A school graduation class wants to hire buses and vans for a trip to Jasper National Park. Each bus
holds 40 students and 3 teachers and cost $1200 to rent. Each van holds 8 students and 1 teacher
and costs $100 to rent. The school has at least 400 students wanting to go, but at most 36 teachers.
What is the minimum transportation cost?

Answers

Answer 1
Let the school hire x buses and y vans.

A bus can hold 40 students and 3 teachers.
A van can hold 8 students and 1 teacher.

The number of students riding in  buses and vans is at least 400, therefore
40x + 8y ≥ 400          (1)

The number of teachers riding in buses and vans is at most 36, therefore
3x + y ≤ 36                (2)

Write (1) and (2) as
y ≥ 50 - 5x                 (3)
y ≤ 36 - 3x                 (4)

The equality portion of the solution of (3) and (4) is
36 - 3x = 50 - 5x
2x = 14
x = 7   =>  y = 36 - 3*7 = 15

A graph of the inequalities indicates the acceptable solution in shaded color, as shown below.

The minimum cost of renting buses and vans is
7*$1200 + 15*$100 =  $9900

Answer: The minimum cost is $9,900

A School Graduation Class Wants To Hire Buses And Vans For A Trip To Jasper National Park. Each Bus Holds

Related Questions

Benjamin has $6000 invested in two accounts. One earns 8% interest per year, and the other pays 7.5% interest per year. If his total interest for the year is $472.50, how much is invested at 8%?

Answers

0.08x+0.075 (6000-x)=472.5
Solve for x
0.08x+450-0.075x=472.5
0.08x-0.075x=472.5-450
0.005x=22.5
X=22.5/0.005
X=4500 invested at 8%

Answer:

Benjamin invested $4,500 at 8%.

Step-by-step explanation:

We know that Benjamin has invested $6,000 in two different accounts.

Let account 1 earn 8% interest per year be defined as [tex]x[/tex] and account 2 earn 7.5% interest per year as [tex]y[/tex].

The sum of both accounts must be $6,000:

[tex]x+y=6,000[/tex]

We also know that at the end of the year Benjamin earned $472.50, which is the sum of the interest he earned of the amount he invested in account 1 and in account 2, with their different interest rates (in this case, it is useful for us to transform the expression of the interest rate by dividing it by 100, so that it can be simplified):

[tex](0.08x)+(0.075y)=472.5[/tex]

We need to express the [tex]y[/tex] in terms of [tex]x[/tex].

From our first expression, we know that:

[tex]y=6,000-x[/tex]

So we substitute this value in our second equation and solve it:

[tex](0.08x)+(0.075(6,000-x))=472.5[/tex]

[tex](0.08x)+((0.075*6,000)-0.075x)=472.5[/tex]

[tex](0.08x)+((0.075*6,000)-0.075x)=472.5[/tex]

[tex]0.08x+450-0.075x=472.5[/tex]

[tex]0.08x-0.075x=472.5-450[/tex]

[tex]0.005x=22.5[/tex]

[tex]x=\frac{22.5}{0.005}[/tex]

[tex]x=4,500[/tex]

This way, we know that the amount that Benjamin invested in the account that earns 8% interest per year is $4,500.

A furniture store is having a going-out-of-business sale. Two hours after opening, there are 415 sofas still available. Three hours later, there are 301 sofas available. How many hours will the store have to stay open to sell the entire inventory? Assume the sales rate is constant and round your answer to the nearest whole hour.

Answers

Because the sales rate is constant, assume that
x(t) = a + bt
where
x = number of sofas remaining after t hours from opening,
a, b are constants.

When t = 2 hours, x = 415. Therefore
a + 2b = 415          (1)

Three hours later (t = 2 +3 = 5), there are 301 sofas left.
Therefore
a + 5b = 301          (2)

Subtract (2) from (1).
-3b = 415 - 301 = 114
b = -38

From (1), obtain
a = 415 - 2*(-38) = 491

The required function is
x(t) = 491 - 38t

When all sofas are sold, x=0. Therefore the time required to complete the sale is given by
491 - 38t = 0
38t = 491
t = 12.92 hours

Answer:
The time required to sell the inventory is 13 hours (nearest whole hour)

When a jug is half- filled with marbles, it weighs 2.6 kg. The jug weighs 4 kg when it is full. Find the weight of the empty jug.

