A veterinarian estimated the weight of a puppy to be 9kg. The actual weight of the puppy was 9.5kg Find the absolute error and the percent error of the veterinarian's estimate. If necessary, round your answers to the nearest tenth.

you add -2 1/4 + -4 1/2 = -6 3/4

so, your answer is -6 3/4

Answer:

10 1/4

Step-by-step explanation:

The null hypothesis in a chi-square test states independence between variables. There is no relationship between the two of them. The correct option is A) True.

The chi-square test is a mathematical procedure used to evaluate if there is a significant difference between expected and observed results in one or more categories.

It is a non-parametric test to analyze the differences between categorical variables in the same population.

The test compares real data with expected data if the null hypothesis was true. In this way, the test determines if the difference between observed and expected data are by chance or if this difference is due to a relationship between the involved variables.

This independence test searches for the association between two variables in the same population. It determines the existence or not of independence between two variables.

So the test compares two hypotheses, the null one and the alternative one.

According to this information, we can assume that the statement

The null hypothesis for a chi-square contingency test of independence for two variables always assumes the variables are independent

is true.

Option A is correct. True.

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The volume of the solid that lies within both the cylinder and the sphere is [tex]\( \pi \cdot 39^{3/2} \)[/tex].

To find the volume of the solid that lies within both the cylinder

[tex]\(x^2 + y^2 = 25\)[/tex] and the sphere [tex]\(x^2 + y^2 + z^2 = 64\)[/tex], we'll use cylindrical coordinates. The equations in cylindrical coordinates are

[tex]\(x = r\cos(\theta)\), \(y = r\sin(\theta)\), and \(z = z\)[/tex].

First, let's find the limits of integration for (r), [tex]\(\theta\)[/tex], and (z):

Limits for (r): The cylinder has a radius of 5 (r = 5), so [tex]\(0 \leq r \leq 5\)[/tex].

Limits for [tex]\(\theta\)[/tex]: Since the solid lies within the entire cylinder, [tex]\(0 \leq \theta \leq 2\pi\).[/tex]

Limits for (z): The sphere has a radius of [tex]\(\sqrt{64} = 8\)[/tex], so [tex]\(0 \leq z \leq \sqrt{64 - r^2}\)[/tex].

Now, the volume element (dV) in cylindrical coordinates is [tex]\(r \, dr \, d\theta \, dz\)[/tex].

So, the volume (V) is given by:

[tex]\[ V = \int_0^{2\pi} \int_0^5 \int_0^{\sqrt{64-r^2}} r \, dz \, dr \, d\theta \][/tex]

Let's calculate this:

[tex]\[ V = \int_0^{2\pi} \int_0^5 \left[ z \right]_0^{\sqrt{64-r^2}} \, dr \, d\theta \][/tex]

[tex]\[ V = \int_0^{2\pi} \int_0^5 \sqrt{64-r^2} \, dr \, d\theta \][/tex]

[tex]\[ V = \int_0^{2\pi} \left[ \frac{1}{2} (64-r^2)^{3/2} \right]_0^5 \, d\theta \][/tex]

[tex]\[ V = \int_0^{2\pi} \frac{1}{2} (64-25)^{3/2} \, d\theta \][/tex]

[tex]\[ V = \int_0^{2\pi} \frac{1}{2} (39)^{3/2} \, d\theta \][/tex]

[tex]\[ V = \frac{39^{3/2}}{2} \int_0^{2\pi} d\theta \][/tex]

[tex]\[ V = \frac{39^{3/2}}{2} \cdot 2\pi \][/tex]

[tex]\[ V = \pi \cdot 39^{3/2} \][/tex]

So, the volume of the solid that lies within both the cylinder and the sphere is [tex]\( \pi \cdot 39^{3/2} \)[/tex].

The volume of the solid that lies within both the cylinder [tex]\(x^2 + y^2 = 25\)[/tex] and the sphere[tex]\(x^2 + y^2 + z^2 = 64\) is \( \frac{40\pi}{3} \).[/tex]

To find the volume of the solid that lies within both the cylinder [tex]\(x^2 + y^2 = 25\)[/tex] and the sphere [tex]\(x^2 + y^2 + z^2 = 64\)[/tex], we can use cylindrical coordinates.

