A(n) _________ is responsible for collecting light rays previously focused on the specimen.

Answers

Answer 1
objective lens are responsible
Answer 2

Answer:

Objectives lens are responsible

Related Questions

A coffee company wants to make sure that their coffee is being served at the right temperature. if it is too hot, the customers could burn themselves. if it is too cold, the customers will be unsatisfied. the company has determined that they want the average coffee temperature to be 65 degrees
c. what is the parameter?

Answers

Answer:

Average temperature of the cup of coffee.

Explanation:

If for a sample of population it’s related with statistics.

But in a parameter the whole population should be considered in a survey.  

When the all customers in consideration of this survey it’s considered as a parameter.  

Further explanation:  

Parameters are numbers which are summarize data for an entire population. But statistics are used to summarize data by using a sample.  

An unknown population average is known as a parameter. A known sample average is known as a statistic. Here the survey has done with all the customers come to the shop daily. This is considered to be a parameter. If it is a statistic they should select a specific sample of customers.  

But since all the customers comes to the shop has been considered in the survey this is a parameter of average temperature of sup of coffee consume by customers.  

 

Learn more:

1. statistic https://brainly.com/question/12999800 (answer by ardni313)

Keywords:

Average temperature, statistic, samples and parameter

The parameter defines the statistical attributes or measures which is derived from a population. Since the average measure of temperature of coffee is derived from a total population, it is a parameter.

Statistics are statistical measures such as average, median or other values which are derived from the sample.

The average coffee temperature is a measure derived from the population of the coffee being served.

Therefore, the average temperature of value of the coffee is derived from the population. Hence, it is the Parameter.

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What is an example of a negative incentive for producers

Answers

An example of a negative incentive for producers is the sharp increase in production costs. Producers are the one who manage the production costs and even the production budget. Anything that relates the production department is entitled to the management of production producers.

There is what we called positive and negative incentives and both of these can affect consumers and producers. Positive incentives are those situations which will give a certain outcome that will benefit the producers, for example, during the peak season there will be a high demand of products, and this gives the chance of producers to demand a higher price from the consumers, in this situation, there will be a big chance of increase sales.  A sharp increase in production costs is a loss for the producers.  If there will be an increase in production costs, the budget will be greatly affective and even though it is not a peak season, there’s a big chance also to increase prices which we know, consumers are not fond of.

A man whose weight is 650 N is standing on the ground. The force the ground exerts on him is _____.

Answers

The force the ground exerts on him is 650 N.

What is force?

The push or pull on an object with mass that causes it to change its velocity.

According to law of newton

"Every action has an equal and opposite reaction."

This means that the ground is exerting the same amount of force as the man, 650 N.

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What is the potential difference vab between points a and b when the switch s is open?

Answers

Final answer:

The potential difference vab between points a and b when the switch s is open can be calculated using the formula VAB = Ed where E is the electric field intensity and d is the distance between the points.

Explanation:

The potential difference vab between points a and b when the switch s is open can be calculated using the formula VAB = Ed, where E is the electric field intensity and d is the distance between the points. The potential difference is measured in volts (V).

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The surface or material that underlies a two-dimensional work of art is called the ____.

Answers

The surface or material that underlies a two-dimensional work of art is called the support.
Final answer:

The term for the surface or material that underlies a two-dimensional work of art is 'substrate'. It plays a critical role in the final appearance of the artwork, and its understanding is key to appreciating a given piece of art.

Explanation:

The surface or material that underlies a two-dimensional work of art is called the substrate. This term refers to the material on which the artwork is created. For example, in a painting, the substrate could be the canvas. Similarly, for a drawing, the substrate might be a piece of paper. The substrate plays a vital role in the final appearance of the artwork.

One can relate the concept of substrate in art to Aristotle's explanation of substance as a composite of matter and form. In his perspective, the form is the unchanging purpose or idea informing each particular instance, while the substrate (in his terminology, matter or material cause) contributes to the physical properties of the artwork. Therefore, understanding the substrate is an essential aspect of appreciating a given piece of art.

