A shopper pushes a grocery cart 20.0 m at constant speed on level ground, against a 35.0 N frictional force. He pushes in a direction 25.0° below the horizontal. (A) What is the work done on the cart by the friction? (B) What is the work done on the cart by the gravitational force? (C) What is the work done on the cart by the shopper? (D) Find the force the shopper exerts, using energy considerations. (E) What is the total work done on the cart?

Answers

Answer 1

Answer:

(A). The work done on the cart by the friction is -700 J.

(B). The work done on the cart by the gravitational force is 0 J.

(C). The work done on the cart by the shopper is 700 J.

(D). The force the shopper exerts 38.61 N.

(E). The total work done on the cart is zero.

Explanation:

Given that,

Distance =  20.0 m

Frictional force = 35.0 N

Angle = 25.0°

(A). We need to calculate the work done on the cart by the friction

Using formula of work done

[tex]W_{fr} = -F\cdot d[/tex]

Where, F = force

d = distance

Put the value into the formula

[tex]W_{fr}=-35.0\times20[/tex]

[tex]W_{fr}=−700\ J[/tex]

(B). The work done by the gravity is perpendicular to the direction of the motion

We need to calculate the work done on the cart by the gravitational force

Using formula of work done

[tex]W=fd\cos\theta[/tex]

Put the value into the formula

[tex]W=35.0\times20\cos90[/tex]

[tex]W=0\ J[/tex]

(C). We need to calculate the work done on the cart by the shopper

Using formula of work done

[tex]W_{sh}=W_{net}-W_{fr}[/tex]

Put the value into the formula

[tex]W_{sh}=0-(-700)[/tex]

[tex]W_{sh}=700\ J[/tex]

(D). We need to calculate the force the shopper exerts

Using formula of force

[tex]F_{sh}=\dfrac{W_{fr}}{d\cos\theta}[/tex]

Put the value into the formula

[tex]F_{sh}=\dfrac{700}{20\cos25}[/tex]

[tex]F_{sh}=38.61\ N[/tex]

(E). We need to calculate the total work done on the cart

Using formula of work done

[tex]W_{cart}=W_{fr}+W_{sh}[/tex]

Put the value into the formula

[tex]W_{cart}=700-(-700)[/tex]

[tex]W_{cart}=0\ J[/tex]

Hence, (A). The work done on the cart by the friction is -700 J.

(B). The work done on the cart by the gravitational force is 0 J.

(C). The work done on the cart by the shopper is 700 J.

(D). The force the shopper exerts 38.61 N.

(E). The total work done on the cart is zero.

Answer 2

The work done on a grocery cart by friction is -700 J, by gravitation is 0, by the shopper is designed to balance the friction, and the total net work considering only these factors tends to be 0, assuming the system is ideal.

(a) The work done on the cart by friction is given by the formula Work = force × distance × cos(θ). Since the force of friction is 35.0 N acting against the direction of the displacement (180° or π radians), and the distance is 20.0 m, the work done by friction = 35 × 20 × cos(180°) = -700 J.

(b) The work done on the cart by the gravitational force is zero because gravitational force acts vertically downwards and the displacement of the cart is horizontal, making the angle between the force and displacement 90° which leads to no work being done as cos(90°) = 0.

(c) The work done on the cart by the shopper can be found by calculating the component of the shopper's force in the direction of the displacement. Without the exact force the shopper applies, we directly cannot calculate the work done; however, it is designed to counteract friction and maintain constant speed.

(d) To find the force the shopper exerts using energy considerations, we equate the work done against friction to the work done by the shopper. Hence, 700 J of work is done by the shopper as well to overcome friction.

(e) The total work done on the cart is the sum of all works done by individual forces. However, without calculating the exact value of the shopper's force, we consider only the friction work, which is -700 J. If considering only friction, the external work (by the shopper) matches this in magnitude but is positive, suggesting a net work of 0 when only considering these two forces.


Related Questions

The resistance to the motion of electrons through different types of materals is n decreasing order, dry so·most so uderground water, and ron ore. How can this knowledge and the measurement of the charge reaching the detector per unit time help identity what type of material is under Check all that apply.

a. More electrons will reach the detector from iron than from dry soil.
b. The electrons reaching the detector are affected very little by what's under the surface.
c. The detector will get more electric charge if the resistance to flow is less, and resistance is related to the type of material
d. The electrons reaching the detector will carry water with them if water is under the surface

Answers

Answer:

a and d

Explanation:

The ground's resistance is influenced by the form of substances under the earth. Other materials like metals have far less resistance and more electrical conductivity. Therefore more electrons will enter the detectors in the earth that has iron. Therefore, choice a and d is are correct.

Final answer:

Electrons passing through various materials to reach a detector are influenced by the resistance and resistivity of those materials. Iron ore, which has lower resistance, allows more electrons to reach the detector compared to dry soil or underground water. Thus, by measuring the charge reaching the detector per unit time, one can infer the type of material based on the known resistivity of different materials.

Explanation:

The question you've asked relates to how the measurement of electric current reaching a detector can be used to identify the type of material underground by considering the effect of materials' resistance on the flow of electrons. To answer the question, we need to understand some key principles:

Resistance is a measure of how much a material impedes the flow of charge.

The resistance to the flow of electrons through materials is in the decreasing order of dry soil, underground water, and iron ore, meaning iron ore has the lowest resistance among them.

