calculate each of the following by using scientific notation and product rule. write the answer in scientific notation. 2.3 x 10^4 times 4.2 x 10^6

Answers

Answer 1
remember the associative and commutative properties of multiplcation
ab=ba and (ab)c=a(bc)

also, the exponential rules
[tex](x^m)(x^n)=x^{m+n}[/tex]

also, scientific notation is [tex]a*10^m[/tex] where 1≤x<10 and m is an integer


therefor

[tex](2.3*10^4) \space\ times \space\ (4.2*10^6)=[/tex]
[tex](2.3)(10^4)(4.2)(10^6)=[/tex]
[tex](2.3)(4.2)(10^4)(10^6)=[/tex]
[tex](9.66)(10^{4+6})=[/tex]
[tex]9.66*10^{10}[/tex]

Related Questions

A copy machine makes
105
copies in
3
minutes and
45
seconds. How many copies does it make per minute?

Answers

28 x 3 3/4 = 84 + 21 = 105 copies.

Jordan and Manuel are on the track and field team at school.running around the track one day, Jordan ran 444m and Manuel ran 777 m. They both ran an even number of times around the track. How far is the track

Answers

111 is the answer of m the track is

Answer:

The track is 111 m

Step-by-step explanation:

The easiest way to calculate the meters in the track is to find the Greatest Common Divisor (GCD). This method is used to find the largest number to exactly divide both numbers 444 and 777, which are the meters both guys ran. The resulting number will give us the longest distance the track could have.

   There are various techniques used to find the GCD. One of the is to find all divisors of both numbers and then look for the biggest one they have in common.

   D 444 = { 1, 2, 3, 4, 6, 12, 37, 74, 111, 148, 222, 444 }

   D 777 = { 1, 3, 7, 21, 37, 111, 259, 777 }

   As we can see, the only divisors they have in common are 1, 3 ,37 and 111. The greatest of them is 111 ----> GCD(444,777) = 111.

   This means the track has 111 m.

(Actually, the track could have been as long as any of the other common divisors, but it wouldn't have been realistic for the track to be 1, 3 or 37 meters).

Express 192 as a prime factors in order

Answers

You can write this two ways - as a list of prime factors, or combine like factors and represent their quantity with an exponent.
If you begin by dividing by two, you can do that six times, with a three as the remaining prime factor.
2·2·2·2·2·2·3
OR
2∧6 · 3

Matt plans to put concrete on a rectangular portion of his driveway. The portion is 8 feet long and 4 inches high. The price of concrete is $98 per cubic yard. The total cost of the concrete Matt needs is $58.07. Which of the following is closest to the width of the portion of the driveway on which Matt plans to put concrete?

[1 foot = 12 inches; 1 yard = 3 feet]

0.5 feet
1.5 feet
3 feet
6 feet

any help is appreciated offering 15 points ;)

Answers

Hey! Hope that I can help.

Nine coins are placed in a 3x3 matrix with some face up and some face down. you can represent the state of the coins using a 3x3 matrix with values 0 (heads) and 1 (tails). here are some examples: 0 0 0 1 0 1 1 1 0 0 1 0 0 0 1 1 0 0 0 0 0 1 0 0 0 0 1 each state can also be represented using a binary number. for example, the preceding matrices correspond to the numbers: 000010000 101001100 110100001 there are a total of 512 possibilities, so you can use decimal numbers 0, 1, 2, 3,...,511 to represent all the states of the matrix. write a program that prompts the user to enter a number between 0 and 511 and displays the corresponding matrix with the characters h and t.

Answers

Hello,

Here is the program in QB64

CONST Ordre = 3
DIM SHARED mat(1 TO Ordre, 1 TO Ordre) AS INTEGER, n AS INTEGER
CALL ReadN
CALL MakeMat
CALL SeeMat
END

SUB ReadN
SHARED n AS INTEGER
DIM k AS INTEGER
INPUT "0<=n<=511"; k
IF k < 0 OR k > (2 ^ (Ordre * Ordre)) - 1 THEN PRINT "erreur de valeur de n"; n: END
n = k
END SUB

SUB MakeMat
SHARED mat() AS INTEGER, n AS INTEGER
DIM i AS INTEGER, j AS INTEGER, x AS INTEGER
x = n
FOR i = 1 TO Ordre
    FOR j = 1 TO Ordre
        mat(i, j) = x MOD 2
        x = INT(x / 2)
    NEXT j
NEXT i
END SUB

SUB SeeMat
SHARED mat() AS INTEGER
DIM i AS INTEGER, j AS INTEGER
FOR i = 1 TO Ordre
    FOR j = 1 TO Ordre
        IF mat(i, j) = 0 THEN
            PRINT "h|";
        ELSE
            PRINT "t|";
        END IF
    NEXT j
    PRINT " "
NEXT i
END SUB




The entrance fee for an exhibition is $6 for an adult and $4 for a child. $700 was collected from the sale of tickets. There were 5 more adults than children. How many adults were there?