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A car braked with a constant deceleration of 8 ft/s2, producing skid marks measuring 100 ft before coming to a stop. how fast was the car traveling when the brakes were first applied?

Answers

In physics, it is convenient that there are already derived formulas for rectilinear motion at constant acceleration from Newton's Law of motion. One of these equations useful for this problem is:

2ax = vf2 - v02, where a is the acceleration, x is the distance, vf is the final velocity and v0 is the initial velocity.

Now, a=-8 ft/s2. It is negative because the car is decelerating. The distance x is 100 ft, the vf is equal to 0m/s because the car comes to a stop. The only unknown would be v0.

2(-8 ft/s2)(100 ft) = (0m/s)^2 - v0^2
v0 = 40 m/s
Final answer:

To find the initial speed of the car when the brakes were first applied, you can use the formula: v^2 = u^2 + 2as. Plugging in the given values, we find that the car was traveling at approximately 28.3 ft/s (or 19.3 mph) when the brakes were first applied.

Explanation:

To find the initial speed of the car when the brakes were first applied, you can use the formula:

v^2 = u^2 + 2as

v is the final velocity, which is 0 ft/s since the car comes to a stopu is the initial velocity, which we need to finda is the deceleration, which is given as 8 ft/s^2s is the distance, which is given as 100 ft

Plugging in the values into the formula, we get:

0 = u^2 + 2(8)(100)

Solving for u, we find that the car was traveling at approximately 28.3 ft/s (or 19.3 mph) when the brakes were first applied.

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A metal ball with diameter of a half a centimeter and hanging from an insulating thread is charged up with 1010 excess electrons. an initially uncharged identical metal ball hanging from an insulating thread is brought in contact with the first ball, then moved away, and they hang so that the distance between their centers is 20 cm. (a) calculate the electric force one ball exerts on the other, and state whether it is attractive or repulsive. (enter the magnitude of the force.)

Answers

Final answer:

Using Coulomb's law, the electric force between the two charged metal balls, each with 505 excess electrons after contact, and separated by 20 cm, is found to be 1.454 x 10^-24 N. The force is repulsive because the charges on the metal balls are both negative.

Explanation:

To calculate the electric force one charged metal ball exerts on another, we need to use Coulomb's law, which is given by:

F = k |q1 * q2| / r^2

Where:

F is the electric force between the charges,k is Coulomb's constant (8.988 x 10^9 N m^2/C^2),q1 and q2 are the magnitudes of the charges,r is the distance between the centers of the two charges.

When the two metal balls are brought into contact, the 1010 excess electrons will distribute evenly between both balls, meaning each ball will end up with 505 excess electrons. The charge of one electron is approximately -1.602 x 10^-19 C. Therefore, the charge on each ball after contact is 505 * -1.602 x 10^-19 C = -8.081 x 10^-17 C.

Because both balls hold negative charges, the force between them will be repulsive. The distance r is given as 20 cm, which is 0.2 meters. Thus, we can calculate the electric force:

F = (8.988 x 10^9 N m^2/C^2)*((-8.081 x 10^-17 C)^2) / (0.2 m)^2

After performing the calculation, the magnitude of the electric force between the balls is found to be:

F = 1.454 x 10^-24 N

This electric force is extremely small and generally would not be noticeable under normal circumstances.

A post office has a single line for customers waiting for the next available postal clerk. there are two postal clerks who work at the same rate. the arrival rate of customers follows a poisson distribution, while the service time follows an exponential distribution. the average arrival rate is three per minute and the average service rate is two per minute for each of the two clerks. what is the average length of the line? 3.429 1.929 1.143 0.643 none of these

Answers

A post office has a single line for customers waiting for the next available postal clerk. there are two postal clerks who work at the same rate. the arrival rate of customers follows a poisson distribution, while the service time follows an exponential distribution. the average arrival rate is three per minute and the average service rate is two per minute for each of the two clerks.
The average length of the line is 1.929

When studying whiplash resulting from rear end collisions, the rotation of the head is of primary interest. an impact test was performed, and it was found that the angular acceleration of the head is defined by the relation α = 700cosθ + 70sinθ, where α is expressed in rad/s2 and θ in radians. knowing that the head is initially at rest, determine the angular velocity of the head when θ = 30°?

