A skydiver is falling at constant velocity. If a force of 600 N is pulling down on the skydiver, how much force must be acting upward on the skydiver?

exactly 600 N
slightly more than 600 N
slightly less than 600 N
exactly 0 N

(a) 138.2 J

Since the applied force is parallel to the displacement of the block, the work done by the force is given by:

[tex]W=Fd[/tex]

where

F = 46.7 N is the magnitude of the force

d = 2.96 m is the displacement of the block

Substituting the numbers into the equation, we find

[tex]W=(46.7 N)(2.96 m)=138.2 J[/tex]

(b) 45.1 J

In order to calculate the total energy dissipated among the floor and the block as thermal energy, we have to calculate the work done by the frictional force, which is

[tex]W_f = F_f d = (-\mu mg)d[/tex]

where[tex]\mu=0.635[/tex] is the coefficient of friction

m = 4.35 kg is the mass of the block

g = 9.8 m/s^2

d = 2.96 m is the displacement

and the negative sign is due to the fact that the frictional force has opposite direction to the displacement.

Substituting, we find

[tex]W_f =-(0.635)(4.35 kg)(9.8 m/s^2)(2.96 m)=-80.1 J[/tex]

The magnitude of this work is equal to the sum of the thermal energy dissipated between the floor and the block:

[tex]W_f = E_{floor}+E_{block}[/tex]

And since we know

[tex]W_f = 80.1 J\\E_{floor}=35.0 J[/tex]

we find

[tex]E_{floor}=W_f-E_{block}=80.1 J-35.0 J=45.1 J[/tex]

(c) 58.1 J

According to the work-energy theorem, the increase in kinetic energy of the block must be equal to the work done by the applied force minus the work done by friction (which becomes wasted thermal energy):

[tex]\Delta K=W-W_f[/tex]

Substituting

[tex]W=138.2 J\\W_f = 80.1 J[/tex]

We find

[tex]\Delta K=138.2 J-80.1 J=58.1 J[/tex]

diffraction ;-)

When water passes through small hole this type of phenomena happens.

diffraction interaction causes the water to spread as they pass through the rock opening. Hence option B is correct.

Diffraction is the interference or bending of waves via an aperture into the area that is geometrically in the shadow of the aperture or obstruction. Effectively, the wave's secondary source is the diffracting element or aperture. The term "diffraction" was created by Italian scientist Francesco Maria Grimaldi, who also made the first precise measurements of the phenomena in 1660.

On the registration plate, an infinite number of spots (three are illustrated) along length d project phase contributions from the wavefront, resulting in a continually changing intensity theta.

The Huygens-Fresnel principle, which views each point in a propagating wavefront as a collection of unique spherical wavelets, describes the diffraction phenomena in classical physics. When a wave from a certain direction, the distinctive bending pattern is most obvious.

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Answer:

 Electric field E = kQ/r^2  

Distance between charges = 6.30 - (-4.40) = 10.70m  

Say the neutral point, P, is a distance d from q1. This means it is a distance (10.70 - d) from q2.  

Field from q1 at P = k(-9.50x^10^-6) / d^2  

Field from q2 at P = k(-8.40x^10^-6) / (10.70-d)^2  

These fields are in opposite directions and are equal magnitudes if the resultant field = 0  

k(-9.50x^10^-6) / d^2 = k(-8.40x^10^-6) / (10.70-d)^2  

9.50 / d^2 =8.40 / (10.70-d)^2  

d^2 / (10.70-d)^2 = 9.50/8.40 = 1.131  

d/(10.70-d) = sqrt(1.1331) = 1.063  

d = 1.063 ((10.70-d)  

= 10.63 - 1.063d  

2.063d = 10.63  

d = 5.15m  

The y coordinate where field is zero is 6.30 - 5.15 = 1.15m

Explanation:

Explanation:

The law of repulsion is given by Coulomb. The mathematical form of Coulomb law is given by :

[tex]F=\dfrac{kq_1q_2}{r^2}[/tex]...............(1)

Where

F is the force

k is the electrostatic constant

[tex]q_1\ and\ q_2[/tex] are electric charges

r is the distance between charges

The Newton's law of universal gravitation is given by :

[tex]F=\dfrac{Gm_1m_2}{r^2}[/tex]..............(2)

G is the universal gravitational constant

From equation (1) and (2) it is clear that both law obeys inverse square law and both are of same type. So, the law of repulsion by Coulomb agrees with the Newton's law of universal gravitation.

