Reduce to simplest form.
-5/9+ (-7/12)

Answer:

29.25

Step-by-step explanation:

you need to take 35 and turn it into a decimal making it .35 then multiply 45 by .35 and you get 15.75 then subtract that from 45

Answer:

5 eggs.

Step-by-step explanation:

Well, 3/4 of 12 is 9 and 5/6 of 12 is 10. So, 12 - 9 = 3 and 12 - 10 = 2

Therefore, Matthew has 5 eggs left over.

I hope I helped ^^

Answer:

5/12​ dozen eggs

Step-by-step explanation:

confirmed!

Answer:

B. The manager estimate is reasonable. They ordered about 150 picks and sold about 200 picks, so they should have about 50 fewer than they started with.

Step-by-step explanation:

Given:-

Previous guitar In-stock before ordering and selling(P) = 500 picks. -----(equation 1)

Now, ordered guitar is 15 boxes of 9 picks each.

Ordered guitar=15 [tex]\times[/tex] 9

Hence, Ordered guitar(O)=135 picks ------------(equation 2)

Now, selled guitar is 19 boxes of 10 picks each.

So, Selled guitar = 19[tex]\times[/tex] 10

Hence, Selled guitar(S) =190 picks   ------------(equation 3)

Now to calculate current in-stock of guitar we can write as,

Current guitar in-stock(C) =  Previous in-stock(P) + Ordered guitar(O) - Selled guitar(S)

[tex]C=P+O-S[/tex]

[tex]C=500+135-190[/tex]

[tex]C=635-190[/tex]

[tex]C=445[/tex]

[tex]\therefore[/tex] Current guitar in-stock(C) = 445 picks ------(equation 4)

So, difference in-stock (D) = Previous guitar in-stock(P)- Current guitar in stock(C)

[tex]D=P-C[/tex]

[tex]D=500-445[/tex]

[tex]D=55[/tex]

Therefore Difference in Previous and current stock of guitar(D) = 55 = 50 pick approx.

Hence, the manager estimate is reasonable. They ordered about 150 picks and sold about 200 picks, so they should have about 50 fewer than they started with.

Answer:

we have the same test lol dont give me brainlist its just a statment

Step-by-step explanation:

Answer:

5 units

Step-by-step explanation:

ez pz lemon squeezy. hippity hoppity your math is now my property. splish splash your opionion is trash

Answer:

Perimeter of square is [tex]\frac{20}{7} \ units \approx2.86\ units.[/tex]

Step-by-step explanation:

Given:

Perimeter of square = [tex]4x[/tex]

where side length = 'x' units.

We need to find the Perimeter of square with side length[tex]\frac{5}{7}[/tex]

Now We know that;

[tex]x= \frac{5}{7}[/tex]

Substituting the value of x in perimeter of square formula we get;

Perimeter of square = [tex]4\times\frac{5}{7} = \frac{20}{7} \ units \approx2.86\ units.[/tex]

Hence Perimeter of square is [tex]\frac{20}{7} \ units \approx2.86\ units.[/tex]

Answer:

25

Step-by-step explanation:

Given:

32 parks allow camping

43 parks allow playgrounds

10 parks both allow camping and playgrounds

110 total parks

First, we need to add 32, 43, and 10

32 + 43 + 10 = 85

Then, we find the difference of 110 and 85

110 - 85 = 25

Since it isn't a decimal, there is no point in rounding.

Answer:

Exact Form: 5/2

Decimal Form: 2.5

Mixed Number Form: 2 1/2

Step-by-step explanation:

Answer:

5x + 3

Step-by-step explanation:

1) Collect like terms.

(2x − x + 3x + x) + (5 − 2)

2) Simplify

5 x + 3

Answer:

D.) hope this help if i don´t then o well

Step-by-step explanation:

Answer:

i think it's D

Step-by-step explanation:

A relation just represents if the numbers have anything to do with each other. A function is where each number has just one output, which it does in this case since you would say 1 year is however many hours and you wouldn't say the same number of hours for another year gone by.

Answer:

D

Step-by-step explanation:

(7^-2)*(7^6)=7^-2+6

......since the base 7 is the same, when u multiply them, you should add the exponents and keep 7 as it is. That will be 7^4, which in equivalent to ans D(7^2)^2.

Answer:

130%

Good luck!

Answer:

170%

Try it, I tried it, and it worked

-4= Contraction

2.5=Expansion

2/3= Contraction

-3/4= Contraction

Best way to solve this, if the scale factor is less than one, is a contraction. If it is greater than one, than it is an expansion.

The derivative of y=cos(^7)base x is

Dydx = (cos(7x))x⋅(ln(cos(7x))−7x(tan(7x)))

Step-by-step explanation:

step 1 :

y= (cos(7x))x

Take the natural logarithm of either side, bringing the t x down to be the coefficient of the right hand side we get the answer:

step 2 :

⇒ln y = xln (cos (7x))

Differentiate each side with respect to x. The rule of implicit differentiation: ddx (f(y)) = f'(y) ⋅ dydx

step 3 :

∴1y ⋅ dydx  = ddx (x) ⋅ln (cos(7x)) + ddx (ln (cos(7x)))⋅x

Use the chain rule for natural logarithm functions – ddx ( ln (f(x)) )= f'(x)f(x) - we can differentiate the ln (cos (7x))

step 4 :

Ddx (ln (cos(7x))) = −7xsin (7x) cos( 7x 7tan (7x)

Returning to the original equation:

1y ⋅dydx = ln (cos(7x))−7xtan(7x)

Substitute the original y as a function of x value from the start back in.

Dydx = (cos(7x))x⋅(ln(cos(7x))−7x(tan(7x)))

Answer:

The one which has a height of 3 units. H=3

Step-by-step explanation:

Well, the volume of pyramid is equal to the area of base multiply by the height of pyramid and divide by 3. Writing as a formula it can be expressed as V=(A*H)/3 where V is volume of pyramid, A is area of base and H is the height of pyramid. If V=15 cubic units and A=15 square units, H should be equal to 3 (to be cancelled out by 3. Please look at formula above) in order to make V=15.

Answer:

b

Step-by-step explanation:

Answer:

4k-6

Step-by-step explanation:

[tex]3k+ -9k+ -6+10k=3k-9k-6+10k=4k-6[/tex]

Answer:

4k-6

Step-by-step explanation:

3k+-9k=-6k ; -6k + 10k = 4k ; 4k+ -6 = 4k-6

Answer: h =5

Step-by-step explanation:

3(h+1) = 18

Expand the L.H.S to give

3h + 3 = 18

subtract 3 from both sides

3h = 15

divide through by 3

h = 15/3

h = 5

Step-by-step explanation:

Divide both sides by 3

H+1=6

Move the constant to the right

H=6-1

Subtract the numbers

Note: As you have missed to add the attach drawing. After a little research I found the correct drawing of your question. Hence, I am answering your question based on that drawing I have attached.

Answer:

Barbra cut across the park at an angle x = 51.5° as shown in attached figure. Please check the attached figure as complete solution, along with complete question, is given there.

Step-by-step explanation:

All the angles of a rectangle have same size and measure. So, each of the angles in a rectangle is a right angle. Let suppose a, b, c and d are the angles of a rectangle as shown in attached figure.

All the angles combine to make 360 degree. In other words, ever angle in a rectangle is 90 degree.

Please check the attached figure below as it would visualize and make you understand how the below calculation is done.

As a, b, c and d are the angles of a rectangle. As the length of the rectangle is 370 feet and width of rectangle is 294 feet.

So,

tan (a) = opp / adj

tan (a) = 294 / 370

tan (a) = 0.79459

[tex]a = tan^{-1}(0.79459)[/tex]

a = 38.47 °

As every angle of a rectangle makes 90°.  

so,

       <a + <x = 90°

         <x = 51.50°         ∵ <a = 38.47°

Therefore, angle x = 51.50° is the angle Babra cut across the park.

Keywords: angle,

Learn more about using rectangle measure from brainly.com/question/12135418

#learnwithBrainly    

Answer:

  -0.75

Step-by-step explanation:

The table values listed for the left side expression and the right side expression are closest together when the value of x is -0.75.

__

A graphing calculator shows the expressions both have a value near -0.658 when x ≈ - 0.775. The closest table value to x = -0.775 is x = -0.75.

Answer: x = -0.75

            -0.72   -0.65

Step-by-step explanation:

Consider the equation below.

3^(-x) - 3 = 4^x - 1

consider the values of x  = 1.75, -1.5, -1.25, -1, -0.75,-0.5,-0.25

 x         3^(-x) -3                 4^x - 1

-1.75  3.83                 -0.91

-1.5          2.19                -0.88

-1.25         0.95                    -0.82

-1          0                      -0.75

-0.75 -0.72                     -0.65

-0.5          -1.27                     -0.50

-0.25 -1.68                     -0.29

The bold values when x = -0.75 gives -0.72 and -0.65 is the approximate solution to the equation

by approximation -0.72 when rounded off = -0.7

and -0.65 when rounded off = -0.7

Answer:

nearest percent is about 56%

Answer:

56

Step-by-step explanation:

Answer:

Step-by-step explanation:

Given, ∠1≅∠2, ∠3≅∠4 and AP≅DP,

        ∠1≅∠2(given)

     ⇒m∠1=m∠2(definition of congruent angles)

         180°=180°(Reflexive)

      ⇒m∠[tex]ABP+[/tex]m∠1=m∠[tex]DCP[/tex]+m∠2

          But  m∠1 =m∠2 (definition of congruent angles)

     ⇒m∠[tex]ABP+[/tex]m∠1=m∠[tex]DCP[/tex]+m∠1

        m∠[tex]ABP+[/tex]=m∠[tex]DCP[/tex] ( If equals are subtracted from equals, the remainders are equal)

Therefore, Δ[tex]ABP=[/tex]Δ[tex]DCP[/tex] (by AAS criteria)

condition are:

Answer:

Hence, the price of single ticket is $70.

Step-by-step explanation:

Consider the provided equation.

[tex]P(n) = 70n - 1500[/tex]

As we know that: Profit = Income – Cost

Here, P(n) represents the fundraiser's profit (in dollars) and n represents the number of tickets sold and cost is 1500

Since, n is multiplied by 70 that represents the price of per ticket is $70.

Hence, the price of single ticket is $70.

The expenses of the fundraiser are $40.

Step 1:

To find the expenses of the fundraiser, we can use the given equation:

[tex]\[ P = 70n - 1500 \][/tex]

Here, P represents the profit and n represents the number of tickets sold.

Step 2:

Since profit is the difference between income and expenses, and a negative profit means expenses exceeded income, we can set the profit P to zero and solve for the number of tickets n. Then, we can use the value of n to find the expenses.

When [tex]\( P = 0 \)[/tex]:

[tex]\[ 0 = 70n - 1500 \][/tex]

Solving for n:

[tex]\[ 70n = 1500 \][/tex]

[tex]\[ n = \frac{1500}{70} \][/tex]

[tex]\[ n \approx 21.43 \][/tex]

Since you can't sell a fraction of a ticket, we take the next whole number, which is 22.

Step 3:

Now, we can find the expenses using the value of [tex]\( n \)[/tex]:

[tex]\[ P = 70 \times 22 - 1500 \][/tex]

[tex]\[ P = 1540 - 1500 \][/tex]

[tex]\[ P = 40 \][/tex]

Therefore, the expenses of the fundraiser are $40.

Complete Correct Question:

A charity organisation is having a fundraiser. P represents the fundraiser's profit in dollars if 7 tickets are sold. A negative profit means the expenses exceeded the income from tickets. P=70n-1500 What are the expenses of the fundraiser?

The solution is price of 1 slice of pizza  is $ 1.75 and price of 1 bottle of water is $ 1.25

Solution:

Let "p" be the price of 1 slice of pizza

Let "b" be the price of 1 bottle of water

Given that Abby bought two slices of pizza and  three bottles of water for $7.25

So we can frame a equation as:

two slices of pizza x price of 1 slice of pizza  + three bottles of water x price of 1 bottle of water = $ 7.25

[tex]2 \times p + 3 \times b = 7.25[/tex]

2p + 3b = 7.25 ------- eqn 1

Cameron bought four slices of pizza and  one bottle of water for $8.25

So we can frame a equation as:

four slices of pizza x price of 1 slice of pizza  + one bottles of water x price of 1 bottle of water = $ 8.25

[tex]4 \times p + 1 \times b = 8.25[/tex]

4p + 1b = 8.25 ----- eqn 2

Let us solve eqn 1 and eqn 2 to find values of "p" and "b"

Multiply eqn 1 by 2

4p + 6b = 14.5 ----- eqn 3

Subtract eqn 2 from eqn 3

4p + 6b = 14.5

4p + 1b = 8.25

( - ) ------------------

5b = 6.25

b = 1.25

Substitute b = 1.25 in eqn 1

2p + 3b = 7.25

2p + 3(1.25) = 7.25

2p + 3.75 = 7.25

2p = 3.5

p = 1.75

Summarizing the results:

price of 1 slice of pizza  = $ 1.75

price of 1 bottle of water = $ 1.25

The correct statement must be D) the x-term inside the radical has a negative coefficient, as this would ensure the value inside the square root is nonnegative for the domain x \<= 7.

The statement 'If the domain of the square root function f(x) is x \<=7, which statement must be true?' implies a restriction on the input values (domain) of the square root function. This restriction ensures that the value inside the square root is nonnegative, as the square root of a negative number is not a real number. When looking at the options provided, the correct answer can be deduced.

A) Since the domain is 'x \<=7', it does not necessarily mean that 7 is subtracted from the x-term inside the radical.

B) Multiplying the radical by a negative number isn't related to the domain restriction and would not ensure nonnegative values inside the radical.

C) 7 is added to the radical term does not guarantee nonnegative values either, since if x is negative, adding 7 might not be enough to make the inside of the radical nonnegative. Moreover, the domain 'x \<=7' suggests we are limiting x itself, not the expression inside the radical.

D) The x-term inside the radical having a negative coefficient could ensure that for all x \<= 7, the value inside the square root is nonnegative. This is because as x decreases (to values less than or equal to 7), this operation would actually make the term inside the square root larger (or at least nonnegative).

Therefore, the best choice that must be true is option D) the x-term inside the radical has a negative coefficient.

Final answer:

The statement that must be true for the square root function with domain x \<= 7 is that 7 is subtracted from the x-term inside the radical to ensure all values under the radical are non-negative within the domain.

Explanation:

If the domain of the square root function f(x) is x \<= 7, this refers to the set of all x values that the function can accept without resulting in an undefined or imaginary result. Specifically, the function must avoid producing a negative number under the square root, since the square root of a negative number is not a real number. The correct answer to this question must satisfy the condition that the expression under the square root is greater than or equal to zero for all x in the domain.

The correct statement that must be true is A) 7 is subtracted from the x-term inside the radical. This is because if we consider [tex]\sqrt{x - 7}[/tex], for all values x \<= 7, x - 7 will always be a non-negative number, satisfying the condition. Therefore, the expression under the square root will be zero or positive within the domain, making the square root real and defined.

Answer:

The one in the top left corner and bottom middle

Answer:

The perimeter of △LMN is 8 + [tex]\sqrt{10}[/tex]

Step-by-step explanation:

Step 1: Finding the length of LM

Distance formula  = [tex]\sqrt{(x_2-x_1)^2 +(y_2-y_1)^2}[/tex]

here

[tex]x_1[/tex]= 2

[tex]x_2[/tex]= -2

[tex]y_1[/tex]= 4

[tex]y_2[/tex]=1

LM  = [tex]\sqrt{(-2-2)^2 +(1-4)^2}[/tex]

LM  = [tex]\sqrt{(-4)^2 +(-3)^2}[/tex]

LM  = [tex]\sqrt{16 +9)}[/tex]

LM  = [tex]\sqrt{25}[/tex]

LM  = 5

Step 2: Finding the length of MN

Distance formula  = [tex]\sqrt{(x_2-x_1)^2 +(y_2-y_1)^2}[/tex]

here

[tex]x_1[/tex]= -2

[tex]x_2[/tex]= -1

[tex]y_1[/tex]=   1

[tex]y_2[/tex]= 4

LM  = [tex]\sqrt{(-1-(-2))^2 +(4 - 1)^2}[/tex]

LM  = [tex]\sqrt{(11+2)^2 +(3)^2}[/tex]

LM  = [tex]\sqrt{1 +9)}[/tex]

LM  = [tex]\sqrt{10}[/tex]

