a railroad car container can hold 42,000 pounds. Mr.Evans wants to ship 90 ovens and some freezers in the same container. If each freezer weighs 600 pounds, how many freezers can be shipped in the container? Explain

Answer:

THE CORRECT AWNSER IS D

Step-by-step explanation:

The multiplication of 12 and 40 can be simplified using place value. Breaking down the 40 to 4 and multiplying gives 48, but remember to adjust back for place value, giving the final answer of 480.

To solve the equation 12x40 using place value, you need to understand that '40' is essentially '4' in the tens place which is equivalent to '4x10'. Multiplying 12 by '4' gives us '48'. Now, remembering that 4 was actually in the tens place, we apply the place value and turn it back into '480'.

This method is nothing more than a simplification of the normal multiplication process: you’re just breaking down the 40 into a easier to handle number (4), doing the multiplication, then adjusting for the fact that the 4 was actually in the tens place, not the ones. So, 12x40 equals 480.

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The length of a playground = 106 meters

The playground is a rectangular shape. There are several properties possessed by rectangular shapes, namely:

There are two rectangular shapes namely square and rectangle

Square if all sides are the same length

The formula used in rectangular is:

Rectangle

[tex]\large{\boxed{\bold{Area=w\:\times\:l}}}[/tex]

w = width

l = length

Square

[tex]\large{\boxed{\bold{area=a^2}}}[/tex]

a = length of side

Rectangle

[tex]\large{\boxed{\bold{perimeter=2\times(w+l)}}}[/tex]

w = width

l = length

Square

[tex]\large{\boxed{\bold{perimeter=4\times\:a}}}[/tex]

a = length of side

A rectangular playground has an area of 3,392 square meters

[tex]A=3,392\:m^2[/tex]

[tex]\large{\boxed{\bold{Area=w\:\times\:l}}}[/tex]

[tex]3,392\:m^2=32\:meters\times\:l[/tex]

[tex]\displaystyle l=\frac{3,392}{32}[/tex]

[tex]\boxed{\bold{l=106\:meters}}[/tex]

The ratio of the perimeters

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The coordinates of the vertices of a rectangle

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Solve the equation for w

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Emma will need to invite 32 guests for both venues to cost the same amount, which will be $3,394 in total for either venue.

Emma is comparing the cost of two venues for her surprise party and wants to find out after how many guests the costs for both the venues will be the same, as well as the total cost at that point. To solve this, we can set up an equation where the total cost for both venues is equal, with x representing the number of guests.

Let's denote Hall A's cost with an initial reservation fee of $862 plus $76 per dinner as A(x), and Hall B's cost with an initial reservation fee of $894 plus $75 per dinner as B(x).

Therefore, we can write the following equation for the point where both costs are the same:

A(x) = B(x)

862 + 76x = 894 + 75x

After solving this equation for x, we find:

76x - 75x = 894 - 862

x = 32

So, Emma will have to invite 32 guests for the cost of both venues to be the same. At this number of guests, the total cost for either venue can be calculated:

Total cost for Hall A: 862 + 76(32) = $3,394

Total cost for Hall B: 894 + 75(32) = $3,394

Both venues will cost her $3,394 when hosting 32 guests.

Jupiter is 34.023 AU closer to the Sun than Pluto. This is obtained by subtracting Jupiter's distance from the Sun (5.2 AU) from Pluto's distance from the Sun (39.223 AU).

Distance in space can often be measured in Astronomical Units (AU), which is the average distance from Earth to the Sun. Given that Jupiter is 5.2 AU from the Sun, and Pluto is 39.223 AU from the Sun, you want to find out how much closer to the Sun Jupiter is than Pluto.

To get this, you simply subtract Jupiter's distance from Pluto's distance. That is, 39.223 AU (Pluto's distance) - 5.2 AU (Jupiter's distance).

The outcome of this calculation is 34.023 AU, which means that Jupiter is 34.023 AU closer to the Sun than Pluto.

