A ship traveled at an average rate of 22 miles per hour going east. It then traveled at an average rate of 17 miles per hour heading north. If the ship traveled a total of 212 miles in 11 hours, how many miles were traveled heading east?

Answers

Answer 1
recall your d = rt, distance = rate * time

let's say the ship went East at 22mph, now, the ship travelled a total of 212 miles in 11 hours... ok... how many miles did it go East? well, let's say it went "d" miles, and it took "t" hours.

now, if the ship after that went North at a rate of 17mph, then it took the slack from the 11 hours total and "d", or it took going North " 11 - t ", and it covered a distance, of also the slack from 212 miles and "d", or " 212 - d ".

[tex]\bf \begin{array}{lccclll} &distance&rate&time\\ &-----&-----&-----\\ East&d&22&t\\ North&212-d&17&11-t \end{array} \\\\\\ \begin{cases} \boxed{d}=22t\\ 212-d=17(11-t)\\ ----------\\ 212-\boxed{22t}=17(11-t) \end{cases}[/tex]

solve for "t", to see how long it took the ship going East.

how many miles it covered? well d = 22t

Related Questions

Can two numbers have a GCF that is bigger than their LCM? Explain how you know?

Answers

The answer to this question would be: No, they can't

Greatest common factor biggest possible value is the number value itself. There is no factor that bigger than the number.

But the least common multiple smallest possible value is the number. There is no multiple that smaller than the number.

So it is not possible to have GCF bigger than LCM.

In dogs, the drug carprofen has a half-life of 8 hours. If a veterinarian gives a dog an 80-milligram dose, how long will it take for the amount of carprofen in the dog to reach 10 milligrams?

Answers

The formula for half-life is given by:
N(t)=Ne^(-λt)
or
N(t)=N(1/2)^(t/τ)
where:
t=time 
N=initial amount
N(t)=final amount
τ=half-life
thus the time taken for the drug to decay will be:
10=80(1/2)^(t/8)
1/8=(1/2)^(t/8)
introducing natural logs;
ln (1/8)=(t/8)ln (1/2)
thus;
[ln 1/8]/[ln 1/2]=t/8
3=t/8
t=3*8
t=24 hours
the answer is 24 hours

Final answer:

Using the half-life formula, it would take 24 hours for the amount of carprofen to reduce from an initial dose of 80 milligrams to 10 milligrams.

Explanation:

To calculate the time it will take for the amount of carprofen to decrease from 80 milligrams to 10 milligrams in a dog, given the half-life of 8 hours, the exponential decay formula can be used. The half-life formula is:

[tex]C = C0 \times (1/2)^{(t/T)[/tex]

C is the final concentration of the drug.C0 is the initial concentration of the drug.t is the time elapsed.T is the half-life of the drug.

Let's set up the equation using the given values:

[tex]10 mg = 80 mg \times (1/2)^{(t/8 hours)[/tex]

Now, we solve for t:

[tex]10/80 = (1/2)^{(t/8)[/tex]

[tex]1/8 = (1/2)^{(t/8)[/tex]

To find the exponent t/8 that makes this equation true, we can use logarithms:

log2(1/8) = t/8

-3 = t/8

t = -3 * 8

t = -24 hours

The negative result is due to the fact that we are finding a factor by which the concentration is reduced. To get the actual time elapsed, we take the absolute value:

t = 24 hours

Therefore, it would take 24 hours for the amount of carprofen to reduce to 10 milligrams.

Lily is standing at horizontal ground level with the base of the Sears Tower. The angle formed by the ground and the line segment from her position to the top of the building is 15.7°. The Sears Tower is 1450 feet tall. Find Lily's distance from the Sears Tower to the nearest foot.

Answers

This is the concept of trigonometry, the distance of Lily from the tower will be given by:
tan theta=[opposite]/[adjacent]
opposite=1450 ft
adjacent=x ft
theta=15.7
thus;
1450/x=tan15.7
hence;
x=1450/tan15.7
x=5,158.54 ft
x=5,159 (to the nearest foot)

Use the number 913,256. Write the name of the period that has the digits 913.

Answers

9 hundred 13 thirteen thousand

The circle will be dilated by a scale factor of 6. What is the value for n if the expression nPI represents the circumference of the circles in inches?

