2NH4Cl(s)+Ba(OH)2⋅8H2O(s)→2NH3(aq)+BaCl2(aq)+10H2O(l) The ΔH for this reaction is 54.8 kJ . How much energy would be absorbed if 24.7 g of NH4Cl reacts?
The amount of energy absorbed when 24.7 g of NH4Cl reacts according to the given balanced equation is 12.6 kJ.
Explanation:To calculate the amount of energy absorbed when 24.7g of NH4Cl reacts, we need to first convert grams to moles. The molar mass of NH4Cl is 53.49 grams/mole, therefore, 24.7g of NH4Cl in moles is (24.7 / 53.49) = 0.462 mol.
The given balanced equation tells us that 54.8 kJ of energy is absorbed during the reaction of 2 moles of NH4Cl with Ba(OH)2·8H2O, so the amount of energy absorbed when 0.462 mol react is (0.462/2) * 54.8 kJ = 12.6 kJ.
Learn more about Chemistry energy absorption calculation here:https://brainly.com/question/19054372
#SPJ11
The energy absorbed is 25.2 kJ.
Given ΔH = 54.8 kJ, determine the moles of NH₄Cl from 24.7 g, then use stoichiometry to find the energy absorbed.
Calculation: 24.7 g NH₄Cl (molar mass 53.49 g/mol) = 0.46 mol NH₄Cl. Energy absorbed = 54.8 kJ/mol * 0.46 mol = 25.2 kJ.
How does thermal energy transfer when a room is heated by a furnace?
Answer:
the anser is b
Explanation:
What are the three most abundant elements found on the earths crust that combine to form minerals?
A. Silicon, Iron, Aluminum
B. Oxygen, Silicon, Aluminum
C. Iron, Aluminum, Magnesium
D. Oxygen, Silicon, Iron
Answer:
B. Oxygen, Silicon, Aluminum is the correct answer.
Explanation:
The three most abundant elements found on the earths crust that combine to form minerals are Oxygen, Silicon, Aluminum.
oxygen is the first most abundant element found in the earth's crust, it is present in the main compound of silicate minerals that combines to produce minerals.
The second most abundant element present in the earth's crust is silicon.It combines with oxygen to make silicate minerals.
The third abundant element is aluminum in the earth's crust. The rich compounds of Aluminum contain potassium aluminum sulfate, aluminum hydroxide, and aluminum oxide.
Suppose you decide to define your own temperature scale using the freezing point (13 ∘c) and boiling point (360 ∘c) of oleic acid, the main component of olive oil. if you set the freezing point of oleic acid as 0 ∘o and the boiling point as 140 ∘o, what is the freezing point of water on this new scale?
What reagent would distinguish between Ag+ and Fe3+?
A flask with vinegar in it has a mass of 160 grams. A balloon with baking soda in it has a mass of 40 grams. The balloon is attached to the flask to seal the opening and the vinegar and baking soda mixes. The balloon inflates to a large volume. What will the total mass of the balloon and flask be after the balloon inflates? Explain.
Draw a lewis structure for hnc and assign the non-zero formal charges to each atom. draw the lewis structures with the formal charges minimized.
The Lewis structure for HNC (hydrogen isocyanide) consists of a hydrogen atom bonded to a nitrogen atom, which is then bonded to a carbon atom. The formal charges assigned to each atom are H: 0, N: 0, and C: -1.
The Lewis structure for HNC (hydrogen isocyanide): Determine the total number of valence electrons,
1. Determine the total number of valence electrons:
Hydrogen (H) has 1 valence electron.
Nitrogen (N) has 5 valence electrons.
Carbon (C) has 4 valence electrons.
Total valence electrons = 1 (H) + 5 (N) + 4 (C) = 10 valence electrons
2. Place the least electronegative atom (hydrogen) in the center and connect it to the more electronegative atoms (nitrogen and carbon) using single bonds.
H
|
N - C
3. Fill the remaining valence electrons around each atom to complete their octets (except hydrogen, which only needs 2 electrons).
H: 2 electrons (1 bond)
N: 4 electrons (1 bond) + 4 electrons (lone pairs) = 8 electrons (full octet)
C: 4 electrons (1 bond) + 4 electrons (lone pairs) = 8 electrons (full octet)
H
|
N - C
: :
4. Check if all atoms have achieved their octets. In this case, they have.
The Lewis structure for HNC is:
H
|
N - C
: :
Let's assign formal charges to each atom. The formal charge of an atom is calculated by comparing the number of valence electrons an atom has in a Lewis structure with the number of electrons it "owns" in a molecule.
