To find the density of the nitrogen gas, we use the equation of state for ideal gases, PV=nRT and rearrange it to find Volume. We also calculate the mass of gas using the number of moles and molar mass. Finally, we get the density of nitrogen gas as 1.4 g/L.
Explanation:To find the mass density of this nitrogen gas, we will use the equation of state for ideal gases given as PV=nRT. Where:
P is the pressure (given as 1.5 atm),V is the volume which we need to find,n is the number of moles (0.020 moles of N2),R is the universal gas constant (given as 0.0821 l · atm/mol · k),T is the temperature in Kelvin (290 K).First, we rearrange the equation to solve for V (Volume): V = nRT/P. Substituting the given values, we find that volume V = (0.020 mol)(0.0821 l·atm/mol·K)(290 K) / 1.5 atm = 0.40 L.
Now, we compute the mass of the nitrogen gas. We know that the molar mass of molecular nitrogen N₂ is 28.01 g/mol, so the mass m of the gas is m = n*M = (0.020 mol)(28.01 g/mol) = 0.56 g.
Finally to get the density we take Density (ρ) = mass/volume = 0.56 g / 0.40 L = 1.4 g/L.
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What is the mass loss of the nucleus, in u, upon emission of this gamma ray? -g?
The addition of 435.2 j of heat is required to raise the temperature of 3.4 g of olive oil from 21?c to 85?c. what is the specific heat of the olive oil?
The specific heat of olive oil is 2 J/g °C'
From the question,
We are to determine the specific heat of olive oil
From the formula
Q = mcΔT
Where Q is the quantity of heat
m is the mass of substance
c is the specific heat of substance
ΔT is the change in temperature
From the given information
Q = 435.2 J
m = 3.4 g
ΔT = 85 °C - 21 °C = 64 °C
Putting the above parameters into the formula, we get
435.2 = 3.4 × c × 64
435.2 = 217.6c
∴ c = 435.2 ÷ 217.6
c = 2 J/g °C
Hence, the specific heat of olive oil is 2 J/g °C
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The main difference between heat and temperature is the temperature is Solely dependent on the
Answer:the answer is the Velocity of molecules in the body
Explanation:hope this helped have a great day
55 kg of liquefied natural gas (lng) are stored in a rigid, sealed 0.17 m3 vessel. in this problem, model lng as 100% methane. due to a failure in the cooling/insulation system, the temperature increases to 200 k, which is above the critical temperature; thus, the natural gas will no longer be in the liquid phase.
The pressure in the vessel after the temperature increase is approximately 33.65 MPa.
We are given a scenario where liquefied natural gas (LNG) stored in a rigid, sealed vessel experiences a temperature increase beyond its critical point, causing it to transition from a liquid to a gas phase. We need to find the final pressure in the vessel using the ideal gas law.
2. Modeling the system:
We treat the LNG as pure methane ([tex]CH_4[/tex]) for simplification.
We assume the system behaves like an ideal gas, meaning it follows the ideal gas law.
3. Setting up the equation:
The ideal gas law relates pressure (P), volume (V), number of moles (n), gas constant (R), and temperature (T) through the equation:
PV = nRT
4. Identifying known and unknown values:
V: 0.17 m³ (volume of the vessel)
R: 8.314 J/(mol·K) (universal gas constant)
T: 200 K (final temperature)
P: Unknown (pressure we need to solve for)
5. Converting mass of LNG to moles:
Molar mass of methane ([tex]CH_4[/tex]): 16.04 g/mol
Mass of LNG (m): 55 kg = 55,000 g
Number of moles (n):
n = m / molar mass
n = 55,000 g / 16.04 g/mol
n ≈ 3433 mol
6. Solving for pressure:
Plug the known values into the ideal gas law and solve for P:
P = (n * R * T) / V
P = (3433 mol * 8.314 J/(mol·K) * 200 K) / 0.17 m³
P ≈ 33,647,247 Pa
7. Converting units and expressing final answer:
Convert pressure from Pascal (Pa) to Megapascal (MPa):
P = 33,647,247 Pa * (1 MPa / 1,000,000 Pa)
P ≈ 33.65 MPa
The question probable may be:
55 kg of liquefied natural gas (lng) are stored in a rigid, sealed 0.17 m3 vessel. in this problem, model lng as 100% methane. due to a failure in the cooling/insulation system, the temperature increases to 200 k, which is above the critical temperature; thus, the natural gas will no longer be in the liquid phase. What would be pressure in the vessel after the temperature increase
a 0.175 m weak acid acid solution has ph of 3.25 find ka for the acid
To find the Ka value for the weak acid, we can use the given pH and concentration of the acid solution. The Ka value is calculated using the equation Ka = ([H3O+][A-])/[HA].