Answers

A dilation by a scale factor of 6 will cause the radius to increase by a factor of 6. So [tex]r_{new} = 6r[/tex]. If we plug this value of r into the formula for the circumference of a circle we get [tex]C = 2\pi r_{new} = 2\pi *6r = 12\pi r[/tex]

So basically N = 12r. You haven't given me any original radius, so I can't give you a constant for N, but if you do have that original radius you can just plug that into 12r.

Based on your comment, N = 12 * 9 = 108 inches

The value of n is 12 .

What is scale factor?

The scale factor is a measure for similar figures, who look the same but have different scales or measures. Suppose, two circle looks similar but they could have varying radii. The scale factor states the scale by which a figure is bigger or smaller than the original figure.

According to the question

The circle will be dilated by a scale factor of 6 .

so,

New radius of the circle R = 6r

As is it dilated by a scale factor of 6

Now ,

The circumference of the new circles = 2πR  

                                                              = 2.6π

                                                              = [tex]12\pi r[/tex]  -------------------- (1)

and given circumference of the new circles = nπ  ---------------------(2)

when we compare both n = 12

Hence, the value of n is 12 .

 

                                                             

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The car salesman tells you that the car can go from a stop position to 60 mph in six seconds he's giving you the cars rate of

Answers

Answer:

acceleration i think

Step-by-step explanation:

the quadratic formula gives which roots for the equation 2x^2+x-6=0

Answers

2x^2 + x - 6 = 0
a=2, b=1, c=-6
x = -b+_ /(b^2 - 4ac) ÷ 2a
+_ (plus minus) / ( square root)
X = -1 +_ /1^2 - 4(2)(-6) ÷ 2(2)
= -1 +_ /49 ÷ 4
= -1 +_ 7 ÷ 4
= 6/4 or -8/4
= 3/2 or -2

Hope it helped!
Final answer:

The quadratic formula gives two roots for a quadratic equation. The roots of the equation 2x²+x-6=0 are 1.5 and -2.

Explanation:

The quadratic formula gives the roots of a quadratic equation of the form ax²+bx+c=0. For the equation 2x²+x-6=0, the values of a, b, and c are 2, 1, and -6, respectively.

Using the quadratic formula, we can calculate the roots:

x = (-b ± √(b² - 4ac)) / (2a)

Substituting the values of a, b, and c into the formula:

x = (-1 ± √(1² - 4*2*(-6))) / (2*2)

Simplifying the expression:

x = (-1 ± √(1 + 48)) / 4

x = (-1 ± √49) / 4

x = (-1 ± 7) / 4

Therefore, the roots of the equation 2x²+x-6=0 are:

x = (-1 + 7) / 4 = 3/2 = 1.5

x = (-1 - 7) / 4 = -8/4 = -2

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which expression represents the distance between the two points x and y on the number line -4 and 3

Answers

It would have to be 3 because distance can't be a negative number.

Answer with explanation:

The two points on the number line are

  x = -4

  y=3

The distance is a positive Quantity.

So, Distance between x and y can be written as:

  =|x-y| or |y-x|

 =|3-(-4)| or |-4-3|

 =|3+4| or |-7|

 =|7| or |-7|

 =7 Units

The expression will be : =|x-y| or |y-x|

 =|3-(-4)| or |-4-3|

The ordered pair (a, b) gives the location of point P on the coordinate plane. The value of a is negative and the value of b is zero. Where could point P be located on the coordinate plane?





Select one or more:
Quadrant I
Quadrant II
Quadrant IV
Quadrant III
x-axis
y-axis

Answers

If x is negative and y is zero the point would be located on the x-axis.

Answer:

X-axis.

Step-by-step explanation:

Givens

We have point which coordinates are (a,b)The value of a is negative.The value of b is zero.

Now, remember that all coordinates with the form (a,0), represents points on the x-axis, because the y-coordinate is zero.

In this case, we have negative horizontal coordinates and a null vertical coordinate, like (-a,0).

This points is on the x-axis, because y-value is null. Actually, it's on the negative part of x-axis, because its horizontal coordinate is negative.

Therefore, the right answer is x-axis.

what is the other measurement of the shape?

Answers

for the length of the side that is not given:

look at it as part of a triangle with the legs being 4m tall by 6 m wide

 so 4^2 + 6^2 = X62

16+36 = 52^2

square root(52) = 7.211 m

 does it as to round of to nearest whole number? nearest tenth?

round off answer as needed

Write an appropriate inverse variation equation if y = 9 when x = 3.

