To find the probability of choosing a red card we need to add both the cards so we have a total amount of cards.
17 + 9 = 26
Since, the question is asking the probability of choosing a RED card then the probability is a 17/26 chance. The answer choices are written as ratios. The ratio that is the same to 17/26 is [ D. 17:26 ]
Best of Luck!
749/d ∙ d/749=1
what does D equal?
Final answer:
To find the value of d in the equation 749/d ∙ d/749 = 1, we can simplify the equation and solve for d. Canceling out the like terms and cross multiplying leads us to the solution: d = 1.
Explanation:
To find the value of d in the equation 749/d ∙ d/749 = 1, we need to simplify the equation and solve for d.
We can start by canceling out the like terms: 749 and d. Multiplying the numerators and denominators gives us:
(749/d) ∙ (d/749) = (749 ∙ d) / (d ∙ 749)
Since the two fractions are equal to 1, we can set up the equation:
(749 ∙ d) / (d ∙ 749) = 1
Next, we can cross multiply:
749 ∙ d = d ∙ 749
Now, we can divide both sides of the equation by 749:
d = d ∙ 749 / 749
Simplifying further:
d = 749 / 749
Finally, we arrive at the solution:
d = 1
arrange the cones in order from lease volume to greatest volume
cone with DIAMETER of 20 & height of 12
cone with DIAMETER of 18 & height of 10
cone with RADIUS of 10 & height of 9
cone with RADIUS of 11 & height of 9
Answer:
Volume of the cone in ascending order.
[tex]V_{2}=270\pi\ units^{3}<V_{3}=300\pi\ units^{3}<V_{4}=363\pi\ units^{3}<V_{1}=400\pi\ units^{3}[/tex]
cone with DIAMETER of 18 & height of 10
cone with RADIUS of 10 & height of 9
cone with RADIUS of 11 & height of 9
cone with DIAMETER of 20 & height of 12
Step-by-step explanation:
Let [tex]V_{2}. V_{3}. and\ V_{4}.[/tex] be the volume of the cone.
Let d, r and h be the diameter, radius and height of the cone.
Given:
[tex]d_{1} = 20\ and\ h_{1}=12[/tex]
[tex]d_{2} = 18\ and\ h_{2}=10[/tex]
[tex]r_{3} = 10\ and\ h_{3}=9[/tex]
[tex]r_{4} = 11\ and\ h_{14}=9[/tex]
Arrange the cones in order from lease volume to greatest volume.
Solution:
The volume of the cone is given below.
[tex]V=\pi r^{2} \frac{h}{3}[/tex]----------------(1)
where: r is radius of the base of cone.
and h is height of the cone.
The volume of the cone for [tex]d_{1} = 20\ and\ h_{1}=12[/tex]
[tex]r_{1} = \frac{d_{1}}{2}[/tex]
[tex]r_{1} = \frac{20}{2}=10\ units[/tex]
[tex]V_{1}=\pi (r_{1})^{2} \frac{h_{1}}{3}[/tex]
[tex]V_{1}=\pi (10)^{2} \frac{12}{3}[/tex]
[tex]V_{1}=\pi\times 100\times 4[/tex]
[tex]V_{1}=400\pi\ units^{3}[/tex]
Similarly, for volume of the cone for [tex]d_{2} = 18\ and\ h_{2}=10[/tex]
[tex]r_{2} = \frac{d_{2}}{2}[/tex]
[tex]r_{2} = \frac{18}{2}=9\ units[/tex]
[tex]V_{2}=\pi (r_{2})^{2} \frac{h_{2}}{3}[/tex]
[tex]V_{2}=\pi (9)^{2} \frac{10}{3}[/tex]
[tex]V_{2}=\pi\times 81\times \frac{10}{3}[/tex]
[tex]V_{2}=\pi\times 27\times 10[/tex]
[tex]V_{2}=270\pi\ units^{3}[/tex]
Similarly, for volume of the cone for [tex]r_{3} = 10\ and\ h_{3}=9[/tex]
[tex]V_{3}=\pi (r_{3})^{2} \frac{h_{3}}{3}[/tex]
[tex]V_{3}=\pi (10)^{2} \frac{9}{3}[/tex]
[tex]V_{3}=\pi\times 100\times 3[/tex]
[tex]V_{3}=\pi\times 300[/tex]
[tex]V_{3}=300\pi\ units^{3}[/tex]
Similarly, for volume of the cone for [tex]r_{4} = 11\ and\ h_{4}=9[/tex]
[tex]V_{4}=\pi (r_{4})^{2} \frac{h_{4}}{3}[/tex]
[tex]V_{4}=\pi (11)^{2} \frac{9}{3}[/tex]
[tex]V_{4}=\pi\times 121\times 3[/tex]
[tex]V_{4}=\pi\times 363[/tex]
[tex]V_{4}=363\pi\ units^{3}[/tex]
So, the volume of the cone in ascending order.