To calculate the formal charge, we use the formula:
Formal charge = Valence electrons - (Non-bonded electrons + 1/2 * Bonded electrons)
For each atom in HNC:
H: Formal charge = 1 - (0 + 1/2 * 2) = 0
N: Formal charge = 5 - (4 + 1/2 * 2) = 0
C: Formal charge = 4 - (4 + 1/2 * 2) = -1
Know more about hydrogen isocyanide:
https://brainly.com/question/31181111
#SPJ6
Look at the diagram of an electrochemical cell below.
(picture below)
Which part of the cell is the anode?
Na+
SO42-
nickel electrode
platinum electrode
Use the given molar solubilities in pure water to calculate ksp for each compound. part a bacro4; molar solubility =1.08×10−5m
To calculate the Ksp for barium chromate (BaCrO₄), we use the given molar solubility of 1.08 × 10⁻⁵ M. The equilibrium concentrations of the ions are equal to the molar solubility, and the Ksp is calculated as (1.08 × 10⁻⁵)², resulting in 1.1664 × 10⁻¹⁰
To determine the solubility product constant (Ksp) for barium chromate (BaCrO₄), we need to use the given molar solubility in pure water, which is 1.08 × 10⁻⁵ M.
The dissociation equation for BaCrO₄ in water is: BaCrO₄ (s) ⇌ Ba²⁺ (aq) + CrO₄²⁻(aq)At equilibrium, the concentration of Ba²⁺ ions is equal to the molar solubility, s, and the concentration of CrO₄²⁻ ions is also s.
Thus, the Ksp expression is given by: Ksp = [Ba²⁺][CrO₄²⁻] = s × s = s²Plugging in the given molar solubility:
Ksp = (1.08 × 10−5)²Ksp = 1.1664 × 10⁻¹⁰Therefore, the solubility product constant (Ksp) for barium chromate (BaCrO₄) is 1.1664 × 10⁻¹⁰
Correct question is: Use the molar solubility 1.08×10⁻⁵M in pure water to calculate Ksp for BaCrO₄
If 2.4 g of n2 gas has a volume of 0.40 l and a pressure of 6.6 atm , what is its kelvin temperature?
To solve for the absolute temperature, we assume ideal gas behaviour so that we use the equation:
PV = nRT
or T = PV / nR
So calculating:
T = [6.6 atm * 0.40 L] / [(2.4g / 28g/mol) * 0.08205746 L atm / mol K]
T = 375.35 K
H3c6h5o7(aq) + 3nahco3(aq) → 3co2(g) + 3h2o(l) + na3c6h5o7(aq) calculate the number of grams of baking soda (nahco3; molar mass 84.00661 g/mol) that will react with 30.0 ml of 1 m citric acid.
Final answer:
7.560595 grams of baking soda are required to react with 30.0 mL of 1 M citric acid, calculated using the stoichiometry of the reaction where 1 mole of citric acid reacts with 3 moles of baking soda.
Explanation:
To calculate the number of grams of baking soda (NaHCO3) that will react with 30.0 mL of 1 M citric acid (H3C6H5O7), we first use the balanced chemical equation:
H3C6H5O7(aq) + 3NaHCO3(aq) → 3CO2(g) + 3H2O(l) + Na3C6H5O7(aq)
From the equation, 1 mole of citric acid reacts with 3 moles of baking soda. Since we have 30.0 mL of a 1 M solution of citric acid, which is equivalent to 0.030 liters, the number of moles of citric acid is 0.030 moles (1 M × 0.030 L).
Knowing the moles of citric acid, we can find the moles of baking soda needed:
0.030 moles H3C6H5O7 × (3 moles NaHCO3 / 1 mole H3C6H5O7) = 0.090 moles NaHCO3To find the mass of 0.090 moles of baking soda:
Mass = moles × molar massMass = 0.090 moles × 84.00661 g/mol = 7.560595 gTherefore, 7.560595 grams of baking soda are required to react with 30.0 mL of 1 M citric acid.
What is the mass of 3.00 moles of magnesium chloride, MgCl2? Express your answer with the appropriate units.
