At a certain college there are twice as many English majors as history majors and three times as many English majors as mathematics majors. What is the ratio of the number of history majors to the number of mathematics majors?A. 6 to 1B. 3 to 2C. 2 to 3D. 1 to 5E. 1 to 6

Answer:

The answer is 8

Step-by-step explanation:

Lets consider that Sam's call will last x minutes in total. Then, equations for cost will be as follows:

A Pay Phone Cost: [tex]p(x)=1+0,5*x[/tex]

Operator Cost: [tex]o(x)=3+0,25*x[/tex]

If we make both costs equal, the equation will be:

[tex]1+0,5*x=3+0,25*x\\0,25*x=2\\x=8[/tex]

Sam's call need to last 8 minutes to make payphone cost and operator cost same.

Answer:

See proof below

Step-by-step explanation:

Let [tex]r=\frac{w+z}{1+wz}[/tex]. If w=-z, then r=0 and r is real. Suppose that w≠-z, that is, r≠0.

Remember this useful identity: if x is a complex number then [tex]x\bar{x}=|x|^2[/tex] where [tex]\bar{x}[/tex] is the conjugate of x.

Now, using the properties of the conjugate (the conjugate of the sum(product) of two numbers is the sum(product) of the conjugates):

[tex]\frac{r}{\bar{r}}=\frac{w+z}{1+wz} \left(\frac{1+\bar{w}\bar{z}}{\bar{w}+\bar{z}}{\right)[/tex]

=[tex]\frac{(w+z)(1+\bar{w}\bar{z})}{(1+wz)(\bar{w}+\bar{z})}=\frac{w+z+w\bar{w}\bar{z}+z\bar{z}\bar{w}}{\bar{w}+\bar{z}+\bar{w}wz+\bar{z}zw}=\frac{w+z+w+|w|^2\bar{z}+|z|^2\bar{w}}{\bar{w}+\bar{z}+|w|^2z+|z|^2w}=\frac{w+z+\bar{z}+\bar{w}}{\bar{w}+\bar{z}+z+w}=1[/tex]

Thus [tex]\frac{r}{\bar{r}}=1[/tex]. From this, [tex]r=\bar{r}[/tex]. A complex number is real if and only if it is equal to its conjugate, therefore r is real.

The ratio of sixth-grade students to fifth-grade students is 7/8 or 7:8

Step-by-step explanation:

Let us define ratio first.

"Ratio is the quantitative relationship between two quantities which tells that one quantity is how many times of another quantity"

Given

Number of fifth grade students = 8

Number of sixth grade students = 7

We have to find the ratio of sixth grade students to fifth grade students

So,

[tex]r = \frac{sixth-grade\ students}{fifth-grade\ students}\\r = \frac{7}{8}\\r = 7:8[/tex]

Hence,

The ratio of sixth-grade students to fifth-grade students is 7/8 or 7:8

Keywords: ratio, fraction

Learn more about fraction at:

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Answer:

(√2 − √6) / 4

Step-by-step explanation:

Rewrite using special angles.

sin(-11π/12)

sin((4−15)π/12)

sin(4π/12 − 15π/12)

sin(π/3 − 5π/4)

Use angle difference formula:

sin(π/3) cos(5π/4) − sin(5π/4) cos(π/3)

Evaluate:

(√3/2) (-√2/2) − (-√2/2) (1/2)

-√6/4 + √2/4

(√2 − √6) / 4

Answer:

  8x^2 + 34; 45.52 centimeters

Step-by-step explanation:

The perimeter is twice the sum of adjacent edges of a rectangle:

  P = 2((2x^2 +9) +(2x^2 +8)) = 2(4x^2 +17)

  P = 8x^2 +34

Then when x=1.2, the perimeter is ...

