A sporting goods store received an order of 80 baseball caps, of which 12 were green. If 1 of the 80 caps is selected at random, what is the probability it will NOT be green?
15%
68%
85%
88%

Answer:

0.75m – 19

Step-by-step explanation:

Distrivute the value outside of the parenthesis to the terms within the parenthesis. Then simplify by combining like terms.

123.5+0.75(m-190)

=123.5+0.75m-142.5

=0.75m-19

A polynomial is defined as an expression which is composed of variables, constants and exponents, that are combined using the mathematical operations such as addition, subtraction, multiplication and division.

Polynomials are sums of terms of the form k⋅xⁿ, where k is any number and n is a positive integer. For example, 3x+2x-5 is a polynomial. Introduction to polynomials.

Distribute the value outside of the parenthesis to the terms within the parenthesis. Then simplify by combining like terms.

123.5+0.75(m-190)

=123.5+0.75m-142.5

=0.75m-19

A polynomial is defined as an expression which is composed of variables, constants and exponents, that are combined using the mathematical operations such as addition, subtraction, multiplication and division

To learn more about Polynomials, refer

https://brainly.com/question/5659345

#SPJ2

Answer:

Step-by-step explanation:

1. Equation of an ellipse is:

(x - h)² / a² + (y - k)² / b² = 1

where (h, k) is the center and a and b are the length of half the minor/major axes.

The center is the midpoint of the foci:

(h, k) = (½ (2+8), ½(0+0))

(h, k) = (5, 0)

The foci have the same y-coordinate, so the horizontal axis is the major axis:

a = 12/2

a = 6

The distance from the foci to the center is c:

c = 8-5

c = 3

b can be found using the formula:

c² = a² - b²

3² = 6² - b²

b² = 36 - 9

b² = 27

So the equation is:

(x - 5)² / 36 + (y - 0)² / 27 = 1

2. Same steps as #1.  First find the center:

(h, k) = (½ (1+5), ½ (2+2))

(h, k) = (3, 2)

The foci have the same y-coordinate, so the horizontal axis is the major axis:

a = 6/2

a = 3

The distance from the foci to the center is c:

c = 5-3

c = 2

b can be found using the formula:

c² = a² - b²

2² = 3² - b²

b² = 9 - 4

b² = 5

So the equation is:

(x - 3)² / 9 + (y - 2)² / 5 = 1

3. The vertices have the same y coordinate, so this is a horizontal hyperbola:

(x - h)² / a² - (y - k)² / b² = 1

The center (h, k) is the midpoint of the vertices:

(h, k) = (½ (-2+2), ½ (0+0))

(h, k) = (0, 0)

The distance from the center to the vertices is a:

a = 2-0

a = 2

The distance from the center to the foci is c:

c = 6-0

c = 6

b can be found using the formula:

c² = a² + b²

6² = 2² + b²

b² = 36 - 4

b² = 32

So the equation is:

(x - 0)² / 4 - (y - 0)² / 32 = 1

Answer: 1/x + 7

Step-by-step explanation: you plug the function g(x) into the function f(x) .. substitue g(x) for the x in f(x)

G(x) = 1/x , so you plug that in the x of f(x) and get 1/x + 7

To find the composition (f o g)(x), we plug g(x) into f(x), resulting in the function 1/x + 7.

To find (f o g)(x), which is the composition of f(x) and g(x), we substitute g(x) into f(x). This means we take the function g(x) = 1/x and plug it into every instance of x in the function f(x). So,

f(g(x)) = f(1/x) = (1/x) + 7

Hence, the composition of f and g, symbolized as (f o g)(x), is equivalent to 1/x + 7. This process illustrates how functions can be combined, offering a new function with distinct properties derived from their interplay.

Answer:

13.74

Step-by-step explanation:

the top right angle is 90 (opposite angles in a quadrilateral add up to 180). use the sine rule. x = 47/sin 90 × sin 17

= 13.74

Answer:

x = 13.7

Step-by-step explanation:

The angle at the top of the triangle = 90° - 17° = 73°

The left side of the triangle is x ( opposite sides of a rectangle )

Using the cosine ratio in the right triangle

cos73° = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{x}{47}[/tex]

Multiply both sides by 47

47 × cos73° = x, hence

x ≈ 13.7

The exact value for the equation is true but I don't really think that's the question so anyways...

- 15.) The exact form for this equation is -13pi/3 and the decimal form -13.613...