The Law of Coulomb agrees with the inverse-square law and Newton's law of universal gravitation. It doesn't directly correspond with Newton's laws of motion or the findings of Gilbert on magnetism.

The Law of Coulomb is closely related to and agrees with the inverse-square law, which states that a specified physical quantity or intensity is inversely proportional to the square of the distance from the source of that physical property. This rule is also employed in Newton's law of universal gravitation.

However, the Law of Coulomb does not directly correspond or agree with Newton's laws of motion or the findings of Gilbert. Newton's laws of motion govern the relationship between the motion of an object and the forces acting upon it, while Gilbert's findings primarily concern magnetism.

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1104 km/hour

Distance between Dallas Texas to New York = 2760 km

Time the plane took from Dallas to New York = 2 hours

Time the plane took from New York back to Dallas = 2.5 hours

Formula to use

Speed the plane took from Dallas to New York

2760 = 2 x speed

speed = 2760 / 2

          = 1380 km/hour

Speed the plane took from New York to Dallas (ROUND TRIP)

2760 = 2.5 x speed

speed = 2760 / 2.5

           = 1104 km/hour

Answer: The speed of airplane is 1227 km/hr

Explanation:

Average speed is defined as the ratio of total distance traveled to the total time taken.

To calculate the average speed of the airplane, we use the equation:

[tex]\text{Average speed}=\frac{\text{Total distance traveled}}{\text{Total time taken}}[/tex]

We are given:

Total distance traveled = (2760 + 2760) km = 5520 km  (Round trip)

Total time taken = (2 + 2.5) hr = 4.5 hr

Putting values in above equation, we get:

[tex]\text{Average speed of airplane}=\frac{5520km}{4.5hr}=1227km/hr[/tex]

Hence, the speed of airplane is 1227 km/hr

C 82.4 N sorry man if i am wrong but don't even think about reporting my answer

Final answer:

The minimum force needed to start a 12.0 kg steel block moving, with a coefficient of static friction of 0.70, is slightly greater than 82.32 N. The closest given option is 82.4 N (Option C).

Explanation:

To find the minimum force needed to start the 12.0 kg Steel block moving on a surface with a coefficient of static friction of 0.70, we need to calculate the force of friction that must be overcome. This force of friction is given by Fs = μs * N, where Fs is the static friction force, μs is the coefficient of static friction, and N is the normal force. The normal force is equal to the weight of the block, which is the mass of the block times the acceleration due to gravity (9.8 m/s²).

First, calculate the normal force:

N = mass * gravity = 12.0 kg * 9.8 m/s² = 117.6 N

Next, calculate the force of static friction:

Fs = μs * N = 0.70 * 117.6 N = 82.32 N

Therefore, the minimum force needed to start the block moving is slightly greater than 82.32 N. Out of the given options, the closest value is 82.4 N (Option C).

A) Size

hope this helps

A( size like what the other person said

Answer:

20 cm

Explanation:

We can solve the problem by using the magnification equation:

[tex]M=\frac{h_i}{h_o}=-\frac{q}{p}[/tex]

where

[tex]h_i[/tex] is the size of the image

[tex]h_o = 2.0 m[/tex] is the height of the real object (the man)

[tex]q=50 mm =0.050 m[/tex] is the distance of the image from the lens

[tex]p = 5.0 m[/tex] is the distance of the object (the man) from the lens

Solving the formula for [tex]h_i[/tex], we find

[tex]h_i = -\frac{q}{p}h_o=-\frac{0.050 m}{5.0 m}(2.0 m)=-0.02 m = -20 cm[/tex]

And the negative sign means the image is inverted.

The height of the image on the detector is 100 mm.

To determine the height of the image on the detector, we can use the lens equation:

1/f = 1/di - 1/do

Where f is the focal length of the lens, di is the image distance, and do is the object distance.

In this case, the focal length of the lens is 50 mm, the object distance is 5.0 m, and the image distance is 50 mm (since the detector is located 50 mm behind the lens).

Substituting these values into the equation, we can solve for di:

1/50 = 1/di - 1/5000

Simplifying, we get:

di = 100 mm

This means that the height of the image on the detector is 100 mm, since the image distance is equal to the height of the image.

