A new extended-life light bulb has an average service life of 750 hours, with a standard deviation of 50 hours. if the service life of these light bulbs approximates a normal distribution, about what percent of the distribution will be between 600 hours and 900 hours? 95% 68% 34% 99.7%

Answers

Answer 1

Approximately 99.7% of the light bulbs are expected to last between 600 and 900 hours, according to the empirical rule of normal distributions, as these values fall within +/- 3 standard deviations from the mean.

To determine what percent of the distribution of light bulbs will have a service life between 600 and 900 hours, we employ the empirical rule for normal distributions. If we know the mean (750 hours) and standard deviation (50 hours), we can calculate the number of standard deviations each of these values are from the mean:

(600 - 750) / 50 = -3 standard deviations (SD)

(900 - 750) / 50 = 3 standard deviations (SD)

According to the empirical rule (68-95-99.7 rule), approximately:

68% of the data falls within "+/- 1 SD"

95% of the data falls within "+/- 2 SD"

99.7% of the data falls within "+/- 3 SD"

Since 600 hours and 900 hours are three standard deviations away from the mean on either side, the percentage of light bulbs expected to last between these two values would be approximately 99.7%.


Related Questions

a jet descended 0.44 mile in 0.8 minute. What was the plane's average change of altitude per minute?

Answers

7.56 because distance decreases

A restaurant earns $1073 on Friday and $1108 on Saturday. Write and solve an equation to find the amount xx (in dollars) the restaurant needs to earn on Sunday to average $1000 per day over the three-day period. Write your equation so that the units on each side of the equation are dollars per day.

Answers

$819 to make an average 1,000 within 3 day period
(1073 + 1108 + x) / 3 = 1000
(2181 + x) / 3 = 1000
2181 + x = 1000 * 3
2181 + x = 3000
x = 3000 - 2181
x = 819 <=== the restaurant would need to make $ 819

The national vaccine information center estimates that 90% of americans have had chickenpox by the time they reach adulthood.50 (a) is the use of the binomial distribution appropriate for calculating the probability that exactly 97 out of 100 randomly sampled american adults had chickenpox during childhood. (b) calculate the probability that exactly 97 out of 100 randomly sampled american adults had chickenpox during childhood. (c) what is the probability that exactly 3 out of a new sample of 100 american adults have not had chickenpox in their childhood? (d) what is the probability that at least 1 out of 10 randomly sampled american adults have had chickenpox? (e) what is the probability that at most 3 out of 10 randomly sampled american adults have not had chickenpox?

Answers

The correct answers are:

A) yes; B) 0.0059; C) 0.0059; D) 1; E) 0.9872.

Explanation:

A) A binomial experiment is one in which the experiment consists of identical trials; each trial results in one of two outcomes, called success and failure; the probability of success remains the same from trial to trial; and the trials are independent.

All of these criteria fit this experiment.

B) The formula for the probability of a binomial experiment is:

[tex] _nC_r\times(p^r)(1-p)^{n-r} [/tex]

where n is the number of trials, r is the number of successes, and p is the probability of success.

In this problem, p = 0.9.

For part B, n = 100 and r = 97:

[tex] _{100}C_{97}(0.9)^{97}(1-0.9)^3
\\=\frac{100!}{97!3!}\times (0.9)^{97}(0.1)^3
\\
\\=161700(0.9)^{0.97}(0.1)^3=0.00589\approx 0.0059 [/tex]

C) We are changing the probability of success this time. Since 90% of people have had chicken pox, then 100%-90% = 1-0.9 = 0.1 have not had chicken pox. For part C, n = 100, r = 3, and p = 0.1:

[tex] _{100}C_3(0.1)^3(1-0.1)^{100-3}
\\
\\=_{100}C_3(0.1)^3(0.9)^{97}
\\=\frac{100!}{97!3!}\times (0.1)^3(0.9)^{97}
\\
\\=161700(0.1)^3(0.9)^{97}=0.00589\approx 0.0059 [/tex]

D) For this part, we want to know the probability that at least 1 person has contracted chicken pox. For this part, p = 0.9, n = 10 and r = 0. We will then subtract this from 1; this will first give us the probability that none of the 10 contracted chicken pox, then subtracting from 1 means that 1 or more people did:

[tex] 1-(_{10}C_0(0.9)^0(1-0.9)^{10-0})
\\
\\=1-(\frac{10!}{0!10!}\times (0.9)^0(0.1)^{10})
\\
\\=1-(1\times 1\times (0.1)^{10})= 1-0 = 1 [/tex]

