A tree grows 1 3/4 feet per year. How long will it take the tree to grow from a height of 21 1/4 feet to a height of 37 feet?

Answers

Answer 1
so hmmm from 21 1/4 to 37, let's check the difference, to see how many feet is that.

[tex]\bf 37-21\frac{1}{4}\implies 37-\cfrac{21\cdot 4+1}{4}\implies 37-\cfrac{85}{4}\impliedby LCD~is~4 \\\\\\ \cfrac{148-85}{4}\implies \cfrac{63}{4}[/tex]

so hmmm now, its growth rate is    [tex]\bf 1\frac{3}{4}\implies \cfrac{1\cdot 4+3}{4}\implies \cfrac{7}{4}[/tex]

so.... the tree grows 7/4 in 365 days( a year ), how many days does it take it to get to 63/4 feet?

[tex]\bf \begin{array}{ccll} \stackrel{growth}{feet}&\stackrel{time}{days}\\ \text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\ \frac{7}{4}&365\\\\ \frac{63}{4}&d \end{array}\implies \cfrac{\frac{7}{4}}{\frac{63}{4}}=\cfrac{365}{d}\implies \cfrac{7}{4}\cdot \cfrac{4}{63}=\cfrac{365}{d} \\\\\\ \cfrac{28}{252}=\cfrac{365}{d}\implies d=\cfrac{252\cdot 365}{28}\implies d=\cfrac{91980}{28}\implies \boxed{d=3285}[/tex]

Related Questions

Smallville’s town council has records of the town’s budget over a 10-year period. Create a best fit and model for the data. What does the model predict the town’s budget will be in the year 2011?

Answers

I found the missing image and choices.
If these were the missing choices:

A)$391,000

B)$417,000

C)$404,000

D)$411,000

My answer is D) $411,000 in 2011.

There is an average increase of 4% from the previous budget to arrive at the amount of the current year. 

2009 budget $381,700

381,700 * (1.04)² = 381,700 * 1.0816 = 412,846.72  only Choice D. is nearest to the amount

2000 budget $265,100

265,100 * (1.04)¹¹ = 265,100 * 1.540 = 408,254 only Choice D. is nearest to the amount.





Constantine picks two letters at random from the word constantinople with replacement. what is the probability that both letters picked are consonants?

Answers

Constantinople  has a total of 14 letters of which 9 are consonants

P(picking a consonant) = 9/14

P(2 letters are consonants with replacement) = 9/14 * 9/14 = 81/196

Point r is located at (3,0). point s is located at (0,-4). what is the equation of the line through these two points

Answers

(3,0)(0,-4)
slope = (-4 - 0) / (0 - 3) = -4/-3 = 4/3

y = mx + b
slope(m) = 4/3
(0,-4)....x = 0 and y = -4
now we sub and find b, the y int
-4 = 4/3(0) + b
-4 = b
so ur equation is : y = 4/3x - 4....or 4x - 3y = 12 <==

HELP if f(x)=-14x-2, then f^-1(x)=?

Answers

Replace f(x) with y. Then swap x and y. Once the swap has been done, solve for y to get the inverse.

[tex]f(x) = -14x - 2 [/tex]

[tex]y = -14x - 2 [/tex]

[tex]x = -14y - 2 [/tex]

[tex]x+2 = -14y [/tex]

[tex]-14y = x+2 [/tex]

[tex]y = -\frac{x+2}{14} [/tex]

[tex]f^{-1}(x) = -\frac{x+2}{14} [/tex]

The population of a type of local frog can be found using an infinite geometric series where a one equals 84 and the common ratio is one over five find the sum of the infinite series that will be the upper limit of this population. 87,105,425, or this series is divergent

Answers

a=84 and r=1/5

Since r, the common ratio squared is less than one, the sum will converge to a limit.  Rule:  if  r^2<1 infinite series converges, otherwise it diverges.

Since the sum of any geometric sequence is:

s(n)=a(1-r^n)/(1-r)

And if r^2<1, (1-r^n) becomes 1-0=1 as n approaches infinity.