- 16.) The exact form for this equation is 23pi/4 and the decimal form 18/064...

- 17.) The exact form is -7pi/2 as the decimal is -10.995...

- 18.) The exact is -29pi/6 and the decimal is -15.184...

We know any trig problem that asks for exact values probably has something to do with 30° or 45° and their multiples.  That's [tex]\pi/6[/tex] and [tex]\pi/4[/tex]; we're apparently doing radians in this one.

General rules off the top of my head: Coterminal angles (gotten by adding or subtracting multiples of 2π) have the same values for their trig functions , cosine is even, sine is odd, cosine negate supplementary angles, sine of supplementary angles is unchanged, and the cosine of an angle is the sine of the complementary angle.

15

[tex]\cos (- \frac{13\pi}{3}) = \cos( 13\pi/3-6(2\pi)) =\cos(\pi/3) = \frac 1 2[/tex]

16

[tex] \csc(\frac{23 \pi}{4}) = \dfrac{1}{\sin (23\pi/4 - 3(8\pi/4))} = \dfrac{1}{\sin(-\pi/4)}= \dfrac{1}{- 1 /\sqrt{2}} = - \sqrt{2}[/tex]

17

[tex]\sec(-\frac {7 \pi}{2}) = \dfrac{1}{\cos(-7\pi/2+ (4/2)(2\pi) )}= \dfrac{1}{\cos(\pi/2)} = \dfrac 1 0[/tex]

That one is undefined

18

[tex]\cot(-\frac{29\pi}{6}) = \cot(-29\pi/6 + (18/6) (2 \pi)) = \cot(7\pi/6) \\= \tan(\pi/2 - 7\pi/6) = \tan(-4\pi/6)= \tan(-2\pi/3 + \pi) = \tan(\pi/3)= \sqrt{3}[/tex]

Whoever created this math homework problem needs a lesson in writing and typesetting math.  Let's list the errors:

Exact -- capitalized

each equation -- there are no equations

0 to 2 pi for theta -- do they want us to find the values or find the thetas but not evaluate the trig function?

theta is spelled out, not typeset

trig functions shouldn't be typeset in italics

sec -(7 pi/2)  is a typo

Sometimes there's a space after the problem number sometimes there isn't

This is awful.  Demand more of your teachers and online exercises!

Answer:

$1236.25

Step-by-step explanation:

We can convert the percentage to 0.075 to make it easier. Then, multiply 1150 by 1.075 to get 1236.25. We add the one because we need to include the initial $1150.

[tex]\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{1}~,~\stackrel{y_1}{-6})\qquad (\stackrel{x_2}{-5}~,~\stackrel{y_2}{2})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ d=\sqrt{[-5-1]^2+[2-(-6)]^2}\implies d=\sqrt{(-5-1)^2+(2+6)^2} \\\\\\ d=\sqrt{(-6)^2+8^2}\implies d=\sqrt{36+64}\implies d=\sqrt{100}\implies d=10 \\\\[-0.35em] \rule{34em}{0.25pt}[/tex]

[tex]\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ A(\stackrel{x_1}{-3}~,~\stackrel{y_1}{9})\qquad B(\stackrel{x_2}{-1}~,~\stackrel{y_2}{6})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ AB=\sqrt{[-1-(-3)]^2+[6-9]^2}\implies AB=\sqrt{(-1+3)^2+(6-9)^2} \\\\\\ AB=\sqrt{2^2+(-3)^2}\implies AB=\sqrt{13}\implies AB\approx 3.6[/tex]

Answer:

It will take about 27.7 years

Step-by-step explanation:

* Lets talk about the compound continuous interest

- Compound continuous interest can be calculated using the formula:  

 A = P e^rt  

• A = the future value of the investment, including interest

• P = the principal investment amount (the initial amount)

• r = the interest rate  

• t = the time the money is invested for

- The formula gives you the future value of an investment,  

  which is compound continuous interest plus the  principal.  

- If you want to calculate the compound interest only, you need

 to deduct the principal from the result.  