E) For this part, we find the probability that 3 people, 2 people, 1 person and 0 people have not had chicken pox. The probability p = 0.1; n = 10; and r = 3, 2, 1 and 0, respectively:

[tex] _{10}C_3(0.1)^3(1-0.1)^{10-3}+_{10}C_2(0.1)^2(1-0.1)^{10-2}+
_{10}C_1(0.1)^1(1-0.1)^{10-1}+_{10}C_0(0.1)^0(1-0.1)^{10-0}
\\
\\=_{10}C_3(0.1)^3(0.9)^7+_{10}C_2(0.1)^2(0.9)^8+_{10}C_1(0.1)^1(0.9)^9+
_{10}C_0(0.1)^1(0.9)^{10}
\\
\\120(0.1)^3(0.9)^7+45(0.1)^2(0.9)^8+10(0.1)^1(0.9)^9+1(0.1)^0(0.9)^{10}
\\
\\0.057395628+0.1937102445+0.387420489+0.3486784401
\\
\\=0.9872 [/tex]

Final answer:

The binomial distribution is appropriate for calculating the probability of having a specific number of American adults who had chickenpox during childhood. The probability of exactly 97 out of 100 adults having chickenpox can be calculated using the binomial probability formula. The probability that at least 1 out of 10 adults have had chickenpox and at most 3 out of 10 adults have not had chickenpox can also be calculated using the binomial probability formula.

Explanation:

(a) To determine if the use of the binomial distribution is appropriate, we need to check if the conditions for using it are satisfied: (1) There are only two possible outcomes - having or not having chickenpox. (2) Each trial is independent - one person's chickenpox status does not affect another person's. (3) The probability of having chickenpox is the same for each person. The given information satisfies these conditions, so the binomial distribution is appropriate.

(b) The probability of exactly 97 out of 100 randomly sampled American adults having chickenpox during childhood can be calculated using the binomial probability formula:

P(X = k) = C(n, k) * p^k * (1-p)^(n-k)

Where:

P(X = k) is the probability of getting exactly k successes (97 in this case)

C(n, k) is the number of ways to choose k successes out of n trials (100 in this case)

p is the probability of success (probability of having chickenpox = 0.90)

n is the total number of trials (100 in this case)

Using these values, we can calculate:

P(X = 97) = C(100, 97) * 0.90^97 * 0.10^3

= 100 * (0.90)^97 * (0.10)^3

≈ 0.0975

So, the probability that exactly 97 out of 100 randomly sampled American adults had chickenpox during childhood is approximately 0.0975 or 9.75%.

(c) The probability that exactly 3 out of a new sample of 100 American adults have not had chickenpox in their childhood can be calculated using the binomial probability formula:

P(X = k) = C(n, k) * p^k * (1-p)^(n-k)

Where:

P(X = k) is the probability of getting exactly k successes (3 in this case)

C(n, k) is the number of ways to choose k successes out of n trials (100 in this case)

p is the probability of success (probability of not having chickenpox = 0.10)

n is the total number of trials (100 in this case)

Using these values, we can calculate:

P(X = 3) = C(100, 3) * 0.10^3 * 0.90^97

= 161,700 * (0.10)^3 * (0.90)^97

≈ 0.0315

So, the probability that exactly 3 out of a new sample of 100 American adults have not had chickenpox in their childhood is approximately 0.0315 or 3.15%.

(d) To calculate the probability that at least 1 out of 10 randomly sampled American adults have had chickenpox, we can use the complement rule: P(at least 1) = 1 - P(none)

Where P(none) is the probability of none of the 10 sampled adults having chickenpox.

Using the binomial formula:

P(X = 0) = C(n, k) * p^k * (1-p)^(n-k)

Where:

P(X = 0) is the probability of getting exactly 0 successes

C(n, k) is the number of ways to choose 0 successes out of n trials (10 in this case)

p is the probability of success (probability of having chickenpox = 0.90)

n is the total number of trials (10 in this case)

Using these values, we can calculate:

P(X = 0) = C(10, 0) * 0.90^0 * 0.10^10

= 1 * (0.90)^0 * (0.10)^10

≈ 0.3487

So, P(none) ≈ 0.3487

Therefore, P(at least 1) = 1 - P(none) = 1 - 0.3487 = 0.6513

So, the probability that at least 1 out of 10 randomly sampled American adults have had chickenpox is approximately 0.6513 or 65.13%.