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1. 236 kJ

a. The phase (or state of matter) of the substance: from solid state to gas state (sublimation)

b. The enthalphy of sublimation, given by: [tex]\lambda=571 J/g[/tex]

c. The equation to use will be [tex]Q=m\lambda[/tex], where m is the mass of dry ice and [tex]\lambda[/tex] is the enthalpy of sublimation

d. The energy is being absorbed, because the heat is transferred from the environment to the dry ice: as a consequence, the bonds between the molecules of dry ice break and then move faster and faster, and so the substance turns from solid into gas directly.

e. The amount of energy being transferred is

[tex]Q=m\lambda=(412.9 g)(571 J/g)=2.36\cdot 10^5 J=236 kJ[/tex]

2.  165 kJ

a. The phase (or state of matter) of the substance: from gas state to liquid state (condensation)

b. The latent heat of vaporisation of water, given by [tex]\lambda=2260 J/g[/tex]

c. The equation to use will be [tex]Q=m\lambda[/tex], where m is the mass of steam that condenses and [tex]\lambda[/tex] is the latent heat of vaporisation

d. The energy is being released, since the substance turns from a gas state (where molecules move faster) into liquid state (where molecules move slower), so the internal energy of the substance has decreased, therefore heat has been released

e. The amount of energy being transferred is

[tex]Q=m\lambda=(72.9 g)(2260 J/g)=1.65\cdot 10^5 J=165 kJ[/tex]

3. 3.64 kJ

a. Only the temperature of the substance (which is increasing)

b. The specific heat capacity of silver, which is [tex]C_s = 0.240 J/gC[/tex]

c. The equation to use will be [tex]Q=m C_s \Delta T[/tex], where m is the mass of silver, Cs is the specific heat capacity and [tex]\Delta T[/tex] the increase in temperature

d. The energy is being absorbed by the silver, since its temperature increases, this means that its molecules move faster so energy should be provided to the silver by the surroundings

e. The amount of energy being transferred is

[tex]Q=m C_s \Delta T=(39.2 g)(0.240 J/gC)(412.9^{\circ}C-25.9^{\circ}C)=3641=3.64 kJ[/tex]

4. 89 kJ

a. Both the phase of the substance (from solid to liquid) and then the temperature

b. The latent heat of fusion of ice: [tex]\lambda=334 J/g[/tex] and the specific heat capacity of water: [tex]C_s=4.186 J/gC[/tex]

c. The equation to use will be [tex]Q=m\lambda + m C_s \Delta T[/tex], where m is the mass of ice, [tex]\lambda[/tex] the latent heat of fusion of ice, Cs is the specific heat capacity of water and [tex]\Delta T[/tex] the increase in temperature

d. The energy is being absorbed by the ice, at first to break the bonds between the molecules of ice and to cause the melting of ice, and then to increase the temperature of the water

e. The amount of energy being transferred is

[tex]Q=m\lambda +m C_s \Delta T=(156.3 g)(334 J/g)+(156.3 g)(4.186 J/gC)(56.232^{\circ}C-0^{\circ}C)=8.9\cdot 10^4 J=89 kJ[/tex]

The answer is

C. periodic fluctuations in the intensity if sound waves.

Answer:

D. periodic fluctuations in the frequency of sound waves

Explanation:

Beat is referred to the phenomena that occurs when to sound waves interfer with each other and they have different frequencies.

This difference is what creates a beating, wich in sound waves manifest as high and low sounds, this as a result of the oscilating frequency .

Answer:

+e

Explanation:

The charge of an up quark is:

[tex]q_u = +\frac{2}{3}e[/tex]

The charge of a down quark, instead, is:

[tex]q_d = -\frac{1}{3}e[/tex]

In this problem, we have a particle consisting of 1 down quark and 2 up quarks, Therefore, the net charge of the particle will be

[tex]q=1(q_d)+2(q_u)=1(-\frac{1}{3}e)+2(\frac{2}{3}e)=-\frac{1}{3}e+\frac{4}{3}e=\frac{3}{3}e=+e[/tex]

So, the particle has a charge of +e.

Answer:

240 H

Explanation:

The energy stored in an inductor is given by:

[tex]E=\frac{1}{2}LI^2[/tex]

where

L is the inductance of the inductor

I is the current

In this problem, we know:

[tex]I=300 A[/tex] is the current in the inductor

[tex]E=3.0 kWh = 3000 Wh[/tex] is the energy stored. We need to convert it into Joules:

[tex]E=3000 Wh=3000 Wh \cdot (3600 s/h)=1.08\cdot 10^7 J[/tex]

So, we can now solve the equation to find L, the inductance:

[tex]L=\frac{2E}{I^2}=\frac{2(1.08\cdot 10^7 J)}{(300 A)^2}=240 H[/tex]

The inductance needed to store 3.0 kWh of energy in a coil carrying a current of 300A is 240H.