[tex]V_{2}=270\pi\ units^{3}<V_{3}=300\pi\ units^{3}<V_{4}=363\pi\ units^{3}<V_{1}=400\pi\ units^{3}[/tex]
a)) A 55 m long and 35 m broad park is surrounded by a 2.5 m wide
(i) Find the area of the path.
Answer:
Area of the path is 475 m².
Step-by-step explanation:
Let us first draw the diagram for the given question.
Here rectangle ABCD represents a park whose length is 55 m and breadth is 35 m. The shaded portion shows the path all around the park whose width is 2.5 m.
Now, length of rectangle ABCD, l = 55 m
breadth of rectangle ABCD, B = 35 m
Now, width of the path = 2.5 m
So, length of rectangle PQRS, L = 55 + 2.5 + 2.5 = 60 m
breadth of rectangle PQRS, B = 35 + 2.5 + 2.5 = 40 m
Now, to calculate the area of shaded portion or the area of the path, we will subtract the area of the park or area of rectangle ABCD from the area of rectangle PQRS.
Now, area of rectangle PQRS, A₁ = L × B = 60 × 40 = 2400 m²
Area of rectangle ABCD, A₂ = l × b = 55 × 35 = 1925 m²
So, area of the path = A₁ - A₂ = 2400 - 1925 = 475 m²
Hence the area of the path is 475 m².
Find the volume and area for the objects shown and answer Question
Step-by-step explanation:
You must write formulas regarding the volume and surface area of the given solids.
[tex]\bold{\#1\ Rectangular\ prism:}\\\\V=lwh\\SA=2lw+2lh+2wh=2(lw+lh+wh)\\\\\bold{\#2\ Cylinder:}\\\\V=\pi r^2h\\SA=2\pi r^2+2\pi rh=2\pir(r+h)\\\\\bold{\#3\ Sphere:}\\\\V=\dfrac{4}{3}\pi r^3\\SA=4\pi r^2[/tex]
[tex]\bold{\#4\ Cone:}\\\\V=\dfrac{1}{3}\pi r^2h\\\\\text{we need calculate the length of a slant length}\ l\\\text{use the Pythagorean theorem:}\\\\l^2=r^2+h^2\to l=\sqrt{r^2+h^2}\\\\SA=\pi r^2+\pi rl=\pi r^2+\pi r\sqrt{r^2+h^2}=\pi r(r+\sqrt{r^2+h^2})\\\\\bold{\#5\ Rectangular\ Pyramid:}\\\\V=\dfrac{1}{3}lwh\\\\[/tex]
[tex]\\\text{we need to calculate the height of two different side walls}\ h_1\ \text{and}\ h_2\\\text{use the Pythagorean theorem:}\\\\h_1^2=\left(\dfrac{l}{2}\right)^2+h^2\to h_1=\sqrt{\left(\dfrac{l}{2}\right)^2+h^2}=\sqrt{\dfrac{l^2}{4}+h^2}=\sqrt{\dfrac{l^2}{4}+\dfrac{4h^2}{4}}\\\\h_1=\sqrt{\dfrac{l^2+4h^2}{4}}=\dfrac{\sqrt{l^2+4h^2}}{\sqrt4}=\dfrac{\sqrt{l^2+4h^2}}{2}[/tex]
[tex]\\\\h_2^2=\left(\dfrac{w}{2}\right)^2+h^2\to h_2=\sqrt{\left(\dfrac{w}{2}\right)^2+h^2}=\sqrt{\dfrac{w^2}{4}+h^2}=\sqrt{\dfrac{w^2}{4}+\dfrac{4h^2}{4}}\\\\h_2=\sqrt{\dfrac{w^2+4h^2}{4}}=\dfrac{\sqrt{w^2+4h^2}}{\sqrt4}=\dfrac{\sqrt{w^2+4h^2}}{2}[/tex]
[tex]SA=lw+2\cdot\dfrac{lh_1}{2}+2\cdot\dfrac{wh_2}{2}\\\\SA=lw+2\!\!\!\!\diagup\cdot\dfrac{l\cdot\frac{\sqrt{l^2+4h^2}}{2}}{2\!\!\!\!\diagup}+2\!\!\!\!\diagup\cdot\dfrac{w\cdot\frac{\sqrt{w^2+4h^2}}{2}}{2\!\!\!\!\diagup}\\\\SA=lw+\dfrac{l\sqrt{l^2+4h^2}}{2}+\dfrac{w\sqrt{w^2+4h^2}}{2}\\\\SA=\dfrac{2lw}{2}+\dfrac{l\sqrt{l^2+4h^2}}{2}+\dfrac{w\sqrt{w^2+4h^2}}{2}\\\\SA=\dfrac{2lw+l\sqrt{l^2+4h^2}+w\sqrt{w^2+4h^2}}{2}[/tex]