Resistivity of materials affects the quantity of charge reaching the detector per unit time. The lower the resistivity, the higher the conductivity, and thus more charge will reach the detector because there is less opposition to the flow.

Now, evaluating the statements given:

(a) More electrons will reach the detector from iron than from dry soil. This is true because iron ore has a lower resistance compared to dry soil.

(b) The electrons reaching the detector are affected very little by what's under the surface. This is not true; the material significantly affects the electron flow.

(c) The detector will get more electric charge if the resistance to flow is less, and resistance is related to the type of material. This is a correct statement and aligns with the principles of conductivity.

(d) The electrons reaching the detector will carry water with them if water is under the surface. This statement is false, as electrons do not carry water with them.

In the equation: v3 *t/A where v is the speed, t is the time and A is the area. Which of the following represents the dimensions of the result. Select one: a. length*time b. length2 /time c. length/time2 d. 1/time

Answers

Answer:

option C

Explanation:

given,

  [tex] \dfrac{v^3t}{A}[/tex]

where v is the speed

           t is the time

          A is the area

we know v = m/s  

     dimension of v = [LT⁻¹]

                            v³ = [L³ T⁻³]

                t  = s

      dimension of t = [T]

unit of area = m²

     dimension of A = [L²]

dimension of the given equation

  [tex]\dfrac{v^3t}{A}= \dfrac{[L^3T^{-3}][T]}{[L^2]}[/tex]

  [tex]\dfrac{v^3t}{A}= \dfrac{[L]}{[T^2]}[/tex]

                                 =[tex]\dfrac{Length}{time^2}[/tex]

hence, the correct answer is option C

Final answer:

In the equation [tex]v^3[/tex] * t / A, where v is speed, t is time, and A is the area, the result has the dimensions of length/time squared (L/[tex]T^2[/tex]), which represents an acceleration. The correct answer is c. [tex]length/time^2[/tex].

Explanation:

The equation given is [tex]v^3[/tex] * t / A. To determine the dimensions of the result, we need to assess each variable's dimensional formula. The velocity (v) has the dimension of length/time (L/T). Time (t) is already in the dimension of time (T). The area (A) has the dimension of length squared ([tex]L^2[/tex]).

Combining these, we have the dimensions for velocity cubed as [tex](L/T)^3[/tex], which gives us [tex]L^3/T^3[/tex]. This is multiplied by the time (T), resulting in [tex]L^3/T^2[/tex]. When we divide this by the area ([tex]L^2[/tex]), the result simplifies to L/T, which is the dimension of velocity. However, because we are dividing by area and not velocity, the final dimension is L/[tex]T^2[/tex], which is option c: [tex]length/time^2[/tex].

Geographic Information Systems consists of a system of satellites that orbit the earth on precisely paths, broadcasting highly accurate time and location information is known as:_______

Answers

Answer: Global Positioning System (GPS)

Explanation:

Geographic Information Systems consists of a system of satellites that orbit the earth on precisely paths, broadcasting highly accurate time and location information is known as Global Positioning System (GPS). The Global Positioning System consists of various satellites that orbit the Earth and make it possible for people with ground receivers to pinpoint their geographic location. The signals also allow the electronic receiver to calculate the current local time to high precision, which allows time synchronisation.

At standard temperature and pressure, a 0.50 mol sample of H2 gas and a separate 1.0 mol sample of O2 gas have the same A. average molecular knetic energyB. average molecular speedC. volumeD. effusion rateE. density

Answers

Answer:

The correct answer is option A.

Explanation:

The average kinetic energy of the gas particle only depends upon the temperature of the gas.

The formula for average kinetic energy is:

[tex]K.E=\frac{3}{2}kT[/tex]

where,

k = Boltzmann’s constant = [tex]1.38\times 10^{-23}J/K[/tex]

T = temperature

So, at standard temperature and pressure 0.50 moles of hydrogen and 1.0 mole of oxygen sample will have same value of average kinetic energy.

Where as in other option enlisted in question , molar masses of both gases will be involved which will give different answers for both the gases.

This question involves the concepts of the average kinetic energy of the molecules of a gas and temperature.

The gases will have the same "A. average molecular kinetic energy".

The average kinetic energy of gas molecules is given by the following formula:

[tex]K.E = \frac{3}{2}KT[/tex]

where,

K.E = average kinetic energy

K = Boltzmann constant

T = absolute temperature

Hence, the average kinetic energy depends upon the absolute temperature only. Since the temperature is the same for both gases. Hence, their average kinetic energy will also be the same.

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Your car's engine is a heat engine; it converts the thermal energy from burning fuel into energy to move your car and power its systems. On a cold winter day, you needn't feel guilty about cranking up the heat in your car; running the heater doesn't cost any additional energy beyond the small amount needed to run the fan. Explain why this is so.

Answers

Answer:

Explanation:

The efficiency of the heat engine is less than 100%. The heat engine converts the thermal energy from the burning of fuel to the mechanival energy. Thus, some of the energy gets lost as waste heat.

Hence, this waste heat is used up to heat up the interior of the car and person feels warmer in the car.

Thus, the waste heat generated in the engine is used for the heating of the car interior.

Final answer:

Running the heater in a car on a cold winter day doesn't cost much additional energy beyond running the fan because the heat generated by the engine is mostly released into the environment instead of being used for work in the car.