The energy stored in an inductor is given by the equation Eind = 1/2LI². To find the inductance need to store a specific amount of energy, we can rearrange this equation to solve for L (inductance): L = 2E/I². First, we must convert the energy from kilowatt-hours to a compatible SI unit which is joules: E = 3.0 kWh * 3600000 (conversion factor) = 10800,0000J. Substituting in the given values, L = (2 * 10800000) / (300²), it becomes L = 240H. Hence, the inductance needed to store 3.0 kWh of energy in a coil carrying a current of 300A is 240H.

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I believe A. I'm so sorry if it's wrong! but it's the most best answer to me since it makes sense to me.

After 9 years of spectacular findings, NASA shut down the Kepler space telescope at the end of last October (2018).

From 2009 to 2018, the Kepler mission found more than 2,600 planets in other "solar systems" ... in orbit around other stars besides our Sun.  AND, at the time the mission ended, (5 months before the night I'm writing this), there were still more than 2,000 sets of data still to be analyzed.

The results suggest that having a family of planets is really not an unusual thing for a star.  Indeed, the rare, unusual stars may be the few that don't have planets orbiting them.

Planets around other stars are probably so common that they are the rule, and not the exception to the rule.

 = 3.73 seconds

Using the equation;

v = u + at

where v is the final velocity, u is the initial velocity and a is the acceleration due to gravity (-g) and t is the time taken.

Therefore;

v = u - gt

Thus;

v = 24.5 m/s, u = 12.1 m/s, a = -g = 9.8 m/s²

-24.5 m/s = 12.1 - 9.8 × t

36.6 = 9.8 t

t = 36.6/9.8

 = 3.73 seconds

First of all, we need to write the First Law of thermodynamics assigning the correct sign convention:

[tex]\Delta U = Q+W[/tex]

where

[tex]\Delta U[/tex] is the change in internal energy of the system

Q is the heat absorbed/released

W is the work done

and the signs are assigned based on whether there is an increase in the internal energy or not. Therefore:

Q is positive if it is absorbed by the system (because internal energy increases)

Q is negative if it is released by the system (because internal energy decreases)

W is negative if it is done by the system on the surrounding (because internal energy decreases)

W is positive if it is done by the surrounding on the system (because internal energy increases)

Using these definitions, we can now fill the text of the question:

When a system is heated, heat is ABSORBED by the system. The amount of heat added is given a POSITIVE sign. When a system is cooled, heat is RELEASED by the system. The amount of heat is given a NEGATIVE sign. If a gas expands, it must push the surrounding atmosphere away. Thus, work is done BY the system and is given a NEGATIVE sign. If a gas is compressed, then work is done ON the system. This work is given a POSITIVE sign.

Answer:

When a system is heated, heat is ABSORBED by the system. The amount of heat added is given a POSITIVE sign. When a system is cooled, heat is RELEASED by the system. The amount of heat is given a NEGATIVE sign. If a gas expands, it must push the surrounding atmosphere away. Thus, work is done BY the system and is given a NEGATIVE sign. If a gas is compressed, then work is done ON the system. This work is given a POSITIVE sign.

Explanation:

Answer:

C. red main-sequence star

Explanation:

Which of these stars has the hottest core?A)a blue main-sequence star. B)a red supergiant. C)a red main-sequence star.

Stars are basically exploding gases usually hydrogen and helium gases, held together by gravity. The closest to us is the sun. which contains gases

a blue main-sequence star temperature is between 10,000 Kelvin to 40000kelvin

red main-sequence star. can about 10million kelvin

while

B)a red supergiant is 3500-4500 K

Blue stars are generally the hottest, so a blue main-sequence star likely has the hottest core. The star's color provides insight into its core temperature.

The temperature of a star is typically indicated by its color, which can be used to infer information about its core. In general, blue stars are the hottest and red stars are the coolest. Therefore, of the options given, a blue main-sequence star likely has the hottest core. It's interesting to note that a star's core temperature can alter its life cycle stages, hence why we classify stars into different categories like main-sequence, supergiant and so on.

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The difference between visible light and gamma rays is their frequency, energy and wavelength. All electromagnetic waves travel at the same speed, which is called the speed of light. ... Visible light has much lower energy and longer wavelengths than gamma radiation.

Less than

For the parallel circuit in the previous part (with the switch closed), the current through the 20-ω resistor is less than the current through 10-ω resistor.

According to Ohm's Law, the current through a conductor is directly proportional to the potential difference at constant pressure and temperature.

