A sound is recorded at 19 decibels. What is the intensity of the sound?
1 x 10^-8.7 W/m^2
1 x 10^-10.1 W/m^2
1 x 10^-11.9 W/m^2
1 x 10^-9.4 W/m^2

Answers

Answer 1

[tex]1 \times 10^{-10.1} \mathrm{Wm}^{-2}[/tex] is the intensity of the sound.

Answer: Option B

Explanation:

The range of sound intensity that people can recognize is so large (including 13 magnitude levels). The intensity of the weakest audible noise is called the hearing threshold. (intensity about [tex]1 \times 10^{-12} \mathrm{Wm}^{-2}[/tex]). Because it is difficult to imagine numbers in such a large range, it is advisable to use a scale from 0 to 100.

This is the goal of the decibel scale (dB).  Because logarithm has the property of recording a large number and returning a small number, the dB scale is based on a logarithmic scale. The scale is defined so that the hearing threshold has intensity level of sound as 0.

                     [tex]\text { Intensity }(d B)=(10 d B) \times \log _{10}\left(\frac{I}{I_{0}}\right)[/tex]

Where,

I = Intensity of the sound produced

[tex]I_{0}[/tex] = Standard Intensity of sound of 60 decibels = [tex]1 \times 10^{-12} \mathrm{Wm}^{-2}[/tex]

So for 19 decibels, determine I as follows,

                   [tex]19 d B=(10 d B) \times \log _{10}\left(\frac{I}{1 \times 10^{-12} W m^{-2}}\right)[/tex]

                  [tex]\log _{10}\left(\frac{1}{1 \times 10^{-12} \mathrm{Wm}^{-2}}\right)=\frac{19}{10}[/tex]

                  [tex]\log _{10}\left(\frac{1}{1 \times 10^{-12} \mathrm{Wm}^{-2}}\right)=1.9[/tex]

When log goes to other side, express in 10 to the power of that side value,

                  [tex]\left(\frac{I}{1 \times 10^{-12} W m^{-2}}\right)=10^{1.9}[/tex]

                  [tex]I=1 \times 10^{-12} \mathrm{Wm}^{-2} \times 10^{1.9}=1 \times 10^{-12-1.9}=1 \times 10^{-10.1} \mathrm{Wm}^{-2}[/tex]


Related Questions

The study of the transmission of light and sound in the oceans is an example of ________ oceanography.

Answers

Answer:

Physical

Explanation:

The study of the transmission of light and sound in the oceans is an example of Physical oceanography.

Physical oceanography is the analysis of physical conditions and mechanisms in the ocean, particularly ocean waters ' movements and physical characteristics. One of many sub-domains in which oceanography is divided is physical oceanography.

Final answer:

The study of light and sound in oceans relates to physical oceanography, which incorporates wave optics to explain phenomena like diffraction and apply principles to technologies like fiber optics.

Explanation:

The study of the transmission of light and sound in the oceans is an example of physical oceanography. This branch of oceanography explores the wave optics of light as it behaves in different media, specifically how light and sound waves propagate through water. One of the interesting phenomena is the diffraction of waves, which occurs when a wave encounters an obstacle or passes through an aperture and displays bending and spreading. This is not fully explained by geometric optics; instead, it illustrates the intricate nature of wave interactions that can be characterized by wave optics or physical optics. Understanding how light behaves when it exhibits wave characteristics can also lead to practical applications such as fiber optics, which involves the transmission of light down fibers of plastic or glass by employing the principle of total internal reflection.

To avoid compromising your car's aerodynamic properties, you should avoid ________.A. running your air conditioning system B. taking turns at high speeds C. carrying large loads on the outside of the vehicle

Answers

Answer:

C) True   carrying large loads on the outside of the vehicle

Explanation:

The aerodynamic property of an object depends on its outer shape. In general, objects should be thin in the front and not completely flat in the back, to avoid the eddies that create a great Arrate, losing all the aerodynamics of the system.

With this we can review the final statements

A) False The air conditioner is used with the glasses raised, so the exterior shape of the car does not change and its aerodynamics remains unchanged.

B) Phallus. This does not change the outer shape, I get a small inclination,

C) True. External loads dramatically change the external shape of the vehicle significantly reducing its aerodynamic characteristics.

Final answer:

To avoid compromising your car's aerodynamic properties, avoid carrying large loads on the outside of the vehicle and taking turns at high speeds.

Explanation:

To avoid compromising your car's aerodynamic properties, you should avoid carrying large loads on the outside of the vehicle. Large loads increase drag and disrupt the flow of air around the car, negatively affecting its aerodynamics. It is also advisable to avoid taking turns at high speeds as it can create instability and affect the car's balance. Running the air conditioning system does not directly impact the aerodynamic properties of the car, so it is not necessary to avoid running your air conditioning system.

