Alicia draws a diagram to represent two forces, F1 and F2, acting on a body. The angle between the directions of the forces is 50° as shown in the diagram. Alicia notices that she can use the Law of Cosines to find the magnitude of the resultant force R in the diagram. What is the value of R?

Answers

Answer 1
Refer to the diagram shown below.

When the two forces F₁ and F₂ are added vectorially, the resultant force is R.
The angle x = 180° - 50° = 130°.

From the Law of Cosines, obtain
R² = F₁² + F₂² - 2F₁F₂ cos(130°)
Note that 2 cos(130°) = -1.2856.

Answer:
R = √(F₁²+ F₂² + 1.2856 F₁F₂ )
Alicia Draws A Diagram To Represent Two Forces, F1 And F2, Acting On A Body. The Angle Between The Directions
Answer 2
C. 70.7 is my best guess.

Related Questions

At the corner store, Nico bought 5 pencils for $0.10 each and 3 pens for $0.50 each. He used t to represent the sales tax, in dollars, that he also paid. He paid a total of $2.12, including tax.

Nico wrote this equation to represent what he paid. What errors, if any, did he make?

5(0.10) + 3(0.50) - t = 2.12
He should have multiplied 0.10 by 3 instead of 5.
He should have multiplied 0.50 by 5 instead of 3.
He should have added t instead of subtracting t.
He should have multiplied by t instead of subtracting t.

Answers

Answer:

C. He should have added t instead of subtracting t.

Step-by-step explanation:

Answer:

c

Step-by-step explanation:

Johns collection contains US, Indian and British stamos. If the stamps ratios of US to Indian stamps is 5 to 2, and the ratio of Indian stamps to British stamps is 5 to 1, what is the ratio of US to British stamps

Answers

Final answer:

The ratio of US to British stamps is 25 to 2.

Explanation:

To find the ratio of US to British stamps, we need to consider the ratios provided in the question. The ratio of US to Indian stamps is 5 to 2, and the ratio of Indian stamps to British stamps is 5 to 1. We can combine these ratios by multiplying the two ratios together. 5/2 multiplied by 5/1 is equal to 25/2. Therefore, the ratio of US to British stamps is 25 to 2.

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Each class at briarwood elementary collected at least 54 cans of food lduring the food drive.If tbere are 29 clases in the school what was the least numbet of cans collected?

Answers

the answer is 54 cans of food
Let's turn the words into numbers:
For each class → x ≥ 54
Full School → x ≥ 54(29)

If we simplify the second inequality, we get this:
x ≥ 1566

The answer to your query is x ≥ 1566. Hope this helps and have a fantastic day!

There are 365,493 blue pens in a warehouse and 549384 black pens how many pens are there in all

Answers

365,493 + 549,384 = 914,877
To find the answer you add the numbers together to find the sum. 
365,493+549,384

Your answer would be 366,042.384

I hope this helps!

Randy school requires that there are two adult chaperones for every 18 students when the students go on a field trip to the museum if there are 99 students going to the museum how many adult shop around our need it

Answers

Use a proportion.

2 adults to 18 students is as x adults to 99 students.

2/18 = x/99

18x = 2 * 99

18x = 198

x = 11

Answer: 11 adults

Evaluate 3 to the power of 3 + 6 (2 + 3/6)

Answers

if 3 + 6(2 + 3/6) is actually the power, then simplify 3 + 6(2 + 3/6) as a first step.  Must follow Order of Operations rules (PEMDAS):  mult and div BEFORE addition and subtraction. 

Thus, 3 + 6(2 + 3/6)  = 3 + 6 (15/6)
                                   = 3 + 15  =  18.

Then:  3^18 is the answer.  You could expand this if you wanted, but what would be the point of that?

