Calculate the magnitude of the electric field at the center of a square with sides 24.1 cm long if the corners, taken in rotation, have charges of

1.16C,

2.32μC,

3.48μC

4.64μC

(all positive).

The seesaw will average out a little bit, and not be as tilted to one side as before.

Answer:

v₂ = 395.83 m/s

Explanation:

given,

Average speed of nitrogen molecule, v₁ = 475 m/s

Temperature in summer, T₁ = 300 K

Average speed of nitrogen molecule in winter, v₂ = ?

Temperature in winter, T₂ = 250 K

The relation of average speed with temperature

          [tex]v\ \alpha\ \sqrt{T}[/tex]

now,

        [tex]\dfrac{v_2}{v_1} = \dfrac{\sqrt{T_2}}{\sqrt{T_1}}[/tex]

        [tex]\dfrac{v_2}{475} = \dfrac{\sqrt{250}}{\sqrt{300}}[/tex]

                     v₂ = 0.833 x 475

                     v₂ = 395.83 m/s

The average speed on a frigid winter day is equal to v₂ = 395.83 m/s

Answer:

heat

Explanation:

Answer:

50 V / 150 V

Explanation:

Final answer:

The question discusses the grounding of a transformer based on voltage levels and defines the characteristics of step-down and step-up transformers in terms of voltage and current. Transforming the power efficiently is crucial, and the number of windings plays a significant role in determining the output voltage and current.

Explanation:

The question pertains to transformers and their operating principles regarding voltage, current, and the number of windings. If the voltage at the secondary side of a transformer is less than 50 volts and the primary side exceeds 150 volts to ground, the secondary side shall be grounded.

When a transformer has fewer windings in the secondary coil compared to the primary coil, it is a step-down transformer, meaning the secondary voltage is less than the primary voltage. Conversely, a step-up transformer has more windings in the secondary coil, resulting in a higher secondary voltage compared to the primary voltage.

In the context of primary and secondary properties of transformers, option (a) the Primary voltage is higher than secondary voltage defines a step-down transformer. Additionally, (c) the Primary current is higher than secondary current is not typically true for a step-down transformer.

Instead, the primary current would be lower than the secondary current since power (P = IV) is conserved across the transformer. Therefore, if the voltage decreases, the current must increase to maintain the equivalent power (assuming ideal conditions with no power losses).

Answer: c) with the same brightness

Explanation: The load in this case the bulb, is not polarized ( it has no positive and negative points) thus any connection relative to the battery (source) will have no effect on it brightness.

Also, brightness is a function of current and in this case the voltage ( from battery) and resistance of load (bulb) is constant, and according to ohms law (V=IR) if the current is constant at the first connection, it will be the same at the reversed connection.

Final answer:

When a battery is reversed and reconnected to a lightbulb, the bulb will glow with the c) same brightness because the alteration does not change the magnitude of the voltage or the resistance in the circuit.

Explanation:

When a battery is reversed and reconnected to a lightbulb, the bulb will glow with the same brightness. This is because the brightness of a bulb in a simple circuit primarily depends on the voltage across the bulb and the resistance in the circuit. Reversing the battery does not change the magnitude of the voltage or the resistance; it merely changes the direction of current flow.

In addition to this, lightbulbs, being resistive elements, respond to the magnitude of the current. As long as the total voltage remains the same, reversing the battery's specific direction does not affect the brightness, thus the correct answer is (c) with the same brightness.

The magnitude of the position vector :r is approximately 7.32 m. When the centripetal acceleration is directed due east, :r will also be due east. When the centripetal acceleration is directed due south, :r will also be due south.

The magnitude of the position vector :r can be determined using the equation :a = :v^2 / r where :v is the speed of the man and :a is the centripetal acceleration. Rearranging the equation, we get :r = :v^2 / :a. Substituting the given values, we find :r = (3.66^2) / 1.83 which is approximately 7.32 m.

When the centripetal acceleration is directed due east, the position vector :r will be due east. When the centripetal acceleration is directed due south, the position vector :r will be due south.