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20 cubic inches of a gas with an absolute pressure of 5 psi is compressed until its pressure reaches 10 psi. What's the new volume of the gas? (Assume that there's no change in temperature.)A. 100 cubic inchesB. 10 cubic inchesC. 40 cubic inchesD. 5 cubic inches

Answers

Answer:

B. [tex]V_{f}= 10\,cubic\,inches [/tex]

Explanation:

Assuming we are dealing with a perfect gas, we should use the perfect gas equation:

[tex]PV=nRT [/tex]

With T the temperature, V the volume, P the pressure, R the perfect gas constant and n the number of mol, we are going to use the subscripts i for the initial state when the gas has 20 cubic inches of volume and absolute pressure of 5 psi, and final state when the gas reaches 10 psi, so we have two equations:

[tex]P_{i}V_{i}=n_{i}RT_{i} [/tex] (1)

[tex] P_{f}V_{f}=n_{f}RT_{f}[/tex] (2)

Assuming the temperature and the number of moles remain constant (number of moles remain constant if we don't have a leak of gas) we should equate equations (1) and (2) because [tex] T_{i}=T_{f}[/tex], [tex]n_{i}=n_{f} [/tex] and R is an universal constant:

[tex]P_{i}V_{i}= P_{f}V_{f} [/tex], solving for [tex]V_{f} [/tex]

[tex]V_{f} =\frac{P_{i}V_{i}}{P_{f}} =\frac{(5)(20)}{10} [/tex]

[tex]V_{f}= 10 cubic\,inches [/tex]

A pump is required to lift 800 kg of water per minute from a well 14.6 m deep and eject it with a speed of 18.2 m/s..

a. How much work is done per minute in lifting the water?b. How much in giving the water the kinetic energy it has when ejected?K =?c. What must be the power output of the pump?

Answers

Answer:

a)W = 116800 J

b)KE=132496 J

c)P=4154.93 W

Explanation:

Given that

m= 800 kg/min

h= 14.6 m

v= 18.2 m/s

a)

Work done required ,W= m g h

h=height of the well

m=mass

W= 800 x 14.6 x 10                 ( take g= 10 m/s²)

W = 116800 J

b)

kinetic energy = KE

[tex]KE=\dfrac{1}{2}mv^2[/tex]

m=mass

v=velocity

[tex]KE=\dfrac{1}{2}\times 800\times 18.2^2[/tex]

KE=132496 J

c)

Pump power given as

[tex]P=\dfrac{W'}{t}[/tex]

W'=Total work done

t=time

[tex]P=\dfrac{116800+132496}{60}[/tex]

P=4154.93 W

Final answer:

The work done per minute in lifting the water is 114,464 J. The kinetic energy given to the water when it is ejected is 132,488 J. The power output of the pump is 4116.2 W.

Explanation:

The subject of this question is Physics, specifically the topic of work, energy, and power.

To calculate the work done in lifting the water, we can use the formula:

Work = Force × Distance

The force required to lift the water can be calculated using the formula:

Force = Mass × Gravity

(a) To find the work done per minute in lifting the water, we multiply the weight of the water by the height it is lifted. The weight of the water is mass times gravity, which is

Force =800 kg * 9.8 m/s^2 = 7840 N.

So, the work done is 7840 N * 14.6 m = 114,464 J.

(b) To find the kinetic energy given to the water when it is ejected, we use the formula for kinetic energy, which is 1/2 * mass * speed^2.

So, the kinetic energy = 1/2 * 800 kg * (18.2 m/s)^2

                                     = 132,488 J.

(c) The power output of the pump is the total work done per minute divided by the time, which is

Power =(114,464 J + 132,488 J) / 60 s

           = 4116.2 W.

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A car traveling at 7.3 m/s accelerates at the rate of 0.82 m/s2 for an interval of 7.4 s. Find vf.

Answers

Final velocity is 13.37 m/s

Explanation:

We have equation of motion v = u + at

     Initial velocity, u = 7.3 m/s

     Final velocity, v = ?