At an interest rate of 8% compounded annually, how long will it take to double the following investments?
$50
$500
$1700

Answers

let's see, if the first one has a Principal of $50, when it doubles the accumulated amount will then be $100,

recall your logarithm rules for an exponential,

[tex]\bf \textit{Logarithm of exponentials}\\\\ log_{{ a}}\left( x^{{ b}} \right)\implies {{ b}}\cdot log_{{ a}}(x)\\\\ -------------------------------\\\\ \qquad \textit{Compound Interest Earned Amount} \\\\ [/tex]

[tex]\bf A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\to &\$100\\ P=\textit{original amount deposited}\to &\$50\\ r=rate\to 8\%\to \frac{8}{100}\to &0.08\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annnually, thus once} \end{array}\to &1\\ t=years \end{cases} \\\\\\ 100=50\left(1+\frac{0.08}{1}\right)^{1\cdot t}\implies 100=50(1.08)^t \\\\\\ \cfrac{100}{50}=1.08^t\implies 2=1.08^t\implies log(2)=log(1.08^t) \\\\\\ [/tex]

[tex]\bf log(2)=t\cdot log(1.08)\implies \cfrac{log(2)}{log(1.08)}=t\implies 9.0065\approx t\\\\ -------------------------------\\\\ [/tex]

now, for the second amount, if the Principal is 500, the accumulated amount is 1000 when doubled,

[tex]\bf \qquad \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\to &\$1000\\ P=\textit{original amount deposited}\to &\$500\\ r=rate\to 8\%\to \frac{8}{100}\to &0.08\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annnually, thus once} \end{array}\to &1\\ t=years \end{cases} \\\\\\ 1000=500\left(1+\frac{0.08}{1}\right)^{1\cdot t}\implies 1000=500(1.08)^t \\\\\\ [/tex]

[tex]\bf \cfrac{1000}{500}=1.08^t\implies 2=1.08^t\implies log(2)=log(1.08^t) \\\\\\ log(2)=t\cdot log(1.08)\implies \cfrac{log(2)}{log(1.08)}=t\implies 9.0065\approx t\\\\ -------------------------------[/tex]

now, for the last, Principal is 1700, amount is then 3400,

[tex]\bf \qquad \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\to &\$3400\\ P=\textit{original amount deposited}\to &\$1700\\ r=rate\to 8\%\to \frac{8}{100}\to &0.08\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annnually, thus once} \end{array}\to &1\\ t=years \end{cases}[/tex]

[tex]\bf 3400=1700\left(1+\frac{0.08}{1}\right)^{1\cdot t}\implies 3400=1700(1.08)^t \\\\\\ \cfrac{3400}{1700}=1.08^t\implies 2=1.08^t\implies log(2)=log(1.08^t) \\\\\\ log(2)=t\cdot log(1.08)\implies \cfrac{log(2)}{log(1.08)}=t\implies 9.0065\approx t[/tex]

Suzan sees a bag of marbles, she grabs a handful at random. She has seen a bag containing four red marbles, two green ones, four white ones, and three purple ones. She grabs eight of them. Find the probability of the following event, expressing it as a fraction in lowest terms. HINT [See Example 1.] She does not have all the green ones.

Answers

Final answer:

Explanation of calculating the probability of choosing 3 green marbles out of 10 from a bag with 50 marbles.

Explanation:

The probability of choosing exactly 3 green marbles if a total of 10 marbles are selected from a bag filled with 50 marbles, 15 of which are green, can be calculated as follows:

Calculate the total number of ways to choose 3 green marbles out of 15: C(15, 3).Calculate the total number of ways to choose 7 non-green marbles out of 35: C(35, 7).Find the total number of ways to choose 10 marbles out of 50: C(50, 10).Calculate the probability by dividing the product of the above two calculations by the total ways to choose 10 marbles.

Toby, a toy store buyer, ordered 2 gross rubber spiders, 60 teddy bears, and 5 dozen video games. The spiders cost 7 cents each, the bears cost 59.76 dollars per dozen, and the video games were on sale for a special price—12 for 156 dollars. What was the total cost of Toby’s order, in dollars?