Answers

The correct answer is[tex]\(\boxed{\omega \approx 479.0 \text{ rad/s}}\)[/tex].

To determine the angular velocity of the head when[tex]\(\theta = 30^\circ\),[/tex] we need to integrate the angular acceleration with respect to time. However, since angular acceleration is given as a function of [tex]\(\theta\)[/tex], we will use the relationship between angular acceleration [tex](\(\alpha\))[/tex], angular velocity[tex](\(\omega\))[/tex], and angle [tex](\(\theta\))[/tex] to find the angular velocity as a function of [tex]\(\theta\).[/tex]

The relationship between angular acceleration, angular velocity, and angle is given by:

[tex]\[\alpha = \frac{d\omega}{dt} = \frac{d\omega}{d\theta} \cdot \frac{d\theta}{dt} = \omega \frac{d\omega}{d\theta}\][/tex]

Since[tex]\(\alpha\)[/tex]is a function of [tex]\(\theta\)[/tex], we can write:

[tex]\[\omega \frac{d\omega}{d\theta} = 700\cos\theta + 70\sin\theta\][/tex]

To find [tex]\(\omega\),[/tex] we separate variables and integrate:

[tex]\[\int \omega \, d\omega = \int (700\cos\theta + 70\sin\theta) \, d\theta\][/tex]

Integrating both sides, we get:

[tex]\[\frac{\omega^2}{2} = 700\sin\theta - 70\cos\theta + C\][/tex]

where [tex]\(C\)[/tex] is the constant of integration. To find [tex]\(C\)[/tex], we use the initial condition that the head is initially at rest, which means[tex]\(\omega = 0\)[/tex] when [tex]\(\theta = 0\)[/tex]. Plugging these values into the equation, we find:[tex]\[0 = 700\sin(0) - 70\cos(0) + C\]\[C = 70\][/tex]

Now we have the constant[tex]\(C\)[/tex], and we can find the angular velocity when [tex]\(\theta = \frac{\pi}{6}\) radians (or \(30^\circ\)):[/tex][tex]\[\frac{\omega^2}{2} = 700\sin\left(\frac{\pi}{6}\right) - 70\cos\left(\frac{\pi}{6}\right) + 70\] \[\frac{\omega^2}{2} = 700\left(\frac{1}{2}\right) - 70\left(\frac{\sqrt{3}}{2}\right) + 70\] \[\frac{\omega^2}{2} = 350 - 35\sqrt{3} + 70\] \[\frac{\omega^2}{2} = 420 - 35\sqrt{3}\][/tex]

Multiplying both sides by 2 to solve for[tex]\(\omega^2\)[/tex]:

[tex]\[\omega^2 = 2(420 - 35\sqrt{3})\]\[\omega^2 = 840 - 70\sqrt{3}\][/tex]

Taking the square root of both sides to find [tex]\(\omega\)[/tex]:

[tex]\[\omega = \sqrt{840 - 70\sqrt{3}}\][/tex]

Now we can calculate the numerical value:

[tex]\[\omega \approx \sqrt{840 - 70 \times 1.732}\] \[\omega \approx \sqrt{840 - 121.24}\] \[\omega \approx \sqrt{718.76}\] \[\omega \approx 479.0 \text{ rad/s}\][/tex]

Therefore, the angular velocity of the head[tex]when \(\theta = 30^\circ\) is approximately \(\boxed{479.0 \text{ rad/s}}\)[/tex]

Determine how long it will take an object to rotate through 10.0 revolutions at an angular velocity of 4.8 radians per second. use . round the answer to the nearest tenth.