Answers

the difference between a full jug and a jug that is half full will give us the weight of the marbles only in a half full jug:
4 - 2.6 = 1.4 kg

In a half full jug that weighs 2.6 kg, the weight of the marbles is 1.4 kg 
the weight of the jug = 2.6 - 1.4 = 1.2 kg

Answer:

The jug weights empty 1.2 kg.

Step-by-step explanation:

In this case we can define two equations based on the description to find the weight of the empty jug, this is:

Eq. 1: [tex]Jug+\frac{1}{2} Marbles=2.6[/tex]

Eq. 2: [tex]Jug+Marbles=4[/tex]

Now putting the Eq. 2 in the Eq. 1 we have:

[tex]Jug+\frac{1}{2} (4-Jug)=2.6[/tex]

Clearing Jug:

[tex]\frac{1}{2}Jug=2.6-2[/tex]

[tex]Jug=0.6*2[/tex]

[tex]Jug=1.2[/tex]

The jug weights empty 1.2 kg.

EASY 5 POINTS!!! Shaundra wants to triple the volume of a square pyramid. What should she do?

Answers

Answer: Triple the height of the pyramid

Step-by-step explanation:

To triple the volume of a square pyramid, triple the height of the pyramid. Therefore, the option C is the correct answer.

What is the volume?

Volume is the measure of the capacity that an object holds.

Formula to find the volume of the object is Volume = Area of a base × Height.

The volume of a square pyramid refers to the space enclosed between its five faces. The volume of a square pyramid is one-third of the product of the area of the base and the height of the pyramid. Thus, volume = (1/3) × (Base Area) × (Height).

To triple the volume of a square pyramid, triple the height of the pyramid.

Therefore, the option C is the correct answer.

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A container holds 10 quarts of water. How much is this in gallons? Write your answer as a whole number or a mixed number in simplest form

Answers

There are 2.5 gallons in 10 quarts.
10qt(gal/4qts)=10/4 gal=2 2/4 gal= 2 1/2 gallons

1/2 of a group of chickens tried to cross the road. Only 3/4 of those chickens made it to the other side. What fraction of the original group of chickens made it to the other side?

Answers

1/2 tried to cross the road.....3/4 made it..
3/4 of 1/2 = 3/4 * 1/2 = 3/8...so 3/8 made it to the other side

Answer:

[tex]\frac{3}{8}[/tex] of the group

Step-by-step explanation:

[tex]\frac{1}{2}[/tex] of a group of chickens tried to cross the road.

only [tex]\frac{3}{4}[/tex] of those chickens made it to the other side.

So  [tex]\frac{3}{4}[/tex] × [tex]\frac{1}{2}[/tex]

= [tex]\frac{3}{8}[/tex]  of the group of chickens made it to the other side.

32x - 4 = 4x2 + 60 For the equation shown, choose the description of the solutions.

Answers

Final answer:

The quadratic equation 32x - 4 = 4x2 + 60 has real and equal solutions after rearranging to 4x2 - 32x + 64 = 0 and recognizing it as a perfect square.

Explanation:

To solve the equation 32x - 4 = 4x2 + 60, we first rearrange it into standard quadratic form ax2 + bx + c = 0.

We move all terms to one side: 4x2 - 32x + 64 = 0. Once in this form, we can use the quadratic formula, x = (-b ± √(b2 - 4ac)) / (2a), or factor if it is factorable, to find the solutions for x. After rearranging, we note that the quadratic is a perfect square, giving us (2x - 8)2 = 0, which means that the solution for x is 4, with multiplicity of two since it is a repeated root.

The description of the solutions would be that they are real and equal, since we have a repeated solution.