     Time, t = 7.4 s

     Acceleration,a = 0.82 m/s²

     Substituting

                      v = u + at  

                      v = 7.3 + 0.82 x 7.4

                      v = 13.368 m/s

Final velocity is 13.37 m/s

During an investigation, a scientist heated 123.6 g of copper carbonate till it decomposed to form a black residue. The total mass of the black residue formed was 79.6 g. Does the law of conservation of mass hold true in this case? Use complete sentences to justify your answer based on numerical calculations

Answers

Answer:

See below explanation

Explanation:

The correspondent chemical reaction for copper carbonate decomposed by heat is:

CuCO₃ (s) → CuO (s) + CO₂ (g)

Considering all molar mass (MM) for each element ( we consider rounded numbers) :

MM CuCO₃ = 123 g/mol

MM CuO = 79 g/mol

MM CO₂ = 44 g/mol

Statement mentions that scientis heated 123.6 g of CuCO₃ (almost a MM), until a black residue is obtained, which weights 79.6 g : this solid residue is formed by CuO, and the remaining mass (approximatelly 44 g) belongs to teh second product, this is, CO₂; as it is a gas compund, it is not certainly included on the solid residue.

So, law of conservation mass is true for this case, since: 123.6 g = 79.6 g + 44 g. As explained, on the solid residue, we don not include the 44 g, which  "escaped" from our system, since it is a gas compound (CO₂)

You know that you sound better when you sing in the shower. This has to do with the amplification of frequencies that correspond to the standing-wave resonances of the shower enclosure. A shower enclosure is created by adding glass doors and tile walls to a standard bathtub, so the enclosure has the dimensions of a standard tub, 0.75m wide and 1.5m long. Standing sound waves can be set up along either axis of the enclosure. What are the lowest two frequencies that correspond to resonances on each axis of the shower? These frequencies will be especially amplified. Assume a sound speed of 343 m/s.A) What are the lowest two frequencies that correspond to resonances on the short axis?B) What are the lowest two frequencies that correspond to resonances on the longer axis?

Answers

Answer:

Explanation:

For first overtone

Standing waves will be formed lengthwise and breadth-wise in the enclosures  having dimension of .75m  x 1.5 m

A ) For the formation of lowest two frequencies formed by standing waves along the breadth  , fundamental note and first overtone may be considered.  

For fundamental note ,  

the condition is  

wave length λ = 2L = 2 x 0.75 m  

λ = 1.5 m  

frequency n = v / λ

= 343 / 1.5  

= 229  Hz approx

For first overtone

λ = L = 0.75m

frequency n = v / λ

n = 343 / 0.75  

= 457 Hz approx

B)

For the formation of lowest two frequencies formed by standing waves along the length , fundamental note and first overtone may be considered.  

For fundamental note ,  

the condition is  

wave length λ = 2L = 2 x 1.5 m  

λ = 3 m  

frequency n = v / λ

= 343 / 3  

= 114 Hz approx

frequency n = v / λ

n = 343 / 1.5  

= 229 Hz approx

A) The lowest two frequencies that correspond to resonances on the short axis for first overtone.

B) Standing waves will be formed lengthwise and breadth-wise in the enclosures  having dimension of .75m  x 1.5 m

"Sound"

Part A )

For fundamental note ,  

wave length λ = 2L = 2 x 0.75 m  

λ = 1.5 m  

frequency n = v / λ

frequency n = 343 / 1.5  

frequency n = 229  Hz approx

For first overtone

λ = L = 0.75m

frequency n = v / λ

n = 343 / 0.75  

frequency n= 457 Hz approx

Part B)

For fundamental note ,  

wave length λ = 2L = 2 x 1.5 m  

λ = 3 m  

frequency n = v / λ

frequency n= 343 / 3  

frequency n= 114 Hz approx

For first overtone

frequency n = v / λ

frequency n = 343 / 1.5  

frequency n= 229 Hz approx

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A box of mass 45 kg slides down a ramp onto a flat surface. The box slides a distance of 4.9 m across the flat surface and then stops. The coefficient of friction between the flat surface and the box is 0.39. What was the speed of the box at the base of the ramp?

6.1 m/s

0.77 m/s

3.0 m/s

19 m/s

Answers

Answer:

6.1 m/s

Explanation:

Gradpoint

You are standing on a scale in an elevator. suddenly you notice your weight decreases. what do you conclude? a. the elevator is accelerating downwards. b. the elevator is accelerating upwards. c. the elevator is moving at a constant velocity upwards. d. your diet is working. e. the elevator is moving at a constant velocity downwards.

Answers

Answer:

The elevator is accelerating downwards.

Explanation:

When an elevator accelerating downward it moves together with the person inside and the weight of the person does not change, but if the person is standing on a scale the contact force between the person and the scale is reduced.  The scale therefore has to push upward with less force on the person to support the person's weight. Therefore the Normal Force is smaller, so the reading on the scale becomes less than the true weight.

Final answer:

When you feel your weight decrease in an elevator, it means that the elevator is accelerating downwards. This is due to the equivalence principle in physics, where the downward acceleration counteracts some of gravity's pull making you feel lighter.