Explanation:To find the value of Ka for the weak acid, we can use the given pH and concentration of the acid solution. We know that the pH is a measure of the concentration of H3O+ ions in a solution, so we can use the pH to calculate the [H3O+] concentration. From the given pH of 3.25, we can determine that the [H3O+] concentration is 10^(-pH). So, [H3O+] = 10^(-3.25) M.
Now, the equilibrium equation for the dissociation of the weak acid is HA(aq) + H2O(l) -> H3O+(aq) + A-(aq). Since we know the [H3O+] concentration, we can assume that the [HA] concentration is equal to the [H3O+] concentration. So, [HA] = [H3O+] = 10^(-3.25) M.
The Ka value is calculated using the equation Ka = ([H3O+][A-])/[HA]. Substituting the given values, Ka = (10^(-3.25)^2)/10^(-3.25). Simplifying this expression gives us the value of Ka for the acid.
Which of the following is an indication that a substance has undergone a chemical change?
No new product has been formed.
The color of the substance has not changed.
The original constitute has not changed.
The molecular structure has changed.
Answer:
D.
The molecular structure has changed.
Explanation:
I got it right on Plato.
What are three physical properties often analyzed to identify covalent compounds?
Covalent compounds can be identified by their low melting and boiling points, non-conductivity of electricity, and solubility in nonpolar solvents.
Explanation:Covalent compounds, also referred to as molecular compounds, are usually identified through several physical properties such as their low melting and boiling points, non-conductivity of electricity, and their solubility in nonpolar solvents.
Low melting and boiling points: Covalent compounds don't have strong intermolecular forces, resulting in low melting and boiling points.
Non-conductivity of electricity: Since most covalent compounds don't dissociate into ions in solutions, they typically do not conduct electricity.
Solubility in nonpolar solvents: Due to the 'like soluble like' rule, covalent compounds tend to be soluble in nonpolar solvents rather than polar solvents such as water.
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A gas cylinder contains exactly 15 moles of oxygen gas (O2). How many molecules of oxygen are in the cylinder? 4.01 × 1022 molecules 6.02 × 1023 molecules 9.03 × 1024 molecules 2.89 × 1026 molecules
Answer:
answer in picture It's B
Explanation:
Calculate the mass of water produced when 1.92 g of butane reacts with excess oxygen.
Phosphorus has three unpaired electrons and hydrogen has one unpaired electron this means that_____ equivalents of hydrogen can react with ______ equivalents of phosphorus.
Three equivalents of hydrogen can react with one equivalent of phosphorus to form compounds like phosphine, where each hydrogen atom forms a bond with one of the unpaired electrons of phosphorus.
Phosphorus typically has three unpaired electrons and hydrogen has one unpaired electron, which means that three equivalents of hydrogen can react with one equivalent of phosphorus. For instance, in the formation of phosphine, PH₃, three hydrogen atoms will combine with one phosphorus atom, each hydrogen providing one electron to form a single bond with phosphorus. Since phosphorus has three unpaired electrons available, it is able to form three single bonds with three hydrogen atoms, resulting in the phosphine compound.
a) Diamond and graphite are two different forms of pure elemental carbon with densities of 3.51 g/cc and 2.25 g/cc respectively. What volume would be occupied by a 0.50 g diamond? What volume would be occupied by a 0.50 g piece of graphite?
Determine the number of 3s electrons in na.
When does a scientists create the conclusion
A sample of hydrated sodium thiosulfate has a mass of 6.584 g. After it is heated, it has a mass of 4.194 g. What is the percentage by mass of water in the hydrate?
36.30%
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When hydrochloric acid and zinc were combined, the flask was sealed and thus no gas could escape from the flask. why did the pressure decrease as the temperature decreased?
Explanation:
According to the the ideal gas law, PV= nRT.
This means that pressure is directly proportional to temperature.
So, when HCl and zinc are combined in a flask then it will lead to the formation of zinc chloride and hydrogen gas.
The reaction equation will be as follows.
[tex]HCl + Zn \rightarrow ZnCl_{2} + H_{2}[/tex]
Since, the flask is sealed hence, hydrogen gas will not be able to move out of the flask.