If you earn one penny every 10 seconds of your life ,how many dollars would you have after 65 years?

Answers

There are 60 seconds in a minute, 60 minutes in an hour, 24 hours in a day, and 365 days in a year. You are assuming that 65 years is the length. We will find the number of seconds in 65 years.

60 x 60 x 24 x 365 x 65 = 2,049,840,000 seconds.
We should note that every 4 years there is an extra day, so if we find 65 % 4 or the modulus of 65 then we can add this. The modulus of this is 16.
60 x 60 x 24 x 16 x 65 = 89,856,000 seconds

2,139,696,000 seconds (when you add the two calculations together).

You are finding it "every 10 seconds" so divide this value by 10. Then divide by another 100 because you are only counting dollars and 100 pennies is equal to 1 dollar.
The answer is : $2,139,696

Find dy/dx and d2y/dx2, and find the slope and concavity (if possible) at the given value of the parameter. (if an answer does not exist, enter dne.) parametric equations point x = 6 cos θ, y = 6 sin θ θ = π 4

Answers

We are given the parametric equations:

x = 6 cos θ

y = 6 sin θ

We know that the derivative of cos a = - sin a and the derivative of sin a = cos a, therefore taking the 1st and 2nd derivates of x and y:

d x = 6 (-sin θ) = - 6 sin θ

d^2 x = -6 (cos θ) = - 6 cos θ

d y = 6 (cos θ) = 6 cos θ

d^2 y = 6 (-sin θ) = - 6 sin θ

 

Therefore the values we are asked to find are:

dy / dx = 6 cos θ / - 6 sin θ = - cos θ / sin θ = - cot θ

d^2 y / d^2 x = - 6 sin θ / - 6 cos θ = sin θ / tan θ = tan θ

 

We can find the value of the slope at θ = π/4 by using the dy/dx:

dy/dx = slope = - cot θ

dy/dx = - cot (π/4) = - 1 / tan (π/4)

dy/dx = -1 = slope

 

We can find the concavity at θ = π/4 by using the d^2 y/d^2 x:

d^2 y / d^2 x = tan θ

d^2 y / d^2 x = tan (π/4)

d^2 y / d^2 x = 1

Since the value of the 2nd derivative is positive, hence the concavity is going up or the function is concaved upward.

 

Summary of Answers:

dy/dx = - cot θ

d^2 y/d^2 x = tan θ

slope = -1

concaved upward

The surface areas of two similar solids are 340 yd2 and 1,158 yd2. The volume of the larger solid is 1,712 yd3. What is the volume of the smaller solid?

Answers

Let us say that,

1 = smaller solid

2 = larger solid

We must remember that the surface area of an object is proportional to the square of their sides, therefore,

SA = k s^2

where k is the constant of proportionality.

By taking the ratio of the 2 similar solids:

SA2 / SA1 = k s2^2 / k s1^2

SA2 / SA1 = s2^2 / s1^2

sqrt (SA2 / SA1) = s2 / s1

s2 / s1 = sqrt (1158 / 340)


While the volume of an object is proportional to the cube of their sides, therefore:

V = k’ s^3
where k’ is the constant of proportionality.

By taking the ratio of the 2 similar solids:

V2 / V1 = k’ s2^3/ k’ s1^3

V2 / V1 = s2^3/ s1^3

1712 / V1 = [sqrt (1158 / 340)]^3

1712/V1 = 6.28556705

V1 = 272.37 yd^3

if the GCF of two numbers is 1, they are called relatively prime. Find three sets of relatively prime numbers

Answers

The GCF can be obtained by taking the prime factors of two numbers then multiplying the common prime factors. IF there are none, then the GCF is 1 and the numbers are called relatively prime.

There are a lot of relatively prime numbers. To name three sets:

3 and 19

7 and 20

15 and 28

 

For these sets, we see that there are no other common factors except 1. To illustrate the factors:

3 = 1, 3

19 = 1, 19

 

7 = 1, 7

20 = 1, 2, 2, 5

 

15 = 1, 3, 5

28 = 1, 2, 2, 7

 

So we see that only the number 1 is the factor in each set.