Explanation:

Heat engines convert thermal energy into work. In a car engine, heat is produced when fuel is burned, and this heat is converted into kinetic energy to move the car and power its systems. Running the heater in a car on a cold winter day doesn't cost much additional energy beyond running the fan because the heat generated by the engine is mostly released into the environment instead of being used for work in the car.

Dr. Wolski does research on the potential relationship between neurotransmitter deficiencies and mood states. Which psychological specialty does Dr. Wolski's research best represent

Answers

Answer:

Bio psychology

Explanation:

Since, Dr. Wolski does research on the potential relationship between neurotransmitter deficiencies and mood states. His psychological specialty must be biological psychology.

Biological psychology, or bio psychology, is a discipline in which scientific investigation and clinical practice investigates the relation between brain and body. In this area scholars evaluate the biological basis of feelings, impulses and behaviors.

A 12-kg lead brick falls from a height of 1.9 m. (c) The brick falls onto a carpet, 2.0 cm thick. Assuming the force stopping it is constant, find the average force the carpet exerts on the brick.

Answers

Answer:

F = -11199.63 N

Explanation:

given,

mass of the brick = 12 Kg

height of the fall, h = 1.9 m

thickness of the carpet = 2 cm = 0.02 m

average force = ?

velocity of brick just before hitting mat

[tex] v = \sqrt{2gh}[/tex]

[tex]v =\sqrt{2\times 9.81\times 1.9}[/tex]

      v = 6.11 m/s

velocity of brick just before hitting ground= 6.11 m/s

final velocity = 0 m/s

using equation of motion for acceleration calculation.

 v² = u² + 2 a s

 0² = 6.11² + 2x a x 0.02

 [tex]a = -\dfrac{6.11^2}{0.04}[/tex]

    a  =-933.3025 m/s²

now, average force is equal to

F = m a

F = 12 x (-933.3025)

F = -11199.63 N

negative sign represent the decelerating force.

A simple pendulum is swinging back and forth through a small angle, its motion repeating every 1.06 s. How much longer should the pendulum be made in order to increase its period by 0.32 s?

Answers

Answer:

The pendulum should be made longer by 0.194m in order to increase its period by 0.32s

Explanation:

using the formula T= 2π[tex]\sqrt{\frac{L}{g} }[/tex]

rearranging the equation and making L subject of formula we have;

L=T²g/4π²

lets calculate the length when T=1.06s

g=9.8m/s² , π=3.124

[tex]L=\frac{1.06^{2}*9.8 }{4*3.142^{2} }[/tex]

L=0.279m

the new period after its increased by  0.32s = 1.06+0.32 =1.38s

[tex]L_{2}=\frac{1.38^{2}*9.8 }{4 *3.142^{2} }[/tex]

[tex]L_{2}=0.473m[/tex]

increase in length = 0.473 -0.279

               =0.194m

The pendulum should be "0.194 m" longer.

According to the question,

Time,

[tex]T = 1.06 \ s[/tex]

We know,

[tex]g = 9.8 \ m/s^2[/tex][tex]\pi = 3.124[/tex]

By using the formula,

→ [tex]T = 2 \pi \sqrt{\frac{L}{g} }[/tex]

or,

→ [tex]L = \frac{T^2g}{4 \pi^2}[/tex]

By substituting the values, we get

→     [tex]= \frac{1.06^2\times 9.8}{4\times 3.142^2}[/tex]

→     [tex]= 0.279 \ m[/tex]

Now,

The new period after it increased by 0.32 s, we get

= [tex]1.06+0.32[/tex]

= [tex]1.38 \ s[/tex]

then,

→ [tex]L_2 = \frac{1.38^2\times 9.8}{4\times 3.142^2}[/tex]

        [tex]= 0.473 \ m[/tex]

hence,

The increase in length will be:

= [tex]L_2-L[/tex]

= [tex]0.473-0.279[/tex]

= [tex]0.194 \ m[/tex]

Thus the answer above is right.

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In the manufacturing of computer chips, cylinders of silicon are cut into thin wafers that are 3.00 in. in diameter and have a mass of 1.50 g of silicon. How thick, in millimeters, is each wafer if silicon has a density of?

Answers

Final answer:

The thickness of a silicon wafer can be found using the volume of a cylinder and the density formula. Given the diameter and the mass, rearranging to solve for height will give the thickness of the wafer in millimeters.

Explanation:

The thickness of the silicon wafer can be found by using the formula for the volume of a cylinder (Volume = pi * radius2 * height) and the definition of density (Density = mass/volume). Given the silicon wafer has a diameter of 3 inches (or a radius of 1.5 inches), and a mass of 1.5g, we can determine the volume of the wafer from the given density. Rearranging the equation for the volume of a cylinder to solve for height (or thickness, in this case) gives: Thickness = Volume / (pi * radius2). Assuming measurements are converted correctly for consistent units, this calculation will give the thickness of the wafer in millimeters.

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Integration Management, one of the 10 PMBOK Guide Knowledge Areas, represents the processes and activities to identify, define, combine, unify, and coordinate the various processes and project management activities. True or false?

