A system at equilibrium contains i2(g) at a pressure of 0.21 atm and i(g) at a pressure of 0.23 atm . the system is then compressed to half its volume. find the pressure of i when the system returns to equilibrium.

the big number describes the number ratio in a chemical equation

so for example,

2H2 + O2 --> 2H2O means

2 moles of hydrogen reacts with one mole of oxygen to form 2 moles of water

and as you know, the small (subscript) number determines the number of atoms of that element in one molecule of a compound

so I believe that drawing a normal lewis structure ( O=O ) should be correct

Explanation:

For what I understand in the question, the "big number" is called a stoichiometric coefficient and represents the ammount of molecules of the substance that follows it ( in this case O2) involved in a reaction.

In this case there is no reaction but it asks you for the lewis structure of two molecules of oxygen (O2).

The lewis structure of oxygen is: O=O

Two molecules of it can bond by london forces or dative unions forming what is known as a dimer (two molecules of the same substance bonded).

Final answer:

The pH of a 0.160 M ammonia solution can be calculated using the pOH method. The concentration of hydroxide ions in the solution is approximately 1.125 x 10^-4 M, resulting in a pOH of approximately 3.95. The pH of the solution is approximately 10.05.

Explanation:

The pH of a 0.160 M ammonia solution can be calculated using the pOH method. Ammonia is a weak base, so we can use the equation:
pOH = -log[OH-]
pH + pOH = 14

First, we need to find the concentration of hydroxide ions ([OH-]) in the solution. The Kb value for ammonia (NH3) is 1.8 x 10-5.
Given that [NH3] = 0.160 M, we can calculate [OH-] using the Kb expression:
Kb = [NH3][OH-] / [NH4+]
Since [NH4+] can be ignored in this dilute ammonia solution, the equation simplifies to:
Kb = [NH3][OH-].

Now, rearranging the equation to solve for [OH-], we get:
[OH-] = Kb / [NH3]
Substituting the given values into the equation:
[OH-] = (1.8 x 10-5) / (0.160)
[OH-] = 1.125 x 10-4 M

Next, we can calculate the pOH of the solution using the equation:
pOH = -log[OH-]
pOH = -log(1.125 x 10-4)
pOH ≈ 3.95

Finally, we can find the pH using the equation:
pH = 14 - pOH
pH = 14 - 3.95
pH ≈ 10.05

I don't know how 5°C cooled to 85°C but the answer would be 12.878L

Answer:

At constant pressure the new volume of gas is 12.878 L.

Explanation:

Charles's Law consists of the relationship between the volume and temperature of a certain amount of ideal gas, which is maintained at a constant pressure, by means of a proportionality constant that is applied directly. So the ratio between volume and temperature will always have the same value:

[tex]\frac{V}{T} =k[/tex]

where the temperature is expressed in degrees kelvin (° K)

Then, when considering the two situations 1 and 2, keeping the amount of gas and the temperature constant, the relationship must be met:

[tex]\frac{V1}{T1} =\frac{V2}{T2}[/tex]

In this case, you know:

Replacing:

[tex]\frac{10}{278} =\frac{V2}{358}[/tex]

Solving:

[tex]V2=\frac{10}{278} *358[/tex]

V2=12.878 L

At constant pressure the new volume of gas is 12.878 L.

Answer:

B. ethylamine.

Explanation:

So, the compound is ethylamine.

When an alkane is heated in the presence of chlorine gas, monochlorinated products can be formed.

These products can include stereoisomers. In the case of methane, there are four possible monochlorinated products including stereoisomers. The alkane is not specified in the question, but let's assume it is methane (CH4) as an example. When methane is heated in the presence of chlorine gas (Cl2), a substitution reaction occurs. One of the hydrogen atoms in methane can be replaced by a chlorine atom, resulting in a monochlorinated product. In this case, there are four possible monochlorinated products (CH3Cl, CH2Cl2, CHCl3, CCl4) including different stereoisomers.