  P = 8(1.2^2) +34 = 8·1.44 +34 = 45.52 . . . . cm

Answer:

The Answer is: B  8x^2 + 34; 45.52 centimeters

Step-by-step explanation:

Took it on edg

Answer:

11 slips

Step-by-step explanation:

A perfect square is a positive integer that is the square of another integer. For example, 25 is a perfect square of 5. See the calculation below

.

[tex]5^{2} = 5*5\\5^{2} = 25[/tex]

There is a rule that should be kept in mind

1. When two perfect squares are multiplied by each other (e.g. 4 * 9), the result is a perfect square ([tex]36 = 6^{2}[/tex])

Let's identify the combination of numbers that result in perfect square, when multiplied with each other. These combinations are as follows,

• 1*4, 1*9, 1*16  

• 2*8  

• 3*12  

• 4*9, 4*16  

• 9*16  

From the list of numbers 1, 4, 9 and 16 are already perfect square e.g. [tex]2^{2} = 4, 3^{2} = 9[/tex]. If they are multiplied by each other, the result will also be a perfect square. Let’s assume that our first number is 1. Now we can't have any of the three numbers (except for 1), mentioned above. This rule out these three numbers.  

Next, from 2, 8, 3 and 12 we can only draw two numbers. e.g. if we take 2, we can’t take 8 as it will give a perfect square. Same goes with 3 and 12. Hence from these four numbers we can discard two of them.

We discarded three numbers initially and two now. Therefore, out of 16 slipds we can draw a maximum of 11 slips without obtaining a product that is a perfect square.

Answer:

A. Between 14 and 15.

Step-by-step explanation:

Let x be the one leg of the right triangle.

We have been given that the legs of a right triangle are in the ratio of 3 to 1. So, the other leg of the right triangle would be 3x.

We are also told that the length of the hypotenuse of the triangle is √40.

Using Pythagoras theorem, we can set am equation as:

[tex]x^2+(3x)^2=(\sqrt{40})^2[/tex]

Let us solve for x.

[tex]x^2+9x^2=40[/tex]

[tex]10x^2=40[/tex]

[tex]\frac{10x^2}{10}=\frac{40}{10}[/tex]

[tex]x^2=4[/tex]

Take square root of both sides:

[tex]x=\sqrt{4}[/tex]

[tex]x=2[/tex]

The other leg would be [tex]3x\Rightarrow 3\cdot 2=6[/tex].

The perimeter of the triangle would be:

[tex]\text{Perimeter of triangle}=2+6+\sqrt{40}[/tex]

[tex]\text{Perimeter of triangle}=2+6+6.324555[/tex]

[tex]\text{Perimeter of triangle}=14.324555[/tex]

Therefore, the perimeter of the triangle is between 14 and 15 and option A is the correct choice.

The shape and bond angle of oxy-nitrogen ions is determined by the number of bonds and lone pairs around the central atom, with examples being trigonal pyramidal for nitrogen with three bonds and one lone pair, tetrahedral for carbon with four bonds, and bent for oxygen with two bonds and two lone pairs.

The oxynitrogen ions have specific shapes and bond angles that correlate with their electron-pair geometries. For example, a nitrogen atom with three bonds and one lone pair will have a trigonal pyramidal shape with bond angles close to 109°. Carbon atoms in different environments also exhibit varied shapes: a carbon atom in CH₂ with four bonds and no lone pairs has a tetrahedral shape with bond angles of 109.5°, while a carbon atom in CO₂ with two double bonds (treated as equivalent to three bonds) and no lone pairs forms a trigonal planar shape.

An oxygen atom in OH with two bonds and two lone pairs has a bent or angular shape with bond angles close to 109°. It's essential to note that electron pair repulsion and hybridization of orbitals play a crucial role in determining these geometric shapes and the bond angles.

Based on the options provided and the common shapes of oxynitrogen ions, the correct answer would be:

- Trigonal planar, 120°

- Tetrahedral, 109.5°

- Bent, 120°

- Pyramidal, 109°

These shapes and bond angles are commonly observed in oxynitrogen ions depending on the arrangement of atoms and lone pairs around the central nitrogen atom.

