An object is released from rest on a planetthat has no atmosphere. The object fallsfreely for 2.03 m in the first second.What is the magnitude of the accelerationdue to gravity on the planet?

Answer:

To calculate the period of satellite orbiting around a planet, we use Kepler's third law;

Square of T = [(4π)/(G*m)] * R^3.

Therefore,

T = sqrt{[(4π)/(G*m)]*R^3}.

T is the period, m is mass orbiting satellite, G is gravitational constant, R is the radius of of the planet, r is the radius of the orbiting satellite.

For Satellite 1, r is one-half of the planet, that is r = (3/2) * R

For satellite 2, r = R

Explanation:

Answer:

[tex]d=490\ m[/tex] is his final displacement from the point A after 60 seconds.

Explanation:

Given:

Cyclist is moving away from A.

Now as the cyclist is moving away from point A his change in displacement after the mentioned time:

[tex]\Delta d=v.t[/tex]

[tex]\Delta d = 4.1 \times 60[/tex]

[tex]\Delta d=246\ m[/tex]

Now the the final displacement from point A after the mentioned time:

[tex]d=d_i+\Delta d[/tex]

[tex]d=244+246[/tex]

[tex]d=490\ m[/tex]

Answer:

a1 = 3.68m/s²

Explanation:

Given values:

Mass of the block placed on the table, m1 = 12.25 kg

Mass of the block hanging vertically, m2 = 7.5 kg

Acceleration due to gravity, g = 9.8 m/s2

Tension in the string is T

Let the acceleration of mass 1 and mass 2 be a1 and a2

a1 and a2 are equal in magnitude but different in direction. This because the string does not stretch. Hence the two bodies must move equal distances in equal times, and so their speechless at any instant must be equal. When the speeds change , they change by equal amounts in a given time, so the acceleration of the two bodies must have the same magnitude a,

a = m2*g/(m1 + m2)

a = 7.5 x 9.8 / (12.5 + 7.5)

a = 3.68 m/s²

a1 = a2 = 3.68m/s²

a1 is directed to the right and a2 is directed downwards

Below is a diamonds to show the geometrical arrangements of both masses

Answer:

Following are the correct options.

1. In a uniform electric field, the field lines are straight, parallel and uniformly spaced. ( As the field strength does not change in the uniform electric field that is why the field lines are parallel, equally spaced etc).

2. Electric field lines near positive point charges radiate outward. (Due to repulsive forces field lines radiate in outward direction)

3.The electric force acting on a point charge is proportional to the magnitude of the point charge. ( As columb law states that the electrostatic forces between the point charges is proportional to the product of their magnitude and inversely proportional to square of distance between them).

Explanation:

In a uniform electric field, electric field lines are straight, parallel, and uniformly spaced while near positive point charge it emits outwards. Also, the electric force on a point charge is proportional to its magnitude. But, lines near negative point charges radiate inward, not circle clockwise. The electric field created by a point charge isn't constant across space, but diminishes with distance.

Of the five statements you provided:

Therefore, statements 1, 2 and 3 are true, while 4 and 5 are false.

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The speed is 2.5 m/s

Explanation:

The total (mechanical) energy of the mass-spring system at any point during the motion is the sum of the kinetic energy (KE) and the potential energy (PE):

[tex]E=KE+PE=3.24 J[/tex]

and it is constant.

The kinetic energy can be written as

[tex]KE=\frac{1}{2}mv^2[/tex]

where

m = 0.500 kg is the mass

v is the speed

While the potential energy is

[tex]PE=\frac{1}{2}kx^2[/tex]

where

k = 330 N/m is the spring constant

x is the elongation

So the first equation becomes

[tex]E=\frac{1}{2}mv^2 + \frac{1}{2}kx^2[/tex]

Therefore, if we substitute

x = 0.100 m

We can find the speed when the elongation is x = 0.100 m:

[tex]v=\sqrt{\frac{2E-kx^2}{m}}=\sqrt{\frac{2(3.24)-(330)(0.100)^2}{0.500}}=2.5 m/s[/tex]

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Correct Answer:

2.5 m/s

Answer:

Southwest

Explanation:

when the car is moving around a circular track at constant speed, velocity changes due to change in the direction. The direction at any instant is given by tangent drawn at the point on the circular path.

