Amersham station is the highest station in the London Tube at 147 meter above sea level. Waterloo station is the lowest station at 21 meters below sea level. What is the height difference?

Answers

Answer 1

Final answer:

The height difference between Amersham station (147 meters above sea level) and Waterloo station (21 meters below sea level) is 168 meters.

Explanation:

To find the height difference between Amersham station, which is the highest station in the London Tube at 147 meters above sea level, and Waterloo station, the lowest at 21 meters below sea level, we simply add the two values together, treating the below sea level as a negative altitude.

147 meters (Amersham altitude above sea level) + (-21 meters) (Waterloo altitude below sea level) = 168 meters.

Therefore, the height difference between Amersham and Waterloo stations is 168 meters.


Related Questions

Can someone factor this problem for me?

Answers

your factored answer will be

(3x-4y) (x-5y)

hope this helps
3x² - 19xy + 20y² = 
3x² - 4xy - 15xy + 20y² = 
x(3x-4y) - 5y(3x-4y) = 
(3x-4y)(x-5y)

evaluate 2^-3
No, there are no answer choices, but it has to be in fraction form.

Answers

The Fraction of 2^-3 is 1/8 

I'm not sure what this is exactly?

Answers

[tex]_nC_k=_nC_{n-k}[/tex]

so
[tex]_{100}C_{98}=_{100}C_{100-98}=_{100}C_2=4,950[/tex]
[tex]\bf _nC_r=\cfrac{n!}{r!(n-r)!}\\\\\\ _{100}C_2=\cfrac{100!}{2!(100-2)!}\qquad\qquad _{100}C_{98}=\cfrac{100!}{98!(100-98)!}[/tex]

3 -1 ___ 1/4 which one is the correct answer.

=

<

>

Answers

3-1 = 2

 2 is greater than 1/4

 so > is the answer

The Answer To This Problem Is <

What number must be added to the expression below to complete the square?

x^2+3x

A. 9
B. 9/4
C. 3/2
D. 3

Answers

B. (b/2)^2 is 9/4. There

I think it is c or D but it should be C


hope that help

[I don't think it did lol ]


BMK

Daria applied a transformation to triangle ABC to obtain triangle A′B′C′. The two triangles are not congruent. Which of the following could be the transformation Daria applied?

Answers

Daria could have applied dilation.

A sandwich shop offers ham, turkey, tuna, chicken salad, and roast beef. It has Swiss, American, and provolone cheese. You can order a sandwich on white, wheat, or rye bread. If a person orders a sandwich and chooses a meat, cheese, and bread at random, how many sandwich choices are there?

Answers

5 different meats

3 different cheeses

3 different breads

5x3x3 = 15*3 = 45

 there are 45 choices

Final answer:

The sandwich shop offers a total of 45 different sandwich combinations based on the given options of meats, cheeses, and breads. Each sandwich consists of one type of each category.

Explanation:

The question asked is related to the concept of combinations in mathematics. It gives a variety of choices for making a sandwich - 5 types of meats, 3 types of cheeses, and 3 types of breads. Assuming that each sandwich will have one meat, one cheese, and one type of bread, we can calculate the total combinations by multiplying the number of options in each category together. Combinations are used when the order of selection does not matter.

So, the total number of sandwich combinations would be 5 (meats) * 3 (cheeses) * 3 (breads) = 45 different sandwich choices.

Learn more about Sandwich Combinations here:

https://brainly.com/question/29295486

#SPJ12

A blimp is 1100 meters high in the air and measures the angles of depression to two stadiums to the west of the blimp. If those measurements are 75.2° and 17.9°, how far apart are the two stadiums?

Answers

tanα=height/distance

d=h/tanα

d1=1100/tan17.9

d2=1100/tan75.2

So the distance between them is:

d=d1-d2

d=1100/tan17.9-1100/tan75.2 meters

d≈3115.03 m  (to nearest hundredth of a meter or centimeter)

The angle of depression represents the angle from a horizontal layout to a lower surface. The distance between the two stadiums is 3115.1 meters

The given parameters have been illustrated using the attached image of triangles.