Step 3 : Finding the length of NL

Distance formula  = [tex]\sqrt{(x_2-x_1)^2 +(y_2-y_1)^2}[/tex]

here

[tex]x_1[/tex]= -1

[tex]x_2[/tex]= 2

[tex]y_1[/tex]=   4

[tex]y_2[/tex]= 4

NL  = [tex]\sqrt{(2-(-1))^2 +(4 - 4)^2}[/tex]

NL  = [tex]\sqrt{(3)^2 +0}[/tex]

NL  = [tex]\sqrt{9 +0}[/tex]

B  = [tex]\sqrt{9 }[/tex]

NL = 3

Step 4: Finding the perimeter of the triangle

Perimeter =  length of LM +   length of MN +  length of NL

Perimeter = 5 + [tex]\sqrt{10}[/tex] + 3

Perimeter = 8 + [tex]\sqrt{10}[/tex]

Answer:

its D on edg

Step-by-step explanation:

Answer: PART A : [tex]\frac{4.4}{x}[/tex] = [tex]\frac{3}{4}[/tex]

PART B : 5.9 FEET

Step-by-step explanation:

Length of the first sign = 4.4 feet

height of the first sign = 3 feet

Length of the second sign = x feet

height of the second sign = 4 feet

If two shapes are similar , then the ratio of their sides are equal,

That is ;

[tex]\frac{h_{1}}{h_{2} }[/tex] = [tex]\frac{L_{1}}{L_{2} }[/tex]

PART A

[tex]\frac{4.4}{x}[/tex] = [tex]\frac{3}{4}[/tex]

PART B

[tex]\frac{4.4}{x}[/tex] = [tex]\frac{3}{4}[/tex]

cross multiplying , we have

3x = 4.4 x 4

3x = 17.6

Divide through by 3

x = 17.6/3

x = 5.86666666666667

x≈ 5.9 feet

Therefore , the length of the new sign is 5.9 feet

Answer:

see the explanation

Step-by-step explanation:

The correct question is

Prove ∠H≅∠J

we know that

The Angle-Side-Angle postulate (ASA) states that if two angles and the included side of one triangle are congruent to two angles and the included side of another triangle, then the triangles are congruent,

we have

∠HIG≅∠JKI ----> given problem

∠HGI≅∠JIK ----> by corresponding angles (HG and JI are parallel lines)

GI≅IK ----> given problem

so

two angles and the included side of triangle HIG are congruent to two angles and the included side of triangle JKI

therefore

triangle HIG ≅ triangle JKI ---> by ASA postulate

Remember that

If two figures are congruent, then its corresponding sides and corresponding angles are congruent

Hence

∠H≅∠J ----> by definition of congruence (corresponding angles are congruent)

3.1 is already in standard form.

Answer: 30 hours

30*0.4 is 12 or 40 percent of 30 is 12

Hope this helps!

The candle burns 12 inch in 30 hour.

The division in mathematics is one kind of operation. In this process, we split the expressions or numbers into same number of parts.

Given, a candlestick burns at the rate of 0.4 inch per hour.

And 12 inch candle takes time to burn

= division of a 12 with a time taken to burn by ine candle

= 12 / 0.4

= 30 hour

Therefore, the candle burns 12 inch in 30 hour.

To learn more about the division;

https://brainly.com/question/13263114

#SPJ2

Answer:

Step-by-step explanation:

[tex]a-\text{tens digit}\\b-\text{unity digit}\\10a+b-\text{number}\\10b+a-\text{number with reversed digits}\\a+b-\text{sum of digits}\\\\\bold{System\ of\ equations:}\\\\\left\{\begin{array}{ccc}a+b=5\\10b+a=10a+b+27&\text{subtract}\ 10a\ \text{and}\ b\ \text{from both sides}\end{array}\right\\\\\left\{\begin{array}{ccc}a+b=5\\9b-9a=27&\text{divide both sides by 9}\end{array}\right[/tex]

[tex]\underline{+\left\{\begin{array}{ccc}a+b=5\\b-a=3\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad2b=8\qquad\text{divide both sides by 2}\\.\qquad \boxed{b=4}\\\\\text{Put the value of\ b}\ \text{to the first equation}\\\\a+4=5\qquad\text{subtract 4 from both sides}\\\boxed{a=1}[/tex]