Answers

if y=9 when x=3
y = k/x
so, 9 = k/3
k = 9x3
k = 27
then equation is, y = 27/x

The rounding rule for the correlation coefficient requires three decimal places true or false

Answers

Answer:

Round the value of r to three decimal places.

Step-by-step explanation:

The rounding rule for the correlation coefficient requires three decimal places

this statement is true.

The correlation coefficient in statistics is a parameter which measures the degree of strength of relation between two variables .

Its value lies between -1  to +1 .

The closer the correlation coefficient  will be near to 1 the stronger the correlation will be.

The correlation between two variables can be positive or negative

Correlation coefficients are helpful in determining the  functional relationships among the variables

So higher  magnitude  of correlation coefficients lead to accurate functional relation among variables.

The rounding rule for the correlation coefficient requires three decimal places

this statement is true.

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FIND THE FOLLOWING USING THE GIVEN TRIANGLE...PLEASE HELP ME SUCK AT MATH...SOS!!! ASAP!!!!

Answers

perimeter = 20 +20 +24 = 64 feet

 area = 12^2 + x^2 = 20^2

144 + x^2 = 400

x^2 = 256

x = sqrt(256) = 16 feet

area = 1/2 x 16 x 24 = 192 square feet


 cost = 192 x $2 = $384

Andrew estimated the weight of his dog to be 60 lb. The dog’s actual weight was 68 lb. What was the percent error in Andrew’s estimate? Round your answer to the nearest tenth of a percent. __________ %

Answers

well, the error value is 8, he was off by 8 units... so, if we take 68 to be the 100%, what is 8 in percentage off of it?

[tex]\bf \begin{array}{ccllll} amount&\%\\ \text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\ 68&100\\ 8&x \end{array}\implies \cfrac{68}{8}=\cfrac{100}{x}[/tex]

Factor 2x^2-128 completely

Answers

2x² - 128

2(x² - 64), but (x² - 64)  = x² - 8² (difference of 2 squares),[a²-b²=(a-b)(a+b)]

2(x² - 64) = 2(x² - 8²) = 2(x-8)(x+8)

Two standard number cubes are thrown, one after the other. What is the probability that the first cube lands showing a 1 and the second cube lands showing a number that is not 1? Round the answer to the nearest thousandth.

Answers

Let A be the probability that you throw a 1 
Let B be the probability that you don't throw 1

A and B are independent events

P(A)= 1/6  and P(B)= 5/6

Because they are independent you multiply them: 1/6 x 5/6 = 0.138888...

Rounded to the nearest thousandth is 0.139

Answer:

B on edge

Step-by-step explanation:

Simplify: 4x^2+36/4x•1/5x

Answers

[tex] \frac{4x^2+36}{4x}* \frac{1}{5x} = \frac{4(x^2+9)}{20x^2} = \frac{x^2+9}{5x^2} [/tex]

Answer:

Step-by-step explanation:

The given equation is:

[tex]\frac{4x^2+36}{4x}{\times}\frac{1}{5x}[/tex]

On solving the above equation, we get

=[tex]\frac{4x^2+36}{(4x)(5x)}[/tex]

=[tex]\frac{4(x^2+9)}{(4x)(5x)}[/tex]

=[tex]\frac{x^2+9}{(x)(5x)}[/tex]

=[tex]\frac{x^2+9}{(5x^2)}[/tex]

which is the required simplified form.

Thus, the simplified form of the given equation [tex]\frac{4x^2+36}{4x}{\times}\frac{1}{5x}[/tex] is [tex]\frac{x^2+9}{(5x^2)}[/tex].

The law of cosines is a2+b2 - 2abcosC = c^2 find the value of 2abcosC .... A. 40 B. -40 C. 37 D. 20

(The sides are 2,4, and 5; A to B is 2, B to C is 4, and A to C is 5.)

Answers

a² + b² - 2abcosC = c²

Аngle C lies opposite to the side AB, so "c" in the formula it is AB in your triangle

4² + 5² - 2abcosC = 2²
16 + 25 - 2abcosC = 4
41 - 4 = 2abcosC
2abcosC = 37

Given the Law of Cosines, the value of 2abcosC after plugging in the values of a, b, and c is: [tex]\mathbf{2abcosC = 37}[/tex]

Law of Cosines is given as: [tex]a^2+b^2 - 2abcosC = c^2[/tex]

Given also are the sides of a triangle:

a = 4 (side B to C)b = 5 (side A to C)c = 2 (side A to B)