Answers

Answer: TRUE

Explanation: INTEGRATION MANAGEMENT is one of the ten PROJECT MANAGEMENT BODY OF KNOWLEDGE (PMBOK) guide knowledge area can be defined as coordinating responsibilities,resources(financial or non-financial), stakeholders(project team and end users) and any other project aspects. Integration management also involves conflicts resolution between different units of a project, making prudent and best decision between competing activities or needs and analysing the resources available to ensure that it meets the required specifications.

The force exerted on the small piston of a hydraulic lift is 780 N . If the area of the small piston is 0.0075 m2 and the area of the large piston is 0.13 m2, what is the force exerted by the large piston?

Answers

Answer:

13520 N

Explanation:

Pascal's Principle: The principle states that the pressure applied to an enclosed fluid is transmitted undiminished to every portion of the fluid and the walls of the containing vessel.

The operation of hydraulic press and car brake system is based on pascal's principle.

From pascal's principle,

F/A = f/a ........................... Equation 1

Where F = force exerted by the large piston, A = area of the large piston, f = force applied to the small piston, area of the small piston.

Making F the subject of the equation

F = A(f/a)......................... Equation 2

Given: A = 0.13 m², a = 0.0075 m², f = 780 N

Substituting into equation 2

F = 0.13(780/0.0075)

F = 13520 N.

Thus the force exerted by the large piston = 13520 N

A ball has a speed of 15 m/s. Only one external force acts on the ball. After this force acts, the speed of the ball is 7 m/s. Has the force done positive, zero, or negative work on the ball?

Answers

Answer:

Negative work

Explanation:

The work-energy theorem states that the work of the resultant forces acting on a particle modifies its kinetic energy:

[tex]W=\Delta K\\W=\frac{mv_f^2}{2}-\frac{mv_0^2}{2}\\W=\frac{m}{2}(v_f^2-v_0^2)\\W=\frac{m}{2}((7\frac{m}{s})^2-(15\frac{m}{s})^2)\\W=\frac{m}{2}(-178\frac{m^2}{s^2})[/tex]

Since the mass of the ball has to be positive, the work is negative.

Final answer:

The external force did negative work on the ball because the ball's speed decreased from 15 m/s to 7 m/s, indicating a decrease in kinetic energy.

Explanation:

To determine whether the force has done positive, negative, or zero work on the ball, we must consider the change in the ball's kinetic energy. Work done by a force is defined as the change in kinetic energy of an object. The formula for work done (W) is given by the change in kinetic energy:

W = ΔKE = ½mv2final - ½mv2initial

Since the speed of the ball decreased from 15 m/s to 7 m/s, the kinetic energy of the ball also decreased. A decrease in kinetic energy means that negative work was done on the ball by the external force.

A spaceship is traveling toward Earth while giving off a constant radio signal with a wavelength of 1 meter (m). What will the signal look like to people on Earth?

Answers

Answer:

Less than 1 m

Explanation:

When objects are getting closer to each other there is a slight change in the wavelength that is being transmitted by either objects. This is known as the blue shift of waves. Here, the wavelength reduces.

In the opposite case the when objects are getting farther from each other there is a slight change in the wavelength that is being transmitted by either objects. This is known as the red shift. Here, the wavelength increases.

In this case the spaceship is getting close to Earth hence the wavelength will be lower than 1 m.

Explaining how a radio signal from a spaceship appears redshifted to observers on Earth.

Redshift: When a spaceship traveling towards Earth emits a radio signal with a wavelength of 1 meter, it will appear redshifted to people on Earth, meaning the wavelength will increase due to the Doppler effect caused by the relative motion between the spaceship and Earth.

Doppler Effect: This change in wavelength can help observers determine the speed and direction of the spaceship based on how much the signal is redshifted.

Frequency and Wavelength: As the signal travels towards Earth, its wavelength will change, affecting how it is perceived by observers on Earth in terms of frequency and color.

An object is released from rest on a planetthat has no atmosphere. The object fallsfreely for 2.03 m in the first second.What is the magnitude of the accelerationdue to gravity on the planet?

Answers

Answer:

4.06 m/s

Explanation:

It's pretty easy

since it has no atmosphere, so there won't be air/wind resistance that will slow it down.

Distance = ut + (1/2) g t^2

Distance = 2.03

U = initial velocity = 0

t = time = 1sec

g = x

2.03 = x(1^2)/2

4.06 = x

x = g = 4.06.

An Olympic track runner starts from rest and has an acceleration of 2.4 m/s2 for 3.6 s, then has zero acceleration for the remainder of the race. Find the runner's speed (in m/s) at the following times.

Answers

Answer:

The runner's speed at the following times would remain 8.64 m/s.

Explanation:

Acceleration definition: Acceleration is rate of change in velocity of an object with respect to time.

In this case, after 3.6 seconds the acceleration is zero, it means that the velocity of the runner after 3.6 seconds is not changing and it will remain constant for the remainder of the race. Now, we have to find the velocity of the runner that he had after 3.6 seconds and that would be the runner's speed for the remainder of the race. For this we use first equation of motion.

First equation of motion:        Vf = Vi + a×t

Vf stands for final velocity

Vi stands for initial velocity

a stands for acceleration

t stands for time

In the question, it is mentioned that the runner starts from rest so its initial velocity (Vi) will be 0 m/s.