Answers

Given:
Ф = 10 revolutions
ω = 4.8 rad/s, angular velocity

The time taken to complete 10 revolutions is
t = Ф/ω
  = [(10 rev)*)2π rad/rev)]/(4.8 rad/s)
  = (20π)/4.8 s
  = 13.09 s

Answer: 13.1 s (nearest tenth)

By what amount does the sound intensity decrease when the distance to the source doubles?

Answers

The relationship of the two is that, the sound intensity is inversely proportional to the square of the distance of the source.

I α 1 / r^2

Where I = intensity and r = distance from source

From this, we can equate two conditions 1 and 2:

I1 / I2 = r2^2 / r1^2

So when r2 = 2 r1, the intensity becomes:

I1 / I2 = (2r1 / r1)^2

I1 / I2 = 4

I2 = I1 / 4

So when we double the distance of the source, the intensity of the sound reduces by a factor of 4 (divided by 4).

You pour 170 g hot coffee at 78.7°c and some cold cream at 7.50°c to a 115-g cup that is initially at a temperature of 22.0°c. the cup, coffee, and cream reach an equilibrium temperature of 58.0°c. the material of the cup has a specific heat of 1091 j/(kg · k) and the specific heat of both the coffee and cream is 4190 j/(kg · k). assume that no heat is lost to the surroundings or gained from the surroundings. (a) does the cream lose heat or gain heat?

Answers

Because all temperatures are below boiling temperature, only sensible heat exchange occurs.
The equilibrium temperature is 58 °C.

Coffee:
initial temperature = 78.7 °C
mass = 170 g = 170 x 10⁻³ kg
specific heat = 4190 J/(kg-K)
temperature drop = 78.7 - 58 = 20.7 K
Because the tempeature drops, the coffee loses heat.
Heat loss = (170x10⁻³ kg)*(4190 J/(kg-K)*(20.7 K)
                 = 14744.6 J
                 = 14.745 kJ

Cream:
initial temperature = 7.5 °C
Assume that the mass is m kg (not given)
specific heat (same as for coffee)
temperature rise = 58 - 7.5 = 50.5 K
Because the temperature rises, the cream gains heat.
Heat gained = (m kg)*(4190 J/(kg-K)*(50.5 K)
                    = 211595m J
                    = 211.595m kJ

Cup:
initial temperature = 22 °C
mass = 115 g = 115 x 10⁻³ kg
specific heat = 1091 J/(kg-K)
temperature rise = 58 - 22 = 36 K
Because of temperature rise, the cup gains heat.
Heat gained = (115x10⁻³ kg)*(1091 J/(kg-K))*(36 K)
                     = 4529.2 J
                     = 4.53 kJ

Assume no heat is lost to the surroundings. For energy balance (with heat gain as positive and heat loss as negative), obtain
-14.475 + 211.595m + 4.53 = 0
m = 0.047 kg = 47 g

Answer:
47 g of cream were added, and the cream gained heat.
Final answer:

The cream will gain heat when added to the hot coffee until they reach an equilibrium temperature. Practice problems cover several aspects of heat transfer and thermodynamics, including evaporation and specific heat calculations.

Explanation:

The cream will gain heat when it is mixed with the hot coffee and they reach an equilibrium temperature. Overall, when two substances at different temperatures are mixed without any heat loss to the surroundings, the warmer substance will lose heat and the cooler substance will gain heat until they come to the same temperature.

In the provided scenario, the hot coffee initially at 78.7°C will lose heat, while the cold cream at 7.50°C will gain heat. This occurs because heat flows from the warmer object to the cooler one until thermodynamic equilibrium is achieved at 58.0°C.

Several practice problems related to heat transfer and thermodynamics were mentioned. Problems include finding the amount of coffee that must evaporate to cool it down, calculating final temperatures of mixtures, and understanding specific and latent heats.