Final answer:

Three sets of relatively prime numbers are 9 and 16, 14 and 25, and 8 and 21, as they do not share any common prime factors other than 1.

Explanation:

If the Greatest Common Factor (GCF) of two numbers is 1, they are indeed referred to as relatively prime. To find sets of relatively prime numbers, we need to identify pairs of numbers that do not have any prime factors in common other than 1.

9 and 16: The prime factors of 9 are 3· 3, and the prime factors of 16 are 2· 2· 2· 2. They share no common prime factors, so they are relatively prime.

14 and 25: The prime factors of 14 are 2· 7, and the prime factors of 25 are 5· 5. Since they have no common factors, these numbers are also relatively prime.

8 and 21: The prime factors of 8 are 2· 2· 2, and the prime factors of 21 are 3· 7. With no prime factors in common, 8 and 21 are relatively prime.

Therefore, we have found three sets of relatively prime numbers: 9 and 16, 14 and 25, and 8 and 21.

Your six month old baby has doubled his birth weight, is grasping objects and pulling them to his mouth, and seems hungry all the time despite the eight full bottles he drinks each day. do you start solids yet

Answers

I would say that the child is prepared for solid foods because it is capable of grasping things such as food. If the baby can gulp easily and sit up without adjustment solids are okay to switch the child on at this point. Also you can give a child solid food anywhere starting from 4-6 months old.

Supplementary breast milk is given to babies after babies 6 months of age and over with a gradual texture starting from fine, filtered porridge, pureed porridge, then solid food such as adult food. Complementary food for breast milk is better if it contains 4 stars namely carbohydrates, vegetable protein, animal protein, and vegetables.

Further Explanation

When a baby enters the age of 6 months, he needs more calories than just the nutrition he gets through exclusive breastfeeding. At this age, you can introduce your baby's first solid food.

Feeding is not just filling the baby's stomach with nutritious food, but also provides education about pleasant interactions, stimulation of the sense of taste, fine motor training (moving hands and directing to the mouth that requires good coordination between hands, eyes, and of course, the brain), chewing and discipline.

8 Solid Foods for 6-Month-Old Babies

Cereal Banana Sweet Potato Avocado Chicken or Beef Meat Pear Tofu Wheat bread

In addition to some of the foods above, introduce other solid foods as well. Of course, the texture must be adjusted to the stage of growth of the baby. Do not forget, introduce food one by one to see what foods cause allergies in children.

In general, the purpose of first feeding for babies from 6 months of age are:

Meet the nutritional needs of babies. Develops the baby's ability to accept a variety of foods with different tastes and textures. Develops and trains baby's motor skills such as chewing and swallowing.

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Grade: College

Subject: Health

Keyword: complementary, food, baby

Which is least? 0.105 0.501 0.015 or 0.15

Answers

0.015 is the least. 

Because it is the farthest away from the one's place.
Final answer:

The lowest decimal number from 0.105, 0.501, 0.015, and 0.15 is 0.015. This is because when we compare the numbers from left to right, 0.015 has the smallest digit (0) at the second decimal place which is the hundredths place.

Explanation:

To determine which decimal number is the lowest, it's helpful to compare these numbers digit by digit from the left. The four numbers are 0.105, 0.501, 0.015, and 0.15. Each of them starts with 0. The second digit of 0.105, 0.501, and 0.15 is 1, but the second digit for 0.015 is 0. So, 0.015 is the lowest number because it has the smallest digit (0) in the second decimal place (hundredths place). Remember, these numbers are read as decimals and not as whole numbers, so the digit at each decimal place has a different significance.

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The figure has ____ lines of symmetry. A. 0 B. 4 C. 6 D. 8

Answers

Final answer:

A figure with 5-part symmetry has 5 lines of symmetry.

Explanation:

A figure with 5-part symmetry has 5 lines of symmetry. This means that it can be divided into five equal parts by rotating it around these lines. Each line of symmetry divides the figure into two mirror-image halves.