will award brainliest Which of these is the algebraic expression for "five more than the product of ten and some number?" (3 points) 10 + 5x 5 + 10 + x 10x + 5 5 + 10 ÷ x
Find the altitude of a triangle whose area is 100 cm² and whose base is 20 cm.
Altitude = Cm.
Answer:
altitude = 10 cm
Step-by-step explanation:
Finding the altitude of triangle when area and base is given:
[tex]\sf \boxed{\text{\bf Area of triangle = $\dfrac{1}{2}*base*altitude$}}[/tex]
base = 20 cm
Area of a triangle = 100 sq.cm
[tex]\sf \dfrac{1}{2}*20*altitude = 100\\\\\\[/tex]
10 * altitude = 100
altitude = 100 ÷ 10
altitude = 10 cm
What’s the surface area of the right cone below? 8;15
Answer:
Circle the 15 in the diagram, that's the correct answer
Answer:
184π units²
Step-by-step explanation:
see attached for reference
given sloped height = 15 units
base radius = 8 units
the height of the cone can be found by using the Pythagorean equation
(sloped height)² = height ² + (base radius)²
15² = h² + 8²
h² = 15²-8² = 161
h = √161
Base surface area = πr² = π 8² = 64π units²
Lateral Surface Area,
= πr √(r² + h²)
= π(8) √[ (8)² + (√161)² ]
= 8π√(64 + 161)
= 8π√225
= 8π (15)
= 120π
Surface area = base area + lateral surface area
= 64π + 120π
= 184π units²
The graph of a proportional relationship contains the point (-30, 18)
What is the value of k for the relationship?
Enter your answer in the box as a fraction in simplest form
k=
Answer:
The answer is k = [tex]-\frac{3}{5}[/tex]
Explanation:
We know that
A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form [tex]k=\frac{y}{x}[/tex] or [tex]y=kx[/tex]
In a proportional relationship the constant of proportionality k is equal to the slope m of the line and the line passes through the origin
we have the point (-30,18)
so
x=-30, y=18
Find the value of k
[tex]k=\frac{y}{x}[/tex]
substitute
[tex]k=\frac{18}{-30}[/tex]
Simplify
Divide by 6 both numerator and denominator
[tex]k=- \frac{3}{5}[/tex]
Write a two column proof
Answer:
this photo should be it
Please help me! I will give brainliest and 50 points if all correct!
Answer:
10. ○[tex]\displaystyle 4,85; 4\frac{17}{20}[/tex]
9. ○680%
8. ○40%
7. ○[tex]\displaystyle 60[/tex]
6. ○0,4, 40,5%, 11⁄25, 4⁄9
5. ○[tex]\displaystyle 0,928[/tex]
4. ○1%
3. ○76%
2. [tex]\displaystyle See\:above\:grid[/tex]
1. [tex]\displaystyle See\:above\:grid[/tex]
Step-by-step explanation:
10. To convert from a percentage to a decimal, move the decimal mark twice to the left; each 20 is worth 5, and since 5 by 17 is 85, you have your fractional part of 17⁄20, then attach the whole number of 4.