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Answer:

[tex]\frac{dQ}{dt} =-hA\Delta T(t)[/tex]

Explanation:Newton.s law of cooling states that the rate of cooling of an object is proportional to the difference between its own temperatures and temperature of its surroundings. Mathematically,

[tex]\frac{dQ}{dt} =-hA [T(t)-T(s)]\\[/tex]

[tex]\frac{dQ}{dt} =-hA\Delta T(t)[/tex]

where [tex]Q[/tex] is the heat transfer

[tex]h[/tex] is heat transfer coefficient

[tex]A[/tex] is the heat transfer surface area

[tex]T[/tex] is the temperature of the object's surface

[tex]T(s)[/tex] is the temperature of the surroundings

Final answer:

Newton's Law of Cooling can be expressed using a differential equation: dQ/dt = -k(T - Ts).

Explanation:

Newtons's Law of Cooling states that the rate of cooling of an object is proportional to the difference between its temperature and the temperature of its surroundings. In this particular situation, we can express this law using a differential equation:

dQ/dt = -k(T - Ts)

Where:

Explanation:

First we will convert the given mass from lb to kg as follows.

        157 lb = [tex]157 lb \times \frac{1 kg}{2.2046 lb}[/tex]

                   = 71.215 kg

Now, mass of caffeine required for a person of that mass at the LD50 is as follows.

         [tex]180 \frac{mg}{kg} \times 71.215 kg[/tex]

         = 12818.7 mg

Convert the % of (w/w) into % (w/v) as follows.

      0.65% (w/w) = [tex]\frac{0.65 g}{100 g}[/tex]

                           = [tex]\frac{0.65 g}{(\frac{100 g}{1.0 g/ml})}[/tex]

                           = [tex]\frac{0.65 g}{100 ml}[/tex]

Therefore, calculate the volume which contains the amount of caffeine as follows.

   12818.7 mg = 12.8187 g = [tex]\frac{12.8187 g}{\frac{0.65 g}{100 ml}}[/tex]

                       = 1972 ml

Thus, we can conclude that 1972 ml of the drink would be required to reach an LD50 of 180 mg/kg body mass if the person weighed 157 lb.

Given Information:

Radius = r = 0.31 m

Potential difference = V = 1375 Volts

Required Information:

charge = q = ?

Answer:

q = 4.741x10⁻⁸ C

Solution:

[tex]V = kq/r[/tex]

Where k = 8.99x10⁹ N.m²/C² is the Coulomb's constant

Re-arranging the equation to find the q

[tex]q = Vr/k[/tex]

q = (1375*0.31)/8.99x10⁹

q = 4.741x10⁻⁸ C = 47.41 nC

Answer:

The car that went 54 km in 2/3h was faster, 5/4 times faster than the other car

Explanation:

Average speed of a car is the ratio between the displacement [tex]\Delta x [/tex] and the time (t) it takes to do that displacement:

[tex]V_{avg}=\frac{\Delta x}{t} [/tex]

So, for the first car:

[tex]V_{avg1}=\frac{60km}{\frac{5h}{6}} =72\frac{km}{h} [/tex] (1)

for the second car we have:

[tex]V_{avg2}=\frac{60km}{\frac{2h}{3}} =90\frac{km}{h} [/tex] (2)

So, the second cart is faster than the first one. To find how many times divide speed 2 by speed 1:

[tex]\frac{90}{72}=\frac{5}{4} [/tex]

Answer:

180m

Explanation:

V = Final velocity = 18

U = Initial Velocity = 12

a = Acceleration = (18-12)/12 = 6/12 = 0.5

d = ?

V² = U² + 2ad

18² = 12² + 2*0.5*d

324 = 144 +d

d = 324 - 144

d = 180m

Final answer:

The boy travels a distance of 180 meters. This calculation is based on the kinematic equations for uniformly accelerated motion using the given initial and final velocities and the time taken.