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Answer:

5. ΔH = 238.7 kJ; 6 ΔH, = -1504.6 kJ

Step-by-step explanation:

Question 5:

We have three equations:  

(I)  CH₃OH + ³/₂O₂ ⟶ CO₂ + 2H₂O;  ΔH = -726.4 kJ

(II)  C + O₂ ⟶ CO₂;                              ΔH = -393.5 kJ

(III) H₂ + ½O₂ ⟶ H₂O;                         ΔH = -285.8 kJ

From these, we must devise the target equation:  

(IV) C + 2H₂ + ½ O₂ → CH₃OH; ΔH = ?  

The target equation has 1C on the left, so you rewrite Equation (II)..  

(V) C + O₂ ⟶ CO₂;                               ΔH = -393.5 kJ

Equation (V) has 1CO₂ on the right, and that is not in the target equation.  

You need an equation with ½O₂ on the left, so you reverse Equation (I).  

When you reverse an equation, you reverse the sign of its ΔH.  

(VI) CO₂ + 2H₂O ⟶ CH₃OH + ³/₂O₂;  ΔH = 726.4 kJ

Equation (VI) has 2H₂O on the left, and that is not in the target equation.

You need an equation with 2H₂O on the right. Double Equation (III).

When you double an equation, you double its ΔH.  

(VII) 2H₂ + O₂ ⟶ 2H₂O;                        ΔH = -571.6 kJ

Now, you add equations (V), (VI), and (VII), cancelling species that appear on opposite sides of the reaction arrows.

When you add equations, you add their ΔH values.

We get the target equation (IV)  

(V)   C + O₂ ⟶ CO₂;                              ΔH = -393.5 kJ

(VI)  CO₂ + 2H₂O ⟶ CH₃OH + ³/₂O₂ ;  ΔH =  726.4 kJ

(VII) 2H₂ + O₂ ⟶ 2H₂O;                        ΔH = -571.6 kJ

(IV)  C + 2H₂ + ½ O₂ → CH₃OH;             ΔH = -238.7 kJ  

Question 6

We have three equations:  

(I) Mg + ½O₂ → MgO;  ΔH = -601.7 kJ

(II) Mg + S ⟶ MgS;      ΔH = -598.0 kJ

(III) S + O₂ ⟶ SO₂;       ΔH = -296.8 kJ

From these, we must devise the target equation:  

(IV) 3Mg + SO₂ → MgS + 2MgO; ΔH = ?  

The target equation has 1SO₂ on the left, so you reverse Equation(III).

(V) SO₂ ⟶ S + O₂;         ΔH = 296.8 kJ

Equation (V) has 1S on the right, and that is not in the target equation.  

You need an equation with 1S on the left, so you rewrite Equation (II).  

(VI) Mg + S ⟶ MgS;        ΔH = -598.0 kJ

Equation (V) has 1O₂ on the right, and that is not in the target equation.

You need an equation with 1O₂ on the left. Double Equation (I).

(VII) 2Mg + O₂⟶ 2MgO ;  ΔH = -1203.4 kJ  

Now, you add equations (V), (VI), and (VII), cancelling species that appear on opposite sides of the reaction arrows.

We get the target equation (IV)  

(V)   SO₂ ⟶ S + O₂;                    ΔH =    296.8 kJ

(VI)   Mg + S ⟶ MgS;                  ΔH = -  598.0 kJ

(VII) 2Mg + O₂ ⟶ 2MgO;            ΔH = -1203.4 kJ

(IV)  3Mg + SO₂ → MgS + 2MgO; ΔH = -1504.6 kJ

The reactants of cellular respiration are glucose and oxygen, or A. They react to form carbon dioxide, water, and energy as products.

Answer:

Explanation:

The number of protons in the nucleus of the atom is equal to the atomic number (Z). The number of electrons in a neutral atom is equal to the number of protons. The mass number of the atom (M) is equal to the sum of the number of protons and neutrons in the nucleus.