The shape and bond angle of oxynitrogen ions depend on the arrangement of atoms and lone pairs around the central nitrogen atom. Let's go through each option:

1. Linear, 180°: This shape occurs when there are no lone pairs on the central nitrogen atom, and there are two bonded atoms around it. The bond angle is indeed 180°.

2. Trigonal planar, 120°: This shape occurs when there is one lone pair and three bonded atoms around the central nitrogen atom. The bond angle is indeed 120°.

3. Tetrahedral, 109.5°: This shape occurs when there are four bonded atoms around the central nitrogen atom and no lone pairs. The bond angle is indeed 109.5°.

4. Bent, 120°: This shape occurs when there is one lone pair and two bonded atoms around the central nitrogen atom. The bond angle is close to 120° but may deviate slightly due to lone pair-bond pair repulsions.

5. Bent, 109°: This shape is less common for oxynitrogen ions but can occur if there is a lone pair and two bonded atoms around the central nitrogen atom. The bond angle would be closer to 109° due to lone pair-bond pair repulsions.

6. Pyramidal, 109°: This shape occurs when there is one lone pair and three bonded atoms around the central nitrogen atom. The bond angle is indeed close to 109°.

Based on the options provided and the common shapes of oxynitrogen ions, the correct answer would be:

- Trigonal planar, 120°

- Tetrahedral, 109.5°

- Bent, 120°

- Pyramidal, 109°

These shapes and bond angles are commonly observed in oxynitrogen ions depending on the arrangement of atoms and lone pairs around the central nitrogen atom.

Answer:

a) [tex]P(X>3.0)=1-P(X \leq 3.0)= 1- [1- e^{-\frac{1}{2.4} 3.0}]=e^{-\frac{1}{2.4} 3.0}=0.287[/tex]

b) [tex]P(2<X<3)= 1- e^{-\frac{1}{2.4} 3} -[ 1- e^{-\frac{1}{2.4} 2}][/tex]

[tex]P(2<X<3)=e^{-\frac{1}{2.4} 2}- e^{-\frac{1}{2.4} 3}=0.435-0.287=0.148[/tex]

Step-by-step explanation:

Definitions and concepts

The Poisson process is useful when we want to analyze the probability of ocurrence of an event in a time specified. The probability distribution for a random variable X following the Poisson distribution is given by:

[tex]P(X=x) =\lambda^x \frac{e^{-\lambda}}{x!}[/tex]

And the parameter [tex]\lambda[/tex] represent the average ocurrence rate per unit of time.

The exponential distribution is useful when we want to describ the waiting time between Poisson occurrences. If we assume that the random variable T represent the waiting time btween two consecutive event, we can define the probability that 0 events occurs between the start and a time t, like this:

[tex]P(X>x)= e^{-\lambda x}[/tex]

We can express in terms of the mean [tex]\mu =\frac{1}{\lambda}[/tex]

[tex]P(X>x)= e^{-\frac{1}{\mu} x}[/tex]

And the cumulative function would be given by the complement rule like this:

[tex]P(X\leq x)=1- e^{-\frac{1}{\mu} x}[/tex]

Solution for the problem

For this case we have that X the random variable that represent the magnitude of earthquakes recorded in a region of North America, we know that the distribution is given by:

[tex]X\sim Expon(\mu =2.4)[/tex]

a) Find theprobability that an earthquake striking this region will a exceed 3.0 on the Richter scale

So for this case we want this probability:

[tex]P(X>3.0)=1-P(X \leq 3.0)= 1- [1- e^{-\frac{1}{2.4} 3.0}]=e^{-\frac{1}{2.4} 3.0}=0.287[/tex]

b) fall between 2.0 and 3.0 on the Richter scale.