Explanation:

The subject of the question is Physics, and it appears to be at a High School level. The problem deals with kinematics, specifically the equations of motion for an object with constant acceleration. To find the distance traveled by the boy sledding down the hill, we can use the kinematic equation: s = ut + ½ at², where s is the distance, u is the initial velocity, t is the time, and a is the acceleration. The initial speed u is given as +12 m/s, the final velocity v is +18 m/s, and the time t is 12 seconds. We first find the acceleration using the formula a = (v - u) / t. Substituting the known values, we get a = (18 m/s - 12 m/s) / 12 s = 0.5 m/s². Now we can calculate the distance s using the kinematic equation: s = (12 m/s)(12 s) + ½(0.5 m/s²)(12 s)² = 144 m + 36 m = 180 m. Therefore, the boy travels a distance of 180 meters.

Answer:

h= 161.06 m

Explanation:

Given that

Speed of the sound ,C= 343 m/s

Total time ,t= 6.2 s

lets take the depth of the well = h

The time taken by stone before striking the water = t₁

we know that

[tex]h=\dfrac{1}{2}gt_1^2[/tex]

[tex]t_1=\sqrt{\dfrac{2h}{g}}[/tex]

The time taken by sound =t₂

[tex]t_2=\dfrac{h}{343}[/tex]

The total time

t = t₁+ t₂

[tex]6.2 = \sqrt{\dfrac{2h}{g}}+\dfrac{h}{343}[/tex]

[tex]6.2 = \sqrt{\dfrac{2h}{9.81}}+\dfrac{h}{343}[/tex]

Now by solving the above equation we get

h= 161.06 m

Therefore the depth of the well will be 161.06 m.

Answer:

0.0257259766982 m

Explanation:

[tex]P_2[/tex] = Atmospheric pressure = 101325 Pa

[tex]d_1[/tex] = Initial diameter = 1.5 cm

[tex]d_2[/tex] = Final diameter

[tex]\rho[/tex] = Density of water = 1000 kg/m³

h = Depth = 40 m

The pressure is

[tex]P_1=P_2+\rho gh\\\Rightarrow P_1=101325+1000\times 9.81\times 40\\\Rightarrow P_1=493725\ Pa[/tex]

From ideal gas law we have

[tex]\dfrac{P_1V_1}{T_1}=\dfrac{P_2V_2}{T_2}\\\Rightarrow \dfrac{P_1\dfrac{4}{3\times8}\pi d_1^3}{T_1}=\dfrac{P_2\dfrac{4}{3\times8}\pi d_2^3}{T_2}\\\Rightarrow \dfrac{P_1d_1^3}{T_1}=\dfrac{P_2d_2^3}{T_2}\\\Rightarrow d_2=(\dfrac{P_1d_1^3T_2}{P_2T_1})^{\dfrac{1}{3}}\\\Rightarrow d_2=(\dfrac{493725\times 0.015^3\times (20+273.15)}{101325\times (10+273.15)})^{\dfrac{1}{3}}\\\Rightarrow d_2=0.0257259766982\ m[/tex]

The diameter of the bubble is 0.0257259766982 m

Answer: 75.05N

Explanation:

According to newton's second law,

Force = mass×acceleration

Given mass = 5.0kg

Acceleration = change in velocity/time

Velocity = change in displacement/position/time i.e dy/dt

Given position of the particle as y(t)=(2.80 m/s)t +(0.61 m/s)t³

dy/dt = 2.80 + 3(0.61)t²

V = dy/dt = 2.80 + 1.83t²

Acceleration (a) = dv/dt = 2(1.83)t

dv/dt = 3.66t

To get the force when t =4.10second

dv/dt @ t = 4.10s will be 3.66(4.10)

acceleration = 3.66×4.10 = 15.01m/s²

Magnitude of the force F = ma

F = 5.0kg × 15.01m/s²

F = 75.05N

Answer:

Technician B

Explanation:

The current amp value at the battery position is the current value. The current is the same everywhere for a series circuit without any connecting points. The current at the position of the battery is the same as in each resistor position.

Final answer:

Technician B is correct: current is the same in all parts of a series circuit. Technician A is incorrect: current divides in the branches of a parallel circuit and is not the same. The sum of branch currents equals the total current in parallel circuits.