9. To convert from a mixed number\improper fraction to a percentage, first evaluate the fractional part for a decimal answer, then move the decimal mark twice to the right.
8. To convert from a fraction to a percentage, evaluate the fraction for a decimal answer, then move the decimal mark twice to the right.
7. [tex]\displaystyle \frac{132}{220} = \frac{3}{5} =[/tex]60%
Greatest Common Divisor [GCD]: 44
6. [tex]\displaystyle \frac{11}{25} =[/tex]44%
_
[tex]\displaystyle \frac{4}{9} =[/tex]44,4%
[tex]\displaystyle 0,4 =[/tex]40%
Now that these are all percentages, it is alot easier to order them from least to greatest.
5. To convert from a percentage to a decimal, move the decimal mark twice to the left.
4. To convert from a decimal to a percentage, move the decimal mark twice to the right.
3. Each 25 is worth 4, and since 4 by 19 is 76, you get 76%.
2. Each 25 is worth 4, and since 4 by 6 is 24, you get 24%, and this graph.
1. Each 36 is worth 2 7⁄9, and since 12 by 2 7⁄9 is 33⅓, you get 33⅓%, so you would choose this answer.
I am joyous to assist you anytime.
Hellllllllppppppp!!!!!! Quick LIKE QUICK NOW!!!!!! 12 POINTS PLEASE
Answer:
Point T
Step-by-step explanation:
The only point that is right across from (-3,-5) is point T. If you reflect across the Y-axis, you get (3,-5)
the population of deer in a certain national park can be approximated by the function P(x)=150(1.07)^x, where x is the number of years since 1995. In which year will the population reach 300? Hint: an answer such as 2002.4 would represent the year 2002.
A.2026
B.2005
C.2038
D.2016
Answer:
b. 2005
Step-by-step explanation:
(apex)
300=150(1.07)^x
1.07^x=2
x=ln 2/ln 1.07
=10.24
1995 plus ten years = 2005
hope this helps
Answer:
B. 2005
Step-by-step explanation:
We have been given that population of deer in a certain national park can be approximated by the function [tex]P(x)=150(1.07)^x[/tex], where x is the number of years since 1995. We are asked to find the year in which population will reach 300.
To solve our given problem, we will equate [tex]P(x)=300[/tex] and solve for x as:
[tex]300=150(1.07)^x[/tex]
[tex]\frac{300}{150}=\frac{150(1.07)^x}{150}[/tex]
[tex]2=(1.07)^x[/tex]
Now, we will take natural log on both sides as:
[tex]\text{ln}(2)=\text{ln}((1.07)^x)[/tex]
[tex]\text{ln}(2)=x\text{ln}(1.07)[/tex]
[tex]x=\frac{\text{ln}(2)}{\text{ln}(1.07)}[/tex]
[tex]x=10.2447[/tex]
[tex]x\approx 10[/tex]
Now, we will find 10 years after 1995 that is [tex]1995+10=2005[/tex].
Therefore, the population will be 300 in year 2005 and option B is the correct choice.
PLEASE PLEASE HELP ME PLEASE
Which radical expressions are equivalent to
Answer:
D and E
Step-by-step explanation:
Using the rule of radicals
[tex]a^{\frac{m}{n} }[/tex] ⇔ [tex]\sqrt[n]{a^{m} }[/tex]
Given
[tex]3^{\frac{4}{7} }[/tex]
= ([tex]\sqrt[7]{3}[/tex])^4 → D or
= [tex]\sqrt[7]{3^{4} }[/tex] = [tex]\sqrt[7]{81}[/tex] → E
The sum of a number and -9 is -36. What is the number?
Solve for x in this equation.
x+(-9)=-36
x-9=-36
x=-27
answer: -27
How many squares will be in the 7th figure
Answer:
17
Step-by-step explanation:
Answer: 56
Step-by-step explanation:
difference goes up by 2 each time.
a school ordered 3 large boxes of board markers. After giving 15 markets to each of 3 teachers, there were 90 markers left. How many markers were originally in each box?