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Final answer:

Jupiter is 34.023 AU closer to the Sun than Pluto, which is calculated by subtracting Jupiter's distance from Pluto's distance.

Explanation:

Distances in space can be measured using the astronomical unit (AU), where 1 AU is approximately 150 million kilometers, the average distance from Earth to the Sun. To find out how much closer Jupiter is to the Sun than Pluto, we subtract the distance from the Sun to Jupiter from the distance from the Sun to Pluto. Given that Jupiter is 5.2 AU from the Sun and Pluto is 39.223 AU from the Sun:

Distance difference = Pluto's distance - Jupiter's distance

= 39.223 AU - 5.2 AU

= 34.023 AU

Therefore, Jupiter is 34.023 AU closer to the Sun than Pluto.

Final answer:

After dividing the initial total cost of $45.75 by three, each of Juliette and her brothers would pay $15.25. After Juliette's mom contributes $15, the remaining amount of $30.75 is divided by three, resulting in each person paying $10.25.

Explanation:

The question involves dividing a total cost among several people and then re-dividing it after one more person contributes. Initially, Juliette and her two brothers spent $45.75 on flowers. To find out how much each person will initially pay, divide the total cost by the number of people. There are three people, so each person will pay $45.75 ÷ 3 = $15.25.

Next, Juliette's mom decides to chip in $15. After her contribution, the remaining amount to be shared by Juliette and her brothers is $45.75 - $15 = $30.75. Now there are still three people sharing the cost, so each person will pay $30.75 ÷ 3 = $10.25.

Therefore, after Juliette's mom contributes, Juliette and her brothers will each pay $10.25.

In the given equation P-2+qp, when you substitute p=7 and q=4, the final result calculated is 33.

The given equation is P-2+qp. In this expression, we are to use p=7, and q=4. Substituting these values in our equation, it becomes: 7 - 2 + 7 * 4. Now, let's simplify it further step by step. First, calculate the multiplication: 7 * 4 = 28. So, the expression becomes 7 - 2 + 28. Now, perform the addition and subtraction: 7 + 28 = 35; and then 35 - 2 equates to 33. So, when you plug p = 7 and q = 4 into the equation P-2+qp, the result is 33.

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To find the amount of milk a cow can produce in 500 days at the rate of 2000 gallons every 365 days, you can set up a proportion and solve for x.

To find the amount of milk a cow can produce in 500 days at the rate of 2000 gallons every 365 days, we can set up a proportion. The correct proportion to use is:

365 days / 2000 gallons = 500 days / x gallons

To solve for x, we need to cross multiply and then divide:

365 * x = 2000 * 500

x = (2000 * 500) / 365

So the correct proportion to find x is 365 days / 2000 gallons = 500 days / x gallons.

To find the combined save percentage, you need to calculate the total number of saves and shots on goal for both goalies, and then divide the total saves by the total shots on goal. The combined save percentage is approximately 0.909.

Your friend's approach of adding the two save percentages and dividing by 2 to find the combined save percentage is incorrect. This is because save percentage is not a simple average of multiple percentages. To find the combined save percentage, you need to calculate the total number of saves and shots on goal for both goalies, and then divide the total saves by the total shots on goal.

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To convert the insect's length from 3 inches to centimeters, multiply by the conversion factor of 2.54 to get 7.62 centimeters, which is the length to the nearest hundredth of a centimeter.

The student asked: An insect is 3 inches long what is the length to the nearest hundredth of a centimeter of the insect? To convert the insect's length from inches to centimeters, we need to use the conversion factor where 1 inch equals 2.54 centimeters.

First, we multiply the insect's length in inches by the conversion factor:

Therefore, the length of the insect is 7.62 centimeters when converted from inches and rounded to the nearest hundredth of a centimeter.

When measuring the length of small items like insects, it is important to choose an appropriate tool and unit for precision. In this case, a ruler that includes both inches and centimeters would be appropriate for measuring an insect of this size. The centimeter, being smaller than the inch and equivalent to 10 millimeters, offers the precision needed for such measurements.

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