Explanation:

Understanding Current in Series and Parallel Circuits

Technician B is correct when they say current is the same everywhere in a series circuit. In a series circuit, there is only one path for the current to flow, thus the current (I) is identical through any component in the series, as stated: I = I1 = I2 = I3. This principle is known as the first principle of series circuits. On the other hand, Technician A is incorrect in suggesting current is the same in each branch of a parallel circuit. In parallel circuits, the current divides at each junction and the total supplied current is the sum of the currents in the various branches.

So, in summary, in a series circuit, the current is constant through all components, and the total voltage drop across all components adds up to the voltage supplied by the source. In a parallel circuit, meanwhile, each resistance experiences the same voltage difference, while the current through each branch may vary depending on the resistance of that branch.

Answer:

The sound intensity heard standing 20.5 m away = 0.0000343 W/m² = 3.43 × 10⁻⁵ W/m²

Explanation:

Intensity of sound at some distance r away is calculated as (power of the sound/surface area of wall of imaginary sphere at distance r)

Power of the sound = 0.181 W

Surface area of wall of imaginary sphere = 4πr² = 4π(20.5²) = 5281.02 m²

Intensity = 0.181/5281.02 = 0.0000343 W/m² = 3.43 × 10⁻⁵ W/m²

A. Hannah should choose copper for her pot because it has the lowest specific heat, and  she should choose wood for her spoon because it has the highest specific heat

Explanation:

The specific heat capacity of a substance is the amount of heat required to increase the temperature of 1 kg of the substance by 1 degree.

Mathematically:

[tex]C=\frac{Q}{m\Delta T}[/tex]

where

Q is the amount of heat supplied to the substance

m is the mass of the subtsance

[tex]\Delta T[/tex] is the increase in temperature

This means that:

In this situation, we want:

Therefore, the most reasonable choice in this situation is:

A. Hannah should choose copper for her pot because it has the lowest specific heat, and  she should choose wood for her spoon because it has the highest specific heat

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Answer:

Part A:

[tex]Displacement\ vector= -40\hat i+20\hat j+25\hat k[/tex]

Part B:

Magnitude of displacement=44.721359 m

Explanation:

Given Data:

40 m in negative direction of the x axis

20 m perpendicular path to his left (considering +ve y direction)

25 m up a tower (Considering +ve z direction)

Required:

Solution:

Part A:

[tex]Displacement= (0-40)\hat i+(0+20)\hat j+(0+25)\hat k\\Displacement= -40\hat i+20\hat j+25\hat k[/tex]

where:

i,j,k are unit vectors

Part B:

Sign falls to foot of tower so z=0

[tex]Displacement= -40\hat i+20\hat j+0\hat k[/tex]

Magnitude of displacement:

[tex]Magnitude\ of\ displacement=\sqrt{(-40)^2+(20)^2+0^2} \\Magnitude\ of\ displacement=44.721359\ m[/tex]

Answer:

In m/s^2:

a=11.3778 m/s^2

In units of g:

a=1.161 g

Explanation:

Since the racing greyhounds are capable of rounding corners at very high speed so we are going use the following formula of acceleration for circular paths.

[tex]a=\frac{v^2}{r}[/tex]

where:

v is the speed

r is the radius

Now,

[tex]a=\frac{16^2}{45/2}\\ a=11.3778 m/s^2[/tex]

In g units:

[tex]a=\frac{11.3778\ g}{9.8}\\ a=1.161\ g[/tex]

Answer:

3.3 m/s

Explanation:

The question is incomplete, here is the complete question:

After skiding down a snow-covered hill on an inner tube, Ashley is coasting across a level snowfield at a constant velocity of 2.7 m/s. Miranda runs after her at a velocity of 4.1 m/s and hops on the inner tube. How fast do the two of them slide across the snow together on the inner tube? Ashley's mass is 71 kg and Miranda's is 58 kg. Ignore the mass of the inner tube and any friction between the inner tube and the snow.