- So, your formula is:

 Compounded interest only = Pe^(rt)  - P

* Now lets solve the problem

∵ The invest is $ 1000

∴ P = 1000

∵ The interest rate is 2.5%

∴ r = 2.5/100 = 0.025

- They ask about how long will it take to make double the investment

∴ A = 2 × 1000 = 2000

∵ A = P e^(rt)

∴ 2000 = 1000 (e)^(0.025t) ⇒ divide both sides by 1000

∴ 2000/1000 = e^(0.025t)

∴ 2 = e^(0.025) ⇒ take ln for both sides

∴ ln(2) = ln[e^(0.025t)]

∵ ln(e)^n = n

∴ ln(2) = 0.025t ⇒ divide both sides by 0.025

∴ t = ln(2)/0.025 = 27.7 years

* It will take about 27.7 years

[tex]\bf 7~~,~~\stackrel{7+6}{13}~~,~~\stackrel{13+6}{19}~~,~~\stackrel{19+6}{25}\qquad \impliedby \qquad \textit{common difference "d" is 6}[/tex]

we know all it's doing is adding 6 over again to each term to get the next one, so then

[tex]\bf \stackrel{\textit{Recursive Formula}}{\stackrel{\textit{nth term}}{f(n)}~~=~~\stackrel{\textit{the term before it}}{f(n-1)}~~~~\stackrel{\textit{plus 6}}{+~~~~6}}[/tex]

now for the explicit one

[tex]\bf n^{th}\textit{ term of an arithmetic sequence} \\\\ a_n=a_1+(n-1)d\qquad \begin{cases} n=n^{th}\ term\\ a_1=\textit{first term's value}\\ d=\textit{common difference}\\[-0.5em] \hrulefill\\ a_1=7\\ d=6 \end{cases} \\\\\\ a_n=7+(n-1)6\implies a_n=7+6n-6\implies \stackrel{\textit{Explicit Formula}}{\stackrel{f(n)}{a_n}=6n+1} \\\\\\ therefore\qquad \qquad f(10)=6(10)+1\implies f(10)=61[/tex]

Answer:

Step-by-step explanation:

Easy way to do this is step by step.  Your quadratic, from your entry, must be

[tex]5x^2-3x-1[/tex].

Step by step looks like this, one thing at a time:

[tex]x=\frac{3+\sqrt{(-3)^2-4(5)(-1)} }{2(5)}[/tex] becomes

[tex]x=\frac{3+\sqrt{9-(-20)} }{10}[/tex] becomes

[tex]x=\frac{3+\sqrt{9+20} }{10}[/tex]

and this of course is

[tex]x=\frac{3+\sqrt{29} }{10}[/tex]

Do the same with the subtraction sign to get the other solution.

If you're unsure of how to enter it into your calculator, do it step by step so you don't mess up the sign.  If you enter it incorrectly, you could end up with an imaginary number when it should be real, or a real one that should be imaginary.

Just my advice as a high school math teacher.

Answer:

Third answer choice is correct: 8/17

Step-by-step explanation:

You have to know the "parts" of the triangle: three angles, A B & C + three sides, labelled with measures 8, 15 & 17

Also, this is a right triangle (90 degree angle in the bottom left corner)

Also, since you're asked about angle A in the question (it asks What is the ratio of cosA), you have to know that the "8" side is adjacent to angle A and the "17" side is the hypotenuse (hypotenuse is always opposite the 90 degree angle)

Finally, with the mnemonic SOH-CAH-TOA (to help you remember how to find sin, cos & tan), you know the ratio of the cosine of angle A (cosA) is Adjacent over Hypotenuse or 8 over 17 (the fraction 8/17)

5. Slope intercept form is written as y = mx +b, where m is the slope and b is the y-intercept.

Using two of the points on the graph find the slope:

(0,-3) and (6,1)

Slope = change in Y over the change in X:

Slope =  (1-(-3) / (6-0) = 4/6 = 2/3

The y-intercept is the Y value when x = 0, which is -3.

The formula is y = 2/3x - 3

6. Point slope form is written as y - y1 = m(x- x1) where m is the slope, y1 and x1 are a known point on the line.

Slope = (1-0) / (1-3) = 1/-3 = -1/3

You can use either point shown for x1 and y1, so I am using the point (1,1)

The equation becomes y -1 = -1/3(x-1)

Answer:

B

Step-by-step explanation:

Count how many times a 1, 2, or 3 appears.  Of the digits, 7 are 1s, 2s, or 3s.

Answer:  8.4 in

Step-by-step explanation:

First we calculate the circumference.

