Answer:
An atom’s emission of light with a specific amount of energy confirms that electrons emit and absorb energy based on their position around the nucleus. The light emitted from an electron is a result of the electron's quantum jumps/leaps ( atomic electron transitions ) to and from different energy levels.
please help !!
Why are high and low tides heights not very different throughout the whole month? give a brief description, thanks
Answer:
Just as the angles of the sun, moon and Earth affect tidal heights over the course of a lunar month, so do their distances to one another. Because the moon follows an elliptical path around the Earth, the distance between them varies by about 31,000 miles over the course of a month.
Hope this helped, have a nice rest of your day!
Are quarks and or gluons smaller than photons.
Answer:
V
Explanation:
Photons can be any size that I’d greater than around 6 Planck Lengths. So, technically they take the prize on both ends. We can see since the Higgs has the highest Energy. Therefore it will be smaller than most quarks except the top quark
A 10.0-cm-long wire is pulled along a U-shaped conducting rail in a perpendicular magnetic field. The total resistance of the wire and rail is 0.300 Ω . Pulling the wire at a steady speed of 4.00 m/s causes 3.90 W of power to be dissipated in the circuit.
Question:
What are the magnitudes of the pulling force and the magnetic field
Answer:
The magnetic field strength is 2.7 T
The pulling force [tex]F_p[/tex] is 0.975 N
Explanation:
Here we have;
Length of wire, l = 10.0 cm = 0.1 m
Resistance of wire, R = 0.300 Ω
Speed of wire, v = 4.00 m/s
Power dissipated = 3.90 W
Based on the given data, we apply the relation;
[tex]I =\frac{Blv}{R}[/tex]..............(1)
Where:
B = Magnetic field strength
I = Current
Since P = I²R, we have;
3.9 = I²·0.300Ω
∴ I² = 3.9/0.300 = 13
From which I = √13
Substituting the value of I in equation (1) above, we have;
[tex]\sqrt{13}= \frac{B \times 10.0 \times 4.00}{0.300}[/tex]
Therefore;
[tex]B = \frac{\sqrt{13} \times 0.300}{0.1 \times 4.00} = 2.70416 \ T\approx 2.7 \ T[/tex]
The magnitude of the pulling force is given by the following relation;
[tex]F_p = F_m = IlB = l\sqrt{\frac{P}{R} } \frac{\sqrt{PR} }{lv} =\frac{P}{v} = \frac{3.9 \ W}{4.00 \ m/s} = 0.975 \ N[/tex]
The pulling force [tex]F_p[/tex] = 0.975 N.
What is the main difference between the Schrödinger model and the Bohr atomic model?
A) Schrödinger believed that electrons could only exist in orbits, but Bohr stated that electrons could be found anywhere in the atom.
B) Bohr believed electron orbits were circular, but Schrödinger’s equations represent complex shapes describing the probable locations of electrons.
C) The Bohr model did not explain the emission and absorption spectrum, but the energy levels described by Schrödinger explained this property.
D) Bohr believed that the electrons circle the nucleus because positive particles attract negative particles, while Schrödinger believed that an electron was a wave.
Answer:
the answer is B :Bohr believed electron orbits were circular, but Schrödinger’s equations represent complex shapes describing the probable locations of electrons.
Explanation:
just took the test on edge
The main differences between the Schrödinger and Bohr atomic models are the representation of electron orbits and the explanation of the emission and absorption spectrum.
Explanation:
The main difference between the Schrödinger model and the Bohr atomic model is that Bohr believed electron orbits were circular, while Schrödinger's equations describe complex shapes representing the probable locations of electrons. This means that according to Bohr, electrons could only exist in specific orbits, while Schrödinger's model allows for electrons to be found in a range of locations within an atom.
Another difference is that the Bohr model did not explain the emission and absorption spectrum, whereas the energy levels described by Schrödinger's model successfully explained this property.
Lastly, Bohr believed that electrons circled the nucleus due to the attraction between positive and negative charges, while Schrödinger believed that electrons have wave-like properties.
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Stacy begins by hanging metal washers from a force meter. Then she measures the downward pull on the washers. What
force causes this downward pull?