For this case we want this probability:

[tex]P(2 < X <3) = P(X<3) -P(X<2)[/tex]

And replacing we have this:

[tex]P(2<X<3)= 1- e^{-\frac{1}{2.4} 3} -[ 1- e^{-\frac{1}{2.4} 2}][/tex]

[tex]P(2<X<3)=e^{-\frac{1}{2.4} 2}- e^{-\frac{1}{2.4} 3}=0.435-0.287=0.148[/tex]

Answer:

1) [tex]\Delta t=-0.5*t_{X}[/tex]

2) [tex]\Delta t=2*t_{X}[/tex]

Step-by-step explanation:

1) X=production rate of X (units/hour)

Y=production rate of Y (units/hour)

C=order (units)

t=working time (hour)

[tex](X+Y)*t_{toghether}=C[/tex]

[tex]X*t_{X}=C[/tex]

[tex]t_{toghether}=2/3*t_{X}[/tex]

Combining:

[tex](X+Y)*2/3*t_{X}=X*t_{X}[/tex]

[tex](X+Y)*2/3=X[/tex]

[tex]Y*2/3=X-2/3*X[/tex]

[tex]Y=2X[/tex]

In time: [tex]t_{Y}=0.5*t_{X}[/tex]

Difference of time: [tex]\Delta t=0.5*t_{X}-t_{X}=-0.5*t_{X}[/tex]

2) [tex]Y*t_{Y}=C[/tex]

[tex]X*t_{X}=C[/tex]

[tex]t_{Y}=2*t_{X}[/tex]

Difference of time: [tex]\Delta t=2*t_{X}-0.5*t_{X}=2*t_{X}[/tex]

Answer:

EF = (d − b) / 2

Step-by-step explanation:

Let's say that G is the intersection of the trapezoid's diagonals.

Triangle GBC is similar to triangle GDA, so we can write a proportion:

GD / GB = AD / BC

GD / GB = d / b

GD = (d / b) GB

Next, F is the midpoint of BD, so BF equals FD.

BF = FD

GB + GF = GD − GF

2GF = GD − GB

2GF = (d / b) GB − GB

2GF = ((d − b) / b) GB

GF / GB = (d − b) / (2b)

Finally, triangle GBC is similar to triangle GFE, so we can write another proportion:

GF / GB = EF / BC

(d − b) / (2b) = EF / b

EF = (d − b) / 2

Answer:

the answer is na

Step-by-step explanation:

Final answer:

The permutation rule (with different items) applies to this problem because repetition is allowed. The permutation rule (with some identical items) and the combination rule cannot be used with repetition.

Explanation:

The correct answer is A. The permutation rule (with different items) applies to this problem because repetition is allowed. The permutation rule (with some identical items) and the combination rule cannot be used with repetition. The calculations for this lottery game involve the permutation rule because the bettor selects four numbers between 0 and 9, and any selected number can be used more than once. The permutation rule allows for repetition and ensures that the order of the selected numbers is taken into account when determining the probability of winning the top prize.

Answer:

  y = 2^x +5

Step-by-step explanation:

The number of new houses doubles each month, so the base (b) is that multiplier, 2. Then x is the number of months since the construction started (presumably at the end of the open house). If you want x to be something else, then h needs to be chosen so that (x -k) is the number of months the doubling has been taking place.

The value h represents the initial build of 5 houses. This is confirmed by the number 261 = 256 + 5 = 2^8 +5.

So, your equation for the number of houses built over time is ...

  y = 2^x +5

Answer:

A.102%

Step-by-step explanation:

Let cost price of painting=$100

In first year price increased 20%

Then , the price=[tex]100+100(0.20)=[/tex]$120

In second year

Price decreased 15%

Then , the price of painting=[tex]120-120(0.15)[/tex]

The price of painting=$102

Percent =[tex]\frac{final\;price}{Initial\;price}\times 100[/tex]

By using this formula

Then, we get

Percent of the original price=[tex]\frac{102}{100}\times 100[/tex]

Percent of the original price=102%

Option A is true.