So whenever r^2<1 the sum of the infinite series is just:

s(n)=a/(1-r)

Since a=84 and r=1/5 this infinite series has a sum of:

s(n)=84/(1-1/5)

s(n)=84/(4/5)

s(n)=5(84)/4

s(n)=105

Find the missing length.

Answers

Find this using the pythagoream theorem for right triangles.

a^2+b^2=c^2
12^2+9^2=c^2

144+81= c^2
225=c^2
15=c

Final answer: c=15

Find the area of the circle with the given radius or diameter. Use = 3.14.

r = 6

A =

37.68 sq. units
113.04 sq. units
226.08 sq. units

Answers

Radius [ r ] = 6 units

Area of a circle = [tex] \pi r^{2} [/tex] = [tex]3.14 * 6 * 6 = 3.14 * 36 = 113.04 [/tex] sq. units.

Hence, the answer is B.

Answer: 113.04 sq. units

Simplify 5 − (−1).

a. 6
b. −6
c. 4
d. −4

Answers

Hi!

Subtracting a negative number is the same as adding a positive.

So instead of

5 - (-1)

We could write

5 + 1

5 + 1 = 6

The answer is 6.

Hope this helps! :)

Answer: it is  a

Step-by-step explanation: :) :v :B

A club decides to sell T-Shirts for 15$ as a fund-raiser. It cost $20 plus $9 per T-Shirt to make them. How many T-Shirts need to be made to make a profit of at least $150?

Answers

The expression for T-shirt production is 20+9T
The expression for total price of selling the T-shirts is 15T

Profit = Total cost of selling - Total cost of buying
Profit = 15T - (20+9T)
Profit = 15T - 20 - 9T
Profit = 6T - 20 

To make profit ≥150

6T - 20 ≥ 150
6T ≥ 170
T ≥ 170/6
T ≥ 28.3

The minimum number of T-shirts needed is 29 T-shirts

enter an equation in slope-intercept form that describes a line that contains the points (4,1) and (4,2)

Answers

[tex]\bf \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) &({{ 4}}\quad ,&{{ 1}})\quad % (c,d) &({{ 4}}\quad ,&{{ 2}}) \end{array} \\\\\\ % slope = m slope = {{ m}}= \cfrac{rise}{run} \implies \cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{2-1}{4-4}\implies \cfrac{1}{0}\leftarrow unde fined[/tex]

so... the slope is undefined, the graph of it is just a vertical line, check the picture below, and that's the equation.

now... you can't quite put it in y = mx + b, or slope-intercept form, since it has no defined slope and it doesn't have an y-intercept either.

What percent of 210 is 70?

Answers

if we take 210 to be the 100%, what is 70 off of it in percentage then?

[tex]\bf \begin{array}{ccllll} amount&\%\\ \text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\ 210&100\\ 70&x \end{array}\implies \cfrac{210}{70}=\cfrac{100}{x}\implies x=\cfrac{70\cdot 100}{210}[/tex]
percent means parts out of 100
so x%=x/100

'of' means multiply

so

what percent of 210 is 70 translates to
x/100 times 210=70
210x/100=70
21x/10=70
times 10 both sides
21x=700
divide both sides by 21
x=33.333333


33.33333333% of 210 is 70

When 332 college students are randomly selected and surveyed, it is found that 113 own a car. find a 99% confidence interval for the true proportion of all college students who own a car?

Answers

Given:
n = 332, sample size
p = 113/332 = 0.3404, sample proportion
99% confidence interval

The confidence interval for the population is calculated from
[tex]p \pm z^{*} \sqrt{ \frac{p(1-p)}{n} } [/tex]
where z* = 2.58 for the 99% confidence level (from tables)..

[tex]2.58 \sqrt{ \frac{0.3404(1-0.3404)}{332} } =0.0671[/tex]
Therefore the 99% confidence interval is
(0.3404 - 0.0671, 0.3404 + 0.0671) = (0.2733, 0.4075)

Answer:
The 99% confidence interval is (0.273, 0.408) or (27%, 41%).
That is, between 27% and 41% of the students own cars.