Plug in the values into the Law of Cosines,  [tex]a^2+b^2 - 2abcosC = c^2[/tex] to find [tex]\mathbf{2abcosC}[/tex]

Thus:

[tex]4^2+5^2 - 2abcosC = 2^2\\\\16 + 25 - 2abcosC = 4\\\\41 - 2abcosC = 4[/tex]

Subtract 41 from both sides

[tex]41 - 2abcosC - 41 = 4-41\\\\-2abcosC = -37[/tex]

Divide both sides by -1

[tex]\mathbf{2abcosC = 37}[/tex]

Therefore, given the Law of Cosines, the value of 2abcosC after plugging in the values of a, b, and c is: [tex]\mathbf{2abcosC = 37}[/tex]

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Steps to solve y=3x + 8

Answers

Step 1. Subtract 8 from both sides

[tex]y-8=3x[/tex]

Step 2. Divide both sides by 3

[tex] \frac{y-8}{3} =x[/tex]

Step 3. Switch sides

[tex]x= \frac{y-8}{3} [/tex]

Done! :) Hope this helps!

whats the value of the equation

Answers

13x-2(x+4) = 8x+1 =

13x-2x-8 = 8x+1=

11x-8 = 8x+1

-8 =-3x+1=

-9 = -3x

x = -9/-3 = 3

x = 3

which expression is equivalent to (4h^7k^2)^4?

A: 16h^11k^6
B: 16h^28k^8
C; 256h^11k^6
D: 256h^28k^8

Answers

[tex](4h^7k^2)^4 = 4^4 * h^{7*4} * k^{2*4} = 256* h^{28}* k^{8} [/tex]

The answer is D.

Answer: Option 'D' is correct.

Step-by-step explanation:

Since we have given that

[tex](4h^7k^2)^4[/tex]

We need to simplify this :

Here we go:

We will apply :

[tex](a^m)^n=a^{mn}[/tex]

[tex](4h^7k^2)^4\\\\=4^4\times (h^7)^4\times (k^2)^4\\\\=256h^{28}k^8[/tex]

Hence, option 'D' is correct.


Which are the roots of the quadratic function f(q) = q2 – 125? Check all that apply. q = 5 q = –5 q = 3 q = –3 q = 25 q = –25

Answers

Answer:

q=5 sqrt 5 and q=-5 sqrt 5

Step-by-step explanation:

got it right on edge :)

Final answer:

The roots of the quadratic function f(q) = q^2 − 125 are q = -5 and q = 5. Other options listed do not satisfy the function. The roots are found by factoring the equation as a difference of squares.

Explanation:

The roots of the quadratic function f(q) = q2 − 125 can be found by solving the equation q2 − 125 = 0. To find the roots, we need to factor the quadratic or use the square root property since the equation is already set to zero.

We can see that this is a difference of squares equation, so it factors to (q + 5)(q - 5) = 0. Setting each factor equal to zero gives us q = -5 and q = 5.

So, the roots of the quadratic function are q = -5 and q = 5. The other options given (q = 3, q = -3, q = 25, q = -25) do not satisfy the equation f(q) = q2 − 125 = 0, hence they are not roots of this function.

can anone help me please

Answers

Perimeter= 18
Area= 12
Cost= 84

a. The perimeter of the triangle is 18 cm. b. The area of the triangle is 24 cm². c. Tiling the triangle at $7 per square centimeter would cost $168.

a. Perimeter:

Perimeter} = 5 + 5 + 8 = 18 cm

b. Area:

  Use Heron's formula since the sides are known:

[tex]\[ s = \frac{5 + 5 + 8}{2} = 9 \] \[ \text{Area} = \sqrt{s(s-5)(s-5)(s-8)} \] \[ \text{Area} = \sqrt{9 \times 4 \times 4 \times 1} = \sqrt{576} = 24 \, \text{cm}^2 \][/tex]

c. Cost to Tile:

  If the cost is $7 per square centimeter:

[tex]\[ \text{Cost} = \text{Area} \times \text{Cost per square centimeter} \] \[ \text{Cost} = 24 \times 7 = 168 \][/tex]

Therefore,

a. Perimeter = 18 cm

b. Area = 24 cm²

c. Cost to Tile = $168

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To keep heating costs down for a structure, architects want the ratio of surface area to volume as small as possible. An expression for the ratio of the surface area to volume for the square prism shown is ​. Find the ratio when b = 12 ft and h = 18 ft.