Answer:

2.037.

Explanation:

∨ ∝ 1/√M.

Where, ∨ is the rate of diffusion.

M is the molar mass of the gas.

(∨)Ne/(∨)Kr = √(M of Kr/M of Ne) = √(83.8 / 20.2) = 2.037.

Answer:

When an acid and strong reacts with each other the formation of salt occurs, and this reaction is named as neutralization reaction. The pH of salt depends upon the nature of acid and bases reacting in the reaction. When a week acid and a strong base reacts with each other, the base dominates the nature of salt because base involved is strong. The pH of the salt will be greater than 7.

Answer:

0.2286 mol

Explanation:

Mass = 36.5g

Molar Mass = 159.7 g/mol

Number of moles = ?

The formular relating these parameters is given as;

Number of moles = Mass /  Molar mass

Number of moles = 36.5 / 159.7 = 0.2286 mol

When NaOH is added to an acetate/acetic acid buffer system, the pH increases, the concentration of acetic acid decreases, and the concentration of acetate increases.

When a small volume of NaOH solution is added to an acetate/acetic acid buffer system, the following occur:

This is because when NaOH is added, it reacts with acetic acid to form sodium acetate and water. The increase in concentration of sodium acetate leads to an increase in the concentration of acetate ions, causing the pH to increase. At the same time, the reaction consumes acetic acid, resulting in a decrease in its concentration.

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Ag atoms are oxidized to form Ag+ ions

Silver tarnishes when it is oxidized to form Ag+ ions. The process involves the loss of electrons. Silver ions can be reduced back to silver atoms in certain chemical reactions by the use of reducing agents like iron (II) ions or zinc, but not during the tarnishing process which is an oxidation process.

When silver tarnishes, the silver atoms (Ag) are indeed oxidized to form Ag+ ions. This is a chemical reaction where silver loses electrons and hence, is oxidized. This process is represented in the reaction depicted: Ag+ (aq) + e¯ → Ag(s). However, it should be noted that in an oxidation reaction, while one species (here - silver) is oxidized, another species must be reduced concurrently. In the context of your question, Ag atoms are not reduced back to Ag+ ions, as that would counteract the oxidation process.

In cases where silver is recovered from solutions, such as a cyanide solution, reducing agents such as iron (II) ions or zinc might be added, leading to a reaction: 2[Ag(CN)₂](aq) + Zn(s) → 2Ag(s) + [Zn(CN)4] ²¯ (aq). This is a chemical reduction as silver ions are reduced back to silver atoms.

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Answer:

c. rock formation

Explanation:

The Earth’s internal energy provides the means for the parts of the carbon cycle that involve plate tectonics, such as rock formation and subduction.

If the Earth did not have internal energy, the carbon cycle process which would not be possible is: C. rock formation.

Carbon cycle can be defined as the series of biogeochemical processes through which atoms of carbon or carbon compounds are interconverted and used within an environment, by transporting carbon from the atmosphere to the Earth and then back to the atmosphere.

Basically, the four (4) main processes associated with carbon cycle include the following:

Of all the aforementioned processes, only rock formation requires that the Earth has sufficient internal energy for the movement of materials around the core and the mantle, thereby, leading to gradual but significant changes within the Earth's crust.

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No. Catalyst only reduce the activation energy, but don't change the energy released by the reaction.

A catalyst will alter the enthalpy of a reaction (the amount of heat that is released/absorbed) so it's not going to have the desired effect.

A catalyst is a substance that speeds up a chemical reaction, or lowers the temperature or pressure needed to start one, without itself being consumed during the reaction.

A catalyst increases the rate of a reaction, but does not get consumed in the reaction and does not alter the equilibrium constant.

In other words, a catalyst affects the kinetics of a reaction, but not the thermodynamics.

They work by increasing the rate of reaction through lowering the activation energy.