(e) To calculate the probability that at most 3 out of 10 randomly sampled American adults have not had chickenpox, we can add up the probabilities of getting 0, 1, 2, and 3 successes:

P(X ≤ 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)

We can use the binomial probability formula to calculate each individual probability:

P(X = k) = C(n, k) * p^k * (1-p)^(n-k)

Where:

P(X = k) is the probability of getting exactly k successes (0, 1, 2, or 3 in this case)

C(n, k) is the number of ways to choose k successes out of n trials (10 in this case)

p is the probability of success (probability of not having chickenpox = 0.10)

n is the total number of trials (10 in this case)

Using these values, we can calculate each individual probability:

P(X = 0) = C(10, 0) * 0.10^0 * 0.90^10

P(X = 1) = C(10, 1) * 0.10^1 * 0.90^9

P(X = 2) = C(10, 2) * 0.10^2 * 0.90^8

P(X = 3) = C(10, 3) * 0.10^3 * 0.90^7

Adding up these probabilities, we get:

P(X ≤ 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)

≈ 0.9873

So, the probability that at most 3 out of 10 randomly sampled American adults have not had chickenpox is approximately 0.9873 or 98.73%.

Find the standard equation of the circle having the given center (6,-2) and radius 1/5.

Answers

The equation of a circle is (x-h)²+(y-k)²=r², with h being the x value in the center, k being the y value, and r being the radius. Plugging them in, we get 
(x-6)²+(y-(-2))²=(1/5)²
                       =  1/25
                       = (x-6)²+(y+2)²

In January, Emma was 62.25 in tall. In December, she was 65.5 inches tall. How much did Emma grow between January and December?

Answers

she "grew" negative 3.25 inches

 it is negative because she was taller in December than she was in January

The cost of a ticket to a soccer game is $6. There are y number of people in a group that want to go to a game. Which of the following expressions describes the total amount of money the group will need to go to the soccer game?

Answers

The expression is:
6y

Hope this helps!! :)

the equation would look something like

total = 6y


since you don't show the choices look for something similar.

The pie below is cut into 6 equal slices. Show shade 2/3 of this pie.

Answers

Shade 4 slices out of the pie
In order to do this....

Just shade 4 out of 6 slices.

This is because 2/3 = 4/6.

To be sure you can even simplify 4/6 to 2/3.

Hope this helps!

Write y = 2x + 3 using function notation

Answers

f(x) = 2x + 3 i think would be the best way to write it

What is 51,908 rounded to the nearest hundred dollar?

Answers

The thing we need to do while rounding is look at the digit before. The digit before is 0, meaning we have to round down.So:

51, 900

Hope this helps!
the  9 is the hundred dollar digit  
as the following digit is 0 the answer is  51,900

What is 160,656 rounded to the nearest ten thousandth?

Answers

It would be 160,000.

The nearest two ten thousands would be 160,000 and 170,000

160,656 is 656 away from 160,000, and 9,344 away from 170,000.

It is much closer to 160,000 than 170,000.
160,000 that's rounded to the nearest ten thousandth

837,164 and 4,508 the value of 8

Answers

In 837,164, the value of 8 is the hundred thousands place
In 4,508, the value of 8 is the ones place

hope this helps

Find a ·
b. |a| = 60, |b| = 30, the angle between a and b is 3π/4.

Answers

Final answer:

To find the dot product of vectors a and b, we can use the formula: a · b = |a| |b| cos θ, where |a| and |b| are the magnitudes of vectors a and b, and θ is the angle between them.

Explanation:

To find the dot product of vectors a and b, we can use the formula: a · b = |a| |b| cos θ, where |a| and |b| are the magnitudes of vectors a and b, and θ is the angle between them.

In this case, |a| = 60 and |b| = 30. The angle between a and b is given as 3π/4.

Therefore, a · b = 60 * 30 * cos (3π/4) = 60 * 30 * (-√2/2) = -1800√2.

how do you equally divide 12 cookies with 8 people. what fraction of cookies would each person receive?

Answers

each person would receive 1 and an half cookies.
in other words 1 1/2

Final answer:

To equally divide 12 cookies among 8 people, each person would receive 1 1/2 or 1.5 cookies, which is a fraction of 3/2 per person when simplified.