Answers

The answer is 5/6

Hope this helps!

Determine the angular velocity, in radians per second, of 4.3 revolutions in 9 seconds. Round the answer to the nearest tenth.

Answers

[tex]\bf w=\cfrac{4.3rev}{9sec}\cdot \cfrac{2\pi }{rev}\implies w=\cfrac{4.3\cdot 2\pi }{9sec}[/tex]

simplify away.

What are the values of a1 and r of the geometric series?

2 – 2 + 2 – 2 + 2

Answers

First term, a, is 2.  Next term, -2, is the product of 2 and -1 and is -2.  Next term, 2, is the product of -2 and -1.  Thus, the first term, a, is 2 and the common ratio, r, is -1.

Answer:  For the given geometric series, the first term is [tex]a_1=2[/tex] and the common ratio is [tex]r=-1.[/tex]

Step-by-step explanation:  We are given to find the values of [tex]a_1[/tex] and [tex]r[/tex] of the following geometric series:

[tex]2-2+2-2+2-~.~.~..[/tex]

We know that

[tex]a_1[/tex] is the first term and [tex]r[/tex] is the common ratio of the given geometric series.

We can see that the first term of the given geometric series is 2.

So. we must have

[tex]a_1=2.[/tex]

Also, common ratio is found by dividing a term by its preceding term.

Therefore, the common ratio [tex]r[/tex] of the given geometric series is

[tex]r=\dfrac{-2}{2}=\dfrac{2}{-2}=~.~.~.~=-1.[/tex]

Thus, for the given geometric series, the first term is [tex]a_1=2[/tex] and the common ratio is [tex]r=-1.[/tex]

Let g(x) = x - 3 and h(x) = x2 + 6. What is (h o g)(1)?

Answers

[tex]\bf g(x)=x-3\qquad h(x)=x^2+6 \\\\\\ (h\circ g)(1)\implies h[\ g(1)\ ]\impliedby \textit{now, let's find g(1) first} \\\\\\ g(1)=(1)-3\implies g(1)=\boxed{-2}\qquad thus \\\\\\ h[\ g(1)\ ]\implies h\left( \boxed{ -2}\right)\implies h(-2)=(-2)^2+6 \\\\\\ h(-2)=4+6\implies h(-2)=10\impliedby (h\circ g)(1)[/tex]

"if z is a standard normal variable, find the probability. the probability that z lies between 0 and 3.01"

Answers

Probability between z = 0 and z = 3.01 is given by

P(0<z<3.01) = P(z<3.01) - P(z<0)

Reading from the z-table, we have
P(z<0) = 0.5
P(z<3.01) = 0.9987

Hence, P(0<z<3.01) = 0.9987 - 0.5 = 0.4987

The probability that z lies between 0 and 3.01 P(0<z<3.01) = 0.4987.

What is z- score?

The Z-score quantifies the discrepancy between a given value and the standard deviation. The Z-score, also known as the standard score, indicates how many standard deviations a specific data point deviates from the mean. In essence, standard deviation represents the degree of variability present in a given data collection.

Given:

Probability between z = 0 and z = 3.01 is given by

As, P(0<z<3.01)

= P(z<3.01) - P(z<0)

So, the z score values are

P(z<0) = 0.5

and, P(z<3.01) = 0.9987

Hence, the probability that z lies between 0 and 3.01 P(0<z<3.01) = 0.4987.

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Evaluate the surface integral. ∫∫s (x2 + y2 + z2) ds s is the part of the cylinder x2 + y2 = 16 that lies between the planes z = 0 and z = 5, together with its top and bottom disks.

Answers

Decompose the surface into three components, [tex]\mathbf r_1,\mathbf r_2,\mathbf r_3[/tex], corresponding respectively to the cylindrical region and the top and bottom disks:

[tex]\mathbf r_1(u,v)=\begin{cases}x(u,v)=4\cos u\\y(u,v)=4\sin u\\z(u,v)=v\end{cases}[/tex]
where [tex]0\le u\le2\pi[/tex] and [tex]0\le v\le5[/tex],

[tex]\mathbf r_2(u,v)=\begin{cases}x(u,v)=u\cos v\\y(u,v)=u\sin v\\z(u,v)=0\end{cases}[/tex]
where [tex]0\le u\le4[/tex] and [tex]0\le v\le2\pi[/tex], and

[tex]\mathbf r_3(u,v)=\begin{cases}x(u,v)=u\cos v\\y(u,v)=u\sin v\\z(u,v)=5\end{cases}[/tex]
where [tex]0\le u\le4[/tex] and [tex]0\le v\le2\pi[/tex].