At instant 1: direction is northwards

At instant 2: direction is westwards

Let the constant speed be v. Then, at instant 1, the velocity would be:

[tex]v_1=v \hat j[/tex]

At instant 2, the velocity would be:

[tex]v_2 = v (-\hat i)[/tex]

Change in velocity = [tex]v_2-v_1 = v(-\hat i - \hat j)[/tex]

The direction of car's average change would be southwest.

The car's average change in velocity has a northwest direction.

The direction of the car's average change in velocity is determined by the direction of the velocity vectors at the two instances. In this case, when the car is driving northward, its velocity vector points towards the north. Later, when the car is driving westward, its velocity vector points towards the west. Therefore, the car's average change in velocity will have a direction that is a combination of north and west, which is the northwest direction.

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There is one mistake in the question as unit of acceleration is not written correctly.The correct question is here

A car traveling at 7 m/s accelerates uniformly at 2.5 m/s² to reach a speed of 12 m/s. How long does it take for this acceleration to occur?

Answer:

time taken =2 seconds

Explanation:

Given Data

Initial Speed Vi= 7 m/s

Final Speed Vf=12 m/s

Acceleration a= 2.5 m/s²

To find

Time taken for this acceleration

Solution

As we know that

Final velocity=Initial velocity + acceleration×time

[tex]V_{f}=V_{i}+at\\  t=\frac{V_{f}-V_{t}}{a}\\ t=\frac{12m/s-7m/s}{2.5m/s^{2} }\\ t=2 seconds[/tex]

So car takes 2 seconds for this acceleration to occur

Answer:C) BLADDER

D) EPIDERMIS (E) BLOOD VESSEL LINING

Explanation: Autoimmune diseases are diseases caused by the body fighting against its self. In autoimmune diseases the body's defense system tends to attack the body cells, tissues, Organs and the entire system mistaking it for a foreign body such as Viruses or Bacteria,Fungi etc.

Epithelial tissues are tissues which form the surface covering of most of the hollow Organs,all body Organs and are present inside the glands. The body parts that will be involved are the BLADDER, EPIDERMIS AND BLOOD VESSEL LINING.

"Anti-Lock" brake systems release the brakes momentarily when wheel speed sensors indicate a locked wheel during braking and traction.

Explanation:

The safety anti-skid braking system is known as "anti-lock braking system" having huge application on land vehicles like one, two and multiple wheeler vehicles and aircraft. During braking, it avoids wheels to get locked by building tractive contacts to the road's surface.

This seems to be an automated system work on the principles of techniques - threshold and cadence braking. The wheel velocity sensors are utilized by ABS to find whether one or more than one wheels chose to get lock while braking.

Answer:

Anti- Lock

Explanation:

Anti- lock brake systems(ABS) is a safety system used in hindering the wheels from locking up when the brake is applied.

Braking release the brakes momentarily when wheel speed sensors indicate a locked wheel during braking and traction.

Control systems apply the brakes momentarily to one of the drive wheels whenever the wheel speed sensors indicate a wheel is going faster than the others during acceleration.

Answer:

Being an elastic object, rubber ball will be an ideal choice as it will bounce off the bowling pit and will experience a large change in momentum in comparison with the beanbag which will either slow down or come to a halt upon hitting a bowling pit. That is why rubber ball will experience a greater impulse and the bowling pin will experience the negative impulse of the rubber ball.

For Rubber Ball

Upon elastic collision it will reverses the direction and move with velocity equal or less then original

change in momentum = P

[tex]P = m(v_{f} -v_{i})\\v_{f}=-v_{i} \\ P = -2mv_{i}[/tex]

For Beanbag

value of impulse will large if velocity is zero.

