A publishing company has a weekly cost equation of C=96,000+20x and a weekly revenue equation of R=26​x, where x is the number of books produced and sold in a week. The company loses money when R

Answer: 0.12

Step-by-step explanation:

Answer: [tex]30\ ft^2[/tex]

Step-by-step explanation:

We are given that

The base of the rectangle = 2 yards

The height of the rectangle = 5 feet

We know that

1 yard = 3 feet

Then , the base of the rectangle = [tex]2 \times3=6\text{ feet}[/tex]

Now, the are of the rectangle will be :-

[tex]\text{Area}=\text{Height x Base}\\\\\Rightarrow\ \text{Area}=5\times6\text{ square feet}\\\\\text{Area}= 30\text{ square feet}[/tex]

Hence, the area of the rectangle = [tex]30\ ft^2[/tex]

Answer:

i think is 30ft2

Step-by-step explanation:

Answer:

3/4.

Step-by-step explanation:

4/8 simplified=1/2 6/8 simplified=3/4.

cylinder B is 4 times the size of A

To solve this problem, it is necessary determine the integrations limits first.

The solution is:

V = 1666,13×π vol units

In order to express the information in spherical coordinates, we have:

x = ρ×cosθ×sinφ

y = ρ×sinθ×sinφ

z = ρ×cosφ

and     dV = ρ²×sinφ×dρ×dθ×dφ

0 ≤ φ ≤ π

0 ≤ θ ≤ 2×π

x² + y² + z² = 25       and         x² + y² + z² = 1    are two concentric spheres with center at the origin and radius 5 and 1 respectevely .

According to that:

1 ≤  ρ ≤ 5

V = ∫∫∫ ( x² + y² )× dV  

V  =   ∫∫∫ ( x² + y² )×ρ²×sinφ×dρ×dθ×dφ

V =  ∫∫∫ (  ρ²×cos²θ×sin²φ  + ρ²×sin²θ×sin²φ ) ×ρ²×sinφ×dρ×dθ×dφ

V =  ∫∫∫ [  ρ²×sin²φ ( cos²θ + sin²θ )  ×ρ²×sinφ×dρ×dθ×dφ

V =  ∫∫∫ [  ρ²×sin²φ×ρ²×sinφ×dρ×dθ×dφ

V =  ∫∫∫ [ ρ⁴×sin³φ×dρ×dθ×dφ

V =  ∫₁⁵ρ⁴×dρ ×∫dθ ×∫sin³φ×dφ

V =  ρ⁵/5 |₁⁵×∫dθ ×∫sin³φ×dφ

ρ⁵/5 |₁⁵  = 5⁵/5 - 1⁵/5   = 3125 / 5 - 1/5  = 3124/5

V = 3124/5× θ |₀²π×∫sin³φ×dφ

θ |₀²π  = 2×π - 0

V = 3124/5× (2×π) ×∫sin³φ×dφ

∫sin³φ×dφ  [ 0  y π ] = 4/3   (from Simbolab)

V = 3124/5× (2×π) ×4/3

V = 1666,13×π   vol units

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Answer:

1

Step-by-step explanation:

GCF(18, a, 20ab) = 1

18 and a do not necessarily have any factor in common, so their GCF is 1. Adding more terms to the list will not increase the GCF beyond that value.

Gwen will owe her parents a total of $309.

To represent the total amount Gwen owes her parents after borrowing $300 with 3% interest over a year, we can use the formula for simple interest:

[tex]\[ \text{Total amount} = \text{Principal} + \text{Interest} \][/tex]

Given:

Principal (P) = $300

Interest rate (r) = 3% or 0.03 (as a decimal)

Time (t) = 1 year

Now, plug the values into the formula:

[tex]\[ \text{Interest} = P \times r \times t \][/tex]

[tex]\[ \text{Interest} = 300 \times 0.03 \times 1 \][/tex]

[tex]\[ \text{Interest} = 9 \][/tex]

Now, add the interest to the principal to get the total amount:

[tex]\[ \text{Total amount} = 300 + 9 \][/tex]

[tex]\[ \text{Total amount} = \$309 \][/tex]

So, the equation to represent the total amount Gwen owes her parents is:

[tex]\[ \text{Total amount} = 300 + 300 \times 0.03 \times 1 \][/tex]

[tex]\[ \text{Total amount} = 300 + 9 \][/tex]

[tex]\[ \text{Total amount} = \$309 \][/tex]

Therefore, Gwen will owe her parents a total of $309.

Follow below steps:

The location of the oil tanker and the luxury liner at time t hours after 2 p.m.:

The oil tanker's location: (-14t, 0)

The luxury liner's location: (0, 16t)

The distance d between the oil tanker and the luxury liner at time t:

The distance formula = √((-14t - 0)^2 + (0 - 16t)^2) = √(196t^2 + 256t^2) = √(452t^2) = 2√(113)t

The distance d between the oil tanker and the luxury liner at that time is [tex]\( \sqrt{452} \cdot t \)[/tex] kilometers.

To solve this problem, we'll use the concepts of distance, speed, and coordinate geometry.

Let ( t ) be the number of hours after 2 p.m.

Location of the Oil Tanker:

At ( t ) hours after 2 p.m., the oil tanker has traveled ( 14t ) kilometers west from the origin.

So, its location is  (-14t, 0) .

Location of the Luxury Liner:*

At ( t ) hours after 2 p.m., the luxury liner has traveled ( 16t ) kilometers north from the origin.

So, its location is  (0, 16t).

Distance between the Oil Tanker and the Luxury Liner:

We'll use the distance formula: [tex]\( d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \).[/tex]

[tex]\[ d = \sqrt{(-14t - 0)^2 + (0 - 16t)^2} \][/tex]

[tex]\[ d = \sqrt{(-14t)^2 + (-16t)^2} \][/tex]

[tex]\[ d = \sqrt{196t^2 + 256t^2} \][/tex]

[tex]\[ d = \sqrt{452t^2} \][/tex]

[tex]\[ d = \sqrt{452} \cdot t \][/tex]

So, the location of the oil tanker is [tex]\( (-14t, 0) \)[/tex], the location of the luxury liner is [tex]\( (0, 16t) \)[/tex], and the distance between them at ( t ) hours after 2 p.m. is [tex]\( \sqrt{452} \cdot t \)[/tex] kilometers.

The donut and bagel timers at Carlie's bakery will buzz together every 2 hours, so they will buzz at the same time for the first time at 10:00 a.m.

This question is about finding the Least Common Multiple (LCM) of the two numbers - 30 minutes (the time the donut timer buzzes) and 40 minutes (the time the bagel timer buzzes). The LCM of 30 and 40 is 120 minutes. This means that the timers for the bagels and the donuts will buzz at the same time every 120 minutes, or 2 hours. Since Carlie starts both timers at 8:00 a.m., the timers will buzz together for the first time at 10:00 a.m.

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If c – 8 is an odd integer, then c could be any even number greater than 8 such as 10, 12, 14, 16, because when you subtract 8 from these even numbers, the result is an odd integer.

The question requires us to find the value of c if c : 8 is an odd integer. So, if c : 8 is an odd integer, that means whatever number c is, when you subtract 8 from it, you should get an odd number. Odd numbers are integers that are not divisible by 2 and they usually end in 1, 3, 5, 7, or 9. Therefore, the possible values for c can be any even number greater than 8, such as 10, 12, 14, 16, and so on. That's because when you subtract 8 from these even numbers, the result will be an odd integer.

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