Explanation:

To divide 12 cookies equally among 8 people, we need to perform a simple division operation where 12 (total number of cookies) is divided by 8 (number of people). Mathematically, this can be represented as 12/8 which simplifies to 1 1/2 or 1.5 cookies per person. This means that each person would receive one and a half cookies.

If the problem requires the answer as a fraction, we can simplify 12/8 by dividing both numerator and denominator by their greatest common divisor, which is 4 in this case. Thus, we get 12/8 = (12÷4) / (8÷4) = 3/2. Therefore, each person gets 3/2 or one and a half cookies.

Find the value of y log4 64=y

Answers

Answer:

y=log4 64=2.6665.

Step-by-step explanation:

We are given that logarithmic expression

y=log 464

By using logarithmic rules

Substitute the decimal point after end digit and then put zero after decimal point

We can write as

y=log464.0

To put the decimal point after one digit from left then we move two steps.Therefore ,we write 2 on left side of the decimal point in final result

Now, we see the value of 46 at 4 from log table then we get the value of 46 at 4 is 6665

Therefore , y=log464=2.6665

Hence, the value of y=2.6665

The value of y to the equation log₄(64) = y is y = 3.

The given logarithmic equation is :

y = log₄(64)

This can be written in exponential form as :

4^(y) = 64

It is known that :

4 × 4 × 4 = 64

So,

4³ = 64

Hence the value of y = 3.

Learn more about Logarithmic Functions here :

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Write the expression that shows 3 time the sixth power of 10

Answers

3 x 10^6

Shouldn't be too hard for ya ;)

For rhombus LMNO, m∠LON = 102° and NP = 5 units. Use the diagram of rhombus LMNO to find the missing measures. The measure of ∠LPM is °. The measure of ∠PMN is °. The length of LN is units.

Answers

LPM = 90

PMN = 51

LN = 10

Answer:

1. 90

2. 50

3. 10

Step-by-step explanation:

An airlines records show that its flights between two cities arrive on the average 5.4 minutes late with a standard deviation of 1.4 minutes. at least what percentage of its flights between the two cities arrive anywhere between

Answers

Interval between 2.6 minutes late and 8.2 minutes late is within 2 standard deviations of the mean (k =8.2â’5.4/1.4 =5.4â’2.6/1.4 = 2). By Chebyshev’s Theorem, at least 1 â’1/2^2 =3/4 of all flights, i.e. at least 75% of all flights arrive anywhere between 2.6 minutes late and 8.2 minutes late.

For each function f(n) and time t in the table, determine the largest size n of a problem that can be solved in time t, assuming that the algorithm to solve the problem takes f(n) microseconds

Answers

The question involves estimating the largest problem size a one-teraflop computer can solve in a given time, by equating the time complexity function of the problem to the number of operations the computer can perform per second, and solving for n.

The task is to estimate the largest problem size n that can be solved by a one-teraflop machine within a given time t. A teraflop machine is capable of performing 1012 operations per second. To determine n, we must consider the time complexity function f(n) that describes how the number of operations grows with the size of the problem. Given that the machine can perform 1012 instructions per second, and t is measured in microseconds, we first convert t to seconds.

For example, if the function f(n) follows a linear time complexity, such as f(n) = n, and the computation time t is 1 second, the largest problem size that can be solved is 1012, since the machine can perform 1012 operations in one second.

If the computational complexity is higher, say quadratic as f(n) = n2, we would solve for n in the equation n2 = 1012 to find the largest n that can be solved within 1 second.

Similarly, for more complex functions, we would find the value of n that satisfies the equation f(n) = 1012 * t in seconds, ensuring the result is within the operational constraints of the machine.

Go has 3 orange pick for every 2 green if ther are 25 picks in all how many picks are orange

Answers

Hello There!

3:2
3 + 2 = 5
25/5 = 5
3 x 5 = 15
2 x 5 = 10
15:10
Therefore 15 orange picks.

Hope This Helps You!
Good Luck :)

Answer:

15

Step-by-step explanation:

It has been given that Go has 3 orange pick for every 2 green.

Hence, the ratio of Go to Green is 3:2

Total number of picks = 25.

Number of picks of orange in 25 picks is given by

[tex]\frac{3}{3+2}\times25[/tex]

Simplifying, we get

[tex]=\frac{3}{5}\times25[/tex]

Multiply the numerator, we get

[tex]=\frac{75}{5}[/tex]

Dividing, we get

[tex]=15[/tex]

Hence, the number of picks of orange are 15.