The acceleration (a) is given as 2.4 m/s²

The time (t) is given as 3.6 s

Now put the values of Vi, a and t in first equation of motion

                       Vf = Vi + a×t

                       Vf = 0 + 2.4×3.6

                       Vf = 2.4×3.6

                       Vf = 8.64 m/s

So,the runner's speed at the following times would remain 8.64 m/s.

A circular-motion addict of mass 90 kg rides a Ferris wheel around in a vertical circle of radius 10 m at a constant speed of 6.3 m/s. (a) What is the period of the motion?

Answers

Answer:

9.97sec

Explanation:

To solve for the period we can derive the formula as follows

ω=2πf

ω=2π/T

v=rω

v=2πr/T

T=2πr/v

[tex]T=\frac{2*3.142*10}{6.3}[/tex]

T=9.97sec

The positions of a satellite in elliptical orbit are indicated. Rank these quantities from greatest to least: Gravitational Force A) Speed B ) KE C) PE D) momentum

Answers

Answer:

A,B,C,D,E

Explanation: Ranking the quantities from greatest to least, we have:

A.) Gravitational Force

B) Speed

C) KE

D) PE

E) momentum

The gravitational force is the greatest at periapsis and the least at apoapsis. The speed of the satellite orbits is greatest at periapsis and the least at apoapsis. The potential energy is highest at apoapsis and lowest at periapsis, while the kinetic energy is highest at periapsis and lowest at apoapsis.

The gravitational force is the greatest when the satellite is closest to the large mass (periapsis) and the force is the least when the satellite is farthest away (apoapsis).

The speed of the satellite is greatest at periapsis and least at apoapsis. This is because the gravitational force is strongest at periapsis, causing the satellite to accelerate and increase its speed.

The potential energy (PE) is highest when the satellite is farthest away (apoapsis) and lowest when the satellite is closest to the large mass (periapsis). The kinetic energy (KE) is highest when the satellite is closest to the large mass (periapsis) and lowest when the satellite is farthest away (apoapsis).

The momentum of the satellite remains constant throughout the elliptical orbit.

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the volume of an iron sphere is 3.00cm cubed after being heated from 20.0c to 600.0 c what was the initial volume of the iron sphere at 20.0c

Answers

Answer:

V = 2.94cm³

The initial volume at 20°C is 2.94cm³

Explanation:

As the temperature of the iron sphere increases the volume of the sphere also increase.

Using the equation for volumetric expansion:

∆V = VαΔT

where ;

V is the initial volume

α is the volumetric expansion coefficient

∆V is the change in Volume

∆T is the change in temperature

After Expansion the final volume can be written as:

Vf = V + ∆V

Vf = V + VαΔT

Vf = V(1 + αΔT)

making V the subject of formula;

V = Vf/(1+αΔT) .....1

Given:

Vf = 3.00cm³

ΔT= 600-20 = 580

And from the test book.

α = 35.5 × 10⁻⁶K⁻¹

Substituting the values into eqn 1

V = 3.00/(1+580× 35.5×10^-6)

V = 3.00/(1+0.021) = 3.00/1.021

V = 2.94cm³

The initial volume at 20°C is 2.94cm³

Answer: 1cm3

Explanation:

V1 =?

V2 = 3cm3

T1 = 20°C = 20 + 273 = 293K

T2 = 600°C = 600 + 273 = 873K

V1 /T1 = V2 /T2

V1 / 293 = 3 / 873

V1 = 293 x ( 3 / 873)

V1 = 1 cm3

When transiting a great distance a Navigator prepares a __________ track so the ship can steady courses while driving the shortest distance.

Answers

Answer:

composite track

Explanation:

To travel an incredible circular track, the guide must constantly change course because the extraordinary circular track is a turn when plotted on a Mercator map. It is ridiculous to try to navigate an incredible circular route. All things considered, to make the best use of the shorter cruise separation from the extraordinary circular runway, pilots generally divide an incredible hover runway between the underlying position and the target into many much smaller sections ( for trajectory purposes) of approximately one to several days of cruising time (based clearly on the specialty and conditions) and making course changes every day simultaneously, generally in the early afternoon. Absolute separation is thus the set of separations of these fragments determined by the methods of Mercator Sailing. A potential problem with the incredible circular track, however, is the most limited route between two areas, similarly for most tracks closer to the well (or at a higher range) than the two points, starting point or goal. The high areas are often in danger due to the terrible climate and icing. A protected thought of a veteran sailor is to set a range limit for the long voyage plan. This arrangement is called an extraordinary composite circle course arrangement, terminated with way points. This minicomputer soothes the monotonous procedure for deciding these way points for travel.

Answer:

The answer is composite track.

Explanation:

For ships to cover the shortest distance between two points on the surface of the earth, navigators base their calculations using great circles. A great circle is circular line drawn on a globe that follows the circumference of the earth ( thereby dividing the globe into equal halves ).  As the ship moves from one point to the other, the navigator adjusts its course because the earth is on a constant rotation. Great circles, because they usually cover distances of about 40,000km are broken down into smaller lines called Rhumb so as to provide a steady course. The one common great circle is the equator and the ship's heading does not change on this line.

You are in a spaceship moving in a straight line at constant speed. You cannot see out of the ship. Assuming perfectly uniform motion, what can you do to prove you are moving?

Answers

Answer:

There is no experiment to prove that you are in motion

Explanation:

A frame of reference which has constant velocity is known as an inertial frame of reference. Motion is relative. One can detect one's motion only when one observes change in position with respect to a fixed body.