Explanation:

If you are standing on a scale in an elevator and suddenly notice your weight decreases, you can conclude that the elevator is accelerating downwards. The weight we feel is a combination of our actual weight and the effect of the elevator's motion. The apparent reduction in weight is because the downwards acceleration of the elevator is counteracting some of the pull of gravity, causing you to feel lighter.

This is a principle of physics known as the equivalence principle, which is a key part of Einstein's theory of general relativity. When the elevator accelerates downwards, we experience a sensation of decreased weight, as the floor of the elevator 'falls' away from us at an accelerated rate.

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Technician A says that a MAF sensor is a high-authority sensor and is responsible for determining the fuel needs of the engine based on the measured amount of air entering the engine. Technician B says that a cold wire MAF sensor uses the electronics in the sensor itself to heat a wire 20°C below the temperature of the air entering the engine. Who is right?
A) Technician A
B) Technician B
C) Both technicians
D) Neither technician

Answers

Answer:

a. Technician A

Explanation:

Technician A says that a MAF sensor is a high-authority sensor and is responsible for determining the fuel needs of the engine based on the measured amount of air entering the engine. Technician B says that a cold wire MAF sensor uses the electronics in the sensor itself to heat a wire 20°C below the temperature of the air entering the engine. Who is right

MAF wich stands for  mass airflow sensor determines the mass of air flowing into the engine's air intake system. ... , the wire cools When air flows past the wire, decreasing its resistance, thereby more current flows through the circuit. When the MAf goes bad, it can not sense the amount of air intake into the engine.

The instructions for a 13-foot ladder state that the bottom of the ladder must be set at least 5 feet from a building. How high can the ladder safely reach on the garage?

Answers

Answer:

The height at which the ladder safely reach on the garage is 12 meters.

Explanation:

It is given that,

Height of the ladder, H = 13 foot

Bottom of the ladder, B = 5 feet

To find,

How high can the ladder safely reach on the garage?

Solution,

The ladder and the wall follows the Pythagoras theorem. 13 foot is the height of the ladder. Distance between wall and the ladder is 5 feet. Let L is the height at which the ladder safely reach on the garage. On using Pythagoras theorem we get :

[tex]H^2=B^2+L^2[/tex]

[tex]L^2=H^2-B^2[/tex]

[tex]L^2=13^2-5^2[/tex]

L = 12 m

So, the height at which the ladder safely reach on the garage is 12 meters. Hence, this is the required solution.

Rotor windings in wound rotor motors are connected to ? on the shaft of the motor. Brushes allow those windings to be connected to external resistors to control the speed of the motor.

Answers

Answer:

Slip Rings

Explanation:

The wound rotor motor has a three-phase winding with each one connected to seperate slip rings. These slip rings contain brushes which form a secondary circuit where resistance can be inserted and this will allow for the rotor current to run more in phase with the stator current which will result in increased torque that is created

Josh manages security at a power plant. The facility is sensitive, and security is very important. He would like to incorporate two-factor authentications with physical security. Which of the options below is the best way to meet this requirement?

Answers

Question: Josh manages security at a power plant. The facility is sensitive, and security is very important. He would like to incorporate two-factor authentications with physical security. Which of the options below is the best way to meet this requirement?  A) Smart cards B) A mantrap with a smart card at one door and a pin keypad at the other door C) A mantrap with video surveillance D) A fence with smart card gate access  Answer: The correct answer is (B) A mantrap with a smart card at one door and a pin keypad at the other door  Explanation: Multi-factor access control systems are access control systems that authorises access only after more than one piece of evidence is presented to authenticate a user. The mechanisms used in multi-factor authentication include 1.  Knowledge (something the user and only the user knows),  2.  Possession (something the user and only the user has), and  3.  Inherence (something the user and only the user is). A two-factor authentication system uses two of these mechanisms to grant or deny access. An authentication system that uses a mantrap with a smart card (possession) on one door and a pin keypad (knowledge ) on the other door is a two factor authentication system.

Unless otherwise posted, what is the speed limit for cars in a residential area?_

A) 20 mph
B) 25 mph
C) 30 mph

Answers

Final answer:

The typical speed limit in a residential area is 25 miles per hour, which corresponds with option B) 25 mph. Always check local signs as limits can vary. Over this limit, like driving 31 mph in a 30 mph zone, may be tolerated but it's best to strictly follow posted speeds to ensure safety and avoid penalties.

Explanation:

The speed limit for cars in a residential area, unless otherwise posted, is generally 25 miles per hour (mph). This means that option B) 25 mph is typically the correct choice for such a setting. However, it's important to always observe local traffic signs as speed limits can vary depending on specific city, county, or state regulations.