The mass of 3.00 moles of magnesium chloride (MgCl2) is calculated by multiplying the number of moles by the molar mass of MgCl2, giving a result of 285.63 grams.
Explanation:To calculate the mass of 3.00 moles of magnesium chloride (MgCl2), we will use the molar mass of MgCl2. The molar mass of MgCl2 is 95.21 grams per mole. Therefore, to find the mass, multiply the number of moles by the molar mass:
Mass = moles × molar mass
Mass = 3.00 moles × 95.21 g/mol = 285.63 grams of MgCl2
The mass of 3.00 moles of magnesium chloride is thus 285.63 grams.
How many grams of H2 are needed to produce 14.10 g of NH3?
Rutherford and Soddy's research involved:
1)Deflection of alpha particles caused by positive nucleus
2)Defining the components of atomic nuclei
3)The theory that uranium successively disintegrated to lead
4)Non of the above
Answer: -
Rutherford and Soddy's research involved:
3)The theory that uranium successively disintegrated to lead
Radioactivity involves conversion of one atom of an element into another by particle decay or radiation. They stated the disintegration theory of radioactivity, also discovering a large number of radioactive elements.
They both got Nobel prizes as well.
When the equation Ca(OH)2 + HBr → (products) is completed and balanced, one term in the equation will be
Determine the number of atoms in a 48.3-g sample of zinc. express your answer in zinc atoms using scientific notation.
do free electrons exist under normal conditions
Will ag2so4 precipitate when 100 ml of 5.0×10−2 m agno3 is mixed with 10 ml of 5.0×10−2mna2so4 solution?
Silver sulfate (Ag₂SO₄) does not precipitate when 100 mL of 5.0×10⁻² M AgNO3 is mixed with 10 mL of 5.0×10⁻² M Na₂SO₄ because the reaction quotient is less than the solubility product constant.
Precipitation of Ag₂SO₄ When Mixing Solutions:
To determine if silver sulfate (Ag₂SO₄) will precipitate when mixing 100 mL of 5.0×10⁻² M AgNO₃ with 10 mL of 5.0×10⁻² M Na₂SO₄, we need to calculate the concentrations of Ag⁺ and SO₄ ²⁻ ions after mixing.
First, calculate the moles of each ion:
Ag⁺: 0.1 L × 5.0×10⁻² M = 5.0×10⁻³ molesSO₄²⁻: 0.01 L × 5.0×10⁻² M = 5.0×10⁻⁴ molesWhen mixed, the total volume is 110 mL (0.110 L), so the new concentrations are:
[Ag⁺] = 5.0×10⁻³ moles / 0.110 L ≈ 4.55×10⁻² M[SO₄²⁻] = 5.0×10⁻⁴ moles / 0.110 L ≈ 4.55×10⁻³ MThe solubility product (Ksp) of Ag₂SO₄ is 1.2×10⁻⁵. To check for precipitation:
Q = [Ag⁺]² [SO₄²⁻] ≈ (4.55×10⁻²)² × 4.55×10⁻³ = 9.45×10⁻⁷
Since Q < Ksp (9.45×10⁻⁷ < 1.2×10⁻⁵), Ag₂SO₄ does not precipitate.
A boy is pushing on a heavy door, trying to slide it open. His friend stands behind him and helps him push.
How have the forces changed?
A.
The net force applied will increase.
B.
The net force will decrease.
C.
There will be less friction.
D.
The applied force will not change.
_________ is amount of “ground” an object moves from its starting point and __________ is how much “ground” and object covers in total.
Got this question incorrect and no matter how hard I try I can't figure it out!
If the enantiomeric excess of a mixture is 75%, what are the % compositions of the major and minor enantiomer?
Let us say that R is the major enantiomer, while S is the minor enantiomer, therefore the formula for enantiomeric excess (ee) is:
ee = (R – S) * 100%
Let us further say that the fraction of R is x (R = x), and therefore fraction of S is 1 – x (S = 1 – x), therefore:
75 = (x – (1 – x)) * 100
75 = 100 x – 100 + 100 x
200 x = 175
x = 0.875
Summary of answers:
R = major enantiomer = 0.875 or 87.5%
S = minor enantiomer = (1 – 0.875) = 0.125 or 12.5%
The image formed by a lens may be real or virtual. The image formed by a lens is always virtual.