Therefore; V α I

Mathematically;  V = IR ; Where R is the resistance of a device or a conductor.

From the relationship; I = V/R ; which means current and resistance have inverse relationship such that an increase in resistance causes a decrease in electric current.

Therefore; the current through the 20-ω resistor is less than the current through 10-ω resistor.

In a parallel circuit, the current through a 20-ω resistor is half of the current through a 10-ω resistor. This is because in a parallel circuit, resistors with lower resistance will have more current flowing through them, which is a consequence of Ohm's Law.

For a parallel circuit with a closed switch, the current through the resistors is influenced by their resistances.

According to Ohm's law, the current is inversely proportional to the resistance. Therefore, for the resistors of 20-ω and 10-ω, the current through the 20-ω resistor is half the current through the 10-ω resistor.

It is important to understand that in a parallel circuit, the voltage across each component is the same, and the total current in the circuit is the sum of the currents through each component. This implies that lower resistance components will draw more current from the circuit. The reason for this is represented mathematically in Ohm's law, which states that I = V/R.

Thus, when we speak about the 20-ω and 10-ω resistors, since they are assumed to have the same voltage across them, the current in the 20-ω resistor would be V/20, and the current in the 10-ω resistor would be V/10. This essentially means the current through the 20-ω resistor is half of the current through the 10-ω resistor given the same voltage.

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Answer:

Yes

Explanation:

When a sound wave moves through the air, a point in the air undergoes alternative changes in density called compressions and rarefactions.

A sound wave is a longitudinal waves, which means that the vibrations of the particles in the medium occur in a direction parallel to the direction of motion of the wave. Longitudinal waves creates two different regions in the medium:

- Compressions: these are regions where the density of the particles of the medium (in this case, air particles) are higher

- Rarefactions: these are regions where the density of the particles of the medium (in this case, air particles) are lower

25 is the correct answer

The brain is fully developed at the age of 25

Final answer:

Kirchhoff's loop rule for circuit analysis expresses the conservation of energy, stating that the sum of all voltage gains and drops in a closed circuit loop must be zero. This rule, pivotal in analyzing complex electrical circuits, ensures that energy within the circuit is conserved, aligning with the principle that the total energy supplied equals the total energy used.

Explanation:

Kirchhoff's loop rule for circuit analysis is an expression of the conservation of energy. This rule, also known as Kirchhoff's second law or voltage law, asserts that the sum of all voltage drops and rises around any closed circuit loop must equal zero. It effectively ensures that energy is conserved within an electrical circuit, reflecting the principle that the total energy supplied in the circuit equals the total energy used.

Kirchhoff's rules, including both the loop rule and the junction rule (which reflects the conservation of charge), are fundamental in analyzing electrical circuits. They allow for the calculation of potential differences and currents within complex circuits, making them pivotal tools in circuit analysis. Kirchhoff's loop rule is a simplification of Faraday's law of induction and holds true under the assumption that there is no fluctuating magnetic field linking the closed loop.

This simplicity makes the loop rule a powerful tool for analyzing circuits in a wide variety of situations, regardless of the circuit's composition and structure. By applying these rules, currents in the circuit can be related through the junction rule, and a system of equations can be generated using the loop rule to solve for each current value, thus conserving energy throughout the circuit.

Answer:

D

Explanation:

The law of reflection states that:

- The incident ray and the reflected ray lie on the same plane

- The angle of reflection is equal to the angle of incidence

The angle of incidence is the angle between the direction of the incident ray and the normal to the surface, while the angle of reflection is the angle between the direction of the reflected ray and the normal to the surface.

From the figure, we see that the only situation where the angle of reflection is equal to the angle of incidence is ray D.

The law of reflection states that the angle of reflection is equal to the angle of incidence, with these angles measured relative to a line perpendicular to the reflecting surface. Mirrors adhere precisely to this law, reflecting light at specific angles. Your choice, D, is correct if it shows the reflected light ray making the same angle with the normal as the incident light ray.

You are correct in thinking that the answer is D. The law of reflection stipulates that the angle of incidence (the angle at which incoming light hits a surface) is equal to the angle of reflection (the angle at which light is reflected). These angles are always measured relative to a line perpendicular to the surface, called the normal. In your case, the correct answer would be an option where the reflected ray is at the same angle to the normal as the incident ray. If D shows that, then D is indeed the correct answer.

Mirrors, having smooth surfaces, adhere to this law of reflection perfectly, reflecting light at specific angles. Rough surfaces, on the other hand, diffuse light, causing it to scatter in many directions. This is why we can see clearly in mirrors but not on rough surfaces.