If a straight line passes through the point x​ = 8 and y​ = 4 and also through the point x​ = 12 and y​ = 6, the slope of this line is

Answers

The slope of the line would be 1/2

The slope of the line that passes through (4, 8) and (6, 12) will be 1/2.

What is a linear equation?

A connection between a number of variables results in a linear model when a graph is displayed. The variable will have a degree of one.

The linear equation is given as,

y = mx + c

Where m is the slope of the line and c is the y-intercept of the line.

The slope of the line is given as,

m = (y₂ - y₁) / (x₂ - x₁)

If a straight line passes through the point x​ = 8 and y​ = 4 and also through the point x​ = 12 and y​ = 6. Then the slope is given as,

m = (6 - 4) / (12 - 8)

m = 2 / 4

m = 1 / 2

The slope of the line that passes through (4, 8) and (6, 12) will be 1/2.

More about the linear equation link is given below.

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A red string of holiday lights blinks once every 3 seconds while a string of blue lgihts blink once every 4 seconds. how many times with both sets of lights blink at the same time in 1 minute

Answers

So we want to find the times where they intersect, through their multiples.

For example, the multiples of 3 are 6, 9, 12, etc.

3: 3, 6, 9, 12...

4: 4, 8, 12...

So the least common multiple is 12.

So we know they blink at the same time once every 12 seconds.

Now we just need to find how many times 12 fits into a minute, or 60 seconds.

60 / 12 = 5

So the lights will blink at the same time 5 times in one minute.

Differentiate
y=(6x)/(1-cot(x))

Answers

[tex]\bf y=\cfrac{6x}{1-cot(x)}\implies \cfrac{dy}{dx}=\stackrel{quot ient~ru le}{\cfrac{6[1-cot(x)]~-~6x[-csc^2(x)]}{[1-cot(x)]^2}} \\\\\\ \cfrac{dy}{dx}=\cfrac{6-6cot(x)~+~6xcsc^2(x)}{[1-cot(x)]^2}[/tex]

The next train will arrive in 32 minutes and 30 seconds. In how many seconds will the next train arrive

Answers

you need to multiply the 30 with the 32
60x32=1920 +30= 1950 seconds

Fritz drives to work his trip takes 36 ​minutes, but when he takes the train it takes 20 minutes. Find the distance Fritz travels to work if the train travels an average of 32 miles per hour faster than his driving. Assume that the train travels the same distance as the car.

Answers

recall your d = rt, distance = rate * time

so, let's say Fritz travel by Car at a speed of "r", if the Train runs faster then his car, then the Train runs at "r+32".

Bear in mind that, he travels from home to work by Car or Train, so, the distance if the same for either vehicle, let's say is "d" miles.

[tex]\bf \begin{array}{lccclll} &\stackrel{miles}{distance}&\stackrel{mph}{rate}&\stackrel{minutes}{time}\\ &-----&-----&-----\\ Car&d&r&36\\ Train&d&r+32&20 \end{array} \\\\\\ \begin{cases} \boxed{d}=36r\\ d=20(r+32)\\ ----------\\ \boxed{36r}=20(r+32) \end{cases} \\\\\\ \cfrac{36r}{20}=r+32\implies \cfrac{9r}{5}=r+32\implies 9r=5r+160 \\\\\\ 4r=160\implies r=\cfrac{160}{4}\implies \boxed{r=40}[/tex]

so... he travels at 40mph for 36 minutes, now, 36minutes is not even an hour, is 36/60 or 3/5 hr, so...    [tex]\bf 40\cdot \cfrac{36}{60}\implies 40\cdot \cfrac{3}{5}\implies \stackrel{miles}{24}[/tex]

The distance Fritz travels to work is 24 miles if Fritz drives to work his trip takes 36 minutes, but when he takes the train it takes 20 minutes.

What is the distance?

Distance is a numerical representation of the distance between two items or locations. Distance refers to a physical length or an approximation based on other physics or common usage considerations.

It is given that:

Fritz drives to work his trip takes 36 ​minutes, but when he takes the train it takes 20 minutes.

Let the distance Fritz travels to work is x.

As we know,

1 hour = 60 minutes

36/60 = 0.6 hrs

20/60 = 0.33 hrs

Speed = distance/time

Train speed - drive speed = 32

x/0.33 - x/0.6 = 32

After simplification:

9d - 5x = 96

4x = 96

x = 96/4

d = 24 miles

Thus, the distance Fritz travels to work is 24 miles if Fritz drives to work his trip takes 36 minutes, but when he takes the train it takes 20 minutes.