600 is 1/10 of6000 true or false

Answers

True. If you want to know 1/10 of something, move the decimal place to the left.

6,000. then move it to the left once 600.0

and if you want to multiply something by ten, just add a zero
600 add zero and it's 6,000

What is the simplified form of the rational expression below? 5x^2-5 over 3x^2+3x

Answers

The answer is (5(x-1))/3x
Hello there!

5x² - 5/ 3x² + 3x
= 5(x+1)(x-1) all over 3x(x+1)
= 5x - 5 over 3x


I hope that helps!

Suppose a triangle has sides a, b, and c with side c the longest side, and that a^2 + b^2 > c^2. Let theta be the measure of the angle opposite the side of length c. Which of the following must be true? Check all that apply.

the triangle in question is a right triangle
cos(theta) <0
the triangle is not a right triangle
theta is an acute angle

Answers

For special triangles like right triangles, the longest side which is the hypotenuse is always the longest side. The pythagorean theorem that relates all three sides of the triangles is

a²+b²=c²

But since the problem states that the sum of the squares of a and b is greater than the square of the hypotenuse, the c is not the longest side of the triangle anymore. Thus, the triangle IS NOT a triangle. 

About the value of the angle θ, there is no way of knowing it without any given data of the sides. So, the only conclusion we can make is the nature of the triangle.

The inequality [tex]a^2 + b^2 > c^2[/tex] indicates that the triangle is not a right triangle and the angle theta is acute. The cosine of an acute angle theta will be positive, not negative.

When it is given that a triangle has sides a, b, and c, with c being the longest side, and the inequality [tex]a^2 + b^2 > c^2[/tex] holds, we can deduce certain characteristics of the triangle and angle theta, which is opposite to side c. This inequality indicates that the triangle is not a right triangle, because for a right triangle, according to the Pythagorean theorem, the relationship between the sides is [tex]a^2 + b^2 = c^2.[/tex]

Since [tex]a^2 + b^2 > c^2[/tex], we can infer that the angle opposite the longest side, theta, must be acute because the sum of the angles in any triangle equals two right angles. Therefore, if theta were obtuse, the sum of the angles would be greater than two right angles, which contradicts the basic properties of triangles.

The correct statements are that the triangle is not a right triangle and that theta is an acute angle.  cos(theta) is not necessarily < 0; for an acute angle, the cosine value will be positive. The first statement that the triangle is a right triangle is incorrect because it contradicts our given information and the Pythagorean theorem.

Reduce the following fraction: -36x^4y^4z^5/-12x^6y^3z

A. -3x^2yz^4
B. 3yz^4/1x^2
C. -9yz^5/-3x^2
D. 36yz^5/12x^2

Answers

[tex]\bf \left.\qquad \qquad \right.\textit{negative exponents}\\\\ a^{-{ n}} \implies \cfrac{1}{a^{ n}} \qquad \qquad \cfrac{1}{a^{ n}}\implies a^{-{ n}} \qquad \qquad a^{{{ n}}}\implies \cfrac{1}{a^{-{{ n}}}}\\\\ -------------------------------\\\\[/tex]

[tex]\bf \cfrac{-36x^4y^4z^5}{-12x^6y^3z}\quad \begin{cases} 36=2\cdot 2\cdot 3\cdot 3\\ 12=2\cdot 2\cdot 3 \end{cases}\implies \cfrac{-36}{-12}\cdot \cfrac{x^4y^4z^5}{x^6y^3z^1} \\\\\\ \cfrac{\underline{-2\cdot 2\cdot 3}\cdot 3}{\underline{-2\cdot 2\cdot 3}}\cdot \cfrac{x^4y^4z^5x^{-6}y^{-3}z^{-1}}{1}\implies \cfrac{3}{1}\cdot \cfrac{x^4x^{-6}y^4y^{-3}z^5z^{-1}}{1}[/tex]

[tex]\bf \cfrac{3}{1}\cdot \cfrac{x^{4-6}y^{4-3}z^{5-1}}{1}\implies \cfrac{3}{1}\cdot\cfrac{x^{-2}y^{1}z^4}{1}\implies \cfrac{3x^{-2}yz^4}{1}\implies \cfrac{3yz^4}{x^2}[/tex]

A football is thrown with an initial upward velocity of 25 feet per second from a height of 5 feet above the ground. The equation h = −16t^2 +25t + 5 models the height in feet t seconds after it is thrown. After the ball passes its maximum height, it comes down and hits the ground. About how long after it was thrown does it hit the ground?

