and direction.

The number of "lines" per unit area, also known as the electric flux density, is inversely proportional to the electric field strength. The total number of electric field lines passing through a surface determines the amount of electric flux.

Hence, electric flux trough x = 0 plane is = - EL² and the electric flux trough x = l plane is = EL².

Learn more about electric flux here:

https://brainly.com/question/14544020

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