How many cans of paint are needed to cover an area of 2,200 square units if one can of paint covers an area of 400 square units? 4 5 6 8?

Answers

In this case, one can of paint can covers an area of 400 square units. You are asked how much cans needed to cover an area of 2,200 square units.

Then you just need to divide 2,200 square units with 400 square units.
The equation will be : (2,200 square units / 400 square units) x 1 can=  4.5 cans
After you round up the result it would be 5 cans.

Answer: 5 cans

HOW DO YOU MOVE A VARIABLE FROM ONE SIDE OF AN EQUATION TO ANOTHER? I need to know as I'm reviewing module 7 algebra and i want to know please

Answers

The easiest way to do this is to add or subtract the value of the variable.
For example in the equation 5+a=7, subtract a from both sides to get 5=7-a.
If the initial equation was 5-a=7, add from both sides (5=a+7).
Basically, if the initial value is negative, add its value to cancel to zero.
Do the opposite if the initial value is positive.

What is the circumference of this circle, in millimeters? use 22/7 for pi

r = 49

Answers

Circumference=[tex]2\pi r=2\times \dfrac{22}{7} \times 49 = \boxed{308 \text{ mm}}[/tex]

Answer: circumference = 308mm

Step-by-step explanation: the formula for the circumference of a circle is given by

C=2πr

Given that r=49mm

Pi=22/4

C=2*22/7*49

C=44*7=308mm

In geometry, the circumference of a circle is the distance around it. That is, the circumference would be the length of the circle if it were opened up and straightened out to a line segment. Since a circle is the edge of a disk, circumference is a special case of perimeter.

A square garden plot has an area of 75 ft^2. Find the length of each side in simplest radical form. Calculate the length of each side to the nearest tenth of a foot..

Answers

Hello.


The area of a square is calculated by the formula:

A = l²

As A = 75 ft², we have:

75 = l² 

l = √75

Now, note that: 75 = 3 . 25 = 3 . 5²

So:

l = √(3 . 5²) = √3 . √(5²)

l =  5√3 ft


Now, we can assume √3 = 1.73

l ≈ 5 * 1.732

l ≈ 8,7 ft   (Note that I have already put it in the nearest tenth)


OK :)

4n-3<12 solve and please don't give me the answer just the equation

Answers

just as with an equation with an = sign, we want to isolate the variable, n.
So first bring -3 to the right hand side:

4n-3<12 => 4n < 12+3 => 4n < 15

Then divide by 4

4n/4 < 15/4 => n < 15/4

You can't simplify it beyond that.

Redo, Answers please?

Answers

11) ?=12
10) ?=13
14) ?=13
11)

11+15+13 = 39

39 - 27 = 12

so 

answer
? = 12

10)

18 - 11 + 13 = 20

33 - 20 = 13

so 

answer

? = 13

14)

16+17+12=45

45 - 27 = 18

answer

? = 18

A given line has the equation 10x + 2y = −2.

What is the equation, in slope-intercept form, of the line that is parallel to the given line and passes through the point (0, 12)?

Answers

y = -5x + 12 since the slope of that line is -5x and in order to pass through that point the y intercept must be 12

Step 1

Find the slope of the given line

we have

[tex]10x+2y=-2[/tex]

Isolate the variable y

Subtract [tex]10x[/tex] both sides

[tex]2y=-10x-2[/tex]

Divide by [tex]2[/tex] both sides

[tex]y=-5x-1[/tex]

The slope of the given line is

[tex]m=-5[/tex]

Step 2

Find the equation of the line that is parallel to the given line and passes through the point [tex](0, 12)[/tex]

we know that

If two lines are parallel. then their slope are equal

In this problem we have

[tex]m=-5[/tex]

[tex](0, 12)[/tex]

The equation of the line into slope-intercept form is equal to

[tex]y=mx+b[/tex]

substitute the values

[tex]12=-5*0+b[/tex]

[tex]b=12[/tex]

the equation of the line is

[tex]y=-5x+12[/tex]

therefore

the answer is

[tex]y=-5x+12[/tex]

Divide 35b^5 +20ab^3 +20a^2b^2 by 5b^2

Answers

Basically, you just divide each term in the equation by b^2.
So 35b^5 / b^2 = 35b^3, 30ab^3 / b^2 = 30ab, and 20a^2b^2 / b^2 = 20a^2.
So your final answer is 35b^3 + 30ab + 20a^2.

