how wide is a rectangular strip of land with length 6 mi and area 48 square mi? find the perimeter of the rectangular strip of land.
Final answer:
The width of the rectangular strip of land is 8 miles. The perimeter of the strip is 28 miles.
Explanation:
To find the width of a rectangular strip of land with a length of 6 miles and an area of 48 square miles, we use the formula for the area of a rectangle, which is Area = length × width. Since the area and the length are given, the width can be calculated as Area / length, which is 48 square miles/6 miles = 8 miles wide.
Now, to find the perimeter of the rectangular strip of land, we use the formula Perimeter = 2(length + width). Plugging in the given length of 6 miles and the calculated width of 8 miles, the perimeter equals 2(6 miles + 8 miles) = 2 × 14 miles = 28 miles.
Which of the following correctly uses absolute value to show the distance between −70 and 13? A. |−70 − 13| = |−83| = −83 units B. |−70 − 13| = |−83| = 83 units C. |−70 + 13| = |−57| = 57 units D.|−70 + 13| = |−57| = −57 units.Please help I am in a time limit!!!!
Answer:
|−70 − 13| = |−83| = −83 units
Step-by-step explanation:
The following correctly uses absolute value to show the distance.
I took the test too
What is -1.1 repeating as a fraction
in the diagram, ray OT bisects angle SOU, measure of angle UOV equals 35 and measure of angle YOW equals 120 find the measure of each angle
Final Answers:
m∠ZOY = 60°
m∠ZOW = 180°
m∠VOW = 60°
m∠SOU = 190°
m∠TOU = 95°
m∠ZOT = 85°
Here's a step-by-step solution with the final answers:
1. Identify the given angles:
m∠UOV = 35°
m∠YOW = 120°
OT bisects ∠SOU
2. Find m∠VOW:
∠VOW and ∠YOW are supplementary angles because they form a straight line.
m∠VOW = 180° - m∠YOW = 180° - 120° = 60°
3. Find m∠ZOY:
∠ZOY and ∠VOW are vertical angles, so they are congruent.
m∠ZOY = m∠VOW = 60°
4. Find m∠ZOW:
∠ZOW and ∠YOW are adjacent angles that share a common side (OW).
m∠ZOW = m∠ZOY + m∠YOW = 60° + 120° = 180°
5. Find m∠SOU:
Since OT bisects ∠SOU, m∠TOU = 1/2 * m∠SOU.
We'll find m∠TOU later, so keep this relation in mind.
6. Find m∠TOU:
∠TOU and ∠UOV are adjacent angles that share a common side (OU).
m∠TOU = m∠VOW + m∠UOV = 60° + 35° = 95°
7. Find m∠SOU (using the relation from step 5):
m∠SOU = 2 * m∠TOU = 2 * 95° = 190°
8. Find m∠ZOT:
∠ZOT and ∠TOU are supplementary angles because they form a straight line.
m∠ZOT = 180° - m∠TOU = 180° - 95° = 85°
Final Answers:
m∠ZOY = 60°
m∠ZOW = 180°
m∠VOW = 60°
m∠SOU = 190°
m∠TOU = 95°
m∠ZOT = 85°
The probable question is in the image attached.
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The lengths of a rectangle are 2x and x – 3. A triangle has lengths x, x – 2 and x + 4. The rectangle and triangle have the same perimeter.
Solve for x.
0.6x-5=0.1x+7
The solution to the equation 0.6x - 5 = 0.1x + 7 is x = 24.
To solve the equation 0.6x - 5 = 0.1x + 7 for x, we need to isolate the variable x on one side of the equation. Here's the step-by-step explanation:
Step 1: Simplify the equation
Combine like terms on both sides of the equation.
0.6x - 0.1x - 5 = 0.1x - 0.1x + 7
0.5x - 5 = 7
Step 2: Move the constant term to the other side
To isolate the variable x, we want to get rid of the constant term on the same side as x.
0.5x - 5 + 5 = 7 + 5
0.5x = 12
Step 3: Solve for x
Now, we'll solve for x by dividing both sides of the equation by the coefficient of x, which is 0.5.
(0.5x)/0.5 = 12/0.5
x = 24
So the solution to the equation 0.6x - 5 = 0.1x + 7 is x = 24.
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Step-by-step explanation:
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Create and solve equations, showing your work. You must create the equations and show the steps required to solve them.
Your portfolio must include a minimum of the following types of equations:
One one-step equation
One equation that contains fractions
One equation with decimals
One real-world problem that is solved by an equation
One-step equation is 4y=64, equation contains fractions is 3x=24/5, equation with decimals is 9x+0.3=17.7 and equation for real world problem is y=1x+2.
What is the equation of variable?The variable is the unknown part of the equation. Variable changes with change in the quantities for any situation.
One one-step equationThe one step-equation is written below.
[tex]4y=64[/tex]
Divide both side with 4,
[tex]y=16[/tex]
The equation is solved in one-step.
One equation that contains fractions.The following equation is the equation which contains the fraction,
[tex]3x=\dfrac{24}{5}[/tex]
Divide both side with number 3,
[tex]x=\dfrac{24}{5\times3}\\x=\dfrac{8}{5}[/tex]
One equation with decimals-The following equation is the equation which contains the decimals,
[tex]9x+0.3=17.7[/tex]
Subtract both side with decimal number 0.3,
[tex]9x+0.3=17.7\\9x=17.7-0.3\\9x=18[/tex]
Divide both side with number 9,
[tex]x=2[/tex]
One real-world problem that is solved by an equationA taxi driver charge $1 for the a mile of a taxi ride and one time booking charge $2. The equation for this is given as,
[tex]y=1x+2[/tex]
Here in the variable (y) represent the total charge of taxi and variable (x) represent the number of rides the taxi travelled.
Thus, the one-step equation is 4y=64, equation contains fractions is 3x=24/5, equation with decimals is 9x+0.3=17.7 and equation for real world problem is y=1x+2.
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