For the cylinder, we have

[tex]\dfrac{\partial\mathbf r_1}{\partial u}\times\dfrac{\partial\mathbf r_1}{\partial v}=\langle4\cos u,4\sin u,0\rangle\implies\left\|\dfrac{\partial\mathbf r_1}{\partial u}\times\dfrac{\partial\mathbf r_1}{\partial v}\right\|=4[/tex]

and the integral over this surface is

[tex]\displaystyle\iint_{\text{cyl}}(x^2+y^2+z^2)\,\mathrm dS=4\int_{v=0}^{v=5}\int_{u=0}^{u=2\pi}((4\cos u)^2+(4\sin u)^2+v^2)\,\mathrm du\,\mathrm dv[/tex]
[tex]=\displaystyle320\int_{u=0}^{u=2\pi}\mathrm du+8\pi\int_{v=0}^{v=5}v^2\,\mathrm dv[/tex]
[tex]=640\pi+\dfrac83\pi(125)[/tex]
[tex]=\dfrac{2920\pi}3[/tex]

Bottom disk:

[tex]\dfrac{\partial\mathbf r_2}{\partial u}\times\dfrac{\partial\mathbf r_2}{\partial v}=\langle0,0,u\rangle\implies\left\|\dfrac{\partial\mathbf r_2}{\partial u}\times\dfrac{\partial\mathbf r_2}{\partial v}\right\|=u[/tex]

and the integral over the bottom disk is

[tex]\displaystyle\iint_{z=0}(x^2+y^2+z^2)\,\mathrm dS=\int_{v=0}^{v=2\pi}\int_{u=0}^{u=4}u((u\cos v)^2+(u\sin v)^2)\,\mathrm du\,\mathrm dv[/tex]
[tex]=\displaystyle2\pi\int_{u=0}^{u=4}u^3\,\mathrm du[/tex]
[tex]=128\pi[/tex]

The setup for the integral along the top disk is similar to that for the bottom disk, except that [tex]z=5[/tex]:

[tex]\displaystyle\iint_{z=5}(x^2+y^2+z^2)\,\mathrm dS=\int_{v=0}^{v=2\pi}\int_{u=0}^{u=4}u((u\cos v)^2+(u\sin v)^2+5^2)\,\mathrm du\,\mathrm dv[/tex]
[tex]=\displaystyle2\pi\int_{u=0}^{u=4}(u^3+25u)\,\mathrm du[/tex]
[tex]=528\pi[/tex]

Finally, the value of the integral over the entire surface is the sum of the integrals over the component surfaces:

[tex]\displaystyle\iint_S(x^2+y^2+z^2)\,\mathrm dS=\frac{2920\pi}3+128\pi+528\pi=\dfrac{4888\pi}3[/tex]
Final answer:

Evaluate the given surface integral by parameterizing the surface and computing the integral on each surface separately. Take the antiderivatives of both dimensions defining the area, from the bounds of the integral for an accurate solution.

Explanation:

The problem you've presented is a surface integral in the field of calculus, specifically relating to multivariable calculus. To solve this, we need to evaluate the integral over the specified parts of the cylinder and the top and bottom disks. We start by parameterizing the surface. Given that our cylinder is x² + y² = 16 between z = 0 and z = 5, we can use cylindrical coordinates with the parameterization: r(θ, z) = <4cos(θ), 4sin(θ), z> for 0 ≤ θ ≤ 2π and 0 ≤ z ≤ 5. With this parameterization, you can derive the equation for the surface integral and solve it.

When working with surface integrals, it's essential to remember that you are totaling up the quantity across the entire surface of an object. In such a situation, we could handle this problem by separating it into three parts: the side of the cylinder, the top disk, and the bottom disk, and compute the integral on each surface separately.

The integral can be solved by taking the antiderivatives of both dimensions defining the area, with the edges of the surface in question being the bounds of the integral. You can apply this approach to all the separate parts of this question.

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Which measure of variability is the most appropriate for this set of values?
13, 42, 104, 36, 28, 6, 17

Answers

Three of the most knowns measure of variability are variance, standard deviation, and interquartile range. Because the given set of values are very far from each other and are also very much scattered, the best measure of variability is the VARIANCE. 

Answer:

in other words that guy said E

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