For instance, the information given states that 50 kilometers per hour is approximately 31 miles per hour, suggesting that some residential areas might have a speed limit close to this value. However, in the context of the United States, 25 mph is a common residential speed limit, which is enforced to ensure the safety of the neighborhood, including pedestrians, cyclists, and playing children.

It's also important to note that speedometers and radar measurements can vary in accuracy. Therefore, while you may not get in trouble for driving slightly over the speed limit, such as 31 mph in a 30 mph zone, it's safest to adhere strictly to posted limits to avoid traffic violations and fines.

_________is a system that uses the reflection of underwater sound waves to detect objects.

1. sounds
2. ultrasound
3. sonar
4. refraction

Answers

Answer:3-Sonar

Explanation:

Sonar system is used to detect the under water objects by using the deflection of sound waves.

Sonar is an acronym of Sound navigation ranging.Two types of sonar sets are used for working: active and passive. The active sonar system pushes out sound signals called pings, and then absorbs the return sound echo. Passive sound sets obtain sound echoes without transmitting their actual sound signals. Submarines are using sonar to track other vessels.    

Which statement is TRUE? Group of answer choices a) An object that is slowing down while traveling in the negative x-direction always has a positive acceleration. b) An object that is speeding up while traveling in the negative x-direction always has a positive acceleration. c) An object that is slowing down always has a negative acceleration, regardless of the direction it travels. d) An object that is speeding up always has a positive acceleration, regardless of the direction it travels. e) An object that is slowing down always has a positive acceleration, regardless of the direction it travels.

Answers

Answer:

d) An object that is speeding up always has a positive acceleration, regardless of the direction it travels.

Explanation:

a ) a) An object that is slowing down while traveling in the negative x-direction always has a positive acceleration.

It has negative acceleration in  the negative x-direction.

b) An object that is speeding up while traveling in the negative x-direction always has a positive acceleration.

It has a positive acceleration in the negative x-direction'

c) An object that is slowing down always has a negative acceleration, regardless of the direction it travels.

It has a positive  acceleration in opposite direction.

e ) An object that is slowing down always has a positive acceleration, regardless of the direction it travels.

It has a positive acceleration only in opposite direction .

When the termination is a terminal block, care must be taken to ensure a good electrical connection without damaging the conductor. Terminals should not be used for more than ? conductor(s), unless they are identified for such use
a) one
b) two
c) three

Answers

Answer:

When the termination is a terminal block, care must be taken to ensure a good electrical connection without damaging the conductor. Terminals should not be used for more than one

Explanation:

The Terminal block being a modular block, having insulated frame, which can secure more than two wires in it. It has a conducting strip in it. These terminal clocks helps in making the connection safer as well as organised. These terminal blocks are used for power distribution in safer way. Its potential is it can distribute power from single to multiple output. The conductor is used for making it proper contact.

A BASE jumper runs off a cliff with a speed of Which of the following is closest to his speed after 0.5 seconds?
A) 10 m/s
B) 8 m/s
C) 6 m/s
D) 3 m/s
E) not given

Answers

Answer:

8m/s

Explanation:

The question is incomplete.

But if the given speed is 3m/s

t= 0.5s

From Newton's equation of motion v=u+at

U= 3m/s

V= 3+ 0.5×10 a=10m/s^2

v= 8m/s

Final answer:

The BASE jumper's speed after 0.5 seconds, with gravity approximated as 10 m/s², would be 5 m/s. This is calculated using kinematic equations in physics, which are not explicitly stated in the choices, therefore the correct answer is E) not given.

Explanation:

The subject of the question involves the principles of kinematics in physics. Given that we approximate the acceleration due to gravity (g) as 10 m/s², we can calculate the BASE jumper's speed after 0.5 seconds.

The formula to calculate the speed (v) of a falling object at a given time (t) when released from rest is v = gt. Therefore, after 0.5 seconds, the BASE jumper's speed would be v = 10 m/s² × 0.5 s = 5 m/s. None of the options A) 10 m/s, B) 8 m/s, C) 6 m/s, or D) 3 m/s exactly match this result. Hence, the correct answer is E) not given.

Torque can cause the angular momentum vector to rotate in UCM. This motion is called ___________.

Answers

Torque can cause the angular momentum vector to rotate in UCM. This motion is called _Conservation of Angular momentum__________.

Answer:

Conservation of Angular momentum

Explanation:

The motion of an object in a circular path at constant speed is known as uniform circular motion (UCM). An object in UCM is constantly changing direction, and since velocity is a vector and has direction, you could say that an object undergoing UCM has a constantly changing velocity, even if its speed remains constant.