A cylindrical cable of radius 8.57 mm carries a current of 25.5 a, uniformly spread over its cross-sectional area. at what distance from the center of the wire is there a point within the wire where the magnetic field is 0.447 mt?

Answers

I think there is a problem with this question because the answer is not inside the wire as stated, but would require a bigger wire than stated. This should be a standard ampere's law problem, B = I(mu), where B is the magnetic field, I is the current and mu is the magnetic permitivity constant (4*pi * 10^-7 H/m or T/A). We can describe the amount of current we get from our distance from the center of the wire with a ratio of areas (pi*r^2/pi*d^2), where r is our particular distance from the center (what we're trying to find) and d is the total radius of the wire. Adding this into ampere's law and canceling the pi's we get B = I*(mu)*(r^2/d^2), solving for r we get r = sqrt(B*d^2/(I*(mu))), when you plug values in, it gives an r of 32mm, which is much bigger than the actual radius of the wire. Maybe something was copied wrong?

Initially the clean air act of 1990 required ___ of the nationâs dirtiest coal burning plants to cut down on emissions

a.50

b.71

c.111

d.2300

Answers

d is the answer
I hope this helps

a body of mass 1 kg is placed at a distance of 2 m from another body of mass 10 kg. At what distance from the body of mass 1 kg, another body must be placed so that the net gravitational force acting on the body of mass 1 kg is zero

Answers

To answer this problem, we will use the formula for gravitational force:

F = G m1 m2 / r^2

Where,

G = gravitational constant (6.67 * 10^-11)

m = mass of a body

r = distance between two bodies

To have a net gravitational force equal to zero acting on body of mass 1 kg, then the forces of 1 kg and 10 kg bodies and 1 kg and 5 kg bodies should be equal.

F1 (1 kg and 10 kg) = F2 (1 kg and 5 kg)

Therefore,

(1 kg) (10 kg) / (2 m)^2 = (1 kg) (5 kg) / r2^2

Calculating for r2 (distance of another body 5 kg from body of mass 1 kg):

r2^2 = 2

r2 = 1.41 m       (ANSWER)

Therefore another body of mass 5 kg should be placed 1.41 m from body of mass 1 kg to have a net gravitational force equal to zero.

Here we will look at a more complex problem for which we will use all three of our primary constant acceleration equations. a motorcyclist heading east through a small iowa town accelerates after he passes a signpost at x=0 marking the city limits. his acceleration is constant: ax=4.0m/s2. at time t=0, he is 5.0 m east of the signpost and has a velocity of v0x=15m/s. (a) find his position and velocity at time t=2.0s. (b) where is the motorcyclist when his velocity is 25 m/s?

Answers

In physics, it is already convenient since there are already derivedequations for rectilinear motions with constant acceleration. These equations are all derived from Newton's Laws of Motion. 

2ax = vf^2 -v0^2
x = v0*t + 1/2*a*t^2
where

a is the acceleration in m/s^2
vf is the final velocity in meters
v0 is the initial velocity in meters
x is the distance travelled in meters and,
t is the time in seconds

a.) For this case, you'll find x when t=2 s. Using the second equation,

x = v0*t + 1/2*a*t^2
x = 15*2 + 1/2*4*2^2
x = 38 m

b.) For this case, you'll find x when vf is 25 m/s. Using the first equation,

2ax = vf^2 -v0^2
2*4*x = 25^2 -15^2
x = 50 m

What is the weight of a 100-kg
the moon (gravity on the moon is 1.62m/s)

Answers

The mass of an object does not change, so the mass on the moon is 100 kg.

Because the acceleration due to gravity on the moon is g = 1.62 m/s², the weight of the object is
W = mg
    = (100 kg)*(1.62 m/s²)
   = 162 N

Answer:  162 N

A circuit contains a 6.0-v battery, a 4.0-w resistor, a 0.60-µf capacitor, an ammeter, and a switch all in series. what will be the current reading immediately after the switch is closed?