Answer: E. 120

The number of seniors were there in high school X at the beginning of the year = 120

Step-by-step explanation:

Given : At the beginning of the year, the ratio of juniors to seniors in high school X was 3 to 4.

Let the number of juniors be 3x and the number of seniors be 4x.

Since , during the year, 10 juniors and twice as many seniors transferred to another high school, while no new students joined high school X.

i.e. Number of juniors at the end of the year = 3x-10

Number of seniors at the end of the yea = 4x-2(10)=4x-20

At the end of the year, the ratio of juniors to seniors was 4 to 5.

[tex]\Rightarrow\dfrac{3x-10}{4x-20}=\dfrac{4}{5}[/tex]

[tex]\Rightarrow5(3x-10)=4(4x-20)[/tex]

[tex]\Rightarrow15x-50=16x-80[/tex]

[tex]\Rightarrow16x-15x=80-50[/tex]

[tex]\Rightarrow x=30[/tex]

The number of seniors were there in high school X at the beginning of the year = 4(30)=120

Hence, the correct answer is E. 120 .

To find the number of seniors at the high school X at the beginning of the year, calculate based on the given ratio and student transfers.

At the beginning of the year:

Answer:

  -273

Step-by-step explanation:

The n-th term of the sequence is given by ...

  an = a1 +d(n -1)

Filling in the given values and doing the arithmetic, we get ...

  a100 = 222 +(-5)(100 -1) = 222 -495

  a100 = -273

Answer:

-273

Step-by-step explanation:

Answer: b. 2x = 30

Step-by-step explanation:

Given : 30 states joined the United States between 1776 and 1849

and x states joined between 1850 and 1900 .

If the number of states that joined the United States between 1776 and 1849 is twice the number of states that joined between 1850 and 1900.

i.e. No. of states joined the United States between 1776 and 1849= 2 (No. of states that joined between 1850 and 1900)

i.e . 30=  2(x)          [Substitute the values]

i.e . 2x=30

Hence, the true equation : 2x=30

Answer:

The answer is 1240

Step-by-step explanation:

We know that tuxedo shop rents different number of tuxedos each day and at max they rented 55 tuxedos in May. To maximize the number of tuxedos that rented, rented number of tuxedos need to be drop down by 1 for each day. So minimum 25 tuxedos were rented in May. To find the maximum number of tuxedos that rented in May, we need to add all numbers with using the formula for adding consecutive numbers.

[tex]Total = ((55+25)/2)*31=1240[/tex]

The cost of one pack of coffee is $12 and cost of one tea pack is $6.

Step-by-step explanation:

Let,

Cost of one pack of coffee = x

Cost of one pack of tea = y

According to given statement;

39x+45y=738    Eqn 1

11x+13y=210       Eqn 2

Multiplying Eqn 1 by 11

[tex]11(39x+45y=738)\\429x+495y=8118\ \ \ Eqn\ 3\\[/tex]

Multiplying Eqb 2 by 39

[tex]39(11x+13y=210)\\429x+507y=8190\ \ \ Eqn\ 4[/tex]

Subtracting Eqn 3 from Eqn 4

[tex](429x+507y)-(429x+495y)=8190-8118\\429x+507y-429x-495y=72\\12y=72[/tex]

Dividing both sides by 12

[tex]\frac{12y}{12}=\frac{72}{12}\\y=6[/tex]

Putting y=6 in Eqn 2

[tex]11x+13(6)=210\\11x+78=210\\11x=210-78\\11x=132[/tex]

Dividing both sides by 11

[tex]\frac{11x}{11}=\frac{132}{11}\\x=12[/tex]

The cost of one pack of coffee is $12 and cost of one tea pack is $6.