There were 45 markers originally in each box.
Step-by-step explanation:
Given,
Boxes ordered = 3 large boxes
Markers given to one teacher = 15
Markers given to 3 teachers = 15*3 = 45 markers
Remaining markers = 90
Let,
x be the original number of markers in 3 boxes.
Total markers - markers given to teachers = markers left
[tex]x-45=90\\x=90+45\\x=135[/tex]
There were 135 markers in 3 boxes.
3 boxes = 135 markers
1 box = [tex]\frac{135}{3}=45\ markers[/tex]
There were 45 markers originally in each box.
Keywords: multiplication, addition
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68. Solve: 46x - 10) = 8x + 40
A 0
B.5/2
ina
c. 23
D. 5
Solve: 4(6x - 10) = 8x + 40
A 0
B.5/2
c. 23
D. 5
Answer:Option D
The solution to given equation is x = 5
Solution:Given that we have to solve the given equation
4(6x - 10) = 8x + 40
Let us solve the above expression and find value of "x"
Multiplying 4 with terms inside bracket in L.H.S we get,
24x - 40 = 8x + 40
Move the variables to one side and constant terms to other side
24x - 8x = 40 + 40
Combine the like terms,
16x = 80
[tex]x = \frac{80}{16} = 5[/tex]
Thus solution to given equation is x = 5
Maine has a cold climate in the winter. Which statement about the probability of
temperatures falling below 32°F in Maine during the month of January is most likely true?
The probability cannot be determined before February
The probability is 100.
The probability could be -1.
The probability is closer to 1 than to 0.
Answer:
B. FOR SURE !!!
Step-by-step explanation:
Answer: B
Step-by-step explanation:
How does 6 x 3/4 compared to 6
Answer:
6*(3/4) is 75% of 6.
Step-by-step explanation:
3/4 =0.75
Consider this:
6*1 =6, so 1=100%.
6*1/2 =6*0.5=3, so 1/2=50%.
You can then see that 6*0.75=4.5 is 75% of 6.
4. An investment account pays 4.6%
annual interest compounded quarterly.
If $6050 is placed in this account, find
the balance after 6 years.
A. $6810.53
B. $7420.65
C. $7960.43
D. $8134.22
Answer:
Step-by-step explanation:
Use the formula
[tex]A(t)=P(1+\frac{r}{n})^{(n)(t)}[/tex]
where A(t) is the amount after all the compounding is done, P is the initial investment, r is the interest rate as a decimal, n is the number of times the investment is compounded each year, and t is time in years. For us,
P = 6050
r = .046
n = 4
t = 6
A(t) = ?
Filling in our given info:
[tex]A(t)=6050(1+\frac{.046}{4})^{(4)(6)}[/tex]
which simplifies to
[tex]A(t)=6050(1+.0115)^{24}[/tex]
which simplifies a bit more to
[tex]A(t)=6050(1.0115)^{24}[/tex] and
A(t) = 6050(1.31577397) so
A(t) = $7960.43
which is choice C
Final answer:
The balance after 6 years is $6810.53 that is option A is correct.
Explanation:
To find the balance after 6 years, we can use the formula for compound interest: A = P(1 + r/n)^(nt).
Given that the initial principal (P) is $6050, the interest rate (r) is 4.6% (or 0.046 in decimal form), and it is compounded quarterly (n=4 times per year), we can plug in the values and solve for A.
A = $6050(1 + 0.046/4)^(4*6) = $6810.53
Therefore, the balance after 6 years is $6810.53, which corresponds to answer choice A.
A surfboard has an original price of $259. It is on sale
for 55% off the original price. Find the sale price of
the surfboard.
Answer:
.45($259) = $116.55
The sale price of the surfboard is $116.55.
Solve the system of linear equations by graphing. y−x=17 y=4x+2
Answer:
x=5, y=22. (5, 22).