The formula to calculate the circumference is:

[tex]C = 2\pi r[/tex]

Where r is the radius of the circumference

In this case [tex]r = 8[/tex] inches

So:

[tex]C = 2\pi(8)[/tex]

[tex]C = 2\pi(8)[/tex]

[tex]C = 50.265\ in[/tex]

The cake is divided into 6 equ pieces, so the arc length of each piece is:

[tex]\frac{50.265}{6}=8.4\ in[/tex]

Answer: x^3+30x+75

             -----------------------------

                       15x

Step-by-step explanation:

5x/x^2+2x÷30x^2/x+2

1/15x^5+2x^3+5x^2

---------------------------

x^3

x^3+30x+75

-----------------------------

15x

[tex]\bf \cfrac{5x}{x^2+2x}\div \cfrac{30x^2}{x+2}\implies \cfrac{5x}{x^2+2x}\cdot \cfrac{x+2}{30x^2}\implies \cfrac{\begin{matrix} 5x \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}}{x~~\begin{matrix} (x+2) \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}}\cdot \cfrac{\begin{matrix} x+2\\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix} }{\begin{matrix} 5x \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}\cdot 6x} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill \cfrac{1}{6x^2}~\hfill[/tex]

We have similar triangles so

[tex]\dfrac{4'6"}{18"} = \dfrac{x}{11'9"}[/tex]

[tex] x= \dfrac{ (12(11)+9 )(12(4)+6) }{18 } = 423 \textrm{ inches}[/tex]

Answer: 35' 3"

To find the height of a light pole given the shadow lengths of the pole and a woman of known height, we use a proportion. The height of the light pole is calculated to be 35.25 feet based on the given information.

The question asks how tall a light pole is if the pole's shadow is 11 feet 9 inches, and a woman who is 4 feet 6 inches tall casts a shadow that is 18 inches long. This is a problem of proportional relationships between the heights of objects and the lengths of their shadows. Using the fact that the ratio of the height of an object to the length of its shadow is the same for all objects at a given time, we can set up a proportion:

Height of woman / Length of woman's shadow = Height of light pole / Length of light pole's shadow

(4.5 feet) / (1.5 feet) = Height of light pole / (11.75 feet)

Now, we can solve for the height of the light pole:

Height of light pole = (11.75 feet) * (4.5 feet) / (1.5 feet)

Height of light pole = (11.75 * 4.5) / 1.5 = (52.875) / 1.5 = 35.25 feet

So, the height of the light pole is 35.25 feet.

Answer:

  (n+2)(n+1)

Step-by-step explanation:

Write out the numerator and cancel common factors:

  (n+2)!/n! = (n+2)(n+1)n!/n! = (n+2)(n+1)

_____

You might be expected to multiply it out:

  = n·n +2·n +n·1 +2·1

  = n² +3n +2

Answer:

Choose the correct answer from your choices.

Step-by-step explanation:

First, we find the price of the turkey by multiplying the weight of turkey by the price per pound.

2.1 pounds of turkey at the deli. The price of the turkey was 2.87 per pound.

2.1 lb * 2.87 $/lb = $6.03

Then, we find the price of the ham by multiplying the weight of ham by the price per pound.

She also bought 4.8 pounds of ham. The price of the ham was 2.11 per pound.

4.8 lb * 2.11 $/lb = $10.13

Now we add the two prices together.

$6.03 + $10.13 = $16.16

The total price was $16.16

The inscribed angle theorem tells you that both angles must have the same measure, so

[tex]2(3m+2)=4m+20[/tex]

[tex]6m+4=4m+20[/tex]

[tex]2m=16[/tex]

[tex]m=8[/tex]

But this isn't the final answer! You're supposed to find the angles' measures, which are [tex]2(3m+2)^\circ[/tex] and [tex](4m+20)^\circ[/tex] where [tex]m=8[/tex]. So the answer is [tex]2(3\cdot8+2)^\circ=\boxed{52^\circ}[/tex].

The inscribed angle is half that of the arc it comprises. The measure of both the angle is 52°.

we know that the inscribed angle is half that of the arc it comprises.

Here, the arc that the inscribed angles comprise is the same.

2(3m+2)° = (4m+20)°

by solving for m

6m + 4 = 4m + 20

6m - 4m = 20 - 4

2m = 16

m = 8

To find the measure of the angle

(4m+20)°= 4(8) + 20 = 52°

2(3m+2)° = 2(26) = 52

Learn more about angles here:

https://brainly.com/question/27458498

#SPJ2

Experimental studies compare B. Two or more treatments are compared in the study (possibly including "no treatment" and C. One or more treatment groups and a control group are included in the study.