Keywords: linear equation, subtraction

Learn more about linear equations at:

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Answer:

A pack of coffee=$12

A pack of tea=$6

Step-by-step explanation:

Let the cost of 1 pack of coffee =c

and the cost of 1 pack of tea =t

we can the write the following equations

39c+45t=738...........eqn(1)

11c+13t=738...........eqn(2)

Multiply eqn(1) by 11

429c+495t=8118...........eqn(3)

Multiply eqn(2) by 39

429c+507t=8190...........eqn(4)

eqn(4)-eqn(3)

This implies

12t=72

Dividing through by 12 ,we get

t=6

substituting the value of t into equation two,we obtain

11c+13(6)=210

11c+78=210

11c=210-78

11c=132

Dividing through by 11,we obtain

c=12

Answer:

The statement is true only when both (1) and (2) are valid. If only one of (1) and (2) is valid, them the statement is not true.

Step-by-step explanation:

(1) alone is not sufficient, 27 is 3³ but is not a 12th power

(2) alone is not sufficient either, 81 is 3³ but it is not a 12th power

If both (1) and (2) are valid, then for each prime p that divides x, p should divide y and z, with y³ = x and z⁴=x.

Lets suppose that k is the highest power of p that divides y and m is the highest power that divides z, then (p^k)³ = (p^m)⁴. Therefore

p^3k = p^4m

This means that the power of p that appears on x is a multiple of both 3 and 4. Since those numbers are coprime, then that power is a multiple of 12.

This ensures that every prime dividing x has at least a power of 12 in the prime factirization, hence x is a 12th power.

Answer:

We can expect 8255 numbers of students are liberal arts majors.

Step-by-step explanation:

Given:

Total Number of students in the college = 8943

Now According to Mr. Jones Survey;

60 out of 65 students are liberal arts majors.

We need to find the number of students who are liberal arts majors out of total number of students in college.

Solution:

First we will find the Percentage number of students who are liberal arts majors according to survey.

Percentage number of students who are liberal arts majors can be calculated by dividing 60 from 65 then multiplying by 100.

framing above quote in equation form we get;

Percentage number of students who are liberal arts majors = [tex]\frac{60}{65}\times 100 = 92.31\%[/tex]

Now we will find the Total number of students who are liberal arts major.

Total number of students who are liberal arts major can be calculated by Multiplying Percentage number of students who are liberal arts majors with total number of students in the college and then dividing by 100.

framing above quote in equation form we get;

Total number of students who are liberal arts major = [tex]\frac{92.31}{100}\times 8493 \approx8255.28[/tex]

Since number of students cannot be in point, so we will round the value.

Hence We can expect 8255 numbers of students are liberal arts majors.

Carter has 25 dimes

Solution:

Let "n" be the number of nickels

Let "d" be the number of dimes

Given that Carter has 37 coins, all nickels and dimes in his piggy bank

number of nickels + number of dimes = 37

n + d = 37 -------- eqn 1

Given that value of coins is $ 3.10

Also, value of nickel is 0.05 dollar and value of dime is 0.10 (in dollars) and total value of these 37 coins is 3.10, so we can write:

number of nickels x value of 1 nickel + number of dimes x value of 1 dime = 3.10

[tex]n \times 0.05 + d \times 0.10 = 3.10[/tex]

0.05n + 0.10d = 3.10 ------- eqn 2

Let us solve eqn 1 and eqn 2 to find values of "n" and "d"

From eqn 1,

n = 37 - d ---- eqn 3

Substitute eqn 3 in eqn 2

0.05(37 - d) + 0.10d = 3.10

1.85 - 0.05d + 0.10d = 3.10

0.05d = 3.10 - 1.85

0.05d = 1.25

Thus carter has 25 dimes

By setting up and solving a system of equations, we find that Carter has 25 dimes in his piggy bank.

To solve how many dimes Carter has, we need to set up two equations based on the given information.

Carter has 25 dimes in his piggy bank.

Answer:

Step-by-step explanation:

Wholesaler A is selling 10 pounds of chicken for $40.00. This means that the unit rate at which Wholesaler A is selling the chicken is

40/10 = $4 per pound of chicken.