Hence, a catalyst will alter the enthalpy of a reaction (the amount of heat that is released/absorbed) so it's not going to have the desired effect.

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The direction of a chemical reaction depends on the comparison between the reaction quotient and the equilibrium constant. If the reaction quotient is greater than the equilibrium constant, the reaction goes in the reverse direction, and vice versa. This can be determined using concentrations (Qc, Kc) or partial pressures (Qp, Kp).

In the context of chemistry, a reaction's direction can indeed be predicted by comparing the reaction quotient (Qc) with the equilibrium constant (Kc). If Qc > Kc, the reaction will tend to move in the reverse direction to reach equilibrium, as it indicates that there are too many products and not enough reactants. Conversely, if Qc < Kc, the reaction will proceed in the forward direction, as it means that there are too many reactants and not enough products. Similarly, partial pressures can be used using the reaction quotient (Qp) and equilibrium constant (Kp). These concepts are central in the study of chemical equilibria, and understanding them will help comprehend how concentrations and pressures influence the direction of reactions.

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Equilibrium constants for gas-phase reactions can be expressed in terms of partial pressures. The relationship between partial pressures (Kp) and molar concentrations (Kc) can be derived from the ideal gas equation.

In chemistry, for gas-phase solutions, the equilibrium constant can be expressed either in terms of molar concentrations (Kc) or partial pressures (Kp) of the reactants and products. These two equilibrium constants are interrelated and can be derived using the ideal gas equation: PV = nRT where P is pressure, V is volume, n is the number of moles, R is the gas constant, and T is temperature.

The equilibrium constant Kp for a reaction involving gases is defined in terms of the partial pressures of the gases. For example, consider the reaction:

[tex]C_2H_6(g)[/tex]⇌ [tex]C_2H_4(g) + H_2(g)[/tex]

The equilibrium constant expression based on partial pressures would be:

[tex]Kp = (PC_2H_4)(PH_2) / PC_2H_6[/tex]

The reaction quotient (Qc or Qp) is calculated using initial or current pressures and can predict the direction of the reaction:

Using partial pressures allows for a precise understanding of how the system behaves under different conditions, including changes in initial amounts of reactants/products, temperature, and volume.

The Intermolecular forces increase with increasing polarization of bonds. The strength of Intermolecular forces (and therefore impact on boiling points) is ionic > hydrogen bonding > dipole dipole > dispersion. Boiling point increases with molecular weight, and with surface area.

The liquid mantle flowing through the cracks in Earth's crust during volcanic eruptions.

Final answer:

The formation of Earth's crust is most likely due to the D. liquid mantle flowing through cracks during volcanic eruptions, as at divergent boundaries, molten material from the mantle rises and cools to form new crust.

Explanation:

The processes that help in the constant formation of Earth's crust are primarily associated with tectonic activities and the movement of magma. According to the options provided, the liquid mantle flowing through the cracks in Earth's crust during volcanic eruptions (D) is the most likely process responsible for the formation of new crust. This is because at divergent boundaries, such as the Mid-Ocean Ridge, molten material from the mantle rises through the gaps created by tectonic plates moving apart.

As the molten material cools, it solidifies and forms new crust. Convection currents in the mantle (B) are thought to drive the movement of tectonic plates, contributing to processes such as sea floor spreading and the creation of new crust along the Mid-Ocean Ridge. Additionally, subduction zones where oceanic crust collides with continental crust (B) can lead to volcanic activity and the formation of new crust.

If 1 dozen apples has a mass of 2.0 kg and 0.20 bushel is 1 dozen apples, how many bushels of apples are in 1.0 kg of apples?

0.1 bushels

There are 0.1 bushels in 1 kg of apple.

A dozen is a set of 12 things. A dozen of apples mean 12 piece of apples , a dozen of people mean 12 people.

It is given that

a dozen apples has a mass of 2.0 kg

and 0.20 bushel is 1 dozen apples,

bushels of apples are in 1.0 Kg of apples = ?