[tex]v_{f}=0\\ P = -mv_{i}[/tex]

Explanation:

The rubber ball will impact a greater force on the heavy bowling pin because its kinetic energy will be conserved while the beanbag will impact lesser force due to loss of kinetic energy.

A collision between two objects can be elastic or inelastic.

The impulse experienced by each throwing object is equal to change in the momentum of the object.

[tex]J = \Delta P[/tex]

The rubber ball will impact a greater force on the heavy bowling pin because its kinetic energy will be conserved while the beanbag will impact lesser force due to loss of kinetic energy.

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Answer: work Melvin did=9000J

Explanation:

Given to complete the question: If the sled moved 33.9m,how much work did Melvin do? Answer in unit of J and round to the nearest thousandth.

W = F ×S

W = 317 × cos 33°×33.9

W=9012.6055J

W=9000J to the nearest thousandth

Answer:

a short-to-ground

Explanation:

Many failures that occur in vehicles can be diagnosed as electrical problems. The reason for these usually relate mainly to the electricity generated in the battery or alternator, in the ignition system as well as those produced by blown wires or fuses.

Cables or fuses: a blown fuse or a damaged electrical wire or one that is making ground or earth effect can be the cause of an electrical problem. Keep in mind that everyone is connected to each other through the wires of the electrical system. Fuses protect car components from power surges. If you have a problem with one, check it to see if you will have to replace it.

A failure where an insulated wire rubs through and touches the steel body of a vehicle is known as a short circuit.

If an insulated (power side) wire rubs through a part of the insulation and the wire conductor touches the steel body of a vehicle, this type of failure is known as a short circuit. This happens when a wire carrying current touches the vehicle's body, which is grounded. As the body acts like a path of least resistance, the current prefers flowing through it rather than its intended path, creating a short circuit. This can result in various problems like damage to components, blowing a fuse, or even triggering a fire.

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Answer:

-M6

-G2

-A5

-O9

Explanation:

Answer:

Sublimation

Explanation:

Example: Dry ice, camphor

They travel at a speed of 0.68 m/s south ([tex]90^{\circ}[/tex] south of west)

Explanation:

We can solve this problem by using the law of conservation of momentum: in fact, in absence of external forces, the total momentum of the two players must be conserved before and after they collide.

Mathematically:

[tex]p_i = p_f\\m_1 u_1 + m_2 u_2 = (m_1+m_2)v[/tex]  

where, taking north as positive direction:

[tex]m_1 = 92 kg[/tex] is the mass of the first player

[tex]u_1 = -5.8 m/s[/tex] is the initial velocity of the first player (south, so negative)

[tex]m_2 = 110 kg[/tex] is the mass of the second player

[tex]u_2 = 3.6 m/s[/tex] is the initial velocity of the second player (north, so positive)

[tex]v[/tex] is the final combined velocity of the two players

Solving for v, we find the final velocity of the two players combined:

[tex]v=\frac{m_1 u_1 + m_2 u_2}{m_1+m_2}=\frac{(92)(-5.8)+(110)(3.6)}{92+110}=-0.68 m/s[/tex]

where the negative sign indicates their final direction is south.

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To find the final speed and direction after the tackle, we use the conservation of momentum. The fullback and lineman's initial momenta are calculated and combined to find the total initial momentum, which equals the final momentum because momentum is conserved. The direction is either south (90 degrees) or north (270 degrees) depending upon the sign of the final velocity.

To solve this physics problem, we will use the principle of conservation of momentum, which states that in the absence of external forces, the total momentum of a system remains constant. The formula for momentum (p) is the product of mass (m) and velocity (v), or p = mv.