Answers

A = -16
B = 25
C = 5

Plug into the quadratic equation and you get: -0.18 and 1.75. Since we cannot have a negative time our answer is 1.75 seconds.

Answer:

1.74 second long after it was thrown does it hit the ground.

Step-by-step explanation:

Given : A football is thrown with an initial upward velocity of 25 feet per second from a height of 5 feet above the ground. The equation [tex]h =-16t^2+25t+5[/tex] models the height in feet t seconds after it is thrown.

To find : How long after it was thrown does it hit the ground?

Solution :

The equation model is [tex]h(t)=-16t^2+25t+5[/tex]

After the ball passes its maximum height, it comes down and hits the ground.

i.e. h=0

So, [tex]-16t^2+25t+5=0[/tex]

Solve by quadratic formula of equation [tex]ax^2+bx+c=0[/tex] is [tex]x = \frac{-b \pm \sqrt{b^2-4ac}}{2a}[/tex]

Here, a=-16 , b=25 and c=5

[tex]t=\frac{-25 \pm \sqrt{(25)^2-4(-16)(5)}}{2(-16)}[/tex]

[tex]t=\frac{-25 \pm \sqrt{625+320}}{-32}[/tex]

[tex]t=\frac{-25 \pm \sqrt{945}}{-32}[/tex]

[tex]t=\frac{-25+\sqrt{945}}{-32},\frac{-25-\sqrt{945}}{-32}[/tex]

[tex]t=-0.179,1.741[/tex]

We reject t=-0.179.

Therefore, 1.74 second long after it was thrown does it hit the ground.

When a certain type of thumbtack is​ flipped, the probability of its landing tip up​ (U) is 0.54 0.54 and the probability of its landing tip down​ (D) is 0.46 0.46. Suppose you flip two such​ thumbtacks, one at a time. The probability distribution for the possible outcomes of these flips is shown below. a. Find the probability of getting 0​ ups, 1​ up, or 2 ups when flipping two thumbtacks. b. Make a probability distribution graph of this.

Answers

Part A. In probability and statistics, there is an equation for repeated trials. This is useful for situations like tossing a coin or rolling a dice. Each possible result of a situation has its own probability of p. You want to find the total probability of getting 'r' number of successes out of 'n' trials. The equation is

P = n!/r!(n-r!) * p^(n-r) * q^r, where
n is the number of trials; in this case n=2
r is the number of times an event can happen successfully
p is the probability of that success
q is the probability of failing; note that p+q=1

The p for ups is 0.54, while q is 0.46. When r=0 ups
P = 2!/0!(2-0!) * (0.54)^(2-0) * (0.46)^0
P = 0.2916

The same thing is done to r=1 and r=2. The complete table is shown below

     r            P
    0         0.2916
    1         0.4968
    2         0.2116

When you graph r against P, you will get a probability distribution graph as shown in the picture (Part B).

A DELL computer hardware has a yearly 17% rate of failure. Answer the following question. Convert your answer to a percentage. What is the probability that if you buy four computers, at least 1 will fail within a year?

Answers

Let X be num of computers that will not fail. P(X >= 1) = 1 - P(X = 0) P(X=0) is probability that ALL 4 computers fail P(X>=1) = 1 - (.17)^4 = 0.99916 = 99.916%

Answer:

Failure of a Single Dell computer in terms of percentage=17%

It means you buy a computer, there is 17% chance that it will be bad Machine and (100-17)%=83% chance that, it will be a good machine.