The Answer is:
Weight
(hope that helped)
Answer:
Earth’s gravity causes the downward pull on the washers.
Explanation:
This is the sample answer on Edmentum. :)
A student is asked to design a cart that will have the smallest force of impact when it collides with another object. Which of these would be the best design
Answer:D
Explanation:
Because I got it wrong
According to the concept of length contraction, what happens to the length of an object as it approaches the speed of light and then slows down, eventually coming to a stop?
Answer:
It contracts and returns to its original length when it stops.
Explanation:
As it approaches the speed of light, the length of the object is observed to contract. Then as it comes to a stop, it returns back to its original length.
A sound wave with a frequency of 510 Hz and a wavelength of 3.5 m is directed toward the bottom of a lake to measure its depth. If the echo of the sound from the bottom is heard 0.39 seconds later, how deep is the lake?
Answer:
Approximately [tex]2.9 \times 10^2 \; \rm m[/tex].
Explanation:
In that [tex]0.39\; \rm s[/tex], this sound wave travelled from the surface of the lake to the bottom, got reflected, and travelled back from the bottom to the surface. The sound wave travelled from the surface to the bottom (without bouncing back) in only [tex]1/2[/tex] that much time. In other words, it took only [tex]\displaystyle ((1/2) \times 0.39)\; \rm s[/tex] for the sound wave to travel from the surface to the bottom of the lake.
The speed [tex]v[/tex] of sound in cold water ([tex]20\; \rm ^\circ C[/tex], [tex]1\; \rm atm[/tex]) is approximately [tex]1.482\times 10^{3} \; \rm m \cdot s^{-1}[/tex].
In [tex]t = ((1/2) \times 0.39) \; \rm s[/tex], that sound wave would have travelled a distance of:
[tex]\begin{aligned}s &= v \cdot t \\ &= 1.482 \times 10^3 \; \rm m \cdot s^{-1} \times \left(\frac{1}{2} \times 0.39 \; \rm s\right) \\ &\approx 2.9 \times 10^2\; \rm m \end{aligned}[/tex].
Therefore, the depth of the lake is approximately [tex]2.9 \times 10^2 \; \rm m[/tex].
Length is fundamental quantity whereas area is derived quantity. Justify
Answer:
A fundamental quantity is something that can only be found by measuring, such as measuring the length of a pencil. We have no other way to find out the length of the pencil other than measuring it in some way.
A derived quantity is something that is calculated and that is not measured directly. Area is found by multiplying two lengths together. We cant find the area other than computing it somehow
helppppp!!!!
In this experiment, you will use a track, a toy car, and some washers to explore Newton’s first two laws of motion. You will make observations and collect data regarding the motion of these objects. In the space below, write a general scientific question that you will answer by doing this experiment.
Answer:
What speed is the car traveling at the longest distance and the shortest distance, and how do they compare?"
"Does the car move faster or slower for longer distances?
Explanation:
Hope it helps! :)
The experiment aims to examine how the force exerted on the cart does work as the cart moves through a distance by using various materials and equipment.
Explanation:The general scientific question that can be answered by conducting this experiment is: How does the force exerted on the cart do work as the cart moves through a distance?
In this experiment, you can examine the relationship between force, work, and distance by using a cart track, two carts, several masses, a position-sensing pulley, and a rough surface. By varying the force exerted on the cart and measuring the work done as the cart moves through a distance, you can analyze how force affects the work done on the cart.
An example of how to design this experiment would involve measuring the force using the masses and the position-sensing pulley. By increasing the mass and measuring the displacement of the cart, you can determine how the force applied affects the work done.