The stadiums are represented with A and B.

First, calculate distance BO using:

[tex]\tan T =\frac{BO}{TO}[/tex]

Where:

[tex]\angle T = 90 -75.2 = 14.8[/tex]

[tex]TO = 1100[/tex]

So, we have:

[tex]\tan(14.8^o) = \frac{BO}{1100}[/tex]

Make BO the subject

[tex]BO = 1100 * \tan(14.8^o)[/tex]

[tex]BO = 1100 * 0.2642[/tex]

[tex]BO = 290.62[/tex]

Next, calculate distance AO using:

[tex]\tan T =\frac{AO}{TO}[/tex]

But in this case:

[tex]\angle T = 90 -17.9 = 72.1[/tex]

[tex]TO = 1100[/tex]

So, we have:

[tex]\tan(72.1^o) = \frac{AO}{1100}[/tex]

Make AO the subject

[tex]AO = 1100 * \tan(72.1^o)[/tex]

[tex]AO = 1100 * 3.0961[/tex]

[tex]AO = 3405.71[/tex]

The distance AB between the 2 stadiums is:

[tex]AB = AO - BO[/tex]

[tex]AB = 3405.71-290.61[/tex]

[tex]AB = 3115.1[/tex]

Hence, the distance between the 2 stadiums is 3115.1 meters.

Read more about angles of depression at:

https://brainly.com/question/13697260

What is the sum of the first five terms of a geometric series with a1 = 10 and r = 1/5?

Answers

a₁ = 10
r = 1/5

Sum of GP = a₁(1-rⁿ)/(1-r), where a₁ = 1st term; n= rank and r = common ratio

Sum = 10[1-(1/5)⁵] /(1-1/5)
Sum = 10(1-1/3250)/(4/5)
Sum = 1562/125

Answer: 12.496

Step-by-step explanation:

The formula to find the sum of geometric progression is given by :-

[tex]S_n=\dfrac{a(1-r^n)}{1-r}[/tex]

Given : The first term : [tex]a_1=10[/tex]

Common ratio = [tex]r=\dfrac{1}{5}=0.2[/tex]

Then , the sum of first five terms of a geometric series is given by :-

[tex]S_5=\dfrac{10(1-(0.2)^5)}{1-0.2}=12.496[/tex]

Hence, the sum of the first five terms of given geometric series =12.496

what is the area of a triangle that has a base of 8 yd and height of 3 yd

Answers

area = 1/2 x b x h

1/2 x 8 x 3 = 12

area is 12 square yards

Find the equation for the tangent line of f(x)=−3x2−7x+3 at x=3.

Answers

hello : 
the equation for the tangent line at point : A(x' , y' ) is :
y - y' = f'(x') (x-x')........f'(x') the slope
in this exercice : 
f(x) = -3x²-7x+3  and : x' = 3
y' = f(3) = -3(3)²-7(3) +3 =- 45
but : f'(x) = -6x-7   ...( derivate of : f(x) )
f'(3) = -6(3) -7 = - 25

the equation for the tangent line is : y - (-45) = -25(x-3)
y = -25x+30

Temperature dropped from 11 below zero to 4 below zero how much did the temperature drop

Answers

it would actually rise.

-11 + 4 = 6

-11 -10 -9 -8 -7 -6 -4 -3 -2 -1 0
   l ------------------->  l

it rose 6 degrees (or dropped -6 degrees, to match the question) :)

in order to use a normal distribution to calculate confidence intervals for p, what conditions on np and nq need to be satisfied? Select one: a. n and q must be integers b. n must be positive c. np>10 and nq<0 d. np and nq must be > 5

Answers

Final answer:

To use normal distribution for calculating confidence intervals for proportion p, both np and nq must be greater than or equal to 5.