Step-by-step explanation:
y-x=17
y=4x+2
----------
4x+2-x=17
3x+2=17
3x=17-2
3x=15
x=15/3
x=5
y-5=17
y=17+5
y=22
Answer:
x = 5, y = 22 → (5, 22)Step-by-step explanation:
[tex]\left\{\begin{array}{ccc}y-x=17&(1)\\y=4x+2&(2)\end{array}\right\\\\\\\text{substitute (2) to (1):}\\\\(4x+2)-x=17\qquad\text{combine like terms}\\\\(4x-x)+2=17\qquad\text{subtract 2 from both isdes}\\\\3x+2-2=17-2\\\\3x=15\qquad\text{divide both sides by 3}\\\\\dfrac{3x}{3}=\dfrac{15}{3}\\\\x=5[/tex]
[tex]\text{Put the value of x to (2):}\\\\y=4(5)+2\\\\y=20+2\\\\y=22[/tex]
Write the number 393,234,000,034 in words.
Answer:
three hundred and ninety three billion, two hundred and thirty four million, and thirty four.
Step-by-step explanation:
billion is any digit that has seven to nine digits behind it
Answer:
Three hundred and ninety three billion, two hundred and thirty four million and thirty four.
Step-by-step explanation:
What is the solution to the system of equations?
y=5x+2
3x=-y + 10
(-4,-18)
(-18,-4)
(7,1)
(1,7)
Answer:
Y = 5x + 2 . . . . . . . . . . (1)
3x = -y + 10 . . . . . . . . (2)
3x = -(5x + 2) + 10
3x = -5x - 2 + 10
3x + 5x = -2 + 10
8x = 8
x = 1
y = 5(1) + 2 = 5 + 2 = 7
Solution is (1, 7)
Step-by-step explanation:
The Solution is (1,7) is the solution to the system of equations:
y=5x+2, 3x=-y + 10
What is simplification?Simplify simply means to make it simple. In mathematics, simply or simplification is reducing the expression/fraction/problem in a simpler form. It makes the problem easy with calculations and solving.
here, we have,
given that,
We need to find the solution of the system of following equations.
y= 5x + 2 eq(1)
3x = -y +10 eq(2)
We will solve the equations using Substitution method to find the values of x and y
we put value of y from eq (1) into eq (2), The eq(2) will be:
3x = - (5x + 2) + 10
3x = -5x -2 +10
3x+5x = -2+10
8x = 8
x= 1
Now, putting value of z in eq(1) to find value of y
y = 5x +2
y = 5(1) + 2
y = 5+2
y = 7
So, Solution is (1,7).
Hence, The Solution is (1,7) is the solution to the system of equations:
y=5x+2, 3x=-y + 10
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The Green Goober, a wildly unpopular superhero, mixes 333 liters of yellow paint with 555 liters of blue paint to make 888 liters of special green paint for his costume.
Write an equation that relates y, the amount of yellow paint in liters, and b, the amount of blue paint in liters, needed to make the Green Goober's special green paint.
PLEASE ANSWER!!!!!!!!!!!!!!!!!!!!!!!!!!
The equation that relates y, the amount of yellow paint in liters, and b, the amount of blue paint in liters, needed to make the Green Goober's special green paint is y + b = 888
Solution:
Given that the Green Goober mixes 333 liters of yellow paint with 555 liters of blue paint to make 888 liters of special green paint for his costume.
Let "y" be the amount of yellow paint in liters needed to make the Green Goober's special green paint
Let "b" be the amount of blue paint in liters needed to make the Green Goober's special green paint
The required equation is:
amount of yellow paint in liters + amount of blue paint in liters = Green Goober's special green paint
y + b = 888
Where y = 333 liters and b = 555 liters ( from given information)
Thus the equation is found
Answer:
y=3/5b
Step-by-step explanation:
Two congruent 30-60-90 triangles are placed,as shown,so that they overlap partly and their hypotenuses coincide. If the hypotenuse is 12 cm,find the area common to the both triangles.
The area common to both triangles is [tex]18\sqrt3[/tex] square centimeters.
In a 30-60-90 triangle, the ratio of the side lengths is [tex]1:\sqrt{3} :2[/tex]. Since the hypotenuse is 12 cm, we can determine the lengths of the other sides using this ratio.
