a sample of CO2 occupies a volume of 280ml at a pressure of 1.3 atm and a temperature of 18 degrees celsius, what volume will the gas occupy at a temp of 35 degrees celsius and a pressure of 3.0 atm

The fraction is calculated like this:

[tex] \frac{1}{ {2}^{50 \div 10} } = \frac{1}{32} [/tex]

If you want an universal equation for all problems like this:

[tex] \frac{1}{ {2}^{time \div halflife} } [/tex]

The fraction of the original mass of the radioactive isotope with a half-life of 10 years that will remain after 50 years is 1/32.

We can find the fraction of the original mass with the exponential decay equation:

[tex] N(t) = N_{0}e^{-\lambda t} [/tex]  (1)

Where:

N(t): is the amount of radioactive isotope at time t

N₀: is the initial amount of radioactive isotope

λ: is the decay constant

t: is the time = 50 y

We can find the decay constant as follows:

[tex] \lambda = \frac{ln(2)}{t_{1/2}} [/tex]   (2)

Where:

[tex]t_{1/2}[/tex]: is the half-life of the isotope = 10 y

The decay constant is (eq 2):

[tex] \lambda = \frac{ln(2)}{t_{1/2}} = \frac{ln(2)}{10 y} = 0.069 y^{-1} [/tex]

Now, the fraction of the original amount is (eq 1):

[tex] \frac{N(t)}{N_{0}} = e^{-\lambda t} = e^{-0.069 y^{-1}*50 y} = 0.0317 [/tex]

Since we need to calculate the fraction of the original mass, after some algebraic operations we have:

[tex] \frac{N_{0}}{N(t)} = 32 [/tex]  

[tex] N(t) = \frac{1}{32}N_{0} [/tex]                          

Therefore, the fraction of the original mass that will remain is 1/32.

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I hope it helps you!  

You didn’t list the statements.

Answer:

The answer is C. I just had this question.

Explanation:

Q=mc*temperature change

400=5.6/1000*c*(87-23)

c=1160.07J/kg/k

The latitude changes the climate, so if the ocean water is in the Antarctic Ocean, it will most likely be cold. The depth of the ocean water matters because it determines the amount of sunlight that the water receives therefore heating it.

Nitrogen and oxygen are primary gases in the atmosphere.  

Trace  

Variable  

Primary  

Rare

They are he Primary gasses in the atmosphere with the percentages being 78% nitrogen, 21% oxygen

hope this has helped

I do believe the answer is A. Hope this helps.

I think A would be the correct answer

Answer:

34.33 %.

Explanation:

W% = [(W of solute NaF)/(W of solution)] x 100.

W of solute NaF = 65.4 g.

W of solution = W of solute NaF + W of water = 65.4 g + 125.1 g = 190.5 g.

∴ W% = [(W of solute NaF)/(W of solution)] x 100 = [(65.4 g)/(190.5 g)] x 100 = 34.33 %.

B.The rate of forward reaction increases.

Answer: B) The rate of forward reaction increases.

Change in temperature affects the rate of reaction since it causes a change in the number of collisions per unit time.  These collisions cause the breaking of bonds and formation of new ones  giving out new products. An increase in temperature increases the rate of collisions hence increasing the rate of reaction while a decrease in temperature leads to a decrease in the rate of reaction due to the decreased number of collisions per unit time. thus the correct choice for blank A is: B. the number of collisions between molecules and for blank B: decrease.

Answer:

A decrease in temperature changes "the number of collisions between molecules. The reaction rate will decrease.

Blank A: "the number of collisions between molecules.

Blank B: decrease.

An increase in temperature causes a rise in the energy levels of the molecules involved in the reaction, so the rate of the reaction increases. Similarly, the rate of reaction will decrease with a decrease in temperature.

ΔH° = -851.5 kJ/mol given that

[tex]\begin{array}{cc}\textbf{Species}&{\bf {\Delta H_f\textdegree{}}}\\ \text{Fe}_2\text{O}_3\;(s) & -824.2\;\text{kJ}\cdot\text{mol}^{-1}\\\text{Al}_2\text{O}_3\;(s) & -1675.7\;\text{kJ}\cdot\text{mol}^{-1}\end{array}[/tex]

(Source: Chemistry Libretexts.)

Refer to a thermodynamic data table for the standard enthalpy of formation for each species.