SOLUTION:

mass of Ashley (Ma) = 71 kg

mass of Miranda (Mm) = 58 kg

initial velocity of Ashley (Va) = 2.7 m/s

initial velocity of Miranda (Vm) = 4.1 m/s

Find the final velocity (Vf) at which they both slide together

from the conservation of momentum, initial momentum = final momentum

Ma.Va + Mm.Vm = (Ma + Mm) . Vf

[tex]Vf = \frac{Ma.Va + Mm.Vm}{Ma + Mm} \\ Vf=\frac{(71 x 2.7) + (58 x 4.1)}{71+58}[/tex]

Vf = (191.7 +237.8) / (129)

Vf = 3.3 m/s

Answer:

DL = 1.5*10^-4[m]

Explanation:

First we will determine the initial values of the problem, in this way we have:

F = 60000[N]

L = 4 [m]

A = 0.008 [m^2]

DL = distance of the beam compressed along its length [m]

With the following equation we can find DL

[tex]\frac{F}{A} = Y*\frac{DL}{L} \\where:\\Y = young's modulus = 2*10^{11} [Pa]\\DL=\frac{F*L}{Y*A} \\DL=\frac{60000*4}{2*10^{11} *0.008} \\DL= 1.5*10^{-4} [m][/tex]

Note: The question should be related with the distance, not with the diameter, since the diameter can be found very easily using the equation for a circular area.

[tex]A=\frac{\pi}{4} *D^{2} \\D = \sqrt{\frac{A*4}{\pi} } \\D = \sqrt{\frac{0.008*4}{\\pi } \\\\D = 0.1[m][/tex]

The energy is derived from A.sun.

Explanation:

Answer:

Net force = 129.4, Force as multiple of weight of her hand = 18.84

Explanation:

Given Data:

Total body weight = 56.0 kg   ;

no. of turns = 2.5/second        ;

hand to hand distance = 1.5m ;

weight of hand = 1.25% of body weight ;

Solution:

mass of hand = [tex]\frac{1.25}{100}[/tex]*56 = 0.7kg ;

radius = d/2 = 1.5/2 = 0.75m     ;

Now we need to find velocity, as we know that velocity can be calculated by dividing distance by time

v = d/t = [tex]\frac{2.5*2*3.14*0.75}{1}[/tex] = 11.775 m/s or 12 m/s;

a.

The formula to calculate force is given as

F = mv²/r = (0.7*11.775²)/0.75 = 129.4 N

b.

To calculate force as multiple of weight on her hand, we need to calculate the gravitational force W on her hand first.

W = gm = 9.81 * 0.7 = 6.867 N

Now the wieght on her hand can be represented by

[tex]\frac{Force_{net} }{weight of hand}[/tex]  = 129.4 / 6.867 = 18.84

The force that the ice skater exerts on her hand (150N) is roughly 22 times the weight of her hand (6.86N). She achieves this by spinning with her arms outstretched.

The skater's hand, as given by biometric measurements, makes up about 1.25% of her body weight. Since her body weight is 56.0kg, her hand weight would be 0.0125 * 56.0kg = 0.7kg. In terms of newtons (N), when we consider the acceleration due to gravity as approximately 9.8 m/s², the weight of her hand becomes 0.7kg * 9.8 m/s² = 6.86N. Thus, if we're asked to express the force that her wrist exerts on her hand (150N) as a multiple of the weight of her hand, we'll divide the two forces. Namely, F_hand/F_weight = 150N/6.86N which is approximately 21.86. Therefore, the force her wrist exerts on her hand is roughly 22 times the weight of her hand.

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Answer:

Magnitude = 4.056 m

Direction = 42.3⁰

Explanation:

The vector is resolved in terms of the vertical and horizontal components. Let's look each of these separately.

The vector 4.40 is directed East. This automatically becomes a horizontal component.

But we know that there is a vector 3.40 North West. The angle the vector makes with the horizontal is 61⁰.