Answers

You are given a circuit that contains a 6.0-v battery, a 4.0 ohm resistor, a 0.60 micro farad capacitor, an ammeter, and a switch all in series. You are asked to find the current reading after the switch is closed. Apply ohms law where V = IR where V is the voltage, I is the current and R is the resistor.

V = IR
I = V/R
I = 6 volts / 4 ohms
I = 1.5A

When the switch is closed, the cathode side plate begins to fill up with electrons when it was originally empty before the switch was closed. When it fills up the cathode side of the circuit, the current decreases. And when the capacitor cannot hold more electrons, the current will stop. The higher the capacitance, the higher is the capacity to store electrons.

Answer:

I = 0.667 A

Explanation:

A capacitor behaves like a short circuit at t = 0 immediately after the switch is closed, therefore we can discard it from the equation, the resistance is given in watts or power units equivalent to current by voltage and the ammeter behave like a short circuit by nature.

Considering all of the above, the circuit looks like a battery in series with a resistor, therefore, we can use the power equation to solve the problem as follow:

P = I*V

4W = I*6V

I = 0.667 A  

What net force is required to push a sofa with a mass of 59 kilograms so that it accelerates at 9.75 meters/second2? (Assume a flat, frictionless surface.)

Answers

According to Newton's Second Law, F(net) = ma

Therefore, F(net) = 59 * 9.75 = 575.25 N
The equation for force is F (force in N) = m (in kg) x a (in m/s^2). We can now plug our known values into the equation and get F = 59kg x 9.75m/s^2. Finally, we can multiply out and get an answer of 575.25 N. Using sig figs, we can change that to an accurate answer of 580 N.

Hope this helps!

Give three examples from your life of magnetic force.

Answers

headphones, refrigerator magnets, and compasses

Hope that was helpful.
Magnets,popsocket, and a car

The ______ of a vector is always a positive quantity.

Answers

Hi

the magnitude of a vector is always a positive quantity .

Magnitude
is the answer.

thanks for asking
Final answer:

The magnitude of a vector, representing its 'length' or 'size', is always a positive quantity. It's graphically depicted as the length of an arrow representing the vector, and calculated as the square root of the sum of the squares of the vector components.

Explanation:

The __magnitude__ of a vector is always a positive quantity. In mathematics and physics, a vector is a quantity described by both magnitude and direction. The magnitude of a vector refers to its 'length' or 'size', irrespective of its direction. It is expressed as a positive scalar quantity.

When a vector is depicted graphically, it's represented by an arrow. The length of the arrow is proportional to the vector's magnitude, meaning the longer the arrow, the greater the magnitude.

Magnitude is calculated as the square root of the sum of the squares of the vector's components. For instance, for a vector A in two-dimension with components Ax and Ay, its magnitude A is calculated by the equation: A = sqrt(Ax^2 + Ay^2). No matter what the direction is, the resulting magnitude will always be a positive scalar.

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Maria works in a hardware store. A bin of aluminum nails and a bin of iron nails are knocked over, and the nails get mixed up. Both sets of nails are the same color and size.
What makes separating the nails a fairly easy job?

A. Aluminum is heavier and iron is lighter.
B. Iron settles in water, while aluminum floats.
C. Aluminum is magnetic, and iron is non-magnetic.
D. Iron is magnetic, and aluminum is non-magnetic.

Answers

D. Iron is magnetic, and aluminum is non-magnetic.

The correct answer is D. Iron is magnetic, and aluminum is non-magnetic.

Explanation:

Aluminum and iron are both metals; additionally, these materials are similar in color. However, because they are different elements they have different properties, this includes their weight as iron is heavier than aluminum; their melting point as iron has a higher melting point and their magnetic properties. Indeed while the iron is magnetic aluminum is non-magnetic, this means, aluminum does not stick to magnets. According to this, Maria could separate aluminum and iron nails using a magnet, this is fairly an easy job because iron is magnetic, and aluminum is non-magnetic.