Don't be alerted if the data for Al (s) and Fe (s) are missing. Why?

As a result, [tex]\Delta H_f\textdegree{} = 0[/tex] for both Al (s) and Fe (s).

[tex]\displaystyle \Delta H_{\text{rxn}}\textdegree{} = \text{Sum of }\Delta H\text{ for all }\textbf{Product} - \text{Sum of }\Delta H\text{ for all }\textbf{Reactant}}\\\phantom{\Delta H_{\text{rxn}}\textdegree{}} = (1\times \Delta H_f\textdegree{}(\text{Al}_2\text{O}_3\;(s)) + 1\times \Delta H_f\textdegree{}(\text{Al}\;(s)) \\ \phantom{\Delta H_{\text{rxn}}\textdegree{}=}-(1\times \Delta H_f\textdegree{}(\text{Fe}_2\text{O}_3\;(s)) + 1\times\Delta H_f\textdegree{}(\text{Fe}\;(s))[/tex]

[tex]\Delta H_{\text{rxn}}\textdegree{}} = (1 \times (-1675.7)) - (1\times(-824.2)) = -851.5\;\text{kJ}\cdot\text{mol}^{-1}[/tex].

The number "1" here emphasizes that in case there are more than one mole of any species in one mole of the reaction, it will be necessary to multiply the [tex]\Delta H_f\textdegree{}[/tex] of that species with its coefficient in the equation.

Answer:

for table C

Explanation:

What is the concentration of H+ ions at a pH = 11?

1.  ⇒ 0.00000000001 mol/L  

What is the concentration of H+ ions at a pH = 6?

2.  ⇒ 0.000001 mol/L  

How many fewer H+ ions are there in a solution at a

pH = 11 than in a solution at a pH = 6?

3.  ⇒ 100,000

The concentration of H+ ions at pH 11 is 1.0 x 10^-11 mol/L and at pH 6 is 1.0 x 10^-6 mol/L. There are 100,000 times fewer H+ ions at a pH of 11 than at a pH of 6.

The concentration of H+ ions in a solution can be calculated using the pH value, which is the negative logarithm (base 10) of the hydrogen ion concentration. Therefore, pH = -log[H+], and to find [H+], we can use the inverse logarithmic relationship: [H+] = 10^-pH.

For a solution with a pH of 11, the concentration of H+ ions would be: [H+] = 10^-11 mol/L, which equals 1.0 x 10^-11 mol/L.

For a solution with a pH of 6, the concentration of H+ ions would be: [H+] = 10^-6 mol/L, which equals 1.0 x 10^-6 mol/L.

To find how many fewer H+ ions are in a solution with a pH of 11 compared to a pH of 6, we divide the two concentrations: (1.0 x 10^-11 mol/L) / (1.0 x 10^-6 mol/L) = 1.0 x 10^-5. This means that the solution with a pH of 11 has 100,000 times fewer H+ ions than the solution with a pH of 6.

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Answer: the answer is letter c. melting

Answer:

C melting

Explanation: we can eliminate 2 right off the bat eroison and weathering you can eliminate them because their above ground and subsurface means below the surface. You eliminate cementing because it wants in the deeper section of the earth.

Similar chemical properties

(OPTION C)

Answer:

similar chemical properties

Explanation:

i can confirm his answer

B solids made of atoms

Solids with the highest melting points are typically those with either covalent networks or ionic bonds, due to the strength of their atomic or ionic interactions.  So the correct option is C.

The type of solid that often has the highest melting points are those made of atoms arranged in a covalent network or those formed by ionic bonds. Solids that consist of ionic bonds, such as sodium chloride (NaCl), typically have high melting points due to the strong electrostatic interactions between the positively and negatively charged ions within a crystal lattice. Similarly, materials with a covalent network, like diamond or silicon dioxide (SiO2), have very high melting points because they consist of a three-dimensional array of covalently bonded atoms that require a lot of energy to break apart. In contrast, molecular solids composed of nonpolar or polar molecules have lower melting points due to their weaker intermolecular forces, such as London dispersion forces, dipole-dipole interactions, and in some cases, hydrogen bonding.

Answer:

2.138 I think

Explanation:

N2 + 3H2 -> 2NH3

This means that 3 moles of H2 gives 2 moles of NH3

Lets convert 12.12 g of NH3 into moles.