If 2 kg apples mean 1 dozen = 12 apples

then 1 kg apples will mean 6 apples

1 dozen or 12 apples = 0.20 bushels

6 apples will be 0.20 /2 = 0.1 bushels

Therefore there are 0.1 bushels in 1 kg of apple.

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the number and kind of each atom on the reactants side must be equal to number and kind of each atom on products side.

Final answer:

In a chemical reaction, the number and type of atoms remain constant from reactants to products, following the law of conservation of matter. Chemical equations are balanced by adjusting the molecular coefficients to ensure this atomic consistency. Conservation of mass is also observed, with mass being equivalent in the reactants and products.

Explanation:

In accordance with the law of conservation of matter, the number and kind of atoms must remain constant throughout a chemical reaction. This means the number of each type of atom in the reactants is equal to the number of each type of atom in the products.

To ensure this is the case, chemists balance chemical equations by adjusting coefficients in front of the chemical formulas, which represent the amount (in moles) of substances involved in the reaction. Balancing an equation may require a methodical back-and-forth process until the same numbers of atoms for each element are present on both sides of the equation.

Furthermore, while the number of atoms is conserved during the reaction, the number of molecules may change because molecules can break apart, and atoms rearrange to form different molecules. The mass of the reactants and products is also conserved, exemplified by Avogadro's number relating atoms to moles, and moles to molar mass. This conservation of mass is a fundamental concept in chemical reactions.

Cellular Respiration is an Exothermic reaction as the product is ATP (energy)

please mark me as the brainliest

Answer:

Exothermic reaction because the product produced is ATP (energy)

Explanation:

The answer is E. You must use the formula q=mCDeltaT to solve this equation. You must also use the formula that q(reaction)=q(solution) to solve this problem

Answer:

The specific heat capacity of the metal piece is [tex]0.571J/g^oC[/tex].

Explanation:

The heat given by the hot body(metal pace) is equal to the heat taken by the cold body(water).

[tex]q_1=-q_2[/tex]

[tex]m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)[/tex]

where,

[tex]c_1[/tex] = specific heat of metal = ?

[tex]c_2[/tex] = specific heat of water = [tex]4.184 J/g^oC[/tex]

[tex]m_1[/tex] = mass of metal = 57.3 g

[tex]m_2[/tex] = mass of water = 155 g

[tex]T_f[/tex] = final temperature of water = [tex]24.72^oC[/tex]

[tex]T_1[/tex] = initial temperature of metal = [tex]88^oC[/tex]

[tex]T_2[/tex] = initial temperature of water = [tex]21.53^oC[/tex]

Now put all the given values in the above formula, we get

[tex]57.3g\times c_1\times (24.5-88.0)^oC=-155g\times 4.184J/g^oC\times (24.72-21.53)^oC[/tex]

[tex]c_1=0.571 J/g^oC[/tex]

The specific heat capacity of the metal piece is [tex]0.571J/g^oC[/tex].

Answer:

[CH₃OH] to decrease and [CO] to increase.

Explanation:

[CH₃OH] to decrease and [CO] to increase.

Answer:

        c. 2N₂O₅(g) ⇄ 4 NO₂(g)+ O₂(g), and

        d. N₂O₄(g) ⇄ 2 NO₂(g)

Explanation:

Volume and pressure are inversely related (Boyle's law).

Volume and number of molecules are directly related (Avogadro's principle).

As per Le Chatelier's principle, the reaction will shift toward the side that permits to overcome or minimize the force that disturbs the equilibrium.

With those concepts you can predict which equilibria will shift toward formation of more products if the volume of a reaction mixture at equilibrium increases by a factor of 2

Let's dig into each option.

a. 2 SO₂(g)+ O₂(g) ⇄ 2 SO3(g)

Incorrect.