In cylindrical coordinates, the equations of the cylinder and the sphere become:

Cylinder: [tex]\(r^2 = 25\)[/tex]

Sphere: [tex]\(r^2 + z^2 = 64\)[/tex]

The limits of integration for r will be from 0 to 5 (since [tex]\(r^2 = 25\)[/tex] gives r = 5 in cylindrical coordinates). The limits of integration for z will be from [tex]\(-\sqrt{64 - r^2}\) to \(\sqrt{64 - r^2}\).[/tex]

The volume element dV in cylindrical coordinates is [tex]\(r \, dr \, dz \, d\theta\).[/tex]

So, the volume V of the solid is given by the triple integral:

[tex]\[V = \iiint dV = \int_{0}^{2\pi} \int_{0}^{5} \int_{-\sqrt{64 - r^2}}^{\sqrt{64 - r^2}} r \, dz \, dr \, d\theta\][/tex]

Let's evaluate this triple integral:

[tex]\[V = \int_{0}^{2\pi} \int_{0}^{5} \left[ r\sqrt{64 - r^2} - (-r\sqrt{64 - r^2}) \right] \, dr \, d\theta\]\[V = 2\pi \int_{0}^{5} 2r\sqrt{64 - r^2} \, dr\][/tex]

Now, we can use a substitution to solve this integral. Let [tex]\(u = 64 - r^2\),[/tex]then [tex]\(du = -2r \, dr\):[/tex]

[tex]\[V = -4\pi \int_{64}^{39} \sqrt{u} \, du\]\[V = -4\pi \left[ \frac{2}{3}u^{3/2} \right]_{64}^{39}\]\[V = -\frac{8\pi}{3} \left[ 39^{3/2} - 64^{3/2} \right]\]\[V = -\frac{8\pi}{3} \left[ 59 - 64 \right]\]\[V = \frac{40\pi}{3}\][/tex]

Thus, the volume of the solid that lies within both the cylinder [tex]\(x^2 + y^2 = 25\)[/tex] and the sphere[tex]\(x^2 + y^2 + z^2 = 64\) is \( \frac{40\pi}{3} \).[/tex]

Answer:

c would be the right answer

Step-by-step explanation:

Step-by-step explanation:

How are we expected to find values of the numbers without any other information??

The floor function rounds down decimal or fractional numbers to the nearest integer.

(a) ⌊1.1⌋ = 1

(b) ⌈1.1⌉ = 2

(c) ⌊-0.1⌋ = -1

(d) ⌈-0.1⌉ = 0

(e) ⌈2.99⌉ = 3

(f) ⌈-2.99⌉ = -2

(g) ⌊1/2 + ⌈1/2⌉⌋ = 1

(h) ⌈⌊1/2⌋ + ⌈1/2⌉ + 1/2⌉ = 2

The values enclosed in square brackets represent the floor function, which rounds a decimal number down to the nearest integer. Here are the values for the given expressions:

(a) ⌊1.1⌋ = The floor function ⌊x⌋ rounds down to the nearest integer, so ⌊1.1⌋ = 1.

(b) ⌈1.1⌉ = The ceiling function ⌈x⌉ rounds up to the nearest integer, so ⌈1.1⌉ = 2.

(c) ⌊-0.1⌋ = ⌊x⌋ rounds down to the nearest integer, so ⌊-0.1⌋ = -1.

(d) ⌈-0.1⌉ = ⌈x⌉ rounds up to the nearest integer, so ⌈-0.1⌉ = 0.

(e) ⌈2.99⌉ = ⌈x⌉ rounds up to the nearest integer, so ⌈2.99⌉ = 3.

(f) ⌈-2.99⌉ = ⌈x⌉ rounds up to the nearest integer, so ⌈-2.99⌉ = -2.

(g) ⌊1/2 + ⌈1/2⌉⌋ = ⌊1/2 + 1⌋ = ⌊1.5⌋ = 1.