Probability that if you buy four computers, atleast 1 will fail within a year

            [tex]=_{1}^{4}\textrm{P}\times [P(S)]^3\times P(F)+_{2}^{4}\textrm{P}\times [P(S)]^2\times [P(F)]^2+_{3}^{4}\textrm{P}\times P(S)\times [P(F)]^3+_{4}^{4}\textrm{P}\times [P(F)]^4\\\\=4 \times (0.83)^3\times (0.17)+6\times (0.83)^2\times (0.17)^2+4\times (0.83)\times (0.17)^3+1\times (0.17)^4\\\\=0.3881516+0.11945526+0.01631116+0.00083521\\\\=0.52475323[/tex]

=0.53(Approx)

=0.53 × 100

=53%

Miguel earns $490 a week, and he works 5 days a week. What is his daily wage?

Answers

Answer: $98 per day

Step-by-step explanation:

Let us calculate the amount he is paid per day.

Since Miguel works 5 days a week, we will divide his total pay per week by the number of days he works every week to get the amount of money he is paid daily.

Therefore, daily pay = 490/5

daily pay =$ 98.

Alternatively,

If 5 days ------> $490

1 day------->$x

Cross multiply and work out the value of x:

5x = 490

therefore, x= 490/5

x=$98 /day

The equation y = ax describes the graph of a line. If the valise of a is positive , the line:

Answers

Given a linear equation of the form y=ax, 

like: y=5x, y=-14x, y=-7x, y=(1/2)x etc,

then this equation represents a line.

If :

i) a>0, the line is increasing
ii)a<0, the line is decreasing
iii) a= 0, then y=ax becomes y=0, which is the equation of the x-axis.


Answer: the line is increasing, that is it rises continuously as it moves to the right.

The numbers of seats in the first 12 rows of a high-school auditorium form an arithmetic sequence. The first row has 9 seats. The second row has 11 seats. a) Write a recursive formula to represent the sequence. b) Write an explicit formula to represent the sequence. c) How many seats are in the 12th row?

Answers

a₁ = 9
a₂ = 9+2  → a₂ = a₁ + 2. Since it's an AP, d, the common difference is 2

1) Then the recursive formula is :
a(n) = a(n-1) + 2

2) Explicit formula:
It's an AP, with first term a₁, d= common difference and n = number of term, which is the number of rows in this problem.
the value of the nth term is given by the formula is:
value of nth term  = a₁ + (n-1).d

3) Number of seats in the 12th row:

9 + (12-1).2 = 31 seats


Final answer:

The recursive formula for the sequence is an = an-1 + 2. The explicit formula is an = 9 + (n-1)(2). There are 31 seats in the 12th row.

Explanation:

a) Recursive formula: The difference between the numbers of seats in consecutive rows is always 2. So, the recursive formula can be written as: an = an-1 + 2. Here, an represents the number of seats in the nth row, and an-1 represents the number of seats in the (n-1)th row.

b) Explicit formula: The first term of the arithmetic sequence is 9, and the common difference is 2. The explicit formula can be written as: an = a1 + (n-1)d. Substituting the values, we get an = 9 + (n-1)(2).

c) Seats in the 12th row: Using the explicit formula, we can calculate the number of seats in the 12th row: a12 = 9 + (12-1)(2) = 9 + 22 = 31. So, there are 31 seats in the 12th row.

As part of Kayla's exercise program, she either runs 6 miles/day or rides her bike 10 miles/day. Her new goal is to cover a minimum distance of 200 miles, with at least 15 of the days running. She would like to determine the number of days it would take to accomplish this.

Answers

Answer:

Kayla will be able to cover the distance of 200 miles by riding bike for 11 days and by running for 15 days.