There are three molecules in the reactant side and two in the product side. so the increase in volume will favor the reverse reaction. This is, the equilibrium will shift to the formation of more reactants, and this is an incorrect choice.

b. NO(g) + O₃(g) ⇄ NO₂(g) + O₂(g)

Incorrect.

There are the same number of molecules in the reactant side and the product side. Hence, the increase of volume will not produce a change in the equlibrium.

c. 2N₂O₅(g) ⇄ 4 NO₂(g)+ O₂(g)

Correct.

There are 2 molecules in the reactant side (left) and four molecules in the product side (right). So, the increase in volume in this system will produce a shift toward the product side.

d. N₂O₄(g) ⇄ 2 NO₂(g)

Correct.

There are more molecules in the product side than in the reactant side, so you predict that the equilibrium will shift toward the formation of more product to overcome the increase of volume.

Equilibrium shift is the shift of the reaction towards the stressed conditions in the reactions. The shift towards the formation of the products will occur in [tex]\rm 2N_{2}O_{5}(g) \rightleftharpoons 4 NO_{2}(g)+ O_{2}(g)[/tex] and [tex]\rm N_{2}O_{4}(g) \rightleftharpoons 2 NO_{2}(g)[/tex].

According to the Le principle the reaction shift towards the site or the reactants and products where the disturbance or the stress is present so that it can be overcome.

In the third equation reaction, [tex]\rm 2N_{2}O_{5}(g) \rightleftharpoons 4 NO_{2}(g)+ O_{2}(g)[/tex]  the number of the molecules on the left side is 2 and on the right side of the product have 4 molecules.  When the volume is increased then the reaction shifts towards the right or the product side.

In the fourth reaction, [tex]\rm N_{2}O_{4}(g) \rightleftharpoons 2 NO_{2}(g)[/tex] the number of the products are more compared to the reactants and hence the increase in the volume will shift the reaction towards the formation of the product.

Therefore, option c. [tex]\rm 2N_{2}O_{5}(g) \rightleftharpoons 4 NO_{2}(g)+ O_{2}(g)[/tex] and option d. [tex]\rm N_{2}O_{4}(g) \rightleftharpoons 2 NO_{2}(g)[/tex] are the reactions that shift towards product formation.

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2.54m/s. See the attached image for work. X represents the velocity of SF4.

To calculate the velocity of sulfur tetrafluoride under the same conditions as oxygen, we need to consider their molar masses and use the formula for calculating the velocities of gases.

In order to determine the velocity at which sulfur tetrafluoride would travel under the same conditions as oxygen, we need to consider their molar masses. The molar mass of sulfur tetrafluoride (SF4) is 108.07 g/mol, while the molar mass of oxygen (O₂) is 32.00 g/mol. Since the velocities of gases are inversely proportional to the square root of their molar masses, we can use the formula:

The velocity of sulfur tetrafluoride = Velocity of oxygen × √(molar mass of oxygen / molar mass of sulfur tetrafluoride)

Using the given velocity of oxygen as 29.0 m/s, we can substitute the molar masses and calculate the velocity of sulfur tetrafluoride.

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Answer:

[tex]-253.2 ^{\circ}C[/tex]

Explanation:

First of all, we need to convert the pressure of the gas from torr to Pa. We know that:

1 torr = 133.3 Pa

So, the pressure in Pascals is

[tex]p=(312 torr)(133.3 Pa/torr)=4.16\cdot 10^4 Pa[/tex]

Then we also have:

n = 0.133 number of moles of the gas

[tex]V=525 mL=0.525 L=5.25\cdot 10^{-4} m^3[/tex] volume of the gas

The ideal gas equation states that

[tex]pV=nRT[/tex]

where R is the gas constant and T the absolute temperature. Solving the equation for T, we find

[tex]T=\frac{pV}{nR}=\frac{(4.16\cdot 10^4 Pa)(5.25\cdot 10^{-4} m^3)}{(0.133 mol)(8.314 J/mol K)}=19.8 K[/tex]

In Celsius, it becomes

[tex]T=19.8 K-273=-253.2 ^{\circ}C[/tex]

Answer:

40 atm

Explanation:

Boyle’s law states that for a fixed amount of gas the pressure is inversely proportional to the volume of the gas at constant temperature.

P1V1 = P2V2

Where P1 is pressure and V1 is volume at the first instance

And P2 is pressure and V2 is volume at the second instance

Substituting the values in the equation

2.0 atm x 200 mL = P2 x 10 mL

P2 = 40 atm

The new pressure is 40 atm

The new pressure of the helium gas is 40 atm.

To calculate the new pressure of the helium, we use the formula below.

Formula:

Where:

Make P' the subject of the equation

From the question,

Given:

Substitute these values into equation 2

Hence, The new pressure of the helium gas is 40 atm.

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A is correct (1 h should be written as 1 s)

I just took this exam. :)

Answer:

Your correct answer is A. 1 h should be written as 1 s.

Explanation:

Answer:

C) reduced

Explanation:

NAD+ becomes reduced when it gains a hydrogen atom, transforming into NADH, which plays a significant role in cellular energy metabolism.

When a molecule of NAD+ (nicotinamide adenine dinucleotide) gains a hydrogen atom, the molecule becomes reduced. This process of gaining an electron (or hydrogen atom) is known as reduction in metabolism. Essentially, NAD+ serves as an important electron carrier within cells and as it accepts electrons, it becomes reduced to its alternate form called NADH. It's important to note that oxidation and reduction reactions often go hand in hand in biological systems, which is why they are typically referred to as redox reactions. In this context, NAD+ is reduced (gains an electron) to form NADH, which then plays a crucial role in energy metabolism within the cell.

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[H+] = 0.051 M

[SO4=] = 0.051M  

[HSO4-] = 0.16M

HSO4- <==> H+ + SO4= ..... Ka = 1.3x10^-2

Ka = [H+] [SO4=] / [HSO4-]  

1.3x10^-2 = x^2 / (0.21-x)  

Using algebra and solving the quadratic equation to solve for x.  

x = 0.051  

Therefore;

[H+] = [SO4=] = 0.051M  

[HSO4-] = 0.16M

Answer : The concentration of [tex]HSO_4^-[/tex], [tex]SO_4^{2-}[/tex] and [tex]H^+[/tex] are 0.29 M, 0.061 M and 0.061 M respectively.

Explanation :

First we have to calculate the concentration of [tex]HSO_4^-[/tex]

The dissociation of [tex]KHSO_4[/tex] is:

[tex]KHSO_4\rightarrow K^++HSO_4^-[/tex]

As, 1 mole of [tex]KHSO_4[/tex] gives 1 mole of [tex]HSO_4^-[/tex]

So, 0.35 M of [tex]KHSO_4[/tex] gives 0.35 M of [tex]HSO_4^-[/tex]

Now we have to determine the concentration of [tex]SO_4^{2-}[/tex] and [tex]H^+[/tex].

The dissociation of [tex]HSO_4^-[/tex] is:

                          [tex]HSO_4^-\rightleftharpoons H^++SO_4^{2-}[/tex]

Initial conc.      0.35           0       0

At eqm.          (0.35-x)        x        x

The expression of acid dissociation constant will be:

[tex]K_a=\frac{[H^+][SO_4^{2-}]}{[HSO_4^-]}[/tex]

Now put all the given values in this expression, we get:

[tex]1.3\times 10^{-2}=\frac{(x)\times (x)}{(0.35-x)}[/tex]

[tex]x=0.061M[/tex]

Thus, the concentration of [tex]SO_4^{2-}[/tex] = x = 0.061 M

The concentration of [tex]H^+[/tex] = x = 0.061 M

The concentration of [tex]HSO_4^-[/tex] = 0.35 - x = 0.35 - 0.061 = 0.29 M