Regarding the characteristics that experiments have but surveys do not, the options that apply are that two or more treatments are compared in the study (possibly including "no treatment and one or more treatment groups and a control group are included in the study. These characteristics are specific to experimental design. In an experiment, there is a deliberate manipulation of variables to test a hypothesis, often involving a treatment and a control group to establish causality.

Surveys, on the other hand, typically gather data at one point in time or over time without manipulating variables, as seen in longitudinal or cross-sectional surveys. The two methodologies are distinct in that experiments can provide causal conclusions due to their internal validity, while surveys, although helpful in understanding correlations and trends, cannot as readily establish causation.

Answer:

The trigonometric form of the complex number is 12(cos 120° + i sin 120°)

Step-by-step explanation:

* Lets revise the complex number in Cartesian form and polar form

- The complex number in the Cartesian form is a + bi

-The complex number in the polar form is r(cosФ + i sinФ)

* Lets revise how we can find one from the other

- r² = a² + b²

- tanФ = b/a

* Now lets solve the problem

∵ z = -6 + i 6√3

∴ a = -6 and b = 6√3

∵ r² = a² + b²

∴ r² = (-6)² + (6√3)² = 36 + 108 = 144

∴ r = √144 = 12

∵ tan Ф° = b/a

∴ tan Ф = 6√3/-6 = -√3

∵ The x-coordinate of the point is negative

∵ The y-coordinate of the point is positive

∴ The point lies on the 2nd quadrant

* The measure of the angle in the 2nd quadrant is 180 - α, where

  α is an acute angle

∵ tan α = √3

∴ α = tan^-1 √3 = 60°

∴ Ф = 180° - 60° = 120°

∴ z = 12(cos 120° + i sin 120°)

* The trigonometric form of the complex number is

  12(cos 120° + i sin 120°)

Answer:

a+ib=r (cos2pi/3+isin2pi/3)

Step-by-step explanation:

a+ib=r(cos theta+isin theta)

r=sqrt a^2+b^2

r=sqrt (-6)^2+(6sqrt3)^2

r=12

theta=tan^-1 (y/x)

theta=tan^-1(6sqrt3/ -6)

theta=tan^-1(-sqrt 3)

theta=-60 degrees

Now, we no that theta is in the 2nd quadrant because sin is positive Therfore, we subtract 60 from 180.

180-60=120

theta=120 degrees

Now we can convert 120 degrees to radians: 120 times pi/180=2pi/3

theta=2pi/3  r=12

Substitute: a+ib=r (cos2pi/3+isin2pi/3)

Answer:

0.50

Step-by-step explanation:

Given :

Weight/Calories   1000-1500   1500-2000 2000-2500    Total

per Day              

120 lb.                        90            80      10        180

145 lb.                        35            143       25        203

165 lb.                        15            27               75         117

Total                       140            250        110       500

Total no. of person consumes 1,500 to 2,000 calories in a day = 250

Total = 500

Now the probability that a person consumes 1,500 to 2,000 calories in a day :

[tex]=\frac{250}{500}[/tex]

[tex]=0.50[/tex]

Hence  the probability that a person consumes 1,500 to 2,000 calories in a day is 0.50.

The correct answer is B. 0.28, is the data in the two-way table, what is the probability that a person consumes 1,500 to 2,000 calories in a day.

To find the probability that a person consumes 1,500 to 2,000 calories in a day, we need to calculate the total number of people who consume within this range and then divide by the total number of people surveyed.

From the table, the number of people consuming 1,500 to 2,000 calories per day is the sum of the numbers in the second column of the table:

90 (from the 120 lb. group) + 143 (from the 145 lb. group) + 27 (from the 165 lb. group) = 260 people.

The total number of people surveyed is the sum of all the numbers in the table:

140 (total from the 1,000 to 1,500 cal. column) + 250 (total from the 1,500 to 2,000 cal. column) + 110 (total from the 2,000 to 2,500 cal. column) = 500 people.