Step-by-step explanation:

Numbers of days Kayla's has to run be x

Numbers of days Kayla's has to ride bike be y

Speed while running = 6 miles/day

Distance covered by running in x days = 6miles/day × x

Speed while riding a bike = 10 mile/day

Distance covered by riding bike in y days = 10 miles/day × y

Distance desired by Kayla to cover = 200 miles

[tex]200miles=6 miles/day\times x+10 miles/day \times y[/tex]

At least 15 of the days running.Put  x = 15 days in above equation:

[tex]200miles=6 miles/day\times 15 days+10 miles/day \times y[/tex]

[tex]200 miles - 90 miles=10 miles/day \times y[/tex]

[tex]\frac{110 miles}{10 miles/day}=y[/tex]

y= 11 days

Kayla will be able to cover the distance of 200 miles by riding bike for 11 days and by running for 15 days.

STVU is an isosceles trapezoid. If SV= 3x - 11 and TU = x + 13, find the value of x.

Answers

In an isosceles trapezoid, the two diagonals are congruent.
Therefore SV=TU, or 3x-11=x+13
Solve for x in
3x-11=x+13
subtract x-11 from either side to isolate x,
3x-x=13+11
2x=24
x=12

Check: SV=3(12)-11=25 = (12)+13 = TU, ok.

Answer: x=12

Find the value of a and z: x5⋅x4=axz a = , z = Find the values of a and z: 6x20+5x20=axz a = , z = Find the value of a and z: (x5)4=axz a = , z = Find the value: x25−x25 = Find the values of a, b and z: 8x−9=abxz a = , b = , z =

Answers

Final answer:

To find the values of a and z, we need to solve the given equations. Without specific numerical values, we cannot determine the exact values of a and z.

Explanation:

To find the values of a and z, we need to solve the given equations. Let's go through each question:

1. For the equation x^5 * x^4 = axz, we can simplify it as x^9 = axz. Since there is no specific numerical value given, we cannot find the exact values of a and z.

2. Similarly, for the equation 6x^20 + 5x^20 = axz, we can simplify it as 11x^20 = axz. Again, without a specific value for x, we cannot determine the values of a and z.

3. In the equation (x^5)^4 = axz, we can simplify it as x^20 = axz. Without numerical values, we cannot find the exact values of a and z.

4. The equation x^25 - x^25 simplifies to 0. There are no variables to solve for.

5. Lastly, for 8x - 9 = abxz, we cannot determine the values of a, b, and z without additional information.

what is the sum of -7/10 + 1/4

Answers

 Exact form -9/20 or in decimal form is -0.45

Jamie has a deck of 60 sports cards, of which some are baseball cards and some are football cards. jamie pulls out a card randomly from the deck, records its type, and replaces it in the deck. jamie has already recorded three baseball cards and nine football cards. based on these data, what is, most likely, the number of baseball cards in the deck?
12
15
24
30

Answers

3 baseball + 9 football  9+3 = 12

3 out of 12 were base ball

3/12=0.25

60*0.25 = 15

 so there would be 15 baseball cards

Answer:

The answer is 15

Step-by-step explanation:

i took the test

Consider an assembly line with 20 stations. Each station has a 0.5% probability of making a defect. At the end of the line, an inspection step singles out the defective units. The inspection step catches 80% of all defects. From inspection, units that are deemed to be non-defective are moved to the shipping department. If a defect is found at inspection, it is sent to the rework department. Rework fixes about 95% of the defective units. Units are directly shipped from the rework department with no further inspection taking place. What is the probability that a unit ends up in rework (in decimal form)?

Answers

To find the probability of a unit ending up in rework in an assembly line process, you calculate the probabilities at each step of the process, including station defects, inspection, and rework.

To find the probability that a unit ends up in rework, we need to consider the probability at each step:

The probability of a defective unit at any station is 0.5% or 0.005.

The inspection catches 80% of defects, so the probability of defect detection at inspection is 0.8.

For the units that are sent to rework, the rework department fixes about 95% of the defects, making the probability of a defective unit passing rework 0.05.

Calculating the probability that a unit ends up in rework:

Multiplying the probabilities at each step: 0.005 (station) * 0.2 (not caught at inspection) * 0.95 (not fixed at rework) = 0.00095. Therefore, the probability that a unit ends up in rework is 0.00095 or 0.095% in decimal form.

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