The function s(t) = vt + h – 0.5at2 represents the height of an object, s, in feet, above the ground in relation to the time, t, in seconds, since the object was thrown into the air with an initial velocity of v feet per second at an initial height of h feet and where a is the acceleration due to gravity (32 feet per second squared). A baseball player hits a baseball 5 feet above the ground with an initial velocity of 70 feet per second. About how long will it take the baseball to hit the ground? A) 2 seconds B) 3 seconds C) 4 seconds D) 5 seconds
Answer:
C) 4 seconds
Explanation:
The height of an object is given by the following formula:
[tex]s(t)=h+vt-0.5at^2\\\\a=32ft/s[/tex]
To find the flight time you equal the height s to zero:
[tex]0=5ft+70\frac{ft}{s}\ t-0.5(32\frac{ft}{s^2})t^2\\\\0=5ft+70\frac{ft}{s}\ t-16\frac{ft}{s^2}t^2[/tex]
Then, you have a quadratic equation of the form:
[tex]ax^2+bx+c[/tex]
you use the quadratic formula in order to find the roots of the polynomial:
[tex]t_{1,2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\a=-16\\\\b=70\\\\c=5\\\\t_{1,2}=\frac{-70\pm \sqrt{(70)^2-4(-16)(5)}}{2(-16)}\\\\t_{1,2}=\frac{-70\pm 72.24}{-32}\\\\t_1=4.44s\approx4s\\\\t_2=-007s[/tex]
you take the positive value of t because this has physical meaning.
Hence:
the time is C) 4 seconds
From the data provided, the time taken for the baseball to hit the ground is 4.0 seconds
What is the time taken for the baseball to hit the ground?The function: s(t) = vt + h – 0.5at^2 represents the height of an object
From the data provided:
v = 70 ft/sfinal height above ground, s = 0h = 5 fta = 32 ft/s^2t = ?Substituting the values:
0 = 70t + 5 - 0.5(32)t^2
16t^2 -+ 70t - 5 = 0
solving quadratically:
[tex]t = \frac{ - b \sqrt{b {}^{2} - 4ac} }{2a} [/tex]
[tex]t = \frac{ - 70 \sqrt{ {70}^{2} - 4 \times ( - 16) \times 5} }{2 \times ( - 16)} [/tex]
t = 4.4 s or - 0.07
taking only positive values for t, t= 4 seconds
Therefore, the time taken for the baseball to hit the ground is 4.0 seconds.
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A test model for a new experimental gasoline engine does 45 J of work in one cycle for every 76 J of heat it takes in. What is the engines efficiency?
Answer:
The efficiency of the engine is 59.2%.
Explanation:
We have,
Work done by the gasoline engine is 45 J and the for every 76 J of heat it takes in.
It is required to find the efficiency of the engine. Efficiency of the engine is given by the ratio of work done to the heat taken i. Its formula is given by :
[tex]\eta=\dfrac{W}{Q}\\\\\eta=\dfrac{45}{76}\\\\\eta=0.592\\\\\eta=59.2\%[/tex]
So, the efficiency of the engine is 59.2%.
Final answer:
The efficiency of the engine is approximately 59.21%, calculated by dividing the work done by the engine (45 J) by the heat input (76 J) and then multiplying by 100.
Explanation:
The efficiency of a heat engine is the ratio of work output to heat input, expressed as a percentage. To calculate the engine's efficiency, you divide the work done by the engine by the heat energy that was put into the engine, and then multiply by 100 to convert the decimal to a percentage. In the given problem, the engine does 45 J of work and takes in 76 J of heat, which means the efficiency (η) is calculated as:
η = (Work done / Heat input) × 100
η = (45 J / 76 J) × 100
η = (0.59210526315...) × 100 ≈ 59.21%
The engine's efficiency is therefore approximately 59.21%.
Two concave mirrors are kept in a straight line as shown in fig. Mirror A forms 2 times enlarged real image of an object kept in front of it on the same straight line. The focal length of mirror A is given as 10cm.
i. Using sign conventions calculate the object position and image position in the case of mirror A
ii. Mirror B forms a 1/4times diminished real image of the same object. Find the object position, image position and the focal length in this
case.
iii. Draw the ray diagrams in both the cases.
3
Answer:
For mirror A:
Object distance from mirror is 15 cm
Image distance from mirror is 30 cm
For mirror B;
Object distance = 15 cm
Image distance = 3.75 cm
Focal lenght = 3 cm
Explanation:
Detailed explanation and calculation is shown in the images below.
The area around a charged object that can exert a force on other charged objects is a(n) _________. electric field field line conductor electric potential energy
Answer:
A is the correct answer
Electric field
What is electric field?Electric field is a electric force per unit charge.
The electric field is radially in toward a negative point charge and radially outward from a positive charge.
The direction of the field is in the direction of the force it exert on a positive test charge.
The formula of electric field is given as.
E = F /Q.
Properties of an Electric Field
Electric Field lines never intersect each other and they are perpendicular to the surface charge.
Electric field is strong when the lines are close together, and it is weak when the field lines move apart from each other.
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which of the following best describes each particle?
A. Protons are negative, neutrons are neutral, and electrons are positive.
B. Protons are neutral, neutrons are positive, and electrons are negative.
C. Protons are positive, neutrons are neutral, and electrons are negative.
D. Protons are neutral, neutrons are negative, and electrons are positive.
Answer:
C. Protons are positive, neutrons are neutral, and electrons are negative
The description that correctly labels each particle's charge is option C: Protons are positive, neutrons are neutral, and electrons are negative. These particles compose the anatomy of an atom.
Explanation:The question asks for the correct assignment of charges to particles that make up atoms. The best description for each particle is given by option C. Here, protons are correctly labeled as positive, neutrons as neutral, and electrons as negative. In an atom, protons and neutrons reside in the nucleus (the center), while electrons occupy space around the nucleus, in what's known as electron clouds or shells.
Understanding the correct assignment of charges to atomic particles is fundamental in grasping the structure of atoms. Protons, carrying a positive charge, and neutrons, which are neutral, are concentrated in the nucleus, forming the central core. Meanwhile, electrons, negatively charged, orbit the nucleus in electron clouds or shells, contributing to the overall electrical balance of the atom.
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A5 cm object is 18.0 cm from a convex lens, which has a focal length of 10.0 cm.
What is the distance of the image from the lens? Round your answer to three significant figures.
cm
What is the height of the image? Round your answer to three significant figures.
cm
Intro
Answer:
answer in picture
Explanation:
If the potential difference across the bulb in a certain flashlight is 3.0 V, What is the potential difference across the combination of batteries used to power it?
Answer:
3.0 V
Explanation:
The voltage across the bulb is the voltage across the batteries, since the batteries are the only source of power for the bulb. So the voltage across the batteries is 3.0 V.
The potential difference should be 3.0 V.
Calculation of the potential difference:In the case when the potential difference for the flashlight is 3.0V so here the batters should be considered as the only source with respect to the power for the bulb. Due to this, the potential difference across the batteries combination that used to power should also be 3.0 V.
Therefore, The potential difference should be 3.0 V.
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Cleo stated that light travels through air in straight paths, and when it moves from air to water, light changes direction, speeds up, and bends toward the normal.
Which statement best describes Cleo’s mistake?
Light travels through air and water in angled, scattered paths.
Light does not change direction when it moves from air into water.
Light slows down when it moves from air into water.
Light bends away from the normal when it moves from air into water.
Answer:
Light slows down when it moves from air into water.
Explanation:
It is the property of light that travels faster in a less dense medium.
In a more dense medium, the speed of the light slows down and bends towards the normal.
The air is less dense medium and water is a more dense medium.
When light passes from air to water, the light bends.
This is known as the refraction of light.
Answer:
C is the correct answer on Ed gen uity
Care din propozitiile de mai jos sunt propozitii simple si care sunt propozitii dezvoltate? Argumentati oral raspunsurile a) mâța a mâzgălit mâsuța. B) va găti bunica c) pisica toarce d) voi nu iubiți pisicile? E) dintr-o săritură, mâța va fi la geam f) noi nu ajungeam la timp niciodată
Answer:
a) developed
b) simple
c) simple
d) developed
e) developed
f) developed
Question:
Which of the following sentences are simple sentences and which are developed sentences? Orally argue the answers
a) the cat scribbled the little girl.
b) Grandma will cook
c) The cat will spin
d) You don't love cats?
e) in one jump, the cat will be at the window
f) we will never arrived on time
Explanation:
To differentiate the simple sentences from the developed sentences, let's understand what they are.
A Simple sentence is a sentence that contain a subject and a predicate. The sentence is complete in thought.
A developed sentence is a sentence that contain a subject, predicate as well as other parts of sentence.
a) the cat scribbled the little girl (developed)
b) Grandma will cook (simple)
c) The cat will spin (simple)
d) You don't love cats? (developed)
e) in one jump, the cat will be at the window (developed)
f) we will never arrived on time (developed)
Hence option b and c are simple sentences, while options a, d, e and f are developed.
If a force of 3000 N is applied to a large rock, but the rock does not move, how much work is done on the rock?
Answer:
No work was done.
W = 0
Explanation:
Work is said to be done whenever a force of one newton moves a body of one kilogram through a distance of one meter. Meaning the applied force has to move the body from a point of rest through certain distance.
Work = force × distance
So, in the case of this question, we only have the force been applied, but no distance was covered. Hence, no work was done.
W = 3000× 0 meter
W = 0
A wire on the left with 9 coils and labeled primary winding. Another coil is near it with 3 coils labeled secondary winding V subscript 2 baseline equals 120. Use the values provided to calculate the initial voltage at the primary winding.
V1 = ? V
Answer:
V1 = 360 V
Explanation:
Applying,
Vs/Vp = Ns/Np................ Equation 1.
Vs = Voltage of the secondary coil, Vp = voltage of the primary coil, Ns = number of coils in the secondary winding, Np = number of coils in the primary winding
make Vp the subject of the equation
Vp = VsNp/Ns............ Equation 2
Given: Vs = 120 V, Np = 9 coils, Ns = 3 coils
Substitute into equation 2
Vp = 120(9)/3
Vp = 360 V.
Hence, V1 = 360 V
Answer:
V1 = 360 V
Explanation:
hope i helped
What kind of magnets are shown in the figure above?
Answer:
Electromagnets.
Explanation:
They acquire their magnetism by flow of current and electromagnetic induction
The kind of magnet that should be shown in the figure is electromagnet.
What is an electromagnet?An electromagnet refer to the type of magnet where the magnetic field is generated via an electric current. It comprise of wire wound into a coil. A current via the wire develops a magnetic field i.e. concentrated in the hole, represents the center of the coil. Also, it acquire their magnetism with the help of flow of current and electromagnetic induction.
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Which best describes the energy of a sound wave as it travels through a medium
a. it remains the same
b. It increases.
c. It depends on the medium
d. it decreases
The energy of a sound wave as it travels through a medium decreases
What is energy of a sound wave ?It is the physical vibration waves that travel through the air to reach the ears . Sound energy is the result when force makes an object vibrate.
A wave can lose energy as it travel through a medium because medium can also absorb the energy . The medium changes some of the acoustic energy of the sound wave into heat .
correct option is d) it decreases
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The energy of a sound wave decreases as it propagates through a medium due to damping, which lessens the amplitude of the wave. The decrease happens because the energy is dispersed over a growing area and is absorbed by the medium.
Explanation:The question asks which best describes the energy of a sound wave as it travels through a medium. The correct answer is that the energy of a sound wave decreases as it propagates through a medium. This decrease in energy is due to damping, which is an effect that decreases the amplitude of the wave as it travels. Damping occurs because the energy of the sound wave is spread out over an increasingly larger area and is absorbed by the medium.
Factors Affecting Sound Wave PropagationThe amplitude of a sound wave decreases with distance from its source.When a sound wave enters a medium where its speed increases, the wavelength also increases, but the speed of sound primarily depends on the properties of the medium, not the amplitude or wavelength.The energy of a sound wave is affected by the medium through which it travels, with factors like damping leading to a decrease in energy.A changing current in one loop of wire can induce a current in another loop of wire even though the wires do not touch. The induced current appears almost instantaneously for loops close together. How can this energy exchange happen?
Answer:
It is done via an electromagnetic wave.
Explanation:
A model rocket is fired vertically upward from rest. Its acceleration for the first three seconds is a(t) = 66 t, at which time the fuel is exhausted and it becomes a freely "falling" body. 15 seconds later, the rocket's parachute opens, and the (downward) velocity slows linearly to -23 ft/s in 5 s. The rocket then "floats" to the ground at that rate.
Determine the position function s and the velocity function v (for all times t).
(x=yt-2)^2(56-tea)^2x10r
Using the given information, we determined the position and velocity functions of the model rocket at different time intervals. The velocity function varies during the rocket's upward acceleration, free fall, and the subsequent parachute slowing. The position function gives the height of the rocket at any time.
Explanation:To determine the position function s(t) and the velocity function v(t), we need to analyze the rocket's motion in different time intervals:
From time t = 0 to t = 3 seconds: The acceleration is given by a(t) = 66t. To find the velocity function, we integrate the acceleration function, v(t) = ∫ 66t dt = 33t2 + C1, where C1 is a constant of integration. We can determine C1 by using the initial condition of the rocket being at rest at t = 0 (initial velocity is 0), which gives us C1 = 0. So, v(t) = 33t2.From time t = 3 to t = 18 seconds: The rocket becomes a freely falling body. This means it is subject to a constant acceleration due to gravity, a(t) = -32 ft/s2. The velocity function can be found by integrating the acceleration, resulting in v(t) = -32t + C2. To determine C2, we use the fact that at t = 3 seconds, the velocity is 0 (since the fuel is exhausted). Plugging in these values, we find C2 = 96. Thus, v(t) = -32t + 96.From time t = 18 to t = 23 seconds: The velocity decreases linearly from -23 ft/s to 0 ft/s in 5 seconds. This means the acceleration is given by a(t) = (-23 - 0) / 5 = -4.6 ft/s2. Integrating the acceleration function, we get v(t) = -4.6t + C3. Using the fact that at t = 23 seconds the velocity is 0, we find C3 = 105.8. Thus, v(t) = -4.6t + 105.8.To find the position function s(t), we integrate the velocity function for each time interval:
From time t = 0 to t = 3 seconds: s(t) = ∫ (33t2) dt = 11t3 + C4. Using the initial condition s(0) = 0, we find C4 = 0. Therefore, s(t) = 11t3.From time t = 3 to t = 18 seconds: s(t) = ∫ (-32t + 96) dt = -16t2 + 96t + C5. Since the rocket is at rest at t = 3 seconds, we have the condition s(3) = 0, which gives us C5 = 1176. Hence, s(t) = -16t2 + 96t + 1176.From time t = 18 to t = 23 seconds: s(t) = ∫ (-4.6t + 105.8) dt = -2.3t2 + 105.8t + C6. Since the rocket starts floating to the ground at t = 18 seconds, we have the condition s(18) = 0, giving us C6 = -685. Thus, s(t) = -2.3t2 + 105.8t - 685.The position function s(t) represents the height of the rocket at any time t, while the velocity function v(t) represents the rate at which the height is changing with respect to time.
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Marcus tries to move a refrigerator but can't. Has he done work?
Yes, because he used energy.
No, because he did not move the object.
Yes, because he exerted a force.
No, because he did not use energy.
The de Broglie wavelength of an electron in a hydrogen atom is 1.66 nm.Identify the integer n that corresponds to its orbit.
Answer:
[tex]n=5[/tex]
Explanation:
The De Broglie equation is given by:
[tex]\lambda=\frac{h}{mv}[/tex]
Where:
h is the Plank constant [tex]h=6.626*10^{-34}J[/tex]m is the electron mass [tex]m_{e}=9.1*10^{-31}kg[/tex]v is the speed of the electronThen:
[tex]v=\frac{h}{m\lambda}[/tex] (1)
The energy equation of a hydrogen electron in a orbit n is:
[tex]E=-\frac{R_{H}}{n^{2}}[/tex] (2)
R(H) is the Rydberg constant [tex]R_{H}=2.18*10^{-18}J[/tex]n is an integer that corresponds to electron orbit.We can write E as a kinetic energy an use v of the equation (1)
[tex]\frac{1}{2}mv^{2}=\frac{R_{H}}{n^{2}}[/tex]
[tex]n^{2}=\frac{2R_{H}}{mv^{2}}[/tex]
[tex]n=\frac{m\lambda}{h}\sqrt{\frac{2R_{H}}{m}}[/tex]
[tex]n=\frac{9.1*10^{-31}*1.66*10^{-9}}{6.626*10^{-34}}\sqrt{\frac{2*2.18*10^{-18}}{9.1*10^{-31}}}[/tex]
[tex]n=5[/tex]
I hope it helps you!