Before the tackle, the fullback's momentum is southward and the lineman's is northward. We treat south as the positive direction. Thus, the initial momentums of the fullback and lineman are:

The total initial momentum (pinitial) is the sum of these:

pinitial = pFB + pL

After the tackle, the players stick together and move as one mass (M = 92 kg + 110 kg), with a final velocity (V), so:

pfinal = MV

Since momentum is conserved, pinitial = pfinal, and we can solve for V:

V = pinitial / M

Once we calculate the final velocity, the direction is south if V > 0, north if V < 0. To convert the direction into an angle south of west, note that if they move southward, the angle is simply 90 degrees (directly south), while any northward movement would result in a 270-degree angle.

To solve the problem, we use the kinematic equation for distance considering the initial velocity, acceleration due to gravity, and the distance from the top of the cliff to 6m above the ground. The equation gives two possible times: one when the rock is on the way up, and one when it's on the way down.

In this physics question, we are dealing with kinematic equations which describe the motion of the rock. The equation we will use for this question is d = vit + 0.5gt^2, where 'd' represents total distance, 'vi' is initial velocity, 'g' is acceleration due to gravity and 't' is time.

Here, d = 43m - 6m = 37m (distance from the top of the cliff to 6m above the ground), vi = 26m/s (initial velocity of the rock when thrown upwards), and g = 9.8m/s^2 (acceleration due to gravity, but since the rock is thrown downwards, we take it as positive).

Now plug these values into the equation, you have two possible times- one for the rock on its way up and one for on its way down.

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Answer: y = 40 + 21t

Explanation:

Apply the equation of distance covered.

d = vt + C

Where d is the distance covered

v = velocity , t = time

C = constant = initial distance covered

For the case above....

d = y

y(t) = vt + C

But y(0) =40 = C

C = 40ft

velocity v = 21 ft/s

Therefore, the equation of the altitude is given by;

y(t) = 21t +40

y = 40 + 21t

The function representing the helicopter's altitude as it gains height is y = 21t + 40. The helicopter gains altitude at a rate of 21 feet per second and it starts at 40 feet above the ground.

The function that represents this situation is a linear function because the change in the helicopter's altitude is constant over time.

The formula for a linear function is y = mx + b, where m is the slope (rate of change), b is the y-intercept (initial value), y is the dependent variable (altitude in this case), and x is the independent variable (time in this case).

In this scenario, we're given that the helicopter starts 40 feet above the ground (our y-intercept, b) and it's gaining altitude at 21 feet per second (our slope, m).

Therefore, the function to represent the helicopter’s altitude, y, after t seconds can be written as y = 21t + 40.

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Answer:

Beta radiation

Explanation:

Beta radiation is a radioactive phenomenon of nuclear decay in which an unstable atom or isotop, by transforming a neutron into a proton, or by transforming a proton into a neutron, becomes stable. For example, the decay of carbon 14 produces beta radiation.

Answer:

[tex]1.18454\times 10^{-19}\ Pa[/tex]

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

m = Mass of bullet = [tex]2.6\times 10^{23}\ kg[/tex]

r = Radius of barrel = [tex]2.8\times 10^{23}\ m[/tex]

[tex]v^2-u^2=2as\\\Rightarrow a=\dfrac{v^2-u^2}{2s}\\\Rightarrow a=\dfrac{370^2-0^2}{2\times 0.61}\\\Rightarrow a=112213.11475\ m/s^2[/tex]

Pressure is given by

[tex]P=\dfrac{F}{A}\\\Rightarrow P=\dfrac{ma}{\pi r^2}\\\Rightarrow P=\dfrac{2.6\times 10^{23}\times 112213.11475}{\pi (2.8\times 10^{23})^2}\\\Rightarrow P=1.18454\times 10^{-19}\ Pa[/tex]

The pressure of the expanding gas is [tex]1.18454\times 10^{-19}\ Pa[/tex]

Answer:

A. Weight

Explanation:

Mass And Weight

Mass is a fundamental property of objects and is defined as a measure of the amount of matter in the object. The symbol for mass is m and its SI unit is the kilogram (kg). At normal speeds, i.e. much smaller than the speed of light, the mass is considered as a constant property.