The shorter leg (opposite the 30-degree angle) is (1/2) times the hypotenuse, which is (1/2) * 12 cm = 6 cm.
The longer leg (opposite the 60-degree angle) is [tex]\sqrt3[/tex] times the shorter leg, which is 6 * [tex]\sqrt{3[/tex] cm = [tex]6\sqrt3[/tex] cm.
Now, since the two triangles are congruent, the overlapping region forms an isosceles triangle with two sides measuring 6 cm (the shorter leg) and a base measuring [tex]6\sqrt3[/tex] cm (the longer leg).
The base of the isosceles triangle is [tex]6\sqrt3[/tex] cm, and since it's an isosceles triangle, the height is the same as the shorter leg, which is 6 cm.
Common Area = ([tex]6\sqrt3[/tex] cm * 6 cm) / 2 = [tex]36\sqrt3[/tex] cm² / 2 = [tex]18\sqrt3[/tex] cm².
Therefore, the area common to both triangles is [tex]18\sqrt3[/tex] square centimeters.
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The area common to both triangles is 144 square centimeters.
To find the area common to both triangles, we need to determine the overlapping region, which is a rhombus formed by the intersection of the two 30-60-90 triangles.
First, let's consider one of the 30-60-90 triangles. The sides of a 30-60-90 triangle are in the ratio 1:√3:2. In this case, the hypotenuse is 12 cm, so the sides of the triangle are:
Shorter leg (opposite the 30-degree angle) = 12 cm / 2 = 6 cm
Longer leg (opposite the 60-degree angle) = 6 cm * √3
Now, let's look at the overlapping region, which forms a rhombus. The diagonals of a rhombus are perpendicular bisectors of each other, so each diagonal will be twice the length of the shorter leg of the 30-60-90 triangle.
Diagonal of the rhombus = 2 * 6 cm = 12 cm
The area of a rhombus can be calculated using the formula: Area = (diagonal1 * diagonal2) / 2
In this case, both diagonals are equal (12 cm each), so the area of the rhombus (and hence the common area of the triangles) is:
Area = (12 cm * 12 cm) / 2
Area = 144 cm²
So, the area common to both triangles is 144 square centimeters.
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X= __________
Answer:
x-=13
Step-by-step explanation:
9x+2=119
subrtact 2 from both sides
9x=117
divide 9 from both sides
x=13
Answer: x=13
Step-by-step explanation:
Since alternate interior angles are congruent so
9x+2=119
9x=119-2
9x=117
x=117/9
x=13
what is 750x+150<1,000
Answer:
1.13 repeated
Step-by-step explanation:
Answer:
1 and 100 over 750
Step-by-step explanation:
You are given g(x)=4x^2 + 2x and
f(x) = the integral of g(t) from 0 to x.
How would you find f(6)?
Answer:
324
Step-by-step explanation:
Given:
[tex]g(x)=4x^2+2x\\ \\f(x)=\int\limits^x_0 {g(t)} \, dt[/tex]
Find:
[tex]f(6)[/tex]
First, find f(x):
[tex]f(x)\\ \\=\int\limits^x_0 {g(t)} \, dt\\ \\=\int\limits^x_0 {(4t^2+2t)} \, dt\\ \\=\left(4\cdot \dfrac{t^3}{3}+2\cdot \dfrac{t^2}{2}\right)\big|\limits^x_0\\ \\=\left(\dfrac{4t^3}{3}+t^2\right)\big|\limits^x_0\\ \\= \left(\dfrac{4x^3}{3}+x^2\right)-\left(\dfrac{4\cdot 0^3}{3}+0^2\right)\\ \\=\dfrac{4x^3}{3}+x^2[/tex]
Now,
[tex]f(6)\\ \\=\dfrac{4\cdot 6^3}{3}+6^2\\ \\=288+36\\ \\=324[/tex]
How many times will interest be added to the principal in one year if the
interest is compounded annually?
Answer:
Only 1 time
Step-by-step explanation:
When it is compound interest it can be added in the following ways:
Annually = 1 Time in a year
Semiannually = 2 Times in a year
Quarterly = 4 Times in a year
Monthly = 12 Times in a year
Answer:
2
Step-by-step explanation:
a.p.e.x