Explanation:

In order to use a normal distribution to calculate confidence intervals for a population proportion p, the conditions on np and nq need to be such that both np ≥ 5 and nq ≥ 5. These conditions are necessary because they ensure that the shape of the binomial distribution is similar to that of a normal distribution, which allows for the approximation of the binomial distribution by the normal distribution. When performing a hypothesis test of a single population proportion, it is imperative that the sample data meet these conditions to ensure a valid test. Therefore, the correct answer to the question is d. np and nq must be > 5.

Multiply 3 [ 1 5 -5 6 0 0 ]

Answers

Simply multiply the number outside the brackets with each one inside it..

3 [ 1 5 -5 6 0 0 ]
3 x 1 = 3
3 x 5 = 15
3 x -5 = -15
3 x 6 = 18
3 x 0 = 0
3 x 0 = 0
[ 3 15 -15 18 0 0 ]

[ 3 15 ]
[ -15 18 ]
[ 0 0]

The answer is B and I hope I explained this well for you.

which other angle must also measure 130°

Answers

opposite angles are identical so if angle 1 = 130

 than angle 3 is also 130 degrees

Answer:

Angle 3

Step-by-step explanation:

we know that

[tex]m<1=m<3[/tex] -----> by vertical angles

we have

[tex]m<1=130\°[/tex]

therefore

[tex]m<3=130\°[/tex]

The length and width of a rectangle are 4.9^9 cm and 5.3^3 cm, respectively. What is the approximate area of the rectangle, using only positive exponents?
A) 5^6cm^2
B) 4^6cm^2
C) 5^12cm^2
D) 4^12cm^2

Answers

approximate 
L = 4.9^9 cm = 5^9 cm
W = 5.3^3 cm = 5^3 cm

Area = L x W
Area = 5^9 x 5^3 = 5^12 cm^2

answer
C) 5^12 cm^2

What is the quotient (3x3 + 10x2 + 10x + 4) ÷ (x + 2)?


a. 3x2 + 16x + 42
b. 3x2 + 4x + 2
c. 3x2 − 16x + 42
d. 3x2 − 4x + 2

Answers

the correct choice is  B
3x^2 + 4x + 2

Answer:

Option B is correct.

[tex]3x^2+4x+2[/tex].

Step-by-step explanation:

We are asked to find the quotient obtained by dividing the expression [tex](3x^3+10x^2+10x+4)[/tex] by the expression [tex](x+2)[/tex]

We can also write this expression as i.e. we are asked to find the value of the expression:

[tex]\dfrac{3x^3+10x^2+10x+4}{x+2}[/tex]

We can write the expression on the numerator as:

[tex]3x^3+10x^2+10x+4=(3x^2+4x+2)(x+2)[/tex]

Hence,

[tex]\dfrac{3x^3+10x^2+10x+4}{x+2}=\dfrac{(3x^2+4x+2)(x+2)}{x+2}[/tex].

Hence,

[tex]\dfrac{3x^3+10x^2+10x+4}{x+2}=3x^2+4x+2[/tex].

Hence, option B is correct.

Hence, the quotient is:

[tex]3x^2+4x+2[/tex].

If the value of 2x3 is 2, then what is the value of x?

Answers

If the expression is 2*x*3, x must be 1/3 in order to cancel out the 3 which would leave the 2.
x = 1, -1 .
____________________________
  Given:  2x³ = 2 ;  Divide each side of the equation by "2" ;

               [2x³] / 2 = 2 / 2 ; 

    to get:   x³ = 1 ;  

Now, take the "cube root" of EACH SIDE of the equation; to isolate "x" on ONE SIDE of the equation; and to solve for "x" ;

   ∛(x³)  = ∛1  ;

      x = 1, -1 .
____________________________________________

place a square on a coordinate graph and label each vertex with variables. prove that the diagonals of a square are congruent and perpendicular to each other.