In two or more complete sentences, compare the number of x-intercepts in the graph of f(x) = x2 to the number of x-intercepts in the graph of g(x) = -(x-4)2. Be sure to include the transformations that occurred between the parent function f(x) and its image g(x).

Answers

There is only one x-intercept for f(x) and g(x), f(x) having a minimum value of zero and g(x) having a maximum value of zero. f(x)=0 when x=0, g(x)=0 when x=4.

g(x) is f(x) reflected about the about the x-axis and shifted to the right by 4 units. 
Since x^2 = 0 implies x = 0 with multiplicity 2, there is one x-intercept
Since -x^2-5 = 0 implies x = +-sqrt(5)i, there are no x-intercepts
Transformations:
Reflect f(x) in the x-axis,
then vertically shift the result down by 5 units,
to get g(x).

Consider the leading term of the polynomial function. What is the end behavior of the graph? Describe the end behavior and provide the leading term.
-3x^5 + 9x^4 + 5x^3 + 3

Answers

The leading term is -3x^5.  The end behavior of any function is the behavior that the highest powered term has as x approaches ±oo.

In this case because the highest order term is -3x^5, as x approaches -oo, y approaches +oo.  And as x approaches +oo, y approaches -oo.

The perimeter of a square is 96 inches. if the side length is 2x + 4, what is the value of x and the length of each side?

Answers

subtract 4 from 96 and divide by 2

The circle given by x^2+y^2-4x-10=0 can be written in standard form like this: (x-h)^2+y^2=14. What is the value of h in this equation??

Answers

Answer: H=2

Step-by-step explanation:

we just need to complete the square for the x terms

gropu x terms

x^2-4x

take 1/2 of linear coefient and square it

-4/2=-2, (-2)^2=4

x^2-4x+4

factor

(x-2)^2

h=2

The value of h is 2.

Completing the square for the x terms by grouping x terms

x^2-4x

Taking 1/2 of linear coefficient and squaring it.

-4/2=-2, (-2)^2=4

x^2-4x+4

Factorizing the equation.

(x-2)^2

h=2.

What is an equation?

An equation is a mathematical statement this is made of two expressions related with the aid of an identical sign. As instance, 3x – 5 = 16 is an equation. To fix this equation, we get the value of the variable x as x = 7.

Learn more about the equation here: https://brainly.com/question/2972832

#SPJ2

A volcano fills the volume between the graphs z=0 and z=1/(x^2+y^2)^10 and outside the cylinder x+y=1. find the volume.

Answers

 

For this case, we use the cylindrical coordinates: 
x² + y² = r² 
dV = r dz dr dθ 

The limits are:
z = 0 to z = 1/(r²)^10 = 1/r^20
r = 1 to ∞ 
θ = 0 to 2π 

Integrating over the limits:
V = ∫ [0 to 2π] ∫ [1 to ∞] ∫ [0 to 1/r^20] r dz dr dθ 
V = ∫ [0 to 2π] ∫ [1 to ∞] rz | [z = 0 to 1/r^20] dr dθ 
V = ∫ [0 to 2π] ∫ [1 to ∞] 1/r^19 dr dθ 
V = ∫ [0 to 2π] −1/(18r^18) |[1 to ∞] dθ 
V = ∫ [0 to 2π] 1/18 dθ 
V = θ/18 |[0 to 2π] 
V = π/9

The volume of the volcano is an illustration of definite integral

The volume of the volcano is: [tex]\mathbf{\frac{1}{9}\pi}[/tex]

The graphs are given as:

[tex]\mathbf{z = 0}[/tex] and [tex]\mathbf{z = \frac{1}{(x^2 + y^2)^{10}}}[/tex]

The cylinder is:

[tex]\mathbf{x + y =1}[/tex]

For cylindrical coordinates, we have:

[tex]\mathbf{r^2 =x^2 + y^2}[/tex]

So, we have:

[tex]\mathbf{z = \frac{1}{(r^2)^{10}}}[/tex]

[tex]\mathbf{z = \frac{1}{r^{20}}}[/tex]

Where:

[tex]\mathbf{r = 1 \to \infty}[/tex]

[tex]\mathbf{\theta = 0 \to 2\pi}[/tex]

So, the integral is:

[tex]\mathbf{V = \int\limits^{2\pi}_0 {\int\limits^{\infty}_1 {\frac{1}{r^{20}}} \, r\ dr } \, d\theta }[/tex]

Cancel out r

[tex]\mathbf{V = \int\limits^{2\pi}_0 {\int\limits^{\infty}_1 {\frac{1}{r^{19}}} \, dr } \, d\theta }[/tex]

Rewrite as:

[tex]\mathbf{V = \int\limits^{2\pi}_0 {\int\limits^{\infty}_1 {r^{-19}} \, dr } \, d\theta }[/tex]

Integrate

[tex]\mathbf{V = \int\limits^{2\pi}_0 {{-\frac{1}{18}r^{-18}}} |\limits^{\infty}_1 \, d\theta }[/tex]

Expand

[tex]\mathbf{V = \int\limits^{2\pi}_0 {{-\frac{1}{18}(\infty^{-18} -1^{-18}) }} , d\theta }[/tex]

[tex]\mathbf{V = \int\limits^{2\pi}_0 {{-\frac{1}{18}(0 -1) }} , d\theta }[/tex]

[tex]\mathbf{V = \int\limits^{2\pi}_0 {{-\frac{1}{18}( -1) }} , d\theta }[/tex]

[tex]\mathbf{V = \int\limits^{2\pi}_0 {{\frac{1}{18} }} , d\theta }[/tex]

Integrate

[tex]\mathbf{V = \frac{1}{18}(\theta)|\limits^{2\pi}_0}[/tex]

Expand

[tex]\mathbf{V = \frac{1}{18}(2\pi - 0)}[/tex]

[tex]\mathbf{V = \frac{1}{18}(2\pi )}[/tex]

Cancel out 2

[tex]\mathbf{V = \frac{1}{9}\pi}[/tex]

Hence, the volume is: [tex]\mathbf{\frac{1}{9}\pi}[/tex]

Read more about volumes at:

https://brainly.com/question/9897385

please help on b (left of c) and c !!!

rewrite each of the following expressions so that your answer has no negative or fractional exponents

Answers

alrighty


remember
[tex](ab)^c=(a^c)(b^c)[/tex]
and
[tex]x^\frac{m}{n}=\sqrt[n]{x^m}[/tex]
and
[tex](x^m)^n=x^{mn}
and
[tex]x^0=1[/tex] for all real numbers x
and
[tex]x^{-m}=\frac{1}{x^m}[/tex]


b.
[tex](x^5y^4)^\frac{1}{2}=((x^5)^\frac{1}{2})((y^4)^\frac{1}{2})[/tex]=
[tex](x^\frac{5}{2})(y^\frac{4}{2})=(\sqrt{x^5})(\sqrt{y^4})=x^2y^2\sqrt{x}[/tex]

c.
x^0=1
so
that (x^-3y)^0=1
because exponents first in pemdas
so we are left with
x^2y^-1
[tex]x^2y^{-1}=(x^2)(y^{-1})=(x^2)(\frac{1}{y^1})=\frac{x^2}{y}[/tex]
[tex](x^5y^4)^{ \frac{1}{2} }= \sqrt{x^5y^4} =x^2y^2 \sqrt{x} \\ \\ \\ (x^2y^{-1})(x^{-3}y)^0= (x^2y^{-1})*1= \frac{x^2}{y} [/tex]