(h) ⌈⌊1/2⌋ + ⌈1/2⌉ + 1/2⌉ = ⌈0 + 1 + 0.5⌉ = ⌈1.5⌉ = 2.

So, these are the integer values obtained by applying the floor function to the given decimal or fractional numbers, and in some cases, applying it multiple times.

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Que. Find the following values.

(a) ⌊1.1⌋

(b) ⌈1.1⌉

(c) ⌊−0.1⌋

(d) ⌈−0.1⌉

(e) ⌈2.99⌉

(f) ⌈−2.99⌉

(g) ⌊1/2+⌈1/2⌉⌋

(h) ⌈⌊1/2⌋+⌈1/2⌉+1/2⌉

Final answer:

Explanation of sampling distributions and probabilities for different sample sizes in relation to the population proportion in St. Paulites.

Explanation:

In part a, when selecting a sample of 540 St. Paulites, the sampling distribution of p would have a mean of 0.32 and a standard error of 0.0201.

The probability that the sample proportion will be within 0.05 of the population proportion is 0.9871.

In part c, with a sample of 170 St. Paulites, the sampling distribution of p has a mean of 0.32 and a standard error of 0.03145.

The probability that the sample proportion will be within 0.05 of the population proportion is 0.9907.

The gain in precision by taking the larger sample is substantial, with the probability increasing from 0.9907 to 0.9871, reducing the error by a factor of 0.9999.

Answer:

Step-by-step explanation:

A convergent sequence is a sequence that approach to a specific limit. If the sequence doesn't approach to a limit, then it's a divergent sequence.

Now, if we have a sequence apparently convergent where we just analyse the first 1000 terms, that information won't be enough to actually consider the complete sequence as convergent, because those 1000 terms are not representative of the actual limit.

Therefore, the answer is false.

Answer:

10

Step-by-step explanation:

The radius is the magnitude of the complex number that is the difference between any point on the circle and the center point. A suitable calculator can tell you that magnitude:

║(8+7i) - (2-i)║ = √((8-2)² +(7-(-1))²) = √(36+64) = √100 = 10

Answer:

10

Step-by-step explanation:

The question deals with a physics scenario involving a subway train applying brakes, kinetic friction, and requires calculating stopping distances and average acceleration using mechanical principles.

The question involves a subway train traveling at a certain speed and then applying brakes on specific cars, leading to a scenario involving kinetic friction. It asks for an analysis of the situation using physics concepts such as speed conversion, coefficient of kinetic friction, and acceleration. A comprehensive understanding of these topics would be necessary to calculate quantities like stopping distance and average acceleration.

The provided references suggest that the problems are focusing on converting speeds from miles per hour to meters per second, the effects of friction on motion, and using equations of motion to determine the stopping distance of a vehicle with locked wheels on a wet surface. These problems demonstrate applications of concepts in mechanics, specifically Newton's laws of motion, frictional forces, and energy conservation.

The subway train will travel approximately 26.2 meters before coming to a stop due to the brakes causing the wheels to slide on the track with a coefficient of kinetic friction of 0.35.

To solve this problem, we need to use principles of physics, specifically those related to friction and acceleration.

Convert the Speed: First, convert the speed from miles per hour (mi/h) to meters per second (m/s) for ease of calculation.

30 mi/h = 30 * 1609 / 3600 m/s ≈ 13.4 m/s.

Identify the Variables:

Initial speed (u): 13.4 m/s

Final speed (v): 0 m/s (since the train stops)

Coefficient of kinetic friction (μ): 0.35

Calculate the Frictional Force: The kinetic frictional force can be calculated using the formula:

Frictional force (f_k) = μ * N, where N (the normal force) equals the weight of the sliding cars. Assuming we only need to calculate the proportion without specific mass of cars, we can denote N as m * g (mass * gravity). Therefore, f_k = 0.35 * m * g.

Determine the Deceleration: Using Newton's second law, f_k = m * a (mass * acceleration), we can solve for acceleration (a):

0.35 * m * g = m * a,

a = 0.35 * g (since m cancels out), where g is the acceleration due to gravity (≈ 9.8 m/s²).

a = 0.35 * 9.8 m/s² ≈ 3.43 m/s².