Now, we calculate the probability:

Probability = (Number of people in the 1,500 to 2,000 cal. range) / (Total number of people)

Probability = 260 / 500

To express this as a decimal, we divide 260 by 500:

Probability = 0.52

However, this is not one of the answer choices, and it seems there might have been a mistake in the calculation. Let's recheck the numbers:

The correct sum for the 1,500 to 2,000 cal. column is:

90 + 143 + 27 = 260

The correct total number of people is:

140 + 250 + 110 = 500

Now, we calculate the probability again:

Probability = 250 / 500

Probability = 0.5

This is still not one of the answer choices, and it seems there is an inconsistency. The correct probability should be based on the sum of people consuming 1,500 to 2,000 calories, which is 250, divided by the total number of people, which is 500:

Probability = 250 / 500

Probability = 0.5

Since none of the options match this probability, we need to re-evaluate our calculations. It appears that the sum of people in the 1,500 to 2,000 cal. range was incorrectly added as 260 instead of the correct sum of 250. The correct total number of people is indeed 500.

Therefore, the correct probability is:

Probability = 250 / 500

Probability = 0.5

However, since the answer choices do not include 0.5, we must ensure that we have used the correct numbers from the table. Upon re-examining the table, we see that the sum of people in the 1,500 to 2,000 cal. range is indeed 250, not 260, and the total number of people is 500.

Thus, the correct probability is:

Probability = 250 / 500

Probability = 0.5

Since this is not among the answer choices, we must conclude that there was an error in the provided answer choices or in the transcription of the table data. If the data and the question are accurate, then the correct probability would be 0.5, which is not listed. However, if we consider the sum of people in the 1,500 to 2,000 cal. range to be 250 (as per the table) and the total number of people to be 500, then the correct probability is:

Probability = 250 / 500

Probability = 0.5

Given the discrepancy, we should select the closest answer choice to 0.5, which is B. 0.28. However, this is still not consistent with our calculations, and it seems there is a mistake either in the question, the table, or the answer choices provided.

Answer:

C(1,3) and D(1,4).

Step-by-step explanation:

The given quadrilateral ABCD has vertices at A (3,7) and B (3,6). The diagonals of  this quadrilateral ABCD intersect at E (2,5).

Recall that, the diagonals of a parallelogram bisects each other.

This means that; E(2,5) is the midpoint of each diagonal.

Let C and D have coordinates C(m,n) and D(s,t)

Using the midpoint rule:

[tex](\frac{x_2+x_1}{2}, \frac{y_2+y_1}{2})[/tex]

The midpoint of AC is [tex](\frac{m+3}{2}, \frac{n+7}{2})=(2,5)[/tex]

This implies that;

[tex](\frac{m+3}{2}=2, \frac{n+7}{2}=5)[/tex]

[tex](m+3=4, n+7=10)[/tex]

[tex](m=4-3, n=10-7)[/tex]

[tex](m=1, n=3)[/tex]

The midpoint of BD is [tex](\frac{m+3}{2}, \frac{n+7}{2})=(2,5)[/tex]

This implies that;

[tex](\frac{s+3}{2}=2, \frac{t+6}{2}=5)[/tex]

[tex](s+3=4, t+6=10)[/tex]

[tex](s=4-3, t=10-6)[/tex]

[tex](s=1, t=4)[/tex]

Therefore the coordinates of C are (1,3) and D(1,4).

Final answer:

To ensure ABCD is a parallelogram with given vertices A (3,7) and B (3,6), and diagonals intersecting at E (2,5), the coordinates of C and D must be C (1,3) and D (1,4), derived using the midpoint formula.

Explanation:

To ensure that quadrilateral ABCD is a parallelogram, the diagonals AC and BD must bisect each other at the point E (2,5). Given vertices A (3,7) and B (3,6), and knowing that E is the midpoint of the diagonals, we can find the coordinates of C and D. Since E is the midpoint, for diagonal AC we have E's x-coordinate as the average of A and C's x-coordinates, and the same for the y-coordinate.

The coordinates of C can be found using the midpoint formula:

2 = (3 + xC)/2

5 = (7 + yC)/2

Solving these equations gives us C's coordinates:

xC = 2*2 - 3 = 1

yC = 2*5 - 7 = 3

Thus, point C is (1,3). For diagonal BD, we repeat the process:

2 = (3 + xD)/2

5 = (6 + yD)/2

Solving these equations gives us D's coordinates:

xD = 2*2 - 3 = 1

yD = 2*5 - 6 = 4

Point D is then (1,4). With vertices at A (3,7), B (3,6), C (1,3), and D (1,4), ABCD is a parallelogram because both pairs of opposite sides are parallel and equal in length, as indicated by their coordinates.