The image formed by a lens can be either real or virtual, depending on the position of the object relative to the lens and the type of lens used. Real images are formed when light rays converge at a point after passing through the lens, while virtual images are formed when the extended light rays appear to diverge from a point behind the lens.
The statement is not accurate. The image formed by a lens can be either real or virtual, depending on the position of the object relative to the lens and the type of lens used.
Real Image: A real image is formed when light rays converge at a point after passing through the lens. This image can be captured on a screen because the light rays converge at a specific location. Real images are formed by convex lenses when the object is placed beyond the focal point and by concave lenses when the object is placed within the focal point.Virtual Image: A virtual image is formed when the extended light rays appear to diverge from a point behind the lens. This image cannot be captured on a screen because the light rays only appear to converge when extended backward. Virtual images are typically formed by convex lenses when the object is placed within the focal point and by concave lenses when the object is placed beyond the focal point.So, the statement that the image formed by a lens is always virtual is incorrect. The nature of the image (real or virtual) depends on the specific conditions and the type of lens used.
Answer:
Convex and Concave
Explanation:
Took Test
Draw a structural formula of an alkene or alkenes (if more than one) that undergo acid-catalyzed hydration and without rearrangement give 1-methylcyclohexanol as the major product.
The alkene that would undergo acid-catalyzed hydration without rearrangement to give 1-methylcyclohexanol is 1-methylcyclohexene. During hydration, one of the carbon-carbon double bonds breaks, binds with hydrogen, and the other hydrogen forms a bond with the oxygen to form an alcohol.
Explanation:The major product of the acid-catalyzed hydration of an alkene without rearrangement is 1-methylcyclohexanol. This suggests that the initial alkene contains a double bond which would shift to form the alcohol after the reaction. By adding water and acid to an alkene, we have the general reaction mechanism:
The alkene reacts with H2O in the presence of H3O+ (from the acid). One of the alkenes' carbon-carbon double bonds breaks and forms a bond with the hydrogen atom from the H3O+. The other hydrogen from the H3O+ ion forms a bond with the oxygen, resulting in an alcohol.
Therefore, the structural formula of the alkene that would produce 1-methylcyclohexanol through an acid-catalyzed hydration reaction without rearrangement is 1-methylcyclohexene.
Learn more about Acid-Catalyzed Hydration of Alkenes here:https://brainly.com/question/31732900
#SPJ6
Consider the hydrocarbon below.
What is the name of this hydrocarbon?
1-ethyne
1-pentyne
1-ethane
1-butyne
Answer: Option (b) is the correct answer.
Explanation:
The given hydrocarbon has five carbon atoms. Also, there is a triple bond at the extreme right end, therefore it is an alkyne.
Since there is only a triple bond in the give hydrocarbon chain. So, numbering will be started from extreme right end in order to give least number to the triple bond.
Hence, name of the given hydrocarbon is 1-pentyne.
How many moles of gas were added to a balloon that started with 2.3 moles of gas and a volume of 1.4 l given that the final volume was 7.2 l?
a.12
b.0.085
c.4.4
d.9.5
e.none of the above?
The number of moles of gas were added to a balloon that started with 2.3 moles of gas and a volume increases from 1.4L to 7.2L is 11.82 moles.
How do we calculate moles?Number of moles of any gas will be calculated by uisng the ideal gas equation PV = nRT, for the given question equation becomes as:
V₁/n₁ = V₂/n₂, where
V₁ = initial volume = 1.4L
n₁ = initial moles = 2.3mol
V₂ = final volume = 7.2L
n₂ = final moles = ?
On putting values, we get
n₂ = (7.2)(2.3) / (1.4) = 11.82 moles
Hence required moles of gas is 11.82 mol.
To know more about ideal gas equation, visit the below link:
https://brainly.com/question/15046679
#SPJ3
According to the Law of Conservation of Matter is this drawing accurate?
A. The drawing is correct because there are larger molecules on the reactant side.
B. The drawing is incorrect, because there are more molecules on the products side.
C. The drawing is correct, because there are eight white atoms and eight red atoms on each side of the reaction.
D. The drawing is incorrect, because there are different numbers of molecules on each side of the reaction.
What is the molarity of a naoh solution if 11.9 ml of a 0.220 m h2so4 solution is required to neutralize a 25.0-ml sample of the naoh solution?