Resolving the vectors should yield the horizontal and vertical components:

Horizontal components

The first component is 4.40 m

The second one is derived by resolving 3.40 to the horizontal like this 3.40 × - cos 61⁰ = -1.648 m

Adding the horizontal component gives 4.40 m + ( -1.648 m) = 2.752 m

Vertical components

Resolve 3.40 with the angle 61⁰ like this: vertical comp = 3.41 × sin 61

                                                                                           = 2.98 m

The magnitude is given by √[(2.98)²+ (2.752)²] = 4.056 m Ans

The direction us given by tan⁻¹ (2.98/2.752) = 42.3⁰ Ans

To find the tension in the silk strand, we can use the formula: T = (4 x L x f^2 x m x pi^2 x r^2) / (g x rho x sin(theta)). Plugging in the given values, we can solve for T.

To find the tension in the silk strand, we can use the formula:

T = (4 x L x f^2 x m x pi^2 x r^2) / (g x rho x sin(theta))

Where:

Plugging in the given values:

By substituting these values into the equation and solving for T, we can find the tension in the silk strand.

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The spider must adjust the tension in a 16 cm strand of silk to approximately 0.185 N to achieve a resonance frequency of 200 Hz.

The formula for the fundamental frequency (f) of a stretched string is:

f = (1 / 2L) * √(T / μ)

Where:

First, we calculate the linear mass density (μ) of the spider silk, using:

μ = ρ * A

Where:

Given the diameter (d) of the strand is 0.0020 mm or 2.0 x 10⁻⁶ m, the cross-sectional area can be calculated as:

A = π * (d / 2)²

A = π * (1.0 x 10⁻⁶)² = π x 10⁻¹² m²

Therefore:

μ = 1300 kg/m³ * π x 10⁻¹² m² = 4.084 x 10⁻⁹ kg/m

Using the frequency formula, rearranged to solve for tension (T):

T = (2Lf)² * μ

T = (2 * 0.16 m * 200 Hz)² * 4.084 x 10⁻⁹ kg/m

T = 184.8272 x 10⁻⁹ N

T ≈ 0.185 N

The tension the spider must adjust to achieve a resonance at 200 Hz for a 16 cm long strand of silk is approximately 0.185 N.

To calculate the distance that it will take to bring the car to a stop, we can use the equations of motion. The force of kinetic friction can be calculated by multiplying the coefficient of friction by the normal force. Using the equations v = u + at and s = ut + 0.5at^2, we can find the distance.

To calculate the distance that it will take to bring the car to a stop, we can use the equations of motion. The force of kinetic friction can be calculated by multiplying the coefficient of friction by the normal force. The normal force is equal to the weight of the car, which is given by the mass of the car multiplied by the acceleration due to gravity. The force of kinetic friction is equal to the mass of the car multiplied by the acceleration. Rearranging the equation F = ma to solve for acceleration gives us a = F/m. Substituting the force of kinetic friction for F and the mass of the car for m, we can find the acceleration. Using the equation v = u + at, where v is the final velocity (0 m/s), u is the initial velocity (20.0 m/s), a is the acceleration, and t is the time, we can solve for t. Finally, we can use the equation s = ut + 0.5at^2 to calculate the distance s that it will take to bring the car to a stop. Plugging in the values for u, t, and a will give us the answer.

Answer:

[tex]2.044 * 10^{-18}[/tex] J

Explanation:

Parameters given:

[tex]n_{1} = 4\\\\n_{2} = 1[/tex]

We know that the electron fell from level 4 to level 1. We can use the Rydberg's equation to find the [tex]2.044 * 10^{-18}[/tex] that is emitted by the electron in the process. Rydberg's equation is given as:

1/λ = [tex]R * (\frac{1}{(n_{2})^2} - \frac{1}{(n_{1})^2})[/tex]

where R = Rydberg's constant = [tex]1.0973731568508 * 10^{7}[/tex]

1/λ =    [tex]1.0973731568508 * 10^{7} (\frac{1}{1^{2}} - \frac{1}{4^{2}} } )[/tex]

1/λ =    [tex]1.0973731568508 * 10^{7} (\frac{1}{1} - \frac{1}{16} } )[/tex]

1/λ =   [tex]1.0973731568508 * 10^{7} * \frac{15}{16}[/tex]

1/λ =   [tex]1.029 * 10^{7}[/tex] [tex]m^{-1}[/tex]

∴ λ = [tex]9.72 * 10^{-8}[/tex] m

Energy of the photon is given by:

E = (hc)/λ

where

h = Planck's constant = [tex]6.62607004 * 10^{-34} m^2 kg / s[/tex]

c = speed of light = 299792458 m / s

∴ E =    [tex]\frac{6.62607004 * 10^{-34} * 299792458}{9.72 * 10^{-8}}[/tex]

E = [tex]2.044 * 10^{-18}[/tex] J

The energy of the photon is [tex]2.044 * 10^{-18}[/tex] J

Final answer:

The energy of a photon emitted when an electron in a hydrogen atom falls from n=4 to n=3 can be found using the Rydberg formula. The constant R (Rydberg constant) along with the energy levels n1 and n2 are used in the formula to calculate this energy in joules.

Explanation:

The magnitude of energy of a photon of light that is emitted when an excited electron in a hydrogen atom falls from n = 4 to n = 3 can be calculated using the Rydberg formula for the energy difference between two hydrogen energy levels. In this case, since the question only specifies a drop of one energy level, we'll correct the typo where it currently indicates a fall from n=4 to n=1, and we'll proceed with the fall from n=4 to n=3. The formula to use is:

E = R ×  (1/n1² - 1/n2²)

where:

R is the Rydberg constant (2.179 × 10⁻¹⁸ J),

n1 and n2 are the principal quantum numbers (integers) for the initial and final energy levels, respectively.

The calculation is then:

E = 2.179 × 10⁻¹⁸ J ×  (1/3² - 1/4²) = 2.179 × 10⁻¹⁸ J ×  (1/9 - 1/16) = 2.179 × 10⁻¹⁸ J × (7/144)

After calculating the above expression, you will get the energy in joules of the photon emitted due to the electron's transition.

Answer:

Explanation:

Given

Halley's closest distance from sun is [tex]r_1=0.59\ A.U.[/tex]

Greatest distance is [tex]r_2=35\ A.U.[/tex]

Comet's speed at closest approach is [tex]v_1=47\ km/s[/tex]

As there is no external torque so angular momentum of comet about the sun is conserved

[tex]L_1=L_2[/tex]

[tex]mr_1^2\times \omega _1=mr_2^2\times \omega _2[/tex]

where [tex]\omega =angular\ velocity [/tex]

This can be written as [tex]\omega =\frac{v}{r}[/tex]

Therefore  

[tex]mr_1^2\times \frac{v_1}{r_1}=mr_2^2\times \frac{v_2}{r_2}[/tex]

[tex]r_1\times v_1=r_2\times v_2[/tex]

[tex]0.59\times 47=35\times v_2[/tex]

[tex]v_2=0.79\ km/s[/tex]  

Answer:

D) Sound waves carry energy parallel to the motion of the wave, while light waves carry energy perpendicular to it.

Explanation:

A) This is incorrect because Light waves do not need a medium to pass through it while Sound waves need a medium to pass through it.

B) This is incorrect as explained above.

C) This is incorrect because Light waves do not carry energy parallel to the motion of the wave.

Light waves are transverse waves, as so they carry energy perpendicular to the motion of the wave while Sound waves are longitudinal waves and so, they carry energy parallel to the motion of the wave.

D) This is correct because Sound waves carry energy parallel to the motion of the wave.

Sound waves are transverse waves, as so they carry energy parallel to the motion of the wave while Light waves are longitudinal, as so they carry energy perpendicular to the motion of the wave.

Answer:

D-Sound waves carry energy parallel to the motion of the wave, while light waves carry energy perpendicular to it.

Explanation:

Answer:

d = 78 [km]

Explanation:

The displacement shift was from Tipton to Iowa city, so we have:

d1 = 27[km]

Then he travels back for 15[km]

d2 = 15[km]

Finally he returns back to Iowa city the displacement 36 [km]

d3 = 36[km]

d = d1 + d2 + d3

d = 27 + 15 + 36

d = 78 [km]