The weight W is defined as the force of gravity on the object, that is, the gravitational attraction between the object and the Earth. Its SI unit is the Newton (Nw or N).

Answer:

c. The astronaut does not need to worry: the charge will remain on the outside surface.

Explanation:

The all-metal chamber (conductor) receives an external electromagnetic field, so it is positively charged in the direction the electromagnetic field is going, and negatively charged in the opposite direction. Since the chamber is polarized, it generates an electric field equal in magnitude, but opposite the external electromagnetic field, then the net electric field inside the conductor is 0.

When all boxes (conductors) receive environmental electromagnetic frequencies, they become electrostatically attracted inside the plane of the magnetic wave and charged negatively in a reverse way.

Therefore, the answer is " Option c".

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Answer:

b. Medicine balls

Explanation:

A medicine ball (also called an exercise ball, or a health ball) is a weighted ball about the shoulder diameter (approx. 13.7 inches), often used for recovery and strength training.... In 1705 similar large balls had been used in Persia.So you can use your medicine ball as a projectile to boost the strength of your throws.

Answer:

The answer to your question is 4.82 x 10²⁷ atoms of Hydrogen

Explanation:

Data

final mass = 8.0 kg

mass of hydrogen = 1.0 u

number of hydrogens = ?

Process

1.- Use proportions to solve this problem

                  1 u -------------------------  1.66 x 10⁻²⁷ kg

                 x u -------------------------  8 kg

                 x = (8 x 1) / 1.66 x 10⁻²⁷

                 x = 8 / 1.66 x 10⁻²⁷

                x = 4.82 x 10 ²⁷ u or 4.82 x 10²⁷ atoms of Hydrogen

Answer:

E2/E1 =99.2

Explanation:

time after release of E1 (t) = 27.3 s

time after release of E2 (t') = 3.03 s

acceleration (a) = [tex]\frac{QE1}{M}[/tex]

where

after 27.3 s

velocity (V) = a x t = [tex]\frac{QE1}{M}[/tex] x 27.3  = [tex]\frac{27.3QE1}{M}[/tex]

distance to turning point (s) = 0.5a[tex]t^{2}[/tex] = 0.5 x [tex]\frac{QE1}{M}[/tex]x [tex]27.3^{2}[/tex] = [tex]\frac{372.65QE1}{M}[/tex]

now for its return back to its starting point

acceleration (a') = [tex]-\frac{QE2}{M}[/tex]

total distance S' = distance to turning point + distance from turning point to starting point

S' = S + vt' + 0.5 a'[tex]t'^{2}[/tex]

S' = [tex]\frac{372.65QE1}{M}[/tex] + ([tex]\frac{27.3QE1}{M}[/tex] x 3.03) + (0.5 x [tex]-\frac{QE2}{M}[/tex]x [tex]3.03^{2}[/tex])

S' is the distance at the starting point and = 0

0 = [tex]\frac{372.65QE1}{M} + \frac{82.72QE1}{M}-\frac{4.59QE2}{M}[/tex]

[tex]\frac{4.59QE2}{M}=\frac{372.65QE1}{M} + \frac{82.72QE1}{M}[/tex]

multiplying both side by M/Q we have

4.59.E2 = 372.65E1 + 82.72E1

4.59.E2 = 455.37E1

E2/E1 = 455.37 / 4.59

E2/E1 =99.2

The ratio of the magnitude of electric field E2 to E1, when a proton returns to its initial point after the direction of a uniform electric field changes, is approximately 0.0123.

A proton is initially at rest in an electric field that points due north. After 27.3 seconds, the electric field changes direction and points due south, and after 3.03 seconds the proton returns to its starting point. To find the ratio of the magnitudes of E2 to E1, we must consider the distances covered by the proton under the influence of both fields given that it starts and ends at the same position.