Answers

Rubber spider total cost:
7 × 2 gross (1 gross = 144 units)
7 cents x 288 = 2016 cents = $20.16

Total cost of teddy bear:
59.76 x (60÷12) (1 dozen = 12 units)
59.76 x 5 = $298.80

Total cost of video games:
156 x 5 = $780.00

Total spent:
780 + 298.80 + 20.16 = $1098.96

If 4f(x)+f(5-x)=x2

What is f(x)?

Answers

We are given that [tex]4f(x)+f(5-x)=x^2[/tex].

Substitute x with 5-x, then the above equation becomes:

[tex]4f(5-x)+f(5-(5-x))=(5-x)^2[/tex], that is

[tex]4f(5-x)+f(x)=(5-x)^2[/tex]


So, we have the following system of equations:

i) [tex]4f(x)+f(5-x)=x^2[/tex]
ii) [tex]4f(5-x)+f(x)=(5-x)^2[/tex]

multiply the first equation by -4, so that we eliminate f(5-x)'s

i) [tex]-16f(x)-4f(5-x)=-4x^2[/tex]
ii) [tex]4f(5-x)+f(x)=(5-x)^2[/tex]

adding the 2 equations side by side we have:

[tex]-15f(x)=-4x^2+(5-x)^2[/tex]

expanding the binomial, and collecting same terms we have:

[tex]-15f(x)=-4x^2+(25-10x+x^2)[/tex]

[tex]-15f(x)=-3x^2-10x+25[/tex]

dividing by -5:

[tex]3f(x)=\frac{3}{5}x^2+2x-5[/tex]

dividing by 3:

[tex]\displaystyle{f(x)= \frac{1}{5}x^2+ \frac{2}{3}x-\frac{5}{3} [/tex]


Answer: [tex]\displaystyle{f(x)= \frac{1}{5}x^2+ \frac{2}{3}x-\frac{5}{3} [/tex]

Which of the following represents the zeros of the function
g(x) = x3 - 9x2 + 2x + 48 ?

A. x= -8, x= 2 , and x= -3
B. x = 8, x = -2 , and x = 3
C. x = 6, x = -4 , and x = 9
D. x = -6, x = 4 , and x = -9

Answers

g(x) = x^3 - 9x^2 + 2x + 48 ?

Probe some roots. When you use x = - 2

you will have: (-2)^3 - 9(-2)^2 + 2(-2) + 48 = -8 - 36 - 4 + 48 = 0

So, - 2 is a root

From that you can divide x^3 - 9x^2 + 2x + 48 by x + 2 and you will get

x^2 - 11x + 24

Then you can factor that: (x - 8)(x - 3)

So, the three roots are x = - 2, x = 3 and x = 8, which is the option B.

Answer: option B. x = 8, x = -2 , and x = 3
 

Owl can clean piglets house in 25 minutes. eeyore can clean piglets house in 40 minutes. how long will it take owl and eeyore to do the job if they work together?

Answers

Let us say that the task of cleaning the house is equal to 1 job. Therefore the rates are:

 

rate of Owl = 1 job / 25 minutes

rate of eeyore = 1 job / 40 minutes

 

So working together, the time is:

(1 / 25) + (1 / 40) = 1 / t

0.065 = 1 / t

t = 15.38 minutes

 

So it takes about 15.38 minutes working together.

What is the value of r, the part of the job that Marina can complete in 1 hour? 0.1 0.4 0.5 0.6

Answers

so, Katherine can do 0.1 of the job per hour. (if she needs 10 hours for the job, each hour she can do the whole divided by the time, so 1/10, which is 0.1)

if in two hours she and Marina can be done, then Marina will do 1(the whole job)-2/10 (twice as much as she can do in an hour)=0.8 of the job. So if Marina does 0.8 of the job in two hours, each hour she will do half of it: 0.4 - and this is the correct answer 

Some luggage pieces have wheels and a handle so that the luggage can be pulled along the ground. Suppose the length from the bottom of the bag to the place on the floor perpendicular to the hand on the bag is 14 inches, and the length of the bag with its handle is 19 inches. At which angle made by the bag and the floor would it be comfortable to roll the bag?