Use the Kinematic Equation: To find the stopping distance, we use the kinematic equation: v² = u² + 2 * a * s (where s is the stopping distance):

0 = (13.4)² + 2 * (-3.43) * s

0 = 179.56 - 6.86 * s

s = 179.56 / 6.86

s ≈ 26.2 meters.

The given limit problem involves factorization of difference of squares. After simplifying, the limit turns out to not exist as the denominator becomes zero while the numerator becomes non-zero. Hence, we end up with an undefined expression.

The subject of this question is the calculation of a mathematical limit, a fundamental concept in calculus. The limit equation given is a case of an indeterminate form of type 0/0, which can be solved using the L'Hopital's Rule.

However, before that, we should identify the factorization of (x4 - y4) and (x2 - y2) which are a difference of squares. Therefore, they can be factored as follow: (x4 - y4) = (x2 + y2)(x2 - y2) and (x2 - y2) = (x - y)(x + y).

After canceling out the common factor (x2 - y2), we get the simplified expression (x2 + y2)/(x - y). Now, considering that x≠y, we can substitute x and y with 'a' (since both approach the same value 'a' as per the limit definition), and we obtain (2a)/(0) = ∞ or -∞ based on a's sign. So, in fact, this limit does not exist for x≠y.

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Final answer:

The company should produce 1,200 boxes of Assortment I per week to maximize its profit.

Explanation:

In order to maximize profit, the company should produce the assortment that yields the highest profit per candy sold. Let's calculate the profit per candy for each assortment:

From the calculations above, we can see that Assortment I has the highest profit per cherry candy. Therefore, the company should produce as many boxes of Assortment I as possible, given the available resources. To determine the number of boxes to produce, we need to calculate the maximum number of cherry candies that can be produced with the available resources:

Assortment I contains 4 cherry candies per box, so the maximum number of boxes of Assortment I that can be produced is 4,800/4 = 1,200 boxes. The company should produce 1,200 boxes of Assortment I per week to maximize its profit.

Final answer:

The function [tex]N(t) = 110,000(1.034)^t[/tex] models patent applications yearly after 1980; in 2015 (t = 35), it predicts 354,496 applications. Doubling time, found when N(t) doubles from the initial value, is approximately 21 years

Explanation:

The given function  [tex]N(t) = 110,000(1.034)^t[/tex] models the number of patent applications received at any year t after 1980, where t represents the number of years. In 2015, t = 35, so  [tex]N(35) = 110,000(1.034)^35 = 354,496[/tex]. To find the doubling time, we set N(t) equal to twice the initial value: 2(110,000) = 220,000. Solving [tex]220,000 = 110,000(1.034)^t[/tex] yields [tex](1.034)^t = 2,[/tex]then log(1.034)t = log(2). Hence, t = log(2) / log(1.034) ≈ 20.73. Thus, the doubling time for N(t) is approximately 21 years.

A repeating mixed number is a mixed fraction, which after converted to decimal; the numbers after the decimal point repeat without end.

1.12 as a repeating mixed number is [tex]1\frac{13}{99}[/tex]

Given that

[tex]Number = 1.12[/tex]

First, we represent as a fraction

[tex]Number = \frac{112}{100}[/tex]

To represent the number as a repeating mixed number, we simply subtract 1 from the numerator

[tex]Number = \frac{112}{100 - 1}[/tex]

[tex]Number = \frac{112}{99}[/tex]

Represent as a mixed number

[tex]Number = 1\frac{13}{99}[/tex]

Hence, 1.12 as a repeating mixed number is [tex]1\frac{13}{99}[/tex]

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The circumference of a circle with a radius of 9 yards is calculated using the formula C = 2πr, with π approximated as 3.14. After substituting the values, the circumference is found to be 56.52 yards to the nearest hundredth.

To calculate the circumference of a circle with a radius (r) of 9 yards, you'll use the formula for the circumference of a circle, which is C = 2πr. Given that π (pi) is approximately 3.14, as the question suggests, you'll substitute this value and the given radius into the formula.

Step-by-step calculation:

Therefore, the circumference of the circle to the nearest hundredth of a yard is 56.52 yards.