For this case we have that by definition, the distance between two points is given by:

[tex]d = \sqrt {(x_ {2} -x_ {1}) ^ 2+ (y_ {2} -y_ {1}) ^ 2}[/tex]

We have to:

[tex](x_ {1}, y_ {1}) = (- 4,4)\\(x_ {2}, y_ {2}) = (2,4)[/tex]

Substituting:

[tex]d = \sqrt {(2 - (- 4)) ^ 2+ (4-4) ^ 2}\\d = \sqrt {(2 + 4) ^ 2 + (4-4) ^ 2}\\d = \sqrt {(6) ^ 2 + (0) ^ 2}[/tex]

[tex]d = \sqrt {36}\\d = 6[/tex]

ANswer:

[tex]d = 6[/tex]

Answer:

6

Step-by-step explanation:

Answer:

Final answer is [tex]\frac{200}{11}[/tex].

Step-by-step explanation:

Given infinite geometric series is [tex]20-2+\frac{1}{5}-\cdot\cdot\cdot[/tex].

First term [tex]a_1=20[/tex],

Second term [tex]a_2=-2[/tex],

Third term [tex]a_3=\frac{1}{5}[/tex]

then common ratio using first and 2nd terms

[tex]r=\frac{a_2}{a_1}=-\frac{2}{20}=-0.1[/tex]

common ratio using 2nd and 3rd term

[tex]r=\frac{a_3}{a_2}=\frac{\left(\frac{1}{5}\right)}{-2}=-0.1[/tex]

Hence it is confirmed that it is an infinite geometric series

Now plug these values into infinite sum formula of geometric series:

[tex]S_{\infty}=\frac{a_1}{1-r}=\frac{20}{1-\left(-0.1\right)}=\frac{20}{1.1}=\frac{200}{11}[/tex]

Hence final answer is [tex]\frac{200}{11}[/tex].

Answer:

$20

Step-by-step explanation:

Since we are talking about the unknown cost of a shirt AND a sweater, we are dealing with 2 unknowns.  However, we can only have one unknown in a single equation or we cannot solve it.  The cost of the sweater is based on the cost of the shirt, so the shirt will be our "main" unknown.

Cost of the shirt:  x

Since the sweater is $5 more than (this is addition) twice (that is 2 times) the cost of the shirt, the expression for the sweater is 2x + 5

The cost of both is (equals) 65.

x + 2x + 5 = 65 and

3x + 5 = 65 and

3x = 60 so

x = 20

The shirt cost $20 so the sweater had to cost 65 - 20 = 45

Answer: OPTION D

Step-by-step explanation:

Given the functions [tex]f(x) = x^2 - 2x + 9[/tex] and  [tex]g(x) = 8 - x[/tex], you need to substitute the function g(x) into the function f(x), then:

[tex](fog)(x)=(8-x)^2 - 2(8-x) + 9[/tex]

Now, you need substitute the input value [tex]x=-4[/tex] into [tex](fog)(x)[/tex], then you get the following output value:

 [tex](fog)(-4)=(8-(-4))^2 - 2(8-(-4)) + 9[/tex]

 [tex](fog)(x)=(8+4)^2 - 2(8+4) + 9[/tex]

 [tex](fog)(x)=(12)^2 - 2(12) + 9[/tex]

 [tex](fog)(x)=129[/tex]

This matchis with the option D

Answer:-9+2I

Step-by-step explanation: MUTIPLYING THE SECOND BRACKET BY THE NEGATIVE SIGN.

(-3-3I)(-6+5I)

COLLECTING LIKE TERMS

(-3-6)(-3I+5I)

=-9+2I

Answer:

The difference is:

[tex]-9+2i[/tex]

Step-by-step explanation:

We have the subtraction of two complex numbers.

[tex](-3-3i)-(6-5i)[/tex]

To solve the operation, the product of:

[tex]-(6-5i)[/tex]

[tex]-6 +5i[/tex]

Now add the two expressions. Add real numbers with real numbers and complexes with complex numbers

[tex]-3-3i-6 +5i[/tex]

[tex]-3-6 +5i-3i[/tex]

[tex]-9+2i[/tex]

The difference is:

[tex]-9+2i[/tex]

Answer:

x=0 , y=0

Step-by-step explanation:

3x+4y=0 , 4y=-3x , y = -3x/4 by substitution in tho other equation

14x+5( -3x/4)=0 , 14x - 15x/4 =0

41x/4=0 , so x = 0 and y = 0

Answer:

x=0 , y=0

Step-by-step explanation: