A positive integer is 47 more than 9 times another. their product is 18601860. find the two integers.

The equation of the line with the given ordered pairs is y = 4x + 3.

The equation of a line is given by:

y = mx + c

where m is the slope of the line and c is the y-intercept.

Example:

The slope of the line y = 2x + 3 is 2.

The slope of a line that passes through (1, 2) and (2, 3) is 1.

We have,

The ordered pairs:

(-1,1), (0,3), (1,5), and (2,7)

The equation of the line is y = mx + c.

Pick any two ordered pairs.

(-1, -1) and (0, 3)

m = (3 - (-1)) / (0 - (-1)) = (3 + 1)/1 = 4/1 = 4

Now,

(0, 3) = (x, y)

3 = 4 x 0 + c

c = 3

Thus,

The equation of the line is y = 4x + 3

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Final answer:

The total resistance in a series circuit is found by summing the resistances of individual components. For the given resistors of 3+j5 ohms, 5-j8 ohms, and 6+j4 ohms, the total resistance is 14+j1 ohms.

Explanation:

In a series circuit, the total resistance (Rtotal) is the sum of the individual resistances. We have three resistors with complex resistance values: R1 = 3 + j5 ohms, R2 = 5 - j8 ohms, and R3 = 6 + j4 ohms. Adding these together will give us:

Rtotal = R1 + R2 + R3

Calculate the real parts of each resistor and the imaginary parts separately:

Real part = 3 + 5 + 6 = 14 ohms,
Imaginary part = j5 - j8 + j4 = j1 ohm.

Thus, the total resistance in the circuit is Rtotal = 14 + j1 ohms.

The value of x is 10 and RS is 60 units.

It is required to find the value of x  and RS.

Length is defined as the measurement or extent of something from end to end. It is the larger of the two or the highest of three dimensions of geometrical shapes or objects.

Given:

S is between R and T

RS=6x,  ST=12,    RT=72

We know that ,

RS + ST = RT

6x + 12 = 72

Substract 12 on both sides we have,

6x + 12 - 12= 72 - 12

6x = 60

x = 10 units.

Put the value of x in RS we have,

RS = 6x

RS = 6(10)

RS = 60 units.

Therefore, the value of x is 10 and RS is 60 units.

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To calculate the number of traffic lights needed for a town with 6 streets intersecting each other, you can use the formula Number of traffic lights = Number of intersections. In this case, 15 traffic lights are needed.

A traffic light is needed at each intersection. How many traffic lights are needed if there are 6 streets in the town?

To determine the number of traffic lights needed for 6 streets, we use the formula: Number of traffic lights = Number of intersections. In a town with 6 streets, each street intersects with every other street, resulting in 15 intersections. Therefore, 15 traffic lights are needed for the 6 streets.

supplementary angles add up to 180 degrees

 angle 1 = x

 angle 2 = 8x

 x +8x = 180

9x = 180

x = 180/9 = 20 degrees

larger angle = 8*20 = 160 degrees

To find the measure of the larger angle, set up an equation. Solve the equation to find the value of the smaller angle. Multiply the smaller angle by 8 to find the measure of the larger angle.

To find the measure of the larger angle, we need to set up an equation based on the given information. Let's say the smaller angle is x degrees. The larger angle is then 8 times the smaller angle, which means it is 8x degrees. We know that two angles are supplementary, meaning they add up to 180 degrees. So we can set up the equation x + 8x = 180. Simplifying this equation gives us 9x = 180. Dividing both sides by 9, we find that x = 20 degrees. Therefore, the larger angle is 8x = 8 * 20 = 160 degrees.

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Answer:

Step-by-step explanation:

For all Plato users.

x= child

2x = adult

6.20x +9.80(2x) =593.40

6.20x +19.6x=593.40

25.80x =593.40

x=593.40/25.80 = 23

 23 childrens tickets were sold

Answer:

[tex]f(x)\rightarrow +\infty\text{ as }x\rightarrow -\infty[/tex]

[tex]f(x)\rightarrow +\infty\text{ as }x\rightarrow +\infty[/tex]

Step-by-step explanation:

Given polynomial function is,

[tex]f(x)=3x^4+2x^2-x[/tex]

Since, the end behavior of a polynomial is same as the end behavior of leading term,

Here, the leading term = [tex]3x^4[/tex]

[tex]\text{As }x\rightarrow -\infty[/tex]

The leading term is positive,

[tex]\text{While, as }x\rightarrow +\infty[/tex]

The leading term is positive,

Hence, the end behavior of the given polynomial is,

[tex]f(x)\rightarrow +\infty\text{ as }x\rightarrow -\infty[/tex]

[tex]f(x)\rightarrow +\infty\text{ as }x\rightarrow +\infty[/tex]

⇒ In the graph of f(x), both ends will go upward.