Wholesaler B is selling 15 pounds of chicken for $45.00. This means that the unit rate at which Wholesaler B is selling the chicken is

45/15 = $3 per pound of chicken.

Wholesaler C is selling 20 pounds of chicken for $50.00. This means that the unit rate at which Wholesaler C is selling the chicken is

50/20 = $2.5 per pound of chicken.

Wholesaler C has the best price because she has the lowest unit rate pound of chicken.

Answer:  The required length of the diameter of the circumscribed circle is 24 units.

Step-by-step explanation:  Given that one side of a triangle has length 12 units and its opposite angle measures 30 degrees.

We are to find the diameter of the circumscribed circle.

We know that

if a, b, c are the lengths of the three sides of a triangle and A, B, C are the corresponding measures of the opposite angles respectively, then the ratio

[tex]\dfrac{a}{\sin A}=\dfrac{b}{\sin B}=\dfrac{c}{\sin C}=d,[/tex]

is said to the length of the diameter of the circumscribed circle of the triangle.

According to the given information, we have

a = 12  and  A = 30°.

Therefore, the length of the diameter of the circumscribed circle is

[tex]d=\dfrac{a}{\sin A}=\dfrac{12}{\sin 30^\circ}=\dfrac{12}{\frac{1}{2}}=24.[/tex]

Thus, the required length of the diameter of the circumscribed circle is 24 units.

Given the details of a triangle with  one of its sides as 12 and opposite angle as 30 degrees, the diameter of the circumscribed circle is twice the length of thegiven side. Since the hypotenuse of the triangle is the diameter of a circumscribed circle, the diameter in this case is 24.

The subject of this question is pertaining to geometry, specifically, the relationship between sides and angles in triangles, and circles. In particular, we are dealing with a situation where we have a triangle inscribed in a circle (a triangle with a circumscribed circle), and we are asked to find the diameter of the said circle.

Now, from trigonometry, we know that the sine of any angle in a right triangle is defined as the length of the opposite side divided by the length of the hypotenuse. In this case, you're given that one side of the triangle (which we'll assume is the opposite side) is 12, and its opposite angle is 30 degrees. Since the sine of 30 degrees is 0.5, this means that the hypotenuse of this triangle is actually twice the length of the given side. Thus, the hypotenuse is 2 * 12 = 24.

This is significant because, in any triangle inscribed in a circle, the diameter of the circle is equal to the length of the hypotenuse. Therefore, in this case, the diameter of the circle would be 24.

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Final answer:

The standard deviation for the given data is approximately 4.47.

Explanation:

The standard deviation is a measure of how spread out the data is from the mean. To calculate the standard deviation, we follow a formula that involves finding the difference between each data point and the mean, squaring those differences, and taking the average of the squared differences. Finally, we take the square root of the average to get the standard deviation.

For the given data, which is 13, 17, 9, and 21, we first find the mean (average) which is (13 + 17 + 9 + 21) / 4 = 60 / 4 = 15. Next, we calculate the squared differences from the mean for each data point:
(13 - 15)^2 = 4
(17 - 15)^2 = 4
(9 - 15)^2 = 36
(21 - 15)^2 = 36

Then, we find the average of the squared differences:
(4 + 4 + 36 + 36) / 4 = 80 / 4 = 20

Finally, we take the square root of the average:
sqrt(20) ≈ 4.47

So, the standard deviation for the given data is approximately 4.47.

Answer:

[tex]\displaystyle y=-2sin(6t)[/tex]

Step-by-step explanation:

Sinusoid

The shape of a sinusoid is well-know because it describes a curve with a smooth and periodic oscillation. The sine and cosine are the two trigonometric functions in which the graph matches the description of a sinusoid. The sine can be identified because its value is zero at time zero.