Answers

Final answer:

To prove that the diagonals of a square are congruent and perpendicular, label the vertices of a square on a coordinate grid and calculate the slopes and lengths using the slope formula and distance formula respectively. The diagonals have slopes of +1 and -1, proving they are perpendicular, and they have equal lengths, proving they are congruent.

Explanation:

To prove that the diagonals of a square are congruent and perpendicular, we place a square with its vertices on a coordinate grid and label each vertex with variables.

Let's consider a unit square where c = 1 for simplicity, which means the length of each side is 1 unit. Place the square so that one vertex is at the origin (0,0), and label the vertices A(0,0), B(1,0), C(1,1), and D(0,1).

The diagonal AC will have endpoints at A(0,0) and C(1,1), and diagonal BD will have endpoints at B(1,0) and D(0,1). The slope of diagonal AC is (1 - 0)/(1 - 0) = 1, and the slope of diagonal BD is (1 - 0)/(0 - 1) = -1. Since the product of their slopes is -1 (1 * -1 = -1), this proves that they are perpendicular to each other.

To show they are congruent, we calculate their lengths using the distance formula: the distance between two points (x1,y1) and (x2,y2) is √[(x2 - x1)² + (y2 - y1)²]. Applying this to AC and BD reveals both lengths to be √[(1-0)² + (1-0)²] = √[1 + 1] = √2, proving the diagonals are congruent.

If f(x) is an odd function, which statement about the graph of f(x) must be true?
It has rotational symmetry about the origin.
It has line symmetry about the line y = –x.
It has line symmetry about the y-axis.
It has line symmetry about the x-axis.

Answers

An odd function, by definition, is a function that is symmetric about the origin.

An even function, by definition, is a function that is symmetric with respect to the y-axis.

Since the question says that f(x) is an odd function, it has rotational symmetry about the origin. First option is correct.


ANSWER: symmetric about the origin.

Answer:It has rotational symmetry about the origin.

Step-by-step explanation:

An odd function : is a function that is symmetric about the origin.

An even function : is a function that is symmetric with respect to the y-axis.

Since , f(x) is an odd function, it has rotational symmetry about the origin.

its meaning that its graph remains unchanged after rotation of 180 degrees about the origin.

Therefore, It has rotational symmetry about the origin.

Can someone please explain me this

Answers

sure for a 4*2 is 8 so 3*2 = x aka x=6
u r dealing with proportions...

x/8 = 3/4
cross multiply...multiply denominator of one, by numerator of the other and vice-versa
(4)(x) = (3)(8)
4x = 24
x = 24/4
x = 6

sub it back into the proportion
6/8 = 3/4.....notice that if u reduce 6/8, it equals 3/4. Proportions are nothing but equivalent fractions.
====================
2/5 = x/40
cross multiply
(5)(x) = (40)(2)
5x = 80
x = 80/5
x = 16

check..
2/5 = 16/40... u can aslo cross multiply to check
(2)(40) = (5)(16)
80 = 80...correct
===================
1/8 = x/12
cross multiply
(8)(x) = (1)(12)
8x = 12
x = 12/8
x = 3/2

check...
1/8 = (3/2) / 12
cross multiply
(8)(3/2) = (12)(1)
24/2 = 12
12 = 12 (correct)
=================
I am gonna leave u with the last one....u can do this :)




An amusement park charges $9.00 for admission $4.00 per ride. Write an equation that gives the cost in dollars as a function of number of rides

Answers

a $9 fee plus $4 oper ride

let T = total cost

X= number of rides

T=9.00+4.00X

With y = the total cost, and x = # of rides, we get the equation y=4x+9 where 9 is the fixed cost of the admission, the 4 is the cost per ride.

Determine if the graph is symmetric about the x-axis, the y-axis, or the origin. r = -5 - 5 cos θ

Answers

It is symmetric about the x-axis

Answer:

The graph of polar equation is symmetric about the x-axis.

Step-by-step explanation:

The given polar equation is

[tex]r=-5-5\cos \theta[/tex]

If [tex](r,\theta)[/tex] and [tex](r,-\theta)[/tex] lie on the graph then the graph of polar equation is symmetric about the x-axis.

Substitute [tex]\theta=-\theta[/tex] in the given equation.

[tex]r=-5-5\cos (-\theta)[/tex]

Cosine is an even function.

[tex]r=-5-5\cos \theta[/tex]                   [tex][\cos (-\theta)=\cos (\theta)][/tex]

Point [tex](r,-\theta)[/tex] lies on the graph, therefore the graph of polar equation is symmetric about the x-axis.

A rectangle has a length of the cube root of 81 inches and a width of 3 to the 2 over 3 power inches. Find the area of the rectangle.

3 to the 2 over 3 power inches squared
3 to the 8 over 3 power inches squared
9 inches squared
9 to the 2 over 3 power inches squared

Answers

[tex]A= \sqrt[3]{81}*3^{ \frac{2}{3} }= \sqrt[3]{3^4}*3^{ \frac{2}{3} } = 3^{ \frac{4}{3} }*3^{ \frac{2}{3} }=3^{ \frac{4}{3} + \frac{2}{3} }=3^2=9 \ [/tex]

9 inches squared

Answer:

9 square inches.

Step-by-step explanation:

We have been given that a rectangle has a length of the [tex]\sqrt[3]{81}[/tex] inches and a width of [tex]3^{\frac{2}{3}}[/tex] power inches. We are asked to find the area of given rectangle.

We know that area of rectangle in length times width of rectangle.

[tex]\text{Area of rectangle}=\sqrt[3]{81}\times 3^{\frac{2}{3}}[/tex]

We can write 81 as [tex]3^4[/tex] as:

[tex]\text{Area of rectangle}=\sqrt[3]{3^4}\times 3^{\frac{2}{3}}[/tex]

Using exponent rule [tex]\sqrt[n]{a^m}=a^{\frac{m}{n}}[/tex], we can write [tex]\sqrt[3]{3^4}=3^{\frac{4}{3}}[/tex].

[tex]\text{Area of rectangle}=3^{\frac{4}{3}}\times 3^{\frac{2}{3}}[/tex]

Using exponent rule [tex]a^b\cdot a^c=a^{b+c}[/tex], we will get:

[tex]\text{Area of rectangle}=3^{\frac{4}{3}+\frac{2}{3}}[/tex]

[tex]\text{Area of rectangle}=3^{\frac{4+2}{3}}[/tex]

[tex]\text{Area of rectangle}=3^{\frac{6}{3}}[/tex]

[tex]\text{Area of rectangle}=3^{2}[/tex]

[tex]\text{Area of rectangle}=9[/tex]

Therefore, the area of given rectangle is 9 square inches.

Use the graph below to answer the following question:

graph of parabola going through negative 4, 4, negative 1, 5, and 1, negative 1

What is the average rate of change from x = –4 to x = 1?

–3
–1
0
1

Answers

Average change = (final y - start y ) / (final x - start x ) = (-1-4)/(1-(-4) ) = -5/5=-1!

Second one!

Your answer should be

-1


Don't forget to MARK BRAINLIEST!! <3 :)

A skier is trying to decide whether whether or not to buy a season ski pass. A daily pass cost 67. A season ski pass costs 350. The skier would have to rent skis with either pass for 25 per day. How many days would the skier have to go skiing in order to make the season pass cost the same as the daily pass option.

Write an expression using words to represent the cost of a daily pass. Write the algebraic expression. Write an expression using words to represent the cost of a season pass. Write the algebraic expression
How can you compare the cost of a daily pass with the cost of a season pass algebraically?

Answers

The total cost of using daily passes is the number of days the skier goes skiing times 67.
The algebraic expression for this is 67n (n=the number of days).

 The cost of a season pass is 350. If the number of days the skier skis times 67 equals 350 then the cost for both options is the same.
67n=350
n=350/67

 n=5.22

If the skier goes skiing 5 times or fewer using daily passes costs less. If the skier goes skiing 6 times or more a season pass costs less.

What is the slope of the line that is perpendicular to the line whose equation is 2x + y = 4.

Answers

peprendicular lines have slopes that multiply to get -1

y=mx+b
m=slope

2x+y=4
minus 2x
y=-2x+4
slope is -2

-2 times what=-1
what=-1/-2
what=1/2

the slope is 1/2

Answer:

The slope of the line that is perpendicular to the line whose equation is 2x + y = 4 is   [tex]\frac{1}{2}[/tex].

Step-by-step explanation:

Given : Equation is 2x + y = 4.

To find : What is the slope of the line that is perpendicular to the line.

Formula used : equation of line y =  m[tex]m_{1}[/tex] x + c.

Solution : We have 2x + y = 4.

Rearranging the equation :  y = - 2x + 4.

On comparing   m[tex]m_{1}[/tex] = - 2.

Condition for  slope of the line that is perpendicular to the line :

      m[tex]m_{1}[/tex] × m[tex]m_{2}[/tex] = -1 .

So,       -2 × m[tex]m_{2}[/tex] = -1 .

On dividing by 2 both we get ,

  m[tex]m_{2}[/tex] = [tex]\frac{1}{2}[/tex].

Therefore, The slope of the line that is perpendicular to the line whose equation is 2x + y = 4 is   [tex]\frac{1}{2}[/tex].

I SERIOUSLY NEED HELP HERE!!!!!


PLEASE SOMEONE HELP ME ON THIS!!!!!

NEED MAJOR HELP HERE CALCULATOR QUIT ON ME!!!!!!!
scientific calculator of a TI83 or TI84  ( does that help?)
Use the data below to find the correlation coefficient. (Remember to choose DiagnosticOn on your calculator.)




x        y
270   70
230   75
250   68
310   82
285   80
275   76
281   73
267   81
252   72
246   79

The correlation coefficient is _____. Round to the nearest thousandth.

THESE ARE MY OPTIONS:
a. 0.438
b. 0.192
c. 0.5
d. 0.720

Answers

The plot of the data and the regression line is shown in the figure below.
The best straight line is
y = 51.0686 + x 0.092x

The correlation coefficient is 0.192.

Answer: b

The equation of a line is 2(y+1)=10x+3
The y-intercept of the line is ___, and the slope of the line is ___.

Answers

2y+2=10x+3
2y=10x+1
y=5x+1/2
y intercept is (0,1/2)
slope is 5

Answer:  The answer is 0.5 and 5.

Step-by-step explanation: The given equation of the line is

[tex]2(y+1)=10x+3.[/tex]

We are to find the y-intercept and the slope of the given line.

We know that the slope-intercept form of a line is given by

y = mx + c, where, 'm' is the slope and 'c' is the y-intercept of the line.

We have

[tex]2(y+1)=10x+3\\\\\Rightarrow 2y+2=10x+3\\\\\Rightarrow 2y=10x+3-2\\\\\Rightarrow 2y=10x+1\\\\\Rightarrow y=5x+0.5.[/tex]

Therefore, c = 0.5 and m = 5.

Thus, the y-intercept of the line is 0.5 and the slope is 5.

Linda is putting money into a savings account. She starts with $450 in the savings account, and each week she adds $70 .

Let S represent the total amount of money in the savings account (in dollars), and let W represent the number of weeks Linda has been adding money. Write an equation relating S to W . Then use this equation to find the total amount of money in the savings account after 19 weeks.

Answers

450+added

S=450+70W would be the equation

then afet 19 weeks
W=19
S=450+70(19)
S=450+1330
S=1780



equation is
S=70W+450
after 19 weeks, has 1780
The equation is
S (w)=450+70w

The total amount of money in the savings account after 19 weeks is
S (19)=450+70×19
S (19)=1,780
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