Thus, if you are in a spaceship moving at a constant speed in a straight line and unable to look outside, you would not be able to prove that you are moving. Everything within the spaceship would have same speed. If you will throw any object within the spaceship, then the parameters measured by you would also not show that the spaceship is in motion.

What is the difference between a continuous spectrum and a line spectrum

Answers

Answer:

Explanation:

The continuous spectrum is a band of visible colors of light. The continuous spectrum contains all the colors of all the visible wavelengths. Usually, most of the light is emitted from a single source. Whereas a line spectrum contains only a few colors and wavelengths of the visible spectrum with gaps of the discontinuity between them. The line spectrum is usually emitted by an excited electron of an atom that is going back to its ground state.
Final answer:

A continuous spectrum shows all colors of the rainbow with no gaps, produced by a solid or very dense gas emitting radiation. In contrast, a line spectrum consists of only certain discrete wavelengths - either as an absorption spectrum with dark lines representing absorbed wavelengths, or as an emission spectrum showing bright lines for emitted wavelengths from excited gas atoms.

Explanation:

The difference between a continuous spectrum and a line spectrum mainly lies in the type of light they represent. A continuous spectrum is formed when a solid or a very dense gas gives off radiation, showing an array of all wavelengths or colors of the rainbow. This can be seen when white light is passed through a prism as represented in Figure 5.10. It's like viewing a rainbow where all the colours blend into each other without any gaps.

On the other hand, a line spectrum, which could either be an absorption or an emission spectrum, consists of light in which only certain discrete wavelengths are present. Absorption spectrum appears as a pattern of dark lines or missing colors superimposed on the continuous spectrum, created when a cloud of gas absorbs certain wavelengths from the continuous spectrum behind it. Meanwhile, an emission spectrum appears as a series of bright lines when we examine an excited gas cloud, demonstrating that the gas is emitting light at only certain wavelengths, as showcased in Figure 5.12.

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Humans require organ systems to carry out life processes. Single-celled organisms do not have organ systems and yet they are able to carry out life processes. This is because
Human organ systems lack the organelles found in single-celled organisms

A human cell is more efficient than the cell of a single-celled organism

It is not necessary for single-celled organisms to maintain homeostasis

Organelles present in single-celled organisms act in a manner similar to organ systems

Answers

Answer: is Organelles present in single-celled organisms act in a manner similar to organ systems

Explanation:  

Multicellular organisms organ system play a critical role for the smooth functioning of whole body. Millions of cells combined to make an organism. The role of organ system in whole body is to provides oxygen and nutrients to the cells and eliminates the toxic material such as carbon dioxide. Organ systems like, respiratory system, digestion system, and cardiovascular play an important role in the human body to perform various functions for its survival.  

Unlike multicellular organisms the unicellular only consists of single cell e.g. prokaryotic organisms and eukaryotic organisms namely, Amoeba, Euglena, salmonella, Fungi etc. Single celled organisms are able to carry out all processes mandatory for the sustenance of life with the help of single cell only e.g. respiration and digestion.They can survive with the help of single cell. Unlike multicellular organisms unicellular do not require multiple number of cell for its survival.

Organelles present in single-celled organisms act very similar to organ systems in multicellular organisms.

Organelles:

They are the small bio-molecular system that carry out the vital processes inside a cell.

For example-

Mitochondria produce energy in the cell.Nucleus is the information center that run the whole cell like a human brain.Lysosomes digest the objects inside the cell, work as digestive system inside the body.

Therefore, organelles present in single-celled organisms act very similar to organ systems in multicellular organisms.

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Multicellular organisms

organ system play a critical role for the smooth functioning of whole body. Millions of cells combined to make an organism. The role of organ system in whole body is to provides oxygen and nutrients to the cells and eliminates the toxic material such as carbon dioxide. Organ systems like, respiratory system, digestion system, and cardiovascular play an important role in the human body to perform various functions for its survival.  

Unlike multicellular organisms the unicellular only consists of single cell e.g. prokaryotic organisms and eukaryotic organisms namely, Amoeba, Euglena, salmonella, Fungi etc. Single celled organisms are able to carry out all processes mandatory for the sustenance of life with the help of single cell only e.g. respiration and digestion.They can survive with the help of single cell. Unlike multicellular organisms unicellular do not require multiple number of cell for its survival

A 430 g soccer ball lying on the ground is kicked and flies off at 25 m/s. If the duration of the impact was .01 s, what was the average force acting on the ball?

Answers

The average force acting on the ball is 1075 N in the direction of travel of ball.

Explanation:

Force is given by rate of change of momentum.

Mass of soccer ball = 430 g = 0.43 kg

Initial velocity = 0 m/s

Final velocity = 25 m/s

Change in momentum = 0.43 x 25 - 0.43 x 0

Change in momentum = 10.75 kg m/s

Time taken = 0.01 s

Rate of change of momentum = Change in momentum ÷ Time

Rate of change of momentum = 10.75 ÷ 0.01

Rate of change of momentum = 1075 N

Force = 1075 N

The average force acting on the ball is 1075 N in the direction of travel of ball.

On the scale of the cosmic calendar, in which the history of the universe is compressed to 1 year, how long has human civilization (i.e., since ancient Egypt) existed?
A. About half the year
B. About a month about a month about a month
C. A few hours
D. A few seconds
E. Less than a millionth of a second

Answers

Answer:

D. A few seconds

Explanation:

Cosmic Calendar is a way of visualizing the history/timeline of the whole universe in just one year. It starts with Big Bang happening on January 1st midnight. The current moment is taken on the December 31st just before the midnight. Every second on this calendar accounts for around 435 years.

The earliest remains of life are thought to have surfaced on September 14. The primitive humans arrived at 22:24 on December 31st. The ancient Egyptian civilization arrived only at 23:59:48 on December 31st. So seen at a cosmic scale the human civilization is just 12 seconds old.

Wo baseballs are fired into a pile of hay. If one has twice the speed of the other, how much farther does the faster baseball penetrate?

Answers

Answer:

Explanation:

Given

Two baseballs are fired into a pile of hay such that one has twice the speed of the other.

suppose u is the velocity of first baseball

so velocity of second ball is 2u

suppose [tex]d_1[/tex] and [tex]d_2[/tex] are the penetration by first and second ball

using [tex]v^2-u^2=2 ad[/tex]

where v=final velocity

u=initial velocity

a=acceleration

d=displacement

here v=0 because ball finally stops

[tex]0-u^2=2ad_1----1[/tex]

for second ball

[tex]0-(2u)^2=2ad_2----2[/tex]

divide 1 and 2 we get

[tex]\frac{u^2}{4u^2}=\frac{d_1}{d_2}[/tex]

as deceleration provided by pile will be same

[tex]\frac{1}{4}=\frac{d_1}{d_2}[/tex]

[tex]d_2=4d_1[/tex]

thus faster ball penetrates 4 times of first ball

Final answer:

The faster baseball will penetrate farther into the pile of hay due to the greater change in kinetic energy caused by its higher speed.

Explanation:

In this scenario, we can analyze the problem using the concept of work and energy. When the slower baseball and the faster baseball are both fired into the pile of hay, the work done by air resistance on each baseball will be different. The work done by air resistance is equal to the change in kinetic energy of the baseball. Since the faster baseball has twice the speed of the slower baseball, it will experience a greater change in kinetic energy and therefore penetrate farther into the pile of hay.

What is the purpose of family?
How many different types of families currently exist in our society today? What are their differences and similarities? ASAP!!! I'll give you brainliest answer

Answers

Answer:

Purpose of family:

Basically main role of a family towards the society is its continuity by both reproduction and  interaction with each other. The main contribution of family to the society is society's continuation.

Types of families:

The family further divided into six types nowadays. Namely,

Nuclear FamilySingle ParentExtended FamilyChildless FamilyStep family Grandparent Family

Defining each Family and their pros and cons :

1). Nuclear Family: The most basic kind of family is nuclear family based on two parents and their biological or adopted children. Number of children is variable, some have one and others have more than one. The main aim of the nuclear family is to up bring their kids and teach them how to socialize in the society.

Pros of nuclear family:

Both parents work and more likely financially stable Children gets more balanced parentingConcerned about educationFocus more on health issues both mental and physicalMore socialize in the society

Cons of nuclear family:

Higher level of stress factor due to increased number of dependentsHave higher rates of disputesChildren become egotistical due to over possessive parents

2). Single Parent: Consists of either a mother or a father living with one or more than one child. Parents may initially married, separated or departed, or passed away (one of them). Like other family structures single parents also have some pros and cons.

Pros of single parent:

Close relationship with each other due to less family membersMore responsible as duties are not being further divided.Both children and parents are strong and independent

Cons of single parent:

Less income due to sole parentMay relay on financial helpQuality living may compromise due to sole earningChildren become mentally unstable by living alternatively with parents (in divorced cases).

3). Extended Family: Basically extended families are joint families, in which grandparents, parents and children live together to support each other both financially and socially.

Pros of extended family:

More tolerance level among childrenCare and  Respects for people older in age is practicedHave emotional supportHave social support

Cons of extended family:

Face more financial crises due to large number of members in a familyIntervening in personal matters with each other Low privacy

4).Childless Family: Partners who have no any children either by choice or due to infertility.

Pros of childless family:

More financially strongNo one to take care of More free to do basic thing like travelling, shopping and fun activitiesHave more chance to fulfill desired goal

Cons of childless family:

Develop fear of isolation by the time Society pressure (not having kids)Develop sense of lacking something important (infertile couples)

5). Step family:

When two families start living to gather, like two divorced people get married and living together with their children (from 1st partner).

Pros of step family:

Child gets advantage by living with both parentsFinancially stable due to two source of incomes

Cons of step family:

Feeling of living forcefully with second parentCouple fight often due to each other's children conflictchildren develop leas tolerance

6) Grandparent Family: In which grandchildren are raised by their grandparents.

Pros of grandparent family:

Children have strong relationship with their elderlyMore protective environment for children

Cons of grandparent family:

Less financially tableDifficult to raise children due to old age and related health issueBig age gap  

Similarities and Differences:

By considering the pros and cons of different family structure we come to the point that many of them have some similarities like financial stability, strong bonding, and more socialization. Likewise there are few differences as well as some families share strong bond while other suffers from isolation. Some are more financially stable and others are less. Some have children while other are childless. Some children have both parents while other have single or step patent. Some of them have high tolerance while other has less. Some live quality life whiles other compromise on their needs and wants.

Using a force of 28.0 Newton, a student pulls a 70.0 Newton weight along the tabletop for a distance of 15.0 meters in 3.0 seconds. Compute the power developed by the student.

Answers

Answer:

140 watt

Explanation:

We are given that

Force applied by student ,F=28 N

Weight pulled  by students=70 N

Displacement,s=15 m

Time=3 s

We have to find the power developed  by the student.

Work done=w=[tex]F\times s[/tex]

Work done by the student=[tex]28\times 15=420 J[/tex]

Power=[tex]\frac{work\;done}{time}[/tex]

Using the formula

Power=[tex]\frac{420}{3}=140watt[/tex]

Hence, the power developed by the students=140 watt

Final answer:

To determine the power developed by the student pulling the weight, we use the equation P = Fv, with a force of 28.0 N and a velocity of 5.0 m/s, which yields a power of 140.0 Watts.

Explanation:

To calculate the power developed by the student pulling the weight, we can use the formula for power when the force is applied along the direction of the displacement: P = Fv, where P is power, F is force, and v is velocity. Power is the rate at which work is done or energy is transferred over time. In this case, the student does work by applying a force to pull the weight across the tabletop.

The student pulls the weight for a distance of 15.0 meters in 3.0 seconds, which means the velocity (v) of the weight is v = distance/time = 15.0 m / 3.0 s = 5.0 m/s. We are given the force (F) as 28.0 Newtons. Therefore, the power (P) developed by the student is:

P = Fv = 28.0 N × 5.0 m/s = 140.0 Watts.

A rubber ball with a mass of 0.145 kg is dropped from rest. From what height (in m) was the ball dropped, if the magnitude of the ball's momentum is 0.800 kg · m/s just before it lands on the ground?

Answers

Answer:

1.55 m

Explanation:

Momentum: This can be defined as the product of  mass of a body and it velocity. the S.I unit of momentum is kgm/s.

Mathematically,

Momentum can be represented as,

M = mv................................. Equation 1

Where m = mass of the body, v = velocity of the body, M = momentum.

Making v the subject of the equation,

v = M/m........................................... Equation 2

Given: M = 0.80 kg.m/s, m = 0.145 kg.

Substituting into equation 2,

v = 0.8/0.145

v = 5.52 m/s.

Using the equation of motion,

v² = u² + 2gs ....................... Equation 3.

Where v = final velocity of the rubber ball, u = initial velocity of the rubber ball, s = distance, g = acceleration due to gravity.

Given: v = 5.52 m/s, u = 0 m/s, g = 9.81 m/s².

Substituting into equation 2

5.52² = 0² + 2(9.81)s

30.47 = 19.62s

s = 30.47/19.62

s = 1.55 m.

Thus the ball was dropped from a height of 1.55 m

A 0.5 kg ball is dropped from rest at a point 1.2m above the floor. The ball rebounds straight upward to a height of 0.7m. What are the magnitude and direction of the impulse of the net force applied to the ball during the collision with the floor.

Answers

Answer:

4.281 kgm/s upward

Explanation:

Impulse:This can be defined product of force and time. The S.I unit of impulse is Ns.

From Newton's second law of motion,

Impulse = Change in momentum.

I = mΔv....................... Equation 1.

Where m = mass of the ball, Δv = change in velocity of the ball  

and Δv = v -u

Where u = velocity of the ball before it hit the floor, v = velocity of the ball after if hit the floor

I = m(v-u) -------------- Equation 2

But

the initial kinetic energy of the ball = potential energy at the initial height (1.2 m above)

1/2mu² = mgh₁

Where h₁ = initial height. or height of the ball before collision

making u the subject of the equation,

u = √(2gh₁)........................ Equation 3

Where h₁ = 1.2 m g = 9.81 m/s²

Substitute into equation 3

u = √(2×1.2×9.81)

u =√(23.544)

u = -4.852 m/s.

Note: u is negative because the ball was moving downward at the first instance.

Similarly,

v = √(2gh₂)............................. Equation 3

h₂ = height of the ball after collision

Given: h₂ = 0.7 m, g = 9.81 m/s²

Substitute into equation

v = √(2×9.81×0.7)

v = √13.734

v = 3.71 m/s.

Also given: m = 0.5 kg,

Substituting into equation 2

I = 0.5(3.71-(4.852)

I = 0.5(8.562)

I = 4.281 kgm/s. Upward.

Thus the impulse = 4.281 kgm/s upward

What is the length of the shadow cast on the vertical screen by your 10.0 cm hand if it is held at an angle of θ=30.0∘ above horizontal?

Answers

Answer:

Length of shadow cast by hand= 5.0 cm

Explanation:

With the hand inclined at an angle θ=30.0∘ above horizontal, it can be imagined to form part of a right angled triangle that has the following parts

vertical screen=vertical part of the triangle where we cast the shadow of the hand

The hand=the hypotenuse side

The horizontal = side to which the hand makes the 30.0° angle

By trigonometric relationship

Sin θ°= Opposite/hypotenuse

Sin θ° = (Shadow cast by hand)/(Length of hand)

Sin 30° = ( length of shadow cast by hand)/10cm

or 0.5 = (length of shadow cast by hand)/10cm

Length of shadow cast by hand= 0.5 × 10cm = 5.0 cm

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