So, when it will behave ideally then due to directly proportional relation between pressure and temperature there will occur a decrease in temperature with decrease in pressure.
Find the missing part of this equation
________ is the science of obtaining reliable measurements from photographs.
Calculate the vapor pressure of a solution containing 27.2 g of glycerin (c3h8o3) in 132 ml of water at 30.0 ?c. the vapor pressure of pure water at this temperature is 31.8 torr. assume that glycerin is not volatile and dissolves molecularly (i.e., it is not ionic) and use a density of 1.00 g/ml for the water.
Final answer:
To find the vapor pressure of the glycerin solution, calculate the moles of glycerin and water, determine the mole fraction of water, and apply Raoult's law using the vapor pressure of pure water at the specified temperature.
Explanation:
To calculate the vapor pressure of the solution containing glycerin in water, we will use Raoult's law, which states that the vapor pressure of a solution is directly proportional to the mole fraction of the solvent. The first step is to calculate the number of moles of glycerin (C3H8O3) by using its molar mass (92.09 g/mol), and then calculate the number of moles of water using its given density (1.00 g/mL) to convert the volume to mass and then to moles with its molar mass (18.015 g/mol).
Once we have both amounts in moles, we can calculate the mole fraction of water and apply Raoult's law to find the new vapor pressure of the solution, knowing the vapor pressure of pure water at the given temperature (30.0 °C) is 30.6 Torr.
What gas was produced by the decomposition of hydrogen peroxide? what happened when the smoldering toothpick came into contact with the gas? b boldi italicsu underline bulleted list numbered list superscript subscript?
Calculate the equilibrium constant k for the isomerization of glucose-1-phosphate to fructose-6-phosphate at 298 k. express your answer numerically using two significant figures. hints
The equilibrium constant for isomerization reaction is [tex]\boxed{9.615}[/tex]
Further Explanation:
The standard Gibbs free energy change in a reaction [tex]\left( {{{\Delta {\text{G}}_{{\text{rxn}}}^{{^\circ }}} \right)[/tex] is the difference of sum of the standard free energies of formation of product molecules and sum of standard free energies of formation of reactant molecules at the standard conditions. The formula used to calculate the value of standard Gibbs free energy change for a reaction [tex]\left( {{{\Delta {\text{G}}_{{\text{rxn}}}^{{^\circ }}} \right)[/tex] is as follows:
[tex]\Delta\text{G}_{\text{rxn}}^{\circ}=\sum\text{n}\Delta\text{G}_{\text{f}(\text{products})}^{\circ}-\sum\text{m}\Delta\text{G}_{\text{f}(\text{reactants})}^{\circ}[/tex]
Here, n is the stoichiometric coefficients of products, and m are the stoichiometric coefficients of reactants in a balanced chemical equation.
The formula to determine the relationship between change in standard Gibbs free energy [tex]\left( \Delta{\text{G}^{\circ}} \right)[/tex] and equilibrium constant [tex]\left({\text{K}}\right)[/tex] is given as follows:
[tex]{\Delta }}{{\text{G}}^{{^\circ }}} = - {\text{RTlnK}}[/tex] ......(1)
Here,
[tex]\Delta{\text{G}^{\circ}[/tex] is the standard Gibbs free energy change.
[tex]{\text{R}[/tex] is the gas constant.
[tex]{\text{T}}[/tex] is the temperature in Kelvin.
[tex]{\text{K}}[/tex] is the equilibrium constant.
The isomerization of glucose-1-phosphate to fructose-6-phosphate occurs in 2 steps:
The reaction of step 1 is as follows:
[tex]{\text{glucose - 1 - phosphate}} \to {\text{glucose - 6 - phosphate}}[/tex]
......(2)
[tex]\Delta{\text{G}^{\circ}_{1}[/tex] for equation (2) is [tex]- 7.28\;{\text{kJ/mol}}[/tex]
The reaction of step 2 is as follows:
[tex]{\text{fructose - 6 - phosphate}} \to {\text{glucose - 6 - phosphate}}[/tex]
......(3)
[tex]\Delta{\text{G}^{\circ}_{2}[/tex] for equation (3) is [tex]- 1.67\;{\text{kJ/mol}}[/tex]
Reverse the reaction of step 2.
[tex]{\text{glucose - 6 - phosphate}} \to {\text{frutcose - 6 - phosphate}}[/tex]
......(4)
[tex]\Delta{\text{G}^{\circ}_{3}[/tex] for equation (4) is [tex]+ 1.67\;{\text{kJ/mol}}[/tex]
Add equation (1) and (3) to get the final equation.