The distance covered under E1 can be calculated using the formula s = 0.5 × a × t^2, where 'a' is the acceleration and 't' is the time. Since the proton moves for 27.3 s under E1, the distance s1 is s1 = 0.5 × a1 × (27.3)^2. The proton then moves in the opposite direction under E2 for 3.03 s, covering the same distance in opposing direction, thus s2 = 0.5 × a2 × (3.03)^2. Since s1 = s2, we can equate them: 0.5 × a1 × (27.3)^2 = 0.5 × a2 × (3.03)^2.

Furthermore, the acceleration of the proton is directly proportional to the electric field (since a = F/m and F = qE), giving us a1 ∝ E1 and a2 ∝ E2. By simplifying the above equation, we find that a1/a2 = (3.03/27.3)^2, and therefore the ratio of the magnitudes of electric fields is also E2/E1 = (3.03/27.3)^2. Calculating this, we get the ratio E2/E1 approximately equal to 0.0123.

Answer:

a) 20.34 N

b)17.64 N

c)16.47 N

d)38.63m

Explanation:

a) F=m*a. Earth gravity is 9.8m/s2. If the elevator goes upwards, tension on the rope will be higher. To find the tension we need to all accelerates. Total accelerates effects the elevator is a=9.8+1.5=11.3 m/s2. Then;

[tex]F=1.8*11.3=20.34[/tex]

the tension is 20.34N

b) There is no accelerate in this situation therefore the tension is:

F=1.8*9.8=17.64 N

c) In this situation elevator goes down. We need to subtract gravity from elevator acceleration. a=9.8-0.65=9.15m/s2

F=1.8*9.15=16.47 N

d) Total distance is:

[tex]x=0.5*a*t^2+v*t+v*t-0.5*a*t^2\\=0.5*1.5*2.2^2+9*(1.5*2.2)+2*(1.5*2.2)-0.5*0.65*2^2\\=38.63 m[/tex]

Answer:

The answer to your question is angle = 18.46°

Explanation:

Data

d = 75 m

v₀ = 35 m/s

α = ?

Formula

                     [tex]d = \frac{vo^{2}sin2\alpha}{g}[/tex]

solve for sin2α

                  sin 2α = [tex]\frac{dg}{vo^{2}}[/tex]

Substitution

                 sin 2α = [tex]\frac{75(9.81)}{35^{2}}[/tex]

Simplify

                sin 2α = [tex]\frac{735.75}{1225}[/tex]

Divide

                sin 2α = 0.600

Get sin⁻¹

                      2α = 36.9°

Divide by 2

                        α = 18.5°                

Answer:

Her angular speed (in rev/s) when her arms and one leg open outward is 1.4 rev/s

Explanation:

given information:

moment inertia of arm and leg when in, I₁ = 0.9 kgm²

moment inertia of arm and leg when extended, I₂ = 2.9 kgm²

angular speed when in, ω₁ = 4.5 rev/s

so, her angular speed (in rev/s) when her arms and one leg open outward is

L₁ = L₂

I₁ω₁ = I₂ω₂

ω₂ = I₁ω₁/I₂

     = 0.9 x 4.5/2,9

     = 1.4 rev/s

Answer:

A small force over a long time period.                                        

Explanation:

The second law of motion gives the relationship between the external force and the change in momentum of the object. The rate of change of linear momentum is equal to the external force applied. It is given by :

[tex]F=\dfrac{\Delta p}{\Delta t}[/tex]

[tex]\Delta p=F\times \Delta t[/tex]

It is clear that for the smallest change in momentum, a small force should be applied for a long period of time. Hence, the correct option is (c) "a small force over a long time period".

Answer:

D. a small force over a short time period

C is incorrect.

Answer:

option (b)

Explanation:

The density of cool air is more so always falls downwards.

Compared to the cool air, the density of air is less and it tends to rise.

Thus, option (b) is correct.

Explanation:

The Natural Greenhouse Effect However, the amount that directly escapes to space is only about 12 percent of incoming solar energy. The remaining fraction—a net 5-6 percent of incoming solar energy—is transferred to the atmosphere when greenhouse gas molecules absorb thermal infrared energy radiated by the surface.