The graph shown in the figure corresponds to a sine. The other characteristics of the sine function are

* It completes a cycle in[tex]2\pi[/tex] radians

* It has a maximum of 1 and a minimum of -1

* It's increasing for a quarter of the cycle, decreasing for half of the cycle, and increasing for the remaining quarter of the cycle

* The equation is

[tex]y=Asin(wt)[/tex]

The function starts decreasing for the first quarter, which only is possible if the amplitude A is negative. We can also see the maximum and minimum values are 2 and -2 respectively. This means the amplitude is A=-2

We can also see the function completes 3 cycles in [tex]t=\pi[/tex] radians or 6 cycles in [tex]2\pi[/tex] radians. Or, equivalently

[tex]wt=12\pi[/tex]

[tex]w(2\pi)=12\pi[/tex]

[tex]\displaystyle w=\frac{12}{2}=6\ rad/sec[/tex]

Thus, the function can be expressed as

[tex]\boxed{\displaystyle y=-2sin(6t)}[/tex]

Answer:

y=-2sin6x

Step-by-step explanation:

The solution to the compound inequality is 20 < x < 50. Malcolm should consume more than 20 but less than 50 grams of carbohydrates to adhere to his low-carbohydrate diet.

To solve the compound inequality 50 < 2x + 10 and 2x + 10 < 110 for Malcolm's diet, we'll deal with each part of the inequality separately and then combine the results to find the range of values for x that satisfies both conditions.

Combining these inequalities gives us 20 < x < 50. This means that Malcolm should consume more than 20 but less than 50 grams of carbohydrates to stay within his targeted dietary range on his low-carbohydrate diet.

The helicopter uses 11 gallons of fuel per hour, so for 4 hours, it would use 44 gallons of fuel.

The question provides that the number of gallons of fuel used by a helicopter is directly proportional to the number of hours it spends flying. This is a proportionality problem, which can be solved using basic algebraic principles.

Firstly, we know from the question that the helicopter uses 33 gallons of fuel for 3 hours of flight. So, the proportionality constant, or the rate of fuel consumption, is 33 gallons/3 hours = 11 gallons/hour.

To find out how many gallons of fuel the helicopter would consume in 4 hours, we simply multiply the rate of fuel consumption by 4:

11 gallons/hour x 4 hours = 44 gallons.

Therefore, the helicopter would use 44 gallons of fuel to fly for 4 hours.

https://brainly.com/question/32437705

Answer: the amount invested on the first mutual fund is $600 and the the amount invested on the second mutual fund is $1700

Step-by-step explanation:

Let x represent the amount of money that the investor invested in one mutual fund.

Let y represent the amount of money that the investor invested in the second mutual fund.

An investor invested a total of $2,300 in two mutual funds. This means that

x + y = 2300

Considering the first mutual fund, it earned a 8% profit. This means that amount earned is

8/100 × x = 0.08x

Considering the second mutual fund, it earned a 2% profit. This means that amount earned is

2/100 × y = 0.02y

If the investors total profit was $82, it means that

0.08x + 0.02y = 82 - - - - - - - - 1

Substituting x = 2300 - y into equation 1, it becomes

0.08(2300 - y) + 0.02y = 82

184 - 0.08y + 0.02y = 82

- 0.08y + 0.02y = 82 - 184

- 0.06y = - 102

y = - 102/- 0.06 = 1700

x = 2300 - y = 2300 - 1700

x = 600

Answer:

The required function is F(x) = tanx - 2.

Step-by-step explanation:

We all know the graph of tanx ,

The graph of tanx passes through the origin and repeats in the interval of π.

Now , after looking into the graph we can clearly say that it is the shifted graph of tanx , Which is shifted in the -y direction .

Thus ,

It is clear that F(x) must be like F(x) = tanx - c , where c is a positive constant .

Also, At x = 0 , Value of the function is coming out to be -2 ,

Putting x = 0 in F(x) = tanx - c , we get , F(x) = -c .

Thus c = 2.

So, the required function is F(x) = tanx - 2.