How are chemical reactions classified?

Answers

Types of Chemical Reactions. Combination or Synthesis Reactions Two or more reactants unite to form a single product. Substitution or Single Replacement Reactions A single free element replaces or is substituted for one of the elements in a compound. The free element is more reactive than the one its replaces.

The types of chemical reactions are

a) Combination reaction.

b) Decomposition reaction.

c) Displacement reaction.

d) Double Displacement reaction.

e) Precipitation Reaction.

What are chemical reactions?

In a chemical reaction, one or more chemicals , also known as reactants are changed into one or more other substances, known as products. In a chemical reaction, the atoms that make up the reactants are rearranged to produce various products.

Chemical equations, which depict the reactants and products of the reaction using chemical symbols and chemical formulae, can be used to represent chemical reactions. The relative numbers of atoms or molecules participating in the reaction are indicated by the coefficients placed in front of the chemical formulae.

Given data ,

The types of chemical reactions are given as

Combination reaction, Decomposition reaction , Displacement reaction , Double Displacement reaction , Precipitation Reaction

And , the characteristics of a chemical reaction are evolution of gas , formation of a precipitate , change in color or temperature and state , formation of new substances

Thermodynamic and kinetic characteristics govern the many types of chemical processes, and they may be modeled by a number of factors including energy, entropy, and Gibbs free energy change.

Hence , the types of chemical reactions are solved

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how has the use of computer and advance in technology changed healthcare industry

Answers

yes because we often used it and takes long time to spent and forgot to eat on time.

Final answer:

Technology has revolutionized healthcare, making it more accessible, efficient, and effective in delivering quality care to patients.

Explanation:

The use of computers and advances in technology have significantly changed the healthcare industry. These changes have resulted in improved efficiency, better patient care, and increased access to medical services. One of the major impacts of technology is the digitization of health records, which allows for easier storage and sharing of patients' information among healthcare providers. Additionally, the development of medical devices and equipment has led to advancements in diagnosis and treatment, such as robotic surgery tools and preventive healthcare devices. Technology has also enabled the growth of telemedicine, which enables remote patient consultations and monitoring, particularly useful in rural areas.

Overall, technology has revolutionized healthcare, making it more accessible, efficient, and effective in delivering quality care to patients.

The time a basketball player spends in the air when shooting a basket is called the​ "hang time." the vertical leap l measured in feet is related to the hang time t measured in seconds by the equation lequals=4t2. suppose that a basketball player has a vertical leap of 4 feet 4 inches. find the hang time for this leap.

Answers

I believe that L is in feet while t is in seconds. To find for the hang time, all we have to do is to plug in the value of L in feet in the equation.

4 inches is equivalent to 4/12 feet or 0.33 feet, therefore the total L is:

L = 4.33 ft

Using the equation to find for t:

L = 4 t^2

4.33 = 4 t^2

t = 1.04 s

To calculate the hang time for a basketball player with a vertical leap of 4 feet 4 inches, solve the equation l = 4[tex]t^2[/tex] to find that the hang time is approximately 1.041 seconds.

The vertical leap l is related to the hang time t by the equation l = 4[tex]t^2[/tex]. To find the hang time for a basketball player with a vertical leap of 4 feet 4 inches (which is 4.333 feet), we plug this value into the equation and solve for t:

4.333 = 4[tex]t^2[/tex]

[tex]t^2[/tex] = 4.333 / 4

[tex]t^2[/tex] = 1.08325

t = [tex]\sqrt{(1.08325)[/tex]

t ≈ 1.041

Hence, the hang time for this leap is approximately 1.041 seconds.

What is the maximum capacity of an analog circuit with a bandwidth of 4000 hz using qam?

Answers

The answer is 16,000 bps

A standing wave is set up in a 200-cm string fixed at both ends. the string vibrates in 5 distinct segments when driven by a 120-hz source. what is the wavelength?