Answers

Draw a right triangle with adjacent-leg equal to the length from the bottom to the place on the floor, whose meausre is 14 inches, and the hypotenuse is 19 inches.

The trigonometric ratio cosine, relates the angle with those lengths:

cos(angle) = adjacent-leg / hypotenuse = 14 / 19

=> angle = arc cosine (14/19) = 42.5°

Answer: 42.5°

Suppose five construction companies have the ability to build a factory overseas to produce a manufactured good. The marginal cost of building a factory for each construction company is shown in the table​ below: Producer Marginal Cost Company 1 ​$1,000,000 Company 2 ​$1,250,000 Company 3 ​$1,300,000 Company 4 ​$1,350,000 Company 5 ​$1,500,000 If the market price of an overseas factory is ​$ 1 470 000 ​, what is the surplus for these five​ companies?

Answers

The surplus for the five companies is amounting to $830,000

What is the surplus for the five companies?

Producer Surplus is the difference between the price at which a producer is willing to spend and the price which he is getting from the market for his product.

The minimum price at which a producer is willing to spend is the Marginal Cost of producing that product.Therefore, Producer surplus is Market Price- Marginal CostProducer Marginal Cost Market Price Producer Surpus Company 1 1,000,000 1,470,000 (1,470,000-1,000,000)=470,000

Company 2 1,250,000 1,470,000 (1,470,000-1,250,000)=220,000

Company 3 1,300,000 1,470,000 (1,470,000-1,300,000)=170,000

Company 4 1,350,000 1,470,000 (1,470,000-1,350,000)=120,000

Company 5 1,500,000 1,470,000 (1,470,000-1,500,000)=-30,000

Total producer surplus= 470,000 + 220,000 + 170,000 + -30,000 = 830,000

The surplus for the five companies is amounting to $830,000

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Final answer:

The surplus for Companies 1, 2, and 3 is $470,000, $220,000, and $170,000 respectively, as their marginal costs are less than the market price of $1,470,000. Companies 4 and 5 do not have a surplus since their marginal costs are above the market price. The total surplus is $860,000.

Explanation:

The surplus for the five construction companies based on their marginal costs and the market price of an overseas factory can be calculated as the difference between the market price and the marginal cost for each company. Only the companies that have a marginal cost lower than the market price will experience a surplus. Given that the market price is $1,470,000:

Company 1 has a surplus of $470,000 ($1,470,000 - $1,000,000).

Company 2 has a surplus of $220,000 ($1,470,000 - $1,250,000).

Company 3 has a surplus of $170,000 ($1,470,000 - $1,300,000).

Companies 4 and 5 do not have a surplus because their marginal costs are higher than the market price. The total surplus for the three companies with a surplus is $860,000 ($470,000 + $220,000 + $170,000).

The salaries of the president and the Vice President of a certain country total $562,500 a year. If the president makes $237,400 more than the Vice President , find each of their salaries.

Answers

To do this question, you simply add what the Vice President makes to how much more the President makes. $562,500+ $237,400=799,900.

I need to solve and show work for 3x over4 divided by 5-1 over 8

Answers

3or4vxe
     4  



Is the answer 
Sounds as tho' you want to evaluate

3x
---
  4

over

5x-1
------
    8

To accomplish this, invert the 2nd fraction and then multiply:


3x     5x-1
---   * ------  = 15x^2-3x   divided by 32.
  4       8

Find an equation of the normal line to the parabola y = x2 â 9x + 7 that is parallel to the line x â 7y = 2.

Answers

Please, could you proof read your input before posting a question?    The character  " â " does not belong here.  "x2" should be written as x^2, where the "^" denotes exponentiation.

I'm taking the liberty of correcting your input:  "Find an equation of the normal line to the parabola y = x2 â 9x + 7 that is parallel to the line x â 7y = 2." may be:

Find an equation of the normal line to the parabola y = x^2 -  9x + 7 that is parallel to the line x - 7y = 2.  