Answer : The concentration of the [tex]NaOH[/tex] is, 0.209 M
Explanation :
Using neutralization law,
[tex]n_1M_1V_1=n_2M_2V_2[/tex]
where,
[tex]n_1[/tex] = basicity of an acid [tex]H_2SO_4[/tex] = 2
[tex]n_2[/tex] = acidity of a base (NaOH) = 1
[tex]M_1[/tex] = concentration or molarity of [tex]H_2SO_4[/tex] = 0.220 M
[tex]M_2[/tex] = concentration or molarity of NaOH = ?
[tex]V_1[/tex] = volume of [tex]H_2SO_4[/tex] = 11.9 ml
[tex]V_2[/tex] = volume of NaOH = 25.0 ml
Now put all the given values in the above law, we get the concentration of the [tex]NaOH[/tex].
[tex]2\times 0.220M\times 11.9ml=1\times M_2\times 25.0ml[/tex]
[tex]M_2=0.209M[/tex]
Therefore, the concentration of the [tex]NaOH[/tex] is, 0.209 M
A compound with the empirical formula SiH3 was found to have a molar mass of approximately 62 g. What is the molecular formula of the compound?
The molecular formula of a compound with the empirical formula SiH3 and a molar mass of 62 g is Si2H6.
Explanation:The subject of the question is the molecular formula of the compound with the empirical formula SiH3 and a molar mass of 62 g. The empirical formula mass of this compound can be calculated from its components: Si stands for silicon, with an atomic mass of roughly 28 g/mol, and H stands for hydrogen, with an atomic mass of roughly 1 g/mol. So the total atomic mass of SiH3 would be 31 g/mol. Comparing this with the given molar mass of 62 g/mol, we can deduce that the molecule contains two empirical formula units. Therefore, the molecular formula should be Si2H6.
Learn more about Molecular Formula here:https://brainly.com/question/28647690
#SPJ11
Limonene is the natural product found in orange peel. draw the major product of the reaction of limonene with bromine under the conditions shown. stereochemistry is not required.
As shown in scheme attached below, Limonene (C₁₀H₁₆) contains two double bond one within the six membered ring and another outside the ring.
Hence, it is an unsaturated compound. As we know an Addition reaction takes place in unsaturated compounds. Therefore, an addition reaction called as Halogenation reation or more specifically Bromination reaction takes place when Limonene is treated with Bromine in the presence of inert solvent like tetrachloromethane.
The reaction is shown below, two moles of Br₂ are added across two double bonds of Limonene yielding a product with chemical formula C₁₀H₁₆Br₂.
The progress of this reaction can be easily be monitored as the color of Bromine discharges with the formation of tetrabromo product.
The major product formed when limonene reacts with bromine is tetra brominated limonene and that is attached in the image.
Further Explanation:
Electrophilic addition reaction is defined as an organic reaction in which an electrophile attacks on the electron-rich pi bond and add across the double bonds forming two new sigma bonds. An electrophile is an electron deficient species.
The reaction of alkene with bromine is an electrophilic addition reaction. The mechanism of addition can be illustrated in two steps. In the first step, [tex]{\text{B}}{{\text{r}}_{\text{2}}}[/tex] comes in the vicinity of olefin bond and being electrophilic it attacks on the electron-rich olefinic bond, forming a sigma bond to each of the olefinic bond. Such interaction results in formation of a bromonium ion intermediate that is three-membered intermediate rings.
In the second step, the strained three-membered ring then opens up such that the other bromine atom can attack at the electron-deficient carbon atom.
The limonene is a terpenoid that has olefinic bonds present inside the ring as well as on the side chain. The reaction of limonene with bromine is an electrophilic addition reaction
The mechanistic pathway and the stereospecific anti-addition of bromine to alkenes is described in the attached image.
This attack proceeds in a stereospecific manner such that only anti addition is allowed and the addition product has the trans stereochemistry.
Learn more:
1. Identify the precipitate in the reaction: https://brainly.com/question/8896163
2. Balanced chemical equation: https://brainly.com/question/1405182
Answer details:
Grade: College
Subject: Chemistry
Chapter: Electrophilic addition reaction
Keywords: limonene, electrophilic addition, major product, olefin, anti-addition, anti-addition, stereospecific.