The molecular weight of NH3 is 17 g/mol

So 12.12 g is 0.713 moles

If 2 NH3 comes from 3 moles of H2

1 mole comes from 1.5 moles of H2

So 0.713 moles of NH3 comes from 1.5 x 0.713 moles of H2 =1.069 moles of H2

1 mole of H2 weights 2g

So 1.069 moles of H2 weighs 2.138 g

Molarity's formula is known as: Molarity(M)=moles of solute/liters solution.

In this case we are already given moles and liters so you just have to plug the numbers into the equation.

0.400 mol HCL/9.79L solution=0.040858M

If you were to use scientific notation, the answer will be: 4.1*10^-2, but otherwise, you can just use the decimals above and round appropriately as you see fit.

Final answer:

To calculate the molarity of a solution with 0.400 mol of HCl in 9.79 L, divide the moles by the volume, resulting in a molarity of 0.0409 M.

Explanation:

The question asks how to calculate the molarity of a hydrochloric acid (HCl) solution. Given that the solution contains 0.400 mol of HCl and has a total volume of 9.79 liters, we can use the definition of molarity. Molarity is defined as the number of moles of solute (in this case, HCl) divided by the volume of the solution in liters.

To find the molarity, we perform the following calculation:

Molarity = moles of solute / liters of solution
Molarity = 0.400 mol / 9.79 L

This gives us a molarity of:

0.0409 M

Therefore, the molarity of the HCl solution is 0.0409 M.

Fire is burning, which is combustion, and combustion is a type of oxidation reaction. Oxidation means combined chemically with oxygen . Oxidation is an exothermic reaction, meaning it gives releases heat energy.

for a is burning. which is combustion and that is a type of oxidation means to combine chemically with oxygen.

Answer:

Human activities have a tremendous impact on the carbon cycle. Burning fossil fuels, changing land use, and using limestone to make concrete all transfer significant quantities of carbon into the atmosphere. This extra carbon dioxide is lowering the ocean's pH, through a process called ocean acidification.

Significant amounts of carbon are released into the atmosphere as a result of the burning of fossil fuels, changing how land is used, and the production of concrete with limestone.

The flow of carbon on earth in its elemental and mixed phases is represented by the carbon cycle. The elemental kinds of carbon are diamond and graphite, and when they are mixed, they are found as carbonates throughout minerals as well as carbon dioxide gases throughout the atmosphere. Carbon is returned to the atmosphere as plants and animals perish and are degraded.

Plants use carbon from the atmosphere to produce photosynthesis. Animals eat these plants, which causes carbon to bioaccumulate in their bodies. Significant amounts of carbon are released into the atmosphere as a result of the burning of fossil fuels, changing how land is used, and the production of concrete with limestone. The carbon cycle is greatly impacted by human activity.

Therefore, significant amounts of carbon are released into the atmosphere as a result of the burning of fossil fuels, changing how land is used, and the production of concrete with limestone.

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A is the answer i dont really know but i think is right

Answer : The correct option is, (A) Pressure is directly proportional to density.

Explanation :

Density : It is defined as the mass contained per unit volume.

Formula used for density :

[tex]Density=\frac{Mass}{Volume}[/tex]

From this we conclude that, the density depends on mass and volume of substance.

The density is directly proportional to the mass of substance and inversely proportional to the volume of substance.

[tex]Density\propto \frac{1}{Volume}[/tex]

And as we know that, the volume is also depends on pressure and temperature. That means,

Volume is directly proportional to the temperature and inversely proportional to the pressure.

[tex]Volume\propto Temperature\\\\Volume\propto \frac{1}{Pressure}[/tex]

From this we conclude that,

The relation between the density, volume and pressure is:

[tex]Density\propto \frac{1}{Volume}\propto Pressure[/tex]

The relation between the density, volume and temperature is:

[tex]Density\propto \frac{1}{Volume}\propto \frac{1}{Temperature}[/tex]

From the given option, only option A is correct option. While the other options are incorrect.

Hence, the correct option is A.

Final answer:

The final temperature after thermal equilibrium is reached is approximately 46.6°C.

Explanation:

To find the final temperature after thermal equilibrium is reached, we can use the principle of conservation of energy. The heat gained by the cool water is equal to the heat lost by the hot water.

Let's denote the final temperature as T. The heat gained by the cool water can be calculated using the equation q = m * c * ΔT, where q is the heat gained, m is the mass of the cool water, c is the specific heat of water, and ΔT is the change in temperature. The heat lost by the hot water can be calculated using the same equation. Setting the two equations equal to each other and solving for T will give us the final temperature.

Using the given values, we can calculate:

qcool = (200 g) * (4.18 J/g°C) * (T - 32°C)

qhot = (50 g) * (4.18 J/g°C) * (55°C - T)

Setting qcool equal to qhot:

(200 g) * (4.18 J/g°C) * (T - 32°C) = (50 g) * (4.18 J/g°C) * (55°C - T)

Simplifying and solving for T:

800(T - 32°C) = 50(55°C - T)

T = 46.6°C

Therefore, the final temperature after thermal equilibrium is reached is approximately 46.6°C.

1. First calculate the total molar mass of the entire compound.

Mg = 3 x 24.31 = 72.93 g/mol

P = 2 x 30.97 = 61.94 g/mol

O = 8 x 16.00 = 128.00 g/mol

* Add them up;

72.93 + 61.94 + 128.00 = 262.87 g/mol

2. Take the individual masses of each element that you calculated, divide them by the total mass (262.87 g/mol) and then multiply by 100.

Mg = 72.93/262.87 = 0.2774 x 100 = 27.74%

P = 61.94/262.87 = 0.2356 x 100 = 23.56%

O = 128.00/262.87 = .4870 x 100 = 48.70%

3. All of the percentages should add up to equal 100%.

* Hope this helps

1. Firstly we have to calculate the total molar mass of the entire compound.

2. Now we have to Take the individual masses of each element that you calculated, then divide them by the total mass (262.87 g/mol), and also then multiply by 100.

3. Thus All of the percentages should add up to equal 100%.

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Molarity's formula is: moles solute/liters solution.

In this question, we are given grams of solute so we have to convert that to moles.

NaNO3 has a molar mass of 84.9947g/mol. Here we begin with the given 212.5g and multiplying it by 1mol/84.9947g because the grams have to cancel out to give moles.

[tex](212.5 grams NaNO3)/(\frac{1 mole NaNO3}{84.9947 grams NaNO3} ) =2.5 moles NaNO3[/tex]

Now that we have moles of solute, we just plug it into the formula.

2.5 mols NaNO3/3L solution=0.8333 M of solution

The molarity of the solution containing 212.5 g of NaNO₃ in 3 L of solution is 0.83 M

This is defined as the mole of solute per unit litre of solution. Mathematically, it can be expressed as:

Molarity = mole / Volume

Mole = mass / molar mass

Mole of NaNO₃ = 212.5 / 85

Mole of NaNO₃ = 2.5 mole

Molarity = mole / Volume

Molarity = 2.5 / 3

Molarity = 0.83 M

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It is the atomic number. So it is D.

Answer:

0.00479099293329 g

Explanation:

The formula for GPE is PE=mgh, where “m” is the mass of the object, “g” is the acceleration due to gravity (~9.8 m/s^2 on Earth’s surface), and “h” is the height of the object from the ground. Therefore,

PE=mgh

PE=(6 kg)(9.8 m/s^2)(1 m)

PE=58.8 kg•m^2/s^2 or 58.8 Newtons

The GPE of the bowling ball under these conditions would be about 59 Newtons.

Hope this helps!

Answer:

Polar , bent , polar

An SCl2 molecule has polar bonds and a bent molecular shape. As a result, an SCl2 molecule is polar.

Explanation:

The correct blanks for 1, 2 and 3 are polar bonds, bent molecular shape and polar respectively.

An [tex]SCl_2[/tex] molecule has 1. polar bonds and a 2. bent molecular shape. As a result, an SCl2 molecule is 3. polar. In [tex]SCl_2[/tex], the sulfur (S) and chlorine (Cl) atoms form double bonds. Because chlorine is more electronegative than sulfur, resulting in an unequal distribution of electron density, the S–Cl bonds in[tex]SCl_2[/tex]  are polar. [tex]SCl_2[/tex] has a bent or V-shaped molecular shape. On sulfur, which has a lone pair of electrons and two bond pairs, the repulsion between these electron pairs leads the molecule to a bent shape.

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B. Helium

It has only He atoms

answer is one first one for one electron.