A can factory requires 2 sheets of metal to make 36 cans and 10 sheets of metal to make 180 cans. The proportionality constant between the number of cans made and the number of sheets of metal used is

a-36
b-18
c-288
d-5

Answers

B. 18 because you divide the total number of cans by the number of sheets used to make them. 36/2 = 18, 180/10 = 18

Match the perfect square trinomials with their factors 4a2 + 4a + 1 (2 + a)(2 + a) 4a2 − 4a + 1 (2a + 1)(2a + 1) 4 − 4a + a2 (2a − 1)(2a − 1) 4 − 4a − a2 (2 − a)(2 − a) 4 + 4a + a2

Answers

4a2 + 4a + 1 = (2a +1)^2 = (2a + 1)(2a + 1)
4 − 4a + a2  = (2 - a)^2 = (2 − a)(2 − a)
4a2 − 4a + 1 = (2a -1)^2 = (2a − 1)(2a − 1)
4 + 4a + a2 = (2 + a)^2 = (2 + a)(2 + a) 

One student can paint a wall in 10 minutes. another student can paint the same wall in 15 minutes. working together, how long will it take for them to paint the wall?

Answers

the answer:
One student can paint a wall in 10 minutes
another student can paint the same wall in 15 minutes.
If they paint together the wall, the result time will be

15mn - 10mn = 5 mn

proof:
let  / =  minute


student 1:    /     /     /     /    /    /    /    /    /    /


student2:     /     /     /     /    /    /    /    /    /    /    /    /    /    /    /
                   x----------------------------------------x
                                already done
the remain time is /  /  /  /  /  =   five minutes


Answer:

6 days

Step-by-step explanation:

Given that one student can paint a wall in 10 minute and another student in 15 minutes.

Since if number of persons increase, painting time decreases, this is a question of inverse proportion

Hence if they work together they can paint in one day

[tex]\frac{1}{10} +\frac{1}{15}[/tex] part of the work

i.e. work completed in 1 day when they work together

=[tex]\frac{1}{10} +\frac{1}{15} \\=\frac{9+6}{90} \\=\frac{1}{6}[/tex]

Hence in 6 days they can together complete the full work

Determine the number of possible triangles, abc, that can be formed given c = 85°, a = 10, and c = 13. 0 1 2

Answers

Given:
m∠C = 85°, a= 10,  c = 13

From the Law of Sines,
sin(A)/a = sin(C)/c
sin(A) = (a/c)*sin(C)
          = (10/13)*sin(85°)
          = 0.7663
m∠A = sin⁻¹ 0.7663 = 50°, or 130°

When m∠A = 50°, obtain
m∠B = 180° - (m∠A + m∠C) = 180 - (50+85) = 45°
Again from the Law of Sines, obtain
b = (sinB/sinC)*c = 9.2

When m∠A = 130°, obtain
m∠B = 180° - (130 + 85) = -35° (not possible)
Therefore this triangle does not exist.

Answer:
There is only one possible triangle, with
A=50°, B=45°, C=85°, a=10, b=9.2, c=13.

Final answer:

Correcting for the apparent typo in the question, assuming 'c' refers to an angle and a side length respectively, there can only be one possible triangle formed given the angle and two sides. This is based on geometric principles where a unique triangle can be determined from an angle opposite and its respective side length.

Explanation:

The question presents a probable typo since it mentions two different values for 'c'. Assuming 'c = 85°' refers to an angle, and 'c = 13' refers to the length of a side opposite this angle, the proper interpretation involves finding possible triangles given an angle and two sides. However, the principles of geometry dictate that with one angle and two sides specified, especially in this non-ambiguous manner where one side length and the angle opposite are known, one can determine a unique triangle, assuming the given information leads to a viable geometric figure.

By using the Law of Sines, one might attempt to find the other angles or sides, but since we only have one angle and one side length, we directly know there's no ambiguity - geometrically speaking, there's only one way to construct such a triangle, thus, only one possible triangle can be formed given the corrected assumptions.

Other Questions
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