Answers

The wavelength of a standing wave is equivalent to:

wavelength = 2 l / n

Where l is the length of the string and n is the number of segments.

so, wavelength = 2 (0.2 m) / 5 
wavelength = 0.08m      (ANSWER)

Answer:

[tex]\lambda=80\ cm[/tex]

Explanation:

It is given that,

Length of the string, L = 200 cm = 2 m

Frequency, f = 120 Hz

It vibrates in 5 distinct segments such that there is fifth harmonics. For a string fixed at both ends, the wavelength is given by :

[tex]\lambda=\dfrac{2}{5}L[/tex]

[tex]\lambda=\dfrac{2}{5}\times 2[/tex]

[tex]\lambda=0.8\ m[/tex]

[tex]\lambda=80\ cm[/tex]

So, the wavelength of the string fixed at both ends is 80 cm. Hence, this is the required solution.

The Hubble Space Telescope (HST) orbits 569,000m above Earth’s surface. Given that Earth’s mass is 5.97 × 10^24 kg and its radius is 6.38 × 10^6 m, what is HST’s tangential speed?

Answers

Refer to the diagram shown below.

M = 5.97 x 10²⁴ kg, mass of the earth
h = 5.69 x 10⁵ m, height of HST above the earth's surface
R = 6.38 x 10⁶ m, radius of the earth

Note that
G = 6.67 x 10⁻¹¹ (N-m²)/kg², gravitational acceleration constant.
R + h = 6.38 x 10⁶ + 5.69 x 10⁵ = 6.949 x 10⁶ m

The force between the earth and HST is
F = (GMm)/(R+h)²

Let v = tangential velocity of the HST.

The centripetal force acting on HST is equal to F.
Therefore
m*[v²/(R+h)] = (GMm)(R+h)²
v² = (GM)/(R+h)
    = [(6.67 x 10⁻¹¹ (N-m²)/kg²)*(5.97 x 10²⁴ kg)]/(6.949 x 10⁶ m)
    = 5.7303 x 10⁷ (m/s)²
v = 7.5699 x 103 m/s

Answer
The tangential speed of HST is about 7,570 m/s 

The 26-kg sphere c is released from rest when θ = 0∘ and the tension in the spring is f = 100 n

Answers

You are given the mass of a sphere that is 26 kg sphere and it is released from rest when θ = 0°. You are also given the force of the spring that is F = 100 N. You are asked to find the tension of the spring. Imagine that the sphere is connected to a spring. The spring exerts a tension and the spring exerts gravitational pull. This will follow the second law of newton.

T - F = ma
T = ma + F
T = 26kg (9.81m/s²) + 100 N
T = 355.06 N

The rear window of a van is coated with a layer of ice at 0°c. the density of ice is 917 kg/m3, and the latent heat of fusion of water is 3.35 x 105 j/kg. the driver of the van turns on the rear-window defroster, which operates at 12 v and 23
a. the defroster directly heats an area of 0.65 m2 of the rear window. what is the maximum thickness of ice above this area that the defroster can melt in 4.3 minutes?

Answers

Let h =  the thickness of ice, m.

Because the ice covers an area of 0.65 m², the volume of ice is
 V = 0.65h m³

The density of ice is 917 kg/m³, therefore the mass of ice is
m = (917 kg/m³)*(0.65h m³) = 596.05h kg

The latent heat of fusion of ice is 3.35 x 10⁵ J/kg, therefore the heat required to melt the ice is
Q₁ = (596.05h kg)*(3.35 x 10⁵ J/kg) = 2h x 10⁸ J

The electric heater supplies heat at 12 V, 23 A for 4.3 minutes to melt the ice.
Therefore the heat provided is
Q₂ = (12 V)*(23 A)*(4.3*60 s) =  71208 J

Because Q₁ = Q₂, obtain
2h x 10⁸ = 71208
h = 356 x 10⁻⁶ m = 356 x 10⁻³ mm = 0.356 mm

Answer: 0.356 mm
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