[tex]{\text{glucose - 1 - phosphate}} \to {\text{frutcose - 6 - phosphate}}[/tex]
To calculate [tex]\Delta {\text{G}}_{{\text{rxn}}}^{^\circ }}[/tex], add [tex]\Delta{\text{G}^{\circ}_{1}[/tex] and [tex]\Delta{\text{G}^{\circ}_{3}[/tex] as follows:
[tex]\Delta{\text{G}^{\circ}_{\text{rxn}}=\Delta{\text{G}^{\circ}_{1}+\Delta{\text{G}^{\circ}_{3}[/tex] ......(5)
Substitute [tex]- 7.28\;{\text{kJ/mol}}[/tex] for [tex]\Delta{\text{G}^{\circ}_{1}[/tex] and [tex]+ 1.67\;{\text{kJ/mol}}[/tex] for [tex]\Delta{\text{G}^{\circ}_{3}[/tex] in equation (5).
[tex]\begin{aligned}\Delta {\text{G}}_{{\text{rxn}}}^{{^\circ }} &= - 7.28\;{\text{kJ/mol + }} + 1.67\;{\text{kJ/mol}}\\{\text{}}&= - 5.61\;{\text{kJ/mol}}\\\end{aligned}[/tex]
For equilibrium constant (K), rearrange equation (1)
[tex]{\text{K}}={\text{e}}\frac{-\Delta{\text{G}}^{\circ}}{\text{RT}}[/tex] ......(6)
Substitute [tex]- 5.61\;{\text{kJ/mol}}[/tex] for [tex]\Delta{\text{G}^{\circ}[/tex],[tex]8.314\;{\text{J/mol}} \cdot {\text{K}}[/tex] for R and [tex]298\;{\text{K}}[/tex] for T in equation (6)
[tex]\begin{aligned} {\text{K}}&= {{\text{e}}^{\frac{{ - \left( { - 5.61\;{\text{kJ/mol}}} \right)}}{{\left( {8.314\;{\text{J/mol}} \cdot {\text{K}}} \right)\left( {\frac{{{\text{1J}}}}{{1000{\text{kJ}}}}} \right)\left( {298\;{\text{K}}} \right)}}}}\\&= {{\text{e}}^{2.2634}}\\&= 9.615\\\end{aligned}[/tex]
The equilibrium constant for the reaction is 9.615.
Learn more:
1. The change in standard gibbs free is for a reaction: https://brainly.com/question/10838453
2. Determination of the equilibrium constant for pure water: https://brainly.com/question/3467841
Answer details:
Grade: Senior Secondary School
Subject: Chemistry
Chapter: Chemical Equilibrium
Keywords: Standard Gibbs free energy, equilibrium, constant, glucose-1-phosphate and fructose-6-phosphate.
What acid and what base would you choose to prepare the salt potassium perchlorate (kclo4)?
Answer : The perchloric acid and potassium hydroxide base is used to prepare the salt of potassium perchlorate, [tex](KClO_4)[/tex]
Explanation :
when the perchloric acid react with the potassium hydroxide as a base to form a salt of potassium perchlorate, [tex](KClO_4)[/tex]
The balanced chemical reaction will be,
[tex]HClO_4+KOH\rightarrow KClO_4+H_2O[/tex]
By the stoichiometry, we can say that 1 mole of perchloric acid react with the 1 mole of potassium hydroxide base to give 1 mole of potassium perchlorate and 1 mole of water as a product.
Hence, the perchloric acid and potassium hydroxide base is used to prepare the salt of potassium perchlorate, [tex](KClO_4)[/tex]
The molar mass of carbon dioxide is 44.0 g/mol. a mass of 150.0 grams of carbon dioxide is equivalent to how many moles?
A) 3.00 mol
B) 3.41 mol
C) 29.3 mol
D) 106 mol
The molar mass of carbon dioxide is 44.0 g/mol. a mass of 150.0 grams of carbon dioxide is equivalent to 3.41 mol of carbon dioxide.
What is mole?In the International System of Units, the mole is the unit of substance quantity (SI). How so many elementary units of a certain substance are present in an item or sample is determined by the quantity of that material. There are precisely 6.022×10²³ elementary entities in a mole.
For instance, although having differing volumes and weights, 10 moles containing water along with ten moles of mercury both contain the same quantity of material, and the mercury includes exactly 1 atom for every molecule of water.