Answer:both ends go down !

Step-by-step explanation:

The domain for the function f(x) = 2x² + 5√(x + 2) is all real numbers greater than or equal to -2.

In interval notation, we can express this as:

Domain: x ∈ [-2, ∞)

Given is a function f(x) = 2x² + 5√2, we need to determine the domain of the function,

To complete the statement, we need to determine the domain for the function f(x) = 2x² + 5√(x + 2).

The domain of a function represents all the possible values of x for which the function is defined.

In this case, we need to consider two factors that can restrict the domain:

For a real number to be a valid input for the square root (√), the expression inside the square root (x + 2) must be greater than or equal to 0.

Otherwise, we would encounter the issue of taking the square root of a negative number, which is not defined in the real number system.

There are no other restrictions in the function that would cause it to be undefined for certain values of x.

Since x² is defined for all real numbers, there are no issues there.

Let's solve the inequality for the square root expression:

x + 2 ≥ 0

Subtract 2 from both sides:

x ≥ -2

So, the domain for the function f(x) = 2x² + 5√(x + 2) is all real numbers greater than or equal to -2.

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Answer:

B.) x = –4 or x = 1/6 .

Step-by-step explanation:

Given  : g(x) = 6x² + 23x – 4.  

To find : Solve.

Solution : We have given that

g(x) = 6x² + 23x – 4.  

If g(x) = 0

6x² + 23x – 4 = 0 .

On factoring

6x² + 24x - 1x – 4 = 0

Taking common 6x from first two terms and -1 from last two terms.

6x ( x + 4 ) -1 (x + 4) = 0.

On grouping

(6x -1) ( x +4) = 0

For 6x -1 = 0

6x = 1

on dividing by 6

x = 1/6.

For x +4 = 0

On subtracting 4 from both sides

x = -4.

Therefore, B.) x = –4 or x = 1/6 .

Answer:

45 Fake Dollars

Step-by-step explanation:

4x5=20

d=20+25

d=45 Fake Dollars

Answer:

45

Step-by-step explanation:

Answer:

Hence, the difference in Mean of two teams is:

0.52

Step-by-step explanation:

Five members of the soccer team and five members of the track team ran the 100-meter dash.

Their time is listed as:

Soccer          Track

   12.3              12.3

   13.2               11.2

   12.5               11.7

   11.3                12.2

    14.4               13.7

The mean of the soccer team is given by:

[tex]Mean_1=\dfrac{12.3+13.2+12.5+11.3+14.4}{5}\\\\Mean_1=12.74[/tex]

The mean of track team is given by:

[tex]Mean_2=\dfrac{12.3+11.2+11.7+12.2+13.7}{5}\\\\Mean_2=\dfrac{61.1}{5}\\\\Mean_2=12.22[/tex]

Hence, the Difference in Mean is:

[tex]Mean_1-Mean_2\\\\=12.74-12.22\\\\=0.52[/tex]

Hence, the difference in Mean of two teams is:

0.52

Answer:

(-0.55,0),(4.55,0)

Answer:  the correct option is (B) 29.

Step-by-step explanation:  We are given to find the length of the hypotenuse x, if (20, 21, x) is a Pythagorean triple.

We know that

in a right-angled triangle, the lengths of the sides (hypotenuse, perpendicular, base) is a Pythagorean triple, where

[tex]Hypotenuse^2=Perpendicular^2+base^2.[/tex]

So,  for the given Pythagorean triple, we have

[tex]x^2=20^2+21^2\\\\\Rightarrow x^2=400+441\\\\\Rightarrow x^2=841\\\\\Rightarrow x=\sqrt{841}~~~~~~~~~~~~~~~~~[\textup{taking square root on both sides}]\\\\\Rightarrow x=\pm29.[/tex]

Since the length of the hypotenuse cannot be negative, so x = 29.

Thus, the length of the hypotenuse, x = 29.

Option (B) is CORRECT.