Learn more about the distance here:

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if the flour to sugar ratio is 5 liters flour to 1 liter sugar, then how much sugar is needed if only 2 liters of flour are used ?

Answers

2/5 liters of sugar would be used

Answer:

0.4 liters of sugar.

Step-by-step explanation:

Hello, I think I can help you with this

you can easily solve this by using a rule of three

Step 1

if

5 liters flour⇒  1 liter sugar

2 liters flour⇒ x?liter sugar

do the relation

[tex]\frac{5\ liters\ flour}{1\ liter\ sugar}=\frac{2\ liters\ flour}{x}\\\\solve\ for\ x\\\\\\\frac{x*5\ liters\ flour}{1\ liter\ sugar}=2\ liters\ flour\\x=\frac{2\ liters\ flour*1\ liter\ sugar}{5\ liters\ flour} \\x=\frac{2}{5}liter\ sugar\\x=0.4\ liters\ of\ sugar\\[/tex]

0.4 liters of sugar

I hope it helps, Have a great day-

Joan and Jane are sisters. Jean is Joan's daughter and 12 years younger than her aunt. Joan is twice as old as Jean. Four years ago, Joan was the same age as Jane is now, and Jane was twice as old as her niece. How old is Jean?

Answers

Jean is 12 years old. Joan is 24 years old, and Jane is 20 years old. Four years ago, Joan was 20 and Jane was 16.

Let's denote:

- Joan's current age as J

- Jane's current age as N

- Jean's current age as I

Given:

1. Jean is 12 years younger than Joan: I = J - 12

2. Joan is twice as old as Jean: J = 2I

3. Four years ago, Joan was the same age as Jane is now: J - 4 = N

4. Jane was twice as old as her niece four years ago: N - 4 = 2(I - 4)

Using equation (1) and (2):

J = 2(J - 12)

J = 2J - 24

J = 24

Now substituting J = 24 into equation (1):

I = 24 - 12

I = 12

So, Jean is currently 12 years old.

If ab= 8 in. and cd= 6 in., how long is a radius?

Answers

The answer is 7 in because the diameter is 14 in.

combing like terms? 4(1.75y-3.5)+1.25y

Answers

First you gotta distribute.
4 (1.75y - 3.5) + 1.25y
4 * 1.75 y = 7
4* (-3.5) = (-14)

7y - 14 + 1.25y
Combine like terms
8.25y - 14

Answer:

8.25y-14

Step-by-step explanation:

The given expression is [tex]4(1.75y-3.5)+1.25y[/tex]

Distribute 4 over the parenthesis

[tex]4\cdot1.75y+4\cdot(-3.5)+1.25y\\\\=7y-14+1.25y[/tex]

Now. group the like terms

[tex](7y+1.25y)-14[/tex]

Finally combine the like terms

[tex]8.25y-14[/tex]

Therefore, the simplified expression is 8.25y-14

Determine tan(t) if cos(t)= -3/5 and sin(t) >0

Answers

[tex]\bf cos(\theta)=\cfrac{adjacent}{hypotenuse} \qquad % tangent tan(\theta)=\cfrac{opposite}{adjacent}\\\\ -------------------------------\\\\ cos(t)=-\cfrac{\stackrel{adjacent}{3}}{\stackrel{hypotenuse}{5}}[/tex]

now, the hypotenuse is just a radius unit, so, is never negative, so, the fraction is negative because the numerator is negative, that is, the adjacent side is -3.

now, let's use the pythagorean theorem to find the opposite side.

[tex]\bf \textit{using the pythagorean theorem}\\\\ c^2=a^2+b^2\implies \pm\sqrt{c^2-a^2}=b\qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ \pm\sqrt{5^2-(-3)^2}=b\implies \pm\sqrt{25-9}=b\implies \pm 4=b[/tex]

ok... so, which is it? the +/-?   well, we also know that sin(t) >0, namely that the sine of the angle is positive, so, then  is +4 then.

[tex]\bf tan(\theta)=\cfrac{opposite}{adjacent}\qquad \qquad tan(t)=\cfrac{4}{-3}\implies \boxed{tan(t)=-\cfrac{4}{3}}[/tex]

if the quotient of -20 and 4 is decreased by 3 what number results

Answers

quotient is divide

-20/4 = -5

-5 -3 = -8

Other Questions
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