How do you find the slope of a normal line to the graph of a given quadratic?  Differentiate    y = x^2 - 9x + 7:     dy/dx = 2x - 9

You can see that this slope varies with x.  You have not named an x-value here, so   I will have to stop   at   dy/dx = 2x - 9.

The slope of a line perpendicular to the tangent line is the negative reciprocal of   the slope of the tangent line, or

-1
-------   which obviously depends upon the x value you choose or are given.
(2x)

Now focus on the given line x - 7y = 2.  Solving for y, 7y =x-2.  The slope of this line is (1/7).  Thus, 

    -1            1
--------- = ----------     Cross-multiplying, -7 = 2x; x = -3.5
    2x            7

So it appears we DO have the x-value at the point of tangency on the curve.

Find the associated y-value by subst. x = -3.5 into the eq'n of the parabola.

Call it Y.

Then the eq'n of the normal line to the parabola that is parallel to x - 7y = 2

is             y-Y = (1/7)(x-[-3.5])
Final answer:

The normal line to the parabola y = x^2 - 9x + 7 that is parallel to the line x - 7y = 2 is y = -7x + 65, which was determined by finding the normal slope and point of tangency using the derivative.

Explanation:

In mathematics, the normal line to a curve at a particular point is the line that is perpendicular to the tangent of the curve at that point. First, it's important to establish that any line parallel to x - 7y = 2 would have the same slope, which in this case is 1/7. To find the normal line, we need a line that is perpendicular to this -- hence, it would have a slope of -7.

Now, to find the point of tangency, you must take the derivative of y = x^2 - 9x + 7, making it 2x - 9. Set this equal to -7 (the slope of the normal line) and solve for x, which comes out to be 8. Substituting x = 8 back into our parabola equation gives us y = -9. Therefore, our point of tangency is (8, -9).

Finally, using the point-slope form of a line formula, we can find our equation of the normal line, which is  y - (-9) = -7*(x - 8), simplifying to y = -7x + 65.

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If you put all the flowers together end to end, what would be the total length of all the flowers?

Answers

1/8 + 3(1/4) + 2(1/2) + 5/8 + 3/4 + 7/8 + 1 =
1/8 + 3/4 + 1 + 5/8 + 3/4 + 7/8 + 1 =
13/8 + 6/4 + 2 =
13/8 + 12/8 + 16/8 =
41/8 =
5 1/8 inches <==

Find the minimum and maximum values of the function subject to the given constraint. (if an answer does not exist, enter dne.) f(x, y) = x2y + x + y, xy = 5

Answers

Via Lagrange multipliers:

[tex]L(x,y,\lambd)=x^2y+x+y+\lambda(xy-5)[/tex]
[tex]L_x=2xy+1+\lambda y=0[/tex]
[tex]L_y=x^2+1+\lambda x=0[/tex]
[tex]L_\lambda=xy-5=0[/tex]

[tex]\underbrace{10}_{2xy}+1+\lambda y=0\implies \lambda=-\dfrac{11}y[/tex]
[tex]xy=5\implies y=\dfrac5x\implies\lambda=-\dfrac{11}5x[/tex]

[tex]\impliesx^2+1+\left(-\dfrac{11}5x\right)x=0\implies x^2=\dfrac56\implies x=\pm\sqrt{\dfrac56}[/tex]
[tex]xy=5\implies y=\pm\sqrt{30}[/tex]

At these points, we get local minima of [tex]f\left(\pm\sqrt{\dfrac56},\pm\sqrt{30}\right)=\pm2\sqrt{30}[/tex].

- - -

Another way to do this is to make [tex]f(x,y)[/tex] a function independent of [tex]y[/tex], which is made possible by the constraint.

[tex]xy=5\implies y=\dfrac5x[/tex]
[tex]\implies f(x,y)=f\left(x,\dfrac5x\right)=F(x)=6x+\dfrac5x[/tex]
[tex]\implies F'(x)=6-\dfrac5{x^2}=0\implies x=\pm\sqrt{\dfrac56}[/tex]

and so on.

A line has a slope of -2/3 and a y-intercept of (0, 3). What is the value of y when x = 4?