The law of conservation of angular momentum states that when no external torque acts on an object, no change of angular momentum will occur.

Key Points

When an object is spinning in a closed system and no external torques are applied to it, it will have no change in angular momentum.

The conservation of angular momentum explains the angular acceleration of an ice skater as she brings her arms and legs close to the vertical axis of rotation.

If the net torque is zero, then angular momentum is constant or conserved.

Angular Momentum

The conserved quantity we are investigating is called angular momentum. The symbol for angular momentum is the letter L. Just as linear momentum is conserved when there is no net external forces, angular momentum is constant or conserved when the net torque is zero. We can see this by considering Newton’s 2nd law for rotational motion:

τ→=dL→dt, where  

τ is the torque. For the situation in which the net torque is zero,  

dL→dt=0.

If the change in angular momentum ΔL is zero, then the angular momentum is constant; therefore,

L  =constant

L=constant (when net τ=0).

This is an expression for the law of conservation of angular momentum.

Example and Implications

An example of conservation of angular momentum is seen in an ice skater executing a spin,  The net torque on her is very close to zero,

because (1) there is relatively little friction between her skates and the ice, and (2) the friction is exerted very close to the pivot point.

Conservation of angular momentum is one of the key conservation laws in physics, along with the conservation laws for energy and (linear) momentum. These laws are applicable even in microscopic domains where quantum mechanics governs; they exist due to inherent symmetries present in nature.

Final answer:

Precession is the rotation of the angular momentum vector in uniform circular motion (UCM) caused by torque. Torque's direction aligns with the direction of the angular momentum it produces. Any alteration in angular momentum is influenced by the average torque and the time period of its exertion, adhering to the conservation laws of angular momentum.

Explanation:

The motion caused by torque making the angular momentum vector to rotate in UCM is called precession. In other words, precession is the circular motion of the pole of the axis of a spinning object around another axis due to torque. This is similar to how a spinning top wobbles as it continues to spin.

For example, if we consider a merry-go-round, torque is perpendicular to the plane formed by radius and force. This direction aligns with the direction your right thumb would point to if you curled your fingers in the direction of the force. This shows that the direction of the torque is the same as that of the angular momentum it produces.

It's important to note that angular momentum, like energy and linear momentum, is conserved when the net external torque is zero. This is a universally applicable law underlying unity in physical laws. The change in angular momentum is given by the product of average torque and the time interval during which the torque is exerted, embodying the conservation laws of angular momentum.

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A 24 year old motorcycle driver would not be required to wear protective eyewear when riding in Florida.
A) True
B) False

Answers

Answer:

False

Explanation:

A 24 year old motorcycle driver would not be required to wear protective eyewear when riding in Florida,This is a False statement.

The law is all riders would have to wear protective eyewear when riding in Florida.

Pedestrians, bicyclists and slow-moving vehicles are not allowed on expressways because expressways have minimum speed limit requirements that these travelers cannot reach.
A. True
B. False

Answers

Answer:

TRUE

Explanation:

It is TRUE that pedestrians, bicyclists and slow-moving vehicles are not allowed on expressways because expressways have minimum speed limit requirements that these travelers cannot reach. This minimum limit of speed varies country to country.

In America, the minimum speed limit in Rural Areas is 40 mph (miles per hour) i.e. 65km/h (kilometer per hour) while in Urban Areas it is 55mph i.e. 90km/h which cannot be met by pedestrians and by-cycles easily.

How far will it go, given that the coefficient of kinetic friction is 0.10 and the push imparts an initial speed of 3.9 m/s ?

Answers

Final answer:

The question is asking for the distance an object will travel given its initial speed and a coefficient of friction. However, without knowing the object's mass, we cannot calculate the exact distance.

Explanation:

The question is asking you to calculate the distance an object will travel, given an initial speed and friction. This is a physics problem that can be solved using the principles of friction and kinetic energy.

Since we know the coefficient of kinetic friction (μk) and initial speed (v), we can calculate the distance travelled. The frictional force is equal to μk * m * g, where m is the mass of the object and g is the gravity. However, we do not have the mass of the object.

As we have incomplete information provided in the question, we cannot calculate the exact distance travelled. The chapter references given also do not give us the necessary information to solve the problem. With full information, we would use the formula relating kinetic energy to work done by friction to find the distance:

1/2 * m * v² = μk * m * g * d,  which simplifies to d = v² / (2 * g * μk)

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950 - kg toyota collides into the rear end of a 2200-kg cadillac stopped at a red light. THe bumpers lock, the brakes are locked and the two car skid forward 4.8 meteres before stopping. The police officer, knowing the the coefficient of kinetic friction between tires and road is 0.4, calculates the speed of the toyota impact. What was the speed of the car?