M(CO₂)=44.0 g/mol
m(CO₂)=150.0 g
n(CO₂)=m(CO₂)/M(CO₂)
n(CO₂)=150.0/44.0=3.41 mol
Therefore, 3.41 mol of carbon dioxide is there.
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If the ΔG value of a reaction is negative, what is true of the ΔG value of the reverse reaction?
A. ΔG > 0
B. ΔG < 0
C. ΔG = 0
D. ΔG fluctuates
When a colorless aqueous solution of lead nitrate is combined with a colorless aqueous solution of sodium iodide a bright yellow precipitate is formed. what is the chemical formula for the precipitate?
The chemical formula of the bright yellow precipitate is PbI₂ (lead iodide).
What is the balanced chemical equation?A chemical equation is the representation of a chemical reaction which consists of reactants participating, formed products, and an arrow indicating the direction of the chemical reaction.
The equation that has the number of atoms of substances equal on either side of the chemical equation is known as a balanced chemical equation.
The law of conservation of mass has to be followed by a balanced chemical equation, according to which, the total mass of the elements on the reactant side must be equal to the total mass of elements on the product side.
The chemical equation of the reaction of lead nitrate and an aqueous solution of sodium iodide:
[tex]Pb(NO_3)_2(aq) + 2NaI \longrightarrow 2NaNO_3(aq) + PbI_2 (s)[/tex]
The bright yellow precipitate formed in the above chemical reaction has the chemical formula PbI₂.
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How Does The Modern Periodic Table Arrange Elements? By Atomic Mass By Atomic Number
By Number Isotopes
By Electron Mass
True or false if you refuse to submit a breath you’re in a blood test is an assumable for evidence in a DUI criminal proceedings in Florida
Answer:
True
Explanation:
Pressure and volume are inversely related. When the pressure on a gas is doubled, what happens to the volume
Answer: Volume decreases to half of original volume
Explanation:
Boyle's Law: This law states that pressure is inversely proportional to the volume of the gas at constant temperature and number of moles.
[tex]P\propto \frac{1}{V}[/tex] (At constant temperature and number of moles)
[tex]{P_1V_1}={P_2V_2}[/tex]
where,
[tex]P_1[/tex] = initial pressure of gas = p
[tex]P_2[/tex] = final pressure of gas = 2p
[tex]V_1[/tex] = initial volume of gas = v
[tex]V_2[/tex] = final volume of gas = ?
Now put all the given values in the above equation, we get the final pressure of gas.
[tex]{p\times v}=2p\times V_2[/tex]
[tex]V_2=\frac{v}{2}[/tex]
Therefore, the final volume of the gas will become half of initial volume.
Which of the following does not apply to obtaining a career in chemistry?
•There is only one path to get a career in chemistry.
•There are many paths to getting a career in chemistry.
•Start by talking to teachers and counselors about different career options.
•Talk to students already enrolled in the programs that you are interested in.
ANSWER: There is only one path to get a career in chemistry.
EXPLANATION: There are many paths of career in Chemistry and not only one. It would not be justified to say that there is only one path to get a career in chemistry. Careers in chemistry would include Biochemistry, Forensic Scientist, Research Scientist, Chemical Engineer, Chemical Plant Operator and even a Science teacher or Chemistry professor in a school or university.
Compare bond lengths in butane and t butylcyclohexane
Answer:
The lengths of the C-C bonds increases with the decrease in the resistance of said bond, for example, a triple bond has a shorter length than in the case of a single bond. Butane has the single bonds and the CC bond is hybridized with sp3 hybridization, however in the butylcyclohexane structure the CC bond is also sp3 and the angle is 120°, however the angle shown is equal to 109.5°, so there is a certain angular tension and it is very unstable with respect to butane
Explanation:
How much energy would be released if 1.0 g of material were completely converted into energy?
Final answer:
The energy released from converting 1.0 g of mass into energy is 9 × 10¹³ joules (J), using the equation E = mc², where c is the speed of light.
Explanation:
According to Einstein's famous equation E = mc², where E represents energy, m is mass, and c is the speed of light in a vacuum, the energy released from completely converting 1.0 g of mass into energy is tremendously large. Since the speed of light, c, is approximately 3 × 10⁸ meters per second, and the mass m is 1.0 g (which is 1/1000 of a kilogram), the calculation is E = (1.0 g / 1000) × (3 × 10⁸ m/s)². This results in an energy release of 9 × 10¹³ joules (J), which is equivalent to about twice the energy released by the atomic bomb dropped on Hiroshima.