Answers

recall the slope-intercept form.

ahemmm so, we know the slope, and we also know the y-intercept, thus the equation of that line is

[tex]\bf y=\stackrel{slope}{-\cfrac{2}{3}}x\stackrel{y-intercept}{+3} \\\\\\ \textit{when x = 4, what is \underline{y}?}\qquad y=-\cfrac{2}{3}(4)+3\implies y=-\cfrac{8}{3}+3 \\\\\\ y=\cfrac{-8+9}{3}\implies y=\cfrac{1}{3}[/tex]

If an article costs a store $7.45 and if it sells the article for $9.95, what percentage (to the nearest tenth) markup is it using?

Answers

subtract to find the difference:

9.95 - 7.45 = 2.50

 divide 2.50 by cost price to get mark up percentage

2.50 / 7.45= 0.3355

= 33.6 percent to the nearest tenth

Answer:

Markup Percentage is 33.56 %

Step-by-step explanation:

Given: Cost of an article = $ 7.45

           Selling price of the article = $ 9.95.

To find: Markup percentage or profit percentage

Clearly Selling price is greater we have profit in this case.

Profit amount = 9.95 - 7.45 =  $ 2.50

Profit percentage = [tex]\frac{2.50}{7.45}\times100=33.5570469799=33.56[/tex] %

Therefore, Markup Percentage is 33.56 %

last week, several gas stations in a neighborhood all charged the same price for a gallon of gas.The table below shows how much gas prices have changed from last week to this week.

a. Order the numbers in the table from least to greatest.

b. Which gas station has the cheapest gas this week?

c. Critical Thinking. Which gas station changed their price the least this week?

Gas and Samson. Star
Go. Gas. Gas
-6.6. 5.8. -6 3/4


Corner store. tip top
27/5. shop
-5 5/8

Answers

To compare the numbers, we'd better convert the fractions into decimals. 

–6 3/4 = –6.75
27/5 = 5.4
–5 5/8 = –5.625

Now that the numbers are –6.6, 5.8, –6.75, 5.4 and –5.625.
a) A negative number is always less than a positive number. In addition, a negative with a larger magnitude would be less. Like –4 < –3. So the order from least to greatest is –6.75 < –6.6 < –5.625 < 5.4 < 5.8. In other words, –6 3/4 < –6.6 < –5 5/8 < 27/5 < 5.8.

b) A negative change means that the gas price decreased. The gas station that decreased the gas price the most is the Star gas since the –6 3/4 is the least number in the list.

c) The changes in prices can be compared in relation to each other based on their magnitude, which is the value without the sign. For example, the magnitude of –4 is 4. The magnitudes of the changes in prices are 6.6, 5.8, 6.75, 5.4 and 5.625. So the least change is 5.4, that is, 27/5. So the Corner Store changed the price the least. 

Final answer:

Without the correctly formatted data, we cannot give direct answers. However, the answers would come from ordering the data from least to greatest, identifying the least positive or most negative change as the cheapest gas, and the smallest change as the least change in price.

Explanation:

Unfortunately, the question you provided is a bit unclear because the table is not formatted correctly. However, it's clear that you're asked to analyze a set of data, which refers to changes in gas prices at several gas stations. Usually, to order the numbers from least to greatest, you would list them in ascending numerical order, taking into account whether they are positive or negative, with negative numbers being less than positive numbers. The gas station with the cheapest gas this week would be the one with the least positive change or the greatest negative change. The gas station that changed their price the least would be the gas station with the smallest change in price, whether positive or negative. However, without the correct formatting of data, I am unable to provide specific answers. It's always important to check your data for clarity in order to perform accurate mathematical analyses. These principles of data analysis and number order are crucial skills in your mathematical education.

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f(x) = x2 + 5x – 1 is shifted 3 units left. The result is g(x). What is g(x)?

A. g(x) = (x – 3)2 + 5(x – 3) – 1
B. g(x) = x2 + 5x + 2
C. g(x) = (x + 3)2 + 5x – 1
D. g(x) = (x + 3)2 + 5(x + 3) – 1

Answers

D. When you shift left you add the units to all x because the x is what shifts. Even though you moved left, it is positive. If you move right , it is minus.