Answers

Answer:

u = 20.33 m/s

Explanation:

given,

mass of Toyota car = 950 Kg

mass of Cadillac = 2200 Kg

distance to stop = 4.8 m

coefficient of friction = 0.4

initial speed of the Toyota = ?

we know,

F = ma

and frictional foce

F = μ N = μ m g

where N is normal force

now equating both the equation

ma  = μ m g

 a = μ g

 a = 0.4 x 9.8

 a = 3.92 m/s²

using equation of motion

v² = u² + 2 a s

v² = 0² + 2 x 3.92 x 4.8

v = 6.13 m/s

above given velocity is the combined velocity of the Toyota and Cadillac

now, using conservation of momentum

m u = (M + m) v

950 x u = (2200+ 950) x 6.13

u = 20.33 m/s

The speed of Toyota before impact is equal to u = 20.33 m/s

Final answer:

The speed of the Toyota at the moment of impact is 0 m/s.

Explanation:

To find the speed of the Toyota at the moment of impact, we can use the principle of conservation of momentum. The momentum before the collision is equal to the momentum after the collision.

The momentum of an object is given by the product of its mass and velocity. So, we can write:

massT * velocityT = massC * velocityC

where massT and velocityT are the mass and velocity of the Toyota, and massC and velocityC are the mass and velocity of the Cadillac.

The mass of the Toyota is 950 kg, and the mass of the Cadillac is 2200 kg. The velocity of the Cadillac is 0 m/s because it is stopped. Solving for the velocity of the Toyota:

velocityT = (massC * velocityC) / massT

velocityT = (2200 kg * 0 m/s) / 950 kg = 0 m/s

Therefore, the speed of the Toyota at the moment of impact is 0 m/s.

As a result of the motion through the magnetic field, a charge in the rod will experience a force F⃗ =qv⃗ ×B⃗ : the usual part of the Lorentz force for charges moving through magnetic fields. This force will push the charge in the rod, and hence this force will be an electromotive force (EMF). For now, we shall say that the force that moves the charges is due to an induced electric field Einduced, which will enable us to calculate the EMF. The fact that there is an induced electric field at all is rather subtle, because there is no closed loop that encloses some changing flux. Therefore, a method that does not involve Faraday's law must be used to solve this motional EMF problem. In fact, this problem is a good introduction to some of the ideas behind Faraday's law. Find the y component of the induced electric field Einduced.

Answers

Based on the information given, it should be noted that the y component of the induced electric field will be E = -Bv.

An induced electric field simply means a nonconversative field that is generated due to a changing magnetic field.

The force that acts on the charge moving with the velocity is given. In this case, the component of the induced electric field will be E = -Bv.

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If an apprentice makes 55% of Journeyman wages, what would an apprentice make per hour if the Journeyman scale is $17.64?

Answers

Answer:

$9.702  per hour

Explanation:

The apprentice earns 55% of what the journeyman earns on a hourly scale.

Amount the apprentice makes per hour = 55% of $17.64

                                                             = (55/100) *17.64

                                                           = 0.55 *17.64

                                                          = $9.702

Final answer:

The apprentice would make $9.70 per hour if the Journeyman scale is $17.64, as 55% of $17.64 is $9.70.

Explanation:

Given:
Journeyman scale = $17.64/hour
Apprentice wages = 55% of Journeyman wages

Calculation:
Apprentice wages = 0.55 * $17.64
Apprentice wages = $9.702

Therefore, an apprentice would make $9.70 per hour.

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A 1000-N boulder on the right end of a seesaw is raised when the left end of the seesaw is pushed downward. If both ends of the seesaw are equal distances from the fulcrum, then to raise the boulder, the left end should be pushed downward with a minimum force of
a. 500 N
b. 750 N.
c. more than 1000 N.
d. 1000 N.

Answers

Answer:

d. 1000 N.

Explanation:

For the seesaw to be in equilibrium the moment on left of the fulcrum and the moment to the right of the fulcrum must be equal.

Let L be the distance on either side of fulcrum at which the boulder is kept

F be the minimum force used to pushdown the left end

According to principle

L×1000= L×F

F= 1000 N

Hence option D is correct

Suppose you are driving due east, traveling a distance of 1500 min 2 minutes. You then turn due north and travel the same distance in the same time. What can be said about the average speeds and the average velocities for the two segments of the trip?

(a) The average speeds are the same, and the average velocities are the same.
(b) The average speeds are the same, but the average velocities are different.
(c) The average speeds are different, but the average velocities are the same.

Answers

Answer:

(b) The average speeds are the same, but the average velocities are different.