Answers

The answer should be 55 adults.

Write 125.06 million 4 different ways.

Answers

125,060,000
125 and 06/100 million
125.06 x 100000
125 million, sixty thousand.

Answer:

125.0600 million

[tex]\frac{6253}{50} million[/tex]

125,060,000

125 million 60 thousand

Step-by-step explanation:

It does not matter how many zeroes we add to the right end after the decimal, it does not change the value of the number.

Thus, 125.06, 125.060, 125.0600,.... all have the same values.

Similarly 125.06 can be change into the rational form

Thus, [tex]125.06=\frac{6253}{50} =\frac{12506}{100} \text{all have same values}[/tex]

We can also write the word "million" into the digits.

Thus, 125.06 million = 125,060,000 = 125 million 60 thousand








































You are baking cookies for your class. There are 23 total students in your class and you have baked 12 cookies. Write and solve an equation to find the additional number x of cookies you need to bake in order to have 2 cookies for each student. Write your equation so that the units on each side of the equation are cookies per student.

Answers


Your equation must look like the following:

(something) = 2 cookies/student.

12+x cookies           2 cookies
--------------------- = ---------------
    23 students          1 student

Solve the following equation:       12+x          2
                                                    ---------       ----
                                                       23             1

Cross-multiplying:  (1)(12+x) = (2)(23) = 46

12+x = 46
      x  = 46-12=34

Must make 34 more cookies to ensure that every student receives 2 cookies.

What is the relationship between the measure of angle and the reflex measure of the angle

Answers

The relationship between the measure of an angle and its reflex angle is their sum is 360 degrees

Angles are measured in degrees and their reflex measures can be obtained by adding 180 degrees to their measures.

In mathematics, an angle is a measure of the amount of turn between two lines or rays that share a common endpoint. The measure of an angle is given in degrees, and it represents the amount of rotation needed to move from one ray to the other.

The reflex measure of an angle is the sum of the angle's measure and 180 degrees. It represents the amount of rotation needed to move from one ray to the other while going in the opposite direction. For example, if an angle has a measure of 30 degrees, its reflex measure would be 30 degrees + 180 degrees = 210 degrees.

So, the relationship between the measure of an angle and its reflex measure is that the reflex measure is obtained by adding 180 degrees to the measure of the angle.

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The price of a dozen roses in the united states is about $30. if $0.559 u.s. dollars can purchase 1.00 turkish lira, how much does the same dozen roses cost in turkey, if purchasing power parity holds?

Answers

Sent you a picture of the solution.

Answer:

16.77

Step-by-step explanation:

MA BRAIN

DVD cases are sold in packages of 20 padded mailing envelopes or so in packets of 12 what is the least number of cases and envelopes you could buy so that there is one case for each envelope with none left over

Answers

The least number of cases and envelopes so that there would be no remainder can be determined by finding their least common multiple. The solution is as follows

     4 | 20  12
        ---------------
        |  5     3
        -------------------

Multiplying 4*5*3 = 60. The least common multiple is 60. Thus, there should be at least 60 each of the envelopes and the packets.

Number of mailing envelopes = 20x = 60
x = 3 
Number of packets = 12y = 60
y = 5

That would be 3 packs of the envelopes, and 5 packs of the packets.


Solve for x. 4−(2x+4)=5 x=32 x=−52 x=−10 x=6


please help

Answers

If you asked about solving this:

4−(2x+4)=5
4-2x - 4 =5
-2x = 5

x= -5/2 = -2.5


Done!
Final answer:

The solution to the equation 4−(2x+4)=5 is x = -2.5. None of the provided suggestions x = 32, x = -52, x = -10, x = 6 are correct.

Explanation:

To solve for x in the equation 4−(2x+4)=5, you first simplify the expression in the parentheses, which creates the equation 4 - 2x - 4 = 5. This simplifies to -2x = 5. You then divide each side by -2 which results in x = -5/2 or x = -2.5. So the solution to this equation is not any of the provided x = 32, x = -52, x = -10, x = 6 but rather x = -2.5.

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A container holds 7 quarts of water. How much is this in gallons?

Answers

To convert 7 quarts to gallons, divide 7 by 4, as there are 4 quarts in a gallon. The result is that 7 quarts equal 1.75 gallons.

To convert quarts to gallons, one must understand the unit equivalence between the two. One gallon is equivalent to 4 quarts. To find out how many gallons are in 7 quarts, divide the number of quarts by the number of quarts in a gallon.

Using the equivalence provided:

1 gallon = 4 quarts

You would perform the following calculation:
7 quarts
4 quarts per gallon = 1.75 gallons

Therefore, 7 quarts is equal to 1.75 gallons.

Answer:

7 quarts of water is equivalent to 1.75 gallons.

Explanation:

To convert quarts to gallons, you can use the conversion factor that 1 gallon is equal to 4 quarts.

Given that the container holds 7 quarts of water, you can use the conversion factor to find out how many gallons that is:

[tex]\[ \text{Number of gallons} = \frac{\text{Number of quarts}}{4} \][/tex]

[tex]\[ \text{Number of gallons} = \frac{7 \text{ quarts}}{4} \][/tex]

[tex]\[ \text{Number of gallons} = 1.75 \text{ gallons} \][/tex]

Which product is negative

Answers

One thing for sure it is not b,d,c its a

1st one -*- =+,+*- = -,-*- = +

2nd one = 0

3rd one-*-=+,+*+=+,+*+=+

4th one +*-=-,-*-=+,+*- = -

 4th one is negative

What is 9 X 10 to the fifth?

Answers

900,000 should be correct. :)
9,000,000 juss add 5 zeros to 90... I'm pretty sure

1 point) the solution of a certain differential equation is of the form y(t)=aexp(3t)+bexp(4t), y ( t ) = a exp ⁡ ( 3 t ) + b exp ⁡ ( 4 t ) , where a a and b b are constants. the solution has initial conditions y(0)=3 y ( 0 ) = 3 and y′(0)=3. y ′ ( 0 ) = 3 . find the solution by using the initial conditions to get linear equations for a a and

Answers

y(t) = a exp(3t) + b exp(4t) conditions, y(0) = 3 y'(0) = 3 y(0) = a exp(3 x 0) + b exp(4 x 0) = a exp(0) + b exp(0) = (a x 1) + (b x 1) = a + b y'(0) = 0 so the linear equation is, a + b = 3

find the equation of the circle where (-9,4),(-2,5),(-8,-3),(-1,-2) are the vertices of an inscribed square.

Answers

check the picture below, so, that'd be the square inscribed in the circle.

so... hmm the diagonals for the square are the diameter of the circle, and keep in mind that the radius of a circle is half the diameter, so let's find the diameter.

[tex]\bf \textit{distance between 2 points}\\ \quad \\ \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) &({{ -2}}\quad ,&{{ 5}})\quad % (c,d) &({{ -8}}\quad ,&{{ -3}}) \end{array}\qquad % distance value d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2} \\\\\\ \stackrel{diameter}{d}=\sqrt{[-8-(-2)]^2+[-3-5]^2} \\\\\\ d=\sqrt{(-8+2)^2+(-3-5)^2}\implies d=\sqrt{(-6)^2+(-8)^2} \\\\\\ d=\sqrt{36+64}\implies d=\sqrt{100}\implies d=10[/tex]

that means the radius r = 5.

now, what's the center?  well, the Midpoint of the diagonals, is really the center of the circle, let's check,

[tex]\bf \textit{middle point of 2 points}\\ \quad \\ \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) &({{ -2}}\quad ,&{{ 5}})\quad % (c,d) &({{ -8}}\quad ,&{{ -3}}) \end{array}\qquad \left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right) \\\\\\ \left( \cfrac{-8-2}{2}~,~\cfrac{-3+5}{2} \right)\implies (-5~,~1)[/tex]

so, now we know the center coordinates and the radius, let's plug them in,

[tex]\bf \textit{equation of a circle}\\\\ (x-{{ h}})^2+(y-{{ k}})^2={{ r}}^2 \qquad \begin{array}{lllll} center\ (&{{ h}},&{{ k}})\qquad radius=&{{ r}}\\ &-5&1&5 \end{array} \\\\\\\ [x-(-5)]^2-[y-1]^2=5^2\implies (x+5)^2-(y-1)^2=25[/tex]
Final answer:

The equation of the circle where the vertices of an inscribed square are (-9,4),(-2,5),(-8,-3),(-1,-2) is (x+5)² + (y-1)² = 25. This is found by getting the average x and y coordinates to find the center of the circle, calculating the radius, and applying it to the standard equation of a circle.

Explanation:

To find the equation of the circle where the vertices of an inscribed square are located at (-9,4),(-2,5),(-8,-3),(-1,-2), first, you need to find the center of the circle. In the case of a square inscribed in a circle, the center of the square is the same as the center of the circle. This can be found by averaging the x and y coordinates of the vertices of the square.

The average x-coordinate = [(-9) + (-2) + (-8) + (-1)] / 4 = -5
The average y-coordinate = [4 + 5 - 3 - 2] / 4 = 1

So, the center of the circle is at (-5, 1).

Next, you need to calculate the radius of the circle. The radius in an inscribed square is the half of the square's diagonal. Calculate the distance between two opposite vertices of the square - for example (-9,4) and (-1,-2). Apply the distance formula: √[(-1 - (-9))^2 + (-2 - 4)^2 ]. That's √[64 + 36], giving a distance of √100 = 10. As this is the diagonal of the square, the radius would be half of this, giving us a radius of 5.

Finally, the equation of the circle in its standard form (x-h)² + (y-k)² = r² can be written as (x+5)² + (y-1)² = 5².

Thus, the equation of the circle is (x+5)² + (y-1)² = 25.

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f(t)=10t2+5t+1 . Find the value of t for which the tangent line to the graph of f(t) has slope 1.

Answers

[tex]\bf f(t)=10t^2+5t+1\implies \stackrel{\textit{slope of tangent}}{\cfrac{df}{dt}}=20t+5\implies 1=20t+5 \\\\\\ -4=20t\implies -\cfrac{4}{20}=t\implies -\cfrac{1}{5}=t[/tex]

The value of t for which the tangent line to the graph of f(t) has slope 1 is -1/5.

The given function is f(t)=10t²+5t+1.

We need to find the value of t for which the tangent line to the graph of f(t) has slope 1.

What is the tangent line to the graph?

In geometry, the tangent line (or simply tangent) to a plane curve at a given point is the straight line that "just touches" the curve at that point. Leibniz defined it as the line through a pair of infinitely close points on the curve.

Now, f'(t) = slope of the tangent line to the curve at the point (t, f(t)).

Given, f'(t) = 1

f(t)=10t²+5t+1

⇒f'(t)=20t+5

⇒1=20t+5

⇒20t=-4

⇒t=-4/20

⇒t=-1/5

Therefore, the value of t for which the tangent line to the graph of f(t) has slope 1 is -1/5.

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−20≤10n i need a solution.

Answers

TAKE 10 ON THE OTHER SIDE 10 IS MULTIPLYING WITH n HENCE WHEN IT GOES TO OTHER SIDE IT WILL UNDERGO DIVISION
-20/10<n (or equal to)
-2<n


sin α = 21/29, α lies in quadrant II, and cos β = 15/17, β lies in quadrant I Find sin (α - β).

Answers

[tex]\sin(\alpha-\beta)=\sin\alpha\cos\beta-\cos\alpha\sin\beta[/tex]

[tex]\sin\alpha=\dfrac{21}{29}\implies \cos^2\alpha=1-\sin^2\alpha=\dfrac{400}{841}[/tex]

Since [tex]\alpha[/tex] lies in quadrant II, we have [tex]\cos\alpha<0[/tex], so

[tex]\cos\alpha=-\sqrt{\dfrac{400}{841}}=-\dfrac{20}{29}[/tex]

[tex]\cos\beta=\dfrac{15}{17}\implies\sin^2\beta=1-\cos^2\beta=\dfrac{64}{289}[/tex]

[tex]\beta[/tex] lies in quadrant I, so [tex]\sin\beta>0[/tex] and

[tex]\sin\beta=\sqrt{\dfrac{64}{289}}=\dfrac8{17}[/tex]

So

[tex]\sin(\alpha-\beta)=\dfrac{21}{29}\dfrac{15}{17}-\left(-\dfrac{20}{29}\right)\dfrac8{17}=\dfrac{475}{493}[/tex]
Final answer:

The value of sin (α - β), where sin α = 21/29 and α is in the 2nd quadrant, and cos β = 15/17 and β is in the 1st quadrant, is calculated to be 379/493.

Explanation:

In trigonometry, the formula for sin (α - β) is defined as sin α cos β - cos α sin β. Given the problem, we know sin α is 21/29 and cos β is 15/17.

However, we need to determine cos α and sin β. In these cases, we use the identity sin² α + cos² α = 1, and its counterpart for β. For α being in the second quadrant, cos α would be negative. Therefore, cos α = -√(1 - (21/29)²), which simplifies to -8/29. Similarly, for β in the first quadrant (where sin β is positive), sin β = √(1 - (15/17)²), which simplifies to 8/17.

Substitute these values into the formula for sin (α - β), we have sin (α - β) = (21/29 * 15/17) - (-8/29 * 8/17) = 315/493 + 64/493 = 379/493.

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What number is needed to complete the pattern below?

66 73 13 21 52 __ 10 20

Answers

Put the numbers in pairs and find the differences.

73-66= 7
21-13= 8
? -52= ?
20-10= 10

The difference should increase by one each time. The missing difference is 9 (7, 8, 9, 10).

? -52= 9
61-52=9

Final answer: 61

Should the quotient of an integer divided by a nonzero integer always be a rational number? Why or Why not?

Answers

YES , it is a rational number



a rational number is defined as

a/b , where a and b are integers, with b≠0



when you divide two integers you get exactly that form

You have been able to do the dishes in 30 minutes and vacuum in 15 minutes. youer roomate takes 40 minutes to do the dishes and 60 minutes to vacuum. based on this scenario

Answers

yours d+v=45minutes and roommate d+v=100minutes 






A man has 24 coins in his pocket, all of which are dimes and quarters. If the total value of his change is 345 cents, how many dimes and how many quarters does he have?

Answers

The man has 17 dimes and 7 quarters.

A system of equations was set up, using the total number of coins and their total value, to determine the quantity of each coin type.

Let's denote the number of dimes as d and the number of quarters as q. We are given two facts: (1) the man has a total of 24 coins, and (2) the total value of the coins is 345 cents. Thus we have two equations:

d + q = 24 (since the total number of coins is 24)10d + 25q = 345 (since the value of each dime is 10 cents and each quarter is 25 cents, and their total value is 345 cents)

We can solve this system of equations to find the values of d and q.

Subtracting the first equation from the second (multiplied by 10) to eliminate the variable d:

10d + 25q = 345
-(10d + 10q = 240)
-------------------------
15q = 105

Dividing by 15 to solve for q, we get q = 7. This means the man has 7 quarters. Substituting q = 7 into the first equation:

d + 7 = 24
d = 24 - 7
d = 17

So, the man has 17 dimes.

Therefore, the man has 17 dimes and 7 quarters.

3x^2-5x-1 from 8x^2+2x-9

Answers

8x^2 + 2x - 9 - (3x^2 - 5x - 1) =
8x^2 + 2x - 9 - 3x^2 + 5x + 1 =
5x^2 + 7x - 8 <===
[tex](3x^2-5x-1)-(8x^2+2x-9) =3x^2-5x-1-8x^2-2x+9 =3x^2-8x^2-5x-2x-1+9 =-5x^2-7x+8 [/tex].

What's the answer to 2z-31=-9z+24

Answers

2z-31=-9z+24
add 9z to both sides
11z-31=24
add 31 to both sides
11z=55
divide by 11 on both sides
z=5
the answer is to this is z=5

Select the answer for this number showing three significant figures. Remember to round. 566 (1)600 (2)570 (3)566(4) 500

Answers

The answer is (1)600! I'm taking the same course, and I know this gets confusing. Hope I helped!

We have to round 566, such that , it has three significant figures.

→ Option 1

600=It has only one Significant figure.Zeroes which lie on right side of digit ,if there is no decimal after zeroes are not significant.

Option 2

570=Two Significant figure.

→ Option 3

566=Three Significant figure.

→ Option 4

500=One Significant figure.

Option 3 ,which is equal to 566, is most appropriate ,among given Options, that is when this number is rounded , it has three significant figures.

Put these decimals in order from least to greatest.

7.0,0.07,0.7,0.077

Answers

0.07,   0.077,    0.7, 7.0

hope this helps (there are only 4 of them right?)

0.07, 0.077, 0.7, 7.0

That's the answer from least to greatest

What is 121.6 in word form

Answers

One-Hundred and Twenty-One point Six
one hundred twenty-one and six tenths

The initial population of a town is 2600, and he grows with the doubling time of 10 years. What will the population be in 12 years?

Answers

I think it would be 5,720, because if you figure every year the population grows 260, then 2600x2 would be doubled then add the 2 years missing so add 260+260. It would equal 5,720. 
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