Answer:

g(x) =  (x+3)² + 5(x+3) – 1.

Step-by-step explanation:

Given  : f(x) = x² + 5x – 1 is shifted 3 units left.

To find : The result is g(x). What is g(x).

Solution : We have given that

f(x) = x² + 5x – 1  is shifted 3 units left.

By the transformation rule : If f(x) →→ f(x +h) shifted by h unit left .

f(x) = x² + 5x – 1 is shifted 3 units left.

Here , h = 3

Then g(x) =  (x+3)² + 5(x+3) – 1.

Therefore,  g(x) =  (x+3)² + 5(x+3) – 1.

brainleiest!!! What is the unit rate for 4543.08 km in 52.4 h? Enter your answer, as a decimal, in the box. km/h

Answers

(52.4) / (4543.08) = 0.0115 hour per kilometer  

(4543.08) / (52.4) = 86.7 km per hour 

Answer:

86.7

Step-by-step explanation:

you divide 4543.08 by 52.4

Benny wants to put a rectangular fence in his yard, and he wants the length of the fence to be 5 less feet than twice its width. He also found that every foot of fencing will cost $3.16. The total cost of the fence is C = 3.16(6w - 10), where w is the width of the fence. What does 6w - 10 represent?

Answers

6w-10 represents the total amount of fence will need to complete the rectangle of fence in his yard. The fence will need two lengths and 2 widths to complete the rectangle. If the width is w, and the length is 2w-5, then the total for the rectangle would be w+w+2w-5+2w-5 which simplifies to 6w-10.

PLEASE HELP ASAP DUE IN A DAY What is the unit rate for 768.57 m 41.1 h? Enter your answer, as a decimal, in the box.

Answers

The unit rate for 768.57 meters in 41.1 hours is approximately 18.68 meters per hour. This calculation is derived by dividing the distance by the time to find the rate of movement.

To find the unit rate, divide the distance by the time:

[tex]\[ \text{Unit rate} = \frac{\text{Distance}}{\text{Time}} \][/tex]

[tex]\[ \text{Unit rate} = \frac{768.57 \, \text{m}}{41.1 \, \text{h}} \][/tex]

[tex]\[ \text{Unit rate} \approx \frac{768.57}{41.1} \, \text{m/h} \][/tex]

[tex]\[ \text{Unit rate} \approx 18.68 \, \text{m/h} \][/tex]

So, the unit rate is approximately 18.68 meters per hour.

Over the last three evenings, Raina received a total of 83 phone calls at the call center . The first evening, she received 7 more calls than the third evening. The second evening, she received 2 times as many calls as the third evening. How many phone calls did she receive each evening ?

Answers

x = 1st evening, y = 2nd evening, z = 3rd evening

x + y + z = 83
x = z + 7
y = 2z

z + 7 + 2z + z = 83
4z + 7 = 83
4z = 83 - 7
4z = 76
z = 76/4
z = 19 <=== 3rd evening calls

x = z + 7
x = 19 + 7
x = 26 <=== 1st evening calls

y = 2z
y = 2(19)
y = 38 <=== 2nd evening calls

how do i calculate an estimated regression line with the information
n=12, ∑x=66, ∑y=588, ∑xy=2244, ∑x2=396

Answers

The regression line is
y = ax + b
where
a = [(Σy)(Σx²) - (Σx)(Σxy)]/D
b = [n(Σxy) - (Σx)(Σy)]/D
D = n(Σx²) - (Σx)²

Therefore,
D = 12(396) - 66² = 396
a = [588*396 - 66*2244]/396 = 214
b = [12*2244 - 66*588]/396 = -30

Answer:
The regression line is y = 214x - 30

If the equation were y=40x+70.What would the x-intercept be? Plz...Help!?!

Answers


[tex]( - \frac{7}{4} .0)[/tex]
the period is a comma
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