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Answer:

They travel along the surface of the Earth and through the earth.

Answer:

[tex]8.1\cdot 10^{-4} C^{-1}[/tex]

Explanation:

The volumetric expansion of the liquid is given by

[tex]\Delta V=\alpha V_0 \Delta T[/tex]

where

[tex]\alpha[/tex] is the coefficient of volume expansion

[tex]V_0[/tex] is the initial volume

[tex]\Delta T[/tex] is the change in temperature

For the liquid in this problem,

[tex]V_0 = 2.35 m^3\\\Delta T=48.5^{\circ}C\\\Delta V=0.0920 m^3[/tex]

So we can solve the equation to find [tex]\alpha[/tex]:

[tex]\alpha=\frac{\Delta V}{V_0 \Delta T}=\frac{(0.0920 m^3)}{(2.35 m^3)(48.5^{\circ}C)}=8.1\cdot 10^{-4} C^{-1}[/tex]

(a) 700 Hz

For standing waves on a string, the number of antinodes (n) corresponds to the order of the harmonic. So, three antinodes corresponds to the third harmonic. Also, the frequency of the nth-harmonic is the nth-integer multiple of the fundamental frequency, so we have:

[tex]f_3 = 3 f_1 = 420 Hz[/tex]

where [tex]f_1[/tex] is the fundamental frequency. Solving for f1, we find

[tex]f_1 = \frac{420 Hz}{3}=140 Hz[/tex]

And so now we can find the frequency of the 5th-harmonic:

[tex]f_5 = 5 f_1 = 5 (140 Hz)=700 Hz[/tex]

(b) 56.4 N

The fundamental frequency of a string is given by:

[tex]f_1 = \frac{1}{2L} \sqrt{\frac{T}{\mu}}[/tex]

where we have:

L = 60 cm = 0.60 m is the length of the string

[tex]\mu = 2.0 g/m = 0.002 kg/m[/tex] is the linear density

T = ? is the tension in the string

Solving the formula for T and using the fundamental frequency, f1=140 Hz, we find

[tex]T=\mu (2Lf_1)^2=(0.002 kg/m)(2(0.60 m)(140 Hz))^2=56.4 N[/tex]

The frequency of the fifth harmonic of the string is 700 Hz, and the tension in the string is 56.448 N.

The question pertains to harmonic frequencies and tension in instruments, particularly a guitar string. Using the information given, we will apply the principles of standing waves on the string, wave speed derived from linear mass density and tension, and harmonic frequencies.

(a) If you're looking for the frequency of the fifth harmonic, note that the frequency of a particular harmonic is that harmonic number times the fundamental frequency. In this case, the string shows a standing wave with three antinodes, which refers to the third harmonic. So, the third harmonic frequency is 420 Hz; thus, the fundamental frequency is 420 Hz / 3 = 140 Hz. So, the frequency of the fifth harmonic is 5 times the fundamental frequency = 5*140 Hz = 700 Hz.

(b) To determine the tension in the string, you must first calculate the wave speed. The wave speed (Vw) can be derived from the formula for the frequency of a string, Vw=2Lf, where L is the length of the string in meters and f is the fundamental frequency. Here, L=0.6 m and f= 140 Hz, hence Vw = 2*(0.6m)*(140Hz) = 168 m/s. Given that wave speed is also calculated via the square root of tension (T) divided by linear mass density (μ), you can rearrange this formula to solve for T. This gives you T = (Vw)^2 * μ . The linear density is given as 2.0 g/m, but we need to convert it to kg/m to match the wave speed unit, so μ = 0.002 kg/m. Plugging in the values we find the tension: T = (168 m/s)^2 * 0.002 kg/m = 56.448 N.

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If you are using PLATO, which I'm sure you are cause I've had the same question, the answer it the following:

Transformers increase and decrease voltage as needed.

The alternating current more effective at long–distance travel than direct current because transformers increase and decrease voltage as needed.

Alternating current is an electric current which periodically reverses direction and changes its magnitude continuously with time.

The voltage difference developed through transmission lines is very high,. This reduces the current and minimizes the energy lost through transmission. So, alternating current is chosen over direct current for transmitting electricity.  It is much cheaper to change the voltage of an alternating current.

Thus, the alternating current more effective at long–distance travel than direct current because transformers increase and decrease voltage as needed

Learn more about alternating current.

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B.A heat engine that uses work to move heat

the plane was flying at 2,691. 33 m at 5.32°