Explanation:

The average speed is a scalar quantity which is calculated on the total distance travelled. Distance is the length of path traced and the speed is calculated as distance per unit time.

Mathematically:

[tex]v=\frac{d}{t}[/tex]

[tex]v=\frac{(1500+1500)}{2\times 60}\ m.s^{-1}[/tex]

While the velocity is a vector quantity calculated on the displacement and is defined as the rate of displacement.

Mathematically:

[tex]\vec v=\frac{\vec s}{t}[/tex]

[tex]\vec v=\frac{\sqrt{1500^2+1500^2} }{2\times 60}\ m.s^{-1}[/tex]

The main water line enters a house on the first floor. The line has a gauge pressure of 2.64 x 105 Pa.

(a) A faucet on the second floor, 6.50 m above the first floor is turned off. What is the gauge pressure at this faucet?

(b) How high could a faucet be before no water would flow from it, even if the faucet were open?

Answers

Answer:

a. P1=200235pa

b. h=26.91m

Explanation:

The main water line enters a house on the first floor. The line has a gauge pressure of 2.64 x 105 Pa.

(a) A faucet on the second floor, 6.50 m above the first floor is turned off. What is the gauge pressure at this faucet?

(b) How high could a faucet be before no water would flow from it, even if the faucet were open?

pressure is the force per unit area.

force is that which tends to change a boy's state of rest or uniform motion in a straight line

rho stands for the density of water which is 1000kg/m3

p2=p1+rhogh

p1=p2-rhogh

the gauge pressure at 6.5m

will be:

2.64 x 10^5 Pa-100kg/m3*9.81*6.5

P1=200235pa

b. How high could a faucet be before no water would flow from it, even if the faucet were open?

b.h=p2-p1/(grho)

h=2.64 x 105 Pa/(1000*9.81)

h=26.91m

Final answer:

To find the gauge pressure and height limit of a faucet on the second floor compared to the first floor in a house with a main water line.

Explanation:

(a) To find the gauge pressure at the faucet on the second floor, we can use the equation: P2 = P1 + ρgh. Here, P1 = 2.64 x 105 Pa, ρ is the density of water, g is the acceleration due to gravity, and h is the height difference between the first and second floor. Plugging in the values, we get: P2 = 2.64 x 105 + (1000 kg/m3) x (9.8 m/s2) x 6.50 m. Solving for P2 gives us the gauge pressure at the faucet on the second floor.

(b) To find the maximum height a faucet could be before no water would flow from it, we can equate the gauge pressure to zero in the equation: P2 = P1 + ρgh. Solving for h, we can find the maximum height.

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An object will be stable if __________.
a. its center of gravity lies outside
b. its base of support its center of gravity lies over
c. its base of support
d. its center of gravity is below
e. its highest point

Answers

Answer:

option (b)

Explanation:

An object is said to be in stable equilibrium if its potential energy is minimum and the force acting on the object is zero.

When the base of an object is too broad so that the vertical line passing through its centre of gravity line passes though this base, it is said to be in stable equilibrium. \

Thus, option (b) is correct.

Final answer:

An object will be stable when its center of gravity lies over c. its base of support.

Explanation:

An object will be stable if its center of gravity lies over its base of support, which corresponds to option (b). Considering a person standing with feet narrowly-separated, they would be in a stable equilibrium to sideway displacements, as their center of gravity is above the base of support. However, even small displacements can make them unstable if it takes their center of gravity outside the base.

Therefore, enhanced stability can be achieved by lowering the center of gravity or expanding the base by spreading the feet farther apart. Furthermore, using a support device such as a cane increases stability by broadening the base of support. These principles are crucial in understanding why, for instance, children learning to walk experience more instability due to their higher center of gravity positioned between their shoulders.

In the double-slit experiment with electrons, the electrons arrive at the screen in a
A. Wave-like way with a pattern that is particle-like
B. Wave-like way with a pattern that is wave-like
C. Particle-like way with a pattern that is particle-like
D. Particle-like way with a pattern that is wave-like

Answers

Answer:

B. Wave-like way with a pattern that is wave-like

Explanation:

The double slit experiment when performed with electromagnetic waves, gives a pattern of light lines and dark areas, equally spaced.

In the case of electrons we must use Broglie's duality principle that states that all things have the characteristics of particles and waves together. The characteristic observed in a given experiment depends on the type of experiment, using the relationship

          p = h /λ

Where p is the amount of motion of the particle and λ the wavelength associated with this particle

In consequence of the previous one to the screen it should arrive as a wave with a wave type pattern

Let's review the answer.

A) False. The pattern is wave type

B) True. The whole process is with undulating characteristics

C) False. A wave arrives

D) False. A wave arrives

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