Given an electron in a hydrogen atom with a de Broglie wavelength of 1.66 nm, the quantum number or integer n that corresponds to its orbit is likely 1, suggesting the electron is in the ground state orbit of the atom.
Explanation:Given the de Broglie wavelength (λ) of an electron in a hydrogen atom is 1.66 nm, we're to identify the integer n or quantum number that corresponds to its orbit. Specifically in the model of the atom proposed by Bohr and later modified by de Broglie, the electron orbits the nucleus in quantized orbits. These quantized orbits correspond to the de Broglie 'standing wave' concept where an integer number of wavelengths must fit exactly within the orbit.
To determine the quantum number n for the electron's orbit, we need to apply the formula for the de Broglie wavelength in a Bohr orbit: λ = 2πrn/n, where rn is the radius of the nth orbit. The radius of the nth orbit in a hydrogen atom is given by the formula rn = 0.529 * n² nm. Solving for n, we find n equals to approximately 1. This means the electron is likely in the ground state orbit of the hydrogen atom.
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I need help with my physics. It’s on waves :(
Answer:
E is the Crest.
An areoplane initially at rest, undergoes a constant acceleration on of 2.5m/second down the runway for 30sec before taking off
Answer:
I'll just assume that the question is what's the velocity of the airplane before it takes off because you haven't included a question. Where u: velocity, a: acceleration, t: time
[tex]u = a \times t \\ u = 2.5 \times 30 \\ u = 70ms[/tex]
Multiple choice
Which of the following is NOT found in the Milky Way galaxy’s galactic halo?
A. A few lone stars
B. Dark matter
C. Some star clusters
D. The sun
Which of the following is the correct order of the components of the Milky Way galaxy from outermost to innermost
A. Thick Disc, thin disc, extreme disc, galactic halo, black hole
B. Thing disc, extreme disc, thick disc, galactic halo back hole
C. Galactic halo, thick disc, thing disc, extreme disc, black hole
D. Extreme disc, thick disc, thin disc, galactic halo, black hole
Answer:
The correct options are;
D. The Sun
C. Galactic halo, thick disc, thin disc, extreme disc, black hole
Explanation:
1) The Milky Way galaxy consists of a disk, a central bulge and a halo , with the most prominent and visible part of the Milky Way galaxy being the disk
The Sun can be found in the thin disk and not in the Milky Way's galactic halo
2) The structure of the Milky Way galaxy consists of
(1) Galactic halo (2) Spherical component (3) Spiral arms (4) Thick and thin disk (5) Central bulge (extreme disc) (6) Nucleus with black hole
Therefore, the correct order of the components of the Milky Way galaxy from outermost to innermost is as follows
Galactic halo, thick disc, thin disc, extreme disc, black hole.
The Sun is not found in the Milky Way galaxy's galactic halo. The order of components of the Milky Way galaxy from outermost to innermost is: Galactic halo, thick disc, thin disc, extreme disc, black hole.
Explanation:The Milky Way galaxy's galactic halo is a spherical region encompassing the main, disc-shaped structure of the galaxy. It encompasses a few lone stars (Option A), dark matter (Option B), and some star clusters (Option C). However, the Sun (Option D) is not located in the galactic halo; instead, it's positioned within one of the spiral arms of the galaxy's disc. So, the answer is the Sun (Option D) is NOT found in the Milky Way galaxy’s galactic halo.
As for the order of components of the Milky Way galaxy from outermost to innermost: it starts with the galactic halo, followed by the thick disc, thin disc, extreme disc, and finally, at the center, we have the supermassive black hole. Therefore, the correct order is presented in Option C: Galactic halo, thick disc, thin disc, extreme disc, black hole.
Learn more about Milky Way Galaxy here:https://brainly.com/question/17606059
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